Circuits, current, voltage and resistance
By the end of this chapter you will be able to
- Name the circuit symbols and draw a simple series or parallel circuit
- Say what current and potential difference are, and where to place an ammeter and a voltmeter
- Use the rules for current and voltage in series and parallel circuits
- Calculate resistance from R = V / I, and describe an I-V graph
- Describe how an LDR and a thermistor change resistance, and why mains electricity is dangerous
You should already know
- Electricity in Year 7 and Year 8 Science (cells, bulbs and simple circuits)
- Speed, distance and time, and reading graphs (Year 7 and Year 8 Science)
Where this leads
- Magnetism and electromagnets in Chapter 11, which uses the current in a circuit
National Curriculum for England, Key Stage 3 science, Year 9. Content: 9P2 electric circuits: cells, batteries and the symbols for cells, lamps, switches, resistors, ammeters and voltmeters, 9P2 current as a flow of charge, in amperes (A); potential difference, in volts (V), 9P2 series circuits: same current, voltages add; parallel circuits: voltage the same across each branch, currents add, 9P2 mains electricity and its dangers (awareness only; no mains practicals), 9P3 resistance R = V / I (ohms); I-V graphs for a resistor, a filament lamp and a diode (basic), 9P3 resistors in series and in parallel (basic); LDR and thermistor as variable resistors (basic).
Exercise P Do you remember?
Method. Recall the component.
- Recall. A cell (or a battery) supplies energy to the circuit.supplies energy
- Write the answer. cell
Check. Two or more cells make a battery. ✓
Method. Share 6 into 2 equal parts.
- Divide. Share 6 into 2 equal groups.6 / 2 = 3
- Write the answer. 3
Check. 3 x 2 = 6. ✓
Method. Recall the flow of electrons.
- Recall. Electrons leave the negative terminal and move towards the positive one.leave the negative
- Write the answer. negative
Check. Conventional current is shown the other way. ✓
Method. Recall the unit.
- Recall. The SI base unit of mass is the kilogram.kilogram
- Write the answer. kilogram
Check. The symbol is kg. ✓
Method. Add the three numbers.
- Add. 0.5 + 0.2 = 0.7, then 0.7 + 0.3 = 1.0.0.5 + 0.2 + 0.3 = 1
- Write the answer. 1
Check. 1 - 0.3 = 0.7. ✓
Circuit symbols and components
A circuit diagram uses symbols, not pictures. A cell supplies energy; a battery is two or more cells together. A lamp transfers electrical energy to light and thermal energy. A switch opens or closes the circuit. A resistor resists the current. An ammeter measures current and is placed in series. A voltmeter measures potential difference and is placed across a component.
| Component | What it does in a circuit |
|---|---|
| cell or battery | supplies energy; sets the potential difference |
| lamp | transfers electrical energy to light and thermal energy |
| ammeter (A in a circle) | measures current, placed in series |
| voltmeter (V in a circle) | measures potential difference, placed across a component |
| resistor | resists the current; fixed resistance |
| switch | opens or closes the circuit |
| LDR and thermistor | variable resistors; resistance changes with light or temperature |
Key ideas
- A circuit diagram uses symbols for each component.
- An ammeter is placed in series (in line with the component).
- A voltmeter is placed across (in parallel with) a component.
- A battery is two or more cells together.
Method. Recall the ammeter.
- Recall. An ammeter measures current.measures current
- Connect. It is placed in series, in line with the component.in series
- Write the answer. ammeter, in series
Check. The ammeter is always in series. ✓
Method. Recall the voltmeter.
- Recall. A voltmeter measures potential difference.potential difference
- Connect. It is placed across the component, in parallel with it.across
- Write the answer. voltmeter, across the component
Check. The voltmeter is across the component. ✓
Method. Think about what a switch controls.
- Think. A switch controls whether current can flow.controls current
- Name it. It opens the circuit to stop current, or closes it to let current flow.opens or closes
- Write the answer. opens or closes the circuit
Check. An open switch breaks the circuit. ✓
Watch out
Watch out: an ammeter is never placed across a component. It is in series. A voltmeter is always placed across a component.
