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KS3 Maths · Year 9Chapter 1 · Indices and surds
Year 9 · Chapter 1

Indices and surds

By the end of this chapter you will be able to

  • Read a fractional index as a root and a power, and find its value
  • Use negative indices to write reciprocals, and work out their values
  • Simplify surds and add or subtract like surds
  • Multiply and expand brackets that contain surds, and simplify the result
  • Extension: rationalise a denominator with a single surd or a conjugate pair

You should already know

  • Index notation and the index laws with whole-number powers (Year 8, Chapter 1)
  • Square and cube numbers, and square roots (Year 8, Chapter 2)
  • Simplifying a surd such as √50 = 5√2 and multiplying two brackets (Year 8, Chapters 2 and 5)

Where this leads

  • Standard form and bounds (Year 9, Chapter 2)
  • Quadratic expressions and the difference of two squares (Year 9, Chapter 4)
  • Algebraic index laws with letters (GCSE)

National Curriculum for England, Key Stage 3 mathematics, Year 9. Content: Use fractional indices, such as 8(1/3) and 9(3/2), and move between root and index forms, Use negative and fractional index laws in calculations, Simplify surds, add and subtract like surds, and multiply and expand brackets containing surds, Extension: rationalise a denominator.

Exercise P  Do you remember?

Non-calculator
1
FWork out 2 × 2 × 2 × 2.
2
FWrite 5 × 5 × 5 in index form.
3
FWhat is the square root of 81?
4
FWhat is the cube root of 8?
5
RIs 50 a square number? Explain how you know.
1.1

Fractional indices as roots

Year 9
Use fractional indices, and move between root and index forms
Video lesson: Fractional indices as rootsComing soon
A cube-shaped water tank holds 216 litres. Its side length is the cube root of 216. Engineers write this as 216(1/3), using a fraction as the index.

A fractional index tells us to take a root. The index 1/2 means the square root, and 1/3 means the cube root. In general, a(1/n) is the n-th root of a.

Here is the idea with 8(1/3). We need a number that, multiplied by itself three times, gives 8. That number is 2, so 8(1/3) = 2.

Key ideas

  • a(1/2) is the square root of a: 9(1/2) = √9 = 3.
  • a(1/3) is the cube root of a: 27(1/3) = 3.
  • The denominator of the index tells you which root to take.
  • Brackets keep the fraction together in the index: 8(1/3).
Worked example 1.1.1
Work out 16(1/4).

Method. Work out the root from the denominator, then the power from the numerator. The index (1/4) is the fourth root of 16, with the power 1.

  1. Use the denominator as the root. The denominator 4 means the fourth root. The numerator is the power.
    16(1/4) = (fourth root of 16)1
  2. Find the root. 2 multiplied by itself 4 times gives 16, so 2 is the fourth root.
    2 × 2 × 2 × 2 = 16, so the fourth root of 16 is 2
  3. Raise the root to the power. The numerator is 1, so raise 2 to the power 1.
    21 = 2
  4. Write the answer.
    2

Check. The fourth root of 16 is 2, and 21 = 2.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Worked example 1.1.2
Work out 125(1/3).

Method. Work out the root from the denominator, then the power from the numerator. The index (1/3) is the cube root of 125, with the power 1.

  1. Use the denominator as the root. The denominator 3 means the cube root. The numerator is the power.
    125(1/3) = (cube root of 125)1
  2. Find the root. 5 multiplied by itself 3 times gives 125, so 5 is the cube root.
    5 × 5 × 5 = 125, so the cube root of 125 is 5
  3. Raise the root to the power. The numerator is 1, so raise 5 to the power 1.
    51 = 5
  4. Write the answer.
    5

Check. The cube root of 125 is 5, and 51 = 5.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Worked example 1.1.3
Write the cube root of 64 using an index.

Method. The cube root of a number is the same as raising it to the power 1/3.

