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GCSE Maths · EdexcelChapter 10 · Inequalities
GCSE Maths · Inequalities · Foundation · Lesson 10.6

GCSE Maths: Forming and solving inequalities from context (Foundation)

Part of the GCSE Maths inequalities chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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10.6

Forming and solving inequalities from context

Edexcel 1MA1: A22
Grade 4-6

Many exam questions describe a real situation in words. You must turn the words into an inequality, solve it, and then explain what your answer means in the situation. Follow these steps.

  1. Choose a letter for the unknown and say what it stands for.
  2. Write an expression for each amount in the problem (for example, 7 tickets at £n each costs 7n pounds).
  3. Choose the sign from the key phrase: “at most” is ≤, “at least” is ≥, “less than” is <, “more than” is >.
  4. Solve the inequality.
  5. Interpret the answer: if you are counting things, the answer must be a whole number, and you must round the correct way. Then check it in the original problem.

Rounding the correct way. If the solution is n ≤ 6.29 (tickets), you cannot buy 6.29 tickets. The largest whole number that works is 6. If the solution is n ≥ 18.67 (weeks), the smallest whole number that works is 19, because 18 weeks is not enough. Always round so that the condition is still true, not to the nearest number.

Totals and means. A total is built by adding the pieces. A mean is the total divided by the number of values, so “the mean of four marks is at least 65” becomes (total of marks) ÷ 4 ≥ 65.

Key ideas

  • Choose a letter and say what it means.
  • Key phrases: at most = ≤, at least = ≥, less than = <, more than = >.
  • Solve, then interpret in context.
  • For counting problems, the answer must be a whole number: round down for an upper limit and up for a lower limit.
  • Always check the answer by substituting back into the story.
Worked example 10.6.1
Sam has £50 to spend. Cinema tickets cost £7 each, and he also buys a drink for £6. What is the greatest number of tickets he can buy?

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Turn the words into an inequality, solve it, then say what the answer means in the context of the question.

  1. Choose a letter. Let n be the number of tickets Sam buys.
  2. Write an inequality. The tickets cost 7n pounds, and the drink costs £6. The total must be at most £50, so we use ≤.
    7n + 6 ≤ 50
  3. Get the plain numbers on the other side. Subtract 6 from both sides. This is the inverse of adding 6.
    7n ≤ 44
  4. Divide both sides by 7. 7n means 7 lots of n. The inverse of multiplying by 7 is dividing by 7. 7 is positive, so the inequality sign stays the same.
    n ≤ 44 ÷ 7 = 447
  5. Answer the question in words. The inequality says the number is less than or equal to 447. Because the number of tickets must be a whole number, we need the largest whole number that fits.
    6 tickets

Check. Test a value inside the solution: n = 6 gives left side = 7 × 6 + 6 = 48, right side = 50. Is 48 ≤ 50? Yes, it is true. ✓
Test a value outside it: n = 7 gives left side = 7 × 7 + 6 = 55, right side = 50. Is 55 ≤ 50? No, it is false, so 7 is correctly left out.

Watch out. Always finish by answering the question that was asked, using the right units, and check whether the answer must be a whole number.

Worked example 10.6.2
A rectangle has length (x + 4) cm and width 3 cm. Its perimeter is less than 30 cm. Find the possible values of x.

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Turn the words into an inequality, solve it, then say what the answer means in the context of the question.

  1. Choose a letter. Let x cm be the unknown length.
  2. Write an expression for the perimeter. A rectangle has two lengths and two widths, so the perimeter is 2(x + 4) + 2 × 3. Expand: 2x + 8 + 6.
    Perimeter = 2x + 14
  3. Get the plain numbers on the other side. Subtract 14 from both sides. This is the inverse of adding 14.
    2x < 16
  4. Divide both sides by 2. 2x means 2 lots of x. The inverse of multiplying by 2 is dividing by 2. 2 is positive, so the inequality sign stays the same.
    x < 16 ÷ 2 = 8
  5. Answer the question in words. The length is (x + 4) cm, so x is just a number. It does not have to be whole.
    x < 8 cm

Check. Test a value inside the solution: x = 7 gives left side = 2 × 7 + 14 = 28, right side = 30. Is 28 < 30? Yes, it is true. ✓
Test a value outside it: x = 9 gives left side = 2 × 9 + 14 = 32, right side = 30. Is 32 < 30? No, it is false, so 9 is correctly left out.

Watch out. Always finish by answering the question that was asked, using the right units, and check whether the answer must be a whole number.

Worked example 10.6.3
Tom scored 62, 70 and 58 in three tests. He wants his mean mark over four tests to be at least 65. What mark does he need in the fourth test?

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Turn the words into an inequality, solve it, then say what the answer means in the context of the question.

