Electrolysis and oxidation and reduction
By the end of this chapter you will be able to
- Explain what an electrolyte is, and what happens at the cathode and anode
- Name the products of electrolysis of molten compounds and solutions
- Explain selective discharge and predict the products of an aqueous solution
- Identify oxidation and reduction in a reaction
- [H] Write and check half equations for electrode reactions
You should already know
- Ions and their charges (Chapter 4)
- Reactivity series and displacement (Chapter 3)
Where this leads
- Metal extraction and recycling (Chapter 19)
- Electrolysis of brine and the chemical industry
GCSE Chemistry. Content follows the GCSE (9-1) subject content for England (Edexcel and AQA). Content references: Describe electrolysis as the decomposition of an ionic compound by electricity, and name the products at each electrode, Predict the products of electrolysis of aqueous solutions (selective discharge), Identify oxidation and reduction in terms of electrons and of oxygen, [H] Write half equations for the reactions at the electrodes, and balance electrons, Describe the uses of electrolysis, including aluminium extraction and electroplating.
Exercise P Do you remember?
Method. Chlorine gains one electron.
- Recall. Cl- has one more electron than protons: -1.-1
- Write the answer. -1
Check. The charge of a sodium ion is +1. ✓
Method. Recall the ion from acids.
- Recall. Acids produce hydrogen ions, H+.H+
- Write the answer. H+
Check. Alkalis produce OH-. ✓
Method. Recall the group.
- Recall. Halogens are in group 7.7
- Write the answer. 7
Check. Halogens gain one electron. ✓
Method. Multiply three 2s.
- Multiply. 2 x 2 = 4, then 4 x 2 = 8.8
- Write the answer. 8
Check. Two electrons times four is eight. ✓
Method. Use the reactivity series.
- Compare. Magnesium is above copper in the series.magnesium
- Write the answer. magnesium
Check. Magnesium displaces copper from copper sulfate. ✓
Electrolysis of molten compounds
Electrolysis is the breaking down of an ionic compound by electricity. The compound must be molten or dissolved, so that its ions are free to move. The electrolyte is the substance being broken down. The positive electrode is the anode (it attracts negative ions); the negative electrode is the cathode (it attracts positive ions). Positive ions (cations) move to the cathode and are reduced there; negative ions (anions) move to the anode and are oxidised there.
Electrolysis of molten compounds is a teacher demonstration only. The molten compounds are very hot and the products are hazardous.
Key ideas
- Electrolysis breaks down an ionic compound using electricity.
- The ions must be free to move: molten or dissolved.
- Cations (+) move to the cathode (-), where they gain electrons (reduction).
- Anions (-) move to the anode (+), where they lose electrons (oxidation).
Method. Positive ions move to the negative electrode.
- Recall. Cathode is negative, so it attracts the positive ions.positive
- Decide. The positive ion in sodium chloride is Na+.Na+
- Write the answer. Na+
Check. Cl- moves to the anode. ✓
Method. The cathode gains electrons from the metal ion.
- Ion. The cation is Pb2+.Pb2+
- Product. Pb2+ gains electrons at the cathode and forms lead metal.lead
- Write the answer. lead
Check. Bromine forms at the anode. ✓
Method. The anions are oxidised at the anode.
- Ion. The anion is Cl-.Cl-
- Product. Two Cl- lose electrons to form Cl2 gas.chlorine
- Write the answer. chlorine
Check. Chlorine is a green gas. ✓
Watch out
Watch out: in electrolysis, the metal is formed at the negative electrode (cathode), not the positive one. Cations go to the cathode.
Exam tip
Exam tip. Write “cathode: metal” and “anode: non-metal” for a molten binary compound, and check the charges.
Exercise 11A Electrolysis of molten compounds
Method. Recall the definition.
- Recall. Electrolysis breaks down an ionic compound using electricity.breaking down
- Write the answer. breaking down an ionic compound by electricity
Check. The compound must be molten or dissolved. ✓
Method. Recall the electrode names.
