Radioactivity, nuclear equations and half-life
By the end of this chapter you will be able to
- Compare alpha, beta and gamma radiation in a table
- Complete a nuclear equation for an alpha or beta decay
- Find the half-life from a graph of count rate against time
- Calculate the count after a number of half-lives, and correct a count for background
- Choose a suitable source for a use, and explain how radiation is kept safe
You should already know
- Nuclide notation and isotopes (Chapter 10)
- Standard form and powers of ten (KS3 Maths)
Where this leads
- Nuclear fission and fusion (Chapter 12)
- Energy resources (Chapter 4)
GCSE Physics. Content follows the GCSE (9-1) subject content for England (Edexcel and AQA). Content references: Describe alpha, beta and gamma radiation: their nature, charge, penetration and ionising power, Write nuclear equations for alpha and beta-minus decay, and state the change in mass and atomic number for gamma, Explain that radioactive decay is random and unstable nuclei decay; define activity in becquerels, Define half-life, and find it from a graph and from count data; correct count rates for background radiation, Describe uses and dangers of radiation (medical, tracers, dating) and how risks are reduced.
Exercise P Do you remember?
Method. Halve the number.
- Divide. 800 / 2 = 400.800 / 2 = 400
- Write the answer. 400
Check. ✓
Method. An alpha particle is two protons and two neutrons.
- Recall. 2 protons + 2 neutrons = 4.2 + 2 = 4
- Write the answer. 4
Check. ✓
Method. Recall the beta particle.
- Recall. A beta-minus particle is an electron.electron
- Write the answer. electron
Check. ✓
Method. Divide.
- Divide. 1200 / 4 = 300.1200 / 4 = 300
- Write the answer. 300
Check. ✓
Method. Convert to the same unit.
- Convert. 1 hour = 60 minutes, which is more than 5 minutes or 50 seconds.60 minutes
- Write the answer. hour
Check. ✓
Alpha, beta and gamma radiation
Some nuclei are unstable. They give out radiation to become more stable. This is called radioactive decay. There are three main types:
- Alpha (α): two protons and two neutrons, a helium nucleus. It has a charge of +2 and is stopped by paper or a few centimetres of air. It is strongly ionising.
- Beta (β-): a fast electron from the nucleus. It has a charge of -1, is stopped by a few millimetres of aluminium, and is moderately ionising.
- Gamma (γ): electromagnetic waves with no mass and no charge. It needs thick lead or concrete to reduce it, and is weakly ionising.
| Radiation | What it is | Charge | Penetration | Ionising power |
|---|---|---|---|---|
| alpha (α) | two protons and two neutrons | +2 | stopped by paper or a few cm of air | strong |
| beta (β-) | a fast electron from the nucleus | -1 | stopped by about 3 mm of aluminium | moderate |
| gamma (γ) | electromagnetic waves from the nucleus | 0 | needs thick lead or concrete | weak |
Key ideas
- Alpha: +2 charge, stopped by paper, strongly ionising.
- Beta: -1 charge, stopped by aluminium, moderately ionising.
- Gamma: no charge, needs thick lead or concrete, weakly ionising.
- Ionising power: how much a radiation knocks electrons out of atoms.
Method. Compare the penetration of each type.
- Look. Alpha is the least penetrating, stopped by paper or a few centimetres of air.least penetrating
- Decide. So alpha is the type stopped by paper.alpha
- Write the answer. alpha
Check. ✓
Method. Compare the penetration.
- Look. Gamma is the most penetrating type.most penetrating
- Decide. So gamma needs thick lead or concrete.gamma
- Write the answer. gamma
Check. ✓
Method. Recall the beta particle.
- Recall. A beta-minus particle is an electron, with charge -1.-1
- Decide. So it is negative.negative
- Write the answer. negative
Check. ✓
Watch out
Watch out: beta-minus is an electron from the nucleus, not one of the orbiting electrons. It is a fast particle with negative charge.
Exam tip
Exam tip. When asked which radiation is most ionising, pick alpha. When asked which penetrates most, pick gamma.
Exercise 11A Types of radiation
Method. Recall the particle.
- Recall. An alpha particle is a helium nucleus, two protons and two neutrons.alpha
- Write the answer. alpha
Check. ✓
Method. Recall the particle.