Exam tip
Exam tip. Draw components with their symbols, and make sure all wires join in a complete loop.
Try it (with your teacher, or a grown-up at home). With your teacher, use a low-voltage cell, a switch, a bulb holder and a bulb. Build the circuit and draw it with symbols. Check that the switch opens and closes the circuit. Use low voltage only. Never connect a circuit to a mains socket.
Exercise 10A Circuit symbols and components
Method. Recall the component.
- Recall. A cell supplies energy to the circuit.supplies energy
- Write the answer. cell
Check. Two cells together form a battery. ✓
Method. Recall the definition.
- Recall. A battery is two or more cells joined together.two or more cells
- Write the answer. two or more cells
Check. A single cell is not a battery. ✓
Method. Recall the meter.
- Recall. An ammeter measures current.measures current
- Write the answer. ammeter
Check. Current is measured in amperes. ✓
Method. Recall the meter.
- Recall. A voltmeter measures potential difference.potential difference
- Write the answer. voltmeter
Check. Potential difference is measured in volts. ✓
Method. Recall the job.
- Recall. A switch opens or closes the circuit.opens or closes
- Write the answer. opens or closes the circuit
Check. An open circuit has no current. ✓
Method. Recall the component.
- Recall. A lamp transfers electrical energy to light and thermal energy.light and thermal energy
- Write the answer. lamp
Check. Lamps waste some energy as thermal energy. ✓
Method. Recall the component.
- Recall. A resistor resists the flow of current.resists the flow
- Write the answer. resistor
Check. A resistor has a fixed resistance. ✓
Method. Recall the connection.
- Recall. An ammeter is always placed in series, in line with the component.in series
- Write the answer. series
Check. An ammeter across a component would short it. ✓
Method. Recall the connection.
- Recall. A voltmeter is placed across the component.across the component
- Write the answer. across
Check. Voltmeters are placed in parallel with the part. ✓
Method. Count the cells in the battery.
- Count. A battery of 3 cells has 3 cells.3 cells
- Total. So the number is 3.3
- Write the answer. 3
Check. A battery is two or more cells. ✓
Method. Count the other components.
- Count. The switch, lamp and resistor are three components.three components
- Total. So 3 are not cells.3
- Write the answer. 3
Check. Only the cell is a source. ✓
Method. Think about an open circuit.
- Think. An open switch breaks the loop.breaks the loop
- Decide. So no current flows; the answer is no.no
- Write the answer. no
Check. The loop must be complete for current. ✓
Method. Think about the resistance of a voltmeter.
- Think. A voltmeter has a very high resistance.very high resistance
- Conclude. In series it would stop almost all the current.stop almost all
- Write the answer. Accept any sentence saying a voltmeter has a very high resistance, so placing it in series would stop the current.
Check. Meters are connected to measure without stopping the circuit. ✓
Method. Check the loop and the symbols.
- Draw. Place the cell, switch and lamp in one closed loop.one closed loop
- Name. The components are the cell, the switch and the lamp.cell, switch, lamp
- Write the answer. Accept: cell, switch, lamp in one loop.
Check. A complete loop lets current flow. ✓
Current in series and parallel circuits
Current is the flow of charge round a circuit. It is measured in amperes, A. In a series circuit there is only one path, so the current is the same at every point.
In a parallel circuit the current splits at a junction. The currents in the branches add up to the main current, so the main current is bigger than the current in either branch.
| Quantity | In a series circuit |
|---|---|
| current | the same at every point |
| potential difference | shared; the parts add up to the supply |
| resistance | the resistances add up |
| Quantity | In a parallel circuit |
|---|---|
| current | the branch currents add to the main current |
| potential difference | the same across each branch |
| resistance | the total is less than the smallest branch resistance |
Key ideas
- Current is the flow of charge, in amperes (A).
- Series: one path, so the current is the same everywhere.
- Parallel: the branch currents add to the main current.