- Recall. The negative electrode is the cathode.cathode
- Write the answer. cathode
Check. The positive electrode is the anode. ✓
Method. Recall the electrode names.
- Recall. The positive electrode is the anode.anode
- Write the answer. anode
Check. Anions move to the anode. ✓
Method. Opposite charges attract.
- Recall. The cathode is negative, so positive ions (cations) move to it.positive ions
- Write the answer. positive ions
Check. Cations move to the cathode. ✓
Method. Sodium ions are reduced at the cathode.
- Recall. Na+ gains an electron and forms sodium metal.sodium
- Write the answer. sodium
Check. Sodium is a soft, reactive metal. ✓
Method. Chloride ions are oxidised at the anode.
- Recall. Cl- loses electrons to form Cl2 gas.chlorine
- Write the answer. chlorine
Check. Chlorine is toxic. ✓
Method. Bromide ions are oxidised at the anode.
- Recall. Br- loses electrons to form bromine.bromine
- Write the answer. bromine
Check. Bromine is a red-brown liquid. ✓
Method. Think about what carries the current.
- Look. Ions in a solid are fixed in place and cannot move.fixed
- Conclude. When molten or dissolved, the ions are free to move to the electrodes.so ions can move
- Write the answer. so that the ions can move
Check. A solid ionic compound does not conduct. ✓
Method. Negative ions move to the anode.
- Recall. Br- is negative, so it moves to the positive anode.Br-
- Write the answer. Br-
Check. Pb2+ moves to the cathode. ✓
Method. Lead ions are positive.
- Look. Pb2+ is positive and moves to the negative electrode.negative
- Decide. So lead forms at the cathode.cathode
- Write the answer. cathode
Check. Bromine forms at the anode. ✓
Method. Bromide ions go to the anode.
- Ion. Br- is the anion in potassium bromide.Br-
- Product. It loses electrons at the anode to form bromine.bromine
- Write the answer. bromine
Check. Potassium forms at the cathode. ✓
Method. Think about the hazards.
- Heat. Molten compounds are very hot and can cause severe burns.very hot
- Products. The products, such as chlorine and molten metals, are hazardous.hazardous
- Write the answer. Accept any sentence that says molten compounds are very hot and the products are hazardous.
Check. Only a teacher uses the equipment. ✓
Method. Compare the solid and the molten state.
- Solid. In the solid, the ions are fixed in the lattice.fixed
- Molten. When molten, the ions are free to move and carry charge.free to move
- Write the answer. Accept any sentence that says the ions are fixed in the solid but free to move when molten.
Check. Ionic lattices are explained in Chapter 4. ✓
Electrolysis of aqueous solutions
In an aqueous solution, the water also provides ions: H+ and OH-. At the cathode, the ion that is discharged is the one that is less reactive: a metal less reactive than hydrogen is deposited, but a metal more reactive than hydrogen is not. This is selective discharge. At the anode, a halide ion (Cl-, Br-) is discharged to give a halogen, but in dilute solution oxygen can form instead.
| Substance | Form | Cathode (-): product | Anode (+): product |
|---|---|---|---|
| molten lead bromide, PbBr2 | molten | lead | bromine |
| molten sodium chloride, NaCl | molten | sodium | chlorine |
| aqueous sodium chloride (concentrated) | solution | hydrogen | chlorine |
| aqueous copper sulfate, CuSO4 | solution | copper | oxygen (and the solution becomes acidic) |
Key ideas
- Selective discharge: the less reactive ion is discharged at the cathode (copper is deposited, not sodium).
- Hydrogen is formed at the cathode when the metal is more reactive than hydrogen (for example sodium).
- Concentrated NaCl solution: hydrogen at the cathode, chlorine at the anode.
- Copper sulfate solution with inert electrodes: copper at the cathode, oxygen at the anode, and the solution becomes acidic.
Try it (with your teacher). Teacher demonstration only: electrolysis of copper sulfate solution with carbon electrodes. Pupils observe. A copper layer forms on the cathode, and bubbles of oxygen form at the anode. The blue colour of the solution fades as copper is removed. Wear goggles; keep the apparatus under the teacher’s control.
