GCSE Maths Standard Form, Indices and Surds (Foundation): worked examples and questions with answers
By the end of this chapter you will be able to
- Use index notation and the laws of indices to multiply, divide and raise powers to powers, with numbers and with letters
- Work with zero and negative indices
- Calculate with roots and (Higher) with fractional indices
- Write very large and very small numbers in standard form and change them back
- Compare, order and calculate with numbers in standard form, with and without a calculator
- Give exact answers in terms of π
- (Higher) Simplify, add, multiply and expand with surds, and rationalise denominators
You should already know
- Multiplying and dividing whole numbers and decimals (Chapter 1)
- Square numbers, cube numbers and roots (Chapter 2)
- Fractions and reciprocals (Chapter 3)
- Rounding to significant figures (Chapter 4)
- Using letters in algebra
Where this leads
- Expanding brackets and factorising (Chapter 7)
- Area and circumference of circles (Chapter 18)
- Pythagoras and exact trigonometry (Chapter 20)
- Growth and decay (Chapters 5 and 25)
Edexcel GCSE (9–1) Mathematics 1MA1, Foundation tier. Content references: N7, N8, N9, A4.
- 6.1 Index notation and the laws of indices: Worksheet (PDF) · Answers (PDF) · lesson page
- 6.2 Zero and negative indices: Worksheet (PDF) · Answers (PDF) · lesson page
- 6.3 Roots and fractional indices: Worksheet (PDF) · Answers (PDF) · lesson page
- 6.4 Standard form: large and small numbers: Worksheet (PDF) · Answers (PDF) · lesson page
- 6.5 Comparing and calculating with standard form: Worksheet (PDF) · Answers (PDF) · lesson page
- 6.6 Exact answers with π: Worksheet (PDF) · Answers (PDF) · lesson page
- Check-up and exam-style questions: Worksheet (PDF) · Answers (PDF) · lesson page
Exercise P Do you remember?
Non-calculatorKey words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 4 tells us to multiply 4 lots of 2 together.24 = 2 × 2 × 2 × 2
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.2 × 2 = 4
4 × 2 = 8
8 × 2 = 16
Check. Split the power: 22 × 22 = 4 × 4 = 16. ✓
Watch out. 24 does not mean 2 × 4. The index says how many lots of 2 are multiplied.
Method. Multiplying by 1000 moves every digit 3 places to the left (the decimal point moves 3 places right).
- Move the decimal point 3 places right. Each × 10 moves it one place; fill the gap with zeros.3.7 → 37 → 370 → 3700
- Write the answer. 3700
Check. 3700 ÷ 1000 = 3.7. ✓
Watch out. Multiplying makes the number bigger.
Method. Dividing by 100 moves the decimal point 2 places to the left.
- Move the decimal point 2 places left. Fill the gap with a zero.6.4 → 0.64 → 0.064
- Write the answer. 0.064
Check. 0.064 × 100 = 6.4. ✓
Watch out. Dividing makes the number smaller.
Method. Find the number that multiplies by itself (2 or 3 times) to give the original.
- Square root of 81. 9 × 9 = 81.√81 = 9
- Cube root of 27. 3 × 3 × 3 = 27.3√27 = 3
- Write both answers. 9 and 3
Check. 92 = 81 and 33 = 27. ✓
Watch out. The square root of 81 is not 40.5.
Method. Significant figures are counted from the first non-zero digit.
- Find the first non-zero digit. The zeros at the start do not count.0.043756: the first significant figure is 4.
- Keep 3 figures. The 3 significant figures are 4, 3 and 7.0.0437|56
- Look at the next digit. The next digit is 5, so round the 7 up to 8.0.0438
Check. 0.0438 is closer to 0.043756 than 0.0437. ✓
Watch out. Leading zeros are not significant.
Index notation and the laws of indices
Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page
Fold a sheet of paper in half and it has 2 layers. Fold it again and there are 4 layers. Fold again: 8. Every fold doubles the number of layers, so after 3 folds there are 2 × 2 × 2 layers. Mathematicians write this in a short way: 23, said “2 to the power 3”. This is called index notation.
The big number is the base. The small raised number is the index (plural: indices; it is also called the power or exponent). The index tells you how many lots of the base are multiplied together. You already know two special cases: “squared” means index 2 and “cubed” means index 3. Be careful: 23 is 2 × 2 × 2 = 8. It is not 2 × 3 = 6.
The index counts lots, and counting lots is easy. That is why there are three simple laws of indices. Each one comes straight from writing the powers out in full.
Law 1 (multiplying). When you multiply powers of the same base, add the indices. 34 × 32 = 34+2 = 36.
Law 2 (dividing). When you divide powers of the same base, subtract the indices. 35 ÷ 32 = (3 × 3 × 3 × 3 × 3) ÷ (3 × 3). Two of the 3s cancel on the top and bottom, leaving three of them: 35−2 = 33.
Law 3 (power of a power). (32)3 means three lots of 32, that is 32 × 32 × 32 = 32+2+2 = 36. Three lots of 2 is 3 × 2, so we multiply the indices.
These laws only work when the bases are the same. They also work with letters, because a letter stands for a number. For example x2 × x5 = x7. When there are numbers in front of the letters (the coefficients), deal with the numbers and the letters separately: 3x2 × 4x5 = (3 × 4) × x2+5 = 12x7. A letter on its own has index 1, so x = x1.
Key ideas
- am × an = am+n (add the indices)
- am ÷ an = am−n (subtract the indices)
- (am)n = am×n (multiply the indices)
- The bases must be the same for the first two laws.
- With coefficients: multiply or divide the numbers, then use the laws on each letter. (2a)3 = 23a3 = 8a3.
- a1 = a.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Count how many 2s are multiplied to get the index, then multiply them out.
- Count the 2s. The index of a power is the number of equal numbers being multiplied.There are 5 lots of 2, so the index is 5.
- Write it as a power. Base 2, index 5.2 × 2 × 2 × 2 × 2 = 25
- Multiply step by step. Do one multiplication at a time.2 × 2 = 4
4 × 2 = 8
8 × 2 = 16
16 × 2 = 32 - Write the answer. 25 = 32
Check. 25 = 22 × 23 = 4 × 8 = 32. ✓
Watch out. 25 is not 2 × 5 = 10. The index counts lots of 2 multiplied together.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 3.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.34 = 3 × 3 × 3 × 3
32 = 3 × 3
Together: 4 lots of 3 and 2 lots of 3 make 6 lots of 3. - Add the indices. Joining the lots means adding the number of lots.4 + 2 = 6
- Write the answer as a single power. Keep the same base and use the new index.34 × 32 = 36
Check. Work out the numbers: 34 = 81 and 32 = 9. 81 × 9 = 729, and 36 = 729. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 5.
- Work out the top first: multiply, so add the indices. am × an = am+n.7 + 2 = 9, so the top is 59
- Divide: subtract the indices. am ÷ an = am−n.5956 = 59 ÷ 56 = 53, because 9 − 6 = 3
Check. The total of the indices on top is 9 and on the bottom is 6; 9 − 6 = 3. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Write the bracket out as repeated multiplication. The outer index 4 means 4 lots of 23 multiplied together.(23)4 = 23 × 23 × 23 × 23
= 23 + 3 + 3 + 3
That is 4 lots of 3, which is 4 × 3 = 12. - Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.3 × 4 = 12
- Write the answer as a single power. Keep the same base and use the new index.(23)4 = 212
- Work out the value. 212 means 12 lots of 2 multiplied together.212 = 2 × 2 × … × 2 (12 lots of 2) = 4096
Check. Work out the numbers: 23 = 8, and 84 = 4096. Also 212 = 4096. ✓
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.3 × 4 = 12
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x2 × x5 = x2 + 5 = x7
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.12x7
Check. Choose numbers: x = 2. The original expression has the value 1536, and the answer 12x7 also has the value 1536. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.(2)4 = 2 × 2 × 2 × 2 = 16
- Raise the letter a to the power: multiply the indices. (am)n = am×n.(a3)4 = a3 × 4 = a12
- Put it all together. 16a12
Check. Choose numbers: a = 2. The original expression has the value 65,536, and the answer 16a12 also has the value 65,536. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Watch out
Do not multiply the bases and do not multiply the indices when you are multiplying powers. 32 × 34 is not 96. The base stays 3 and the indices add: 36. And you cannot combine powers of different letters or different numbers: x3 + x2 does not equal x5, and 23 × 32 is not 65.Exam tip
In an exam, show the indices adding: write 34+2 = 36. If the question says “work out the value” you must also give the final number.Exercise 6A Powers and the laws of indices with numbers
Non-calculatorKey words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Count how many times each number is multiplied; that count is the index.
- Count how many times each number appears. The index of a power counts the number of equal factors in the multiplication.5 appears 4 times
- Write each number with its count as the index. A number that appears c times is written as (number)c.5 appears 4 times: 54
- Write the answer. 54
Check. Expand it again: 54 = 5 × 5 × 5 × 5; the same list of factors. ✓
Watch out. The index is the number of lots, not the answer. 5 × 5 × 5 is 53 (=125), not 5 × 3 (=15).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Count how many times each number is multiplied; that count is the index.
- Count how many times each number appears. The index of a power counts the number of equal factors in the multiplication.2 appears 6 times
- Write each number with its count as the index. A number that appears c times is written as (number)c.2 appears 6 times: 26
- Write the answer. 26
Check. Expand it again: 26 = 2 × 2 × 2 × 2 × 2 × 2; the same list of factors. ✓
Watch out. The index is the number of lots, not the answer. 5 × 5 × 5 is 53 (=125), not 5 × 3 (=15).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Count how many times each number is multiplied; that count is the index.
- Count how many times each number appears. The index of a power counts the number of equal factors in the multiplication.10 appears 3 times
- Write each number with its count as the index. A number that appears c times is written as (number)c.10 appears 3 times: 103
- Write the answer. 103
Check. Expand it again: 103 = 10 × 10 × 10; the same list of factors. ✓
Watch out. The index is the number of lots, not the answer. 5 × 5 × 5 is 53 (=125), not 5 × 3 (=15).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Count how many times each number is multiplied; that count is the index.
- Count how many times each number appears. The index of a power counts the number of equal factors in the multiplication.7 appears 2 times
- Write each number with its count as the index. A number that appears c times is written as (number)c.7 appears 2 times: 72
- Write the answer. 72
Check. Expand it again: 72 = 7 × 7; the same list of factors. ✓
Watch out. The index is the number of lots, not the answer. 5 × 5 × 5 is 53 (=125), not 5 × 3 (=15).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 5 tells us to multiply 5 lots of 2 together.25 = 2 × 2 × 2 × 2 × 2
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.2 × 2 = 4
4 × 2 = 8
8 × 2 = 16
16 × 2 = 32
Check. Split the power: 22 × 23 = 4 × 8 = 32. ✓
Watch out. 25 does not mean 2 × 5. The index says how many lots of 2 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 4 tells us to multiply 4 lots of 3 together.34 = 3 × 3 × 3 × 3
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.3 × 3 = 9
9 × 3 = 27
27 × 3 = 81
Check. Split the power: 32 × 32 = 9 × 9 = 81. ✓
Watch out. 34 does not mean 3 × 4. The index says how many lots of 3 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 3 tells us to multiply 3 lots of 10 together.103 = 10 × 10 × 10
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.10 × 10 = 100
100 × 10 = 1000
Check. Split the power: 101 × 102 = 10 × 100 = 1000. ✓
Watch out. 103 does not mean 10 × 3. The index says how many lots of 10 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 3 tells us to multiply 3 lots of 5 together.53 = 5 × 5 × 5
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.5 × 5 = 25
25 × 5 = 125
Check. Split the power: 51 × 52 = 5 × 25 = 125. ✓
Watch out. 53 does not mean 5 × 3. The index says how many lots of 5 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 3 tells us to multiply 3 lots of 4 together.43 = 4 × 4 × 4
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.4 × 4 = 16
16 × 4 = 64
Check. Split the power: 41 × 42 = 4 × 16 = 64. ✓
Watch out. 43 does not mean 4 × 3. The index says how many lots of 4 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 2 tells us to multiply 2 lots of 6 together.62 = 6 × 6
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.6 × 6 = 36
Watch out. 62 does not mean 6 × 2. The index says how many lots of 6 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 1 tells us to multiply 1 lots of 2 together.21 = 2
- Write the answer. An index of 1 means just one lot of the base, so the number does not change.21 = 2
Watch out. 21 does not mean 2 × 1. The index says how many lots of 2 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 2 tells us to multiply 2 lots of 2 together.22 = 2 × 2
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.2 × 2 = 4
Watch out. The index says how many lots are multiplied; it is not the same as multiplying the base by the index.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 3 tells us to multiply 3 lots of 2 together.23 = 2 × 2 × 2
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.2 × 2 = 4
4 × 2 = 8
Check. Split the power: 21 × 22 = 2 × 4 = 8. ✓
Watch out. 23 does not mean 2 × 3. The index says how many lots of 2 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 4 tells us to multiply 4 lots of 2 together.24 = 2 × 2 × 2 × 2
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.2 × 2 = 4
4 × 2 = 8
8 × 2 = 16
Check. Split the power: 22 × 22 = 4 × 4 = 16. ✓
Watch out. 24 does not mean 2 × 4. The index says how many lots of 2 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 5 tells us to multiply 5 lots of 2 together.25 = 2 × 2 × 2 × 2 × 2
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.2 × 2 = 4
4 × 2 = 8
8 × 2 = 16
16 × 2 = 32
Check. Split the power: 22 × 23 = 4 × 8 = 32. ✓
Watch out. 25 does not mean 2 × 5. The index says how many lots of 2 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 2.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.23 = 2 × 2 × 2
24 = 2 × 2 × 2 × 2
Together: 3 lots of 2 and 4 lots of 2 make 7 lots of 2. - Add the indices. Joining the lots means adding the number of lots.3 + 4 = 7
- Write the answer as a single power. Keep the same base and use the new index.23 × 24 = 27
Check. Work out the numbers: 23 = 8 and 24 = 16. 8 × 16 = 128, and 27 = 128. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 5.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.52 = 5 × 5
56 = 5 × 5 × 5 × 5 × 5 × 5
Together: 2 lots of 5 and 6 lots of 5 make 8 lots of 5. - Add the indices. Joining the lots means adding the number of lots.2 + 6 = 8
- Write the answer as a single power. Keep the same base and use the new index.52 × 56 = 58
Check. Work out the numbers: 52 = 25 and 56 = 15,625. 25 × 15,625 = 390,625, and 58 = 390,625. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 7.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.75 = 7 × 7 × 7 × 7 × 7
71 = 7
Together: 5 lots of 7 and 1 lots of 7 make 6 lots of 7. - Add the indices. Joining the lots means adding the number of lots.5 + 1 = 6
- Write the answer as a single power. Keep the same base and use the new index.75 × 71 = 76
Check. Work out the numbers: 75 = 16,807 and 71 = 7. 16,807 × 7 = 117,649, and 76 = 117,649. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 10.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.103 = 10 × 10 × 10
103 = 10 × 10 × 10
Together: 3 lots of 10 and 3 lots of 10 make 6 lots of 10. - Add the indices. Joining the lots means adding the number of lots.3 + 3 = 6
- Write the answer as a single power. Keep the same base and use the new index.103 × 103 = 106
Check. Work out the numbers: 103 = 1000 and 103 = 1000. 1000 × 1000 = 1,000,000, and 106 = 1,000,000. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 6.
- Say what the rule means. Dividing cancels lots of the base from the top: every lot on the bottom removes one lot from the top.68 has 8 lots of 6; we take away 3 lots.
- Subtract the indices. The number of lots left is the first index take away the second.8 − 3 = 5
- Write the answer as a single power. Keep the same base and use the new index.68 ÷ 63 = 65
Check. Work out the numbers: 68 = 1,679,616 and 63 = 216. 1,679,616 ÷ 216 = 7776, and 65 = 7776. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 4.
- Say what the rule means. Dividing cancels lots of the base from the top: every lot on the bottom removes one lot from the top.49 has 9 lots of 4; we take away 5 lots.
- Subtract the indices. The number of lots left is the first index take away the second.9 − 5 = 4
- Write the answer as a single power. Keep the same base and use the new index.49 ÷ 45 = 44
Check. Work out the numbers: 49 = 262,144 and 45 = 1024. 262,144 ÷ 1024 = 256, and 44 = 256. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 3.
- Write both powers out in full as a fraction. Dividing is the same as writing a fraction, and then we can cancel (divide top and bottom by the same thing).
3×3× 3 × 3 × 3 × 3 × 33×3
Each 3 on the bottom cancels with one 3 on the top (3 ÷ 3 = 1).
2 of the 7 are cancelled, leaving 5 lots of 3. - Subtract the indices. The number of lots left is the first index take away the second.7 − 2 = 5
- Write the answer as a single power. Keep the same base and use the new index.37 ÷ 32 = 35
Check. Work out the numbers: 37 = 2187 and 32 = 9. 2187 ÷ 9 = 243, and 35 = 243. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 10.
- Write both powers out in full as a fraction. Dividing is the same as writing a fraction, and then we can cancel (divide top and bottom by the same thing).
10×10×10×10× 10 × 1010×10×10×10
Each 10 on the bottom cancels with one 10 on the top (10 ÷ 10 = 1).
4 of the 6 are cancelled, leaving 2 lots of 10. - Subtract the indices. The number of lots left is the first index take away the second.6 − 4 = 2
- Write the answer as a single power. Keep the same base and use the new index.106 ÷ 104 = 102
Check. Work out the numbers: 106 = 1,000,000 and 104 = 10,000. 1,000,000 ÷ 10,000 = 100, and 102 = 100. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Write the bracket out as repeated multiplication. The outer index 4 means 4 lots of 32 multiplied together.(32)4 = 32 × 32 × 32 × 32
= 32 + 2 + 2 + 2
That is 4 lots of 2, which is 4 × 2 = 8. - Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.2 × 4 = 8
- Write the answer as a single power. Keep the same base and use the new index.(32)4 = 38
Check. Work out the numbers: 32 = 9, and 94 = 6561. Also 38 = 6561. ✓
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Write the bracket out as repeated multiplication. The outer index 2 means 2 lots of 53 multiplied together.(53)2 = 53 × 53
= 53 + 3
That is 2 lots of 3, which is 2 × 3 = 6. - Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.3 × 2 = 6
- Write the answer as a single power. Keep the same base and use the new index.(53)2 = 56
Check. Work out the numbers: 53 = 125, and 1252 = 15,625. Also 56 = 15,625. ✓
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Write the bracket out as repeated multiplication. The outer index 3 means 3 lots of 25 multiplied together.(25)3 = 25 × 25 × 25
= 25 + 5 + 5
That is 3 lots of 5, which is 3 × 5 = 15. - Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.5 × 3 = 15
- Write the answer as a single power. Keep the same base and use the new index.(25)3 = 215
Check. Work out the numbers: 25 = 32, and 323 = 32,768. Also 215 = 32,768. ✓
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Write the bracket out as repeated multiplication. The outer index 3 means 3 lots of 102 multiplied together.(102)3 = 102 × 102 × 102
= 102 + 2 + 2
That is 3 lots of 2, which is 3 × 2 = 6. - Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.2 × 3 = 6
- Write the answer as a single power. Keep the same base and use the new index.(102)3 = 106
Check. Work out the numbers: 102 = 100, and 1003 = 1,000,000. Also 106 = 1,000,000. ✓
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 2.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.23 = 2 × 2 × 2
22 = 2 × 2
Together: 3 lots of 2 and 2 lots of 2 make 5 lots of 2. - Add the indices. Joining the lots means adding the number of lots.3 + 2 = 5
- Write the answer as a single power. Keep the same base and use the new index.23 × 22 = 25
- Work out the value. 25 means 5 lots of 2 multiplied together.25 = 2 × 2 × 2 × 2 × 2 = 32
Check. Work out the numbers: 23 = 8 and 22 = 4. 8 × 4 = 32, and 25 = 32. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 3.
- Write both powers out in full as a fraction. Dividing is the same as writing a fraction, and then we can cancel (divide top and bottom by the same thing).
3×3×3× 3 × 33×3×3
Each 3 on the bottom cancels with one 3 on the top (3 ÷ 3 = 1).
