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KS3 Maths · Year 8Chapter 9 · Pythagoras and angles
Year 8 · Chapter 9

Pythagoras and angles

By the end of this chapter you will be able to

  • Use Pythagoras' theorem to find the longest side of a right-angled triangle, and give an exact answer
  • Use Pythagoras' theorem to find a shorter side, by subtracting the squares
  • Find missing angles in triangles, quadrilaterals and at a point, and explain each angle fact
  • Identify corresponding, alternate and co-interior angles, and find angles in parallel lines
  • Find the interior and exterior angles of regular polygons, and the number of sides from an angle

You should already know

  • Squares and square roots, and square numbers (Year 7 and Year 8, Chapter 2)
  • Angles on a straight line, at a point and in a triangle (Year 7)
  • Parallel lines and the names of the angles they make (Year 7)

Where this leads

  • Trigonometry in right-angled triangles, and the exact values of sine, cosine and tangent (Year 9 and GCSE)
  • Three-dimensional Pythagoras and its uses in coordinates (Year 9)
  • Circle theorems and proofs using angle facts (GCSE)

National Curriculum for England, Key Stage 3 mathematics, Year 8. Content: Find the hypotenuse of a right-angled triangle using Pythagoras' theorem, Find a shorter side of a right-angled triangle using Pythagoras' theorem, Use angles on a straight line, at a point, vertically opposite, in a triangle and in a quadrilateral, Use angles in parallel lines: corresponding, alternate and co-interior angles, Use the interior and exterior angles of polygons, and the angle sum of a polygon.

Exercise P  Do you remember?

Non-calculator
1
FWork out 62.
2
FWhat is √49?
3
FThe angles in a triangle add up to how many degrees?
4
FAngles on a straight line add up to how many degrees?
5
FWork out 5 + 12 × 0 + 32.
9.1

Finding the hypotenuse with Pythagoras' theorem

Year 8
Find the hypotenuse of a right-angled triangle using Pythagoras' theorem
Video lesson: Finding the hypotenuse with Pythagoras' theoremComing soon
A ramp rises 3 metres and goes 4 metres along the ground. Noah wants to know the length of the ramp itself, which is the longest side of the right-angled triangle formed.

In a right-angled triangle, the longest side is the hypotenuse. It is always opposite the right angle.

Pythagoras’ theorem says: c2 = a2 + b2, where c is the hypotenuse and a and b are the other two sides.

To find the hypotenuse: square the two shorter sides, add the squares, then take the square root.

abc

Key ideas

  • Pythagoras’ theorem only works for a right-angled triangle.
  • The hypotenuse is opposite the right angle, and it is the longest side.
  • To find the hypotenuse, add the squares of the two shorter sides, then take the square root.
  • Give an exact answer, such as √13, if the square root is not a whole number.
Worked example 9.1.1
A right-angled triangle has shorter sides 3 cm and 4 cm. Find the hypotenuse.

Method. Use Pythagoras' theorem: c2 = a2 + b2. Add the squares, then take the square root.

  1. Write the rule. The hypotenuse is the longest side, so c is the side opposite the right angle.
    c2 = a2 + b2
  2. Square the two shorter sides. Square 3 and 4.
    32 + 42 = 9 + 16
  3. Add. Add the two squares to find c2.
    c2 = 25
  4. Take the square root. c is the square root of the total.
    c = √25 = 5
  5. Write the answer.
    5

Check. Check: 5 squared is 25, which is the sum of the squares of the two shorter sides.

Watch out. Do not add the lengths. Square them first, add the squares, then take the square root.

Worked example 9.1.2
Find the hypotenuse of a right-angled triangle with shorter sides 2 cm and 3 cm. Give an exact answer.

Method. Use Pythagoras' theorem: c2 = a2 + b2. Add the squares, then take the square root.

  1. Write the rule. The hypotenuse is the longest side, so c is the side opposite the right angle.
    c2 = a2 + b2
  2. Square the two shorter sides. Square 2 and 3.
    22 + 32 = 4 + 9
  3. Add. Add the two squares to find c2.
    c2 = 13
  4. Take the square root. c is the square root of the total.
    c = √13 = √13
  5. Write the answer.
    √13

Check. Check: (√13)2 = 13, and 22 + 32 = 13.

