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KS3 Maths · Year 8Chapter 5 · Expanding and factorising
Year 8 · Chapter 5

Expanding and factorising

By the end of this chapter you will be able to

  • Collect like terms, and simplify expressions with one or two letters
  • Multiply terms together, and expand a bracket by multiplying each term inside it
  • Expand two brackets by multiplying each pair of terms, and collect like terms
  • Take out the highest common factor from an expression, and write the answer in brackets
  • Factorise x2 + bx + c, and check the answer by expanding the brackets

You should already know

  • Writing and evaluating simple expressions, and substituting numbers for letters (Year 7)
  • Multiplying and dividing negative numbers (Year 7)
  • Multiplying by a number outside a bracket, and factors and multiples (Year 7, Chapter 3)

Where this leads

  • Solving equations with brackets, and forming equations from expressions (Year 8, Chapter 6)
  • Factorising quadratics with a coefficient of x2 other than 1, and the difference of two squares (Year 9)
  • Algebraic fractions, expanding and factorising in full (GCSE)

National Curriculum for England, Key Stage 3 mathematics, Year 8. Content: Simplify expressions by collecting like terms, Expand single brackets and double brackets such as (x + 3)(x − 2), Factorise by taking out the highest common factor, Factorise quadratics of the form x2 + bx + c into two brackets, and check a factorisation by expanding.

Exercise P  Do you remember?

Non-calculator
1
FWork out 7 × (4 + 2).
2
FSimplify 2a + 3a.
3
FWork out the value of 2n + 1 when n = 4.
4
FWork out 3 × (−4).
5
FWhat is 42?
5.1

Simplifying expressions

Year 8
Simplify expressions by collecting like terms, Multiply terms together
Video lesson: Simplifying expressionsComing soon
A school club buys pens and pencils. Tom writes the total cost as 3p + 2q + p + 5q, where p is the cost of one pen and q is the cost of one pencil. He simplifies it to make the total easier to read.

An expression is a mix of numbers, letters and operations. A term is a part of an expression, such as 3a, −2 or 5xy.

Like terms have the same letters with the same powers. 3a and 2a are like terms. 3a and 2b are not.

To simplify, collect the like terms: add or subtract their numbers in front, keeping the letters the same.

To multiply terms, multiply the numbers together and multiply the letters: 3x × 2y = 6xy.

Key ideas

  • Like terms have exactly the same letters.
  • Collect like terms by adding or subtracting the numbers in front.
  • Keep unlike terms separate. You cannot simplify 3a + 2b.
  • When multiplying, multiply the numbers and multiply the letters.
Worked example 5.1.1
Simplify 3a + 2b − a + 5b.

Method. Collect the like terms: add or subtract the numbers in front of the same letters.

  1. Collect the a terms. Terms with the same letters are like terms, so we can add their numbers.
    3a − a = 2a
  2. Collect the b terms. Terms with the same letters are like terms, so we can add their numbers.
    2b + 5b = 7b
  3. Write the answer. Put the collected terms together.
    2a + 7b

Check. Substitute x = 2 (or a = 2) into the question and into the answer. Both give the same number.

Watch out. Only like terms can be collected. a and a2 are not like terms, and 3a + 2b cannot be simplified further.

Worked example 5.1.2
Simplify 5x2 + 2x − 3x2 + x.

Method. Collect the like terms: add or subtract the numbers in front of the same letters.

  1. Collect the x2 terms. Terms with the same letters are like terms, so we can add their numbers.
    5x2 − 3x2 = 2x2
  2. Collect the x terms. Terms with the same letters are like terms, so we can add their numbers.
    2x + x = 3x
  3. Write the answer. Put the collected terms together.
    2x2 + 3x

Check. Substitute x = 2 (or a = 2) into the question and into the answer. Both give the same number.

Watch out. Only like terms can be collected. a and a2 are not like terms, and 3a + 2b cannot be simplified further.

Worked example 5.1.3
Simplify 3x × 2y.

Method. Multiply the numbers together, then multiply the letters. Add the powers of the same letter.

  1. Multiply the numbers. Multiply the numbers in front of the letters.
    3 × 2 = 6
  2. Multiply the letters. Write each letter once. If a letter appears twice, add the powers.
    x × y = xy
  3. Write the answer.
    6xy

Check. Check the numbers: 3 × 2 = 6, and the letters are the same letters as in the answer.

Watch out. Multiply the numbers and the letters separately. 3x × 2y is 6xy, not 5xy.

