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KS3 Maths · Year 7Chapter 9 · Angles, polygons and constructions
Year 7 · Chapter 9

Angles, polygons and constructions

By the end of this chapter you will be able to

  • Recognise and use angle facts at a point, on a straight line and vertically opposite, and solve for a missing angle
  • Use alternate and corresponding angles with parallel lines
  • Use the angle sum of a triangle and a quadrilateral, and the properties of isosceles and equilateral triangles
  • Work out the interior and exterior angles of regular polygons, and the angle sum of any polygon
  • Describe ruler and compass constructions, and label triangles ABC

You should already know

  • Measuring and drawing angles, and the names of acute, right, obtuse and reflex angles (Year 6, Chapter 7)
  • Angles in a triangle and quadrilateral, and angles at a point (Year 5 and Year 6, geometry chapters)
  • Solving equations (Chapter 6)

Where this leads

  • Congruence and similarity of triangles (Chapter 10)
  • Pythagoras and trigonometry in right-angled triangles (Chapter 11, and Year 8)

National Curriculum for England, Key Stage 3 mathematics, Year 7. Content: G3 draw and measure line segments and angles, and interpret scale drawings, G4 ruler and compass constructions: perpendicular bisector, perpendicular from or at a point, angle bisector, G5 points, lines, parallel and perpendicular lines, right angles, regular and symmetric polygons, conventional terms, G6 labelling conventions for triangles (ABC) and the sides and angles opposite them, G7 derive and illustrate properties of triangles, quadrilaterals and plane figures, G10 angles at a point, on a straight line and vertically opposite angles, G11 parallel lines: alternate and corresponding angles, G12 the angle sum of a triangle and of any polygon; the properties of regular polygons.

Exercise P  Do you remember?

Non-calculator
1
FHow many degrees are there in a straight line?
2
FHow many degrees are there in a right angle?
3
FHow many degrees are there in one full turn?
4
FIs an angle of 120° acute, right, obtuse or reflex?
5
FWhat is the name of a shape with five sides?
9.1

Angles at a point, on a line and vertically opposite

Year 7
G10, G3
Video lesson: Angles at a point, on a line and vertically oppositeComing soon
A gate opens to make an angle with the fence. Where two lines cross, the four angles have clear rules, and these rules let us find a missing angle without measuring it.

Angles at a point add up to 360°. Angles on a straight line add up to 180°. When two lines cross, the angles opposite each other are vertically opposite, and they are equal.

xy

Key ideas

  • Angles at a point add up to 360°.
  • Angles on a straight line add up to 180°.
  • Vertically opposite angles are equal.
  • Angles are measured in degrees (°). A right angle is 90°.
Worked example 9.1.1
Find the missing angle x: angles on a straight line are 62° and x.

Method. Angles on a straight line add up to 180°.

  1. Write the equation. The two angles make a straight line.
    62 + x = 180
  2. Subtract 62. This leaves x on its own.
    x = 180 − 62 = 118
  3. Write the answer. Check it against the question and give the unit.
    118°

Check. 62 + 118 = 180. ✓

Watch out. Take the known angle away from 180.

Worked example 9.1.2
Find x: angles at a point are 125°, 85° and x.

Method. Angles at a point add up to 360°.

  1. Write the equation. Three angles meet at a point.
    125 + 85 + x = 360
  2. Add the two known angles. Add 125 and 85.
    210 + x = 360
  3. Subtract 210. This gives x.
    x = 150
  4. Write the answer. Check it against the question and give the unit.
    150°

Check. 125 + 85 + 150 = 360. ✓

Watch out. Add the known angles first, then subtract from 360.

Worked example 9.1.3
Two lines cross. One angle is 47°. Find the vertically opposite angle.

Method. Vertically opposite angles are equal.

  1. Identify the opposite angle. The angle opposite the 47° angle is vertically opposite.
    opposite angle = 47
  2. Check with the angle next to it. The angle next to 47° on the straight line is 180 − 47 = 133, which is not the answer.
    180 − 47 = 133
  3. Write the answer. Check it against the question and give the unit.
    47°

Check. The angles on a straight line: 47 + 133 = 180. ✓

Watch out. Opposite angles are equal; the angles next to each other are not.

Watch out

Watch out: an angle at a point is 360°, not 180°. Only angles on a straight line add up to 180°.

Exam tip

Grown-up tip. Ask the pupil to measure one angle with a protractor and check it against the sum: a line of 180° split into two parts.