- The current splits at a junction, and rejoins at the next.
Method. Use the rule for series circuits.
- Think. In series the current is the same at every point.the same at every point
- Conclude. So the other lamp also has 0.4 A.0.4
- Write the answer. 0.4
Check. One path, one current. ✓
Method. Add the branch currents.
- Add. The branch currents add to the main current.0.2 + 0.3
- Calculate. So the main current is 0.5 A.0.2 + 0.3 = 0.5
- Write the answer. 0.5
Check. The main current is bigger than either branch. ✓
Method. Subtract the known branch from the main current.
- Subtract. The other branch is 0.9 - 0.4.0.9 - 0.4
- Calculate. So the other branch carries 0.5 A.0.9 - 0.4 = 0.5
- Write the answer. 0.5
Check. 0.4 + 0.5 = 0.9 A. ✓
Watch out
Watch out: in a parallel circuit, the main current is not the same as the current in a branch. It is the sum of the branch currents.
Exam tip
Exam tip. In series, say “the same everywhere”; in parallel, say “the branch currents add up”.
Try it (with your teacher, or a grown-up at home). With your teacher, build a series circuit and a parallel circuit with a low-voltage cell, two bulbs and an ammeter. Measure the current at each point. Write down whether the readings are the same or add up, and say which type of circuit it was.
Exercise 10B Current in series and parallel circuits
Method. Recall the unit.
- Recall. Current is measured in amperes, with the symbol A.amperes
- Write the answer. A
Check. The ammeter reads current in amperes. ✓
Method. Recall the definition.
- Recall. Current is the flow of charge round a circuit.flow of charge
- Write the answer. flow of charge
Check. Charge carries energy around the circuit. ✓
Method. Recall the rule.
- Recall. There is only one path, so the current is the same everywhere.the same everywhere
- Write the answer. yes
Check. Series means one path. ✓
Method. Recall the rule.
- Recall. The branch currents add up to the main current.add up
- Write the answer. yes
Check. The current splits at a junction. ✓
Method. Use the series rule.
- Think. Series current is the same at every point.same at every point
- Conclude. So it is also 0.4 A.0.4
- Write the answer. 0.4
Check. Series current does not change. ✓
Method. Add the branch currents.
- Add. 0.2 + 0.3 = 0.5.0.2 + 0.3 = 0.5
- Write the answer. 0.5
Check. 0.5 is bigger than either branch. ✓
Method. Subtract the known branch.
- Subtract. 0.9 - 0.4 = 0.5.0.9 - 0.4 = 0.5
- Write the answer. 0.5
Check. 0.4 + 0.5 = 0.9. ✓
Method. Add all three branch currents.
- Add. 0.1 + 0.2 + 0.3 = 0.6.0.1 + 0.2 + 0.3 = 0.6
- Write the answer. 0.6
Check. 0.6 - 0.3 = 0.3. ✓
Method. The series current is the same everywhere.
- Think. The cell and the lamp are in the same single path.same single path
- Conclude. So the current through the cell is also 0.25 A.0.25
- Write the answer. 0.25
Check. One path, one current. ✓
Method. Think about the two branches.
- Think. Parallel branches give more paths, so less total resistance.more paths
- Decide. So the parallel circuit has the bigger main current.parallel
- Write the answer. parallel
Check. More paths lowers the total resistance. ✓
Method. Think about the junction.
- Think. At a junction, the current splits between the branches.splits
- Conclude. So each branch carries only part of the main current.part of the main current
- Write the answer. Accept any sentence saying the main current is shared between the branches, so each branch has a part of it.
Check. The branches add to the main current. ✓
Method. Think about what is used up.
- Think. Charge is not used up; the lamp transfers energy, not charge.not used up
- Conclude. So the current is the same on both sides of the lamp in series.same on both sides
- Write the answer. Accept any sentence saying the current is the same, because charge is not used up in a single loop.
Check. The lamp transfers energy, not charge. ✓
Potential difference in series and parallel circuits
Potential difference (p.d.) is the energy transferred per unit charge between two points. It is measured in volts, V. A voltmeter is placed across a component to measure it.