3 of the 5 are cancelled, leaving 2 lots of 3. - Subtract the indices. The number of lots left is the first index take away the second.5 − 3 = 2
- Write the answer as a single power. Keep the same base and use the new index.35 ÷ 33 = 32
- Work out the value. 32 means 2 lots of 3 multiplied together.32 = 3 × 3 = 9
Check. Work out the numbers: 35 = 243 and 33 = 27. 243 ÷ 27 = 9, and 32 = 9. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Write the bracket out as repeated multiplication. The outer index 3 means 3 lots of 22 multiplied together.(22)3 = 22 × 22 × 22
= 22 + 2 + 2
That is 3 lots of 2, which is 3 × 2 = 6. - Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.2 × 3 = 6
- Write the answer as a single power. Keep the same base and use the new index.(22)3 = 26
- Work out the value. 26 means 6 lots of 2 multiplied together.26 = 2 × 2 × 2 × 2 × 2 × 2 = 64
Check. Work out the numbers: 22 = 4, and 43 = 64. Also 26 = 64. ✓
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 10.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.102 = 10 × 10
103 = 10 × 10 × 10
Together: 2 lots of 10 and 3 lots of 10 make 5 lots of 10. - Add the indices. Joining the lots means adding the number of lots.2 + 3 = 5
- Write the answer as a single power. Keep the same base and use the new index.102 × 103 = 105
- Work out the value. 105 means 5 lots of 10 multiplied together.105 = 10 × 10 × 10 × 10 × 10 = 100,000
Check. Work out the numbers: 102 = 100 and 103 = 1000. 100 × 1000 = 100,000, and 105 = 100,000. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 5.
- Write both powers out in full as a fraction. Dividing is the same as writing a fraction, and then we can cancel (divide top and bottom by the same thing).
5×5× 5 × 55×5
Each 5 on the bottom cancels with one 5 on the top (5 ÷ 5 = 1).
2 of the 4 are cancelled, leaving 2 lots of 5. - Subtract the indices. The number of lots left is the first index take away the second.4 − 2 = 2
- Write the answer as a single power. Keep the same base and use the new index.54 ÷ 52 = 52
- Work out the value. 52 means 2 lots of 5 multiplied together.52 = 5 × 5 = 25
Check. Work out the numbers: 54 = 625 and 52 = 25. 625 ÷ 25 = 25, and 52 = 25. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out each power first, then multiply the results.
- Work out each power separately. A power means repeated multiplication of the base.23 = 2 × 2 × 2 = 8
52 = 5 × 5 = 25 - Multiply the values together. The original question was a product of the powers.8 × 25 = 200
Check. Multiplying in a different order gives the same result: 25 × 8 = 200. ✓
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out each power first, then multiply the results.
- Work out each power separately. A power means repeated multiplication of the base.22 = 2 × 2 = 4
33 = 3 × 3 × 3 = 27 - Multiply the values together. The original question was a product of the powers.4 × 27 = 108
Check. Multiplying in a different order gives the same result: 27 × 4 = 108. ✓
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out each power first, then multiply the results.
- Work out each power separately. A power means repeated multiplication of the base.103 = 10 × 10 × 10 = 1000
42 = 4 × 4 = 16 - Multiply the values together. The original question was a product of the powers.1000 × 16 = 16,000
Check. Multiplying in a different order gives the same result: 16 × 1000 = 16,000. ✓
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out each power first, then multiply the results.
- Work out each power separately. A power means repeated multiplication of the base.32 = 3 × 3 = 9
24 = 2 × 2 × 2 × 2 = 16 - Multiply the values together. The original question was a product of the powers.9 × 16 = 144
Check. Multiplying in a different order gives the same result: 16 × 9 = 144. ✓
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the law of indices to write an equation for the missing index.
- Check that the bases match. The laws of indices need the same base on both sides.The base is 3 throughout.
- Write an equation for the indices. Multiplying powers adds the indices.4 + ? = 9
- Solve it for the missing index. Use the inverse operation.? = 9 − 4 = 5
? = 5
Check. 34 × 35 = 34 + 5 = 39. ✓
Watch out. Check by putting your answer back into the question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the law of indices to write an equation for the missing index.
- Check that the bases match. The laws of indices need the same base on both sides.The base is 7 throughout.
- Write an equation for the indices. Multiplying powers adds the indices.? + 2 = 5
- Solve it for the missing index. Use the inverse operation.? = 5 − 2 = 3
? = 3
Check. 73 × 72 = 73 + 2 = 75. ✓
Watch out. Check by putting your answer back into the question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the law of indices to write an equation for the missing index.
- Check that the bases match. The laws of indices need the same base on both sides.The base is 5 throughout.
- Write an equation for the indices. Dividing powers subtracts the indices.8 − ? = 3
- Solve it for the missing index. Use the inverse operation.? = 8 − 3 = 5
? = 5
Check. 58 ÷ 55 = 58 − 5 = 53. ✓
Watch out. Check by putting your answer back into the question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the law of indices to write an equation for the missing index.
- Check that the bases match. The laws of indices need the same base on both sides.The base is 2 throughout.
- Write an equation for the indices. Dividing powers subtracts the indices.? − 3 = 4
- Solve it for the missing index. Use the inverse operation.? = 4 + 3 = 7
? = 7
Check. 27 ÷ 23 = 27 − 3 = 24. ✓
Watch out. Check by putting your answer back into the question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the law of indices to write an equation for the missing index.
- Check that the bases match. The laws of indices need the same base on both sides.The base is 4 throughout.
- Write an equation for the indices. A power of a power multiplies the indices.? × 3 = 12
- Solve it for the missing index. Use the inverse operation.? = 12 ÷ 3 = 4
? = 4
Check. (44)3 = 44 × 3 = 412. ✓
Watch out. Check by putting your answer back into the question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 5.
- Work out the top first: multiply, so add the indices. am × an = am+n.7 + 2 = 9, so the top is 59
- Divide: subtract the indices. am ÷ an = am−n.5956 = 59 ÷ 56 = 53, because 9 − 6 = 3
Check. The total of the indices on top is 9 and on the bottom is 6; 9 − 6 = 3. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 2.
- Work out the top first: multiply, so add the indices. am × an = am+n.3 + 5 = 8, so the top is 28
- Divide: subtract the indices. am ÷ an = am−n.2824 = 28 ÷ 24 = 24, because 8 − 4 = 4
Check. The total of the indices on top is 8 and on the bottom is 4; 8 − 4 = 4. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 3.
- Work out the top first: multiply, so add the indices. am × an = am+n.9 = 9, so the top is 39
- Work out the bottom: add the indices. The bottom is also a multiplication of the same base.2 + 3 = 5, so the bottom is 35
- Divide: subtract the indices. am ÷ an = am−n.3935 = 39 ÷ 35 = 34, because 9 − 5 = 4
Check. The total of the indices on top is 9 and on the bottom is 5; 9 − 5 = 4. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 7.
- Work out the top first: multiply, so add the indices. am × an = am+n.4 + 3 = 7, so the top is 77
- Work out the bottom: add the indices. The bottom is also a multiplication of the same base.2 + 1 = 3, so the bottom is 73
- Divide: subtract the indices. am ÷ an = am−n.7773 = 77 ÷ 73 = 74, because 7 − 3 = 4
Check. The total of the indices on top is 7 and on the bottom is 3; 7 − 3 = 4. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out both sides as single numbers and compare them.
- Use the multiplication law on the left. The bases are the same (2), so add the indices.23 × 24 = 23+4 = 27 = 2 × 2 × 2 × 2 × 2 × 2 × 2 = 128
- Work out the right-hand side. Write 47 as repeated multiplication.47 = 4 × 4 × 4 × 4 × 4 × 4 × 4 = 16,384
- Compare. 128 is not equal to 16,384.So Zoe is not right.
Check. The rule says add the indices and keep the base. Multiplying the bases (2 × 2 = 4) is the mistake. ✓
Watch out. When you multiply powers of the same base, the base does not change.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the division law and compare it with what Dan did.
- See what Dan did. He got 3 from the indices 6 and 2.6 ÷ 2 = 3, so he divided the indices.
- Use the correct law. When you divide powers of the same base, you subtract the indices.56 ÷ 52 = 56−2 = 54
- Write the correct answer and the mistake. Correct answer 54. Dan divided the indices instead of subtracting them.
Check. 56 ÷ 52 = 15,625 ÷ 25 = 625 = 54. ✓
Watch out. Subtract the indices when dividing powers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. After each fold the layers double, so after 6 folds there are 2 × 2 × 2 × 2 × 2 × 2 layers.
- Write it as a power. Six doublings means six lots of 2 multiplied together.26
- Multiply out. Work one step at a time.2 × 2 = 4, 4 × 2 = 8, 8 × 2 = 16, 16 × 2 = 32, 32 × 2 = 64
- Write the answer. 26 = 64 layers
Check. Fold 3 times to get 8, and fold 3 more times: 8 × 8 = 64. ✓
Watch out. After 6 folds the index is 6, not the number of layers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. List the powers of 2 until one is bigger than 1000.
- Write the powers of 2. Each fold doubles the layers, so n folds give 2n layers.26 = 64, 27 = 128, 28 = 256, 29 = 512, 210 = 1024
- Find the first one above 1000. 29 = 512 is too small. 210 = 1024 is bigger than 1000.The smallest number of folds is 10.
Check. 9 folds give 512 layers (not enough) and 10 folds give 1024 layers (more than 1000). ✓
Watch out. You need strictly more than 1000, so 512 is not enough.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the power as repeated multiplication of the base, then multiply.
- Say what the power means. The index 5 tells us to multiply 5 lots of 3 together.35 = 3 × 3 × 3 × 3 × 3
- Multiply step by step, left to right. Do one multiplication at a time so it is easy to follow.3 × 3 = 9
9 × 3 = 27
27 × 3 = 81
81 × 3 = 243
Check. Split the power: 32 × 33 = 9 × 27 = 243. ✓
Watch out. 35 does not mean 3 × 5. The index says how many lots of 3 are multiplied.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out the numbers in each round and multiply, then also use the index law.
- Round 3 and round 2. 33 people and 32 people.33 = 27 and 32 = 9
- Multiply them. 27 × 9 = 243
- Compare with round 5. The index law says 33 × 32 = 33+2 = 35.35 = 243 (from the first part), so they are equal.
Check. 27 × 9 = 243 and 35 = 243. ✓
Watch out. Add the indices (3 + 2 = 5), do not multiply them (3 × 2 = 6).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Volume = (edge)3, so use the power-of-a-power law, then write the answer as a number.
- Write the volume. The edge is 102.V = (102)3
- Multiply the indices. (am)n = am×n.2 × 3 = 6, so V = 106
- Write 106 as a number. 106 is 1 followed by 6 zeros.V = 1,000,000 cm3
Check. 102 = 100 and 100 × 100 × 100 = 1,000,000. ✓
Watch out. The index of the edge is multiplied by 3, not added.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write 8 and 16 as powers of 2, then use the multiplication law.
- Write 8 as a power of 2. Find how many 2s multiply to make 8.2 × 2 × 2 = 8, so 8 = 23
- Write 16 as a power of 2. 2 × 2 × 2 × 2 = 16, so 16 = 24
- Multiply using the law. The bases are the same, so add the indices.8 × 16 = 23 × 24 = 23+4 = 27
- Check the value. 8 × 16 = 128 and 27 = 128, so they are equal.
Check. 27 = 24 × 23 = 16 × 8 = 128. ✓
Watch out. In a “show that” question end with a sentence that states the result.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Turn each statement into an equation for the indices, then solve the two equations.
- Use the multiplication law. Multiplying adds the indices.a + b = 8
- Use the division law. Dividing subtracts the indices.a − b = 2
- Add the two equations. The b terms cancel: (a + b) + (a − b) = 8 + 2.2a = 10, so a = 5
- Find b. Put a = 5 into a + b = 8.5 + b = 8, so b = 3
Check. 25 × 23 = 32 × 8 = 256 = 28, and 25 ÷ 23 = 32 ÷ 8 = 4 = 22. ✓
Watch out. Write an equation for the indices first.
Exercise 6B The laws of indices with letters
Non-calculatorKey words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x3 × x4 = x3 + 4 = x7
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.x7
Check. Choose numbers: x = 2. The original expression has the value 128, and the answer x7 also has the value 128. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Deal with the letter y: add the indices. The letter is the same in both terms, so the index law applies. (y on its own means y1.)y5 × y2 = y5 + 2 = y7
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.y7
Check. Choose numbers: y = 3. The original expression has the value 2187, and the answer y7 also has the value 2187. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Deal with the letter a: add the indices. The letter is the same in both terms, so the index law applies. (a on its own means a1.)a1 × a6 = a1 + 6 = a7
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.a7
Check. Choose numbers: a = 2. The original expression has the value 128, and the answer a7 also has the value 128. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Deal with the letter p: add the indices. The letter is the same in both terms, so the index law applies. (p on its own means p1.)p3 × p3 = p3 + 3 = p6
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.p6
Check. Choose numbers: p = 2. The original expression has the value 64, and the answer p6 also has the value 64. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter x: subtract the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x9 ÷ x4 = x9 − 4 = x5
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.x5
Check. Choose numbers: x = 2. The original expression has the value 32, and the answer x5 also has the value 32. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter y: subtract the indices. The letter is the same in both terms, so the index law applies. (y on its own means y1.)y7 ÷ y2 = y7 − 2 = y5
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.y5
Check. Choose numbers: y = 3. The original expression has the value 243, and the answer y5 also has the value 243. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter m: subtract the indices. The letter is the same in both terms, so the index law applies. (m on its own means m1.)m8 ÷ m1 = m8 − 1 = m7
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.m7
Check. Choose numbers: m = 2. The original expression has the value 128, and the answer m7 also has the value 128. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter t: subtract the indices. The letter is the same in both terms, so the index law applies. (t on its own means t1.)t5 ÷ t4 = t5 − 4 = t1
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.t
Check. Choose numbers: t = 2. The original expression has the value 2, and the answer t also has the value 2. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the letter x to the power: multiply the indices. (am)n = am×n.(x3)2 = x3 × 2 = x6
- Put it all together. x6
Check. Choose numbers: x = 2. The original expression has the value 64, and the answer x6 also has the value 64. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the letter y to the power: multiply the indices. (am)n = am×n.(y4)3 = y4 × 3 = y12
- Put it all together. y12
Check. Choose numbers: y = 3. The original expression has the value 531,441, and the answer y12 also has the value 531,441. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the letter a to the power: multiply the indices. (am)n = am×n.(a2)5 = a2 × 5 = a10
- Put it all together. a10
Check. Choose numbers: a = 2. The original expression has the value 1024, and the answer a10 also has the value 1024. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the letter p to the power: multiply the indices. (am)n = am×n.(p6)2 = p6 × 2 = p12
- Put it all together. p12
Check. Choose numbers: p = 2. The original expression has the value 4096, and the answer p12 also has the value 4096. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.3 × 4 = 12
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x2 × x5 = x2 + 5 = x7
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.12x7
Check. Choose numbers: x = 2. The original expression has the value 1536, and the answer 12x7 also has the value 1536. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.2 × 5 = 10
- Deal with the letter y: add the indices. The letter is the same in both terms, so the index law applies. (y on its own means y1.)y3 × y1 = y3 + 1 = y4
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.10y4
Check. Choose numbers: y = 3. The original expression has the value 810, and the answer 10y4 also has the value 810. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.6 × 2 = 12
- Deal with the letter a: add the indices. The letter is the same in both terms, so the index law applies. (a on its own means a1.)a4 × a2 = a4 + 2 = a6
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.12a6
Check. Choose numbers: a = 2. The original expression has the value 768, and the answer 12a6 also has the value 768. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.7 × 3 = 21
- Deal with the letter p: add the indices. The letter is the same in both terms, so the index law applies. (p on its own means p1.)p1 × p3 = p1 + 3 = p4
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.21p4
Check. Choose numbers: p = 2. The original expression has the value 336, and the answer 21p4 also has the value 336. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.12 ÷ 4 = 3
- Deal with the letter y: subtract the indices. The letter is the same in both terms, so the index law applies. (y on its own means y1.)y8 ÷ y3 = y8 − 3 = y5
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.3y5
Check. Choose numbers: y = 3. The original expression has the value 729, and the answer 3y5 also has the value 729. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.20 ÷ 5 = 4
- Deal with the letter a: subtract the indices. The letter is the same in both terms, so the index law applies. (a on its own means a1.)a7 ÷ a2 = a7 − 2 = a5
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.4a5
Check. Choose numbers: a = 2. The original expression has the value 128, and the answer 4a5 also has the value 128. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.18 ÷ 6 = 3
- Deal with the letter x: subtract the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x5 ÷ x1 = x5 − 1 = x4
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.3x4
Check. Choose numbers: x = 2. The original expression has the value 48, and the answer 3x4 also has the value 48. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.8 ÷ 2 = 4
- Deal with the letter m: subtract the indices. The letter is the same in both terms, so the index law applies. (m on its own means m1.)m6 ÷ m6 = m6 − 6 = 1 (anything to the power 0 is 1)
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.4
Check. Choose numbers: m = 2. The original expression has the value 4, and the answer 4 also has the value 4. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.(2)4 = 2 × 2 × 2 × 2 = 16
- Raise the letter a to the power: multiply the indices. (am)n = am×n.(a3)4 = a3 × 4 = a12
- Put it all together. 16a12
Check. Choose numbers: a = 2. The original expression has the value 65,536, and the answer 16a12 also has the value 65,536. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.(5)3 = 5 × 5 × 5 = 125
- Raise the letter x to the power: multiply the indices. (am)n = am×n.(x2)3 = x2 × 3 = x6
- Put it all together. 125x6
Check. Choose numbers: x = 2. The original expression has the value 8000, and the answer 125x6 also has the value 8000. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.(3)2 = 3 × 3 = 9
- Raise the letter y to the power: multiply the indices. (am)n = am×n.(y4)2 = y4 × 2 = y8
- Put it all together. 9y8
Check. Choose numbers: y = 3. The original expression has the value 59,049, and the answer 9y8 also has the value 59,049. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.
- Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.(10)2 = 10 × 10 = 100
- Raise the letter p to the power: multiply the indices. (am)n = am×n.(p3)2 = p3 × 2 = p6
- Put it all together. 100p6
Check. Choose numbers: p = 2. The original expression has the value 6400, and the answer 100p6 also has the value 6400. ✓
Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.3 × 5 = 15
- Deal with the letter a: add the indices. The letter is the same in both terms, so the index law applies. (a on its own means a1.)a2 × a1 = a2 + 1 = a3
- Deal with the letter b: add the indices. The letter is the same in both terms, so the index law applies. (b on its own means b1.)b1 × b3 = b1 + 3 = b4
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.15a3b4
Check. Choose numbers: a = 2, b = 3. The original expression has the value 9720, and the answer 15a3b4 also has the value 9720. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.4 × 2 = 8
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x2 × x1 = x2 + 1 = x3
- Deal with the letter y: add the indices. The letter is the same in both terms, so the index law applies. (y on its own means y1.)y1 × y2 = y1 + 2 = y3
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.8x3y3
Check. Choose numbers: x = 2, y = 3. The original expression has the value 1728, and the answer 8x3y3 also has the value 1728. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.6 ÷ 3 = 2
- Deal with the letter p: subtract the indices. The letter is the same in both terms, so the index law applies. (p on its own means p1.)p3 ÷ p1 = p3 − 1 = p2
- Deal with the letter q: subtract the indices. The letter is the same in both terms, so the index law applies. (q on its own means q1.)q2 ÷ q1 = q2 − 1 = q1
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.2p2q
Check. Choose numbers: p = 2, q = 3. The original expression has the value 24, and the answer 2p2q also has the value 24. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.10 ÷ 5 = 2
- Deal with the letter m: subtract the indices. The letter is the same in both terms, so the index law applies. (m on its own means m1.)m5 ÷ m2 = m5 − 2 = m3
- Deal with the letter n: subtract the indices. The letter is the same in both terms, so the index law applies. (n on its own means n1.)n4 ÷ n1 = n4 − 1 = n3
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.2m3n3
Check. Choose numbers: m = 2, n = 3. The original expression has the value 432, and the answer 2m3n3 also has the value 432. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Work out the product correctly and compare with Mia.