Watch out. Do not add the lengths. Square them first, add the squares, then take the square root.

Worked example 9.1.3
Find the hypotenuse of a right-angled triangle with shorter sides 6 cm and 6 cm. Give your answer as a surd.

Method. Use Pythagoras' theorem: c2 = a2 + b2. Add the squares, then take the square root.

  1. Write the rule. The hypotenuse is the longest side, so c is the side opposite the right angle.
    c2 = a2 + b2
  2. Square the two shorter sides. Square 6 and 6.
    62 + 62 = 36 + 36
  3. Add. Add the two squares to find c2.
    c2 = 72
  4. Take the square root. c is the square root of the total.
    c = √72 = 6√2
  5. Write the answer.
    6√2

Check. Check: 6√2 squared is 36 × 2 = 72, which is correct.

Watch out. Do not add the lengths. Square them first, add the squares, then take the square root.

Watch out

Watch out: do not add the two shorter sides. 3 + 4 = 7, but 32 + 42 = 25, and √25 = 5.

Exam tip

Exam tip. Write the formula c2 = a2 + b2 first, then put in the numbers. Examiners often give a mark for the correct formula.

Exercise 9A  Finding the hypotenuse

Non-calculator
1
FA right-angled triangle has shorter sides 3 cm and 4 cm. Find the hypotenuse. Give an exact answer.
3 cm4 cmc
2
FA right-angled triangle has shorter sides 5 cm and 12 cm. Find the hypotenuse. Give an exact answer.
5 cm12 cmc
3
FA right-angled triangle has shorter sides 6 cm and 8 cm. Find the hypotenuse. Give an exact answer.
6 cm8 cmc
4
FA right-angled triangle has shorter sides 2 cm and 3 cm. Find the hypotenuse. Give an exact answer.
2 cm3 cmc
5
FA right-angled triangle has shorter sides 1 cm and 4 cm. Find the hypotenuse. Give an exact answer.
1 cm4 cmc
6
FA right-angled triangle has shorter sides 2 cm and 5 cm. Find the hypotenuse. Give an exact answer.
2 cm5 cmc
7
FA right-angled triangle has shorter sides 4 cm and 6 cm. Find the hypotenuse. Give an exact answer.
4 cm6 cmc
8
FA right-angled triangle has shorter sides 3 cm and 3 cm. Find the hypotenuse. Give an exact answer.
3 cm3 cmc
9
FA right-angled triangle has shorter sides 5 cm and 5 cm. Find the hypotenuse. Give an exact answer.
5 cm5 cmc
10
FA right-angled triangle has shorter sides 7 cm and 24 cm. Find the hypotenuse. Give an exact answer.
7 cm24 cmc
11
FA right-angled triangle has shorter sides 8 cm and 15 cm. Find the hypotenuse. Give an exact answer.
8 cm15 cmc
12
FA right-angled triangle has shorter sides 9 cm and 12 cm. Find the hypotenuse. Give an exact answer.
9 cm12 cmc
13
FA right-angled triangle has shorter sides 1 cm and 1 cm. Find the hypotenuse. Give an exact answer.
1 cm1 cmc
14
PSThe shorter sides of a right-angled triangle are 6 cm and 6 cm. Find the hypotenuse as a surd.
15
PSA rectangle is 12 cm long and 5 cm wide. Find the length of its diagonal.
16
RAli says the hypotenuse of a triangle with sides 3 and 4 is 7. Is Ali right? Explain how you know.
17
RA right-angled triangle has shorter sides 2 cm and 2 cm. Is the hypotenuse a whole number? Explain.
18
PSA ladder of length 10 m is placed against a wall. The foot of the ladder is 6 m from the wall. How high up the wall does the ladder reach? Use the hypotenuse to explain.
19
PSA kite string is 13 m long and the kite is 5 m high above the ground. Find the horizontal distance from the kite to the person holding the string, assuming a right-angled triangle.
20
FFind the hypotenuse of a right-angled triangle with shorter sides 8 cm and 15 cm.
21
FA right-angled triangle has shorter sides 4 cm and 5 cm. Find the hypotenuse, as a surd.
9.2

Finding a shorter side with Pythagoras' theorem

Year 8
Find a shorter side of a right-angled triangle using Pythagoras' theorem
Video lesson: Finding a shorter side with Pythagoras' theoremComing soon
A tent pole is 5 m long, and the pole reaches the top of the tent. The base of the tent is 3 m across from the middle. Priya works out how high the top is, using Pythagoras’ theorem.