Exercise 9A  Angles at a point, on a line and vertically opposite

Non-calculator
1
FAngles on a straight line are 65° and x. Find x.
2
FAngles on a straight line are 140° and y. Find y.
3
FThree angles meet at a point: 90°, 120° and z. Find z.
4
FFour angles meet at a point: 75°, 80°, 105° and x. Find x.
5
FTwo lines cross. One of the angles is 58°. What is the angle vertically opposite it?
6
FTwo lines cross. The angles opposite each other are 2x + 30 and x + 60. Find x.
7
FAngles on a straight line are 3x and 2x. Find the two angles.
8
FClassify each angle as acute, right, obtuse or reflex: 35°, 90°, 150°, 200°.
9
PSThe angle between the hands of a clock at 3 o'clock is a right angle. What is the angle at 3 o'clock, measured as a whole turn?
10
FFind the missing angle in each: (a) angles on a line 50° and x (b) vertically opposite angles 2y and 80° (c) angles at a point x, x and 160°
(a)(a) 50° and x on a line
(b)(b) vertically opposite 2y and 80°
(c)(c) x, x and 160° at a point
11
PSThree angles on a straight line are x, x + 10 and x + 20. Find the three angles.
12
RSam says that two angles on a straight line can be 100° and 90°. Is he right? Explain.
9.2

Parallel lines: alternate and corresponding angles

Year 7
G11, G5
Video lesson: Parallel lines: alternate and corresponding anglesComing soon
Two parallel railway tracks are crossed by a road at an angle. The angles the road makes with each track are linked. Parallel lines never meet, and a line that crosses them is called a transversal.

When a transversal crosses two parallel lines, the corresponding angles (in the same position at each crossing) are equal. The alternate angles (on opposite sides of the transversal, between the parallel lines) are also equal.

parallelabc

Key ideas

  • Parallel lines are marked with arrows and never meet.
  • Corresponding angles (F-shape, same position) are equal.
  • Alternate angles (Z-shape, opposite sides) are equal.
  • Angles on a straight line still add up to 180°.
Worked example 9.2.1
A transversal crosses two parallel lines. One angle is 65°. The alternate angle is what?

Method. Alternate angles are equal.

  1. Identify the alternate angle. The angle on the other side of the transversal, between the parallel lines.
    alternate angle
  2. Use the rule. Alternate angles are equal.
    65 = 65
  3. Write the answer. Check it against the question and give the unit.
    65°

Check. Alternate angles lie on a Z shape and are equal. ✓

Watch out. Alternate angles are equal only for parallel lines.

Worked example 9.2.2
Find x: alternate angles are 3x and 75°.

Method. Alternate angles are equal.

  1. Write. The two alternate angles are equal.
    3x = 75
  2. Divide by 3. This gives x.
    x = 25
  3. Write the answer. Check it against the question and give the unit.
    x = 25

Check. 3 × 25 = 75. ✓

Watch out. Equal angles give equal expressions.

Worked example 9.2.3
Find y: corresponding angles are y and 2y − 40°.

Method. Corresponding angles are equal.

  1. Write. The two corresponding angles are equal.
    y = 2y − 40
  2. Solve. Subtract y, then add 40.
    y = 40
  3. Write the answer. Check it against the question and give the unit.
    y = 40

Check. 2 × 40 − 40 = 40. ✓

Watch out. Check the angle, not just the letter.

Watch out

Watch out: the angles are equal only when the lines are parallel. The marking with arrows tells you the lines are parallel.

Exam tip

Grown-up tip. Ask the pupil to trace the letter F for corresponding and Z for alternate, to find the matching angles.

Exercise 9B  Parallel lines and transversals

Non-calculator
1
FA transversal crosses two parallel lines. A corresponding angle is 65°. What is the other corresponding angle?
2
FAn alternate angle to 65° is what?
3
FAngle x and an angle of 112° are corresponding angles on parallel lines. Find x.
4
FAn alternate angle is 58°. Find the angle on a straight line next to it.
5
FA corresponding angle is 74°. What is the alternate angle to it?
6
FAlternate angles are 3x and 75°. Find x.
7
FCorresponding angles are y and 2y − 40°. Find y.
8
FAlternate angles are 2x + 10 and 4x − 10. Find x, and find the angle.
9
FOn parallel lines: (a) an alternate angle is 47°; find the alternate angle on the other side. (b) a corresponding angle is 102°; find the corresponding angle at the other line. (c) an angle is 102°; find the angle on a straight line next to it.
(a)(a) alternate angle 47°
(b)(b) corresponding angle 102°
(c)(c) angle 102° on a line
10
PSTwo parallel fences are crossed by a path at 58°. What is the angle on the other side of the path, on the same fence?
11
RExplain why alternate angles are equal when the two lines are parallel.
9.3

Angles in triangles and quadrilaterals

Year 7
G7, G12
Video lesson: Angles in triangles and quadrilateralsComing soon
A triangular sail is cut from cloth. Its three corners must add up to a fixed total, so if two corners are known, the third is found by subtraction.

