Working scientifically and practical skills
By the end of this chapter you will be able to
- Name the independent, dependent and control variables in a practical
- Write a risk assessment with a hazard, a risk and a control measure
- Calculate a mean, decide whether an anomaly should be removed, and explain precision and accuracy
- Convert units, write numbers in standard form and calculate a percentage change
- Read values from a graph, describe a pattern, and evaluate a conclusion
You should already know
- Working with units, means and graphs at KS3 (Year 9 Science and Maths)
Where this leads
- Every required practical in the course (Chapters 2 to 18)
- Cell sizes in standard form (Chapter 2)
GCSE Biology. Content follows the GCSE (9-1) subject content for England (Edexcel and AQA). Content references: Identify independent, dependent and control variables, and plan a fair test, Assess the risks of a practical and describe control measures, Calculate means, identify anomalies, and explain precision, accuracy and reliability, Use units and standard form, and calculate percentage change, Draw and read tables and graphs, and evaluate a method and a conclusion.
Exercise P Do you remember?
Method. Add the values, then divide by how many there are.
- Add. Add the three values: 4 + 6 + 8 = 18.4 + 6 + 8 = 18
- Divide. Divide the total by 3.18 / 3 = 6
- Write the answer. 6
Check. 6 x 3 = 18. ✓
Method. Recall the length units.
- Recall. One centimetre is ten millimetres.1 cm = 10 mm
- Write the answer. 10
Check. 10 mm divided by 10 is 1 cm. ✓
Method. Multiply by 10 and check the number of zeros.
- Multiply. Add one zero to 100.100 x 10 = 1000
- Write the answer. 1000
Check. 1000 divided by 10 is 100. ✓
Method. Recall the words.
- Recall. The independent variable is the one that is changed on purpose.changed on purpose
- Write the answer. the one you change on purpose
Check. The measured one is the dependent variable. ✓
Method. Recall the use of a line graph.
- Recall. A line graph joins points to show how a value changes over time.change over time
- Write the answer. change over time
Check. A bar chart shows separate groups instead. ✓
Variables and fair tests
In a practical, the independent variable is the one you change on purpose. The dependent variable is the one you measure to see its effect. A control variable is any other factor that could change the result, so it is kept the same. A test is fair when only the independent variable is changed.
A testable hypothesis is a prediction that can be checked by measuring or counting. “Pondweed looks nice” cannot be tested. “More light gives more bubbles” can be tested.
| Type of variable | In the pondweed test |
|---|---|
| Independent (changed on purpose) | distance from the lamp (cm) |
| Dependent (measured) | bubbles per minute |
| Control (kept the same) | type of pondweed, water temperature, length of the cut stem |
Key ideas
- The independent variable is changed on purpose.
- The dependent variable is measured to show the effect.
- Control variables are kept the same so the test is fair.
- Change only one variable at a time.
Method. Find the variable that is changed on purpose.
- Find the change. Ravi moves the lamp on purpose.moves the lamp
- Name the variable. The distance from the lamp is the variable being changed.distance from the lamp
- Write the answer. distance from the lamp
Check. The distance is set before each count. ✓
Method. Find the variable that is measured.
- Find the measurement. Ravi counts the bubbles, so the count is measured.counts the bubbles
- Name the variable. The number of bubbles per minute is the dependent variable.bubbles per minute
- Write the answer. bubbles per minute
Check. The bubbles depend on the distance from the lamp. ✓
Method. Find a factor that must stay the same.
- Think. A control variable stays the same for every reading.stays the same
- Name one. If the water temperature changed, the test would not be fair.water temperature
- Write the answer. Accept any one: type of pondweed, water temperature, or length of the cut stem.
Check. Keep each control the same for every distance. ✓
Watch out
Watch out: if Ravi moves the lamp and also changes the water temperature, he cannot say which change caused the result.
Exam tip
Exam tip. Name a variable in full, for example “distance from the lamp”, not just “distance”.
Try it (with your teacher). Set up pondweed in water under a lamp at two distances. Keep the pondweed type, the water and the time the same. Count the bubbles for one minute at each distance. Name the independent, dependent and control variables.
Exercise 1A Variables and fair tests
Method. Find the variable changed on purpose.
- Find it. The pupil changes the distance on purpose.changes the distance
- Name it. The distance from the lamp is the independent variable.distance from the lamp
- Write the answer. distance from the lamp
Check. Light intensity changes with the distance. ✓
Method. Find the variable that is measured.
- Find it. The pupil counts the bubbles each minute.counts the bubbles
- Name it. The number of bubbles per minute is the dependent variable.bubbles per minute
- Write the answer. bubbles per minute
Check. The count depends on the light. ✓
Method. Think about what must not change.