When a shorter side is missing, rearrange the rule: b2 = c2 − a2.

Subtract the square of the known shorter side from the square of the hypotenuse. Then take the square root.

Key ideas

  • When a shorter side is missing: b2 = c2 − a2.
  • The hypotenuse is always the biggest side, so the answer must be smaller than c.
  • Subtract the squares; do not subtract the lengths.
  • Give an exact answer, such as 2√10, if the number is not a square.
Worked example 9.2.1
A right-angled triangle has hypotenuse 13 cm and one shorter side 5 cm. Find the other shorter side.

Method. Rearrange Pythagoras' theorem to find the shorter side: b2 = c2 − a2.

  1. Write the rule. The hypotenuse c is the longest side, so subtract the known shorter side squared.
    b2 = c2 − a2
  2. Square and subtract. Square 13 and 5, then subtract.
    132 − 52 = 169 − 25 = 144
  3. Take the square root. b is the square root of the result.
    b = √144 = 12
  4. Write the answer.
    12

Check. Check: 132 = 52 + (12)2, which is 169 = 25 + 144.

Watch out. Subtract the squares: the hypotenuse is always the biggest. Check your answer is smaller than c.

Worked example 9.2.2
A right-angled triangle has hypotenuse 10 cm and one shorter side 6 cm. Find the other shorter side.

Method. Rearrange Pythagoras' theorem to find the shorter side: b2 = c2 − a2.

  1. Write the rule. The hypotenuse c is the longest side, so subtract the known shorter side squared.
    b2 = c2 − a2
  2. Square and subtract. Square 10 and 6, then subtract.
    102 − 62 = 100 − 36 = 64
  3. Take the square root. b is the square root of the result.
    b = √64 = 8
  4. Write the answer.
    8

Check. Check: 102 = 62 + (8)2, which is 100 = 36 + 64.

Watch out. Subtract the squares: the hypotenuse is always the biggest. Check your answer is smaller than c.

Worked example 9.2.3
A right-angled triangle has hypotenuse 7 cm and one shorter side 3 cm. Find the other shorter side as a surd.

Method. Rearrange Pythagoras' theorem to find the shorter side: b2 = c2 − a2.

  1. Write the rule. The hypotenuse c is the longest side, so subtract the known shorter side squared.
    b2 = c2 − a2
  2. Square and subtract. Square 7 and 3, then subtract.
    72 − 32 = 49 − 9 = 40
  3. Take the square root. b is the square root of the result.
    b = √40 = 2√10
  4. Write the answer.
    2√10

Check. Check: 72 = 32 + (2√10)2, which is 49 = 9 + 40.

Watch out. Subtract the squares: the hypotenuse is always the biggest. Check your answer is smaller than c.

Watch out

Watch out: do not add the squares when a shorter side is missing. Subtract: 132 − 52, not 132 + 52.

Exam tip

Exam tip. Check your answer is smaller than the hypotenuse. If it is bigger, you have added instead of subtracted.

