Websink Prep UKGCSE MathsTextbook contentsMaths textbooksYear 1Year 2Year 4Year 5Year 6GCSEBrowse allPast papersFind a tutorBecome a tutor
GCSE Maths · EdexcelChapter 18 · Perimeter, area and circles
GCSE Maths · Perimeter, Area and Circles · Higher · Lesson 18.7

GCSE Maths: Area of a circle, semicircles and composite shapes (Higher)

Part of the GCSE Maths perimeter, area and circles chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

Download worksheet (PDF)Answers (PDF)
18.7

Area of a circle, semicircles and composite shapes

Edexcel 1MA1: G9, G17, G14
Grade 4-6

To see why the area of a circle is πr2, cut the circle into thin sectors, like slices of pizza, and lay them alternately point up and point down. The pieces fit together to make a shape that is almost a rectangle. The more slices you cut, the closer it is to a rectangle.

The circle cut into 8 sectors, re-arranged. With more sectors the shape becomes a rectangle.

The long side of this rectangle is half of the circumference, ½ × 2πr = πr. The short side is the radius r. So the area is πr × r:

Area of a circle A = πr2

Always use the radius. If you are given the diameter, halve it first. Then square the radius first (BIDMAS: powers before multiplying) and multiply by π. As before, you may be asked for an answer with a calculator (rounded) or in terms of π, such as 36π cm².

Semicircles and quarter circles

A semicircle is half a circle, so its area is ½πr2. A quarter circle has area ¼πr2.

Composite shapes

As in Section 18.4, split the shape into pieces whose area you know (rectangles, triangles, semicircles...) and add, or subtract a piece that has been cut out (a hole, a corner, a middle circle). Keep full calculator values until the very end and round once. If the question says “in terms of π”, keep π as a symbol and add numbers to numbers and π-terms to π-terms.

Working backwards from the area

If you know the area: divide by π to get r2, then take the square root to get r.

6 m8 m10 cm6 cm
Left: a rectangle with a semicircle on top (split and add). Right: a ring (big circle minus small circle).

Key ideas

  • Area of a circle A = πr2. Use the radius; halve a diameter first.
  • Square the radius first, then multiply by π.
  • Semicircle: ½πr2. Quarter circle: ¼πr2.
  • Composite shapes: split and add, or subtract a piece that is removed.
  • Do not round until the final answer. “In terms of π” means keep the π symbol.
  • From the area: divide by π, then square root, to find the radius.

Watch out

The most common mistakes are using the diameter instead of the radius, and multiplying π by the radius before squaring. For a circle of diameter 10 cm the area is π × 52 = 25π cm² = 78.5 cm², not π × 102.
Worked example 18.7.1
Work out the area of the circle, in terms of π.
6 cm

Key words. The area of a circle is the space inside it, in square units. The radius is the distance from the centre to the edge.

Method. The area of a circle is πr2. Make sure you use the radius, square it first, then multiply by π.

  1. Write down the radius. The radius is the distance from the centre to the edge.
    radius = 6 cm
  2. Choose the formula. The area of a circle is π times the radius squared. “Squared” means radius × radius.
    A = πr2
  3. Substitute and square the radius first. BIDMAS: powers come before multiplying. Square the radius, then multiply by π.
    A = π × 62
    62 = 6 × 6 = 36
    A = π × 36
  4. Write the answer in terms of π. Leave the π as a symbol and put the number in front.
    A = 36π cm²

Check. With π ≈ 3.14: 36 × 3.14 = 113.04 cm², a sensible size. ✓

Watch out. Square the radius first: πr2 is π × r × r. It is not (π × r) squared, and it is not 2 × r.

Worked example 18.7.2
Work out the area of the circle. Give your answer to 1 decimal place.
10 cm

Key words. The area of a circle is the space inside it, in square units. The radius is the distance from the centre to the edge.

Method. The area of a circle is πr2. Make sure you use the radius, square it first, then multiply by π.