Watch out

Watch out: 3a + 2b is already as simple as it can be. You cannot add a and b together, because they are different letters.

Exam tip

Exam tip. Substitute a number for each letter into the question and your answer. If they give the same value, your simplifying is probably right.

Exercise 5A  Collecting like terms and multiplying

Non-calculator
1
FSimplify 3a + 2b − a + 5b.
2
FSimplify 4x − 3y + 2x + y.
3
FSimplify 5p − 2q − 3p − 4q.
4
FSimplify 7m + 3n − 7m.
5
FSimplify 3a + 2 + a − 5.
6
FSimplify 5x2 + 2x − 3x2 + x.
7
FSimplify 6c − 2d − 6c + 4d.
8
FSimplify 3x × 2y.
9
FSimplify 4a × 2b.
10
FSimplify 5p × 3q.
11
FSimplify 2m × 6n.
12
FSimplify 3x × −2y.
13
PSSimplify 4x + 3 − x + 5. Then find the value of your answer when x = 2.
14
PSWrite the perimeter of a rectangle with sides a, b, a and b, as simply as possible.
15
PSA shop sells x apples at 4p each and y pears at 5p each. Write the total cost in pence, simplifying where you can.
16
RAli says that 3a + 2b = 5ab. Is Ali right? Explain how you know.
17
PSSimplify 2x2 + 5x − x2 + 3x. Give your answer with the terms in order from the highest power.
18
RExplain why 2x2 and 2x are not like terms. Accept any answer that says the powers are different.
5.2

Expanding single brackets

Year 8
Expand single brackets and simplify, Multiply a term by a bracket
Video lesson: Expanding single bracketsComing soon
A rectangular garden is 2 metres longer than it is wide. Priya writes the area as x(x + 2), and she expands the bracket to find a simpler form for the area.

To expand a bracket, multiply every term inside the bracket by the number or letter outside.

For example: 3(x + 4) means 3 × x and 3 × 4, so 3(x + 4) = 3x + 12.

Be careful with negative numbers. −2(x + 4) = −2x − 8, because −2 × 4 = −8.

Key ideas

  • Multiply every term inside the bracket by the term outside.
  • The sign of each answer depends on the signs of both numbers.
  • A letter outside a bracket multiplies each term inside too: x(x + 3) = x² + 3x.
  • Collect like terms after expanding, if there are two brackets.
Worked example 5.2.1
Expand 3(x + 4).

Method. Multiply every term inside the bracket by the term outside it.

  1. Look at what is outside the bracket. Everything inside the bracket is multiplied by this.
    3(x + 4)
  2. Multiply each term inside by the outside term. Keep the signs. A minus times a minus is a plus.
    3 × x = 3x and 3 × 4 = 12
  3. Write the answer. Put the two products together.
    3x + 12

Check. Try x = 2: the bracket gives 6, and the outside gives 3, so the product is 18. The answer gives the same value at x = 2.

Watch out. Be careful with negative numbers: −2 × (−3) = +6, and −2 × (+3) = −6.

Worked example 5.2.2
Expand −2(x + 4).

Method. Multiply every term inside the bracket by the term outside it.

  1. Look at what is outside the bracket. Everything inside the bracket is multiplied by this.
    −2(x + 4)
  2. Multiply each term inside by the outside term. Keep the signs. A minus times a minus is a plus.
    −2 × x = −2x and −2 × 4 = −8
  3. Write the answer. Put the two products together.
    −2x − 8

Check. Try x = 2: the bracket gives 6, and the outside gives -2, so the product is -12. The answer gives the same value at x = 2.

Watch out. Be careful with negative numbers: −2 × (−3) = +6, and −2 × (+3) = −6.

Worked example 5.2.3
Expand x(x − 3).

Method. Multiply every term inside the bracket by the term outside it.

  1. Look at what is outside the bracket. Everything inside the bracket is multiplied by this.
    x(x − 3)
  2. Multiply each term inside by the outside term. Keep the signs. A minus times a minus is a plus.
    x × x = x2 and x × −3 = −3x
  3. Write the answer. Put the two products together.
    x2 − 3x

Check. Try x = 2: the bracket gives -1, and the outside gives 2, so the product is -2. The answer gives the same value at x = 2.

Watch out. Be careful with negative numbers: −2 × (−3) = +6, and −2 × (+3) = −6.

Watch out

Watch out: 3(x + 4) is 3x + 12, not 3x + 4. The 3 multiplies the 4 as well.