Method. Copper is less reactive than hydrogen, so it is discharged.
- Ions. The cations are Cu2+ and H+.Cu2+ and H+
- Discharge. Copper is less reactive than hydrogen, so Cu2+ is discharged.copper
- Write the answer. copper
Check. Copper deposits as a red-brown layer. ✓
Method. Chloride ions are discharged at the anode when concentrated.
- Ions. The anions are Cl- and OH-.Cl- and OH-
- Discharge. Concentrated chloride ions are discharged to form chlorine.chlorine
- Write the answer. chlorine
Check. Chlorine is made commercially this way. ✓
Method. Compare the reactivity of sodium and hydrogen.
- Compare. Sodium is more reactive than hydrogen, so water is reduced instead.sodium more reactive
- Conclude. So H+ from water is discharged and hydrogen gas forms.hydrogen
- Write the answer. sodium is more reactive than hydrogen, so hydrogen is discharged
Check. Water provides the H+ ions. ✓
Watch out
Watch out: in a solution, the metal is not always formed at the cathode. Only metals less reactive than hydrogen are deposited; a more reactive metal leaves hydrogen to form.
Exam tip
Exam tip. For an aqueous solution, list all the ions present (including H+ and OH- from water), then decide which is discharged at each electrode.
Exercise 11B Electrolysis of aqueous solutions
Method. Recall the product.
- Recall. Copper is deposited on the cathode.copper
- Write the answer. copper
Check. Copper is less reactive than hydrogen. ✓
Method. Recall the product at the anode.
- Recall. Oxygen is released at the anode.oxygen
- Write the answer. oxygen
Check. The solution becomes acidic. ✓
Method. Think about the H+ ions.
- Recall. The solution becomes more acidic, so the pH falls.lower
- Write the answer. lower
Check. H+ ions build up as copper is removed. ✓
Method. Recall the product.
- Recall. Chlorine forms at the anode from concentrated chloride ions.chlorine
- Write the answer. chlorine
Check. Chlorine is a toxic gas. ✓
Method. Recall the product.
- Recall. Hydrogen is formed at the cathode because sodium is more reactive than hydrogen.hydrogen
- Write the answer. hydrogen
Check. Sodium hydroxide is left in the solution. ✓
Method. Recall the ions of water.
- Recall. Water provides H+ and OH- ions.H+ and OH-
- Write the answer. H+ and OH-
Check. These take part in selective discharge. ✓
Method. Compare with hydrogen.
- Compare. Sodium is more reactive than hydrogen, so sodium ions are not discharged.more reactive
- Decide. So sodium is not deposited; hydrogen forms instead.sodium
- Write the answer. sodium
Check. Copper is less reactive, so copper is deposited. ✓
Method. In dilute solution, chloride ions are less concentrated.
- Look. In dilute solution, the OH- ions are discharged more easily.OH-
- Decide. So oxygen forms at the anode.oxygen
- Write the answer. oxygen
Check. Concentrated solutions give chlorine. ✓
Method. Potassium is more reactive than hydrogen.
- Compare. Potassium is more reactive, so H+ from water is discharged.H+ discharged
- Decide. Hydrogen gas forms at the cathode.hydrogen
- Write the answer. hydrogen
Check. Potassium hydroxide remains in solution. ✓
Method. Use the reactivity series.
- Series. Copper is below hydrogen in the reactivity series.below hydrogen
- Conclude. So its ions are discharged in preference to H+.discharged
- Write the answer. Accept any sentence that says copper is less reactive than hydrogen, so its ions are discharged.
Check. Selective discharge decides the product. ✓
Method. Think about the anode.
- Anode. At the anode, OH- ions are discharged to form oxygen.OH- discharged
- Conclude. H+ ions are left in solution, so the solution becomes acidic.acidic
- Write the answer. Accept any answer that says OH- is discharged at the anode, leaving H+ ions behind.
