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GCSE Maths · EdexcelChapter 10 · Inequalities
GCSE Maths · Inequalities · Higher · Lesson 10.3

GCSE Maths: Solving linear inequalities (Higher)

Part of the GCSE Maths inequalities chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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10.3

Solving linear inequalities

Edexcel 1MA1: A22
Grade 3-5

You already know how to solve an equation such as 2x + 3 = 11. You do the same thing to both sides, like a pair of balanced scales, until the letter is on its own. Solving an inequality works in almost exactly the same way. The only difference is that the answer is a range of values, and there is one important new rule (see Section 10.4).

Why can we do the same to both sides? Start with a true statement: 3 < 7. Add 2 to both sides: 5 < 9, still true. Subtract 1 from both sides: 2 < 6, still true. Multiply both sides by 2: 6 < 14, still true. Divide both sides by 2: 1.5 < 3.5, still true. Adding, subtracting, and multiplying or dividing by a positive number keeps the inequality true and keeps the sign the same.

The method. Use inverse operations, in this order:

  1. Undo any adding or subtracting first (these are the furthest from the letter).
  2. Then undo any multiplying or dividing.
  3. Keep the inequality sign the same as you go (as long as you only multiply or divide by positive numbers).
  4. Write the answer as x < … or x > … (letter on the left).

Reading the answer. The solution x > 4 does not mean x equals 4. It means x can be any number bigger than 4. Always test your answer: choose a number that should be a solution and one that should not, and put each back into the original inequality.

Letter on the right. If the letter is on the right-hand side, for example 12 > 2x + 4, solve in the same way and you will get 4 < x. This is fine, but it is neater to turn it round: 4 < x says the same as x > 4 (the sign still points at the smaller number).

Key ideas

  • Adding or subtracting the same number on both sides keeps the sign the same.
  • Multiplying or dividing both sides by a positive number keeps the sign the same.
  • Undo +/− first, then ×/÷.
  • The solution is a range of values, so test one value inside and one outside.
  • Turn a result such as 4 < x round to x > 4 (the sign still points at the small number).
Worked example 10.3.1
Solve x + 7 > 12.

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Solve it like an equation: do the same to both sides to get the letter on its own. The one new rule: multiplying or dividing both sides by a negative number reverses the inequality sign.

  1. Write down the inequality. We want the letter on its own on one side. We do this by doing the same thing to both sides, exactly as when solving an equation.
    x + 7 > 12
  2. Get the plain numbers on the other side. Subtract 7 from both sides. This is the inverse of adding 7.
    x > 5
  3. State the solution. This is the complete set of values that make the inequality true.
    x > 5

Check. Test a value inside the solution: x = 6 gives left side = 6 + 7 = 13, right side = 12. Is 13 > 12? Yes, it is true. ✓
Test a value outside it: x = 4 gives left side = 4 + 7 = 11, right side = 12. Is 11 > 12? No, it is false, so 4 is correctly left out.

Watch out. The sign only reverses when you multiply or divide by a negative number. Otherwise leave it alone, and keep the “or equal to” part of ≤ and ≥ exactly as it was.

Worked example 10.3.2
Solve 3x − 4 ≤ 11, and show the solution on a number line.

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Solve it like an equation: do the same to both sides to get the letter on its own. The one new rule: multiplying or dividing both sides by a negative number reverses the inequality sign.

  1. Write down the inequality. We want the letter on its own on one side. We do this by doing the same thing to both sides, exactly as when solving an equation.
    3x − 4 ≤ 11
  2. Get the plain numbers on the other side. Add 4 to both sides. This is the inverse of subtracting 4.
    3x ≤ 15
  3. Divide both sides by 3. 3x means 3 lots of x. The inverse of multiplying by 3 is dividing by 3. 3 is positive, so the inequality sign stays the same.
    x ≤ 15 ÷ 3 = 5
  4. State the solution. This is the complete set of values that make the inequality true.
    x ≤ 5
    On a number line: a closed (filled) circle at 5 with an arrow pointing left.
    2345678

Check. Test a value inside the solution: x = 4 gives left side = 3 × 4 − 4 = 8, right side = 11. Is 8 ≤ 11? Yes, it is true. ✓
Test a value outside it: x = 6 gives left side = 3 × 6 − 4 = 14, right side = 11. Is 14 ≤ 11? No, it is false, so 6 is correctly left out.

Watch out. The sign only reverses when you multiply or divide by a negative number. Otherwise leave it alone, and keep the “or equal to” part of ≤ and ≥ exactly as it was.

Worked example 10.3.3
Solve x/4 + 3 ≥ 5.

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Solve it like an equation: do the same to both sides to get the letter on its own. The one new rule: multiplying or dividing both sides by a negative number reverses the inequality sign.

  1. Write down the inequality. We want the letter on its own on one side. We do this by doing the same thing to both sides, exactly as when solving an equation.
    x4 + 3 ≥ 5
  2. Multiply both sides by 4 to get rid of the fraction. Multiplying by the denominator cancels the division. 4 is a positive number, so the inequality sign does not change.
    x + 12 ≥ 20
  3. Get the plain numbers on the other side. Subtract 12 from both sides. This is the inverse of adding 12.
    x ≥ 8
  4. State the solution. This is the complete set of values that make the inequality true.
    x ≥ 8

Check. Test a value inside the solution: x = 9 gives left side = 94 + 3 = 5.25, right side = 5. Is 5.25 ≥ 5? Yes, it is true. ✓
Test a value outside it: x = 7 gives left side = 74 + 3 = 4.75, right side = 5. Is 4.75 ≥ 5? No, it is false, so 7 is correctly left out.