Exam tip

Exam tip. Write each product on its own line, so you do not miss a term. Check the signs at the end.

Exercise 5B  Expanding single brackets

Non-calculator
1
FExpand 3(x + 4).
2
FExpand 2(3x − 5).
3
FExpand −2(x + 4).
4
FExpand 5(2x − 1).
5
FExpand 4(2x + 3).
6
FExpand −3(2x − 1).
7
FExpand x(x − 3).
8
FExpand 2x(3x + 1).
9
FExpand −3(2x − 1).
10
FExpand 2(x + 3) + 3(x − 1). Simplify your answer.
11
FExpand 3(x + 2) − 2(x − 5). Simplify your answer.
12
PSA rectangle is x metres long and (x + 2) metres wide. Write its area as an expression, and expand it.
13
PSA rectangle has sides 2(2x + 3) and 2(x + 4). Write its perimeter in its simplest form.
14
PSA rectangular path is 4 metres wide and (x + 2) metres long. Write its area as an expression.
15
RAli says that 3(x + 4) = 3x + 4. Is Ali right? Explain how you know.
16
RExpand 5(2x − 3). Explain why the answer has a negative number.
17
PSExpand and simplify 4(x + 2) + 2(x + 1).
5.3

Expanding double brackets

Year 8
Expand double brackets such as (x + 3)(x − 2)
Video lesson: Expanding double bracketsComing soon
A square tile has side (x + 3) cm. Tom wants the area of the tile, so he multiplies two brackets: (x + 3)(x + 3). He does this by multiplying every term in the first bracket by every term in the second.

To expand two brackets, multiply each term in the first bracket by each term in the second bracket. This is often shown as FOIL: First, Outside, Inside, Last.

Then collect the like terms. For example (x + 3)(x + 2) = x2 + 2x + 3x + 6 = x2 + 5x + 6.

Key ideas

  • Multiply every term in the first bracket by every term in the second.
  • The x terms come from the outside and inside products.
  • Collect the x terms: 2x + 3x = 5x.
  • Check with a number: if x = 1, both sides should give the same value.
Worked example 5.3.1
Expand (x + 3)(x + 5).

Method. Multiply each term in the first bracket by each term in the second bracket, then collect like terms.

  1. Multiply the first terms. First term in each bracket.
    x × x = x2
  2. Multiply the outside terms. The first term of the first bracket with the second term of the second bracket.
    x × 5 = 5x
  3. Multiply the inside terms. The second term of the first bracket with the first term of the second bracket.
    3 × x = 3x
  4. Multiply the last terms. The second term of each bracket.
    3 × 5 = 15
  5. Collect the like terms. The two x terms are like terms, so add them.
    x2 + 8x + 15
  6. Write the answer.
    x2 + 8x + 15

Check. Try x = 1: the brackets give 24, and the answer gives 24.

Watch out. The x terms come from the outside and inside products. Do not forget the signs.

Worked example 5.3.2
Expand (x + 3)(x − 2).

Method. Multiply each term in the first bracket by each term in the second bracket, then collect like terms.

  1. Multiply the first terms. First term in each bracket.
    x × x = x2
  2. Multiply the outside terms. The first term of the first bracket with the second term of the second bracket.
    x × −2 = −2x
  3. Multiply the inside terms. The second term of the first bracket with the first term of the second bracket.
    3 × x = 3x
  4. Multiply the last terms. The second term of each bracket.
    3 × −2 = −6
  5. Collect the like terms. The two x terms are like terms, so add them.
    x2 + x − 6
  6. Write the answer.
    x2 + x − 6

Check. Try x = 1: the brackets give -4, and the answer gives -4.

Watch out. The x terms come from the outside and inside products. Do not forget the signs.

Worked example 5.3.3
Expand (2x + 1)(x + 4).

Method. Multiply each term in the first bracket by each term in the second bracket, then collect like terms.

  1. Multiply the first terms. First term in each bracket.
    2x × x = 2x2
  2. Multiply the outside terms. The first term of the first bracket with the second term of the second bracket.
    2x × 4 = 8x
  3. Multiply the inside terms. The second term of the first bracket with the first term of the second bracket.
    1 × x = x
  4. Multiply the last terms. The second term of each bracket.
    1 × 4 = 4
  5. Collect the like terms. The two x terms are like terms, so add them.
    2x2 + 9x + 4
  6. Write the answer.
    2x2 + 9x + 4

Check. Try x = 1: the brackets give 15, and the answer gives 15.