Check. The pH falls as H+ builds up. ✓
Oxidation and reduction
Oxidation is the loss of electrons or the gain of oxygen. Reduction is the gain of electrons or the loss of oxygen. Reactions in which both happen are redox reactions. The mnemonic OIL RIG helps: oxidation is loss, reduction is gain (of electrons).
| Definition | Oxidation | Reduction |
|---|---|---|
| in terms of electrons | loss of electrons | gain of electrons |
| in terms of oxygen | gain of oxygen | loss of oxygen |
| mnemonic | OIL (oxidation is loss) | RIG (reduction is gain) |
Key ideas
- Oxidation: loss of electrons; gain of oxygen.
- Reduction: gain of electrons; loss of oxygen.
- Redox: a reaction where one substance is oxidised and another is reduced.
- In electrolysis, the cathode is reduction and the anode is oxidation.
Method. Reduction is loss of oxygen.
- Look. CuO loses oxygen to form Cu.loses O
- Decide. So CuO is reduced.CuO
- Write the answer. CuO
Check. The hydrogen gains oxygen and is oxidised. ✓
Method. Oxidation is loss of electrons.
- Look. Magnesium atoms lose 2 electrons to form Mg2+.loses 2e-
- Decide. Loss of electrons is oxidation.oxidised
- Write the answer. oxidised
Check. The magnesium atoms are the reducing agent. ✓
Method. Gain of electrons is reduction.
- Look. Cu2+ gains 2 electrons to form Cu.gains 2e-
- Decide. Gain of electrons is reduction.reduced
- Write the answer. reduced
Check. Reduction is gain: RIG. ✓
Watch out
Watch out: a substance that is reduced gains electrons, or loses oxygen. Do not say it is reduced because its mass goes down, or because it is oxidised by the other substance.
Exam tip
Exam tip. Write the change in oxidation for each element, or the electrons gained and lost, and then name the process.
Exercise 11C Oxidation and reduction
Method. Recall the definition.
- Recall. Oxidation is the loss of electrons.loss
- Write the answer. loss of electrons
Check. OIL: oxidation is loss. ✓
Method. Recall the definition.
- Recall. Reduction is the gain of electrons.gain
- Write the answer. gain of electrons
Check. RIG: reduction is gain. ✓
Method. Recall the definition.
- Recall. Oxidation is the gain of oxygen.gain of oxygen
- Write the answer. gain of oxygen
Check. Rusting of iron is oxidation. ✓
Method. Recall the definition.
- Recall. Reduction is the loss of oxygen.loss of oxygen
- Write the answer. loss of oxygen
Check. Copper oxide is reduced by hydrogen. ✓
Method. The hydrogen gains oxygen.
- Look. H2 gains oxygen to form H2O.gains O
- Decide. So H2 is oxidised.H2
- Write the answer. H2
Check. The copper oxide is reduced. ✓
Method. Recall the definition.
- Recall. The loss of electrons is oxidation.oxidation
- Write the answer. oxidation
Check. OIL. ✓
Method. Recall the definition.
- Recall. The gain of electrons is reduction.reduction
- Write the answer. reduction
Check. RIG. ✓
Method. The oxygen gains electrons to form O2-.
- Look. Oxygen gains electrons, so it is reduced.gains electrons
- Decide. So O2 is reduced.O2
- Write the answer. O2
Check. Magnesium is oxidised. ✓
Method. Zinc loses electrons to form Zn2+.
- Look. Zinc atoms lose 2 electrons.loses electrons
- Decide. So zinc is oxidised.Zn
- Write the answer. Zn
Check. Copper ions are reduced to copper. ✓
Method. Oxidation is loss of electrons.
- Recall. Iron atoms lose electrons to form Fe2+.loses electrons
- Write the answer. they lose electrons
Check. The gain of electrons is reduction. ✓
Method. Think about the electrons.
- Electrons. Electrons cannot be lost without going somewhere.go somewhere
- Conclude. So the electrons lost by one substance are gained by another.gained by another
- Write the answer. Accept any sentence that says the electrons lost by one substance are gained by another.