- Recall. A beta particle is a fast electron from the nucleus.beta
- Write the answer. beta
Check. ✓
Method. Recall the uncharged radiation.
- Recall. Gamma radiation is electromagnetic waves, with no charge.gamma
- Write the answer. gamma
Check. ✓
Method. Recall the charge.
- Recall. An alpha particle has a charge of +2.+2
- Write the answer. +2
Check. ✓
Method. Recall the charge.
- Recall. A beta-minus particle has a charge of -1.-1
- Write the answer. -1
Check. ✓
Method. Recall the penetration.
- Recall. Beta is stopped by about 3 mm of aluminium.beta
- Write the answer. beta
Check. ✓
Method. Recall the ionising power.
- Recall. Alpha is the most ionising because it is heavy and highly charged.alpha
- Write the answer. alpha
Check. ✓
Method. Recall the penetration.
- Recall. Gamma is the most penetrating type.gamma
- Write the answer. gamma
Check. ✓
Method. Charged particles are deflected; gamma has no charge.
- Charge. Alpha has +2 and beta has -1, so both are deflected.charged
- Gamma. Gamma has no charge, so it is not deflected.not deflected
- Write the answer. alpha, beta
Check. ✓
Method. Think about the particle and the charge.
- Alpha. Alpha is heavy and has a charge of +2.heavy, charged
- Link. It knocks electrons out of atoms easily, so it is more ionising.ionising
- Write the answer. Accept any sentence that says alpha is heavy and highly charged, so it knocks electrons out of atoms more easily.
Check. ✓
Method. Compare ionising and penetration.
- Ionising. Gamma is weakly ionising, so it is less damaging per particle.weak
- Penetration. It penetrates the body, which is why it is a hazard from outside.penetrates
- Write the answer. Accept any answer that says gamma is weakly ionising, but it penetrates the body, so it is dangerous from outside.
Check. ✓
Method. Match each barrier to the least penetrating radiation.
- Paper. Paper stops alpha.alpha
- Aluminium. Aluminium stops beta.beta
- Write the answer. alpha, beta
Check. ✓
Method. Recall the wave.
- Recall. Gamma radiation is an electromagnetic wave.gamma
- Write the answer. gamma
Check. ✓
Method. Compare each type.
- Check. Only alpha is stopped by paper.alpha
- Write the answer. alpha
Check. ✓
Nuclear equations and random decay
A nuclear equation shows what happens in a decay. The mass number (top) and the atomic number (bottom) must balance on each side.
- Alpha decay: the mass number goes down by 4 and the atomic number goes down by 2. Example: 23892U → 23490Th + 42He.
- Beta-minus decay: a neutron changes into a proton and an electron. The mass number stays the same and the atomic number goes up by 1. Example: 146C → 147N + 0-1e.
- Gamma: the mass number and atomic number do not change; energy is released as a wave.
Radioactive decay is random: we cannot say when a particular nucleus will decay, only how many will decay in a large sample in a given time.
| Decay | Change in mass number | Change in atomic number | Particle emitted |
|---|---|---|---|
| alpha | goes down by 4 | goes down by 2 | helium nucleus, ^4_2He |
| beta-minus | stays the same | goes up by 1 | electron, ^0_-1e |
| gamma | stays the same | stays the same | electromagnetic wave, no mass or charge |
Key ideas
- Balance the mass numbers on both sides, and the atomic numbers on both sides.
- Alpha: A - 4 and Z - 2.
- Beta-minus: A stays the same and Z + 1.
- Decay is random: we cannot predict the exact nucleus that will decay next.
Method. Subtract the alpha particle from the parent.
- Mass. Mass number = 222 - 4 = 218.222 - 4 = 218
- Atomic. Atomic number = 86 - 2 = 84.86 - 2 = 84
- Write the answer. 218, 84
Check. 218 + 4 = 222 and 84 + 2 = 86. ✓
Method. The mass number stays the same; the atomic number goes up by 1.
- Mass. Mass number stays 14.14
- Atomic. Atomic number = 6 + 1 = 7.6 + 1 = 7
- Write the answer. 14, 7
Check. 14 = 14 and 7 - 1 = 6. ✓
Method. Think about random decay.