  1. Choose a letter. Let x be Tom’s mark in the fourth test.
  2. Write an inequality. The total of the four marks is 62 + 70 + 58 + x = (190 + x). The mean is the total divided by 4, and it must be at least 65.
    (x + 190) ÷ 4 ≥ 65
  3. Multiply both sides by 4 to get rid of the fraction. Multiplying by the denominator cancels the division. 4 is a positive number, so the inequality sign does not change.
    x + 190 ≥ 260
  4. Get the plain numbers on the other side. Subtract 190 from both sides. This is the inverse of adding 190.
    x ≥ 70
  5. Answer the question in words. Tom needs at least this mark in the fourth test.
    x ≥ 70 marks

Check. Test a value inside the solution: x = 71 gives left side = 71 + 1904 = 65.25, right side = 65. Is 65.25 ≥ 65? Yes, it is true. ✓
Test a value outside it: x = 69 gives left side = 69 + 1904 = 64.75, right side = 65. Is 64.75 ≥ 65? No, it is false, so 69 is correctly left out.

Watch out. Always finish by answering the question that was asked, using the right units, and check whether the answer must be a whole number.

Worked example 10.6.4
Plan A costs £10 plus £4 per hour. Plan B costs £25 plus £1 per hour. For how many hours is Plan A cheaper than Plan B?

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Turn the words into an inequality, solve it, then say what the answer means in the context of the question.

  1. Choose a letter. Let h be the number of hours.
  2. Write an expression for each plan. Plan A costs 10 + 4h pounds. Plan B costs 25 + h pounds. We want A to be cheaper, so A < B.
    4h + 10 < h + 25
  3. Get the h terms on one side. There are h terms on both sides. We remove the smaller one, so that the h term left over is positive and we do not need to divide by a negative number later.
    Subtract h from both sides:
    3h + 10 < 25
  4. Get the plain numbers on the other side. Subtract 10 from both sides. This is the inverse of adding 10.
    3h < 15
  5. Divide both sides by 3. 3h means 3 lots of h. The inverse of multiplying by 3 is dividing by 3. 3 is positive, so the inequality sign stays the same.
    h < 15 ÷ 3 = 5
  6. Answer the question in words. Plan A is cheaper for fewer than this number of hours.
    h < 5 hours

Check. Test a value inside the solution: h = 4 gives left side = 4 × 4 + 10 = 26, right side = 4 + 25 = 29. Is 26 < 29? Yes, it is true. ✓
Test a value outside it: h = 6 gives left side = 4 × 6 + 10 = 34, right side = 6 + 25 = 31. Is 34 < 31? No, it is false, so 6 is correctly left out.

Watch out. Always finish by answering the question that was asked, using the right units, and check whether the answer must be a whole number.

Watch out

The answer must make sense. If the answer is a number of people, tickets or cakes it must be a whole number, and you must round the right way: n ≤ 6.29 means at most 6, not 7. Also, do not use the nearest whole number blindly: n ≥ 18.67 means at least 19.

Exam tip

Write down what your letter stands for in a short sentence at the start. Examiners award marks for defining the variable, and it helps you avoid mixing up quantities.

Exercise 10G  Inequalities in context

Non-calculator
1
FWrite an inequality for each situation. You do not need to solve it.
(a)Ali has £40. Pens cost £3 each. He buys n pens and a £5 book.
(b)A taxi charges £4 plus £2 per mile. A journey of m miles costs less than £30.
(c)I think of a number x, multiply it by 5 and subtract 8. The result is at least 22.
(d)The perimeter of a square with side s cm is greater than 50 cm.
(e)A rectangle has width 5 cm and length (x + 3) cm. Its perimeter is at most 36 cm.
2
PSAli has £40. Pens cost £3 each, and he also buys a £5 book. What is the greatest number of pens he can buy?
3
PSA taxi charges £4 plus £2 per mile. Rosie has less than £30 to spend on the fare. How far can she travel?
4
PSA lift can carry at most 200 kg. Sam weighs 80 kg and carries boxes that each weigh 12 kg into the lift. What is the greatest number of boxes he can carry?
5
PSA club sells cakes for £3 each. The ingredients cost £25 in total. They want a profit of at least £50. How many cakes must they sell, at least?
6
PSMaya has saved £120. She saves £15 each week. She wants to have at least £400. What is the smallest number of whole weeks she needs to save?
7
PSAli is x years old. His sister is 3 years older. The sum of their ages is less than 30. What is the greatest whole number of years Ali could be?
8
PSGym A charges £15 to join and £8 per month. Gym B charges £5 to join and £12 per month. After how many whole months is Gym A cheaper than Gym B? Give the smallest number of months.
9
PSZara scores 64, 71 and 58 in three tests. She wants a mean of at least 65 over four tests. What must she score in the fourth test?
10
PSI think of a whole number, double it, and subtract 7. The answer is greater than 15. What is the smallest number I could be thinking of?
11
PSAn isosceles triangle has two sides of length (2x + 1) cm and a third side of 9 cm. Its perimeter is less than 40 cm. Find the possible values of x.
12
RIn the cinema problem a student gets n ≤ 6.29 and answers “6.29 tickets”. Explain why this is wrong and what the answer should be.
13
RA student writes “each notebook costs £2 and I have £15, so 2n ≥ 15”. Explain the mistake and write the correct inequality.
14
RTwo sides of a triangle are 5 cm and 8 cm. The third side is x cm. In any triangle the sum of two sides must be greater than the third side. Write down the range of values of x.

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