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GCSE Maths · EdexcelChapter 20 · Pythagoras and trigonometry
GCSE Maths · Pythagoras and Trigonometry · Higher · Lesson 20.5

GCSE Maths: Trigonometry: finding angles (Higher)

Part of the GCSE Maths pythagoras and trigonometry chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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20.5

Trigonometry: finding angles

Edexcel 1MA1: G20
Grade 4-6

In the last section we knew an angle and wanted a side. Now we know two sides and want the angle. The method is almost the same, but at the end we use the inverse function.

Think about sin 30° = 0.5. Sin takes an angle (30°) and gives a ratio (0.5). The inverse function goes the other way: it takes the ratio and gives the angle. It is written sin−1 and said “inverse sine” (or “arcsin”). So sin−1(0.5) = 30°. On a calculator you press SHIFT (or 2ndF) and then sin, cos or tan. This is not the same as 1 ÷ sin. The little −1 is just a name.

6.7 cm10 cmθ
We know O = 6.7 and H = 10, so use SOH: sin θ = 6.7 ÷ 10, then θ = sin−1(0.67).

The method for finding an angle.

  1. Label the two sides you know as O, A or H, measured from the angle you want.
  2. Choose the ratio (SOH, CAH or TOA) that uses those two sides.
  3. Write the ratio as a fraction with the numbers: for example tan θ = 5 ÷ 8.
  4. Use the inverse button on the calculator: θ = tan−1(5 ÷ 8).
  5. Round sensibly and write the degree sign.

Do not round the fraction before pressing the inverse button, because the rounding error in the ratio makes the angle less accurate. Use the fraction key, or put the division in brackets.

Two checks help. First, an angle in a right-angled triangle is less than 90°. Second, the biggest side is opposite the biggest angle, so if the opposite side is long the angle should be large. We also use this method when the triangle is hidden in another shape, for example an isosceles triangle cut in half, or a rectangle with its diagonal drawn in.

Key ideas

  • To find an angle, use the inverse function: sin−1, cos−1 or tan−1 (SHIFT then sin, cos or tan).
  • If sin θ = 0.5 then θ = sin−1(0.5) = 30°.
  • Choose the ratio from the two sides you know.
  • Do not round the ratio before using the inverse.
  • Check: the angle must be less than 90° and the biggest side is opposite the biggest angle.
Worked example 20.5.1
Work out the size of angle x. Give your answer correct to 1 decimal place.
6.7 cm10 cmx

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio as a fraction, then use the inverse function to turn the ratio into an angle.

  1. Label the sides. Stand at the angle we want. The hypotenuse is opposite the right angle. The opposite is across from the angle and the adjacent is next to it.
    6.7 cm is the opposite.
    10 cm is the hypotenuse.
  2. Choose the ratio. We know the opposite and the hypotenuse, so we use the ratio that contains both. Use SOH CAH TOA.
    SOH stands for Sin, Opposite, Hypotenuse:
    sin θ = OH   (O = opposite, H = hypotenuse)
  3. Put the numbers into the ratio. Write the sides as a fraction (top = opposite, bottom = hypotenuse).
    sin x = 6.710 = 0.67
  4. Use the inverse function sin−1. We know the value of sin x and want the angle. The inverse button (SHIFT or 2ndF, then sin) turns the ratio back into an angle.
    x = sin−1(6.710) = sin−1(0.67) = 42.06706…°
  5. Round to 1 d.p. Give the angle to the accuracy asked, with the degree sign.
    x = 42.1°

Check. Work forwards: sin 42.1° = 0.670 and the ratio was 0.670. They agree. ✓

Watch out. To find an angle use the inverse button (sin−1), not sin. Do not round the ratio before pressing the inverse button.

Worked example 20.5.2
Work out the size of angle x. Give your answer correct to 1 decimal place.
8 cm5 cmx

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio as a fraction, then use the inverse function to turn the ratio into an angle.

  1. Label the sides. Stand at the angle we want. The hypotenuse is opposite the right angle. The opposite is across from the angle and the adjacent is next to it.
    5 cm is the opposite.
    8 cm is the adjacent.
  2. Choose the ratio. We know the opposite and the adjacent, so we use the ratio that contains both. Use SOH CAH TOA.
    TOA stands for Tan, Opposite, Adjacent:
    tan θ = OA   (O = opposite, A = adjacent)
  3. Put the numbers into the ratio. Write the sides as a fraction (top = opposite, bottom = adjacent).
    tan x = 58 = 0.625
  4. Use the inverse function tan−1. We know the value of tan x and want the angle. The inverse button (SHIFT or 2ndF, then tan) turns the ratio back into an angle.
    x = tan−1(58) = tan−1(0.625) = 32.00538…°
  5. Round to 1 d.p. Give the angle to the accuracy asked, with the degree sign.
    x = 32.0°

Check. Work forwards: tan 32.0° = 0.625 and the ratio was 0.625. They agree. ✓

Watch out. To find an angle use the inverse button (tan−1), not tan. Do not round the ratio before pressing the inverse button.

Worked example 20.5.3
Work out the size of angle x. Give your answer correct to 1 decimal place.
4.5 m9 mx

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio as a fraction, then use the inverse function to turn the ratio into an angle.