- Look. Each nucleus decays at a random time.random
- Decide. So we cannot predict which one will decay next.no
- Write the answer. no
Check. ✓
Watch out
Watch out: in an equation, the sum of the top numbers (mass) and the sum of the bottom numbers (atomic) must be the same on both sides.
Exam tip
Exam tip. Write the parent on the left. Subtract 4 and 2 for alpha; keep the mass and add 1 to the atomic number for beta-minus.
Exercise 11B Nuclear equations
Method. Recall the rule.
- Recall. An alpha particle has a mass number of 4, so the parent loses 4.4
- Write the answer. 4
Check. ✓
Method. Recall the rule.
- Recall. An alpha particle has an atomic number of 2, so the parent loses 2.2
- Write the answer. 2
Check. ✓
Method. A neutron becomes a proton.
- Recall. A neutron changes to a proton, so the atomic number goes up by 1.up
- Write the answer. up
Check. ✓
Method. The number of nucleons does not change.
- Recall. The electron has almost no mass, so the mass number stays the same.stays the same
- Write the answer. stays the same
Check. ✓
Method. Check the mass and atomic numbers.
- Mass. 238 - 234 = 4.4
- Atomic. 92 - 90 = 2.2
- Particle. A mass of 4 and atomic number 2 is an alpha particle.alpha
- Write the answer. alpha
Check. ✓
Method. The mass is the same, and the atomic number goes up by 1.
- Mass. 14 - 14 = 0.0
- Atomic. 7 - 6 = 1, so the particle has charge -1.-1
- Particle. A particle with mass 0 and charge -1 is an electron.electron
- Write the answer. electron
Check. ✓
Method. Check the change in mass and atomic numbers.
- Mass. 222 - 218 = 4.4
- Atomic. 86 - 84 = 2.2
- Particle. So the emitted particle is an alpha particle.alpha
- Write the answer. alpha
Check. ✓
Method. Subtract 4 from the mass number.
- Subtract. 210 - 4 = 206.210 - 4 = 206
- Write the answer. 206
Check. ✓
Method. Subtract 2 from the atomic number.
- Subtract. 84 - 2 = 82.84 - 2 = 82
- Write the answer. 82
Check. ✓
Method. Think about the protons.
- Protons. Gamma is a wave released by the nucleus, with no particles.wave
- Element. So the number of protons, which defines the element, does not change.same element
- Write the answer. Accept any sentence that says the number of protons (atomic number) does not change.
Check. ✓
Method. Think about random decay.
- Check. Decay is random, so the next nucleus to decay cannot be predicted.random
- Write the answer. no
Check. ✓
Method. Think about one nucleus and many.
- One. We cannot say when one nucleus will decay.cannot predict
- Many. For a large sample, the number decaying in a time follows a steady pattern.pattern
- Write the answer. Accept any sentence that says the decay of one nucleus cannot be predicted, but for many nuclei a pattern is seen.
Check. ✓
Activity, count rate and background radiation
The activity of a source is the number of decays each second, measured in becquerels (Bq). A count rate is the number of counts per second or per minute recorded by a detector. The background radiation comes from natural and man-made sources, and it is always present. To find the count rate due to the source alone, subtract the background count rate:
corrected count rate = measured count rate - background count rate
| Source of background radiation | Example |
|---|---|
| radon gas in the ground and buildings | the largest source for most people in the UK |
| cosmic rays from space | more at high altitude |
| rocks and soil | some rocks contain more radioactive material |
| medical | X-rays and scans |
| food and drink | small amounts in what we eat and drink |
Key ideas
- Activity is measured in becquerels: 1 Bq = 1 decay per second.
- Count rate is measured by a detector, often counts per minute.
- Background radiation is always present and must be subtracted.
- Corrected count rate = measured - background.
Method. Subtract the background from the measured count.
- Read. Measured = 120 counts per minute, background = 20 counts per minute.120, 20
- Subtract. Corrected = 120 - 20 = 100 counts per minute.120 - 20 = 100
- Write the answer. 100
Check. 100 + 20 = 120. ✓
Method. One becquerel is one decay each second.
- Convert. Activity = 500 Bq = 500 decays per second.500 per second
- Read. An activity of 500 Bq means 500 decays each second.500 Bq
- Decide. So 500 decays per second.500
- Write the answer. 500
Check. ✓
Method. Recall the main natural source.