Check. Redox means both happen together. ✓
Method. Look at the reactants and products.
- Look. The copper oxide becomes copper, so the oxygen is removed.O removed
- Conclude. So the oxygen is lost, which is reduction.loss of oxygen
- Write the answer. Accept any sentence that says the oxygen is removed from the copper oxide by the hydrogen.
Check. Both definitions apply to this reaction. ✓
Half equations [H]
[H] Higher tier only. A half equation shows the reaction at one electrode. Electrons are shown explicitly: at the cathode, electrons are on the left (reduction); at the anode, electrons are on the right (oxidation). Both the atoms and the total charge must balance. Example: Cu2+ + 2e- -> Cu (cathode); 2Cl- -> Cl2 + 2e- (anode).
Key ideas
- Cathode: gain of electrons (reduction), e.g. Cu2+ + 2e- -> Cu.
- Anode: loss of electrons (oxidation), e.g. 2Cl- -> Cl2 + 2e-.
- Check both atoms and charge balance on each side.
- Electrons in a half equation are shown as e-.
Method. Aluminium ions gain three electrons.
- Ion. Al3+ has charge +3.+3
- Electrons. It gains 3 electrons to form Al with charge 0.3e-
- Equation. Al3+ + 3e- -> Al.Al3+ + 3e- -> Al
- Write the answer. Al3+ + 3e- -> Al
Check. Charge: +3 - 3 = 0. ✓
Method. Two chloride ions lose one electron each to form Cl2.
- Atoms. Two Cl- form one Cl2, so 2Cl-.2Cl-
- Electrons. Each Cl- loses one electron; charge goes from -2 to 0, so 2e- are released.2e-
- Equation. 2Cl- -> Cl2 + 2e-.2Cl- -> Cl2 + 2e-
- Write the answer. 2Cl- -> Cl2 + 2e-
Check. Charge: -2 on the left, and 0 + (-2) on the right. ✓
Method. At the anode, electrons are lost.
- Recall. Loss of electrons is oxidation at the anode.loss
- Decide. So the electrons appear on the right, as products.right
- Write the answer. right
Check. The cathode half equation has electrons on the left. ✓
Watch out
Watch out: a half equation must balance both the atoms and the charge. Count the electrons carefully: two chloride ions give two electrons, but one copper ion takes two electrons too.
Exam tip
Exam tip. Balance the atoms first, then add electrons until the charge on each side is equal.
Exercise 11D Half equations [H]
Method. Look at the charge of the ion.
- Charge. Cu2+ must lose 2 units of charge to become Cu (0).2
- Write the answer. 2
Check. Cu2+ + 2e- -> Cu. ✓
Method. The charge is +3.
- Charge. Al3+ must gain 3 electrons to become Al.3
- Write the answer. 3
Check. Al3+ + 3e- -> Al. ✓
Method. Two electrons are needed.
- Electrons. Pb2+ gains 2 electrons to become Pb.2e-
- Equation. Pb2+ + 2e- -> Pb.Pb2+ + 2e- -> Pb
- Write the answer. Pb2+ + 2e- -> Pb
Check. Charge: +2 - 2 = 0. ✓
Method. Two bromide ions form one Br2 molecule.
- Atoms. Two Br- give one Br2.Br2
- Electrons. Each loses 1 electron, giving 2e-.2e-
- Equation. 2Br- -> Br2 + 2e-.2Br- -> Br2 + 2e-
- Write the answer. 2Br- -> Br2 + 2e-
Check. Charge: -2 = 0 + (-2). ✓
Method. Oxidation loses electrons.
- Look. In the second, Cl- loses electrons.loses e-
- Decide. So the oxidation is 2Cl- -> Cl2 + 2e-.Cl-
- Write the answer. Cl-
Check. The first is reduction. ✓
Method. Two H+ gain one electron each to form H2.
- Atoms. Two H+ form H2.2H+
- Electrons. Each gains 1 electron, so 2e-.2e-
- Equation. 2H+ + 2e- -> H2.2H+ + 2e- -> H2
- Write the answer. 2H+ + 2e- -> H2
Check. Charge: +2 - 2 = 0. ✓
Method. Two O2- lose four electrons to form O2.