The three angles of any triangle add up to 180°. The four angles of any quadrilateral add up to 360°, because a quadrilateral can be split into two triangles.

An isosceles triangle has two equal sides, and its two base angles are equal. An equilateral triangle has three equal sides and three equal angles of 60°.

Key ideas

  • The angles in a triangle add up to 180°.
  • The angles in a quadrilateral add up to 360°.
  • Isosceles: two equal sides and two equal base angles. Equilateral: all angles 60°.
  • A right-angled triangle has one angle of 90°, so the other two add up to 90°.
Worked example 9.3.1
A triangle has angles 50°, 60° and x. Find x.

Method. Angles in a triangle add up to 180°.

  1. Write the equation. The three angles add to 180.
    50 + 60 + x = 180
  2. Add and subtract. Add 50 and 60, then subtract from 180.
    110 + x = 180, x = 70
  3. Write the answer. Check it against the question and give the unit.
    70°

Check. 50 + 60 + 70 = 180. ✓

Watch out. Add the known angles first.

Worked example 9.3.2
An isosceles triangle has a top angle of 40°. Find the base angles.

Method. The two base angles are equal and add up to 180 − 40.

  1. Find the two base angles together. Take the top angle from 180.
    180 − 40 = 140
  2. Share equally. The two base angles are equal, so divide by 2.
    140 ÷ 2 = 70
  3. Write the answer. Check it against the question and give the unit.
    70° each

Check. 70 + 70 + 40 = 180. ✓

Watch out. The base angles are equal, so divide by 2.

Worked example 9.3.3
A quadrilateral has angles 80°, 95°, 110° and x. Find x.

Method. Angles in a quadrilateral add up to 360°.

  1. Add the known angles. 80 + 95 + 110 = 285.
    285
  2. Subtract from 360. x = 360 − 285.
    x = 75
  3. Write the answer. Check it against the question and give the unit.
    75°

Check. 285 + 75 = 360. ✓

Watch out. Use 360, not 180, for four angles.

Watch out

Watch out: a quadrilateral has 360° of angles, not 180°. Only triangles have a sum of 180°.

Exam tip

Grown-up tip. Ask the pupil to tear the corners off a paper triangle and put them together on a straight line, to see the 180° sum.

Exercise 9C  Angles in triangles and quadrilaterals

Non-calculator
1
FA triangle has angles 35°, 80° and x. Find x.
2
FA right-angled triangle has one angle of 37°. Find the other acute angle.
3
FAn equilateral triangle has one angle x. Find x.
4
FAn isosceles triangle has a top angle of 30°. Find each base angle.
5
FAn isosceles triangle has base angles of 65° each. Find the top angle.
6
FA quadrilateral has angles 90°, 90°, 60° and x. Find x.
7
FA quadrilateral has angles 2x, x, x and x. Find x.
8
FA parallelogram has adjacent angles x and 2x. Find the smaller angle.
9
FA right-angled triangle has angles 90° and 45°. What is the third angle?
10
FFind the missing angle in each triangle or quadrilateral: (a) 20°, 100° and x (b) 90°, 45° and x (c) 70°, 70° and x
(a)(a) 20°, 100° and x
(b)(b) 90°, 45° and x
(c)(c) 70°, 70° and x
11
PSThe angles of a triangle are in the ratio 1 : 2 : 3. Find the largest angle.
12
RCan a triangle have angles 90°, 50° and 45°? Explain.
9.4

Polygons and regular polygons

Year 7
G5, G12
Video lesson: Polygons and regular polygonsComing soon
A tile designer uses regular hexagons, because they fit together with no gaps. To check a design, the designer needs the size of each angle inside a polygon, and the sum of all the angles.

A polygon is a closed shape with straight sides. A regular polygon has all sides equal and all angles equal. The sum of the interior (inside) angles of a polygon with n sides is (n − 2) × 180°.

For a regular polygon, each exterior angle is 360° ÷ n, and each interior angle is 180° minus the exterior angle.

Key ideas

  • Polygon with n sides: sum of interior angles = (n − 2) × 180°.
  • Regular polygon: each exterior angle = 360° ÷ n.
  • Each interior angle = 180° − exterior angle (they lie on a straight line).
  • Names: triangle 3, quadrilateral 4, pentagon 5, hexagon 6, heptagon 7, octagon 8, nonagon 9, decagon 10.
Worked example 9.4.1
Find the sum of the interior angles of a pentagon.