- Look. Some natural gases come up through the ground.ground
- Recall. Radon gas comes from the ground and can build up in buildings.radon
- Write the answer. radon
Check. ✓
Watch out
Watch out: the count rate is usually given per minute, but the activity is in becquerels, which are per second. Convert before you compare.
Exam tip
Practical safety. Only the teacher handles sealed low-activity sources. Pupils keep their distance, and keep the source in its holder. Wash hands after lessons.
Exercise 11C Activity, count rate and background
Method. Recall the unit.
- Recall. Activity is measured in becquerels, Bq.becquerel
- Write the answer. becquerel
Check. ✓
Method. One becquerel is one decay per second.
- Recall. 300 Bq is 300 decays per second.300
- Write the answer. 300
Check. ✓
Method. Subtract the background.
- Subtract. 90 - 15 = 75 counts per minute.90 - 15 = 75
- Write the answer. 75
Check. ✓
Method. Subtract the background count.
- Subtract. 200 - 50 = 150.200 - 50 = 150
- Write the answer. 150
Check. ✓
Method. Recall the source.
- Recall. Cosmic rays come from space.cosmic rays
- Write the answer. cosmic rays
Check. ✓
Method. Recall the medical source.
- Recall. X-rays and scans are medical sources.X-rays
- Write the answer. X-rays
Check. Accept scans or medical X-rays. ✓
Method. Think about what the detector records.
- Detect. The detector counts all radiation, including the background.all radiation
- Correct. So the background must be removed to find the source alone.remove
- Write the answer. Accept any sentence that says background radiation is always present, and would add to the count from the source.
Check. ✓
Method. Correct first, then convert to per second.
- Correct. 480 - 60 = 420 counts per minute.420
- Convert. 420 / 60 = 7 counts per second.420 / 60 = 7
- Write the answer. 7 per second
Check. 7 x 60 = 420. ✓
Method. Convert the time to seconds, then multiply.
- Convert. 5 minutes = 300 s.300 s
- Multiply. 2000 x 300 = 600000 decays.2000 x 300 = 600000
- Write the answer. 600000
Check. ✓
Method. Subtract the background.
- Subtract. 40 - 40 = 0 counts per minute.40 - 40 = 0
- Write the answer. 0
Check. ✓
Method. Think about natural radiation.
- Source. Natural sources such as rocks and cosmic rays are always present.natural
- Count. So a detector always records some counts.some counts
- Write the answer. Accept any sentence that says there is background radiation from natural sources all the time.
Check. ✓
Half-life
The half-life of a radioactive isotope is the time taken for half the nuclei in a sample to decay. It is also the time for the count rate or activity to halve. Each half-life, the count falls to half of its previous value. Half-lives can be very short (fractions of a second) or very long (millions of years).
To find the count after several half-lives, halve the starting count once for each half-life: after n half-lives the count is the start count divided by 2n.
Key ideas
- Half-life: time for the activity or count rate to halve.
- Count after n half-lives = start count / 2 to the power n.
- Read the half-life from a graph: find the time for the count to halve.
- Use the corrected count (background subtracted) before finding the half-life.
Method. 40 minutes is 2 half-lives, so halve twice.
- Count. 40 / 20 = 2 half-lives.2
- Halve. 800 / 2 = 400, then 400 / 2 = 200 counts per minute.200
- Write the answer. 200
Check. 800 / 2 / 2 = 200. ✓
Method. Find the time taken for the count to halve.
- Read. The count goes from 400 to 200 between 0 and 20 minutes.0 to 20
- Decide. So the half-life is 20 minutes.20 min
- Write the answer. 20 minutes
Check. The count is 100 at 40 minutes, which is half of 200. ✓
Method. Halve twice, or divide by 2 squared.
- Halve. After 1 half-life: 600. After 2 half-lives: 300.600, 300
- Check. 1200 / 22 = 1200 / 4 = 300.1200 / 4 = 300
- Write the answer. 300
Check. ✓
Watch out
Watch out: the half-life is a time, not a count. Halving the count once takes one half-life, not one minute.