- Think. Each control variable must stay the same for every distance.stay the same
- Name one. So the type of pondweed is a control variable.type of pondweed
- Write the answer. Accept any one: type of pondweed, water temperature, or length of the cut stem.
Check. Only the distance should change. ✓
Method. Find the variable that is counted.
- Find it. The bubbles are counted at each temperature.bubbles are counted
- Name it. The number of bubbles is the dependent variable.number of bubbles
- Write the answer. number of bubbles
Check. The temperature is the independent variable. ✓
Method. Check whether each one can be measured.
- Check (a). Interesting cannot be counted or measured.cannot be measured
- Check (b). The number of bubbles can be counted for each light level.can be counted
- Decide. So the testable hypothesis is b.b
- Write the answer. b
Check. A testable hypothesis can be checked by measuring. ✓
Method. Count the variables that are changed.
- Count. Two variables are changed at once.two variables
- Decide. The change in bubbles cannot be linked to one cause, so the test is not fair.not fair
- Write the answer. The answer is no.no
- Write the answer. no
Check. Change one variable at a time. ✓
Method. Look for the factors that do not change.
- Look. The number of seeds, the water and the light all stay the same.all stay the same
- Name one. So the amount of water is a control variable.amount of water
- Write the answer. Accept any one: number of seeds, amount of water, or light.
Check. Only the temperature is changed. ✓
Method. The independent variable goes on the x-axis.
- Identify. Time is changed by the pupil as the weeks pass, so it is the independent variable.independent variable
- Place it. The independent variable goes on the x-axis.x-axis
- Write the answer. time
Check. Height is the dependent variable on the y-axis. ✓
Method. State the change and the effect.
- Name the change. The light intensity is the independent variable.light intensity
- Name the effect. The number of bubbles is the dependent variable.number of bubbles
- Combine. So the hypothesis links the two.links the two
- Write the answer. Accept any sentence that says more light gives more bubbles, or less light gives fewer bubbles.
Check. A hypothesis can be checked by counting the bubbles. ✓
Method. Think about what one result can show.
- Think. One test shows a pattern in that test only.that test only
- Consider. Other factors or chance could also explain the pattern.other factors or chance
- Conclude. So more controlled tests are needed before a cause is claimed.more controlled tests
- Write the answer. Accept any sentence that says the result shows a link, but other factors or chance could also explain it, so more controlled tests are needed.
Check. A cause needs a fair test that is repeated. ✓
Risk assessment and safe practice
A hazard is something that could cause harm. The risk is the chance that the harm happens, and how serious it could be. A control measure is an action that reduces the risk. A risk assessment lists the hazards, the risks and the control measures before any practical starts.
Pupils use only safe living material, such as pondweed, bean plants and prepared slides. Microorganisms are handled only under the school’s microbiology rules, and some are used by the teacher as a demonstration only. Anything involving a flame, hot water or electricity is controlled by the teacher.
| Activity | Hazard | Risk | Control measure |
|---|---|---|---|
| Heating water in a beaker for a teacher demonstration | hot water and a flame | burns and scalds | the teacher lights and controls the burner; tie back hair; use a heatproof mat |
| Looking at prepared slides with a microscope | a glass slide and the lamp | cut fingers; hot lamp | handle slides by their edges; switch the lamp off when finished |
| Testing pondweed under a lamp | an electrical lamp near water | electric shock | keep the lamp dry and at a safe distance; a teacher checks the set-up |
| Testing starch with iodine solution | iodine stains skin and clothes and is harmful if swallowed | stained clothes; skin irritation | wear eye protection and an apron; wipe up spills at once |
Key ideas
- A hazard could cause harm; a risk is the chance and seriousness of harm.
- A control measure reduces a named risk.
- Use only safe living material, such as pondweed and bean plants.
- Keep electricity, flames and hot water under teacher control.
Method. Find what could cause harm.
- Look at the set-up. Hot water and a flame can cause burns.hot water and a flame
- Name it. The hazard is the hot water and the flame.hot water and a flame
- Write the answer. hot water and a flame
Check. The hazard is the thing that could cause harm. ✓
Method. Think about the harm that could happen.
- Think. Touching the hot beaker or the flame could hurt a person.could hurt a person
- Name it. So the risk is burns and scalds.burns and scalds
- Write the answer. burns and scalds
Check. A risk is the chance of harm and how serious it could be. ✓
Method. Choose an action that reduces the risk.
- Think. An action that reduces burns is a control measure.reduces burns
- Name one. A teacher who lights and controls the burner reduces the risk.teacher lights
- Write the answer. Accept any one: a teacher lights and controls the burner, or tie back long hair.