  1. Read the root. This is the cube root of 64.
    3√64
  2. Write the root as a power. The cube root is the power 1/3.
    641/3 = 3√64
  3. Write the answer. Brackets keep the 1/n together.
    64(1/3)

Check. Raising 64(1/3) to the power 3 gives 64.

Watch out. Keep the 1/ in brackets. Without brackets 31/2 can be misread.

Watch out

Watch out: 8(1/3) is not 8 ÷ 3. The index tells you to find a root, so 8(1/3) = 2, not 2.67.

Exam tip

Exam tip. If you cannot see the root straight away, list the powers: 23 = 8, 33 = 27, 43 = 64.

Exercise 1A  Fractional indices as roots

Non-calculator
1
FWork out 9(1/2).
2
FWork out 27(1/3).
3
FWork out 64(1/3).
4
FWork out 16(1/2).
5
FWork out 32(1/5).
6
FWork out 81(1/4).
7
FWork out 1000(1/3).
8
FWork out 100(1/2).
9
FWork out each part.
(a)4(1/2)
(b)8(1/3)
(c)16(1/4)
10
FWrite the cube root of 64 using a fractional index.
11
FWrite √7 using a fractional index.
12
PSA cube has a volume of 216 cm3. Its side length is 216(1/3) cm. Work out the side length. Give your answer in cm.
13
RExplain why 64(1/2) is 8 and not 32.
14
PSWork out each part.
(a)49(1/2)
(b)49(1/2) × 2
1.2

Fractional indices with a numerator

Year 9
Use fractional indices with a numerator, as roots and powers
Video lesson: Fractional indices with a numeratorComing soon
A square garden has an area of 9 m2. Sam wants to find the length of its side and then cube that length to compare with a box. He writes 9(3/2) for the cube of the side length.

An index such as m/n has two parts. The denominator n tells you to take the n-th root. The numerator m tells you to raise the answer to the power m. Do the root first, because it keeps the numbers small.

So 8(2/3) means the cube root of 8, which is 2, and then squared: 22 = 4.

Key ideas

  • a(m/n) = (n-th root of a)m. Find the root first, then the power.
  • The denominator is the root. The numerator is the power.
  • Working with the root first keeps the numbers small: 9(3/2) = 33 = 27.
  • The answer for a positive index is always positive.
Worked example 1.2.1
Work out 8(2/3).

Method. Work out the root from the denominator, then the power from the numerator. The index (2/3) is the cube root of 8, with the power 2.

  1. Use the denominator as the root. The denominator 3 means the cube root. The numerator is the power.
    8(2/3) = (cube root of 8)2
  2. Find the root. 2 multiplied by itself 3 times gives 8, so 2 is the cube root.
    2 × 2 × 2 = 8, so the cube root of 8 is 2
  3. Raise the root to the power. The numerator is 2, so raise 2 to the power 2.
    22 = 4
  4. Write the answer.
    4

Check. The cube root of 8 is 2, and 22 = 4.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Worked example 1.2.2
Work out 9(3/2).

Method. Work out the root from the denominator, then the power from the numerator. The index (3/2) is the square root of 9, with the power 3.

  1. Use the denominator as the root. The denominator 2 means the square root. The numerator is the power.
    9(3/2) = (square root of 9)3
  2. Find the root. 3 multiplied by itself 2 times gives 9, so 3 is the square root.
    3 × 3 = 9, so the square root of 9 is 3
  3. Raise the root to the power. The numerator is 3, so raise 3 to the power 3.
    33 = 27
  4. Write the answer.
    27

Check. The square root of 9 is 3, and 33 = 27.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Worked example 1.2.3
Work out 16(3/4).

Method. Work out the root from the denominator, then the power from the numerator. The index (3/4) is the fourth root of 16, with the power 3.

