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GCSE Maths · EdexcelChapter 9 · Linear equations
GCSE Maths · Linear Equations · Higher · Lesson 9.1

GCSE Maths: Equations and the balance idea (Higher)

Part of the GCSE Maths linear equations chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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9.1

Equations and the balance idea

Edexcel 1MA1: A17
Grade 1-3

In algebra a letter stands for a number that we do not know yet. An expression such as 3x + 5 has no equals sign. It is just a recipe for making a number, so it has no single answer. An equation such as 3x + 5 = 20 does have an equals sign. It says that two things have the same value. To solve an equation means to find the value of the letter that makes the statement true.

The best way to think about an equation is as a pair of balanced scales. Whatever is on the left pan weighs exactly the same as whatever is on the right pan. In the picture, the blue box is an unknown mass x and each orange circle is 1 kg. The scales balance, so x + 3 = 7.

xx + 3 = 7xx = 4
Take 3 away from both pans and the scales still balance. The box is left on its own, and it balances 4 circles, so x = 4.

This gives us the one rule of equation solving: whatever you do to one side, do the same to the other side. If you take 3 kg off one pan but not the other, the scales tip and the equation is no longer true. Our aim is always to get the letter on its own, with nothing added to it, taken away from it, multiplying it or dividing it.

To get the letter on its own we undo what has been done to it. We use the inverse operation, which is the operation that does the opposite. Adding and subtracting are inverses of each other. Multiplying and dividing are inverses of each other.

The equation looks likeIt meansDo this to both sides
x + 5 = 125 has been addedsubtract 5
x − 5 = 125 has been taken awayadd 5
5x = 20x has been multiplied by 5divide by 5
x5 = 4x has been divided by 5multiply by 5

Remember that 5x is short for 5 × x: in algebra we do not write the multiplication sign. Also remember that x5 means x ÷ 5, as you saw with fractions in Chapter 3.

xx2x = 8xx = 4
Two equal boxes balance 8 circles. Cut each pan in half (divide both sides by 2): one box balances 4 circles.

Key ideas

  • An equation has an equals sign; an expression does not.
  • To solve an equation is to find the value of the letter that makes it true.
  • Do the same to both sides so that the equation stays balanced.
  • Use the inverse operation: the opposite of + is −, and the opposite of × is ÷.
  • Finish with the letter on its own: x = a number.
Worked example 9.1.1
Solve x + 7 = 15.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x + 7 = 15
  2. Subtract 7 from both sides. This undoes the +7, because +7 − 7 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    x + 7 − 7 = 15 − 7
    x = 8
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 8

Check. Substitute x = 8 into the original equation. Left side: 8 + 7 = 15. Right side: 15. Both sides equal 15, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.1.2
Solve x − 4 = 9.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x − 4 = 9
  2. Add 4 to both sides. This undoes the −4, because −4 + 4 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    x − 4 + 4 = 9 + 4
    x = 13
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 13

Check. Substitute x = 13 into the original equation. Left side: 13 − 4 = 9. Right side: 9. Both sides equal 9, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.1.3
Solve 5x = 35.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    5x = 35
  2. Divide both sides by 5. 5x means 5 multiplied by x. The inverse of multiplying by 5 is dividing by 5, and we do it to both sides to keep the balance. This leaves x on its own.
    5x5 = 355
    x = 355 = 7
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 7

Check. Substitute x = 7 into the original equation. Left side: 5 × 7 = 35. Right side: 35. Both sides equal 35, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.1.4
Solve x3 = 6.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x3 = 6
  2. Multiply both sides by 3. x3 means x divided by 3. The inverse of dividing by 3 is multiplying by 3. We do it to both sides to keep the balance.
    3 × x3 = 3 × 6
    x = 18
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 18

Check. Substitute x = 18 into the original equation. Left side: 183 = 6. Right side: 6. Both sides equal 6, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Watch out

Do the opposite operation. To solve x + 6 = 15 you subtract 6 from both sides, giving x = 9. Adding 6 would give 21, which is wrong. Always check your answer by putting it back into the equation.

Exercise 9A  Equations and one-step equations

Non-calculator
1
FWrite down whether each of these is an expression or an equation.
(a)4x + 1
(b)4x + 1 = 13
(c)7 − x
(d)x5 = 2
2
FSolve these equations. Each one needs you to subtract.
(a)x + 3 = 10
(b)x + 8 = 15
(c)x + 6 = 9
(d)x + 15 = 40
(e)7 + x = 12
(f)x + 25 = 61
3
FSolve these equations. Each one needs you to add.
(a)x − 2 = 7
(b)x − 5 = 9
(c)x − 10 = 4
(d)x − 1 = 20
(e)x − 8 = 8
(f)x − 3 = 0
4
FSolve these equations. Each one needs you to divide.
(a)2x = 14
(b)5x = 20
(c)3x = 27
(d)10x = 90
(e)4x = 36
(f)7x = 56
5
FSolve these equations. Each one needs you to multiply.
(a)x2 = 5
(b)x3 = 4
(c)x5 = 6
(d)x10 = 3
(e)x4 = 8
(f)x7 = 7
6
FWrite down the operation you do to both sides first to get x on its own. You do not need to finish solving.
(a)x + 9 = 14
(b)x − 6 = 10
(c)4x = 20
(d)x5 = 3
7
FSolve these equations, using what you know about inverse operations.
(a)x + 47 = 91
(b)8x = 96
(c)x − 29 = 31
(d)x6 = 12
(e)x + 148 = 372
(f)12x = 180
8
PSRavi thinks of a number. He adds 9 and gets 25. What number did Ravi think of?
9
PSA box of 8 identical chocolates costs £6. Work out the cost of one chocolate. Give your answer in pence.
10
PSThe scales balance. The box has a mass of x kg. Write down an equation and use it to find the mass of the box.
x12box + 5 kg = 12 kg
11
FSam says “x = 4” is the solution of each equation. Substitute 4 for x to decide whether he is right. Write yes or no.
(a)x + 5 = 9
(b)3x = 15
(c)x − 2 = 3
(d)x2 = 2
12
RSam solves x + 6 = 15 and writes x = 21. Explain his mistake and work out the correct solution.
13
PSWrite an equation for each sentence, then solve it to find the number.
(a)A number plus 7 is 19
(b)A number minus 6 is 11
(c)5 times a number is 40
(d)A number divided by 4 is 9
14
RThe equations x + a = 12 and 3x = 18 have the same solution. Work out the value of a.

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