Exam tip
Exam tip. To find the half-life from a graph, start at a count, go down to half of it, then read the time across. Do not use the background count in the reading.
Exercise 11D Half-life calculations
Method. Halve the count once.
- Halve. 600 / 2 = 300.600 / 2 = 300
- Write the answer. 300
Check. ✓
Method. Halve the count.
- Halve. 80 / 2 = 40.80 / 2 = 40
- Write the answer. 40
Check. ✓
Method. 10 minutes is 2 half-lives.
- Halve. After 5 min: 200. After 10 min: 100.200, 100
- Write the answer. 100
Check. 400 / 22 = 100. ✓
Method. 6 hours is 3 half-lives.
- Count. 6 / 2 = 3 half-lives.3
- Divide. 1600 / 23 = 1600 / 8 = 200.1600 / 8 = 200
- Write the answer. 200
Check. ✓
Method. 60 minutes is 3 half-lives.
- Count. 60 / 20 = 3.3
- Divide. 800 / 8 = 100.800 / 8 = 100
- Write the answer. 100
Check. ✓
Method. 30 days is 3 half-lives.
- Count. 30 / 10 = 3.3
- Divide. 640 / 8 = 80.640 / 8 = 80
- Write the answer. 80
Check. ✓
Method. Two half-lives take 16 minutes, so one is 8 minutes.
- Divide. One half-life = 16 / 2 = 8 minutes.16 / 2 = 8
- Write the answer. 8 minutes
Check. ✓
Method. Count the halvings: 400 to 200 to 100.
- Halve. 400 to 200 is one half-life; 200 to 100 is another.2 halvings
- Write the answer. 2
Check. 400 / 22 = 100. ✓
Method. Count the halvings: 180 to 90 to 45.
- Halve. 180 to 90 is one half-life; 90 to 45 is another.2 halvings
- Write the answer. 2
Check. 180 / 4 = 45. ✓
Method. One-eighth is three halvings.
- Halvings. 1/8 = (1/2) x (1/2) x (1/2), so 3 half-lives.3
- Time. 3 x 3 = 9 hours.3 x 3 = 9
- Write the answer. 9 hours
Check. ✓
Method. Think about the remaining sample.
- Halves. After 5 days half is left; after another 5 days half of that is left.half of half
- Link. So the remaining sample halves each time rather than being used up in one go.halves each time
- Write the answer. Accept any answer that says each half-life halves the remaining sample, so it never reaches zero in a fixed time.
Check. ✓
Method. Calculate the fraction left.
- Halves. After 10 minutes, half is left; after 20 minutes, a quarter is left.a quarter
- Conclusion. The source is not gone, so the pupil is wrong.not gone
- Write the answer. Accept any answer that says after 20 minutes only a quarter remains, not zero.
Check. ✓
Uses and dangers of radiation
Radiation has many uses. Gamma sources are used as tracers in medicine, because the gamma rays escape the body and can be detected. Radiotherapy uses radiation to kill cancer cells. Carbon dating uses carbon-14, which has a half-life of about 5700 years, to date old wood and bones.
Radiation is dangerous because it is ionising: it can damage cells and DNA. The risks are reduced by keeping sources in shielded containers, keeping the time of exposure short, and keeping a large distance from the source. Sources are handled with tongs or in a lead container.
Key ideas
- Gamma: used as a medical tracer; escapes the body.
- Radiotherapy: radiation kills cancer cells.
- Carbon dating: carbon-14 (half-life about 5700 years) dates old material.
- Risks: time, distance and shielding reduce the dose.
Method. Choose the radiation that escapes the body.
- Look. Alpha is stopped by the skin and paper, so it does not escape.stopped
- Decide. Gamma escapes the body and can be detected.gamma
- Write the answer. gamma
Check. ✓
Method. A day is 24 hours.
- Time. 1 day = 24 hours.24 h
- Count. 24 / 6 = 4 half-lives.24 / 6 = 4
- Write the answer. 4
Check. ✓
Method. Think about the three ways to reduce exposure.
- Options. Time, distance and shielding all reduce the dose.time, distance, shielding
- Choose. For example, keep the source in a lead container.lead container
- Write the answer. Accept any method that uses time, distance or shielding.