  1. Use the denominator as the root. The denominator 4 means the fourth root. The numerator is the power.
    16(3/4) = (fourth root of 16)3
  2. Find the root. 2 multiplied by itself 4 times gives 16, so 2 is the fourth root.
    2 × 2 × 2 × 2 = 16, so the fourth root of 16 is 2
  3. Raise the root to the power. The numerator is 3, so raise 2 to the power 3.
    23 = 8
  4. Write the answer.
    8

Check. The fourth root of 16 is 2, and 23 = 8.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Watch out

Watch out: 8(2/3) is not 82 ÷ 3. Take the cube root of 8 first, which is 2, and then square it, to get 4.

Exam tip

Exam tip. Write the root and the power separately, as in the examples. This avoids mixing up the numerator and denominator.

Exercise 1B  Fractional indices with a numerator

Non-calculator
1
FWork out 9(3/2).
2
FWork out 8(2/3).
3
FWork out 16(3/4).
4
FWork out 25(3/2).
5
FWork out 27(2/3).
6
FWork out 32(2/5).
7
FWork out 64(5/6).
8
FWork out 4(5/2).
9
FWork out 1000(2/3).
10
FWork out 81(3/4).
11
FWork out 8(4/3).
12
RShow that 27(2/3) = 9.
13
PSA cube has a volume of 27 cm3. Its face area is 27(2/3) cm2. Work out the face area.
14
PSA square has area 25 m2. Work out 25(3/2), the side length cubed, in m3.
1.3

Negative indices

Year 9
Use negative indices, and negative fractional indices, in calculations
Video lesson: Negative indicesComing soon
A shop sells 1 bag of rice for every 2-3 kilograms of rice it has left over. A negative index tells us to take a reciprocal. The shop manager writes 2-3 to show the amount of rice in one sack.

A negative index means one over the matching positive power. So 2(-3) = 1 ÷ 23 = 1/8.

A negative fractional index does both jobs. For 4(-1/2), work out the square root first: √4 = 2, then take the reciprocal: 4(-1/2) = 1/2.

Key ideas

  • a(−n) = 1 ÷ an. A negative index gives a reciprocal.
  • a(−m/n) = 1 ÷ (n-th root of a)m.
  • A negative index does not make the answer negative.
  • The index laws still work: 2(-3) × 25 = 22 = 4.
Worked example 1.3.1
Work out 2(-3).

Method. A negative index gives a reciprocal: work out the positive power, then flip it to a fraction.

  1. Read the negative index. A negative index means one over the matching positive power.
    2−3 = 1 / 23
  2. Work out the positive power. 2 multiplied by itself 3 times.
    23 = 8
  3. Write the answer. The fraction has 1 on top.
    1/8

Check. 23 = 8, so the reciprocal is 1/8 = 1/8.

Watch out. A negative index does not make the answer negative. It makes it a small fraction.

Worked example 1.3.2
Work out 4(-1/2).

Method. Work out the root from the denominator, then the power from the numerator. The index (−1/2) is the square root of 4, with the power 1 flipped to a fraction.

  1. Use the denominator as the root. The denominator 2 means the square root. The numerator is the power.
    4(−1/2) = 1 / ((square root of 4))1
  2. Find the root. 2 multiplied by itself 2 times gives 4, so 2 is the square root.
    2 × 2 = 4, so the square root of 4 is 2
  3. Take the reciprocal. A negative index means one over the positive power.
    1 / 2 = 1/2
  4. Write the answer.
    1/2

Check. The square root of 4 is 2, and 21 = 2.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Worked example 1.3.3
Work out 16(-3/4).

Method. Work out the root from the denominator, then the power from the numerator. The index (−3/4) is the fourth root of 16, with the power 3 flipped to a fraction.

  1. Use the denominator as the root. The denominator 4 means the fourth root. The numerator is the power.
    16(−3/4) = 1 / ((fourth root of 16))3
  2. Find the root. 2 multiplied by itself 4 times gives 16, so 2 is the fourth root.
    2 × 2 × 2 × 2 = 16, so the fourth root of 16 is 2
  3. Take the reciprocal. A negative index means one over the positive power.
    1 / 8 = 1/8
  4. Write the answer.
    1/8

Check. The fourth root of 16 is 2, and 23 = 8.