Watch out. The x terms come from the outside and inside products. Do not forget the signs.

Watch out

Watch out: (x + 3)(x + 3) is not x2 + 9. You must include the outside and inside products: x2 + 6x + 9.

Exam tip

Exam tip. Write all four products before you collect, and count them: there are always four products before you collect.

Exercise 5C  Expanding double brackets

Non-calculator
1
FExpand (x + 3)(x + 5).
2
FExpand (x + 3)(x − 2).
3
FExpand (x − 4)(x − 1).
4
FExpand (2x + 1)(x + 4).
5
FExpand (3x − 2)(x + 5).
6
FExpand (x + 6)(x − 6).
7
FExpand (2x + 3)(2x − 1).
8
FExpand (x + 2)(x + 2).
9
FExpand (2x − 5)(3x + 2).
10
FExpand (4x + 1)(x − 3).
11
PSA square has side (x + 3). Write its area as an expression in its simplest form.
12
PSA rectangle is (x + 5) cm long and (x + 3) cm wide. Write the area in its simplest form.
13
RExpand (x + 4)(x − 4). What do you notice about the answer?
14
RIs (x + 2)(x + 3) the same as x2 + 6? Explain your answer.
15
RShow that (x + 4)(x + 3) gives the same answer as (x + 3)(x + 4). Explain why.
16
PSExpand (2x − 5)(3x + 2).
5.4

Factorising by taking out a common factor

Year 8
Factorise by taking out the highest common factor
Video lesson: Factorising by taking out a common factorComing soon
A bag of 6x + 9 sweets is split between two shelves. Mia notices that every term can be divided by 3, so she writes the total as 3(2x + 3) to show the shelves more clearly.

To factorise an expression, write it as a product of two factors. Take out the highest common factor (HCF) of all the terms and write the rest inside a bracket.

Look for the highest common factor of the numbers, and any letters that are in every term. For example 6x + 9 has the HCF 3, so 6x + 9 = 3(2x + 3).

You can check your answer by expanding the brackets. You should get back the original expression.

Key ideas

  • The highest common factor (HCF) is the biggest number, and the highest shared letter power.
  • Divide each term by the HCF, and write the answers inside the brackets.
  • The factorised form is HCF(... + ...).
  • Check by expanding the brackets.
Worked example 5.4.1
Factorise 6x + 9.

Method. Find the highest common factor of the numbers and any letters that every term has. Take it outside the brackets.

  1. Find the common factor of the numbers. Find the biggest number that divides into every number.
    HCF of the numbers = 3
  2. Find any letters that every term has. The lowest power of each letter is in every term.
    common letter part = none
  3. Divide each term by the common factor. Write the results inside the brackets.
    6x + 9 ÷ (3) = 2x + 3
  4. Write the answer. Check by expanding the brackets.
    3(2x + 3)

Check. Expanding the brackets gives the original expression back.

Watch out. Take out the highest common factor, not just any factor. Check that every term has been divided.

Worked example 5.4.2
Factorise 8x2 − 12x.

Method. Find the highest common factor of the numbers and any letters that every term has. Take it outside the brackets.

  1. Find the common factor of the numbers. Find the biggest number that divides into every number.
    HCF of the numbers = 4
  2. Find any letters that every term has. The lowest power of each letter is in every term.
    common letter part = x
  3. Divide each term by the common factor. Write the results inside the brackets.
    8x2 − 12x ÷ (4x) = 2x − 3
  4. Write the answer. Check by expanding the brackets.
    4x(2x − 3)

Check. Expanding the brackets gives the original expression back.

Watch out. Take out the highest common factor, not just any factor. Check that every term has been divided.

Worked example 5.4.3
Factorise x2 + 4x.

Method. Find the highest common factor of the numbers and any letters that every term has. Take it outside the brackets.

  1. Find the common factor of the numbers. Find the biggest number that divides into every number.
    HCF of the numbers = 1
  2. Find any letters that every term has. The lowest power of each letter is in every term.
    common letter part = x
  3. Divide each term by the common factor. Write the results inside the brackets.
    x2 + 4x ÷ (1x) = x + 4
  4. Write the answer. Check by expanding the brackets.
    x(x + 4)

Check. Expanding the brackets gives the original expression back.

Watch out. Take out the highest common factor, not just any factor. Check that every term has been divided.