- Atoms. Two O2- form one O2.2O2-
- Electrons. Each loses 2 electrons, so 4e-.4e-
- Equation. 2O2- -> O2 + 4e-.2O2- -> O2 + 4e-
- Write the answer. 2O2- -> O2 + 4e-
Check. Charge: -4 = 0 + (-4). ✓
Method. Add the charges on each side.
- Left. +3 from Fe3+ and -1 from the electron: total +2.+2
- Right. Fe2+ has +2.+2
- Write the answer. yes
Check. Fe3+ is reduced to Fe2+. ✓
Method. Think about conservation.
- Atoms. Atoms are not created or destroyed.atoms conserved
- Charge. Charge is also conserved, so both sides must match.charge conserved
- Write the answer. Accept any sentence that says atoms and charge are conserved in every reaction.
Check. This is the same idea as conservation of mass. ✓
Uses of electrolysis
Electrolysis is used to extract very reactive metals such as aluminium, which cannot be reduced with carbon. It is used in electroplating to coat objects with a metal, and to purify copper for electrical wires. The chlorine and hydrogen produced in the electrolysis of brine are useful chemicals.
| Use | What happens | Why electrolysis |
|---|---|---|
| extracting aluminium | aluminium oxide dissolved in molten cryolite is electrolysed | aluminium is too reactive to extract with carbon |
| electroplating | a metal object is coated with another metal | a thin, even layer of metal forms on the cathode |
| purifying copper | impure copper is the anode; pure copper is deposited on the cathode | gives very pure copper for wires |
| producing chlorine and hydrogen | concentrated brine is electrolysed | produces useful gases and sodium hydroxide |
Key ideas
- Aluminium is extracted by electrolysis of aluminium oxide dissolved in molten cryolite.
- Electroplating: the object is the cathode, coated with a thin, even layer of metal.
- Purifying copper: impure copper is the anode; pure copper forms on the cathode.
- Electrolysis of brine gives chlorine, hydrogen and sodium hydroxide.
Method. Compare the reactivity of aluminium with carbon.
- Reactivity. Aluminium is more reactive than carbon.more reactive
- Conclude. So carbon cannot reduce aluminium oxide; electrolysis is needed.electrolysis needed
- Write the answer. aluminium is too reactive to be extracted by reduction with carbon
Check. Aluminium is in the reactivity series above carbon. ✓
Method. The object must be coated, so it is where the metal forms.
- Recall. The metal is deposited on the cathode.cathode
- Decide. So the object is the cathode.cathode
- Write the answer. cathode
Check. The silver is the anode and dissolves into the solution. ✓
Method. Impure copper is dissolved away from the anode.
- Recall. Impure copper is the anode.anode
- Decide. Pure copper is then deposited on the cathode.pure copper
- Write the answer. anode
Check. Pure copper forms on the cathode. ✓
Watch out
Watch out: in electroplating, the object must be the cathode. The metal being plated comes from the anode.
Exam tip
Exam tip. Name the electrode and say what happens there: deposition at the cathode or dissolving at the anode.
Exercise 11E Uses of electrolysis
Method. Recall the metal.
- Recall. Aluminium is extracted by electrolysis.aluminium
- Write the answer. aluminium
Check. Aluminium oxide is dissolved in molten cryolite. ✓
Method. Recall the solvent for aluminium oxide.
- Recall. Aluminium oxide is dissolved in molten cryolite to lower its melting point.cryolite
- Write the answer. cryolite
Check. Cryolite lowers the melting point. ✓
Method. The metal is deposited on the cathode.
- Recall. The object is the cathode.cathode
- Write the answer. cathode
Check. The metal forms as a layer on the object. ✓
Method. Pure copper is deposited.
- Recall. Pure copper is deposited on the cathode.cathode
- Write the answer. cathode
Check. Impure copper is the anode. ✓
Method. Recall a use.
