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GCSE Maths · EdexcelChapter 12 · Straight-line graphs and coordinates
GCSE Maths · Straight-Line Graphs and Coordinates · Higher · Lesson 12.4

GCSE Maths: Gradient (Higher)

Part of the GCSE Maths straight-line graphs and coordinates chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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12.4

Gradient

Edexcel 1MA1: A10, A9
Grade 3-5

The gradient of a line tells you how steep it is. A steep hill has a big gradient; a gentle slope has a small one; flat ground has a gradient of zero. To measure it, compare how far the line goes up with how far it goes across:

gradient = rise ÷ run = (change in y) ÷ (change in x)

The rise is the vertical change and the run is the horizontal change. Always move from left to right, so the run is positive. Then the rise tells you the direction: if the line goes up the rise is positive, and if it goes down the rise is negative.

xy−5−4−3−2−112345−5−4−3−2−112345Ogradient 2gradient ½gradient −1gradient 0
Lines that slope up have a positive gradient, lines that slope down have a negative gradient, and a flat line has a gradient of 0. The bigger the number (ignoring the sign), the steeper the line.

Finding the gradient from a graph

Choose two points on the line that sit exactly on grid corners, as far apart as you sensibly can. Draw a right-angled triangle under the line, count the squares for the run and the rise, and divide. The picture shows a line with a rise of 6 for a run of 3, so its gradient is 6 ÷ 3 = 2: it goes up 2 for every 1 step across.

xy−4−3−2−11234−4−3−2−1123456Orun = 4rise = 8
The gradient triangle on the line y = 2x − 1: rise ÷ run = 6 ÷ 3 = 2.

Finding the gradient from two points

You do not need a picture. If the points are (x1, y1) and (x2, y2), the rise is y2 − y1 and the run is x2 − x1:

gradient = (y2 − y1) ÷ (x2 − x1)

It does not matter which point you call point 1, as long as you subtract in the same order on the top and on the bottom. Simplify the fraction at the end.

Special cases

A horizontal line has a rise of 0, so its gradient is 0. A vertical line has a run of 0, and you cannot divide by 0, so a vertical line has no gradient (we say it is undefined). Gradients are often written as fractions, for example 2/3 or −3/4. Road signs show the gradient as a percentage: a gradient of 0.08 is “8%”.

Key ideas

  • Gradient = rise ÷ run = (change in y) ÷ (change in x). Read the line left to right.
  • Up from left to right: positive. Down from left to right: negative. Horizontal: 0. Vertical: undefined.
  • From two points: (y2 − y1) ÷ (x2 − x1), subtracting in the same order top and bottom.
  • The steeper the line, the bigger the gradient (ignoring the sign).
  • Simplify gradient fractions, and give the sign.
Worked example 12.4.1
Work out the gradient of the line y = 2x − 1 shown on the grid. (The equation is not needed: use the graph.)
xy−4−3−2−11234−4−3−2−1123456O

Key words. The gradient of a line is how steep it is: rise (the change up or down) divided by run (the change across, to the right). A line sloping up from left to right has a positive gradient; sloping down has a negative gradient.

Method. Gradient = rise ÷ run. Draw a triangle on the line and count the squares up (or down) and across.

  1. Choose two points on the line that are exactly on grid corners. Points that sit on crossing grid lines are easy to read accurately. Choose them far apart for the best accuracy.
    (−1, −3) and (3, 5)
  2. Draw a right-angled triangle under the line and count the run. The run is the distance across, moving to the right.
    run = 3 − (−1) = 4
  3. Count the rise. The rise is the distance up (positive) or down (negative) while moving right along the line.
    rise = 5 − (−3) = 8
  4. Mark the triangle on the graph.
    xy−4−3−2−11234−4−3−2−1123456Orun = 4rise = 8
  5. Divide the rise by the run. Gradient = rise ÷ run, simplified.
    gradient = 8 ÷ 4 = 2

Check. The line goes up from left to right, so the gradient should be positive. Also, for every 1 step across the line goes up 2. ✓

Watch out. If the line goes down as you move right, the rise is negative. Always read the line from left to right.

Worked example 12.4.2
Work out the gradient of this line.
xy−3−2−11234−5−4−3−2−112345678O

Key words. The gradient of a line is how steep it is: rise (the change up or down) divided by run (the change across, to the right). A line sloping up from left to right has a positive gradient; sloping down has a negative gradient.

Method. Gradient = rise ÷ run. Draw a triangle on the line and count the squares up (or down) and across.

  1. Choose two points on the line that are exactly on grid corners. Points that sit on crossing grid lines are easy to read accurately. Choose them far apart for the best accuracy.
    (−2, 7) and (4, −5)
  2. Draw a right-angled triangle under the line and count the run. The run is the distance across, moving to the right.
    run = 4 − (−2) = 6
  3. Count the rise. The rise is the distance up (positive) or down (negative) while moving right along the line.
    rise = −5 − 7 = -12
  4. Mark the triangle on the graph.
    xy−3−2−11234−5−4−3−2−112345678Orun = 6rise = −12
  5. Divide the rise by the run. Gradient = rise ÷ run, simplified.
    gradient = -12 ÷ 6 = −2

Check. The line goes down from left to right, so the gradient should be negative. Also, for every 1 step across the line goes down 2. ✓

Watch out. If the line goes down as you move right, the rise is negative. Always read the line from left to right.