  1. Label the sides. Stand at the angle we want. The hypotenuse is opposite the right angle. The opposite is across from the angle and the adjacent is next to it.
    4.5 m is the adjacent.
    9 m is the hypotenuse.
  2. Choose the ratio. We know the adjacent and the hypotenuse, so we use the ratio that contains both. Use SOH CAH TOA.
    CAH stands for Cos, Adjacent, Hypotenuse:
    cos θ = AH   (A = adjacent, H = hypotenuse)
  3. Put the numbers into the ratio. Write the sides as a fraction (top = adjacent, bottom = hypotenuse).
    cos x = 4.59 = 0.5
  4. Use the inverse function cos−1. We know the value of cos x and want the angle. The inverse button (SHIFT or 2ndF, then cos) turns the ratio back into an angle.
    x = cos−1(4.59) = cos−1(0.5) = 60°
  5. Round to 1 d.p. Give the angle to the accuracy asked, with the degree sign.
    x = 60.0°

Check. Work forwards: cos 60.0° = 0.500 and the ratio was 0.500. They agree. ✓

Watch out. To find an angle use the inverse button (cos−1), not cos. Do not round the ratio before pressing the inverse button.

Worked example 20.5.4
An isosceles triangle has two sides of length 10 cm and a base of 12 cm. Work out the size of the base angle x, correct to 1 decimal place.
10 cm10 cm12 cmx

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio as a fraction, then use the inverse function to turn the ratio into an angle.

  1. Draw the line of symmetry. In an isosceles triangle the line of symmetry cuts the base in half at 90° and makes two right-angled triangles. We use one of them.
    Half the base = 12 ÷ 2 = 6 cm. The slanting side is 10 cm (hypotenuse).
  2. Label the sides. Stand at the angle we want. The hypotenuse is opposite the right angle. The opposite is across from the angle and the adjacent is next to it.
    6 cm is the adjacent.
    10 cm is the hypotenuse.
  3. Choose the ratio. We know the adjacent and the hypotenuse, so we use the ratio that contains both. Use SOH CAH TOA.
    CAH stands for Cos, Adjacent, Hypotenuse:
    cos θ = AH   (A = adjacent, H = hypotenuse)
  4. Put the numbers into the ratio. Write the sides as a fraction (top = adjacent, bottom = hypotenuse).
    cos x = 610 = 0.6
  5. Use the inverse function cos−1. We know the value of cos x and want the angle. The inverse button (SHIFT or 2ndF, then cos) turns the ratio back into an angle.
    x = cos−1(610) = cos−1(0.6) = 53.13010…°
  6. Round to 1 d.p. Give the angle to the accuracy asked, with the degree sign.
    x = 53.1°

Check. Work forwards: cos 53.1° = 0.600 and the ratio was 0.600. They agree. ✓

Watch out. To find an angle use the inverse button (cos−1), not cos. Do not round the ratio before pressing the inverse button.

Watch out

Use the inverse button, not the normal one. If you type sin(0.67) you get 0.0117…, not the angle. Also remember to put the degree sign in the answer. And if your calculator gives an error for sin−1 or cos−1, check that the number you typed is not bigger than 1: the hypotenuse must be on the bottom.

Exercise 20G  Finding angles with the inverse functions

Calculator allowed
1
FUse the inverse function on your calculator to find x. Give each answer correct to 1 decimal place.
(a)sin x = 0.6
x
(b)cos x = 0.25
x
(c)tan x = 1.2
x
(d)sin x = 37
x
2
FWork out the size of angle x in each triangle. Give your answers correct to 1 decimal place. All lengths are in centimetres.
(a)
4 cm9 cmx
(b)
7.5 cm12 cmx
(c)
3.2 cm5 cmx
(d)
16 cm21 cmx
3
FWork out the size of angle x in each triangle. Give your answers correct to 1 decimal place. All lengths are in centimetres.
(a)
6 cm10 cmx
(b)
3.8 cm8 cmx
(c)
12 cm15 cmx
(d)
5.5 cm7.2 cmx
4
FWork out the size of angle x in each triangle. Give your answers correct to 1 decimal place. All lengths are in centimetres.
(a)
8 cm5 cmx
(b)
4 cm9 cmx
(c)
7.5 cm7.5 cmx
(d)
11 cm2.4 cmx
5
PSA ramp is 5 m long and rises 0.8 m. Work out the angle the ramp makes with the horizontal, correct to 1 decimal place.
0.8 m5 mx
6
PSA ladder 6 m long stands on level ground with its foot 1.6 m from a vertical wall. Work out the angle between the ladder and the ground, correct to 1 decimal place.
1.6 m6 mx
7
PSThe diagram shows a rectangle 12 cm long and 5 cm wide with a diagonal drawn in. Work out the angle x between the diagonal and the longer side, correct to 1 decimal place.
12 cm5 cm
8
PSA road has a gradient of 1 in 8. This means it rises 1 m for every 8 m measured horizontally. Work out the angle the road makes with the horizontal, correct to 1 decimal place.
8 m1 mx
9
PSThe line OP joins the origin O to the point P(8, 5). Work out the angle that OP makes with the x-axis, correct to 1 decimal place.
xy-112345678910-11234567P(8, 5)x
10
RAli writes sin x = 1.3 for a right-angled triangle. Explain why this cannot be right.
OHx
11
RA right-angled triangle has a hypotenuse of 12 cm and a shorter side of 6 cm. Show that the angle opposite the 6 cm side is 30°.
6 cm12 cmx
12
RChallenge. Triangle ABC has a right angle at C, AC = 12 cm and BC = 5 cm. Work out the size of angle A and angle B, correct to 1 decimal place, and show that your three angles add up to 180°.
CAB12 cm5 cmAB

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