In a series circuit, the potential difference of the cell is shared between the components, so the parts add up to the supply. In a parallel circuit, the potential difference is the same across each branch.
| Circuit | Rule for potential difference |
|---|---|
| series | the parts add to the supply voltage |
| parallel | the same across each branch |
Key ideas
- Potential difference is measured in volts (V) with a voltmeter.
- Series: potential differences across the parts add to the supply.
- Parallel: the potential difference is the same across each branch.
- Two 1.5 V cells in series give 3 V.
Method. Add the two potential differences.
- Add. In series the voltages add to the supply.2 + 4
- Calculate. So the supply is 6 V.2 + 4 = 6
- Write the answer. 6
Check. 6 V is shared as 2 V and 4 V. ✓
Method. Use the parallel rule.
- Think. In parallel the potential difference is the same across each branch.same across each
- Conclude. So each branch has 6 V.6
- Write the answer. 6
Check. Each branch is connected to the full supply. ✓
Method. Add the cell voltages.
- Add. In series the cell voltages add.1.5 + 1.5
- Calculate. So the total is 3 V.1.5 + 1.5 = 3
- Write the answer. 3
Check. 3 V is twice 1.5 V. ✓
Watch out
Watch out: a voltmeter is connected across a component, not in series. The voltage is measured between two points.
Exam tip
Exam tip. In series, add the voltages; in parallel, read the same voltage on each branch.
Try it (with your teacher, or a grown-up at home). With your teacher, use two low-voltage cells and two bulbs. First connect the bulbs in series, then in parallel. Measure the voltage across each bulb with a voltmeter, and say whether the voltages add up or stay the same.
Exercise 10C Potential difference in series and parallel circuits
Method. Recall the unit.
- Recall. Potential difference is measured in volts, V.volts
- Write the answer. V
Check. A voltmeter reads volts. ✓
Method. Recall the rule.
- Recall. In series, the voltages across the parts add to the supply voltage.add to the supply
- Write the answer. yes
Check. The supply is shared between the parts. ✓
Method. Recall the rule.
- Recall. In parallel, each branch is across the full supply.across the full supply
- Write the answer. yes
Check. Each branch gets the same voltage. ✓
Method. Recall the meter.
- Recall. A voltmeter measures potential difference.voltmeter
- Write the answer. voltmeter
Check. An ammeter measures current. ✓
Method. Add the voltages.
- Add. 2 + 4 = 6.2 + 4 = 6
- Write the answer. 6
Check. 6 - 4 = 2 V. ✓
Method. Subtract the known voltage from the supply.
- Subtract. 9 - 5 = 4.9 - 5 = 4
- Write the answer. 4
Check. 5 + 4 = 9. ✓
Method. Use the parallel rule.
- Think. Each branch has the full supply voltage.full supply voltage
- Conclude. So 12 V across each branch.12
- Write the answer. 12
Check. 12 V is the same in each branch. ✓
Method. Add the cell voltages.
- Add. 1.5 + 1.5 = 3.1.5 + 1.5 = 3
- Write the answer. 3
Check. 3 V is 2 x 1.5 V. ✓
Method. Add the three cell voltages.
- Add. 1.5 + 1.5 + 1.5 = 4.5.1.5 + 1.5 + 1.5 = 4.5
- Write the answer. 4.5
Check. 4.5 / 1.5 = 3 cells. ✓
Method. The lamp is in parallel with the supply.
- Think. In parallel, the lamp is across the full supply.across the full supply
- Conclude. So the lamp has 6 V.6
- Write the answer. 6
Check. Parallel voltage is the same as the supply. ✓
Method. Subtract the known voltage from the supply.
- Subtract. 4.5 - 1.5 = 3.4.5 - 1.5 = 3
- Write the answer. 3
Check. 1.5 + 3 = 4.5. ✓
Method. Think about the connections.
- Think. Each branch is connected to the same two points of the supply.same two points
- Conclude. So each branch has the same potential difference.same potential difference
- Write the answer. Accept any sentence saying each branch is connected directly across the supply.