Check. Each control measure must match a named risk. ✓
Watch out
Watch out: a risk is not the same as a hazard. “The beaker is hot” is a hazard. “Burns and scalds” is the risk.
Exam tip
Exam tip. A control measure must match the risk. “Be careful” does not name an action, so it does not earn the mark on its own.
Try it (with your teacher). With your teacher, write a risk assessment for looking at prepared slides under a microscope. Make columns for the activity, hazard, risk and control measure. Check that every control measure reduces a named risk.
Exercise 1B Risk assessment and safe practice
Method. Recall the definition.
- Recall. A hazard is something that could cause harm.could cause harm
- Write the answer. something that could cause harm
Check. A hazard is not yet a harm. ✓
Method. Recall the definition.
- Recall. A risk is the chance that harm happens, and how serious it could be.chance of harm
- Write the answer. the chance of harm and how serious it could be
Check. Risk includes both chance and seriousness. ✓
Method. Think about the harm a broken slide could do.
- Think. Broken glass can cut the skin.cut the skin
- Name it. So the risk is cut fingers.cut fingers
- Write the answer. cut fingers
Check. The slide is the hazard; the cut is the risk. ✓
Method. A control measure is an action that reduces the risk.
- Check (a). A statement of the hazard is not an action.not an action
- Check (b). Handling by the edges reduces the risk of cuts.reduces the risk
- Decide. So the control measure is b.b
- Write the answer. b
Check. A control measure is something you do. ✓
Method. Name the hazard, then the risk.
- Hazard. A lamp near water is an electrical hazard.electrical hazard
- Risk. The risk is an electric shock.electric shock
- Conclude. So the teacher checks the set-up before the lesson.checks the set-up
- Write the answer. Accept any sentence that says the lamp near water could cause an electric shock, so the set-up must be checked.
Check. Keep the lamp dry and at a safe distance. ✓
Method. Choose the material that is known and safe.
- Check (a). Pondweed is a safe living material for a school practical.safe living material
- Check (b). An unknown mould could be harmful and is not allowed.not allowed
- Decide. So the safe choice is a.a
- Write the answer. a
Check. Only known, safe material is used by pupils. ✓
Method. Choose an action that stops the lamp from being hot when touched.
- Think. A lamp cools when it is switched off.cools when off
- Name it. So switching the lamp off between readings is the control measure.switch the lamp off
- Write the answer. switch the lamp off between readings
Check. The control reduces the risk of burns. ✓
Method. Match the action to the risk.
- Look at the risk. Iodine can stain clothes.stain clothes
- Choose. An apron covers the clothes so they are not stained.covers the clothes
- Name it. So wearing an apron is the control measure.wear an apron
- Write the answer. wear an apron
Check. Eye protection controls a different risk. ✓
Method. Think about what a control measure must do.
- Think. A control measure must be an action that reduces a named risk.reduces a named risk
- Check. Being careful does not name an action, so it cannot be checked.cannot be checked
- Conclude. A specific action, such as eye protection and an apron, is needed.eye protection
- Write the answer. Accept any sentence that says it names no specific action to reduce a named risk, such as wearing an apron and eye protection.
Check. A good control measure can be carried out and checked. ✓
Method. Fill in the three columns that match.
- Hazard. The lamp is electrical and it is near water.electrical and near water
- Risk. The risk is an electric shock.electric shock
- Control. Keeping the lamp dry and at a safe distance reduces the risk.keep the lamp dry
- Write the answer. Accept any row that names an electrical hazard, electric shock as the risk, and a named action such as keeping the lamp dry.
Check. Each column matches the one before it. ✓
Means, anomalies, precision and accuracy
The mean is the total of the results divided by the number of results. Repeat each reading several times to find a mean that you can trust. An anomaly is a result that does not fit the pattern of the others. An anomaly is left out of the mean only when there is a clear reason, such as a measuring mistake, and the reason is written down.
Precision is how close repeat results are to each other. Accuracy is how close a result is to the true value. A reliable result is one that gives the same answer when repeated, and that other people can also get using the same method.
| Repeat | Bubbles per minute at 20 cm |
|---|---|
| 1 | 14 |
| 2 | 16 |
| 3 | 15 |
| 4 | 24 |
Key ideas
- Mean = total of the results divided by the number of results.
- An anomaly is left out only with a stated reason.
- Precision is closeness of repeats; accuracy is closeness to the true value.
- Uncertainty for a scale reading is half the smallest division.
Method. Add the results, then divide by the number of results.
- Add. Add the four counts: 14 + 16 + 15 + 24 = 69.14 + 16 + 15 + 24 = 69
- Divide. Divide the total by 4, the number of counts.69 / 4 = 17.25
- Write the answer. 17.25
Check. 17.25 x 4 = 69. ✓
Method. Remove the anomaly, then find the mean of the rest.