  1. Find the radius. The formula for area needs the radius. The radius is half the diameter.
    radius = 10 ÷ 2 = 5 cm
  2. Choose the formula. The area of a circle is π times the radius squared. “Squared” means radius × radius.
    A = πr2
  3. Substitute and square the radius first. BIDMAS: powers come before multiplying. Square the radius, then multiply by π.
    A = π × 52
    52 = 5 × 5 = 25
    A = π × 25
  4. Use the π button on your calculator. Multiply the squared radius by π.
    A = 78.5398… cm²
  5. Round to 1 decimal place. Look at the next digit: 5 or more rounds up.
    A = 78.5 cm²

Check. Estimate: π is about 3, so A is about 3 × 25 = 75 cm², close to 78.5. ✓

Watch out. Square the radius first: πr2 is π × r × r. It is not (π × r) squared, and it is not 2 × r.

Worked example 18.7.3
Work out the area of the quarter circle, in terms of π.
8 cm8 cm

Method. A quarter circle is one quarter of a full circle, so its area is ¼ × πr2.

  1. Write down the radius. Both straight edges of a quarter circle are radii, so the radius is the length shown.
    radius = 8 cm
  2. Area of the quarter circle. A quarter of πr2. Square the radius first.
    ¼ × π × 82 = ¼ × π × 64 = 16π cm²
  3. Write the answer with its units. Leave π as a symbol; the units are square units for an area and plain units for a length.
    Area = 16π cm²

Check. Estimate with π ≈ 3: the answer should be about 48 cm², which is close to the value found. ✓

Watch out. Quarter means divide by 4 (not by 2).

Worked example 18.7.4
Work out the area of this window shape. Give your answer to 2 decimal places.
6 m8 m

Method. Split the shape into a rectangle and a semicircle, find each area and add.

  1. Find the radius of the semicircle. The semicircle sits across the top, so its diameter is the width of the rectangle. The radius is half of that.
    diameter = 6 m, radius = 6 ÷ 2 = 3 m
  2. Area of the rectangle. length × width.
    6 × 8 = 48 m²
  3. Area of the semicircle. Half of πr2, using the radius you found.
    ½ × π × 32 = ½ × π × 9 = 14.13717… m²
  4. Combine the pieces. Add (or subtract) the full calculator values. Do not round the pieces first, or the answer can be a little out.
    Area = 48 + 14.13717… = 62.13717… m²
  5. Round to 2 decimal places. Look at the next digit: 5 or more rounds up.
    Area = 62.14 m²

Check. Estimate with π ≈ 3: the answer should be about 61.5 m², which is close to the value found. ✓

Watch out. The semicircle’s diameter is the width of the rectangle: halve it to get the radius.

Worked example 18.7.5
Work out the area of the shaded ring. Give your answer in terms of π.
10 cm6 cm

Method. The shaded ring is the big circle with the small circle taken away: subtract the two areas.

  1. Area of the big circle. Use πR2 with the outer radius.
    π × 102 = π × 100 = 100π cm²
  2. Area of the small circle. Use the inner radius.
    π × 62 = π × 36 = 36π cm²
  3. Combine the pieces. Subtract the parts that are taken away. Whole numbers go with whole numbers and the π terms go with π terms. A number and a π term cannot be merged into one, so leave them as a sum.
    Area = 100π − 36π = 64π cm²

Check. Estimate with π ≈ 3: the answer should be about 192 cm², which is close to the value found. ✓

Watch out. Square each radius separately and then subtract. (R − r)2 is not the same as R2 − r2.

Worked example 18.7.6
The area of a circle is 100 cm². Work out the diameter, to 1 decimal place.
d = ?

Method. Use A = πr2 and rearrange: divide the area by π, then take the square root.

  1. Write the formula. Area = π × radius squared.
    A = πr2
  2. Substitute the area. Put the number in for A.
    100 = π × r2
  3. Divide both sides by π. To undo “multiply by π” divide by π.
    r2 = 100 ÷ π = 31.8310…
  4. Take the square root. The opposite of squaring is the square root (use the calculator).
    r = √31.8310… = 5.6419…
  5. Double the radius. The diameter is twice the radius.
    diameter = 2 × 5.6419… = 11.2838…
  6. Round to 1 decimal place. Round only at the end.
    diameter = 11.3 cm

Check. Check: π × 5.62 = 98.5, close to 100. ✓

Watch out. Divide by π first, then take the square root. Taking the square root first will give the wrong answer.

Worked example 18.7.7
The shaded area is a square of side 10 cm with a circle cut out. Find the shaded area in terms of π.
10 cm

Method. The shaded corners are the square with the circle taken away. The circle touches all four sides, so its diameter equals the side of the square.