Exercise 9B  Finding a shorter side

Non-calculator
1
FA right-angled triangle has hypotenuse 13 cm and one shorter side 5 cm. Find the other shorter side. Give an exact answer.
5 cm?13 cm
2
FA right-angled triangle has hypotenuse 10 cm and one shorter side 6 cm. Find the other shorter side. Give an exact answer.
6 cm?10 cm
3
FA right-angled triangle has hypotenuse 17 cm and one shorter side 8 cm. Find the other shorter side. Give an exact answer.
8 cm?17 cm
4
FA right-angled triangle has hypotenuse 7 cm and one shorter side 3 cm. Find the other shorter side. Give an exact answer.
3 cm?7 cm
5
FA right-angled triangle has hypotenuse 6 cm and one shorter side 4 cm. Find the other shorter side. Give an exact answer.
4 cm?6 cm
6
FA right-angled triangle has hypotenuse 15 cm and one shorter side 9 cm. Find the other shorter side. Give an exact answer.
9 cm?15 cm
7
FA right-angled triangle has hypotenuse 5 cm and one shorter side 2 cm. Find the other shorter side. Give an exact answer.
2 cm?5 cm
8
FA right-angled triangle has hypotenuse 25 cm and one shorter side 7 cm. Find the other shorter side. Give an exact answer.
7 cm?25 cm
9
FA right-angled triangle has hypotenuse 9 cm and one shorter side 4 cm. Find the other shorter side. Give an exact answer.
4 cm?9 cm
10
FA right-angled triangle has hypotenuse 13 cm and one shorter side 12 cm. Find the other shorter side. Give an exact answer.
12 cm?13 cm
11
FA right-angled triangle has hypotenuse 12 cm and one shorter side 5 cm. Find the other shorter side. Give an exact answer.
5 cm?12 cm
12
PSA ladder of length 10 m leans against a wall with its foot 6 m from the wall. How high up the wall does it reach?
13
PSThe diagonal of a rectangle is 13 cm. One side is 12 cm. Find the other side.
14
PSA right-angled triangle has hypotenuse 6 cm and one shorter side 4 cm. Find the other shorter side as a surd.
15
RAli says that a triangle with shorter sides 3 cm and 4 cm has a hypotenuse of 5 cm. Sam says that a triangle with a hypotenuse of 5 cm and a shorter side of 3 cm has the other side 4 cm. Who is right, if either? Explain.
16
RA right-angled triangle has hypotenuse 5 cm and a shorter side of 5 cm. Can this be a right-angled triangle? Explain.
17
FA right-angled triangle has hypotenuse 17 cm and one shorter side 8 cm. Find the other shorter side.
18
FA right-angled triangle has hypotenuse 7 cm and one shorter side 3 cm. Find the other side, as an exact answer.
19
PSA 15 m wire is fixed to the top of a 9 m pole, and the other end is on the ground. How far from the pole is the wire fixed to the ground?
9.3

Angles in triangles, quadrilaterals and at a point

Year 8
Use angles on a straight line, at a point, vertically opposite, and in a triangle and quadrilateral
Video lesson: Angles in triangles, quadrilaterals and at a pointComing soon
A garden gate has a triangular frame. Tom knows two of the angles of the frame, and he wants to find the third one before he cuts the wood.

Some angle facts are always true:

ABC

Key ideas

  • Triangle: the angles add up to 180°.
  • Quadrilateral: the angles add up to 360°.
  • Straight line: 180°. Full turn at a point: 360°.
  • Vertically opposite angles are equal.
Worked example 9.3.1
In a triangle, two angles are 62° and 48°. Find the third angle.

Method. The angles in a triangle add up to 180°.

  1. Add the two known angles. 62° + 48° = 110°.
    62 + 48 = 110
  2. Subtract from 180°. The third angle is what is left.
    180 − 110 = 70
  3. Write the answer.
    70°

Check. 62 + 48 + 70 = 180.

Worked example 9.3.2
Find the missing angle in a quadrilateral with angles 85°, 110°, 95° and x.

Method. The angles in a quadrilateral add up to 360°.

  1. Add the three known angles. 85° + 110° + 95° = 290°.
    85 + 110 + 95 = 290
  2. Subtract from 360°. The fourth angle is what is left.
    360 − 290 = 70
  3. Write the answer.
    70°

Check. 85 + 110 + 95 + 70 = 360.

Worked example 9.3.3
Two straight lines cross. One angle is 38°. Find the angle opposite it.

Method. Vertically opposite angles are equal.

  1. Look for the opposite angle. The angle x is opposite the angle given, at the same point.
    x is opposite 38°
  2. Check the angles on a straight line. The two angles next to x each make a straight line with a, so they are both 180 − a.
    180 − 38 = 142
  3. Write the answer. Vertically opposite angles are equal.
    38°

Check. The two lines cross, and the opposite angles are the same.

Watch out

Watch out: a triangle has 180° and a quadrilateral has 360°. Do not use the same total for both.

Exam tip

Exam tip. Give a reason with each angle: “angles in a triangle add to 180°”. This earns the reason mark.