- Multiply the numbers in front. 2 × 3 = 6, so Mia's 6 is right.2 × 3 = 6
- Multiply the letters. Same letter, so add the indices.x3 × x4 = x3+4 = x7
- Compare with Mia. Mia got 12 = 3 × 4, so she multiplied the indices instead of adding them.Correct answer: 6x7
Check. Try x = 2: 2x3 = 16 and 3x4 = 48, so the product is 768. And 6x7 = 6 × 128 = 768, but 6x12 = 6 × 4096 = 24,576. ✓
Watch out. Add the indices when multiplying, even when there are numbers in front.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Substitute a number for x and see whether both sides are equal.
- Choose a value. Any value can be used; choose a small one.x = 2
- Work out the left-hand side. Replace x by 2. Each power is worked out first.23 + 22 = 8 + 4 = 12
- Work out the right-hand side. 25 = 32
- Compare. 12 is not equal to 32, so the statement is false.Not true. The index laws apply to multiplying and dividing powers, not adding them.
Check. One counter-example is enough to show a statement is false. ✓
Watch out. You can only add like terms such as 3x2 + 4x2 = 7x2.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Area = length × width, then simplify using the laws of indices.
- Write the product. The area of a rectangle is length multiplied by width.Area = 4x3 × 3x2
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.4 × 3 = 12
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x3 × x2 = x3 + 2 = x5
- Write the answer with units. 12x5 cm2
Check. Try x = 2: length = 32, width = 12, area = 384. And 12 × 25 = 12 × 32 = 384. ✓
Watch out. Multiply the numbers, then add the indices.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Width = area ÷ length. Divide the numbers and subtract the indices.
- Write the division. Area = length × width, so width = area ÷ length.width = 24x7 ÷ 6x3
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.24 ÷ 6 = 4
- Deal with the letter x: subtract the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x7 ÷ x3 = x7 − 3 = x4
- Write the answer with units. 4x4 cm
Check. Multiply back: length × width = 6x3 × 4x4 = 24x7. ✓
Watch out. Divide the numbers, subtract the indices.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Volume = length × width × height. Multiply the three edges, one at a time, using the laws of indices on the number and on each letter.
- Look at the order of the operations. Work from the left, one operation at a time, exactly as in BIDMAS (brackets and powers first).
- Do the first operation: multiply by 3a2. Multiply the numbers; add the indices of each letter.2 × 3 = 6
a1 × a2 = a1 + 2 = a3
Result so far: 6a3 - Do the second operation: multiply by 5a3. Multiply the numbers; add the indices of each letter.6 × 5 = 30
a3 × a3 = a3 + 3 = a6
Result so far: 30a6
Check. Choose numbers: a = 2. The original expression gives 1920 and the answer 30a6 gives 1920. ✓
Watch out. Keep the working in the same order each time. Deal with brackets and powers first, then multiplication and division from left to right.
Zero and negative indices
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So far every index has been a positive whole number. But what do 20 and 2−1 mean? We cannot multiply “zero lots of 2”, so instead we follow the pattern.
Look at the boxes from left to right: 8, 4, 2, then the next number must be 2 ÷ 2 = 1. So 20 = 1. The same thing happens with any base, so any non-zero number to the power 0 equals 1. You can also see it from the division law: a3 ÷ a3 = a3−3 = a0, but anything divided by itself is 1.
Continue the pattern past 1: the next value is 1 ÷ 2 = 1/2, so 2−1 = 1/2. Then 2−2 = 1/4 and 2−3 = 1/8. A negative index means “one over” (the reciprocal; see Chapter 3):
a−n = 1an
A negative index does not make the answer negative. It makes the answer small: a fraction. For a fraction base, the reciprocal turns the fraction upside down, so 23−2 = 322 = 94.
Two more things to know. 10−1 = 0.1, 10−2 = 0.01 and 10−3 = 0.001 (you will need these for standard form in section 6.4). And all the laws of section 6.1 still work with zero and negative indices. For example 52 × 5−4 = 52+(−4) = 5−2 = 125, and x3 ÷ x5 = x−2 = 1x2.
Key ideas
- a0 = 1 for any number a that is not 0. (50 = 1, 10000 = 1.)
- a1 = a.
- a−n = 1 ÷ an. A negative index means “one over”, not a negative number.
- (a/b)−n = (b/a)n: flip the fraction and make the index positive.
- 10−1 = 0.1, 10−2 = 0.01, 10−3 = 0.001.
- The laws of indices work for all whole-number indices, including zero and negative ones.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. Powers are worked out before multiplying and adding (BIDMAS): each zero power becomes 1.50 = 1 and 30 = 1
50 + 2 × 30 = 1 + 2 × 1
= 1 + 2 = 3 - Write the answer. 3
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".2−3: the index is −3
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 22 = 4, 21 = 2, 20 = 1, and each step is ÷ 2, so 2−1 = 12.)2−3 = 123
- Work out the bottom. 23 means 3 lots of 2 multiplied together.23 = 2 × 2 × 2 = 8
- Write the answer as a fraction. 2−3 = 18
Check. Multiply the answer by 23: 18 × 8 = 1, and 2−3 × 23 = 20 = 1. ✓
Watch out. A negative index does not give a negative answer: 2−3 = 18, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.(23)−2: the index is −2
- Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 23 is 32.(23)−2 = (32)2
- Raise the top and the bottom to the power. The index 2 applies to the numerator and to the denominator.3222 = 94
- Write the answer (simplify if possible). 94
Check. Multiply the answer by (23)2 = 49: the product is 1, as (23)−2 × (23)2 = (23)0 = 1. ✓
Watch out. A negative index does not give a negative answer: (23)−2 = 94, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".125
- Write the denominator as a power of the base. 25 = 5 × 5 = 52125 = 152
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.152 = 5−2
Check. Convert back: 5−2 = 152 = 125. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 5.
- Say what the rule means. The index counts the lots of the base. Multiplying powers joins the lots together.52 has 2 lots of 5; 5−4 has −4 lots of 5.
- Add the indices. Joining the lots means adding the number of lots. The rule works for negative indices too, so take care with the signs.2 + (−4) = −2
- Write the answer as a single power. Keep the same base and use the new index.52 × 5−4 = 5−2
- Work out the value. A negative index means "one over" the positive power (see section 6.2).5−2 = 152 = 125
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter x: subtract the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x3 ÷ x5 = x3 − 5 = x−2 = 1x2
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.x−2
- Write with positive indices. A negative index means "one over": a−n = 1/an.x−2 = 1x2
Check. Choose numbers: x = 2. The original expression has the value 14, and the answer x−2 also has the value 14. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Watch out
A negative index does not make a number negative. 2−3 is 18, not −8 and not −6. Also be careful with zero: 50 = 1, not 0. And in 5x0 the index 0 belongs to the x only, so it is 5 × 1 = 5, while (5x)0 = 1.Exercise 6C Zero and negative indices
Non-calculatorKey words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. Only the part that has the 0 index becomes 1. Anything else stays.70 = 1
- Write the answer. 1
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. Only the part that has the 0 index becomes 1. Anything else stays.1000 = 1
- Write the answer. 1
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. The bracket (−3) is a non-zero number, so its zero power is 1.(−3)0 = 1
- Write the answer. 1
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. Only the part that has the 0 index becomes 1. Anything else stays.20 = 1 and 30 = 1
1 + 1 = 2 - Write the answer. 2
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. Only the part that has the 0 index becomes 1. Anything else stays.40 = 1
5 × 1 = 5 - Write the answer. 5
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".2−1: the index is −1
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 22 = 4, 21 = 2, 20 = 1, and each step is ÷ 2, so 2−1 = 12.)2−1 = 121
- Work out the bottom. 21 means 1 lots of 2 multiplied together.21 = 2 = 2
- Write the answer as a fraction. 2−1 = 12
Check. Multiply the answer by 21: 12 × 2 = 1, and 2−1 × 21 = 20 = 1. ✓
Watch out. A negative index does not give a negative answer: 2−1 = 12, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".3−2: the index is −2
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 32 = 9, 31 = 3, 30 = 1, and each step is ÷ 3, so 3−1 = 13.)3−2 = 132
- Work out the bottom. 32 means 2 lots of 3 multiplied together.32 = 3 × 3 = 9
- Write the answer as a fraction. 3−2 = 19
Check. Multiply the answer by 32: 19 × 9 = 1, and 3−2 × 32 = 30 = 1. ✓
Watch out. A negative index does not give a negative answer: 3−2 = 19, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".10−3: the index is −3
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 102 = 100, 101 = 10, 100 = 1, and each step is ÷ 10, so 10−1 = 110.)10−3 = 1103
- Work out the bottom. 103 means 3 lots of 10 multiplied together.103 = 10 × 10 × 10 = 1000
- Write the answer as a fraction. 10−3 = 11000
Check. Multiply the answer by 103: 11000 × 1000 = 1, and 10−3 × 103 = 100 = 1. ✓
Watch out. A negative index does not give a negative answer: 10−3 = 11000, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".5−2: the index is −2
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 52 = 25, 51 = 5, 50 = 1, and each step is ÷ 5, so 5−1 = 15.)5−2 = 152
- Work out the bottom. 52 means 2 lots of 5 multiplied together.52 = 5 × 5 = 25
- Write the answer as a fraction. 5−2 = 125
Check. Multiply the answer by 52: 125 × 25 = 1, and 5−2 × 52 = 50 = 1. ✓
Watch out. A negative index does not give a negative answer: 5−2 = 125, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".4−1: the index is −1
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 42 = 16, 41 = 4, 40 = 1, and each step is ÷ 4, so 4−1 = 14.)4−1 = 141
- Work out the bottom. 41 means 1 lots of 4 multiplied together.41 = 4 = 4
- Write the answer as a fraction. 4−1 = 14
Check. Multiply the answer by 41: 14 × 4 = 1, and 4−1 × 41 = 40 = 1. ✓
Watch out. A negative index does not give a negative answer: 4−1 = 14, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".2−4: the index is −4
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 22 = 4, 21 = 2, 20 = 1, and each step is ÷ 2, so 2−1 = 12.)2−4 = 124
- Work out the bottom. 24 means 4 lots of 2 multiplied together.24 = 2 × 2 × 2 × 2 = 16
- Write the answer as a fraction. 2−4 = 116
Check. Multiply the answer by 24: 116 × 16 = 1, and 2−4 × 24 = 20 = 1. ✓
Watch out. A negative index does not give a negative answer: 2−4 = 116, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".18
- Write the denominator as a power of the base. 8 = 2 × 2 × 2 = 2318 = 123
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.123 = 2−3
Check. Convert back: 2−3 = 123 = 18. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".19
- Write the denominator as a power of the base. 9 = 3 × 3 = 3219 = 132
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.132 = 3−2
Check. Convert back: 3−2 = 132 = 19. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".1100
- Write the denominator as a power of the base. 100 = 10 × 10 = 1021100 = 1102
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.1102 = 10−2
Check. Convert back: 10−2 = 1102 = 1100. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".1125
- Write the denominator as a power of the base. 125 = 5 × 5 × 5 = 531125 = 153
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.153 = 5−3
Check. Convert back: 5−3 = 153 = 1125. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".132
- Write the denominator as a power of the base. 32 = 2 × 2 × 2 × 2 × 2 = 25132 = 125
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.125 = 2−5
Check. Convert back: 2−5 = 125 = 132. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.(12)−3: the index is −3
- Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 12 is 21.(12)−3 = (21)3
- Raise the top and the bottom to the power. The index 3 applies to the numerator and to the denominator.2313 = 81
- Write the answer (simplify if possible). 8
Check. Multiply the answer by (12)3 = 18: the product is 1, as (12)−3 × (12)3 = (12)0 = 1. ✓
Watch out. A negative index does not give a negative answer: (12)−3 = 8, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.(23)−2: the index is −2
- Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 23 is 32.(23)−2 = (32)2
- Raise the top and the bottom to the power. The index 2 applies to the numerator and to the denominator.3222 = 94
- Write the answer (simplify if possible). 94
Check. Multiply the answer by (23)2 = 49: the product is 1, as (23)−2 × (23)2 = (23)0 = 1. ✓
Watch out. A negative index does not give a negative answer: (23)−2 = 94, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.(15)−2: the index is −2
- Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 15 is 51.(15)−2 = (51)2
- Raise the top and the bottom to the power. The index 2 applies to the numerator and to the denominator.5212 = 251
- Write the answer (simplify if possible). 25
Check. Multiply the answer by (15)2 = 125: the product is 1, as (15)−2 × (15)2 = (15)0 = 1. ✓
Watch out. A negative index does not give a negative answer: (15)−2 = 25, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.(34)−2: the index is −2
- Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 34 is 43.(34)−2 = (43)2
- Raise the top and the bottom to the power. The index 2 applies to the numerator and to the denominator.4232 = 169
- Write the answer (simplify if possible). 169
Check. Multiply the answer by (34)2 = 916: the product is 1, as (34)−2 × (34)2 = (34)0 = 1. ✓
Watch out. A negative index does not give a negative answer: (34)−2 = 169, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.(25)−1: the index is −1
- Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 25 is 52.(25)−1 = (52)1
- Raise the top and the bottom to the power. The index 1 applies to the numerator and to the denominator.5121 = 52
- Write the answer (simplify if possible). 52
Check. Multiply the answer by (25)1 = 25: the product is 1, as (25)−1 × (25)1 = (25)0 = 1. ✓
Watch out. A negative index does not give a negative answer: (25)−1 = 52, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−1 = 1101
- Work out the bottom. 101 is 1 followed by 1 zeros.101 = 10, so 10−1 = 110
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 1 times, starting from 1.1 → 0.1
Check. 1 ÷ 10 = 0.1. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−2 = 1102
- Work out the bottom. 102 is 1 followed by 2 zeros.102 = 100, so 10−2 = 1100
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 2 times, starting from 1.1 → 0.1 → 0.01
Check. 1 ÷ 100 = 0.01. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−3 = 1103
- Work out the bottom. 103 is 1 followed by 3 zeros.103 = 1000, so 10−3 = 11000
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 3 times, starting from 1.1 → 0.1 → 0.01 → 0.001
Check. 1 ÷ 1000 = 0.001. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−4 = 1104
- Work out the bottom. 104 is 1 followed by 4 zeros.104 = 10,000, so 10−4 = 110,000
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 4 times, starting from 1.1 → 0.1 → 0.01 → 0.001 → 0.0001
Check. 1 ÷ 10,000 = 0.0001. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−5 = 1105
- Work out the bottom. 105 is 1 followed by 5 zeros.105 = 100,000, so 10−5 = 1100,000
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 5 times, starting from 1.1 → 0.1 → 0.01 → 0.001 → 0.0001 → 0.00001
Check. 1 ÷ 100,000 = 0.00001. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A number (or bracket) to the power zero is 1.
- Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.a0 = 1
- Replace every power with index 0 by 1, and work out the rest. Only the part that has the 0 index becomes 1. Anything else stays.100 = 1
Pattern: 1000, 100, 10, then 10 ÷ 10 = 1 - Write the answer. 1
Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓
Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−1 = 1101
- Work out the bottom. 101 is 1 followed by 1 zeros.101 = 10, so 10−1 = 110
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 1 times, starting from 1.1 → 0.1
Check. 1 ÷ 10 = 0.1. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−2 = 1102
- Work out the bottom. 102 is 1 followed by 2 zeros.102 = 100, so 10−2 = 1100
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 2 times, starting from 1.1 → 0.1 → 0.01
Check. 1 ÷ 100 = 0.01. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 5.
- Say what the rule means. The index counts the lots of the base. Multiplying powers joins the lots together.52 has 2 lots of 5; 5−4 has −4 lots of 5.
- Add the indices. Joining the lots means adding the number of lots. The rule works for negative indices too, so take care with the signs.2 + (−4) = −2
- Write the answer as a single power. Keep the same base and use the new index.52 × 5−4 = 5−2
- Work out the value. A negative index means "one over" the positive power (see section 6.2).5−2 = 152 = 125
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you divide powers with the same base, you subtract the indices: am ÷ an = am−n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 2.
- Say what the rule means. Dividing cancels lots of the base from the top: every lot on the bottom removes one lot from the top.23 has 3 lots of 2; we take away 5 lots.
- Subtract the indices. The number of lots left is the first index take away the second.3 − 5 = −2
- Write the answer as a single power. Keep the same base and use the new index.23 ÷ 25 = 2−2
- Work out the value. A negative index means "one over" the positive power (see section 6.2).2−2 = 122 = 14
Check. Work out the numbers: 23 = 8 and 25 = 32. 8 ÷ 32 = 14, and 2−2 = 14. ✓
Watch out. Subtract the indices when you divide. Do not divide the indices, and never divide the bases.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To raise a power to a power, multiply the indices: (am)n = am×n.
- Say what the rule means. The outer index −1 says how many lots of 32 to multiply. Each lot contributes 2 lots of 3.2 × (−1) = −2
- Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.2 × (−1) = −2
- Write the answer as a single power. Keep the same base and use the new index.(32)−1 = 3−2
- Work out the value. A negative index means "one over" the positive power (see section 6.2).3−2 = 132 = 19
Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 10.
- Say what the rule means. The index counts the lots of the base. Multiplying powers joins the lots together.10−3 has −3 lots of 10; 105 has 5 lots of 10.
- Add the indices. Joining the lots means adding the number of lots. The rule works for negative indices too, so take care with the signs.−3 + 5 = 2
- Write the answer as a single power. Keep the same base and use the new index.10−3 × 105 = 102
- Work out the value. 102 means 2 lots of 10 multiplied together.102 = 10 × 10 = 100
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 7.
- Say what the rule means. The index counts the lots of the base. Multiplying powers joins the lots together.7−2 has −2 lots of 7; 7−1 has −1 lots of 7.
- Add the indices. Joining the lots means adding the number of lots. The rule works for negative indices too, so take care with the signs.−2 + (−1) = −3
- Write the answer as a single power. Keep the same base and use the new index.7−2 × 7−1 = 7−3
- Work out the value. A negative index means "one over" the positive power (see section 6.2).7−3 = 173 = 1343
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter x: subtract the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x2 ÷ x6 = x2 − 6 = x−4 = 1x4
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.x−4
- Write with positive indices. A negative index means "one over": a−n = 1/an.x−4 = 1x4
Check. Choose numbers: x = 2. The original expression has the value 116, and the answer x−4 also has the value 116. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Deal with the letter y: subtract the indices. The letter is the same in both terms, so the index law applies. (y on its own means y1.)y3 ÷ y8 = y3 − 8 = y−5 = 1y5
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.y−5
- Write with positive indices. A negative index means "one over": a−n = 1/an.y−5 = 1y5
Check. Choose numbers: y = 3. The original expression has the value 1243, and the answer y−5 also has the value 1243. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Deal with the letter a: add the indices. The letter is the same in both terms, so the index law applies. (a on its own means a1.)a2 × a−5 = a2 + (−5) = a−3
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.a−3
- Write with positive indices. A negative index means "one over": a−n = 1/an.a−3 = 1a3
Check. Choose numbers: a = 2. The original expression has the value 18, and the answer a−3 also has the value 18. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.3 × 4 = 12
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x−2 × x5 = x−2 + 5 = x3
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.12x3
Check. Choose numbers: x = 2. The original expression has the value 96, and the answer 12x3 also has the value 96. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the rule for a negative index and compare it with Jack's answer.
- See what Jack did. He got −9 from 3 × 3 = 9 and then used the minus sign from the index.Jack: 3−2 = −(3 × 3) = −9
- Use the correct rule. A negative index means one over the positive power. It never changes the sign of the number.3−2 = 132 = 19
- Write the conclusion. Jack's mistake: a negative index gives a fraction, not a negative number. Correct value: 19.
Check. 19 × 32 = 19 × 9 = 1, as 3−2 × 32 = 30 = 1. ✓
Watch out. The minus sign in the index means “reciprocal”.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Divide a power by itself in two different ways: with the index law, and with numbers.
- Use the division law. Subtract the indices.53 ÷ 53 = 53−3 = 50
- Work it out with numbers. 53 = 5 × 5 × 5 = 125. Any number divided by itself is 1.53 ÷ 53 = 125 ÷ 125 = 1
- Compare. Both calculations are the same question, so the answers match.50 = 1
Check. The same argument works for any base: an ÷ an = 1 = a0. ✓
Watch out. This is why 50 is 1 and not 0.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. To find “how many times longer” divide the larger length by the smaller length, then use the division law.