Check. ✓
Watch out
Watch out: a tracer is useful because its half-life is short and its radiation escapes. A long half-life means the source stays active for a long time.
Exam tip
Exam tip. When choosing a source for a use, check two things: does the radiation escape the body (or the object), and is the half-life suitable for the time needed?
Exercise 11E Uses and dangers
Method. Recall the tracer.
- Recall. Gamma radiation escapes the body and is used as a tracer.gamma
- Write the answer. gamma
Check. ✓
Method. Recall the value.
- Recall. Carbon-14 has a half-life of about 5700 years.5700
- Write the answer. 5700 years
Check. ✓
Method. Recall the use.
- Recall. Radiotherapy kills cancer cells.cancer cells
- Write the answer. cancer cells
Check. ✓
Method. Recall the danger.
- Recall. Ionising radiation can damage cells.ionising
- Write the answer. ionising
Check. ✓
Method. Recall the methods.
- Recall. Keeping a greater distance reduces the dose.distance
- Write the answer. distance
Check. ✓
Method. Divide the time by the half-life.
- Divide. 8 / 2 = 4 half-lives.8 / 2 = 4
- Write the answer. 4
Check. ✓
Method. A short test needs a short half-life that does not leave a long-lived source.
- Compare. A short half-life loses its activity quickly, so it is safer after the test.short half-life
- Write the answer. 2 hours
Check. ✓
Method. Think about shielding.
- Shield. Gamma needs thick lead to reduce it.thick lead
- Dose. So the lead reduces the dose to people nearby.reduces dose
- Write the answer. Accept any sentence that says lead absorbs gamma radiation, reducing the dose to people nearby.
Check. ✓
Method. Think about time and the rules.
- Time. A short time reduces the dose, but it is still exposure.short time
- Rules. Pupils never handle sources; trained people use tongs or containers.trained people
- Write the answer. Accept any answer that says short exposure reduces the dose but a source must still be handled only by trained people, with tongs or a container.
Check. ✓
Method. Count the halvings: 800 to 400 to 200 to 100.
- Count. 800 / 2 = 400; 400 / 2 = 200; 200 / 2 = 100. That is 3 halvings.3
- Write the answer. 3
Check. 800 / 8 = 100. ✓
Method. Multiply the half-life by the number of half-lives.
- Multiply. 5700 x 3 = 17100 years.5700 x 3 = 17100
- Write the answer. 17100 years
Check. ✓
Chapter summary
| Skill | Method |
|---|---|
| Types of radiation | Alpha +2, stopped by paper; beta -1, stopped by aluminium; gamma no charge, needs lead |
| Nuclear equations | Alpha: A - 4, Z - 2; beta-minus: A same, Z + 1; balance both numbers |
| Activity and background | Activity in Bq (decays per second); corrected count = measured - background |
| Half-life | Time for the count to halve; count after n half-lives = start / 2 to the power n |
| Uses and dangers | Gamma tracers, radiotherapy, carbon dating; reduce risk with time, distance and shielding |
Can you…?
- I can compare alpha, beta and gamma radiation
- I can complete nuclear equations for alpha and beta-minus decay
- I can correct a count rate for background radiation
- I can find a half-life from a graph and from count data
- I can explain how radiation is used and how risks are reduced
Key terms
- radioactive decay
- the random process by which an unstable nucleus gives out radiation
- alpha particle
- two protons and two neutrons, given out by some nuclei
- beta particle
- a fast electron given out by a nucleus when a neutron changes to a proton
- gamma radiation
- electromagnetic waves given out by a nucleus, with no mass or charge
- activity
- the number of decays each second, in becquerels (Bq)
- half-life
- the time for the activity or count rate to halve
- background radiation
- radiation always present from natural and man-made sources
Exercise 11Z Check-up
Method. Recall.
- Recall. Alpha is a helium nucleus.alpha
- Write the answer. alpha
Check. ✓
Method. Recall.
- Recall. Beta is stopped by about 3 mm of aluminium.beta
- Write the answer. beta
Check. ✓
Method. Check the numbers.
- Mass. 226 - 222 = 4.4
- Atomic. 88 - 86 = 2.2
- Particle. An alpha particle.alpha
- Write the answer. alpha
Check. ✓
Method. The atomic number goes up by 1 and the mass is the same.