Exercise 9C  Angles in triangles, quadrilaterals and at a point

Non-calculator
1
FTwo angles of a triangle are 62° and 48°. Find the third angle.
2
FTwo angles of a triangle are 35° and 85°. Find the third angle.
3
FTwo angles of a triangle are 90° and 30°. Find the third angle.
4
FTwo angles of a triangle are 40° and 75°. Find the third angle.
5
FTwo angles of a triangle are 25° and 25°. Find the third angle.
6
FTwo angles of a triangle are 70° and 50°. Find the third angle.
7
FThree angles of a quadrilateral are 85°, 110° and 95°. Find the fourth angle.
8
FThree angles of a quadrilateral are 90°, 90° and 60°. Find the fourth angle.
9
FThree angles of a quadrilateral are 70°, 80° and 100°. Find the fourth angle.
10
FAn angle on a straight line is 130°. Find the other angle on the line.
11
FAngles at a point are 90°, 120° and x. Find x.
12
FAngles around a point are 100°, 80°, 70° and x. Find x.
13
FTwo lines cross. One angle is 38°. Find the angle x opposite it.
14
PSA triangle is isosceles with a base angle of 40° at the bottom of each side? Find the top angle, if the two base angles are equal and each is 55°.
15
PSA triangle has angles x, 2x and 3x. Find x.
16
PSFind the size of angle x in a quadrilateral with angles x, x, 60° and 120°.
17
RAli says that vertically opposite angles are always supplementary (add up to 180°). Is Ali right? Explain.
18
RIn a triangle, one angle is a right angle (90°) and another is 35°. Find the third angle. Explain why it is a right-angled triangle.
9.4

Angles in parallel lines

Year 8
Use corresponding, alternate and co-interior angles in parallel lines
Video lesson: Angles in parallel linesComing soon
A railway line has two parallel tracks. A straight road crosses both tracks. Ali measures one of the angles where the road crosses the first track, and uses the parallel-lines rules to find the others.

When a straight line (a transversal) crosses two parallel lines, it makes several angles that are related:

parallel65°x

Key ideas

  • Corresponding angles (F shape) are equal.
  • Alternate angles (Z shape) are equal.
  • Co-interior angles (C shape) add up to 180°.
  • The lines must be parallel for these rules to work.
Worked example 9.4.1
A transversal crosses two parallel lines. One angle is 65°. Find the corresponding angle.

Method. Corresponding angles are equal when the lines are parallel.

  1. Name the rule. Corresponding angles are equal.
    x = 65
  2. Check the position. The angles are in matching positions (an F shape or a Z shape) on the two parallel lines.
    F or Z shape
  3. Write the answer.
    65°

Check. The corresponding angle has the same size, because the lines are parallel.

Worked example 9.4.2
One alternate angle is 40°. Find the other alternate angle.

Method. Alternate angles are equal when the lines are parallel.

  1. Name the rule. Alternate angles are equal.
    x = 40
  2. Check the position. The angles are in matching positions (an F shape or a Z shape) on the two parallel lines.
    F or Z shape
  3. Write the answer.
    40°

Check. The alternate angle has the same size, because the lines are parallel.

Worked example 9.4.3
Two co-interior angles are between parallel lines. One is 110°. Find the other.

Method. Co-interior angles (between the parallel lines, on the same side of the transversal) add up to 180°.

  1. Name the rule. Co-interior angles add up to 180°.
    110 + x = 180
  2. Subtract. Take 110° from 180°.
    180 − 110 = 70
  3. Write the answer.
    70°

Check. 110 + 70 = 180.

Watch out

Watch out: co-interior angles add up to 180°, but corresponding and alternate angles are equal. Check the letter shape.

Exam tip

Exam tip. Write the name of the rule, such as “alternate angles are equal”. A reason is needed for full marks.