- Write the division. Cell length ÷ virus length.10−5 ÷ 10−7
- Subtract the indices. Same base 10, so subtract. Take care: subtracting a negative adds.−5 − (−7) = −5 + 7 = 2, so the answer is 102
- Write 102 as a number. 102 = 10 × 10.102 = 100. The cell is 100 times longer.
Check. 100 × 10−7 = 102 × 10−7 = 10−5, so the cell is 100 times as long as the virus. ✓
Watch out. Subtracting a negative index: −5 − (−7) = −5 + 7.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write each power as a fraction, then compare the fractions.
- Write each as a fraction. A negative index means one over the positive power.2−3 = 18 and 3−2 = 19
- Compare the fractions. Both fractions have 1 on top, so the one with the smaller denominator is larger (the pieces are bigger).8 < 9, so 18 > 19
- Write the conclusion. 2−3 is larger.
Check. As decimals: 1/8 = 0.125 and 1/9 = 0.111…, and 0.125 > 0.111…. ✓
Watch out. With the same top, a bigger bottom means a smaller fraction.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Substitute each value of n, and use the negative index rule.
- Mass after 3 days. 2−3 means 1 over 23.2−3 = 18, so mass = 80 × 18 = 80 ÷ 8 = 10 g
- Mass after 5 days. 2−5 = 1 over 25 = 1 over 32.80 × 132 = 80 ÷ 32 = 2.5 g
- Write the answers. 10 g after 3 days and 2.5 g after 5 days.
Check. Each extra day halves the mass: 80, 40, 20, 10 (day 3), 5, 2.5 (day 5). ✓
Watch out. A negative power divides; it does not give a negative mass.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 2.
- Work out the top first: multiply, so add the indices. am × an = am+n.−3 + 5 = 2, so the top is 22
- Divide: subtract the indices. am ÷ an = am−n.222−2 = 22 ÷ 2−2 = 24, because 2 − (−2) = 4
- Work out the value. Write the power in full and multiply.24 = 2 × 2 × 2 × 2 = 16
Check. The total of the indices on top is 2 and on the bottom is −2; 2 − (−2) = 4. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Exercise 6D Index equations and mixed practice
Non-calculatorKey words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 2 that equals 32. A list makes it easy to spot.20 = 1
21 = 2
22 = 4
23 = 8
24 = 16
25 = 32 - Find the one that matches. Read down the list until you see 32.25 = 32
- Write the value of the unknown. The unknown n is the index of the matching power.n = 5
Check. Put it back: 25 = 32. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 3 that equals 81. A list makes it easy to spot.30 = 1
31 = 3
32 = 9
33 = 27
34 = 81 - Find the one that matches. Read down the list until you see 81.34 = 81
- Write the value of the unknown. The unknown n is the index of the matching power.n = 4
Check. Put it back: 34 = 81. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 5 that equals 125. A list makes it easy to spot.50 = 1
51 = 5
52 = 25
53 = 125
54 = 625 - Find the one that matches. Read down the list until you see 125.53 = 125
- Write the value of the unknown. The unknown n is the index of the matching power.n = 3
Check. Put it back: 53 = 125. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 10 that equals 1000. A list makes it easy to spot.100 = 1
101 = 10
102 = 100
103 = 1000
104 = 10,000 - Find the one that matches. Read down the list until you see 1000.103 = 1000
- Write the value of the unknown. The unknown n is the index of the matching power.n = 3
Check. Put it back: 103 = 1000. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 2 that equals 128. A list makes it easy to spot.20 = 1
21 = 2
22 = 4
23 = 8
24 = 16
25 = 32
26 = 64
27 = 128 - Find the one that matches. Read down the list until you see 128.27 = 128
- Write the value of the unknown. The unknown n is the index of the matching power.n = 7
Check. Put it back: 27 = 128. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 2 that equals 18. A list makes it easy to spot.2−3 = 18
2−2 = 14
2−1 = 12
20 = 1
21 = 2
22 = 4
23 = 8
24 = 16 - Find the one that matches. Read down the list until you see 18.2−3 = 18
- Write the value of the unknown. The unknown n is the index of the matching power.n = −3
Check. Put it back: 2−3 = 18. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 3 that equals 19. A list makes it easy to spot.3−3 = 127
3−2 = 19
3−1 = 13
30 = 1
31 = 3
32 = 9
33 = 27
34 = 81 - Find the one that matches. Read down the list until you see 19.3−2 = 19
- Write the value of the unknown. The unknown n is the index of the matching power.n = −2
Check. Put it back: 3−2 = 19. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 10 that equals 1100. A list makes it easy to spot.10−3 = 11000
10−2 = 1100
10−1 = 110
100 = 1
101 = 10
102 = 100
103 = 1000
104 = 10,000 - Find the one that matches. Read down the list until you see 1100.10−2 = 1100
- Write the value of the unknown. The unknown n is the index of the matching power.n = −2
Check. Put it back: 10−2 = 1100. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 5 that equals 15. A list makes it easy to spot.5−3 = 1125
5−2 = 125
5−1 = 15
50 = 1
51 = 5
52 = 25
53 = 125
54 = 625 - Find the one that matches. Read down the list until you see 15.5−1 = 15
- Write the value of the unknown. The unknown n is the index of the matching power.n = −1
Check. Put it back: 5−1 = 15. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the number on the right as a power of the same base, then compare the indices.
- Write the powers of the base in a list. We are looking for the power of 4 that equals 116. A list makes it easy to spot.4−3 = 164
4−2 = 116
4−1 = 14
40 = 1
41 = 4
42 = 16
43 = 64
44 = 256 - Find the one that matches. Read down the list until you see 116.4−2 = 116
- Write the value of the unknown. The unknown n is the index of the matching power.n = −2
Check. Put it back: 4−2 = 116. ✓
Watch out. If the right-hand side is a fraction such as 1/8, the index is negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use equal bases: if the powers are equal, the indices are equal.
- Both sides have the same base. When the bases are equal, the indices must be equal too.Base 2 on both sides.
- Make the indices equal. If ap = aq then p = q.x + 3 = 8
- Solve the simple equation. Subtract 3 from both sides.x = 8 − 3 = 5
Check. Put x = 5 back: the left-hand index is 5 + 3 = 8, so we get 28, which matches the right-hand side. ✓
Watch out. Check by substituting back into the original equation.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use equal bases: if the powers are equal, the indices are equal.
- Both sides have the same base. When the bases are equal, the indices must be equal too.Base 3 on both sides.
- Make the indices equal. If ap = aq then p = q.x − 1 = 4
- Solve the simple equation. Add 1 from both sides.x = 4 + 1 = 5
Check. Put x = 5 back: the left-hand index is 5 − 1 = 4, so we get 34, which matches the right-hand side. ✓
Watch out. Check by substituting back into the original equation.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use equal bases: if the powers are equal, the indices are equal.
- Both sides have the same base. When the bases are equal, the indices must be equal too.Base 5 on both sides.
- Make the indices equal. If ap = aq then p = q.x + 2 = 6
- Solve the simple equation. Subtract 2 from both sides.x = 6 − 2 = 4
Check. Put x = 4 back: the left-hand index is 4 + 2 = 6, so we get 56, which matches the right-hand side. ✓
Watch out. Check by substituting back into the original equation.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use equal bases: if the powers are equal, the indices are equal.
- Both sides have the same base. When the bases are equal, the indices must be equal too.Base 10 on both sides.
- Make the indices equal. If ap = aq then p = q.x − 2 = 3
- Solve the simple equation. Add 2 from both sides.x = 3 + 2 = 5
Check. Put x = 5 back: the left-hand index is 5 − 2 = 3, so we get 103, which matches the right-hand side. ✓
Watch out. Check by substituting back into the original equation.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write each power as a fraction, then add.
- Write each power as a fraction. A negative index means one over the positive power.2−1 = 12 and 2−2 = 14
- Find a common denominator. The LCM of 2 and 4 is 4.12 = 24
- Add the numerators. 24 + 14 = 34
Check. As decimals: 0.5 + 0.25 = 0.75 = 3/4. ✓
Watch out. Convert each power to a fraction before adding.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write each power as a fraction, then add the fractions. Fractions need a common denominator.
- Write each power as a fraction. A negative index means one over the positive power.3−1 = 13 and 3−2 = 19
- Find a common denominator. The denominators are 3 and 9. 9 is a multiple of 3, so use 9.13 = 39
- Add the numerators and keep the denominator. The pieces are now the same size.39 + 19 = 49
Check. As decimals: 0.333… + 0.111… = 0.444… and 4/9 = 0.444…. ✓
Watch out. Convert each power to a fraction before adding. You cannot add the indices when adding powers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write each power as a number or fraction, then add.
- Work out each power. 50 = 1 (zero index) and 5−1 = one over 5.50 = 1 and 5−1 = 15
- Add. Write 1 as a fraction with denominator 5 so the pieces match.1 + 15 = 55 + 15 = 65
- Write as a mixed number if you wish. 65 = 115
Check. As decimals: 1 + 0.2 = 1.2 and 6/5 = 1.2. ✓
Watch out. 50 is 1, not 0.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out the value of each power, then order the values.
- Work out each value. Use the zero and negative index rules and the pattern of doubling.2−1 = 12
20 = 1
2−3 = 18
22 = 4 - Order the values. Smallest first: 1/8, 1/2, 1, 4.18 < 12 < 1 < 4
- Write the original powers in this order. The question asks for the powers, not their values.2−3, 2−1, 20, 22
Check. A larger index (for the same base 2) always gives a larger value, so the order of the indices −3 < −1 < 0 < 2 matches. ✓
Watch out. Put the original expressions in order, not their values.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.
- Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".18
- Write the denominator as a power of the base. 8 = 2 × 2 × 2 = 2318 = 123
- Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.123 = 2−3
Check. Convert back: 2−3 = 123 = 18. ✓
Watch out. The number on the bottom becomes the base. The index gets the minus sign.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Write both numbers as powers of 2, then use the multiplication law.
- Write 8 as a power of 2. 2 × 2 × 2 = 8.8 = 23
- Write 1/32 as a power of 2. 32 = 25, and one over 25 is 2−5.132 = 2−5
- Multiply: add the indices. 23 × 2−5 = 23 + (−5) = 2−2
Check. 8 × 132 = 832 = 14 and 2−2 = 14. ✓
Watch out. Convert to the same base first.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Flip the fraction to remove the negative index, then use the laws of indices with base 3.
- Deal with the fraction to a negative power. Flip the fraction and make the index positive.(13)−2 = (31)2 = 32
- Use the multiplication law. Both are powers of 3, so add the indices.32 × 3−4 = 32 + (−4) = 3−2
- Write 3−2 as a fraction. 3−2 = 132 = 19
Check. Work with numbers: 32 = 9 and 3−4 = 181; 9 × 181 = 981 = 19. ✓
Watch out. The reciprocal of 1/3 is 3.
Roots and fractional indices
Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page
A root undoes a power. A square has area 25 cm2. Its side is the number that multiplies by itself to give 25. That number is 5, so the square root of 25 is 5. We write √25 = 5. A cube has volume 27 cm3. Its edge is the number that gives 27 when multiplied by itself three times, so the cube root of 27 is 3, written 3√27 = 3.
Learn the perfect squares up to 152 = 225 and the cubes 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000 (see Chapter 2). Then roots of these are quick. You can also take roots of fractions and decimals: √(9/16) = 3/4 because (3/4)2 = 9/16, and √0.25 = 0.5 because 0.5 × 0.5 = 0.25.
Most numbers are not perfect squares, but we can say where their roots lie. √50 is between √49 = 7 and √64 = 8, so it is between 7 and 8. A calculator gives √50 = 7.07…. Use the √ key for square roots and the cube root key (often SHIFT then √) for cube roots.
Remember: (√a)2 = a. Equations such as x2 = 49 have two solutions, x = 7 and x = −7, because (−7)2 = 49 too. The √ sign itself means the positive root. You cannot take the square root of a negative number (no real number squares to −9), but a cube root of a negative number is fine: 3√(−8) = −2.
Key ideas
- √a is the positive number that multiplies by itself to give a. 3√a multiplies three times.
- (√a)2 = a, and x2 = k has two solutions, ±√k.
- To place a root between two whole numbers use the perfect squares (or cubes) on each side.
- Roots of fractions: take the root of the top and of the bottom.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√144: which number to the power 2 equals 144?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36, 72 = 49, 82 = 64, 92 = 81, 102 = 100, 112 = 121, 122 = 144
- Write the answer. 122 = 144.12
Check. Check: 122 = 12 × 12 = 144. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Spot that the number is a fraction. A fraction is a top number over a bottom number, and we can deal with each separately.916: top 9, bottom 16
- Take the root of the top and of the bottom. For a fraction, √(a ÷ b) = √a ÷ √b.√9 = 3 and √16 = 4
- Write the answer as a fraction. 34
Check. Check: 34 to the power 2 = 916. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√125: which number to the power 3 equals 125?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8, 33 = 27, 43 = 64, 53 = 125
- Write the answer. 53 = 125.5
Check. Check: 53 = 5 × 5 × 5 = 125. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect squares that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the square root of perfect squares exactly, so use them as markers.72 = 49 and 82 = 64
- Place the number between them. 50 lies between 49 and 64.49 < 50 < 64
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).7 < √50 < 8
Check. A calculator gives √50 = 7.071, which is between 7 and 8. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Method. Work out each root or power separately, then add and subtract.
- Work out each root or power on its own. A root undoes a power; a power is repeated multiplication.√36 = 6, because 6 × 6 = 36
3√27 = 3, because 3 × 3 × 3 = 27
23 = 2 × 2 × 2 = 8 - Put the values into the calculation. Keep the signs the same.√36 + 3√27 − 23 = 6 + 3 − 8
- Work out the answer. Add and subtract from left to right.6 + 3 − 8 = 1
Check. Work through it again from the left: 6 + 3 − 8 = 1. ✓
Watch out. Do each root or power first (BIDMAS: powers and roots before adding and subtracting).
Watch out
The square root of 36 is 6, not 18. A root does not halve the number. And √(9 + 16) is not √9 + √16: √25 = 5 but 3 + 4 = 7. Add or subtract inside the root first.Exercise 6E Roots without a calculator
Non-calculatorKey words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√36: which number to the power 2 equals 36?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36
- Write the answer. 62 = 36.6
Check. Check: 62 = 6 × 6 = 36. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√81: which number to the power 2 equals 81?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36, 72 = 49, 82 = 64, 92 = 81
- Write the answer. 92 = 81.9
Check. Check: 92 = 9 × 9 = 81. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√121: which number to the power 2 equals 121?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36, 72 = 49, 82 = 64, 92 = 81, 102 = 100, 112 = 121
- Write the answer. 112 = 121.11
Check. Check: 112 = 11 × 11 = 121. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√169: which number to the power 2 equals 169?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36, 72 = 49, 82 = 64, 92 = 81, 102 = 100, 112 = 121, 122 = 144, 132 = 169
- Write the answer. 132 = 169.13
Check. Check: 132 = 13 × 13 = 169. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√400: which number to the power 2 equals 400?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36, 72 = 49, 82 = 64, 92 = 81, 102 = 100, 112 = 121, 122 = 144, 132 = 169, 142 = 196, 152 = 225, 162 = 256, 172 = 289, 182 = 324, 192 = 361, 202 = 400
- Write the answer. 202 = 400.20
Check. Check: 202 = 20 × 20 = 400. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Say what the question is asking. The square root of a number is the number that gives the original number when 2 lots of it are multiplied together. It undoes the power 2.√25: which number to the power 2 equals 25?
- Test the powers in order. List the powers until you reach the number.12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25
- Write the answer. 52 = 25.5
Check. Check: 52 = 5 × 5 = 25. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√8: which number to the power 3 equals 8?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8
- Write the answer. 23 = 8.2
Check. Check: 23 = 2 × 2 × 2 = 8. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√27: which number to the power 3 equals 27?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8, 33 = 27
- Write the answer. 33 = 27.3
Check. Check: 33 = 3 × 3 × 3 = 27. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√64: which number to the power 3 equals 64?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8, 33 = 27, 43 = 64
- Write the answer. 43 = 64.4
Check. Check: 43 = 4 × 4 × 4 = 64. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√125: which number to the power 3 equals 125?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8, 33 = 27, 43 = 64, 53 = 125
- Write the answer. 53 = 125.5
Check. Check: 53 = 5 × 5 × 5 = 125. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√1000: which number to the power 3 equals 1000?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8, 33 = 27, 43 = 64, 53 = 125, 63 = 216, 73 = 343, 83 = 512, 93 = 729, 103 = 1000
- Write the answer. 103 = 1000.10
Check. Check: 103 = 10 × 10 × 10 = 1000. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Say what the question is asking. The cube root of a number is the number that gives the original number when 3 lots of it are multiplied together. It undoes the power 3.3√216: which number to the power 3 equals 216?
- Test the powers in order. List the powers until you reach the number.13 = 1, 23 = 8, 33 = 27, 43 = 64, 53 = 125, 63 = 216
- Write the answer. 63 = 216.6
Check. Check: 63 = 6 × 6 × 6 = 216. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Spot that the number is a fraction. A fraction is a top number over a bottom number, and we can deal with each separately.916: top 9, bottom 16
- Take the root of the top and of the bottom. For a fraction, √(a ÷ b) = √a ÷ √b.√9 = 3 and √16 = 4
- Write the answer as a fraction. 34
Check. Check: 34 to the power 2 = 916. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Spot that the number is a fraction. A fraction is a top number over a bottom number, and we can deal with each separately.425: top 4, bottom 25
- Take the root of the top and of the bottom. For a fraction, √(a ÷ b) = √a ÷ √b.√4 = 2 and √25 = 5
- Write the answer as a fraction. 25
Check. Check: 25 to the power 2 = 425. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Spot that the number is a fraction. A fraction is a top number over a bottom number, and we can deal with each separately.136: top 1, bottom 36
- Take the root of the top and of the bottom. For a fraction, √(a ÷ b) = √a ÷ √b.√1 = 1 and √36 = 6
- Write the answer as a fraction. 16
Check. Check: 16 to the power 2 = 136. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Spot that the number is a fraction. A fraction is a top number over a bottom number, and we can deal with each separately.4964: top 49, bottom 64
- Take the root of the top and of the bottom. For a fraction, √(a ÷ b) = √a ÷ √b.√49 = 7 and √64 = 8
- Write the answer as a fraction. 78
Check. Check: 78 to the power 2 = 4964. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Write the decimal as a fraction. A fraction lets us take the root of the top and the bottom separately.0.25 = 25100
- Take the square root of the top and of the bottom. √(a ÷ b) = √a ÷ √b.√25 = 5 and √100 = 10, so 510
- Write the answer as a decimal. Convert the fraction back.0.5
Check. Check: 0.5 × 0.5 = 0.25. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Write the decimal as a fraction. A fraction lets us take the root of the top and the bottom separately.0.81 = 81100
- Take the square root of the top and of the bottom. √(a ÷ b) = √a ÷ √b.√81 = 9 and √100 = 10, so 910
- Write the answer as a decimal. Convert the fraction back.0.9
Check. Check: 0.9 × 0.9 = 0.81. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 2.
- Write the decimal as a fraction. A fraction lets us take the root of the top and the bottom separately.0.0144 = 14410,000
- Take the square root of the top and of the bottom. √(a ÷ b) = √a ÷ √b.√144 = 12 and √10,000 = 100, so 12100
- Write the answer as a decimal. Convert the fraction back.0.12
Check. Check: 0.12 × 0.12 = 0.0144. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Write the decimal as a fraction. A fraction lets us take the root of the top and the bottom separately.0.027 = 271000
- Take the cube root of the top and of the bottom. 3√(a ÷ b) = 3√a ÷ 3√b.3√27 = 3 and 3√1000 = 10, so 310
- Write the answer as a decimal. Convert the fraction back.0.3
Check. Check: 0.3 × 0.3 × 0.3 = 0.027. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Key words. The square root of a number undoes squaring: √49 = 7 because 72 = 49. The cube root undoes cubing: 3√27 = 3 because 33 = 27.
Method. Find the number that gives the original when raised to the power 3.