Watch out. Do the root first, then the power. Writing the power first gives a number that is too big to work with.

Watch out

Watch out: 2(-3) is 1/8, not −8. Also, 8(-1/3) is not −2. The negative index gives a reciprocal, and it is positive.

Exam tip

Exam tip. Deal with the sign of the index last: work out the positive power first, then take the reciprocal.

Exercise 1C  Negative indices

Non-calculator
1
FWork out 2−3.
2
FWork out 5−2.
3
FWork out 4(−1/2).
4
FWork out 8(−1/3).
5
FWork out 16(−3/4).
6
FWork out 81(−1/2).
7
FWork out 9(−3/2).
8
FWork out 32(−2/5).
9
FWork out 27(−2/3).
10
FSimplify 2(-3) × 25. Give your answer as a whole number.
11
PSWork out 4(-1/2) + 8(1/3). Give your answer as a fraction or a whole number.
12
RWhich is bigger, 3(-1) or 3(-2)? Explain your answer.
13
PSWork out 9(-3/2), then find 9(-3/2) × 27.
(a)9(-3/2)
(b)9(-3/2) × 27
1.4

Simplifying and adding surds

Year 9
Simplify surds, and add or subtract like surds
Video lesson: Simplifying and adding surdsComing soon
A rectangle is 10 cm by 20 cm. Its diagonal is found with Pythagoras, and the answer is a surd: √500 cm. Simplifying the surd gives an exact answer that is easier to add to other lengths.

A surd is a root that cannot be written exactly as a whole number, such as √2 or √50. To simplify a surd, find a square number that divides the number under the root. Then split the root: √50 = √(25 × 2) = √25 × √2 = 5√2.

Like surds have the same number under the root, like 3√2 and 5√2. Only like surds can be added or subtracted: 3√2 + 5√2 = 8√2.

Key ideas

  • √(a × b) = √a × √b. Use it to split off a square number.
  • Simplify each surd first, then add or subtract the like surds.
  • Like surds have the same number under the root.
  • You cannot add surds with different numbers under the root: √2 + √3 cannot be simplified.
Worked example 1.4.1
Simplify √72.

Method. Simplify each surd first, then add or subtract the surds that match.

  1. Simplify each surd. Find a square number that divides the number under the root, then take its root out. The root of a product is the product of the roots.
    √72 = √(62 × 2) = 6√2
  2. Collect like surds. Only surds with the same number under the root can be added or subtracted.
    6√2
  3. Write the answer.
    6√2

Check. Both forms are about 8.485.

Watch out. You cannot add surds with different numbers under the root. √2 + √3 does not equal √5.

Worked example 1.4.2
Simplify 2√12 + √27.

Method. Simplify each surd first, then add or subtract the surds that match.

  1. Simplify each surd. Find a square number that divides the number under the root, then take its root out. The root of a product is the product of the roots.
    2√12 = 4√3
    √27 = √(32 × 3) = 3√3
  2. Collect like surds. Only surds with the same number under the root can be added or subtracted.
    4√3 + 3√3 = 7√3
  3. Write the answer.
    7√3

Check. Both forms are about 12.124.

Watch out. You cannot add surds with different numbers under the root. √2 + √3 does not equal √5.

Worked example 1.4.3
Simplify √80 − √20 + √5.

Method. Simplify each surd first, then add or subtract the surds that match.

  1. Simplify each surd. Find a square number that divides the number under the root, then take its root out. The root of a product is the product of the roots.
    √80 = √(42 × 5) = 4√5
    −√20 = −2√5
    √5 is already in its simplest form
  2. Collect like surds. Only surds with the same number under the root can be added or subtracted.
    4√5 − 2√5 + √5 = 3√5
  3. Write the answer.
    3√5

Check. Both forms are about 6.708.