- Particle. A beta-minus particle, an electron.electron
- Write the answer. electron
Check. ✓
Method. Halve it.
- Halve. 240 / 2 = 120.240 / 2 = 120
- Write the answer. 120
Check. ✓
Method. Multiply.
- Multiply. 3 x 4 = 12 hours.3 x 4 = 12
- Write the answer. 12 hours
Check. ✓
Method. Subtract.
- Subtract. 70 - 10 = 60.70 - 10 = 60
- Write the answer. 60
Check. ✓
Method. Recall.
- Recall. Activity is measured in becquerels, Bq.becquerel
- Write the answer. becquerel
Check. ✓
Method. Recall the idea.
- Random. Radioactive decay is a random process for each nucleus.random
- Write the answer. Accept any sentence that says radioactive decay is random.
Check. ✓
Method. Recall the tracer.
- Recall. Gamma escapes the body and can be detected.gamma
- Write the answer. gamma
Check. ✓
Total 28 marks. Allow about 28 minutes.
Exercise 11X Exam-style questions
Method. Check the mass and atomic numbers.
- Check. 238 - 234 = 4 and 92 - 90 = 2, so the particle is an alpha particle.alpha
- Write the answer. alpha
Check. ✓
Method. 15 minutes is 3 half-lives.
- Count. 15 / 5 = 3 half-lives.3
- Divide. 640 / 8 = 80 counts per minute.640 / 8 = 80
- Write the answer. 80
Check. ✓
Method. Subtract the background.
- Subtract. 230 - 30 = 200 counts per minute.230 - 30 = 200
- Write the answer. 200
Check. ✓
Method. Check the numbers and name the particle.
- Numbers. Mass number stays 14; atomic number goes up from 6 to 7.Z up by 1
- Particle. This is a beta-minus particle, an electron.beta-minus
- Write the answer. Accept any answer that says it is a beta-minus particle (an electron), because the atomic number goes up by 1 and the mass number stays the same.
Check. ✓
Method. Describe the method.
- Start. Choose a starting count rate on the graph.start
- Halve. Find the time at which the count rate has halved.halved
- Read. The time taken is the half-life.half-life
- Write the answer. Accept any answer that starts at a count, finds the time for the count to halve, and reads that time as the half-life.
Check. ✓
Method. Think about what the detector records.
- Detect. The detector records all radiation, including background.all radiation
- Correct. The measured count is too high, so subtract the background.subtract
- Write the answer. Accept any answer that says the detector records background, so the measured count is too high unless the background is subtracted.
Check. ✓
Method. Think about the penetration and ionising power.
- Choice. Alpha is suitable for a smoke detector.alpha
- Penetration. It is stopped by a few centimetres of air, so it is contained inside the detector.stopped by air
- Ionising. It is strongly ionising, so a small current changes when smoke enters the air gap.ionising
- Safety. So it poses little risk outside the detector.safe
- Write the answer. Accept any answer that says alpha is used because it is stopped by a short distance of air and is strongly ionising, so the source is contained.
Check. ✓
Method. 9 hours is 3 half-lives; halve three times.
- Count. 9 / 3 = 3 half-lives.3
- Halve. 960 / 2 = 480; 480 / 2 = 240; 240 / 2 = 120.120
- Check. 960 / 8 = 120 counts per minute.960 / 8 = 120
- Write the answer. 120
Check. ✓
Method. Describe the method.
- Count. Measure the carbon-14 count rate in the object and compare with a fresh sample.compare
- Halvings. Count how many halvings have happened.halvings
- Age. Multiply the number of half-lives by about 5700 years.5700
- Check. This gives an estimate of the age.estimate
- Write the answer. Accept any answer that says the carbon-14 count falls by half every 5700 years, so the number of half-lives gives the age.
Check. ✓
Method. Compare the two sources over time.
- Short. The 2 second source loses its activity very quickly.quickly
- Long. The 2000 year source stays active for a very long time.long time
- Caveat. The short-lived source is more active at first, so it needs care in the first moments.more active at first
- Conclusion. Over time the short-lived source is less hazardous to store.less hazardous
- Write the answer. Accept any answer that says the short half-life source loses its activity quickly, so it is less hazardous over time, though it is more active at first.
Check. ✓