- Write the decimal as a fraction. A fraction lets us take the root of the top and the bottom separately.0.008 = 81000
- Take the cube root of the top and of the bottom. 3√(a ÷ b) = 3√a ÷ 3√b.3√8 = 2 and 3√1000 = 10, so 210
- Write the answer as a decimal. Convert the fraction back.0.2
Check. Check: 0.2 × 0.2 × 0.2 = 0.008. ✓
Watch out. The square root of 49 is 7, not 24.5. Do not halve the number: a root undoes a power.
Method. Work out each root or power separately, then add and subtract.
- Work out each root or power on its own. A root undoes a power; a power is repeated multiplication.√49 = 7, because 7 × 7 = 49
√81 = 9, because 9 × 9 = 81 - Put the values into the calculation. Keep the signs the same.√49 + √81 = 7 + 9
- Work out the answer. Add and subtract from left to right.7 + 9 = 16
Check. Work through it again from the left: 7 + 9 = 16. ✓
Watch out. Do each root or power first (BIDMAS: powers and roots before adding and subtracting).
Method. Work out each root or power separately, then add and subtract.
- Work out each root or power on its own. A root undoes a power; a power is repeated multiplication.3√64 = 4, because 4 × 4 × 4 = 64
√16 = 4, because 4 × 4 = 16 - Put the values into the calculation. Keep the signs the same.3√64 − √16 = 4 − 4
- Work out the answer. Add and subtract from left to right.4 − 4 = 0
Check. Work through it again from the left: 4 − 4 = 0. ✓
Watch out. Do each root or power first (BIDMAS: powers and roots before adding and subtracting).
Method. Work out each root or power separately, then add and subtract.
- Work out each root or power on its own. A root undoes a power; a power is repeated multiplication.52 = 5 × 5 = 25
3√125 = 5, because 5 × 5 × 5 = 125 - Put the values into the calculation. Keep the signs the same.52 − 3√125 = 25 − 5
- Work out the answer. Add and subtract from left to right.25 − 5 = 20
Check. Work through it again from the left: 25 − 5 = 20. ✓
Watch out. Do each root or power first (BIDMAS: powers and roots before adding and subtracting).
Method. Work out each root or power separately, then add and subtract.
- Work out each root or power on its own. A root undoes a power; a power is repeated multiplication.√100 = 10, because 10 × 10 = 100
33 = 3 × 3 × 3 = 27
√4 = 2, because 2 × 2 = 4 - Put the values into the calculation. Keep the signs the same.√100 + 33 − √4 = 10 + 27 − 2
- Work out the answer. Add and subtract from left to right.10 + 27 − 2 = 35
Check. Work through it again from the left: 10 + 27 − 2 = 35. ✓
Watch out. Do each root or power first (BIDMAS: powers and roots before adding and subtracting).
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect squares that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the square root of perfect squares exactly, so use them as markers.42 = 16 and 52 = 25
- Place the number between them. 20 lies between 16 and 25.16 < 20 < 25
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).4 < √20 < 5
Check. A calculator gives √20 = 4.472, which is between 4 and 5. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect squares that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the square root of perfect squares exactly, so use them as markers.82 = 64 and 92 = 81
- Place the number between them. 70 lies between 64 and 81.64 < 70 < 81
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).8 < √70 < 9
Check. A calculator gives √70 = 8.367, which is between 8 and 9. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect cubes that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the cube root of perfect cubes exactly, so use them as markers.33 = 27 and 43 = 64
- Place the number between them. 30 lies between 27 and 64.27 < 30 < 64
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).3 < 3√30 < 4
Check. A calculator gives 3√30 = 3.107, which is between 3 and 4. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect cubes that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the cube root of perfect cubes exactly, so use them as markers.43 = 64 and 53 = 125
- Place the number between them. 100 lies between 64 and 125.64 < 100 < 125
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).4 < 3√100 < 5
Check. A calculator gives 3√100 = 4.642, which is between 4 and 5. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect squares that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the square root of perfect squares exactly, so use them as markers.142 = 196 and 152 = 225
- Place the number between them. 200 lies between 196 and 225.196 < 200 < 225
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).14 < √200 < 15
Check. A calculator gives √200 = 14.142, which is between 14 and 15. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Take the square root of both sides. There are two answers: one positive and one negative.
- Say what the equation asks. We need a number which, multiplied by itself 2 times, makes 49.x2 = 49
- Find the positive root. 7 × 7 = 49.72 = 49
- Remember the negative root. A negative number squared is also positive: (−7)2 = 49. An even power cannot tell the sign.x = 7 or x = −7
Check. 72 = 49 and (−7)2 = 49. ✓
Watch out. Do not forget the negative answer when you solve an equation with x2.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Take the square root of both sides. There are two answers: one positive and one negative.
- Say what the equation asks. We need a number which, multiplied by itself 2 times, makes 121.x2 = 121
- Find the positive root. 11 × 11 = 121.112 = 121
- Remember the negative root. A negative number squared is also positive: (−11)2 = 121. An even power cannot tell the sign.x = 11 or x = −11
Check. 112 = 121 and (−11)2 = 121. ✓
Watch out. Do not forget the negative answer when you solve an equation with x2.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Take the cube root of both sides. A cube root gives just one answer.
- Say what the equation asks. We need a number which, cubed, makes 27.x3 = 27
- Find the cube root. 3 × 3 × 3 = 27.x = 3√27 = 3
- Check for other answers. A cube of a negative number is negative, so there is only one answer.x = 3
Check. 33 = 27. ✓
Watch out. Odd powers have only one real solution.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Take the cube root of both sides. A cube root gives just one answer.
- Say what the equation asks. We need a number which, cubed, makes 125.x3 = 125
- Find the cube root. 5 × 5 × 5 = 125.x = 3√125 = 5
- Check for other answers. A cube of a negative number is negative, so there is only one answer.x = 5
Check. 53 = 125. ✓
Watch out. Odd powers have only one real solution.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Squaring and square-rooting are inverse operations, so they undo each other.
- Remember what a square root is. √7 is the number which, multiplied by itself, makes 7.√7 × √7 = 7
- Squaring undoes the square root. Squaring means multiplying by itself.(√7)2 = √7 × √7 = 7
Check. A calculator gives √7 = 2.6458… and its square is 7. ✓
Watch out. (√7)2 is 7, not 49 and not 3.5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Squaring and square-rooting are inverse operations, so they undo each other.
- Remember what a square root is. √13 is the number which, multiplied by itself, makes 13.√13 × √13 = 13
- Squaring undoes the square root. Squaring means multiplying by itself.(√13)2 = √13 × √13 = 13
Check. A calculator gives √13 = 3.6056… and its square is 13. ✓
Watch out. (√7)2 is 7, not 49 and not 3.5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Squaring and square-rooting are inverse operations, so they undo each other.
- Remember what a square root is. √2 is the number which, multiplied by itself, makes 2.√2 × √2 = 2
- Squaring undoes the square root. Squaring means multiplying by itself.(√2)2 = √2 × √2 = 2
Check. A calculator gives √2 = 1.4142… and its square is 2. ✓
Watch out. (√7)2 is 7, not 49 and not 3.5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Squaring and square-rooting are inverse operations, so they undo each other.
- Remember what a square root is. √50 is the number which, multiplied by itself, makes 50.√50 × √50 = 50
- Squaring undoes the square root. Squaring means multiplying by itself.(√50)2 = √50 × √50 = 50
Check. A calculator gives √50 = 7.0711… and its square is 50. ✓
Watch out. (√7)2 is 7, not 49 and not 3.5.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. The side of a square is the square root of its area. The perimeter is 4 times the side.
- Find the side. Side × side = area, so side = √area.√81 = 9, because 9 × 9 = 81. The side is 9 m.
- Find the perimeter. A square has 4 equal sides.4 × 9 = 36
- Write the answers. Side 9 m; fence 36 m.
Check. 9 × 9 = 81 and 9 + 9 + 9 + 9 = 36. ✓
Watch out. Perimeter is a length (m); area is in m2.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Find the edge of the cube using a cube root, then multiply by 12.
- Find the length of one edge. Edge × edge × edge = volume, so edge = 3√volume.3√216 = 6, because 6 × 6 × 6 = 216
- Multiply by 12. A cube has 12 equal edges.12 × 6 = 72
- Write the answer. 72 cm
Check. 6 × 6 = 36, 36 × 6 = 216. ✓
Watch out. Use a cube root for a volume of a cube, not a square root.
Key words. A perfect square is the square of a whole number (1, 4, 9, 16…). A perfect cube is the cube of a whole number (1, 8, 27, 64…).
Method. Find the two perfect squares that the number lies between, then take roots.
- Find the perfect powers on either side of the number. We know the square root of perfect squares exactly, so use them as markers.122 = 144 and 132 = 169
- Place the number between them. 150 lies between 144 and 169.144 < 150 < 169
- Take the root of each part. Roots keep the order (a bigger number has a bigger root).12 < √150 < 13
Check. A calculator gives √150 = 12.247, which is between 12 and 13. ✓
Watch out. Between two whole numbers means one is below and the next one is above.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out both and compare.
- Work out the left side. Add inside the root first.√(9 + 16) = √25 = 5
- Work out the right side. Take each root separately and then add.√9 + √16 = 3 + 4 = 7
- Compare. 5 is not equal to 7.No, they are not the same.
Check. 5 × 5 = 25 and 7 × 7 = 49, so the two values clearly differ. ✓
Watch out. A root of a sum is not the sum of the roots.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Square the two numbers and compare with 50. Squaring keeps the order for positive numbers.
- Square 7. 72 = 49
- Square 7.1. Multiply 71 × 71 = 5041, then put in two decimal places.7.12 = 50.41
- Compare. Since 49 < 50 < 50.41, taking square roots of each part keeps the order.7 < √50 < 7.1
Check. A calculator gives √50 = 7.0710…. ✓
Watch out. Write the squared values next to 50 to make the comparison clear.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Think about the sign of a square.
- Squares of positive numbers. 3 × 3 = 9 is positive.32 = 9
- Squares of negative numbers. (−3) × (−3) = 9, because negative × negative = positive.(−3)2 = 9
- Conclude. Every square is zero or positive, so none can equal −9.No real number squares to −9.
Check. Try 0: 02 = 0, which is not negative either. ✓
Watch out. Be careful to separate √(−9) from −√9 = −3, which is fine.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. List the squares and cubes in the range and look for a number in both lists.
- List the squares between 50 and 100. Square the whole numbers from 8 to 10.82 = 64, 92 = 81, 102 = 100 (72 = 49 is too small)
- List the cubes between 50 and 100. Cube 4 and 5.43 = 64, 53 = 125 (too big)
- Find the number in both lists. 64 (= 82 = 43)
Check. 8 × 8 = 64 and 4 × 4 × 4 = 64. ✓
Watch out. Only 64 works in this range (also 26).
Exercise 6F Powers and roots with a calculator
Calculator allowedMethod. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [√] 7 [=]
- Read the display. The calculator shows many digits.√7 = 2.645751…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.2.65
Check. The answer should lie between 2 and 3, because 22 = 4 and 32 = 9. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [√] 130 [=]
- Read the display. The calculator shows many digits.√130 = 11.401754…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.11.4
Check. The answer should lie between 11 and 12, because 112 = 121 and 122 = 144. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [√] 2000 [=]
- Read the display. The calculator shows many digits.√2000 = 44.72136…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.44.7
Check. The answer should lie between 44 and 45, because 442 = 1936 and 452 = 2025. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [SHIFT] [√] (the cube root key, shown as 3√) 50 [=]
- Read the display. The calculator shows many digits.3√50 = 3.684031…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.3.68
Check. The answer should lie between 3 and 4, because 33 = 27 and 43 = 64. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [SHIFT] [√] (the cube root key, shown as 3√) 300 [=]
- Read the display. The calculator shows many digits.3√300 = 6.69433…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.6.69
Check. The answer should lie between 6 and 7, because 63 = 216 and 73 = 343. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 2.5 [^] 4 [=]
- Read the display. The calculator shows more digits than we need.2.54 = 39.0625…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.39.1
Check. Split the power: 2.52 × 2.52 = 6.25 × 6.25 = 39.0625. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 1.05 [^] 10 [=]
- Read the display. The calculator shows more digits than we need.1.0510 = 1.628895…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.1.63
Check. Split the power: 1.055 × 1.055 = 1.2762815625 × 1.2762815625 = 1.62889462677744140625. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 3.2 [^] (−2) [=]
- Read the display. The calculator shows more digits than we need.3.2−2 = 0.097656…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.0.0977
Check. Split the power: 3.21 × 3.21 = 3.2 × 3.2 = 10.24, and the reciprocal is 1 ÷ 10.24 = 0.097656…. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 0.9 [^] 5 [=]
- Read the display. The calculator shows more digits than we need.0.95 = 0.59049…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.0.590
Check. Split the power: 0.92 × 0.93 = 0.81 × 0.729 = 0.59049. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 8 [^] (−2) [=]
- Read the display. The calculator shows more digits than we need.8−2 = 0.015625…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.0.0156
Check. Split the power: 81 × 81 = 8 × 8 = 64, and the reciprocal is 1 ÷ 64 = 0.015625…. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Side = √area. Use the root key and round to 1 decimal place.
- Write the side as a square root. Side × side = area.side = √90
- Use the calculator. Press [√] 90 [=].√90 = 9.4868…
- Round to 1 decimal place. The digit after the first decimal place is 8, so round up.9.5 cm
Check. 9.5 × 9.5 = 90.25, which is close to 90. ✓
Watch out. Give the unit and the accuracy asked for.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Work out the power first, then multiply. Round only at the very end.
- Work out 1.045. Use the power key: 1.04 [^] 5 [=].1.045 = 1.2166529024
- Multiply by 1500. Keep all the digits for now.1500 × 1.2166529024 = 1824.9793536
- Round to the nearest penny. Two decimal places.£1,824.98
Check. 1.04 × 1.04 × 1.04 × 1.04 × 1.04 ≈ 1.2167, and 1500 × 1.2167 ≈ 1825. ✓
Watch out. Do the power before multiplying (BIDMAS).
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Do the powers first, add, then take the square root (BIDMAS).
- Square each number. Use the x2 key or multiply by itself.5.22 = 27.04
3.92 = 15.21 - Add. The square root covers the whole sum.27.04 + 15.21 = 42.25
- Take the square root. Press [√] 42.25 [=].√42.25 = 6.5
Check. 6.5 × 6.5 = 42.25. ✓
Watch out. Add under the root before square-rooting.
Method. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [√] 11 [=]
- Read the display. The calculator shows many digits.√11 = 3.316625…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.3.32
Check. The answer should lie between 3 and 4, because 32 = 9 and 42 = 16. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the root key on the calculator and round to the accuracy asked for.
- Enter the calculation. Press the root key first, then the number (in a bracket if your calculator needs one).Press: [√] 59 [=]
- Read the display. The calculator shows many digits.√59 = 7.681146…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, then look at the next digit to decide whether to round up.7.68
Check. The answer should lie between 7 and 8, because 72 = 49 and 82 = 64. ✓
Watch out. Round only at the end, and give the number of significant figures asked for.
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 1.5 [^] 6 [=]
- Read the display. The calculator shows more digits than we need.1.56 = 11.390625…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.11.4
Check. Split the power: 1.53 × 1.53 = 3.375 × 3.375 = 11.390625. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Method. Use the power key on the calculator (negative indices in brackets) and round at the end.
- Enter the calculation using the power key. The power key is labelled [x□] or [^]. Type the base, the key, then the index. For a negative index use the (−) key. Put a negative index in brackets.Press: 0.5 [^] (−3) [=]
- Read the display. The calculator shows more digits than we need.0.5−3 = 8…
- Round to 3 significant figures. Count 3 digits from the first non-zero digit, and look at the next digit to round.8.00
Check. Split the power: 0.51 × 0.52 = 0.5 × 0.25 = 0.125, and the reciprocal is 1 ÷ 0.125 = 8…. ✓
Watch out. Do not round in the middle of a calculation. For a negative index remember it means "one over the power".
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Cube both numbers and compare with 100.
- Cube 4.6. Use the power key: 4.6 [^] 3.4.63 = 97.336
- Cube 4.7. 4.73 = 103.823
- Compare. Cube roots keep the order, so 100 lies between the two cubes.97.336 < 100 < 103.823, so 4.6 < 3√100 < 4.7
Check. A calculator gives 3√100 = 4.6416…. ✓
Watch out. Show the two cubes in your answer.
Standard form: large and small numbers
Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page
The Sun is about 150,000,000,000 m from the Earth. A hydrogen atom is about 0.0000000001 m wide. These numbers are long and easy to get wrong. Standard form is a short, standard way to write very big and very small numbers. It uses powers of 10 (see section 6.2).
A number is in standard form when it is written as A × 10n where
- A is at least 1 and less than 10 (one non-zero digit before the decimal point), and
- n is a whole number (positive, negative or zero).
Big numbers have a positive power; small numbers (less than 1) have a negative power. For example 150,000,000,000 = 1.5 × 1011 and 0.0000000001 = 1 × 10−10.
To write a number in standard form: (1) put the decimal point after the first non-zero digit to make A; (2) count how many places the decimal point moved; (3) that count is the power. Moving to the left gives a positive power, and moving to the right gives a negative power. For example 45,000,000: the point moves 7 places left, so 4.5 × 107. And 0.00034: the point moves 4 places right, so 3.4 × 10−4.
To change back to an ordinary number do the opposite: a positive power moves the decimal point right, a negative power moves it left, one place for each power of 10. The number is not made negative by a negative power: 4 × 10−2 = 0.04.
Sometimes a number looks like standard form but the front number is not between 1 and 10, for example 45 × 103. Fix it by changing A and the power together: 45 = 4.5 × 10, so 45 × 103 = 4.5 × 10 × 103 = 4.5 × 104. On a calculator, standard form is often shown with an E: 3.6E8 means 3.6 × 108.
Key ideas
- Standard form: A × 10n with 1 ≤ A < 10 and n a whole number.
- Big number: positive power. Number between 0 and 1: negative power.
- Count how many places the decimal point moves. Left means positive, right means negative.
- To fix 45 × 103: write 45 as 4.5 × 10, then add 1 to the power.
- A calculator shows 3.6 × 108 as 3.6E8.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 45,000,000 is 4.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 4.5
- Count how many places the decimal point has moved. Starting from 45000000 the decimal point has to move 7 places to the left to sit after the 4. Each place moved is a factor of 10.45000000 → 4.5: 7 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 7
- Write the answer. Put A and the power of 10 together.4.5 × 107
Check. Convert back: 4.5 × 107 = 45000000 = 45,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00034 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.4
- Count how many places the decimal point has moved. Starting from 0.00034 the decimal point has to move 4 places to the right to sit after the 3. Each place moved is a factor of 10.0.00034 → 3.4: 4 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −4
- Write the answer. Put A and the power of 10 together.3.4 × 10−4
Check. Convert back: 3.4 × 10−4 = 0.00034 = 0.00034. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 4, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.104 means multiply by 10, 4 times
- Move the decimal point 4 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.3.07 → 30.7 → 307 → 3070 → 30700
- Write the answer. The last number in the chain is the answer.30,700
Check. Convert back to standard form: 30700 has first non-zero digit 3, so A = 3.07 and n = 4. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −5, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−5 means divide by 10, 5 times
- Move the decimal point 5 places to the left. Move it one place at a time and fill the new places with zeros.4.1 → 0.41 → 0.041 → 0.0041 → 0.00041 → 0.000041
- Write the answer. The last number in the chain is the answer.0.000041
Check. Convert back to standard form: 0.000041 has first non-zero digit 4, so A = 4.1 and n = −5. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 45, which is 10 or more, so this is not in standard form.