- Recall. Electroplating coats objects with metals such as chromium or silver.chromium or silver
- Write the answer. Accept any of: chromium plating, silver plating, gold plating of jewellery.
Check. Electroplating also protects metals from corrosion. ✓
Method. Recall the products.
- Recall. Chlorine and hydrogen gases, and sodium hydroxide solution, are formed.chlorine, hydrogen, sodium hydroxide
- Write the answer. Accept any two of: chlorine, hydrogen, sodium hydroxide.
Check. Brine is concentrated sodium chloride solution. ✓
Method. Compare reactivity.
- Reactivity. Aluminium is above carbon in the reactivity series.above carbon
- Conclude. Carbon cannot reduce aluminium oxide, so electricity is used.electricity used
- Write the answer. aluminium is more reactive than carbon, so carbon cannot reduce its oxide
Check. Electricity provides the electrons. ✓
Method. The solution must contain ions of the plating metal.
- Recall. The solution contains copper ions, such as from copper sulfate.copper ions
- Write the answer. Accept copper sulfate.
Check. Copper ions are reduced at the cathode. ✓
Method. Think about impurities.
- Impurities. Impurities disrupt the lattice of the metal.disrupt
- Conclude. So pure copper conducts electricity better.conducts better
- Write the answer. Accept any sentence that says impurities reduce the conductivity, so pure copper conducts better.
Check. Electrolysis gives very pure copper. ✓
Method. Think about the layer.
- Layer. A thin metal layer is put on the object.thin layer
- Benefit. It protects the metal below from corrosion, or improves its look.protects or improves
- Write the answer. Accept any answer that says it protects a metal from corrosion or improves its appearance.
Check. Chromium plating is used on car parts. ✓
Chapter summary
| Skill | Method |
|---|---|
| Electrolysis | Breaking an ionic compound with electricity; the electrolyte must be molten or dissolved. |
| Electrodes | Cathode (-): reduction, cations go here. Anode (+): oxidation, anions go here. |
| Aqueous solutions | Selective discharge: the less reactive ion is discharged; H+ and OH- from water matter. |
| Oxidation and reduction | Oxidation: loss of electrons or gain of oxygen. Reduction: gain of electrons or loss of oxygen. |
| [H] Half equations | Show the electrons; balance atoms and charge on each side. |
| Uses | Aluminium extraction (molten cryolite), electroplating, purifying copper, chlorine and hydrogen from brine. |
Can you…?
- I can name the electrode products of molten and aqueous electrolysis
- I can predict products using selective discharge
- I can identify oxidation and reduction in terms of electrons and oxygen
- [H] I can write and check half equations
- I can describe the uses of electrolysis, including aluminium extraction and electroplating
Key terms
- electrolysis
- the breaking down of an ionic compound by electricity
- electrolyte
- the molten or dissolved ionic compound that is electrolysed
- cathode
- the negative electrode, where positive ions gain electrons
- anode
- the positive electrode, where negative ions lose electrons
- selective discharge
- the ion that is discharged at an electrode is the one less reactive than the others
- oxidation
- the loss of electrons, or the gain of oxygen
- reduction
- the gain of electrons, or the loss of oxygen
- half equation
- [H] an equation showing the electrons gained or lost at one electrode
Exercise 11Z Check-up
Method. Recall the name.
- Recall. The negative electrode is the cathode.cathode
- Write the answer. cathode
Check. The anode is positive. ✓
Method. Sodium ions are reduced.
- Recall. Na+ gains an electron to form sodium.sodium
- Write the answer. sodium
Check. Chlorine forms at the anode. ✓
Method. OH- is discharged at the anode.
- Recall. Oxygen forms at the anode.oxygen
- Write the answer. oxygen
Check. The copper forms at the cathode. ✓
Method. Recall the definition.
- Recall. Oxidation is the loss of electrons.loss
- Write the answer. loss of electrons
Check. OIL: oxidation is loss. ✓
Method. CuO loses oxygen.