  1. Find the radius of the circle. The circle touches opposite sides, so its diameter is the side of the square.
    radius = 10 ÷ 2 = 5 cm
  2. Area of the square. side × side.
    10 × 10 = 100 cm²
  3. Area of the circle. The diameter is 10 cm, so the radius is half of it.
    π × 52 = π × 25 = 25π cm²
  4. Combine the pieces. Subtract the parts that are taken away. Whole numbers go with whole numbers and the π terms go with π terms. A number and a π term cannot be merged into one, so leave them as a sum.
    Area = 100 − 25π = (100 − 25π) cm²

Check. Estimate with π ≈ 3: the answer should be about 25 cm², which is close to the value found. ✓

Watch out. Radius is half the side of the square, not the whole side.

Exercise 18G  Area of a circle, semicircles and composite shapes

Calculator allowed
1
FWork out the area of the circle. Give your answer to 1 decimal place.
5 cm
2
FWork out the area of the circle. Give your answer to 1 decimal place.
12 cm
3
FWork out the area of the circle with radius 9 cm. Give your answer (a) in terms of π and (b) to 1 decimal place.
9 cm
(a)in terms of π
(b)1 d.p.
4
FWork out the area of the circle. Give your answer to 3 significant figures.
3.7 cm
5
FWork out (a) the area and (b) the perimeter of the semicircle. Give your answers to 1 decimal place.
10 cm
(a)area
(b)perimeter
6
FThe shape is a quarter of a circle. Work out (a) its area and (b) its perimeter. Give both answers in terms of π.
8 cm8 cm
(a)area
(b)perimeter
7
FThe diagram shows a window made from a rectangle and a semicircle. Work out (a) the area and (b) the perimeter. Give your answers to 1 decimal place.
6 m8 m
(a)area
(b)perimeter
8
FThe diagram shows a ring. Work out the shaded area. Give your answer in terms of π.
10 cm6 cm
9
PSA running track is a rectangle with a semicircle at each end, as shown. Work out (a) the distance round the track and (b) the area inside the track. Give your answers in terms of π.
10 m6 m
(a)perimeter
(b)area
10
PSA metal plate is a rectangle 12 cm by 8 cm with a circular hole of radius 2 cm cut out. Work out the area of the plate. Give your answer to 1 decimal place.
2 cm12 cm8 cm
11
PSA circle just touches all four sides of a square of side 10 cm. Work out the shaded area. Give your answer to 1 decimal place.
10 cm
12
PSA quarter circle of radius 5 cm is cut from a 12 cm by 8 cm rectangle. Work out the shaded area to 3 significant figures.
8 cm12 cm5 cm
13
FThe area of a circle is 64π cm². Work out the radius.
r = ?
14
FThe area of a circle is 100 cm². Work out the diameter. Give your answer to 1 decimal place.
d = ?
15
PSA pizza shop sells a medium pizza (diameter 30 cm) for £8 and a large pizza (diameter 40 cm) for £12. Which is better value for money? Show your working.
30 cm40 cm
16
PSA circular lawn has radius 4 m. Turf costs £3.50 per square metre and must be bought in whole square metres. Work out the cost of the turf.
4 m
17
RKai says: “The area of a circle with diameter 10 cm is π × 102 = 314 cm².” Explain his mistake and work out the correct area to 1 decimal place.
10 cm
18
RShow that the area of a circle with radius 10 cm is 4 times the area of a circle with radius 5 cm.
5 cm10 cm
19
RA circle has the same value for its area (in cm²) as for its circumference (in cm). Work out its radius.
r = ?
20
PSThe radius of a circle is (x + 2) cm. Its area is 49π cm². Work out the value of x.
(x + 2) cm
21
RA ring has outer radius 3x cm and inner radius x cm. (a) Show that the area of the ring is 8πx2 cm². (b) The area is 72π cm². Work out x.
3xx
(a)(a) show that
(b)(b) find x

Websink Prep UK is an independent site. It is not affiliated with, endorsed by or sponsored by AQA, Pearson Edexcel, OCR, WJEC, Eduqas, CCEA, SQA, GL Assessment, CEM or the Department for Education. All exam board names and trademarks belong to their owners. Past papers are linked from the exam boards' own websites and are not hosted here.

About Websink Prep UK · Find a tutor · Privacy · Terms · Cookie settings