Worked example 12.4.3
Work out the gradient of the line through A(−3, −4) and B(5, 0).

Key words. The gradient of a line is how steep it is: rise (the change up or down) divided by run (the change across, to the right). A line sloping up from left to right has a positive gradient; sloping down has a negative gradient.

Method. Gradient = rise ÷ run = (change in y) ÷ (change in x) = (y2 − y1) ÷ (x2 − x1).

  1. Label the points. Call the first point (A) (x1, y1) and the second (B) (x2, y2). It does not matter which is first, but you must be consistent.
    A = (−3, −4), B = (5, 0)
  2. Find the rise: the change in y. Rise is how far the line goes up (positive) or down (negative). Subtract the y-coordinates, second minus first.
    rise = y2 − y1 = 0 − (−4) = 4
  3. Find the run: the change in x. Run is how far across to the right. Subtract the x-coordinates in the same order as the y-coordinates.
    run = x2 − x1 = 5 − (−3) = 8
  4. Sketch the rise and run. The dashed triangle shows the run (across) and the rise (up or down) between the two points.
    xy−4−3−2−1123456−5−4−3−2−11Orun = 8rise = 4AB
  5. Divide the rise by the run and simplify. Gradient = rise ÷ run. Cancel the fraction if you can. A negative divided by a positive (or the reverse) is negative.
    gradient = rise ÷ run = 4 ÷ 8 = 12

Check. Swap the points: (−4 − 0) ÷ (−3 − 5) = −4 ÷ (−8) = 12, the same. The gradient is positive: the line goes up from left to right. ✓

Watch out. Subtract in the same order on the top and the bottom. Mixing the order (y2 − y1 over x1 − x2) gives the wrong sign.

Worked example 12.4.4
A road climbs 15 m over a horizontal distance of 200 m. Work out the gradient of the road, as a fraction in its simplest form and as a percentage.

Method. Gradient = rise ÷ run. Both must be in the same units, so convert the rise to metres first.

  1. Write the rise and the run in the same units. A fraction compares the vertical change with the horizontal change. Here both are in metres.
    rise = 15 m, run = 200 m
  2. Write the gradient as a fraction. Gradient = rise ÷ run.
    15 ÷ 200 = 15200
  3. Simplify the fraction. Divide the top and the bottom by their highest common factor, 5.
    15200 = 340
  4. Convert to a percentage if needed. A road gradient is often given as a percentage: multiply the decimal by 100.
    3 ÷ 40 = 0.075, so 0.075 × 100 = 7.5%

Check. Going 200 m along the flat, the road rises 7.5 m for every 100 m, which is 15 m in 200 m. ✓

Watch out. Rise and run must use the same units: do not divide metres by kilometres.

Watch out

Rise over run, never run over rise. The gradient is (up) ÷ (across). Also take care with signs: a line that goes down as you move right has a negative gradient. And always subtract in the same order on the top and the bottom of the fraction: y2 − y1 goes with x2 − x1.

Exercise 12E  Gradient

Non-calculator
1
FState whether the gradient of each line A, B, C and D is positive, negative, zero or undefined.
xy−5−4−3−2−112345−5−4−3−2−112345OABCD
(a)line A
(b)line B
(c)line C
(d)line D
2
FWork out the gradient of the line.
xy−4−3−2−11234−6−5−4−3−2−1123456O
3
FWork out the gradient of the line.
xy−3−2−1123456−4−3−2−1123456O
4
FWork out the gradient of the line.
xy−6−5−4−3−2−1123456−4−3−2−11234O
5
FWork out the gradient of the line.
xy−3−2−1123−7−6−5−4−3−2−112345678O
6
FWork out the gradient of the line.
xy−6−5−4−3−2−1123456−6−5−4−3−2−11234O
7
FWork out the gradient of the line through each pair of points.
(a)(1, 2) and (3, 8)
(b)(0, 5) and (4, 1)
(c)(−2, −1) and (2, 5)
(d)(−3, 4) and (1, −4)
8
FWork out the gradient of the line through each pair of points.
(a)(−3, 2) and (4, 2)
(b)(3, −1) and (3, 5)
9
PSA road rises 12 m over a horizontal distance of 150 m. Work out the gradient as a fraction in its simplest form and as a percentage.
10
PSA wheelchair ramp rises 0.4 m over a horizontal distance of 5 m. The rules say the gradient must be no more than 112. Does the ramp meet the rule? Show your working.
11
PSThe line through the points (2, k) and (6, 11) has gradient 2. Find the value of k.
12
RLine A goes through (0, 0) and (2, 5). Line B goes through (0, 0) and (3, 7). Which line is steeper? Show how you know.
13
RBen works out the gradient of the line through (1, 2) and (3, 8). He says it is 2/6 = 1/3. Find his mistake and give the correct gradient.
14
RShow that the points A(0, 1), B(2, 5) and C(5, 11) lie on a straight line.
15
PSThe line through (1, 3) and (k, 9) has gradient 32. Find the value of k.
16
RFour lines have gradients 3, −5, 12 and −1. Which line is the steepest? Explain.

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