- Recall. Reduction is the loss of oxygen; CuO loses oxygen.CuO
- Write the answer. CuO
Check. H2 is oxidised. ✓
Method. Three electrons are needed.
- Equation. Al3+ + 3e- -> Al.Al3+ + 3e- -> Al
- Write the answer. Al3+ + 3e- -> Al
Check. Charge +3 - 3 = 0. ✓
Method. Bromide ions are oxidised.
- Recall. Bromine forms at the anode.bromine
- Write the answer. bromine
Check. Lead forms at the cathode. ✓
Method. Recall the process.
- Recall. Electroplating coats a metal object with a thin layer of another metal.coating
- Write the answer. coating an object with a metal using electrolysis
Check. The object is the cathode. ✓
Method. Think about the ions.
- Ions. In the solid, the ions are fixed in the lattice.fixed
- Conclude. They must be molten or dissolved to move to the electrodes.move
- Write the answer. Accept any sentence that says its ions are fixed and cannot move to the electrodes.
Check. Melting or dissolving frees the ions. ✓
Method. Think about reactivity.
- Reactivity. Aluminium is more reactive than carbon.more reactive
- Conclude. So electricity is used instead of carbon.electricity
- Write the answer. Accept any sentence that says aluminium is too reactive to be reduced by carbon.
Check. Electrolysis uses electrons from the power supply. ✓
Total 20 marks. Allow about 20 minutes.
Exercise 11X Exam-style questions
Method. Recall the products.
- Cathode. Sodium is formed at the cathode.sodium
- Anode. Chlorine is formed at the anode.chlorine
- Write the answer. sodium, chlorine
Check. Sodium is reduced; chlorine is oxidised. ✓
Method. Product and reason.
- Product. Copper is formed at the cathode.copper
- Reason. Copper is less reactive than hydrogen, so its ions are discharged.less reactive
- Write the answer. Accept copper, with a reason that copper is less reactive than hydrogen.
Check. Selective discharge. ✓
Method. Zinc loses electrons.
- Look. Zinc goes from 0 to +2, losing electrons.loses electrons
- Decide. So zinc is oxidised.Zn
- Write the answer. Zn
Check. Copper ions are reduced. ✓
Method. Two Cl- lose two electrons.
- Atoms. Two Cl- form Cl2.2Cl- -> Cl2
- Electrons. Two electrons are released, so 2e-.+ 2e-
- Write the answer. 2Cl- -> Cl2 + 2e-
Check. Charge -2 = 0 - 2. ✓
Method. Describe the process.
- Anode. Impure copper is the anode, and copper dissolves from it.anode
- Cathode. Pure copper is deposited on the cathode.cathode
- Write the answer. Accept any answer that says impure copper is the anode and pure copper is deposited on the cathode.
Check. Impurities fall to the bottom of the cell. ✓
Method. Think about the energy.
- Melting point. Aluminium oxide has a very high melting point.high
- Conclude. Cryolite lowers the melting point, so less energy is needed.less energy
- Write the answer. Accept any answer that says cryolite lowers the melting point, saving energy.
Check. The electrolysis then takes place at a lower temperature. ✓
Method. Two electrons are gained.
- Electrons. Cu2+ gains 2 electrons to form Cu.2e-
- Equation. Cu2+ + 2e- -> Cu.Cu2+ + 2e- -> Cu
- Write the answer. Cu2+ + 2e- -> Cu
Check. Charge +2 - 2 = 0. ✓
Method. Think about the electrons.
- Anode. At the anode, negative ions lose electrons.lose electrons
- Conclude. Loss of electrons is oxidation.oxidation
- Write the answer. Accept any sentence that says ions lose electrons, which is oxidation.
Check. OIL: oxidation is loss. ✓
Method. Choose one use and describe it.
- Use. Electroplating coats an object with a metal.electroplating
- Electrode. The object is the cathode, where the metal ions are reduced and deposited.cathode
- Write the answer. Accept any use with a correct electrode statement, such as electroplating with the object at the cathode.
Check. Other uses include extracting aluminium. ✓