- Remove. The count of 24 does not fit the pattern. Leave it out only because a reason is recorded, for example a counting mistake.remove 24
- Add. Add the three remaining counts: 14 + 16 + 15 = 45.14 + 16 + 15 = 45
- Divide. Divide by 3.45 / 3 = 15
- Write the answer. 15
Check. 15 x 3 = 45. ✓
Method. Compare the spread with the distance from the true value.
- Spread. The readings are close together, so they are precise.close together
- Distance. They are far from the true value, so they are not accurate.far from the true value
- Conclude. The result is precise but not accurate.precise but not accurate
- Write the answer. precise but not accurate
Check. Precision and accuracy are separate ideas. ✓
Watch out
Watch out: do not remove a result just because it is high. Remove an anomaly only when you have a clear reason, and say what the reason is.
Exam tip
Exam tip. A mean can be a decimal. Leave it as a decimal rather than rounding it to a whole number.
Try it (with your teacher). With your teacher, count the bubbles from pondweed for one minute, three times, at one distance. Work out the mean. Look for an anomaly and decide whether there is a reason to leave it out.
Exercise 1C Means, anomalies, precision and accuracy
Method. Add the three numbers.
- Add. Add the numbers: 5 + 7 + 9 = 21.5 + 7 + 9 = 21
- Write the answer. 21
Check. 21 divided by 3 is 7. ✓
Method. Divide the total by how many numbers there are.
- Add. The total is 21.21
- Divide. Divide 21 by 3.21 / 3 = 7
- Write the answer. 7
Check. 7 x 3 = 21. ✓
Method. Add, then divide by 4.
- Add. 12 + 15 + 18 + 21 = 66.66
- Divide. Divide 66 by 4.66 / 4 = 16.5
- Write the answer. 16.5
Check. 16.5 x 4 = 66. ✓
Method. Add the readings, then divide by 3.
- Add. 0.31 + 0.29 + 0.30 = 0.90.0.90
- Divide. Divide 0.90 by 3.0.9 / 3 = 0.3
- Write the answer. 0.3
Check. 0.3 x 3 = 0.9. ✓
Method. Look for the value that does not fit the others.
- Look. The counts 14, 16 and 15 are close together.close together
- Identify. The count of 24 is far above the others, so it is the anomaly.24
- Write the answer. 24
Check. Check whether there is a reason for the result. ✓
Method. Add the three remaining counts, then divide by 3.
- Add. 14 + 16 + 15 = 45.45
- Divide. Divide 45 by 3.45 / 3 = 15
- Write the answer. 15
Check. 15 x 3 = 45. ✓
Method. The range is the largest value minus the smallest.
- Find the largest. The largest value is 10.10
- Find the smallest. The smallest value is 8.8
- Subtract. Subtract the smallest from the largest.10 - 8 = 2
- Write the answer. 2
Check. 8 + 2 = 10. ✓
Method. Recall the two definitions.
- Check (a). Precision is how close repeats are to each other.close to each other
- Check (b). Closeness to the true value is accuracy, not precision.accuracy
- Decide. So precision is described by a.a
- Write the answer. a
Check. Accuracy is the other definition. ✓
Method. Recall the two definitions.
- Check (a). Closeness of repeats is precision.precision
- Check (b). Closeness to the true value is accuracy.accuracy
- Decide. So accuracy is described by b.b
- Write the answer. b
Check. Precision is the other definition. ✓
Method. Uncertainty is half the smallest division.
- Find the smallest division. The smallest division is 1 mm.1 mm
- Halve it. Half of 1 mm is 0.5 mm.1 / 2 = 0.5
- Write the answer. 0.5
Check. A reading of 20 mm would lie between 19.5 mm and 20.5 mm. ✓
Method. Add, then divide by 3.
- Add. 20 + 22 + 24 = 66.66
- Divide. Divide 66 by 3.66 / 3 = 22
- Write the answer. 22
Check. 22 x 3 = 66. ✓
Method. Check the rule for anomalies.
- Rule. An anomaly is left out only with a stated reason.stated reason
- Calculate. Without removing it, the mean of all four counts is 17.25.17.25
- Conclude. So the statement is wrong unless a reason for removing the 24 is given.unless a reason
- Write the answer. Accept any sentence that says the anomaly is left out only with a stated reason, so the mean of all four counts is 17.25.
Check. Removing results without a reason changes the answer unfairly. ✓
Units, standard form and percentage change
Biology uses the metre and its smaller units. Each step in the length units is a multiplication or division by 10 or 1000. Standard form writes a number as a number between 1 and 10, multiplied by a power of 10, for example 4500 = 4.5 x 103. A percentage change is the change divided by the original value, multiplied by 100.