Check. The same two points give the same voltage. ✓
Method. Think about the energy transfer.
- Think. Voltage is the energy per charge transferred to components.per charge
- Conclude. The voltages across the components add to the supply, so none is lost.add to the supply
- Write the answer. Accept any sentence saying the energy is transferred to the components, and the voltages add up to the supply.
Check. Energy is transferred, not used up. ✓
Resistance, R = V / I, and I-V graphs
Resistance is the opposition to the current. It is calculated using R = V / I, where R is in ohms (Ω), V in volts and I in amperes. The greater the resistance, the smaller the current for a given voltage.
For a resistor at a constant temperature, the current is proportional to the voltage, so the I-V graph is a straight line through the origin. For a filament lamp, the filament gets hotter and its resistance rises, so the graph curves. A diode lets current flow in one direction only.
| Component | Potential difference (V) | Current (A) | Resistance (ohm) |
|---|---|---|---|
| resistor A | 6.0 | 0.5 | 12.0 |
| resistor B | 9.0 | 0.3 | 30.0 |
| lamp at low brightness | 4.5 | 0.15 | 30.0 |
Key ideas
- R = V / I, with R in ohms, V in volts and I in amperes.
- Resistor: straight line through the origin (constant R).
- Filament lamp: curves, because its resistance increases as it heats.
- Diode: current flows in one direction only.
Method. Use R = V / I.
- Write. R = 6 / 0.5.6 / 0.5
- Calculate. So R = 12 ohms.6 / 0.5 = 12
- Write the answer. 12
Check. 12 x 0.5 = 6 V. ✓
Method. Use R = V / I.
- Write. R = 9 / 0.3.9 / 0.3
- Calculate. So R = 30 ohms.9 / 0.3 = 30
- Write the answer. 30
Check. 30 x 0.3 = 9 V. ✓
Method. Recall the shape of the graph.
- Recall. A straight line through the origin means constant resistance.constant resistance
- Name it. That is a resistor at a constant temperature.resistor
- Write the answer. resistor
Check. A curved line shows a filament lamp. ✓
Watch out
Watch out: R = V / I, not V = R / I. Multiply V by R only when finding V, not when finding R.
Exam tip
Exam tip. Write R = V / I, substitute the numbers with units, then divide.
Try it (with your teacher, or a grown-up at home). With your teacher, use a low-voltage supply, a resistor, an ammeter and a voltmeter. Change the voltage in steps and read the current each time. Plot the points, and say whether the graph is a straight line through the origin.
Exercise 10D Resistance, R = V / I, and I-V graphs
Method. Recall the unit.
- Recall. Resistance is measured in ohms, with the symbol Ω.ohms
- Write the answer. ohm
Check. The Greek letter omega is used. ✓
Method. Recall the equation.
- Recall. R = V / I, so resistance is potential difference divided by current.divided by current
- Write the answer. resistance = potential difference / current
Check. R = V / I. ✓
Method. Recall the graph.
- Recall. The current is proportional to the voltage.proportional
- Write the answer. straight line
Check. The line passes through the origin. ✓
Method. Recall the effect of heat.
- Recall. As the filament gets hotter, its resistance rises.resistance rises
- Write the answer. yes
Check. That is why the lamp graph curves. ✓
Method. Recall the diode.
- Recall. A diode lets current flow in one direction only.one direction only
- Write the answer. no
Check. A diode is one-way. ✓
Method. Use R = V / I.
- Divide. 6 / 0.5 = 12.6 / 0.5 = 12
- Write the answer. 12
Check. 12 x 0.5 = 6 V. ✓
Method. Use R = V / I.
- Divide. 9 / 0.3 = 30.9 / 0.3 = 30
- Write the answer. 30
Check. 30 x 0.3 = 9. ✓
Method. Rearrange R = V / I to I = V / R.