- Write 45 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the left makes the number 10 times smaller, so we must multiply by 101 to keep the value the same.45 = 4.5 × 101
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.45 × 103 = 4.5 × 101 × 103
= 4.5 × 101 + 3 - Write the answer. 4.5 × 104
Check. Both forms are the same number, 45000: 45 × 1000 = 45000 and 4.5 × 10000 = 45000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Round to 3 significant figures first. Significant figures count from the first non-zero digit.299,792,458 = 300,000,000 to 3 s.f.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 300,000,000 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.00
- Count how many places the decimal point has moved. Starting from 300000000 the decimal point has to move 8 places to the left to sit after the 3. Each place moved is a factor of 10.300000000 → 3.00: 8 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 8
- Write the answer. Put A and the power of 10 together.3.00 × 108
Check. Convert back: 3.00 × 108 = 300000000 (which is 300,000,000 to 3 s.f.). ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Watch out
Count how far the decimal point moves, not how many zeros you can see. And check the sign: a number less than 1 must have a negative power. 0.0072 = 7.2 × 10−3, not 7.2 × 103.Exam tip
A is always at least 1 and less than 10. If you get 12 × 105 or 0.7 × 104 you are not finished: it is not standard form yet.Exercise 6I Writing numbers in standard form
Non-calculatorKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check that the front number is at least 1 and less than 10.
- Remember the rule. A number is in standard form if it is written as A × 10n, where A is at least 1 and less than 10, and n is a whole number.1 ≤ A < 10 and n a whole number
- Check the front number A. A is the number in front of the × 10.A = 3.4: this is at least 1 and less than 10 ✓
- Check the power of 10. The index must be a whole number (it can be positive, negative or zero).n = 5, a whole number ✓
- Decide. Yes, it is in standard form.
Check. 3.4 is inside the range 1 to 10, so the answer is yes. ✓
Watch out. A can equal 1 but it can never be 10. The power of 10 can be 0, positive or negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check that the front number is at least 1 and less than 10.
- Remember the rule. A number is in standard form if it is written as A × 10n, where A is at least 1 and less than 10, and n is a whole number.1 ≤ A < 10 and n a whole number
- Check the front number A. A is the number in front of the × 10.A = 34: this is 10 or more ✗
- Check the power of 10. The index must be a whole number (it can be positive, negative or zero).n = 4, a whole number ✓
- Decide. A must be between 1 and 10. It should be 3.4 × 105.No, it is not in standard form.
Check. 34 is outside the range 1 to 10, so the answer is no. ✓
Watch out. A can equal 1 but it can never be 10. The power of 10 can be 0, positive or negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check that the front number is at least 1 and less than 10.
- Remember the rule. A number is in standard form if it is written as A × 10n, where A is at least 1 and less than 10, and n is a whole number.1 ≤ A < 10 and n a whole number
- Check the front number A. A is the number in front of the × 10.A = 0.5: this is less than 1 ✗
- Check the power of 10. The index must be a whole number (it can be positive, negative or zero).n = 3, a whole number ✓
- Decide. A must be between 1 and 10. It should be 5 × 102.No, it is not in standard form.
Check. 0.5 is outside the range 1 to 10, so the answer is no. ✓
Watch out. A can equal 1 but it can never be 10. The power of 10 can be 0, positive or negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check that the front number is at least 1 and less than 10.
- Remember the rule. A number is in standard form if it is written as A × 10n, where A is at least 1 and less than 10, and n is a whole number.1 ≤ A < 10 and n a whole number
- Check the front number A. A is the number in front of the × 10.A = 9.99: this is at least 1 and less than 10 ✓
- Check the power of 10. The index must be a whole number (it can be positive, negative or zero).n = −2, a whole number ✓
- Decide. Yes, it is in standard form.
Check. 9.99 is inside the range 1 to 10, so the answer is yes. ✓
Watch out. A can equal 1 but it can never be 10. The power of 10 can be 0, positive or negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check that the front number is at least 1 and less than 10.
- Remember the rule. A number is in standard form if it is written as A × 10n, where A is at least 1 and less than 10, and n is a whole number.1 ≤ A < 10 and n a whole number
- Check the front number A. A is the number in front of the × 10.A = 10: this is 10 or more ✗
- Check the power of 10. The index must be a whole number (it can be positive, negative or zero).n = 2, a whole number ✓
- Decide. A must be between 1 and 10. It should be 1 × 103.No, it is not in standard form.
Check. 10 is outside the range 1 to 10, so the answer is no. ✓
Watch out. A can equal 1 but it can never be 10. The power of 10 can be 0, positive or negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check that the front number is at least 1 and less than 10.
- Remember the rule. A number is in standard form if it is written as A × 10n, where A is at least 1 and less than 10, and n is a whole number.1 ≤ A < 10 and n a whole number
- Check the front number A. A is the number in front of the × 10.A = 6: this is at least 1 and less than 10 ✓
- Check the power of 10. The index must be a whole number (it can be positive, negative or zero).n = 0, a whole number ✓
- Decide. Yes, it is in standard form.
Check. 6 is inside the range 1 to 10, so the answer is yes. ✓
Watch out. A can equal 1 but it can never be 10. The power of 10 can be 0, positive or negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 6000 is 6.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 6
- Count how many places the decimal point has moved. Starting from 6000 the decimal point has to move 3 places to the left to sit after the 6. Each place moved is a factor of 10.6000 → 6: 3 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 3
- Write the answer. Put A and the power of 10 together.6 × 103
Check. Convert back: 6 × 103 = 6000 = 6000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 45,000 is 4.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 4.5
- Count how many places the decimal point has moved. Starting from 45000 the decimal point has to move 4 places to the left to sit after the 4. Each place moved is a factor of 10.45000 → 4.5: 4 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 4
- Write the answer. Put A and the power of 10 together.4.5 × 104
Check. Convert back: 4.5 × 104 = 45000 = 45,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 380,000 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.8
- Count how many places the decimal point has moved. Starting from 380000 the decimal point has to move 5 places to the left to sit after the 3. Each place moved is a factor of 10.380000 → 3.8: 5 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 5
- Write the answer. Put A and the power of 10 together.3.8 × 105
Check. Convert back: 3.8 × 105 = 380000 = 380,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 5,600,000 is 5.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 5.6
- Count how many places the decimal point has moved. Starting from 5600000 the decimal point has to move 6 places to the left to sit after the 5. Each place moved is a factor of 10.5600000 → 5.6: 6 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 6
- Write the answer. Put A and the power of 10 together.5.6 × 106
Check. Convert back: 5.6 × 106 = 5600000 = 5,600,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 91,000,000 is 9.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 9.1
- Count how many places the decimal point has moved. Starting from 91000000 the decimal point has to move 7 places to the left to sit after the 9. Each place moved is a factor of 10.91000000 → 9.1: 7 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 7
- Write the answer. Put A and the power of 10 together.9.1 × 107
Check. Convert back: 9.1 × 107 = 91000000 = 91,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 720 is 7.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 7.2
- Count how many places the decimal point has moved. Starting from 720 the decimal point has to move 2 places to the left to sit after the 7. Each place moved is a factor of 10.720 → 7.2: 2 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 2
- Write the answer. Put A and the power of 10 together.7.2 × 102
Check. Convert back: 7.2 × 102 = 720 = 720. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.7 is 7.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 7
- Count how many places the decimal point has moved. Starting from 0.7 the decimal point has to move 1 place to the right to sit after the 7. Each place moved is a factor of 10.0.7 → 7: 1 place to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −1
- Write the answer. Put A and the power of 10 together.7 × 10−1
Check. Convert back: 7 × 10−1 = 0.7 = 0.7. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.06 is 6.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 6
- Count how many places the decimal point has moved. Starting from 0.06 the decimal point has to move 2 places to the right to sit after the 6. Each place moved is a factor of 10.0.06 → 6: 2 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −2
- Write the answer. Put A and the power of 10 together.6 × 10−2
Check. Convert back: 6 × 10−2 = 0.06 = 0.06. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.0035 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.5
- Count how many places the decimal point has moved. Starting from 0.0035 the decimal point has to move 3 places to the right to sit after the 3. Each place moved is a factor of 10.0.0035 → 3.5: 3 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −3
- Write the answer. Put A and the power of 10 together.3.5 × 10−3
Check. Convert back: 3.5 × 10−3 = 0.0035 = 0.0035. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00072 is 7.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 7.2
- Count how many places the decimal point has moved. Starting from 0.00072 the decimal point has to move 4 places to the right to sit after the 7. Each place moved is a factor of 10.0.00072 → 7.2: 4 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −4
- Write the answer. Put A and the power of 10 together.7.2 × 10−4
Check. Convert back: 7.2 × 10−4 = 0.00072 = 0.00072. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.000081 is 8.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 8.1
- Count how many places the decimal point has moved. Starting from 0.000081 the decimal point has to move 5 places to the right to sit after the 8. Each place moved is a factor of 10.0.000081 → 8.1: 5 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −5
- Write the answer. Put A and the power of 10 together.8.1 × 10−5
Check. Convert back: 8.1 × 10−5 = 0.000081 = 0.000081. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.0000046 is 4.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 4.6
- Count how many places the decimal point has moved. Starting from 0.0000046 the decimal point has to move 6 places to the right to sit after the 4. Each place moved is a factor of 10.0.0000046 → 4.6: 6 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −6
- Write the answer. Put A and the power of 10 together.4.6 × 10−6
Check. Convert back: 4.6 × 10−6 = 0.0000046 = 0.0000046. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 3, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.103 means multiply by 10, 3 times
- Move the decimal point 3 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.5 → 50 → 500 → 5000
- Write the answer. The last number in the chain is the answer.5000
Check. Convert back to standard form: 5000 has first non-zero digit 5, so A = 5 and n = 3. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 4, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.104 means multiply by 10, 4 times
- Move the decimal point 4 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.2.4 → 24 → 240 → 2400 → 24000
- Write the answer. The last number in the chain is the answer.24,000
Check. Convert back to standard form: 24000 has first non-zero digit 2, so A = 2.4 and n = 4. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 5, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.105 means multiply by 10, 5 times
- Move the decimal point 5 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.7.08 → 70.8 → 708 → 7080 → 70800 → 708000
- Write the answer. The last number in the chain is the answer.708,000
Check. Convert back to standard form: 708000 has first non-zero digit 7, so A = 7.08 and n = 5. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 6, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.106 means multiply by 10, 6 times
- Move the decimal point 6 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.1.5 → 15 → 150 → 1500 → 15000 → 150000 → 1500000
- Write the answer. The last number in the chain is the answer.1,500,000
Check. Convert back to standard form: 1500000 has first non-zero digit 1, so A = 1.5 and n = 6. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 7, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.107 means multiply by 10, 7 times
- Move the decimal point 7 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.9.2 → 92 → 920 → 9200 → 92000 → 920000 → 9200000 → 92000000
- Write the answer. The last number in the chain is the answer.92,000,000
Check. Convert back to standard form: 92000000 has first non-zero digit 9, so A = 9.2 and n = 7. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −1, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−1 means divide by 10, 1 times
- Move the decimal point 1 place to the left. Move it one place at a time and fill the new places with zeros.4 → 0.4
- Write the answer. The last number in the chain is the answer.0.4
Check. Convert back to standard form: 0.4 has first non-zero digit 4, so A = 4 and n = −1. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −3, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−3 means divide by 10, 3 times
- Move the decimal point 3 places to the left. Move it one place at a time and fill the new places with zeros.6.2 → 0.62 → 0.062 → 0.0062
- Write the answer. The last number in the chain is the answer.0.0062
Check. Convert back to standard form: 0.0062 has first non-zero digit 6, so A = 6.2 and n = −3. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −4, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−4 means divide by 10, 4 times
- Move the decimal point 4 places to the left. Move it one place at a time and fill the new places with zeros.3.07 → 0.307 → 0.0307 → 0.00307 → 0.000307
- Write the answer. The last number in the chain is the answer.0.000307
Check. Convert back to standard form: 0.000307 has first non-zero digit 3, so A = 3.07 and n = −4. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −5, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−5 means divide by 10, 5 times
- Move the decimal point 5 places to the left. Move it one place at a time and fill the new places with zeros.8.5 → 0.85 → 0.085 → 0.0085 → 0.00085 → 0.000085
- Write the answer. The last number in the chain is the answer.0.000085
Check. Convert back to standard form: 0.000085 has first non-zero digit 8, so A = 8.5 and n = −5. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −6, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−6 means divide by 10, 6 times
- Move the decimal point 6 places to the left. Move it one place at a time and fill the new places with zeros.1.1 → 0.11 → 0.011 → 0.0011 → 0.00011 → 0.000011 → 0.0000011
- Write the answer. The last number in the chain is the answer.0.0000011
Check. Convert back to standard form: 0.0000011 has first non-zero digit 1, so A = 1.1 and n = −6. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 45, which is 10 or more, so this is not in standard form.
- Write 45 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the left makes the number 10 times smaller, so we must multiply by 101 to keep the value the same.45 = 4.5 × 101
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.45 × 103 = 4.5 × 101 × 103
= 4.5 × 101 + 3 - Write the answer. 4.5 × 104
Check. Both forms are the same number, 45000: 45 × 1000 = 45000 and 4.5 × 10000 = 45000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 0.6, which is less than 1, so this is not in standard form.
- Write 0.6 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the right makes the number 10 times bigger, so we must multiply by 10−1 (that is, divide by 10) to keep the value the same.0.6 = 6 × 10−1
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.0.6 × 105 = 6 × 10−1 × 105
= 6 × 10−1 + 5 - Write the answer. 6 × 104
Check. Both forms are the same number, 60000: 0.6 × 100000 = 60000 and 6 × 10000 = 60000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 120, which is 10 or more, so this is not in standard form.
- Write 120 as a number between 1 and 10 times a power of 10. Moving the decimal point 2 places to the left makes the number 100 times smaller, so we must multiply by 102 to keep the value the same.120 = 1.2 × 102
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.120 × 10−4 = 1.2 × 102 × 10−4
= 1.2 × 102 + (−4) - Write the answer. 1.2 × 10−2
Check. Both forms are the same number, 0.012: 120 × 0.0001 = 0.012 and 1.2 × 0.01 = 0.012. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 0.08, which is less than 1, so this is not in standard form.
- Write 0.08 as a number between 1 and 10 times a power of 10. Moving the decimal point 2 places to the right makes the number 100 times bigger, so we must multiply by 10−2 (that is, divide by 100) to keep the value the same.0.08 = 8 × 10−2
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.0.08 × 107 = 8 × 10−2 × 107
= 8 × 10−2 + 7 - Write the answer. 8 × 105
Check. Both forms are the same number, 800000: 0.08 × 10000000 = 800000 and 8 × 100000 = 800000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 250, which is 10 or more, so this is not in standard form.
- Write 250 as a number between 1 and 10 times a power of 10. Moving the decimal point 2 places to the left makes the number 100 times smaller, so we must multiply by 102 to keep the value the same.250 = 2.5 × 102
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.250 × 102 = 2.5 × 102 × 102
= 2.5 × 102 + 2 - Write the answer. 2.5 × 104
Check. Both forms are the same number, 25000: 250 × 100 = 25000 and 2.5 × 10000 = 25000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. The E on a calculator display stands for "times ten to the power of". The display is standard form.
- Read the calculator display. The letter E means "× 10 to the power". The number before E is A. The number after E is the power of 10.3.6E8 means 3.6 × 108
- Write the ordinary number. Move the decimal point 8 places to the right.360,000,000
Check. Back to standard form: the first non-zero digit of 360000000 is 3, giving 3.6 × 108. ✓
Watch out. E5 does not mean 5. 3.6E8 is 3.6 × 108.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. The E on a calculator display stands for "times ten to the power of". The display is standard form.
- Read the calculator display. The letter E means "× 10 to the power". The number before E is A. The number after E is the power of 10.2.4E-3 means 2.4 × 10−3
- Write the ordinary number. Move the decimal point 3 places to the left.0.0024
Check. Back to standard form: the first non-zero digit of 0.0024 is 2, giving 2.4 × 10−3. ✓
Watch out. E5 does not mean 5. 3.6E8 is 3.6 × 108.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. The E on a calculator display stands for "times ten to the power of". The display is standard form.
- Read the calculator display. The letter E means "× 10 to the power". The number before E is A. The number after E is the power of 10.7.1E5 means 7.1 × 105
- Write the ordinary number. Move the decimal point 5 places to the right.710,000
Check. Back to standard form: the first non-zero digit of 710000 is 7, giving 7.1 × 105. ✓
Watch out. E5 does not mean 5. 3.6E8 is 3.6 × 108.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. The E on a calculator display stands for "times ten to the power of". The display is standard form.
- Read the calculator display. The letter E means "× 10 to the power". The number before E is A. The number after E is the power of 10.5E-2 means 5 × 10−2
- Write the ordinary number. Move the decimal point 2 places to the left.0.05
Check. Back to standard form: the first non-zero digit of 0.05 is 5, giving 5 × 10−2. ✓
Watch out. E5 does not mean 5. 3.6E8 is 3.6 × 108.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Round to 2 significant figures first. Significant figures count from the first non-zero digit.4,523,000 = 4,500,000 to 2 s.f.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 4,500,000 is 4.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 4.5
- Count how many places the decimal point has moved. Starting from 4500000 the decimal point has to move 6 places to the left to sit after the 4. Each place moved is a factor of 10.4500000 → 4.5: 6 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 6
- Write the answer. Put A and the power of 10 together.4.5 × 106
Check. Convert back: 4.5 × 106 = 4500000 (which is 4,500,000 to 2 s.f.). ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Round to 2 significant figures first. Significant figures count from the first non-zero digit.0.0003846 = 0.00038 to 2 s.f.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00038 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.8
- Count how many places the decimal point has moved. Starting from 0.00038 the decimal point has to move 4 places to the right to sit after the 3. Each place moved is a factor of 10.0.00038 → 3.8: 4 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −4
- Write the answer. Put A and the power of 10 together.3.8 × 10−4
Check. Convert back: 3.8 × 10−4 = 0.00038 (which is 0.00038 to 2 s.f.). ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Round to 3 significant figures first. Significant figures count from the first non-zero digit.299,792,458 = 300,000,000 to 3 s.f.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 300,000,000 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.00
- Count how many places the decimal point has moved. Starting from 300000000 the decimal point has to move 8 places to the left to sit after the 3. Each place moved is a factor of 10.300000000 → 3.00: 8 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 8
- Write the answer. Put A and the power of 10 together.3.00 × 108
Check. Convert back: 3.00 × 108 = 300000000 (which is 300,000,000 to 3 s.f.). ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Round to 3 significant figures first. Significant figures count from the first non-zero digit.6,371,000 = 6,370,000 to 3 s.f.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 6,370,000 is 6.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 6.37
- Count how many places the decimal point has moved. Starting from 6370000 the decimal point has to move 6 places to the left to sit after the 6. Each place moved is a factor of 10.6370000 → 6.37: 6 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 6
- Write the answer. Put A and the power of 10 together.6.37 × 106
Check. Convert back: 6.37 × 106 = 6370000 (which is 6,370,000 to 3 s.f.). ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 8,100,000,000 is 8.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 8.1
- Count how many places the decimal point has moved. Starting from 8100000000 the decimal point has to move 9 places to the left to sit after the 8. Each place moved is a factor of 10.8100000000 → 8.1: 9 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 9
- Write the answer. Put A and the power of 10 together.8.1 × 109
Check. Convert back: 8.1 × 109 = 8100000000 = 8,100,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 384,400 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3.844
- Count how many places the decimal point has moved. Starting from 384400 the decimal point has to move 5 places to the left to sit after the 3. Each place moved is a factor of 10.384400 → 3.844: 5 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 5
- Write the answer. Put A and the power of 10 together.3.844 × 105
Check. Convert back: 3.844 × 105 = 384400 = 384,400. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.0001 is 1.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 1
- Count how many places the decimal point has moved. Starting from 0.0001 the decimal point has to move 4 places to the right to sit after the 1. Each place moved is a factor of 10.0.0001 → 1: 4 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −4
- Write the answer. Put A and the power of 10 together.1 × 10−4
Check. Convert back: 1 × 10−4 = 0.0001 = 0.0001. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00000000000000000000000000167 is 1.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 1.67
- Count how many places the decimal point has moved. Starting from 0.00000000000000000000000000167 the decimal point has to move 27 places to the right to sit after the 1. Each place moved is a factor of 10.0.00000000000000000000000000167 → 1.67: 27 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −27
- Write the answer. Put A and the power of 10 together.1.67 × 10−27
Check. Convert back: 1.67 × 10−27 = 0.00000000000000000000000000167 = 0.00000000000000000000000000167. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 25,000,000 is 2.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 2.5
- Count how many places the decimal point has moved. Starting from 25000000 the decimal point has to move 7 places to the left to sit after the 2. Each place moved is a factor of 10.25000000 → 2.5: 7 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 7
- Write the answer. Put A and the power of 10 together.2.5 × 107
Check. Convert back: 2.5 × 107 = 25000000 = 25,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 500,000,000 is 5.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 5
- Count how many places the decimal point has moved. Starting from 500000000 the decimal point has to move 8 places to the left to sit after the 5. Each place moved is a factor of 10.500000000 → 5: 8 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 8
- Write the answer. Put A and the power of 10 together.5 × 108
Check. Convert back: 5 × 108 = 500000000 = 500,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.003 is 3.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 3
- Count how many places the decimal point has moved. Starting from 0.003 the decimal point has to move 3 places to the right to sit after the 3. Each place moved is a factor of 10.0.003 → 3: 3 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −3
- Write the answer. Put A and the power of 10 together.3 × 10−3
Check. Convert back: 3 × 10−3 = 0.003 = 0.003. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00001 is 1.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 1
- Count how many places the decimal point has moved. Starting from 0.00001 the decimal point has to move 5 places to the right to sit after the 1. Each place moved is a factor of 10.0.00001 → 1: 5 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −5
- Write the answer. Put A and the power of 10 together.1 × 10−5
Check. Convert back: 1 × 10−5 = 0.00001 = 0.00001. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check the rule for A and use the meaning of a power of 10.