Watch out. You cannot add surds with different numbers under the root. √2 + √3 does not equal √5.

Watch out

Watch out: √2 + √2 = 2√2, not 2√4. You can only add surds that are the same. Also √8 is not 8√2; √8 = 2√2.

Exam tip

Exam tip. Look for the largest square number that divides the number under the root, such as 4, 9, 16, 25 or 36.

Exercise 1D  Simplifying and adding surds

Non-calculator
1
FSimplify √200.
2
FSimplify √108.
3
FSimplify √147.
4
FSimplify √180.
5
FSimplify √320.
6
FSimplify √98.
7
FSimplify √75.
8
FSimplify √72.
9
FSimplify 3√2 + 5√2.
10
PSSimplify √12 + √27 − √48.
11
PSSimplify 4√50 − 3√8.
12
PSSimplify √18 + √8.
13
RShow that √72 + √50 = 11√2.
1.5

Multiplying and expanding brackets with surds

Year 9
Multiply and expand brackets that contain surds
Video lesson: Multiplying and expanding brackets with surdsComing soon
A rectangle has sides (√3 + 1) cm and (√3 + 2) cm. To find its area, Ruth multiplies the two brackets.

Expanding brackets with surds works in the same way as expanding brackets with letters. Multiply every term in the first bracket by every term in the second. Then simplify each product, and collect the like terms.

Remember that √a × √a = a. For example, √3 × √3 = 3, and √3 × √12 = √36 = 6.

Key ideas

  • Expand brackets with surds in the same way as brackets with letters: multiply every term by every term.
  • √a × √a = a, and √a × √b = √(ab).
  • Simplify each surd, then collect the like terms.
  • The difference of two squares: (p + √q)(p − √q) = p2 − q, which has no surd.
Worked example 1.5.1
Expand and simplify (2 + √3)(1 − √3).

Method. Multiply out the brackets term by term, then simplify and collect like terms.

  1. Multiply every term in the first bracket by every term in the second. Each term in one bracket multiplies each term in the other, as with double brackets.
    2 × (1) = 2
    2 × (−√3) = −2√3
    √3 × (1) = √3
    √3 × (−√3) = −√9
  2. Simplify the surds. Use √a × √b = √(ab), then take out square factors where you can.
    −√9 = −3
  3. Collect like terms. Add the whole numbers, and add the surds that match.
    2 − 2√3 + √3 − 3 = −1 − √3
  4. Write the answer.
    −1 − √3

Check. Both sides are about -2.732.

Watch out. Remember the minus sign: −2 × √3 is −2√3, and √3 × √3 = 3.

Worked example 1.5.2
Expand and simplify (√5 + 2)(√5 − 2).

Method. Multiply out the brackets term by term, then simplify and collect like terms.

  1. Multiply every term in the first bracket by every term in the second. Each term in one bracket multiplies each term in the other, as with double brackets.
    √5 × (√5) = √25
    √5 × (−2) = −2√5
    2 × (√5) = 2√5
    2 × (−2) = −4
  2. Simplify the surds. Use √a × √b = √(ab), then take out square factors where you can.
    √25 = 5
  3. Collect like terms. Add the whole numbers, and add the surds that match.
    5 − 2√5 + 2√5 − 4 = 1
  4. Write the answer.
    1

Check. Both sides are about 1.000.

Watch out. Remember the minus sign: −2 × √3 is −2√3, and √3 × √3 = 3.

Worked example 1.5.3
Expand and simplify (3 + √2)2.

Method. Multiply out the brackets term by term, then simplify and collect like terms.

  1. Multiply every term in the first bracket by every term in the second. Each term in one bracket multiplies each term in the other, as with double brackets.
    3 × (3) = 9
    3 × (√2) = 3√2
    √2 × (3) = 3√2
    √2 × (√2) = √4
  2. Simplify the surds. Use √a × √b = √(ab), then take out square factors where you can.
    √4 = 2
  3. Collect like terms. Add the whole numbers, and add the surds that match.
    9 + 3√2 + 3√2 + 2 = 11 + 6√2
  4. Write the answer.
    11 + 6√2

Check. Both sides are about 19.485.