- Rearrange. I = V / R = 4 / 20.4 / 20
- Calculate. So I = 0.2 A.4 / 20 = 0.2
- Write the answer. 0.2
Check. 20 x 0.2 = 4 V. ✓
Method. Rearrange R = V / I to V = I x R.
- Rearrange. V = 0.6 x 10.0.6 x 10
- Calculate. So V = 6 V.0.6 x 10 = 6
- Write the answer. 6
Check. 6 / 10 = 0.6 A. ✓
Method. Use R = V / I.
- Divide. R = 2 / 0.1 = 20.2 / 0.1 = 20
- Write the answer. 20
Check. 20 x 0.1 = 2 V. ✓
Method. Calculate both resistances.
- First. R = 6 / 0.5 = 12 ohms.12 ohms
- Second. R = 6 / 0.25 = 24 ohms.24 ohms
- Decide. So the one with 0.25 A has the larger resistance.the one with 0.25 A
- Write the answer. the one with 0.25 A
Check. Less current means more resistance at the same voltage. ✓
Method. Think about the filament.
- Think. The filament gets hotter as the current increases.gets hotter
- Conclude. So its resistance rises, and the current rises more slowly.rises more slowly
- Write the answer. Accept any sentence saying the resistance of the filament increases as it heats up, so the current rises more slowly.
Check. Hotter means more resistance in a filament. ✓
Method. Think about the constant resistance.
- Think. At a constant temperature, the resistance does not change.does not change
- Conclude. So the current is proportional to the voltage, and the graph is straight.straight
- Write the answer. Accept any sentence saying a resistor at constant temperature has a constant resistance, so its graph is straight.
Check. A curve means the resistance changes. ✓
Resistors in series and parallel, variable resistors and mains safety
Two resistors in series add together: 10 ohms and 20 ohms make 30 ohms. Two equal resistors in parallel have a total resistance less than either one: two 10 ohm resistors in parallel make 5 ohms.
An LDR is a light-dependent resistor: its resistance falls in bright light. A thermistor is a temperature-dependent resistor: its resistance falls when it is hotter. Both are used as sensors in circuits.
Mains electricity in the UK is about 230 V. It can cause severe electric shock and burns. Pupils must never test mains equipment, and must never connect a circuit to a mains socket. This is awareness only.
| Component | What happens to its resistance |
|---|---|
| LDR | falls in bright light |
| thermistor | falls when it gets hotter |
| fixed resistor | stays the same at constant temperature |
Key ideas
- Series resistances add.
- Two equal resistors in parallel: total = one resistance divided by two.
- An LDR has lower resistance in bright light.
- A thermistor has lower resistance when hotter.
- Mains is about 230 V: never used by pupils; awareness only.
Method. Add the resistances.
- Add. In series the resistances add.10 + 20
- Calculate. So the total is 30 ohms.10 + 20 = 30
- Write the answer. 30
Check. Series total is more than either resistor. ✓
Method. Share the resistance by the number of branches.
- Think. Two equal branches share the current, so the total is less.less
- Calculate. 10 / 2 = 5 ohms.10 / 2 = 5
- Write the answer. 5
Check. The total is less than 10 ohms. ✓
Method. Use the rule that current is higher at lower resistance.
- Think. With the same voltage, lower resistance means a bigger current.bigger current
- Decide. So the current increases in bright light.increases
- Write the answer. increases
Check. Current = voltage / resistance. ✓
Watch out
Watch out: adding a resistor in parallel does not increase the total resistance. The total always falls, below the smallest branch.
Exam tip
Exam tip. In series add the resistances; in parallel the total is always less than the smallest.
Try it (with your teacher, or a grown-up at home). With your teacher, use a low-voltage supply and a light-dependent resistor (LDR), a meter and a torch. Measure the current with the torch off and on. Say how the LDR changes resistance, and never test any mains socket or mains equipment.
Exercise 10E Resistors in series and parallel, variable resistors and mains safety
Method. Recall the LDR.
- Recall. An LDR is light-dependent, with lower resistance in bright light.lower resistance
- Write the answer. falls
Check. Light lets more current flow. ✓
Method. Recall the thermistor.