- Check the rule for A. A must be at least 1 and less than 10. A = 1 satisfies this.1 ≤ 1 < 10 ✓
- Write 10. 101 = 10, so 1 × 101 = 10.10 = 1 × 101
- Write 0.1. A negative power means “one over”: 10−1 = 1/10 = 0.1.0.1 = 1 × 10−1
- Conclude. We could not write 10 as 10 × 100 because A must be less than 10.Both are in standard form.
Check. 1 × 101 = 10 and 1 × 10−1 = 0.1. ✓
Watch out. A can be 1 but never 10.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Check whether the number is big or small, then count how far the decimal point moves.
- Decide if the number is big or small. 0.0072 is less than 1, so it is small and the power must be negative. Ali used a positive power.0.0072 < 1
- Move the decimal point. To get 7.2 the point moves 3 places to the right.0.0072 → 7.2: 3 places right, so the power is −3
- Write the correct form. 7.2 × 10−3
Check. 7.2 × 103 = 7200, which is nothing like 0.0072. And 7.2 × 10−3 = 0.0072. ✓
Watch out. Small numbers have negative powers.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiplying by 10 adds 1 to the power.
- Write 10N. 10 × 4.5 × 106
- Combine the powers of 10. 101 × 106 = 107.= 4.5 × 101+6
- Write the answer. 4.5 × 107
Check. 4,500,000 × 10 = 45,000,000 = 4.5 × 107. ✓
Watch out. The front number does not change.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Dividing by 100 subtracts 2 from the power.
- Write the division. 100 = 102.4.5 × 106 ÷ 102
- Subtract the indices. 106 ÷ 102 = 106−2.= 4.5 × 104
- Write the answer. 4.5 × 104
Check. 4,500,000 ÷ 100 = 45,000 = 4.5 × 104. ✓
Watch out. Dividing by 100 lowers the power by 2.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write each option as an ordinary number and compare with 35,000.
- Work out 3.5 × 104. Move the decimal point 4 places right.3.5 × 104 = 35,000
- Check A, B and C. A is 35,000 already. B: 350 × 100 = 35,000. C: 0.35 × 100,000 = 35,000.A, B and C are all 35,000.
- Check D. A negative power gives a small number.3.5 × 10−4 = 0.00035
- Decide. D is not equal to 35,000.
Check. Only D is not 35,000. ✓
Watch out. Convert every option to an ordinary number.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Try the powers one at a time and see which give a number between 500 and 50,000.
- Try n = 1. 7.2 × 10 = 72, which is less than 500.72 < 500: too small
- Try n = 2. 7.2 × 100 = 720.720 is between 500 and 50,000 ✓
- Try n = 3 and n = 4. 7.2 × 1000 = 7200 and 7.2 × 10,000 = 72,000.7200 ✓ but 72,000 > 50,000 ✗
- Write the possible values. n = 2 or n = 3
Check. n = 2 gives 720 and n = 3 gives 7200: both are in the range. ✓
Watch out. Test the values in order and stop when the number gets too big.
Exercise 6J Standard form in context
Non-calculatorKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 1,392,000 is 1.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 1.392
- Count how many places the decimal point has moved. Starting from 1392000 the decimal point has to move 6 places to the left to sit after the 1. Each place moved is a factor of 10.1392000 → 1.392: 6 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 6
- Write the answer. Put A and the power of 10 together.1.392 × 106
Check. Convert back: 1.392 × 106 = 1392000 = 1,392,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.0000007 is 7.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 7
- Count how many places the decimal point has moved. Starting from 0.0000007 the decimal point has to move 7 places to the right to sit after the 7. Each place moved is a factor of 10.0.0000007 → 7: 7 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −7
- Write the answer. Put A and the power of 10 together.7 × 10−7
Check. Convert back: 7 × 10−7 = 0.0000007 = 0.0000007. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 67,000,000 is 6.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 6.7
- Count how many places the decimal point has moved. Starting from 67000000 the decimal point has to move 7 places to the left to sit after the 6. Each place moved is a factor of 10.67000000 → 6.7: 7 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 7
- Write the answer. Put A and the power of 10 together.6.7 × 107
Check. Convert back: 6.7 × 107 = 67000000 = 67,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00007 is 7.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 7
- Count how many places the decimal point has moved. Starting from 0.00007 the decimal point has to move 5 places to the right to sit after the 7. Each place moved is a factor of 10.0.00007 → 7: 5 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −5
- Write the answer. Put A and the power of 10 together.7 × 10−5
Check. Convert back: 7 × 10−5 = 0.00007 = 0.00007. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 40,000,000,000,000 is 4.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 4
- Count how many places the decimal point has moved. Starting from 40000000000000 the decimal point has to move 13 places to the left to sit after the 4. Each place moved is a factor of 10.40000000000000 → 4: 13 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 13
- Write the answer. Put A and the power of 10 together.4 × 1013
Check. Convert back: 4 × 1013 = 40000000000000 = 40,000,000,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 8, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.108 means multiply by 10, 8 times
- Move the decimal point 8 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.1.5 → 15 → 150 → 1500 → 15000 → 150000 → 1500000 → 15000000 → 150000000
- Write the answer. The last number in the chain is the answer.150,000,000
Check. Convert back to standard form: 150000000 has first non-zero digit 1, so A = 1.5 and n = 8. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −7, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−7 means divide by 10, 7 times
- Move the decimal point 7 places to the left. Move it one place at a time and fill the new places with zeros.1.2 → 0.12 → 0.012 → 0.0012 → 0.00012 → 0.000012 → 0.0000012 → 0.00000012
- Write the answer. The last number in the chain is the answer.0.00000012
Check. Convert back to standard form: 0.00000012 has first non-zero digit 1, so A = 1.2 and n = −7. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 9, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.109 means multiply by 10, 9 times
- Move the decimal point 9 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.3 → 30 → 300 → 3000 → 30000 → 300000 → 3000000 → 30000000 → 300000000 → 3000000000
- Write the answer. The last number in the chain is the answer.3,000,000,000
Check. Convert back to standard form: 3000000000 has first non-zero digit 3, so A = 3 and n = 9. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −9, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−9 means divide by 10, 9 times
- Move the decimal point 9 places to the left. Move it one place at a time and fill the new places with zeros.2.5 → 0.25 → 0.025 → 0.0025 → 0.00025 → 0.000025 → 0.0000025 → 0.00000025 → 0.000000025 → 0.0000000025
- Write the answer. The last number in the chain is the answer.0.0000000025
Check. Convert back to standard form: 0.0000000025 has first non-zero digit 2, so A = 2.5 and n = −9. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 85,000 is 8.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 8.5
- Count how many places the decimal point has moved. Starting from 85000 the decimal point has to move 4 places to the left to sit after the 8. Each place moved is a factor of 10.85000 → 8.5: 4 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 4
- Write the answer. Put A and the power of 10 together.8.5 × 104
Check. Convert back: 8.5 × 104 = 85000 = 85,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.0092 is 9.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 9.2
- Count how many places the decimal point has moved. Starting from 0.0092 the decimal point has to move 3 places to the right to sit after the 9. Each place moved is a factor of 10.0.0092 → 9.2: 3 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −3
- Write the answer. Put A and the power of 10 together.9.2 × 10−3
Check. Convert back: 9.2 × 10−3 = 0.0092 = 0.0092. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 630,000,000 is 6.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 6.3
- Count how many places the decimal point has moved. Starting from 630000000 the decimal point has to move 8 places to the left to sit after the 6. Each place moved is a factor of 10.630000000 → 6.3: 8 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 8
- Write the answer. Put A and the power of 10 together.6.3 × 108
Check. Convert back: 6.3 × 108 = 630000000 = 630,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 0.00000058 is 5.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 5.8
- Count how many places the decimal point has moved. Starting from 0.00000058 the decimal point has to move 7 places to the right to sit after the 5. Each place moved is a factor of 10.0.00000058 → 5.8: 7 places to the right
- Decide the sign of the power. The number is less than 1 (a small number). We made it bigger to get A, so we must divide by 10 to put the size back. Dividing by 10 is the same as multiplying by 10−1.n is negative: n = −7
- Write the answer. Put A and the power of 10 together.5.8 × 10−7
Check. Convert back: 5.8 × 10−7 = 0.00000058 = 0.00000058. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 1,200,000,000 is 1.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 1.2
- Count how many places the decimal point has moved. Starting from 1200000000 the decimal point has to move 9 places to the left to sit after the 1. Each place moved is a factor of 10.1200000000 → 1.2: 9 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 9
- Write the answer. Put A and the power of 10 together.1.2 × 109
Check. Convert back: 1.2 × 109 = 1200000000 = 1,200,000,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 4, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.104 means multiply by 10, 4 times
- Move the decimal point 4 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.6.3 → 63 → 630 → 6300 → 63000
- Write the answer. The last number in the chain is the answer.63,000
Check. Convert back to standard form: 63000 has first non-zero digit 6, so A = 6.3 and n = 4. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −3, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−3 means divide by 10, 3 times
- Move the decimal point 3 places to the left. Move it one place at a time and fill the new places with zeros.9 → 0.9 → 0.09 → 0.009
- Write the answer. The last number in the chain is the answer.0.009
Check. Convert back to standard form: 0.009 has first non-zero digit 9, so A = 9 and n = −3. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is 6, which is positive, so the number is big. Multiplying by 10 moves every digit one place to the left, which is the same as moving the decimal point one place to the right.106 means multiply by 10, 6 times
- Move the decimal point 6 places to the right. Move it one place at a time. If there are not enough digits, fill the gaps with zeros.1.07 → 10.7 → 107 → 1070 → 10700 → 107000 → 1070000
- Write the answer. The last number in the chain is the answer.1,070,000
Check. Convert back to standard form: 1070000 has first non-zero digit 1, so A = 1.07 and n = 6. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −2, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−2 means divide by 10, 2 times
- Move the decimal point 2 places to the left. Move it one place at a time and fill the new places with zeros.4.4 → 0.44 → 0.044
- Write the answer. The last number in the chain is the answer.0.044
Check. Convert back to standard form: 0.044 has first non-zero digit 4, so A = 4.4 and n = −2. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 32, which is 10 or more, so this is not in standard form.
- Write 32 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the left makes the number 10 times smaller, so we must multiply by 101 to keep the value the same.32 = 3.2 × 101
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.32 × 106 = 3.2 × 101 × 106
= 3.2 × 101 + 6 - Write the answer. 3.2 × 107
Check. Both forms are the same number, 32000000: 32 × 1000000 = 32000000 and 3.2 × 10000000 = 32000000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 0.45, which is less than 1, so this is not in standard form.
- Write 0.45 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the right makes the number 10 times bigger, so we must multiply by 10−1 (that is, divide by 10) to keep the value the same.0.45 = 4.5 × 10−1
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.0.45 × 103 = 4.5 × 10−1 × 103
= 4.5 × 10−1 + 3 - Write the answer. 4.5 × 102
Check. Both forms are the same number, 450: 0.45 × 1000 = 450 and 4.5 × 100 = 450. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 560, which is 10 or more, so this is not in standard form.
- Write 560 as a number between 1 and 10 times a power of 10. Moving the decimal point 2 places to the left makes the number 100 times smaller, so we must multiply by 102 to keep the value the same.560 = 5.6 × 102
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.560 × 10−5 = 5.6 × 102 × 10−5
= 5.6 × 102 + (−5) - Write the answer. 5.6 × 10−3
Check. Both forms are the same number, 0.0056: 560 × 0.00001 = 0.0056 and 5.6 × 0.001 = 0.0056. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 0.09, which is less than 1, so this is not in standard form.
- Write 0.09 as a number between 1 and 10 times a power of 10. Moving the decimal point 2 places to the right makes the number 100 times bigger, so we must multiply by 10−2 (that is, divide by 100) to keep the value the same.0.09 = 9 × 10−2
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.0.09 × 104 = 9 × 10−2 × 104
= 9 × 10−2 + 4 - Write the answer. 9 × 102
Check. Both forms are the same number, 900: 0.09 × 10000 = 900 and 9 × 100 = 900. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 50, which is 10 or more, so this is not in standard form.
- Write 50 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the left makes the number 10 times smaller, so we must multiply by 101 to keep the value the same.50 = 5 × 101
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.50 × 104 = 5 × 101 × 104
= 5 × 101 + 4 - Write the answer. 5 × 105
Check. Both forms are the same number, 500000: 50 × 10000 = 500000 and 5 × 100000 = 500000. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Change the front number A so that it is between 1 and 10, and adjust the power of 10 to match.
- Check the rule for standard form. In A × 10n, A must be at least 1 and less than 10.A = 25, which is 10 or more, so this is not in standard form.
- Write 25 as a number between 1 and 10 times a power of 10. Moving the decimal point 1 place to the left makes the number 10 times smaller, so we must multiply by 101 to keep the value the same.25 = 2.5 × 101
- Replace A in the original and combine the powers of 10. Powers of 10 multiply by adding the indices: 10a × 10b = 10a+b.25 × 10−7 = 2.5 × 101 × 10−7
= 2.5 × 101 + (−7) - Write the answer. 2.5 × 10−6
Check. Both forms are the same number, 0.0000025: 25 × 0.0000001 = 0.0000025 and 2.5 × 0.000001 = 0.0000025. ✓
Watch out. If you make A smaller by moving the point left, the power of 10 gets bigger by the same number of places (and the other way round).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the bigger number by the smaller one and use the division law.
- Write the division. “How many times bigger” means divide the bigger by the smaller.(3 × 105) ÷ (3 × 103)
- Divide the front numbers. 3 ÷ 3 = 1.1
- Divide the powers of 10. Subtract the indices.105 ÷ 103 = 102 = 100
- Conclude. 1 × 100 = 100, so it is 100 times bigger.
Check. 300,000 ÷ 3,000 = 100. ✓
Watch out. Each extra power of 10 makes the number 10 times bigger.
Comparing and calculating with standard form
Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page
Standard form makes big numbers easy to compare. Look at the powers of 10 first. A bigger power means a bigger number, because the front numbers are all between 1 and 10 and cannot make up the difference. So 3.2 × 105 is bigger than 9.9 × 104. If the powers are the same, compare the front numbers. Be careful with negative powers: −3 is bigger than −5, so 10−3 = 0.001 is bigger than 10−5 = 0.00001.
Multiplying. Multiply the front numbers, add the powers of 10 (law 1 of indices), then check that A is between 1 and 10. (2 × 103) × (3 × 104) = 6 × 107. If the front numbers multiply to 10 or more, adjust: (4 × 105) × (3 × 102) = 12 × 107 = 1.2 × 108.
Dividing. Divide the front numbers and subtract the powers. If A comes out less than 1, adjust: (3 × 105) ÷ (5 × 10−2) = 0.6 × 107 = 6 × 106.
Adding and subtracting. The powers of 10 must be the same first (like fractions needing a common denominator). 3.2 × 104 + 8.5 × 103 = 3.2 × 104 + 0.85 × 104 = 4.05 × 104.
With a calculator use the ×10x key (sometimes EXP), then write the answer in standard form to the accuracy asked for. Always estimate first by rounding each A to a whole number. In real problems decide which operation is needed, for example time = distance ÷ speed.
Higher tier: you may also need to find a power or a square root of a number in standard form: (2 × 103)3 = 23 × 109 = 8 × 109. Raise A to the power and multiply the index of 10 by the power.
Key ideas
- Compare the powers of 10 first, then the front numbers.
- Multiply: multiply the A values and add the powers. Divide: divide the A values and subtract the powers.
- Add or subtract: make the powers the same first.
- After any calculation check that A is at least 1 and less than 10; if not, adjust A and the power together.
- Calculator: use the ×10x key and check with an estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.3.2 and 9.9 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference.105 and 104: 5 > 4
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.3.2 × 105 > 9.9 × 104
Check. As ordinary numbers: 320000 and 99000, and 320000 is bigger than 99000. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Order by the power of 10 first; use the front number to break ties.
- List the power of 10 of each number. The power of 10 is the main thing that decides the size.2.5 × 104: power 4
7.1 × 10−3: power −3
2.1 × 104: power 4
9 × 103: power 3 - Order by the powers of 10. We need smallest to largest. Remember that −7 is smaller than −3.power −3, power 3, power 4, power 4
- If two numbers have the same power, compare their front numbers. With equal powers, the bigger front number is the bigger number.power 4: 2.5 and 2.1 → smaller first is 2.1
- Write the numbers in order. 7.1 × 10−3 , 9 × 103 , 2.1 × 104 , 2.5 × 104
Check. As ordinary numbers: 0.0071, 9000, 21000, 25000 — these increase along the list. ✓
Watch out. A negative power is smaller than a positive power, and a larger negative power (like −8) is smaller than −2.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(2.5 × 106) × (4 × 10−2) = (2.5 × 4) × (106 × 10−2)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.Ignore the decimal points: 25 × 4 = 100
There are 1 decimal place altogether in 2.5 and 4, so the answer has 1 decimal place: 2.5 × 4 = 10 - Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.106 × 10−2 = 106 + (−2) = 104
- Put the two parts together. 10 × 104
- Check: is the front number between 1 and 10? 10 is 10 or more, so this is not standard form yet. Write 10 = 1 × 10 and combine the powers of 10.10 × 104 = 1 × 10 × 104 = 1 × 104 + 1 = 1 × 105
- Write the answer. 1 × 105
Check. As ordinary numbers: 2500000 × 0.04 = 100000, which is 1 × 105. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(3 × 105) ÷ (5 × 10−2) = (3 ÷ 5) × (105 ÷ 10−2)
- Divide the front numbers. Do this like an ordinary decimal division.3 ÷ 5 = 0.6
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.105 ÷ 10−2 = 105 − (−2) = 107
- Put the two parts together. 0.6 × 107
- Check: is the front number between 1 and 10? 0.6 is less than 1, so this is not standard form yet. Write 0.6 = 6 × 10−1 and combine the powers of 10.0.6 × 107 = 6 × 10−1 × 107 = 6 × 10−1 + 7 = 6 × 106
- Write the answer. 6 × 106
Check. Multiply back: 6 × 5 = 30 and the powers give 106 × 10−2 = 104, so we get 30 × 104 = 300000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Add standard form numbers: give them the same power of 10, add the front numbers, then tidy the answer back into standard form.