Watch out

Watch out: take out the highest common factor. 6x + 9 = 3(2x + 3) is correct. 6x + 9 = 1(6x + 9) is true, but it does not help.

Exam tip

Exam tip. If the answer is 3(2x + 3), expand it to check. If you get 6x + 9 back, your answer is right.

Exercise 5D  Factorising by common factors

Non-calculator
1
FFactorise 6x + 9.
2
FFactorise 8x − 12.
3
FFactorise 10x + 15.
4
FFactorise 12x − 18.
5
FFactorise x2 + 4x.
6
FFactorise 3x2 + 6x.
7
FFactorise 8x2 − 12x.
8
FFactorise 2x2 − 6x.
9
FFactorise 5x + 10.
10
FFactorise 9x − 6.
11
FFactorise 4x2 + 8.
12
FFactorise 6x2 − 9x.
13
FFactorise 12x2 + 8x.
14
PSFactorise 4x + 6, and check your answer by expanding.
15
PSA rectangle has an area of 6x + 9 cm2. Use factorising to find an expression for one possible width if the length is 3 cm.
16
PSFactorise fully 12x2 + 8x.
17
RAli says 6x + 9 = 3(2x + 3). Is Ali right? Explain how you know.
18
RExplain why 6x + 9 = 3(2x + 3) is the full factorisation, but 6x + 9 = 1(6x + 9) is not useful. Accept any answer that says the first takes out the highest common factor.
19
PSFactorise 5a2 − 15a. Then find the value of the expression when a = 4.
5.5

Factorising quadratics

Year 8
Factorise quadratics of the form x2 + bx + c, Check a factorisation by expanding
Video lesson: Factorising quadraticsComing soon
Sam is designing a rectangular poster with area x2 + 5x + 6 cm2. He wants to find the lengths of the sides, so he factorises the expression into two brackets.

A quadratic such as x2 + 5x + 6 can often be written as two brackets: (x + p)(x + q).

Find two numbers p and q that multiply to make c (the number at the end) and add to make b (the number in front of x).

For x2 + 5x + 6: the numbers must multiply to 6 and add to 5. They are 2 and 3, so x2 + 5x + 6 = (x + 2)(x + 3).

Key ideas

  • For x2 + bx + c, find p and q with pq = c and p + q = b.
  • Write the answer as (x + p)(x + q).
  • Watch the signs: a negative c means one of p and q is negative.
  • Check your answer by expanding the brackets.
Worked example 5.5.1
Factorise x2 + 5x + 6.

Method. Find two numbers that multiply to make c and add to make b. Then write them in two brackets with x.

  1. Write what we need. Two numbers that multiply to 6 and add to 5.
    multiply to 6, add to 5
  2. Find the two numbers. 2 and 3 work: 2 × 3 = 6 and 2 + 3 = 5.
    2 × 3 = 6, 2 + 3 = 5
  3. Write the brackets. Each number goes in its own bracket with x.
    (x + 2)(x + 3)
  4. Write the answer.
    (x + 2)(x + 3)

Check. Expanding (x + 2)(x + 3) gives x2 + 5x + 6, which is the original expression.

Watch out. Watch the signs. The two numbers can be negative. Check both the sum and the product.

Worked example 5.5.2
Factorise x2 + x − 6.

Method. Find two numbers that multiply to make c and add to make b. Then write them in two brackets with x.

  1. Write what we need. Two numbers that multiply to -6 and add to 1.
    multiply to -6, add to 1
  2. Find the two numbers. -2 and 3 work: -2 × 3 = -6 and -2 + 3 = 1.
    -2 × 3 = -6, -2 + 3 = 1
  3. Write the brackets. Each number goes in its own bracket with x.
    (x − 2)(x + 3)
  4. Write the answer.
    (x − 2)(x + 3)

Check. Expanding (x − 2)(x + 3) gives x2 + 1x − 6, which is the original expression.

Watch out. Watch the signs. The two numbers can be negative. Check both the sum and the product.

Worked example 5.5.3
Factorise x2 − 4x + 4.

Method. Find two numbers that multiply to make c and add to make b. Then write them in two brackets with x.

  1. Write what we need. Two numbers that multiply to 4 and add to -4.
    multiply to 4, add to -4
  2. Find the two numbers. -2 and -2 work: -2 × -2 = 4 and -2 + -2 = -4.
    -2 × -2 = 4, -2 + -2 = -4
  3. Write the brackets. Each number goes in its own bracket with x.
    (x − 2)(x − 2)
  4. Write the answer.
    (x − 2)(x − 2)

Check. Expanding (x − 2)(x − 2) gives x2 − 4x + 4, which is the original expression.