Watch out. Remember the minus sign: −2 × √3 is −2√3, and √3 × √3 = 3.

Watch out

Watch out: (3 + √2)2 is not 9 + 2 = 11. The middle terms 3√2 + 3√2 = 6√2 are missing from that idea.

Exam tip

Exam tip. Write out all four products before you simplify. Missing a term is the most common error.

Exercise 1E  Expanding brackets with surds

Non-calculator
1
FExpand and simplify (√2 + 1)(√2 − 1).
2
FExpand and simplify (3 + √2)(1 + √2).
3
PSExpand and simplify (2 + √3)(2 − √3).
4
FExpand and simplify (√7 + 1)(√7 + 2).
5
FExpand and simplify (3√2)(√2 + √8).
6
PSExpand and simplify (√5 − 1)(√5 + 3).
7
FExpand and simplify (4 + √6)(1 − √6).
8
FExpand and simplify (√3 + 2)(√3 + 2).
9
PSExpand and simplify (2√2)(3√2 + 1).
10
FExpand and simplify (1 + 2√2)(1 − 2√2).
11
FExpand and simplify (√10 + 1)(√10 − 1).
12
RShow that (√3 + 1)2 = 4 + 2√3.
1.6

Extension: rationalising denominators

Year 9
Extension: rationalise a denominator
Video lesson: Extension: rationalising denominatorsComing soon
A recipe needs 1/√2 of a cup of flour. It is easier to measure with a fraction that has no surd on the bottom, so the cook writes it as √2/2.

Rationalising a denominator means writing the fraction so that the bottom has no surd. For a single surd on the bottom, multiply the top and bottom by that surd.

If the bottom is a surd with a whole number, such as 2 + √3, multiply top and bottom by the conjugate, 2 − √3. The bottom becomes a whole number, because (2 + √3)(2 − √3) = 4 − 3 = 1.

Key ideas

  • Extension: this topic is more advanced than most KS3 work. Check with your teacher.
  • For k/√n, multiply the top and bottom by √n.
  • For k/(a + √b), multiply the top and bottom by the conjugate (a − √b).
  • The conjugate changes only the sign between the two terms.
Worked example 1.6.1
Rationalise the denominator of 1/√3.

Method. Multiply top and bottom by the surd on the bottom, so the bottom has no surd.

  1. Multiply the top and bottom by √3. Multiplying by √3 / √3 changes the form but not the value. The bottom becomes a whole number.
    1/√3 = 1√3/(√3 × √3) = 1√3/3
  2. Simplify the fraction. Divide the top and the bottom by any common factor.
    1√3/3, which cannot be simplified further
  3. Write the answer.
    √3/3

Check. √3/3 is about 0.577, and 1/√3 is about 0.577.

Watch out. Do not multiply only the bottom. Whatever you do to the bottom you must also do to the top.

Worked example 1.6.2
Rationalise the denominator of 6/√2.

Method. Multiply top and bottom by the surd on the bottom, so the bottom has no surd.

  1. Multiply the top and bottom by √2. Multiplying by √2 / √2 changes the form but not the value. The bottom becomes a whole number.
    6/√2 = 6√2/(√2 × √2) = 6√2/2
  2. Simplify the fraction. Divide the top and the bottom by any common factor.
    6√2/2 = 3√2
  3. Write the answer.
    3√2

Check. 3√2 is about 4.243, and 6/√2 is about 4.243.

Watch out. Do not multiply only the bottom. Whatever you do to the bottom you must also do to the top.

Worked example 1.6.3
Rationalise the denominator of 1/(2 + √3).

Method. Multiply by the conjugate to remove the surd from the bottom, then simplify.