- Recall. A thermistor has lower resistance when hotter.lower resistance
- Write the answer. falls
Check. A thermistor is a temperature sensor. ✓
Method. Recall the mains voltage.
- Recall. The UK mains supply is about 230 V.230 V
- Write the answer. 230
Check. Mains is very dangerous. ✓
Method. Recall the rule.
- Recall. Pupils never test mains electricity.never test mains
- Write the answer. no
Check. Only low-voltage cells are used by pupils. ✓
Method. Add the resistances.
- Add. 10 + 30 = 40.10 + 30 = 40
- Write the answer. 40
Check. 40 is more than 30. ✓
Method. Divide one resistance by the number of branches.
- Divide. 20 / 2 = 10.20 / 2 = 10
- Write the answer. 10
Check. 10 is less than 20. ✓
Method. Add the three resistances.
- Add. 30 + 30 + 30 = 90.30 + 30 + 30 = 90
- Write the answer. 90
Check. 90 / 3 = 30. ✓
Method. Compare with one branch.
- Think. Two branches carry the current together, so the total falls.falls
- Decide. The total is 5 ohms, which is less than 10 ohms, so the answer is yes.yes
- Write the answer. yes
Check. The total is less than the smallest branch. ✓
Method. Recall the safe supply.
- Recall. Pupils use low-voltage cells and batteries only.low-voltage cells
- Write the answer. low-voltage cell
Check. Mains is never used in school practicals. ✓
Method. Think about the change in resistance.
- Think. The thermistor resistance changes with temperature.changes with temperature
- Conclude. So the circuit can detect a change in heat and respond.detect a change
- Write the answer. Accept any sentence saying its resistance changes with temperature, so the circuit can detect a change in heat.
Check. A sensor turns a physical change into an electrical one. ✓
Method. Think about the paths.
- Think. An extra branch gives the current another path to flow.another path
- Conclude. So the total resistance falls below the smallest branch.falls below
- Write the answer. Accept any sentence saying the extra branch gives the current another path, so the total resistance falls.
Check. More paths means less resistance. ✓
Chapter summary
| Skill | Method |
|---|---|
| Circuit symbols | Cell, lamp, switch, resistor, ammeter (in series), voltmeter (across). |
| Current | Flow of charge in amperes; the same in series; the branch currents add in parallel. |
| Potential difference | In volts; series parts add to the supply; the same across each parallel branch. |
| Resistance | R = V / I, in ohms; a resistor gives a straight I-V line; a filament lamp curves; a diode is one-way. |
| Resistors | Series resistances add; parallel total is less than the smallest branch. |
| Sensors and mains | LDR falls in bright light; thermistor falls when hotter; mains (230 V) is never used by pupils. |
Can you…?
- I can name the circuit symbols and place an ammeter and a voltmeter correctly
- I can state the current and potential difference rules for series and parallel circuits
- I can calculate resistance from R = V / I, and describe the shape of an I-V graph
- I can work out series and parallel resistances at basic level
- I can describe an LDR and a thermistor, and explain why mains is dangerous
Key terms
- current
- the flow of charge round a circuit, measured in amperes
- potential difference
- the energy transferred per unit charge between two points, measured in volts
- series circuit
- a circuit with one path for the current
- parallel circuit
- a circuit with more than one path for the current
- resistance
- the opposition to the current, measured in ohms, equal to V / I
- ohm
- the unit of resistance
- ammeter
- a meter placed in series to measure current
- voltmeter
- a meter placed across a component to measure potential difference
- LDR
- a light-dependent resistor whose resistance falls in bright light
- thermistor
- a temperature-dependent resistor whose resistance falls when it is hotter
- diode
- a component that lets current flow in one direction only
- mains electricity
- the supply from the mains socket, about 230 V in the UK, which pupils never test
Exercise 10Z Check-up
Method. Recall the unit.
- Recall. Current is measured in amperes, A.amperes
- Write the answer. A
Check. The ammeter reads amperes. ✓
Method. Recall the rule.