Exercise 9D  Parallel lines

Non-calculator
1
FThe parallel lines are crossed by a transversal. One corresponding angle is 65°. Find the other angle x.
parallel65°x
2
FThe parallel lines are crossed by a transversal. One alternate angle is 40°. Find the other angle x.
parallel40°x
3
FThe parallel lines are crossed by a transversal. One co-interior angle is 110°. Find the other angle x.
parallel110°x
4
FThe parallel lines are crossed by a transversal. One co-interior angle is 75°. Find the other angle x.
parallel75°x
5
FThe parallel lines are crossed by a transversal. One corresponding angle is 120°. Find the other angle x.
parallel120°x
6
FThe parallel lines are crossed by a transversal. One alternate angle is 55°. Find the other angle x.
parallel55°x
7
FThe parallel lines are crossed by a transversal. One co-interior angle is 60°. Find the other angle x.
parallel60°x
8
FThe parallel lines are crossed by a transversal. One corresponding angle is 98°. Find the other angle x.
parallel98°x
9
PSIn a diagram with parallel lines, a corresponding angle is 72°. Find the alternate angle to it.
10
PSFind the co-interior angle to 105°, between parallel lines.
11
RAli says that two co-interior angles between parallel lines are equal. Is Ali right? Explain.
12
PSThe angles 2x and 80° are alternate angles between parallel lines. Find x.
13
PSThe angles x and 3x are co-interior angles between parallel lines. Find x.
14
PSA corresponding angle between parallel lines is (2x + 10)°, and the other corresponding angle is 70°. Find x.
15
RExplain why the angle x and the angle 115° in a parallel-lines diagram must add up to 180°, when they are co-interior. Find x.
16
RA transversal makes an angle of 60° with one parallel line. What is the alternate angle on the other parallel line? Explain your reason.
9.5

Interior and exterior angles of polygons

Year 8
Use the interior and exterior angles of polygons, and the angle sum of a polygon
Video lesson: Interior and exterior angles of polygonsComing soon
A garden designer uses a regular pentagon to make a flower bed. She needs to know the angle at each corner, so she can cut the edging.

A polygon is a closed shape with straight sides. A regular polygon has all sides and all angles equal.

Key ideas

  • Sum of the interior angles: (n − 2) × 180°.
  • Sum of the exterior angles: 360° (for every polygon).
  • Regular polygon: each exterior angle = 360° ÷ n.
  • Interior angle = 180° − exterior angle.
Worked example 9.5.1
Find the sum of the interior angles of a heptagon (7 sides).

Method. Use the rule for the sum of the interior angles: (n − 2) × 180°.

  1. Write the rule. For a polygon with n sides.
    (n − 2) × 180
  2. Put in n. The polygon has 7 sides.
    (7 − 2) × 180
  3. Work it out. Subtract 2 and multiply by 180.
    5 × 180 = 900
  4. Write the answer.
    900°

Check. Split the polygon into 5 triangles, each with 180°.

Worked example 9.5.2
Find each interior angle of a regular pentagon.

Method. The interior angles of a polygon with n sides add up to (n − 2) × 180°. A regular polygon has equal angles.

  1. Find the sum of the interior angles. Use (n − 2) × 180 with n = 5.
    (5 − 2) × 180 = 540
  2. Share the sum equally (regular polygon). There are 5 equal angles.
    540 ÷ 5 = 108
  3. Write the answer.
    108°

Check. The exterior angle is 180 − 108 = 72, and 5 × 72 = 360.

Worked example 9.5.3
Each exterior angle of a regular polygon is 40°. How many sides does it have?

Method. Use the exterior angle: n = 360 ÷ (exterior angle).

  1. Write the rule. The number of sides is 360 divided by one exterior angle.
    n = 360 ÷ 40
  2. Divide. Work out how many exterior angles fit into 360°.
    360 ÷ 40 = 9
  3. Write the answer.
    9 sides

Check. 9 × 40 = 360.

Watch out

Watch out: the exterior angles of ANY polygon add up to 360°. The interior angles depend on the number of sides.

Exam tip

Exam tip. Write the rule first: (n − 2) × 180 or 360 ÷ n. Put in the number of sides last.