  1. Multiply the top and bottom by the conjugate. The conjugate of 2 + √3 is 2 − √3. Multiplying the bottom by it removes the surd.
    1/(2 + √3) = 1(2 − √3) / ((2 + √3)(2 − √3))
  2. Expand the top. Multiply 1 by each term in the bracket.
    1(2 − √3) = 2 − √3
  3. Expand the bottom. Difference of two squares: (p + √q)(p − √q) = p² − q.
    2² − 3 = 1
  4. Simplify the fraction. Divide every term on the top by the same number as the bottom, and tidy the sign.
    (2 − √3)/(1) = 2 − √3
  5. Write the answer.
    2 − √3

Check. 1/(2 + √3) is about 0.268, and the answer is about 0.268.

Watch out. The conjugate changes only the sign between the two terms. Use the difference of two squares on the bottom.

Watch out

Watch out: changing the bottom alone changes the value. Whatever you multiply the bottom by, you must multiply the top by the same number.

Exam tip

Exam tip. Check your answer by working out the decimal value of both the fraction and your answer. They should match.

Exercise 1F  Rationalising denominators (extension)

Non-calculator
1
FRationalise the denominator of 1/√3.
2
FRationalise the denominator of 10/√5.
3
FRationalise the denominator of 6/√2.
4
PSRationalise the denominator of 1/(2 + √3).
5
PSRationalise the denominator of 2/(1 + √5).
6
RRationalise the denominator of 5/(3 + √2).

Chapter summary

SkillMethod
Fractional index a(1/n)The n-th root of a. For example 27(1/3) = 3.
Index a(m/n)Take the n-th root first, then raise to the power m.
Negative index a(−n)One over an. The answer is positive.
Simplify a surdSplit off the largest square factor: √50 = 5√2.
Add surdsSimplify first, then add only the like surds.
Expand with surdsMultiply every term by every term, simplify each surd, then collect like terms.
Extension: rationaliseMultiply top and bottom by √n, or by the conjugate a − √b.

Can you…?

  • I can work out a fractional index as a root and a power
  • I can work out a negative index, including a negative fractional index
  • I can simplify a surd and add or subtract like surds
  • I can expand two brackets that contain surds and simplify the answer
  • Extension: I can rationalise a denominator with a single surd or a conjugate pair

Key terms

index (power)
the small number that shows how many times the base is multiplied by itself
surd
a root that cannot be written exactly as a whole number
like surds
surds with the same number under the root
conjugate
for a + √b, the conjugate is a − √b
rationalise
rewrite a fraction so the denominator has no surd

Exercise 1Z  Check-up

Non-calculator
1
Work out 25(1/2).
2
Work out 125(2/3).
3
Work out 16(-1/4).
4
Work out 2(-4).
5
Simplify √80.
6
Simplify 2√18 + √32.
7
Expand and simplify (√2)(√8).
8
Expand and simplify (1 + 2√2)(1 − 2√2).
9
Rationalise the denominator of 4/√2.
10
Rationalise the denominator of 1/(4 + √5).

Total 21 marks. Allow about 21 minutes.

Exercise 1X  Practice test questions

Non-calculator
1
FWork out 49(1/2).[1 mark]
2
FWork out 216(1/3).[1 mark]
3
FWork out 32(3/5).[2 marks]
4
FWork out 27(-2/3). Give your answer as a fraction.[2 marks]
5
FSimplify √75 + √12, giving your answer in the form a√b.[2 marks]
6
FSimplify 4√45 − 2√20.[2 marks]
7
PSExpand and simplify (√2 + 5)(√2 − 1).[3 marks]
8
RShow that (√7 − 2)(√7 + 2) = 3.[2 marks]
9
PSA square has an area of 50 cm2. Work out the side length in simplest surd form. Give your answer in cm.[3 marks]
10
RAli says (√2 + 1)2 = 2 + 1 = 3. Explain the mistake and work out the correct answer.[3 marks]

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