Method. Use (n − 2) × 180 with n = 5.

  1. Write the formula. A pentagon has 5 sides.
    (5 − 2) × 180
  2. Work out. Subtract 2, then multiply by 180.
    3 × 180 = 540
  3. Write the answer. Check it against the question and give the unit.
    540°

Check. The triangle has 180; three triangles fit in a pentagon: 3 × 180 = 540. ✓

Watch out. Subtract 2 from the number of sides first.

Worked example 9.4.2
Find the size of each interior angle of a regular hexagon.

Method. Find the sum, then divide by the number of angles.

  1. Find the sum. A hexagon has 6 sides: (6 − 2) × 180 = 720.
    720
  2. Share equally. All six angles are equal in a regular hexagon.
    720 ÷ 6 = 120
  3. Write the answer. Check it against the question and give the unit.
    120°

Check. 6 × 120 = 720. ✓

Watch out. Share the sum equally for a regular polygon only.

Worked example 9.4.3
The exterior angle of a regular polygon is 30°. How many sides has it?

Method. Use exterior angle = 360 ÷ n.

  1. Write the equation. 360 ÷ n = 30.
    360 ÷ 30 = n
  2. Solve. Divide 360 by 30.
    n = 12
  3. Write the answer. Check it against the question and give the unit.
    12 sides

Check. Each exterior angle is 360 ÷ 12 = 30. ✓

Watch out. Exterior angles add up to 360.

Watch out

Watch out: the sum of the interior angles is NOT 360° for every polygon. It is 360° only for quadrilaterals; a pentagon has 540°.

Exam tip

Grown-up tip. Ask the pupil to split a polygon into triangles from one corner, and to count the triangles: n − 2 of them.

Exercise 9D  Polygons

Non-calculator
1
FFind the sum of the interior angles of a pentagon.
2
FFind the sum of the interior angles of an octagon.
3
FFind the size of each interior angle of a regular pentagon.
4
FFind the exterior angle of a regular octagon.
5
FA regular polygon has an exterior angle of 30°. How many sides does it have?
6
FFind the size of each interior angle of a regular decagon (10 sides).
7
FName a polygon with 7 sides.
8
FA regular polygon has an interior angle of 150°. Find the number of sides.
9
PSThe sum of the interior angles of a polygon is 900°. How many sides does it have?
10
F(a) Name a quadrilateral with four equal sides and four right angles. (b) Name a triangle with all sides equal. (c) Name a quadrilateral with all sides equal but not all angles equal.
(a)(a) four equal sides and four right angles
(b)(b) triangle with all sides equal
(c)(c) all sides equal, not all angles equal
11
RExplain why an interior angle of a regular polygon cannot be 100°.
9.5

Constructions and labelling triangles

Year 7
G3, G4, G6
Video lesson: Constructions and labelling trianglesComing soon
A gardener must plant a tree exactly halfway between two fence posts, and must find the shortest path from a tap to a hedge. Both tasks are solved with a ruler and a pair of compasses, using constructions.

Label a triangle with capital letters at its corners, ABC. The side opposite corner A is labelled a (side BC), and the angle at A is ∠A. The perpendicular bisector of a line cuts it in half at right angles. A perpendicular from a point to a line is the shortest distance to that line.

Key ideas

  • Label a triangle ABC: the side opposite A is a, opposite B is b, opposite C is c.
  • Perpendicular bisector: a line at 90° through the midpoint of a line segment.
  • Angle bisector: a line that divides an angle into two equal parts.
  • The shortest distance from a point to a line is along the perpendicular.
Worked example 9.5.1
In triangle ABC, which side is opposite angle A?

Method. Find the side that does not touch A.

  1. Look at the corners. The side opposite A goes from B to C.
    BC
  2. Check. The sides AB and AC both touch A, so BC is the one opposite.
    AB and AC touch A
  3. Write the answer. Check it against the question and give the unit.
    BC

Check. BC is the side with no corner A. ✓

Watch out. The opposite side is the one that does not touch the corner.

Worked example 9.5.2
A line AB is 8 cm long. Where is its midpoint, and how far is it from A?

Method. The midpoint is halfway along.

  1. Halve the length. The midpoint is half of the length from A.
    8 ÷ 2 = 4
  2. Say where. It is 4 cm from A, and 4 cm from B.
    4 cm from A
  3. Write the answer. Check it against the question and give the unit.
    4 cm from A

Check. 4 + 4 = 8. ✓

Watch out. The midpoint is the same distance from both ends.

Worked example 9.5.3
On a plan drawn at 1 : 20, a wall is 6 cm long. How long is the real wall?