Watch out. The sign only reverses when you multiply or divide by a negative number. Otherwise leave it alone, and keep the “or equal to” part of ≤ and ≥ exactly as it was.

Worked example 10.3.4
Solve 12 > 2x + 4.

Key words. An inequality compares two quantities using < (less than), > (greater than), ≤ (less than or equal to) or ≥ (greater than or equal to). To solve an inequality means to find all the values of the letter that make it true. The answer is usually a whole range of values, not just one number.

Method. Solve it like an equation: do the same to both sides to get the letter on its own. The one new rule: multiplying or dividing both sides by a negative number reverses the inequality sign.

  1. Write down the inequality. We want the letter on its own on one side. We do this by doing the same thing to both sides, exactly as when solving an equation.
    12 > 2x + 4
  2. Get the plain numbers on the other side. Subtract 4 from both sides.
    8 > 2x
  3. Divide both sides by 2. The inverse of multiplying by 2 is dividing by 2. 2 is positive, so the inequality sign stays the same.
    8 ÷ 2 = 4
    4 > x
  4. Write it with x on the left. 4 > x says the same thing as x < 4: the sign still points to the smaller number.
    x < 4
  5. State the solution. This is the complete set of values that make the inequality true.
    x < 4

Check. Test a value inside the solution: x = 3 gives left side = 12, right side = 2 × 3 + 4 = 10. Is 12 > 10? Yes, it is true. ✓
Test a value outside it: x = 5 gives left side = 12, right side = 2 × 5 + 4 = 14. Is 12 > 14? No, it is false, so 5 is correctly left out.

Watch out. The sign only reverses when you multiply or divide by a negative number. Otherwise leave it alone, and keep the “or equal to” part of ≤ and ≥ exactly as it was.

Watch out

Do not change the inequality sign into an equals sign half way through, and do not drop the “or equal to” line. If you start with ≤, you must finish with ≤. Also, only the letter on its own is the answer: 3x > 6 is not finished until you divide by 3.

Exam tip

Always finish with a quick test. Pick a whole number in your solution, put it into the original inequality, and check that it is true.

Exercise 10C  Solving one-step and two-step inequalities

Non-calculator
1
FSolve each inequality.
(a)x + 5 > 9
(b)x − 3 ≤ 4
(c)2x < 14
(d)x4 ≥ 3
(e)x + 7 ≤ 2
(f)5x > 35
2
FSolve each inequality.
(a)2x + 3 > 11
(b)3x − 4 ≤ 14
(c)5x + 1 < 26
(d)4x − 7 ≥ 9
(e)2x + 9 ≤ 3
(f)6x − 5 > −17
3
FSolve each inequality. Give your answer with x on the left.
(a)12 > 2x + 4
(b)20 ≤ 3x − 1
(c)7 < 5x − 8
(d)10 ≥ 4x + 2
(e)−4 < 2x + 6
(f)2 > 3x − 7
4
FSolve each inequality. (The letter is divided by a number.)
(a)x3 − 2 > 1
(b)x2 + 3 ≤ 5
(c)x5 + 1 ≥ 4
(d)2x3 < 8
5
RHana solves 2x − 5 < 9 and writes x < 2. Explain her mistake and give the correct solution.
6
RShow that x = 4 is a solution of 5x − 3 > 12, but x = 3 is not.
7
PSSolve 4x − 3 ≤ 17. Write down the largest whole number that satisfies the inequality.
8
PSSolve 3n + 5 > 20. Write down the smallest whole number that satisfies the inequality.
9
PSThe number n satisfies 5n − 4 < 31. What is the largest whole-number value of n?
10
PSSolve 2x + 7 ≥ 25 and show your solution on a number line.
11
RSolve 3x + 2 = 14 and 3x + 2 > 14. What is the difference between the two answers?
12
RIs it true that 2x < 10 and 10 > 2x have the same solutions? Show your working.
13
RMia and Leo both solve 3x + 4 > 19. Mia gets x > 5. Leo gets x ≥ 5. Who is right? Test x = 5 to decide.

Exercise 10D  Solving, number lines and whole-number solutions

Non-calculator
1
FSolve each inequality and show the solution on a number line.
(a)2x + 1 > 9
(b)3x − 2 ≤ 7
(c)4x + 5 < 1
(d)5x − 1 ≥ 14
2
FSolve each inequality, then write down the largest whole number that satisfies it.
(a)2x + 3 < 12
(b)5x − 1 ≤ 24
(c)3x + 2 < 9
(d)4x + 1 ≤ 20
3
FSolve each inequality, then write down the smallest whole number that satisfies it.
(a)3x + 1 > 13
(b)2x − 5 ≥ 4
(c)5x + 2 > 6
4
FSolve each inequality, then list the positive whole numbers that satisfy it.
(a)2x + 1 < 11
(b)3x ≤ 12
(c)5x − 3 < 12
(d)4x + 3 ≤ 20
5
PSSam thinks of a whole number, n. He multiplies it by 3 and adds 4. The answer is less than 30. What is the largest number Sam could be thinking of?
6
RDev solves 2x + 1 < 8 and gets x < 3.5. He says the largest whole number is 4. Is he right? Explain.
7
RExplain why the smallest whole number satisfying n > 1.3 is 2, and not 1.
8
FSolve each inequality.
(a)x + 32 ≥ 4
(b)2x − 13 < 5
(c)x + 45 > 3
9
FSolve each inequality.
(a)x + 32 ≥ x − 13
(b)2x − 13 < x + 42
(c)3x + 14 > x − 23

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