Percentage change = (change / original value) x 100.
| Unit | Equal to |
|---|---|
| 1 cm | 10 mm |
| 1 m | 100 cm |
| 1 m | 1000 mm |
| 1 mm | 0.001 m |
Key ideas
- 1 cm = 10 mm; 1 m = 100 cm = 1000 mm.
- Standard form: a number between 1 and 10, times a power of 10.
- Percentage change = change / original value x 100.
- Always write the unit in the answer.
Method. Use 1 cm = 10 mm, so multiply by 10.
- Multiply. Each centimetre is ten millimetres, so multiply by 10.2.5 x 10
- Calculate. Multiply 2.5 by 10 to get the number of millimetres.2.5 x 10 = 25
- Write the answer. 25
Check. 25 mm divided by 10 is 2.5 cm. ✓
Method. Move the decimal point to make a number between 1 and 10, and count the places moved.
- Place the point. Move the point to make 4.5, which is between 1 and 10.4.5
- Count the places. The point moved three places to the left, so the power is 3.3 places
- Write it. So 4500 = 4.5 x 103.4.5 x 103
- Write the answer. 4.5 x 103
Check. 4.5 x 1000 = 4500. ✓
Method. Find the change, then divide by the original value and multiply by 100.
- Find the change. The change is 15 - 12 = 3 cm.15 - 12 = 3
- Divide. Divide the change by the original value, 12.3 / 12 = 0.25
- Multiply. Multiply by 100 to give a percentage.0.25 x 100 = 25
- Write the answer. 25%
Check. 25% of 12 is 3, so 12 + 3 = 15. ✓
Watch out
Watch out: 1 cm is 10 mm, not 100 mm. For percentage change, divide by the original value, not the new value.
Exam tip
Exam tip. Write the unit with your answer, for example “25 mm”, so the marker can see it is correct.
Try it (with your teacher). With your teacher, measure one bean leaf in millimetres. Convert the length to centimetres and check the answer using 1 cm = 10 mm. Then measure it again the next day and work out the percentage change.
Exercise 1D Units, standard form and percentage change
Method. One centimetre is ten millimetres.
- Multiply. Multiply 3 by 10.3 x 10 = 30
- Write the answer. 30
Check. 30 divided by 10 is 3 cm. ✓
Method. One metre is 1000 millimetres, so divide by 1000.
- Divide. Divide 5000 by 1000.5000 / 1000 = 5
- Write the answer. 5
Check. 5 x 1000 = 5000. ✓
Method. One metre is 100 centimetres.
- Multiply. Multiply 2 by 100.2 x 100 = 200
- Write the answer. 200
Check. 200 divided by 100 is 2 m. ✓
Method. One metre is 100 centimetres.
- Multiply. Multiply 0.5 by 100.0.5 x 100 = 50
- Write the answer. 50
Check. 50 divided by 100 is 0.5 m. ✓
Method. Make a number between 1 and 10, then count the places moved.
- Place the point. Move the point to make 6.6
- Count the places. The point moved three places, so the power is 3.3 places
- Write the answer. 6 x 10^3
Check. 6 x 1000 = 6000. ✓
Method. Move the point to the right to make a number between 1 and 10.
- Place the point. Move the point two places to the right to make 4.4
- Give the power. Moving right makes the power negative, so the power is -2.power -2
- Write the answer. 4 x 10^-2
Check. 4 divided by 100 is 0.04. ✓
Method. Multiply 2 by 10 three times, or move the point three places.
- Multiply. 2 x 10 x 10 x 10 = 2000.2 x 1000
- Write it. So 2 x 10^3 = 2000.2000
- Write the answer. 2000
Check. 2000 divided by 1000 is 2. ✓
Method. A negative power divides by 10.
- Divide. 3 divided by 10 is 0.3.3 / 10 = 0.3
- Write the answer. 0.3
Check. 0.3 x 10 = 3. ✓
Method. Change divided by the original value, times 100.
- Change. The change is 50 - 40 = 10 mm.10
- Divide. Divide by the original value, 40.10 / 40 = 0.25
- Multiply. Multiply by 100.0.25 x 100 = 25
- Write the answer. 25%
Check. 25% of 40 is 10. ✓
Method. The change is a decrease, so give the size and the word decrease.
- Change. The change is 80 - 60 = 20 mm.20
- Divide. Divide by the original value, 80.20 / 80 = 0.25
- Multiply. Multiply by 100.0.25 x 100 = 25
- Write the answer. 25% decrease
Check. The leaf got smaller, so it is a decrease. ✓
Method. Multiply by 10 to change centimetres into millimetres.