Method. Multiply by the scale.

  1. Read the scale. Each cm on the plan is 20 cm in real life.
    1 cm : 20 cm
  2. Multiply. Six lots of 20 cm.
    6 × 20 = 120
  3. Write the answer. Check it against the question and give the unit.
    120 cm

Check. 120 ÷ 20 = 6. ✓

Watch out. Use the scale factor.

Watch out

Watch out: the perpendicular bisector is at 90° to the line, not at 45°. Use a set square to check the right angle.

Exam tip

Grown-up tip. Ask the pupil to follow each construction with a ruler and compasses on paper, and to check the result with a protractor.

Exercise 9E  Constructions and labels

Non-calculator
1
FIn triangle ABC, which side is opposite angle B?
2
FIn triangle ABC, which side is opposite angle C?
3
FLine AB is 10 cm long. Where is its midpoint?
4
FDescribe how to construct the perpendicular bisector of a line segment AB.
5
FDescribe how to bisect an angle with compasses.
6
PSA scale drawing has a scale of 1 : 50. A line on the drawing is 4 cm long. How long is the real line, in m?
7
PSPoint P is 5 cm from the line AB. Explain how to find the shortest distance from P to AB.
8
FAn equilateral triangle is constructed. What is each of its angles?
9
RExplain why the angle bisector construction gives two equal angles.
10
FLabel the triangle ABC. Write (a) the side opposite A (b) the angle at C
(a)(a) the side opposite A
(b)(b) the angle at C

Chapter summary

SkillMethod
Angle factsAt a point: 360°; on a straight line: 180°; vertically opposite: equal
Parallel linesCorresponding and alternate angles are equal
Triangles and quadrilateralsTriangle angles add to 180°; quadrilateral angles add to 360°; isosceles base angles equal
PolygonsInterior sum (n − 2) × 180°; regular exterior angle 360° ÷ n
ConstructionsPerpendicular bisector; angle bisector; perpendicular from a point is the shortest distance
LabellingTriangle ABC: side a is opposite A, and so on

Can you…?

  • I can find missing angles at a point, on a straight line and vertically opposite
  • I can use alternate and corresponding angles with parallel lines
  • I can use the angle sums of triangles and quadrilaterals
  • I can work out the angle sum and the angles of regular polygons
  • I can describe the constructions of a perpendicular bisector and an angle bisector
  • I can label a triangle ABC and name the sides opposite its angles

Key terms

transversal
a line that crosses two or more other lines
alternate angles
equal angles on opposite sides of a transversal, between two parallel lines
corresponding angles
equal angles in the same position at two crossings of a transversal
polygon
a closed shape with straight sides
regular polygon
a polygon with all sides equal and all angles equal
perpendicular bisector
a line at 90° that cuts a line segment in half
vertically opposite
the angles opposite each other where two lines cross; they are equal

Exercise 9Z  Check-up

Non-calculator
1
Angles on a straight line are 72° and x. Find x.
2
Four angles meet at a point: 90°, 60°, 110° and x. Find x.
3
Two lines cross. One angle is 48°. Write the vertically opposite angle.
4
A triangle has angles 40°, 75° and x. Find x.
5
Alternate angles are 5x and 100°. Find x.
6
Find the sum of the interior angles of a hexagon.
7
Find the exterior angle of a regular hexagon.
8
A quadrilateral has angles 110°, 80°, 95° and x. Find x.
9
An isosceles triangle has base angles of 50° each. Find the top angle.
10
The exterior angle of a regular polygon is 45°. How many sides does it have?

Total 22 marks. Allow about 22 minutes.

Exercise 9X  Practice test questions

Non-calculator
1
FAngles on a straight line are 135° and x. Find x.[1 mark]
2
FFind the sum of the interior angles of a pentagon.[1 mark]
3
FFind the size of each interior angle of a regular pentagon.[2 marks]
4
FTwo parallel lines are crossed by a transversal. One alternate angle is 3x and the other is 75°. Find x.[2 marks]
5
FA quadrilateral has angles 80°, 95°, 110° and x. Find x.[2 marks]
6
FFind the exterior angle of a regular decagon (10 sides).[2 marks]
7
FA regular polygon has an interior angle of 140°. How many sides does it have?[3 marks]
8
FThree angles on a straight line are x, x + 10 and x + 20. Find the largest angle.[3 marks]
9
RExplain why a triangle with angles 90°, 50° and 45° cannot exist.[3 marks]
10
RPoint P is 5 cm from the line AB. Describe how to find the shortest distance from P to AB, and say why it is the shortest.[3 marks]

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