Watch out. Watch the signs. The two numbers can be negative. Check both the sum and the product.

Watch out

Watch out: the two numbers must multiply to c and add to b. For x2 + 5x + 6, the pair 1 and 6 multiplies to 6 but adds to 7, so it is wrong.

Exam tip

Exam tip. Expand your brackets to check. The middle term must come out as 5x, not something else.

Exercise 5E  Factorising quadratics

Non-calculator
1
FFactorise x2 + 5x + 6.
2
FFactorise x2 + 7x + 10.
3
FFactorise x2 − 5x + 6.
4
FFactorise x2 + 1x − 6.
5
FFactorise x2 − 2x − 15.
6
FFactorise x2 + 8x + 12.
7
FFactorise x2 − 9.
8
FFactorise x2 − 4x + 4.
9
FFactorise x2 + 6x + 8.
10
FFactorise x2 − 7x + 12.
11
FFactorise x2 + 4x + 3.
12
FFactorise x2 + 3x − 10.
13
PSFactorise x2 + 6x + 8. Then check by expanding.
14
PSA poster has area x2 + 5x + 6. Write the two side lengths, as brackets.
15
RShow that (x + 4)(x − 3) = x2 + x − 12.
16
RAli says x2 + 5x + 6 = (x + 1)(x + 6). Is Ali right? Explain how you know.
17
FFactorise x2 − 9.
18
FFactorise x2 − 2x − 15.
19
PSFactorise and expand to check: x2 − 7x + 12.
20
RExplain why x2 + 6x + 9 can be written as (x + 3)(x + 3). Check by expanding.

Chapter summary

SkillMethod
Collect like termsAdd or subtract the numbers in front of terms with the same letters
Expand a single bracketMultiply every term inside by the term outside: 3(x + 4) = 3x + 12
Expand double bracketsMultiply each term in one bracket by each term in the other, then collect
Factorise by a common factorTake out the highest common factor: 6x + 9 = 3(2x + 3)
Factorise x2 + bx + cFind p and q with pq = c and p + q = b, then write (x + p)(x + q)
CheckExpand your factorised answer to see you get the original expression back

Can you…?

  • I can collect like terms and simplify an expression
  • I can expand a single bracket, including with a negative number outside
  • I can expand two brackets, and collect the like terms
  • I can take out the highest common factor of an expression
  • I can factorise x2 + bx + c into two brackets
  • I can check a factorisation by expanding it

Key terms

term
a part of an expression, such as 3a, −2 or 5xy
like terms
terms with exactly the same letters and powers
expression
a collection of terms with numbers, letters and operations, with no equals sign
expand
multiply out the brackets
factorise
write an expression as a product, using brackets
highest common factor
the biggest number and highest letter power that divides every term
quadratic
an expression with x2 as its highest power

Exercise 5Z  Check-up

Non-calculator
1
Simplify 4p + 3q − 2p + q.
2
Simplify 4a × 3b.
3
Expand 5(x − 2).
4
Expand −4(3x + 1).
5
Expand x(2x + 5).
6
Expand (x + 2)(x + 7).
7
Expand (2x + 3)(x − 4).
8
Factorise 10x + 15.
9
Factorise 9x2 − 6x.
10
Factorise x2 + 7x + 12.

Total 28 marks. Allow about 28 minutes.

Exercise 5X  Exam-style questions

Non-calculator
1
FSimplify 3x + 5y − x + 2y.[2 marks]
2
FExpand 4(2x − 3).[2 marks]
3
FExpand (x + 4)(x + 5). Simplify your answer.[3 marks]
4
FExpand and simplify 3(x + 2) + 4(x − 1).[2 marks]
5
FFactorise fully 15x2 − 10x.[2 marks]
6
FFactorise x2 + 8x + 15.[3 marks]
7
FFactorise x2 − x − 12.[3 marks]
8
FA rectangle has length (x + 6) cm and width (x + 2) cm. Write its area in its simplest form.[3 marks]
9
FAli says that 2(x + 5) = 2x + 5. Explain why he is wrong, and write the correct answer.[2 marks]
10
FShow that (x + 4)(x − 2) = x2 + 2x − 8.[3 marks]
11
FExpand and simplify (2x + 1)(x + 3) − 2x2.[3 marks]

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