- Multiply. Each centimetre is 10 mm, so multiply 6 by 10.6 x 10 = 60
- Write the answer. 60
Check. 60 divided by 10 is 6 cm. ✓
Method. Change divided by the original value, times 100.
- Change. The change is 165 - 150 = 15 mm.15
- Divide. Divide by the original value, 150.15 / 150 = 0.1
- Multiply. Multiply by 100.0.1 x 100 = 10
- Write the answer. 10%
Check. 10% of 150 is 15. ✓
Method. Check whether the number before the power of 10 is between 1 and 10.
- Check. The number before the power is 45, which is not between 1 and 10.45 is not between 1 and 10
- Correct it. The correct form is 4.5 x 103.4.5 x 103
- Decide. So Ali is not correct.not correct
- Write the answer. no
Check. 45 x 100 = 4500, but standard form needs 4.5 x 1000. ✓
Method. Write the first part, then give the reason.
- Standard form. Move the point two places to the right to make 2, so the power is -2.2 x 10^-2
- Reason. Standard form avoids long strings of zeros and makes sizes easy to compare.avoids long strings of zeros
- Write the answer. Accept any answer that gives 2 x 10^-2 mm and a sentence saying it avoids long strings of zeros.
Check. 2 divided by 100 is 0.02. ✓
Tables, graphs and conclusions
Choose the graph type from the data. A bar chart shows separate groups or categories. A line graph joins points to show how a value changes, usually over time or over a range of a variable. A scatter graph shows two linked numbers as separate points.
Put the independent variable on the x-axis, label both axes with units, and choose a scale that uses most of the grid. A conclusion says what the data show, how the data support the idea, and how far the test can be trusted.
Key ideas
- Bar chart: separate groups. Line graph: change over a range. Scatter graph: two linked numbers.
- Independent variable on the x-axis; dependent variable on the y-axis.
- A conclusion matches the data and says how far it is supported.
- An evaluation names a weakness and a specific improvement.
Method. Find 20 on the x-axis, go up to the line, then read across to the y-axis.
- Find 20. Find 20 cm on the x-axis.20 cm
- Read across. The point at 20 cm is at 15 on the y-axis.point at 15
- Write the answer. 15
Check. This matches the mean of the three counts from earlier. ✓
Method. Describe the change in y as x increases.
- Look at the trend. As the distance increases, the points go down.points go down
- Describe it. So the number of bubbles falls as the distance increases.falls as the distance increases
- Write the answer. Accept any sentence that says the number of bubbles falls as the distance from the lamp increases.
Check. The pattern uses the values: 40 at 10 cm, down to 5 at 40 cm. ✓
Method. Find the height at each week, then subtract.
- Read week 1. The plant is 6 cm tall at week 1.6 cm
- Read week 3. The plant is 11 cm tall at week 3.11 cm
- Subtract. The change is 11 - 6 = 5 cm.11 - 6 = 5
- Write the answer. 5
Check. 6 + 5 = 11. ✓
Watch out
Watch out: the x-axis carries the independent variable and the y-axis the dependent variable. A conclusion that says “light causes” needs more than one test.
Exam tip
Exam tip. A conclusion should use the data values, for example “5 bubbles at 40 cm and 40 at 10 cm”, not only the words “it went down”.
Try it (with your teacher). With your teacher, plot a line graph of the mean number of bubbles against distance, with the distance on the x-axis. Describe the pattern, and write one improvement to the test.
Exercise 1E Tables, graphs and conclusions
Method. The dependent variable goes on the y-axis.
- Identify. The bubbles per minute are measured, so they are the dependent variable.dependent variable
- Place it. The dependent variable goes on the y-axis.y-axis
- Write the answer. bubbles per minute
Check. Distance goes on the x-axis. ✓
Method. Recall which graph shows groups or categories.
- Recall. A bar chart shows separate categories or groups.separate categories
- Write the answer. bar chart
Check. A line graph joins points over a range. ✓
Method. Recall which graph joins points.
- Recall. A line graph joins points to show change over a range.change over a range
- Write the answer. line graph
Check. A scatter graph does not join its points. ✓
Method. Recall the graph for two linked numbers.
- Recall. A scatter graph shows two linked values as separate points.separate points
- Write the answer. scatter graph
Check. A line graph joins the points. ✓
Method. Find 10 on the x-axis, then read the y-value.
- Find 10. Find 10 cm on the x-axis.10 cm
- Read. The point is at 40 bubbles per minute.40
- Write the answer. 40
Check. The graph falls from 40 to 5. ✓
Method. Find 30 on the x-axis, then read the y-value.
- Find 30. Find 30 cm on the x-axis.30 cm
- Read. The point is at 9 bubbles per minute.9
- Write the answer. 9
Check. 9 is between 15 and 5. ✓
Method. Find week 4 on the x-axis, then read the height.