Exercise 9E  Interior and exterior angles of polygons

Non-calculator
1
FFind the exterior angle of a regular polygon with 5 sides.
2
FFind the exterior angle of a regular polygon with 6 sides.
3
FFind the exterior angle of a regular polygon with 8 sides.
4
FFind the exterior angle of a regular polygon with 10 sides.
5
FFind each interior angle of a regular polygon with 5 sides.
6
FFind each interior angle of a regular polygon with 6 sides.
7
FFind each interior angle of a regular polygon with 8 sides.
8
FFind the sum of the interior angles of a polygon with 7 sides.
9
FFind the sum of the interior angles of a polygon with 9 sides.
10
PSEach exterior angle of a regular polygon is 40°. How many sides does it have?
11
PSEach exterior angle of a regular polygon is 30°. How many sides does it have?
12
PSEach interior angle of a regular polygon is 150°. Find the number of sides, using the exterior angle.
13
PSA regular polygon has interior angles of 135°. Find the number of sides.
14
RThe interior angles of a hexagon add up to 720°. Ali says that a hexagon is a regular polygon with each interior angle 120°. Is Ali right? Explain.
15
RExplain why the exterior angles of any polygon add up to 360°, even if the polygon is not regular. Accept any answer that uses a turn around the polygon.

Chapter summary

SkillMethod
Pythagoras (hypotenuse)c2 = a2 + b2: add the squares, then square root
Pythagoras (shorter side)b2 = c2 − a2: subtract the squares, then square root
TriangleAngles add up to 180°
QuadrilateralAngles add up to 360°
Straight line and point180° on a straight line; 360° around a point
Parallel linesCorresponding and alternate angles are equal; co-interior angles add to 180°
PolygonsInterior sum (n − 2) × 180°; exterior 360°; regular exterior = 360° ÷ n

Can you…?

  • I can find the hypotenuse of a right-angled triangle, and give an exact answer
  • I can find a shorter side, by subtracting the squares
  • I can find missing angles in triangles, quadrilaterals and at a point
  • I can name corresponding, alternate and co-interior angles, and use them
  • I can find the interior and exterior angles of a regular polygon

Key terms

hypotenuse
the longest side of a right-angled triangle, opposite the right angle
transversal
a line that crosses two or more other lines
corresponding angles
angles in the same position at each crossing; they are equal for parallel lines
alternate angles
angles on opposite sides of the transversal; they are equal for parallel lines
co-interior angles
angles on the same side of the transversal, between parallel lines; they add to 180°
polygon
a closed shape with straight sides
regular polygon
a polygon with all sides and all angles equal

Exercise 9Z  Check-up

Non-calculator
1
Find the hypotenuse of a right-angled triangle with shorter sides 5 cm and 12 cm.
2
Find the hypotenuse of a right-angled triangle with shorter sides 1 cm and 2 cm. Give an exact answer.
3
A right-angled triangle has hypotenuse 10 cm and one shorter side 8 cm. Find the other shorter side.
4
A right-angled triangle has hypotenuse 9 cm and one shorter side 4 cm. Find the other shorter side, as an exact answer.
5
Two angles of a triangle are 74° and 56°. Find the third angle.
6
An angle on a straight line is 115°. Find the other angle on the line.
7
Angles at a point are 110°, 95° and x. Find x.
8
Two parallel lines are crossed by a transversal. A corresponding angle is 82°. Find the alternate angle.
9
Find the sum of the interior angles of a polygon with 8 sides.
10
Each exterior angle of a regular polygon is 45°. How many sides does it have?

Total 28 marks. Allow about 28 minutes.

Exercise 9X  Exam-style questions

Non-calculator
1
FA right-angled triangle has shorter sides 3 cm and 6 cm. Find the hypotenuse, as an exact answer.[2 marks]
2
FThe hypotenuse of a right-angled triangle is 15 cm and one shorter side is 12 cm. Find the other shorter side.[2 marks]
3
FFind the size of the angle x in a triangle with angles 40°, 65° and x.[2 marks]
4
FTwo angles on a straight line are x and 3x. Find x.[3 marks]
5
FFind the size of each exterior angle of a regular octagon.[2 marks]
6
FA regular polygon has interior angles of 140°. How many sides does it have? Show your working.[3 marks]
7
FIn a diagram, two parallel lines are crossed by a transversal. One co-interior angle is 118°. Find the other co-interior angle.[2 marks]
8
FA triangle has a right angle and one angle of 52°. Find the third angle.[2 marks]
9
FA quadrilateral has angles 80°, 100°, 110° and x. Find x, and explain which fact you used.[3 marks]
10
FFind the size of one interior angle of a regular decagon (10 sides).[4 marks]
11
FA ladder reaches a window 8 m high. The foot of the ladder is 6 m from the wall. Find the length of the ladder.[3 marks]

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