- Recall. There is only one path in series.one path
- Write the answer. yes
Check. Series means one path. ✓
Method. Add the branch currents.
- Add. 0.2 + 0.3 = 0.5.0.2 + 0.3 = 0.5
- Write the answer. 0.5
Check. 0.5 - 0.3 = 0.2. ✓
Method. Add the voltages.
- Add. 2 + 4 = 6.2 + 4 = 6
- Write the answer. 6
Check. 6 - 4 = 2. ✓
Method. Use the parallel rule.
- Think. Each branch is across the full supply.full supply
- Write the answer. 12
Check. Same voltage in each branch. ✓
Method. Use R = V / I.
- Divide. 6 / 0.5 = 12.6 / 0.5 = 12
- Write the answer. 12
Check. 12 x 0.5 = 6. ✓
Method. Recall the unit.
- Recall. Resistance is measured in ohms.ohms
- Write the answer. ohm
Check. The symbol is the Greek omega. ✓
Method. Add the resistances.
- Add. 10 + 20 = 30.10 + 20 = 30
- Write the answer. 30
Check. 30 is more than 20. ✓
Method. Recall the LDR.
- Recall. The resistance of an LDR falls in bright light.falls
- Write the answer. falls
Check. An LDR is a light sensor. ✓
Method. Think about the proportion.
- Think. The resistance is constant at a constant temperature.constant
- Conclude. So the current is proportional to the voltage.proportional
- Write the answer. Accept any sentence saying the current is proportional to the voltage, because the resistance is constant.
Check. Straight line through the origin. ✓
Total 19 marks. Allow about 19 minutes.
Exercise 10X Practice test questions
Method. Recall the unit.
- Recall. Potential difference is measured in volts, V.volts
- Write the answer. V
Check. A voltmeter reads volts. ✓
Method. Recall the rule.
- Recall. The current is the same at every point in series.same at every point
- Write the answer. current
Check. Voltage is shared, not the same. ✓
Method. Use R = V / I.
- Divide. R = 9 / 0.3 = 30 ohms.9 / 0.3 = 30
- Write the answer. 30
Check. 30 x 0.3 = 9. ✓
Method. Add the branch currents.
- Add. 0.1 + 0.4 = 0.5.0.1 + 0.4 = 0.5
- Write the answer. 0.5
Check. 0.5 - 0.4 = 0.1. ✓
Method. The lamp is across the full supply.
- Conclude. In parallel the lamp has the full supply voltage.6
- Write the answer. 6
Check. Same voltage as the supply. ✓
Method. Follow the heating.
- Heat. More current heats the filament.heats the filament
- Resistance. The resistance rises as the hotter filament resists the current more.resistance rises
- Conclude. So the current rises more slowly than the voltage.more slowly
- Write the answer. Accept any answer saying the filament heats up, and its resistance rises as the atoms vibrate more.
Check. Both steps are needed for full marks. ✓
Method. Divide, then explain.
- Divide. 10 / 2 = 5 ohms.10 / 2 = 5
- Explain. The current has two paths, so the total resistance is less.two paths
- Write the answer. Accept 5 ohms, with a reason that the current has two paths.
Check. The total is less than the smallest branch. ✓
Method. Link the light to the resistance and the current.
- Resistance. The LDR resistance falls in brighter light.resistance falls
- Current. At the same voltage, a lower resistance gives a bigger current.bigger current
- Write the answer. Accept any answer saying the resistance falls, and the current increases.
Check. Lower resistance means more current. ✓
Method. Recall the mains rule.
- Voltage. The UK mains supply is about 230 V.230 V
- Rule. Pupils must never test mains electricity.never test
- Write the answer. 230 V; no
Check. Mains is dangerous. ✓
Method. Think about the meter.
- Think. The voltmeter measures the potential difference between two points.between two points
- Conclude. Connecting it across the part measures this without stopping the current.without stopping
- Write the answer. Accept any sentence saying it measures the voltage across the component without stopping the current.
Check. Voltmeters are connected in parallel. ✓