- Find week 4. Find week 4 on the x-axis.week 4
- Read. The height at week 4 is 12 cm.12 cm
- Write the answer. 12
Check. The plant grows each week. ✓
Method. Read both heights, then subtract.
- Read week 0. The plant is 4 cm at week 0.4 cm
- Read week 2. The plant is 9 cm at week 2.9 cm
- Subtract. The change is 9 - 4 = 5 cm.9 - 4 = 5
- Write the answer. 5
Check. 4 + 5 = 9. ✓
Method. Read both values, then compare.
- Read 40 cm. At 40 cm the mean is 5 bubbles per minute.5
- Read 10 cm. At 10 cm the mean is 40 bubbles per minute.40
- Compare. 5 is fewer than 40.fewer
- Write the answer. fewer
Check. More light gives more bubbles. ✓
Method. Check how the y-values change as x increases.
- Look. The points go down as the distance increases.go down
- Choose the word. So the number of bubbles decreases.decreases
- Write the answer. decreases
Check. The word must match the trend. ✓
Method. Think about the weakness of the method.
- Find a weakness. Only a few repeats were taken at each distance.few repeats
- Improve it. Taking more repeats makes the mean more reliable.more reliable
- Write the answer. Accept any sensible improvement, for example more repeats at each distance, or counting for a longer time.
Check. The improvement should match a named weakness. ✓
Method. Check what one set of data can show.
- Check. The data show a link, but they do not prove a cause on their own.link
- Decide. So Ravi’s claim goes too far.goes too far
- Write the answer. The answer is no.no
- Write the answer. no
Check. Other factors must be controlled before a cause is claimed. ✓
Method. Use the data, then say how far it supports the idea.
- Data. The mean falls from 40 bubbles per minute at 10 cm to 5 at 40 cm.40 and 5
- Support. The data support the idea that light affects bubbles.supports the idea
- Limit. More controlled tests would confirm it.more controlled tests
- Write the answer. Accept any sentence that uses data such as 40 and 5 bubbles per minute and says the result supports the idea, but more controlled tests would confirm it.
Check. A conclusion needs the data and its limits. ✓
Chapter summary
| Skill | Method |
|---|---|
| Fair test | Change only the independent variable; measure the dependent variable; keep the control variables the same. |
| Risk | Hazard (what could cause harm), risk (chance and seriousness), control measure (reduces the risk). |
| Mean and anomaly | Total divided by the number of results; leave out an anomaly only with a stated reason. |
| Precision and accuracy | Precision: repeats close together. Accuracy: close to the true value. |
| Units | 1 cm = 10 mm; 1 m = 100 cm = 1000 mm; standard form is a number from 1 to 10 times a power of 10. |
| Percentage change | Change divided by the original value, times 100. |
| Graphs | Bar chart for groups; line graph for change; scatter graph for two linked numbers. |
Can you…?
- I can name the independent, dependent and control variables in a practical
- I can write a risk assessment with a hazard, a risk and a control measure
- I can calculate a mean and explain when an anomaly may be left out
- I can explain precision, accuracy and reliability
- I can convert units, write numbers in standard form and calculate a percentage change
- I can read a graph, describe a pattern and evaluate a conclusion
Key terms
- independent variable
- the variable that is changed on purpose
- dependent variable
- the variable that is measured to show the effect
- control variable
- a variable that is kept the same so the test is fair
- hazard
- something that could cause harm
- risk
- the chance that harm happens, and how serious it could be
- control measure
- an action that reduces a named risk
- anomaly
- a result that does not fit the pattern of the others
- precision
- how close repeat results are to each other
- accuracy
- how close a result is to the true value
- standard form
- a number from 1 to 10 multiplied by a power of 10
- percentage change
- the change divided by the original value, multiplied by 100
Exercise 1Z Check-up
Method. Find the variable that is measured.
- Find it. The number of bubbles is counted.counted
- Name it. So bubbles per minute is the dependent variable.bubbles per minute
- Write the answer. bubbles per minute
Check. The lamp distance is the independent variable. ✓
Method. Add, then divide by 3.
- Add. 10 + 12 + 14 = 36.36
- Divide. Divide 36 by 3.36 / 3 = 12
- Write the answer. 12
Check. 12 x 3 = 36. ✓
Method. A hazard is what could cause harm.
- Check (a). Hot water and a flame are the things that could cause harm.could cause harm
- Check (b). Burns and scalds are the risk, not the hazard.the risk
- Decide. So the hazard is a.a
- Write the answer. a
Check. The risk is the harm that could happen. ✓
Method. Look for the value that does not fit the others.
- Look. The counts 8, 9 and 9 are close together.close together
- Identify. The count of 20 is far from the others.20
- Write the answer. 20
Check. Only leave it out with a reason. ✓
Method. One metre is 100 centimetres.
- Multiply. Multiply 4 by 100.4 x 100 = 400
- Write the answer. 400
Check. 400 divided by 100 is 4. ✓
Method. Make a number between 1 and 10, then count the places.
- Place the point. Move the point to make 7.7
- Count the places. Three places, so the power is 3.3 places
- Write the answer. 7 x 10^3
Check. 7 x 1000 = 7000. ✓
Method. Change divided by the original value, times 100.
- Change. The change is 26 - 20 = 6 cm.6
- Divide. Divide by 20.6 / 20 = 0.3
- Multiply. Multiply by 100.0.3 x 100 = 30
- Write the answer. 30%
Check. 30% of 20 is 6. ✓
Method. Four separate plants form separate groups.
- Think. Each plant is a separate category, so the data are grouped.separate categories
- Choose. A bar chart shows separate groups.bar chart
- Write the answer. bar chart
Check. A line graph would join the plants wrongly. ✓
Method. Choose an action that reduces burns.
- Think. A cooling lamp is safer to touch.cooling
- Name one. Switching it off between readings lets it cool.switch it off
- Write the answer. Accept any one: switch it off between readings, or let it cool.
Check. The control must reduce the named risk. ✓
Method. Think about what else could change the result.
- Think. Other factors could change the dependent variable.change the dependent variable
- Conclude. So only the independent variable should change.only the independent variable
- Write the answer. Accept any sentence that says other factors could change the result, so only the independent variable should change.
Check. A fair test links one cause to one effect. ✓
Total 19 marks. Allow about 19 minutes.
Exercise 1X Exam-style questions
Method. Find the variable changed on purpose.
- Find it. The length of the wire is changed on purpose.length of the wire
- Write the answer. length of the wire
Check. Resistance is the dependent variable. ✓
Method. Add, then divide by 3.
- Add. 5 + 7 + 9 = 21.21
- Divide. Divide 21 by 3.21 / 3 = 7
- Write the answer. 7
Check. 7 x 3 = 21. ✓
Method. Find the variable changed on purpose.
- Find it. The temperature of the water is changed by the pupil.temperature of the water
- Write the answer. temperature of the water
Check. The bubbles are the dependent variable. ✓
Method. Name the hazard, then a control that reduces its risk.
- Hazard. The hot water could scald the skin.scald the skin
- Control. Keeping the water bath away from the edge of the bench reduces the risk.away from the edge
- Write the answer. Accept any sensible pair, for example hot water and keeping the water bath away from edges.
Check. The control reduces the risk of a spill. ✓
Method. One kilometre is 1000 metres.
- Multiply. Multiply 1.2 by 1000.1.2 x 1000 = 1200
- Write the answer. 1200
Check. 1200 divided by 1000 is 1.2. ✓
Method. Add, then divide by 3.
- Add. 0.22 + 0.26 + 0.28 = 0.76.0.76
- Divide. Divide 0.76 by 3.0.76 / 3 = 0.25
- Write the answer. 0.25
Check. 0.25 x 3 = 0.75, which is close to 0.76. ✓
Method. Change divided by the original value, times 100.
- Change. The change is 46 - 40 = 6 mm.6
- Divide. Divide by 40.6 / 40 = 0.15
- Multiply. Multiply by 100.0.15 x 100 = 15
- Write the answer. 15%
Check. 15% of 40 is 6. ✓
Method. Look at how the values change as the distance increases.
- Look. The values go from 40 down to 5.from 40 down to 5
- Describe. So the number of bubbles falls as the distance increases.falls as the distance increases
- Write the answer. Accept any sentence that says the number of bubbles falls as the distance increases.
Check. The pattern uses the data values. ✓
Method. Check whether the value fits the pattern, then apply the rule.
- Pattern. The values 20 and 22 are close, but 35 is far above them.far above
- Rule. An anomaly is left out only with a stated reason, such as a measuring mistake.stated reason
- Conclude. Without a reason, 35 mm should stay in the mean.stay in the mean
- Write the answer. Accept any answer that says it should only be left out with a stated reason, and that the mean is not changed unfairly without one.
Check. Repeat the reading if a mistake is suspected. ✓
Method. Separate precision from accuracy.
- Precision. Close repeats show that the readings are precise.precise
- Accuracy. Accuracy needs the readings to be close to the true value.true value
- Conclude. So close repeats alone do not show the results are accurate.do not show accurate
- Write the answer. Accept any sentence that says close repeats show precision, not accuracy, because accuracy needs closeness to the true value.
Check. A systematic error can make repeats precise but wrong. ✓