- Make the powers of 10 the same. We can only add when the powers of 10 match, just as we can only add fractions with the same denominator. Change the number with the smaller power so that it uses 104. Each increase of 1 in the power means moving the decimal point of the front number one place to the left.8.5 × 103 = 0.85 × 104
- Add the front numbers. The power of 10 stays the same: it just tells us the size of the unit.3.2 + 0.85 = 4.05
so the result is 4.05 × 104 - Write the answer. 4.05 × 104
Check. As ordinary numbers: 32000 + 8500 = 40500, which is 4.05 × 104. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Decide what to do. The Sun is a long way from the Earth. We want a time. Time = distance ÷ speed, so divide the distance by the speed of light.time = (1.5 × 1011) ÷ (3 × 108)
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(1.5 × 1011) ÷ (3 × 108) = (1.5 ÷ 3) × (1011 ÷ 108)
- Divide the front numbers. Do this like an ordinary decimal division.Multiply both numbers by 10 to make them whole (the answer does not change): 1.5 ÷ 3 = 15 ÷ 30 = 0.5
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.1011 ÷ 108 = 1011 − 8 = 103
- Put the two parts together. 0.5 × 103
- Check: is the front number between 1 and 10? 0.5 is less than 1, so this is not standard form yet. Write 0.5 = 5 × 10−1 and combine the powers of 10.0.5 × 103 = 5 × 10−1 × 103 = 5 × 10−1 + 3 = 5 × 102
- Write the answer with its unit. 5 × 102 s
Check. Multiply back: 5 × 3 = 15 and the powers give 102 × 108 = 1010, so we get 15 × 1010 = 150000000000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 4.5 [×10x] 7 [×] 2.4 [×10x] [(−)] 3 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 1.08 × 105 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.1.08 × 105
Check. Estimate by rounding each front number to the nearest whole number: (5 × 107) × (2 × 10−3) ≈ 1 × 105, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Watch out
Do not add the powers when you add numbers: 3 × 104 + 2 × 103 is not 5 × 107. Make the powers match first. And after multiplying, check A: 12 × 107 is not in standard form.Exam tip
In calculator questions write down the calculation you typed, then the answer, then round. If a question says “in standard form” a plain decimal answer will lose marks.Exercise 6K Comparing and ordering standard form
Non-calculatorKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.3.2 and 9.9 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference.105 and 104: 5 > 4
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.3.2 × 105 > 9.9 × 104
Check. As ordinary numbers: 320000 and 99000, and 320000 is bigger than 99000. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.4.5 and 4.5 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference. For negative powers remember that −3 and −5 are numbers on a number line: the one further to the right is bigger. For example 10−2 = 0.01 is bigger than 10−5 = 0.00001.10−3 and 10−5: −3 > −5
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.4.5 × 10−3 > 4.5 × 10−5
Check. As ordinary numbers: 0.0045 and 0.000045, and 0.0045 is bigger than 0.000045. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.6.1 and 6.8 are both at least 1 and less than 10.
- Compare the powers of 10 first. If the powers are equal, the front numbers decide.Both powers are 107: they are the same.
- Compare the front numbers. With the same power of 10, the bigger A gives the bigger number.6.1 < 6.8, so 6.1 × 107 < 6.8 × 107
Check. As ordinary numbers: 61000000 and 68000000. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.2 and 9 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference. For negative powers remember that −6 and −7 are numbers on a number line: the one further to the right is bigger. For example 10−2 = 0.01 is bigger than 10−5 = 0.00001.10−6 and 10−7: −6 > −7
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.2 × 10−6 > 9 × 10−7
Check. As ordinary numbers: 0.000002 and 0.0000009, and 0.000002 is bigger than 0.0000009. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.1.2 and 9.9 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference.1010 and 109: 10 > 9
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.1.2 × 1010 > 9.9 × 109
Check. The power 10 is bigger than 9. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.7.5 and 2.1 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference.103 and 106: 3 < 6
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.7.5 × 103 < 2.1 × 106
Check. As ordinary numbers: 7500 and 2100000, and 7500 is smaller than 2100000. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.3.3 and 1.9 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference. For negative powers remember that −2 and −4 are numbers on a number line: the one further to the right is bigger. For example 10−2 = 0.01 is bigger than 10−5 = 0.00001.10−2 and 10−4: −2 > −4
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.3.3 × 10−2 > 1.9 × 10−4
Check. As ordinary numbers: 0.033 and 0.00019, and 0.033 is bigger than 0.00019. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.5.6 and 5.1 are both at least 1 and less than 10.
- Compare the powers of 10 first. If the powers are equal, the front numbers decide.Both powers are 108: they are the same.
- Compare the front numbers. With the same power of 10, the bigger A gives the bigger number.5.6 > 5.1, so 5.6 × 108 > 5.1 × 108
Check. As ordinary numbers: 560000000 and 510000000. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.9 and 1 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference. For negative powers remember that −5 and −4 are numbers on a number line: the one further to the right is bigger. For example 10−2 = 0.01 is bigger than 10−5 = 0.00001.10−5 and 10−4: −5 < −4
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.9 × 10−5 < 1 × 10−4
Check. As ordinary numbers: 0.00009 and 0.0001, and 0.00009 is smaller than 0.0001. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Order by the power of 10 first; use the front number to break ties.
- List the power of 10 of each number. The power of 10 is the main thing that decides the size.2.5 × 104: power 4
7.1 × 10−3: power −3
2.1 × 104: power 4
9 × 103: power 3 - Order by the powers of 10. We need smallest to largest. Remember that −7 is smaller than −3.power −3, power 3, power 4, power 4
- If two numbers have the same power, compare their front numbers. With equal powers, the bigger front number is the bigger number.power 4: 2.5 and 2.1 → smaller first is 2.1
- Write the numbers in order. 7.1 × 10−3 , 9 × 103 , 2.1 × 104 , 2.5 × 104
Check. As ordinary numbers: 0.0071, 9000, 21000, 25000 — these increase along the list. ✓
Watch out. A negative power is smaller than a positive power, and a larger negative power (like −8) is smaller than −2.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Order by the power of 10 first; use the front number to break ties.
- List the power of 10 of each number. The power of 10 is the main thing that decides the size.5.2 × 10−6: power −6
4.9 × 10−5: power −5
1.1 × 10−5: power −5
8 × 10−7: power −7 - Order by the powers of 10. We need smallest to largest. Remember that −7 is smaller than −3.power −7, power −6, power −5, power −5
- If two numbers have the same power, compare their front numbers. With equal powers, the bigger front number is the bigger number.power −5: 4.9 and 1.1 → smaller first is 1.1
- Write the numbers in order. 8 × 10−7 , 5.2 × 10−6 , 1.1 × 10−5 , 4.9 × 10−5
Check. As ordinary numbers: 0.0000008, 0.0000052, 0.000011, 0.000049 — these increase along the list. ✓
Watch out. A negative power is smaller than a positive power, and a larger negative power (like −8) is smaller than −2.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Order by the power of 10 first; use the front number to break ties.
- List the power of 10 of each number. The power of 10 is the main thing that decides the size.6 × 108: power 8
6 × 10−8: power −8
5.9 × 108: power 8
1 × 109: power 9 - Order by the powers of 10. We need largest to smallest. Remember that −7 is smaller than −3.power 9, power 8, power 8, power −8
- If two numbers have the same power, compare their front numbers. With equal powers, the bigger front number is the bigger number.power 8: 6 and 5.9 → bigger first is 6
- Write the numbers in order. 1 × 109 , 6 × 108 , 5.9 × 108 , 6 × 10−8
Watch out. A negative power is smaller than a positive power, and a larger negative power (like −8) is smaller than −2.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Order the distances (smallest first) using the powers of 10 and then the front numbers.
- List the powers of 10. Mercury has power 7; the other three all have power 8.Mercury 5.79 × 107: power 7
Venus 1.08 × 108, Earth 1.5 × 108, Mars 2.28 × 108: power 8 - Mercury is the smallest. The smallest power gives the smallest number.7 < 8
- Compare the front numbers of the other three. The powers match, so the front numbers decide.1.08 < 1.5 < 2.28
- Write the planets in order. Smallest distance first.Mercury, Venus, Earth, Mars
Check. As ordinary numbers: 57,900,000 < 108,000,000 < 150,000,000 < 228,000,000. ✓
Watch out. Compare powers first. Do not be misled by 5.79 being bigger than 1.08.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the two numbers: the smaller number is the smaller mass.
- Compare the powers of 10. The front numbers are both between 1 and 10, so the powers decide. With negative powers, the one further left on the number line is smaller.−31 < −27
- Decide. The electron has the smaller power, so it is the smaller number.9.11 × 10−31 < 1.67 × 10−27
- Write the answer. The electron has the smaller mass.
Check. 10−31 is a much smaller number than 10−27 (about 10,000 times smaller). ✓
Watch out. Do not compare 9.11 with 1.67 first.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write both numbers as ordinary numbers.
- Write 9.9 × 102 as an ordinary number. Move the decimal point 2 places right.9.9 × 102 = 990
- Write 1.1 × 105 as an ordinary number. Move the point 5 places right.1.1 × 105 = 110,000
- Compare. 990 < 110,000. The bigger power of 10 gives a number with more digits, so it wins.
Check. The power 5 is bigger than the power 2, so the second number is bigger. ✓
Watch out. Always compare the powers first.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. The number needs a power of 4 with a front number above 3, or a power of 5 with a front number below 3.
- Work out the limits as ordinary numbers. 3 × 104 = 30,000 and 3 × 105 = 300,000
- Choose a number in between. Try power 5 with a front number smaller than 3.1.2 × 105 = 120,000
- Check. 30,000 < 120,000 < 300,000 ✓
Check. Another correct answer is 5 × 104 = 50,000. ✓
Watch out. Many answers are correct. Check yours against both limits.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Convert both to ordinary numbers or compare the powers.
- Compare the powers. The front numbers are equal, so the powers decide. −3 is smaller than −2.−3 < −2
- Check with decimals. 5 × 10−3 = 0.005 and 5 × 10−2 = 0.05
- Decide. 0.005 is smaller than 0.05.False
Check. 0.005 × 10 = 0.05. ✓
Watch out. With negative powers, the bigger index is the bigger number.
Exercise 6L Calculating with standard form (no calculator)
Non-calculatorKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(2 × 103) × (3 × 104) = (2 × 3) × (103 × 104)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.2 × 3 = 6
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.103 × 104 = 103 + 4 = 107
- Put the two parts together. 6 × 107
- Write the answer. 6 × 107
Check. As ordinary numbers: 2000 × 30000 = 60000000, which is 6 × 107. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(4 × 105) × (2 × 10−2) = (4 × 2) × (105 × 10−2)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.4 × 2 = 8
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.105 × 10−2 = 105 + (−2) = 103
- Put the two parts together. 8 × 103
- Write the answer. 8 × 103
Check. As ordinary numbers: 400000 × 0.02 = 8000, which is 8 × 103. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(1.5 × 106) × (4 × 103) = (1.5 × 4) × (106 × 103)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.Ignore the decimal points: 15 × 4 = 60
There are 1 decimal place altogether in 1.5 and 4, so the answer has 1 decimal place: 1.5 × 4 = 6 - Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.106 × 103 = 106 + 3 = 109
- Put the two parts together. 6 × 109
- Write the answer. 6 × 109
Check. As ordinary numbers: 1500000 × 4000 = 6000000000, which is 6 × 109. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(2.5 × 10−3) × (4 × 10−2) = (2.5 × 4) × (10−3 × 10−2)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.Ignore the decimal points: 25 × 4 = 100
There are 1 decimal place altogether in 2.5 and 4, so the answer has 1 decimal place: 2.5 × 4 = 10 - Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.10−3 × 10−2 = 10−3 + (−2) = 10−5
- Put the two parts together. 10 × 10−5
- Check: is the front number between 1 and 10? 10 is 10 or more, so this is not standard form yet. Write 10 = 1 × 10 and combine the powers of 10.10 × 10−5 = 1 × 10 × 10−5 = 1 × 10-5 + 1 = 1 × 10−4
- Write the answer. 1 × 10−4
Check. As ordinary numbers: 0.0025 × 0.04 = 0.0001, which is 1 × 10−4. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(3 × 108) × (3 × 10−5) = (3 × 3) × (108 × 10−5)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.3 × 3 = 9
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.108 × 10−5 = 108 + (−5) = 103
- Put the two parts together. 9 × 103
- Write the answer. 9 × 103
Check. As ordinary numbers: 300000000 × 0.00003 = 9000, which is 9 × 103. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(8 × 109) ÷ (2 × 104) = (8 ÷ 2) × (109 ÷ 104)
- Divide the front numbers. Do this like an ordinary decimal division.8 ÷ 2 = 4
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.109 ÷ 104 = 109 − 4 = 105
- Put the two parts together. 4 × 105
- Write the answer. 4 × 105
Check. Multiply back: 4 × 2 = 8 and the powers give 105 × 104 = 109, so we get 8 × 109 = 8000000000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(6 × 107) ÷ (3 × 10−2) = (6 ÷ 3) × (107 ÷ 10−2)
- Divide the front numbers. Do this like an ordinary decimal division.6 ÷ 3 = 2
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.107 ÷ 10−2 = 107 − (−2) = 109
- Put the two parts together. 2 × 109
- Write the answer. 2 × 109
Check. Multiply back: 2 × 3 = 6 and the powers give 109 × 10−2 = 107, so we get 6 × 107 = 60000000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(9 × 105) ÷ (4 × 102) = (9 ÷ 4) × (105 ÷ 102)
- Divide the front numbers. Do this like an ordinary decimal division.9 ÷ 4 = 2.25
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.105 ÷ 102 = 105 − 2 = 103
- Put the two parts together. 2.25 × 103
- Write the answer. 2.25 × 103
Check. Multiply back: 2.25 × 4 = 9 and the powers give 103 × 102 = 105, so we get 9 × 105 = 900000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(3 × 105) ÷ (5 × 10−2) = (3 ÷ 5) × (105 ÷ 10−2)
- Divide the front numbers. Do this like an ordinary decimal division.3 ÷ 5 = 0.6
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.105 ÷ 10−2 = 105 − (−2) = 107
- Put the two parts together. 0.6 × 107
- Check: is the front number between 1 and 10? 0.6 is less than 1, so this is not standard form yet. Write 0.6 = 6 × 10−1 and combine the powers of 10.0.6 × 107 = 6 × 10−1 × 107 = 6 × 10−1 + 7 = 6 × 106
- Write the answer. 6 × 106
Check. Multiply back: 6 × 5 = 30 and the powers give 106 × 10−2 = 104, so we get 30 × 104 = 300000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(4.5 × 10−3) ÷ (1.5 × 102) = (4.5 ÷ 1.5) × (10−3 ÷ 102)
- Divide the front numbers. Do this like an ordinary decimal division.Multiply both numbers by 10 to make them whole (the answer does not change): 4.5 ÷ 1.5 = 45 ÷ 15 = 3
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.10−3 ÷ 102 = 10−3 − 2 = 10−5
- Put the two parts together. 3 × 10−5
- Write the answer. 3 × 10−5
Check. Multiply back: 3 × 1.5 = 4.5 and the powers give 10−5 × 102 = 10−3, so we get 4.5 × 10−3 = 0.0045, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(1.2 × 106) ÷ (4 × 10−2) = (1.2 ÷ 4) × (106 ÷ 10−2)
- Divide the front numbers. Do this like an ordinary decimal division.Multiply both numbers by 10 to make them whole (the answer does not change): 1.2 ÷ 4 = 12 ÷ 40 = 0.3
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.106 ÷ 10−2 = 106 − (−2) = 108
- Put the two parts together. 0.3 × 108
- Check: is the front number between 1 and 10? 0.3 is less than 1, so this is not standard form yet. Write 0.3 = 3 × 10−1 and combine the powers of 10.0.3 × 108 = 3 × 10−1 × 108 = 3 × 10−1 + 8 = 3 × 107
- Write the answer. 3 × 107
Check. Multiply back: 3 × 4 = 12 and the powers give 107 × 10−2 = 105, so we get 12 × 105 = 1200000, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Add standard form numbers: give them the same power of 10, add the front numbers, then tidy the answer back into standard form.
- Make the powers of 10 the same. We can only add when the powers of 10 match, just as we can only add fractions with the same denominator. Change the number with the smaller power so that it uses 104. Each increase of 1 in the power means moving the decimal point of the front number one place to the left.8.5 × 103 = 0.85 × 104
- Add the front numbers. The power of 10 stays the same: it just tells us the size of the unit.3.2 + 0.85 = 4.05
so the result is 4.05 × 104 - Write the answer. 4.05 × 104
Check. As ordinary numbers: 32000 + 8500 = 40500, which is 4.05 × 104. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Add standard form numbers: give them the same power of 10, add the front numbers, then tidy the answer back into standard form.
- Look at the powers of 10. Both numbers have the same power, 106, so the pieces are the same size and we can add the front numbers straight away. (It is like adding 3 lots of something and 5 lots of the same thing.)Both numbers are in units of 106.
- Add the front numbers. The power of 10 stays the same: it just tells us the size of the unit.5.2 + 4.1 = 9.3
so the result is 9.3 × 106 - Write the answer. 9.3 × 106
Check. As ordinary numbers: 5200000 + 4100000 = 9300000, which is 9.3 × 106. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Subtract standard form numbers: give them the same power of 10, subtract the front numbers, then tidy the answer back into standard form.
- Make the powers of 10 the same. We can only subtract when the powers of 10 match, just as we can only subtract fractions with the same denominator. Change the number with the smaller power so that it uses 105. Each increase of 1 in the power means moving the decimal point of the front number one place to the left.2.5 × 104 = 0.25 × 105
- Subtract the front numbers. The power of 10 stays the same: it just tells us the size of the unit.6 − 0.25 = 5.75
so the result is 5.75 × 105 - Write the answer. 5.75 × 105
Check. As ordinary numbers: 600000 − 25000 = 575000, which is 5.75 × 105. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Subtract standard form numbers: give them the same power of 10, subtract the front numbers, then tidy the answer back into standard form.
- Look at the powers of 10. Both numbers have the same power, 10−3, so the pieces are the same size and we can subtract the front numbers straight away. (It is like subtracting 3 lots of something and 5 lots of the same thing.)Both numbers are in units of 10−3.
- Subtract the front numbers. The power of 10 stays the same: it just tells us the size of the unit.7.2 − 3.1 = 4.1
so the result is 4.1 × 10−3 - Write the answer. 4.1 × 10−3
Check. As ordinary numbers: 0.0072 − 0.0031 = 0.0041, which is 4.1 × 10−3. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Add standard form numbers: give them the same power of 10, add the front numbers, then tidy the answer back into standard form.
- Make the powers of 10 the same. We can only add when the powers of 10 match, just as we can only add fractions with the same denominator. Change the number with the smaller power so that it uses 107. Each increase of 1 in the power means moving the decimal point of the front number one place to the left.7.5 × 106 = 0.75 × 107
- Add the front numbers. The power of 10 stays the same: it just tells us the size of the unit.9.5 + 0.75 = 10.25
so the result is 10.25 × 107 - Check: is the front number between 1 and 10? 10.25 is 10 or more, so write it with one non-zero digit before the decimal point and adjust the power.10.25 × 107 = 1.025 × 101 × 107 = 1.025 × 108
- Write the answer. 1.025 × 108
Check. As ordinary numbers: 95000000 + 7500000 = 102500000, which is 1.025 × 108. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Subtract standard form numbers: give them the same power of 10, subtract the front numbers, then tidy the answer back into standard form.
- Look at the powers of 10. Both numbers have the same power, 104, so the pieces are the same size and we can subtract the front numbers straight away. (It is like subtracting 3 lots of something and 5 lots of the same thing.)Both numbers are in units of 104.
- Subtract the front numbers. The power of 10 stays the same: it just tells us the size of the unit.5.2 − 4.9 = 0.3
so the result is 0.3 × 104 - Check: is the front number between 1 and 10? 0.3 is less than 1, so write it with one non-zero digit before the decimal point and adjust the power.0.3 × 104 = 3 × 10−1 × 104 = 3 × 103
- Write the answer. 3 × 103
Check. As ordinary numbers: 52000 − 49000 = 3000, which is 3 × 103. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Decide what to do. The area of a rectangle is length × width.area = (3 × 104) × (2 × 103)
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(3 × 104) × (2 × 103) = (3 × 2) × (104 × 103)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.3 × 2 = 6
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.104 × 103 = 104 + 3 = 107
- Put the two parts together. 6 × 107
- Write the answer with its unit. 6 × 107 m2
Check. As ordinary numbers: 30000 × 2000 = 60000000, which is 6 × 107. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Decide what to do. Pages per hour × number of hours gives the total number of pages.total = (4 × 103) × (5 × 102)
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(4 × 103) × (5 × 102) = (4 × 5) × (103 × 102)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.4 × 5 = 20
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.103 × 102 = 103 + 2 = 105
- Put the two parts together. 20 × 105
- Check: is the front number between 1 and 10? 20 is 10 or more, so this is not standard form yet. Write 20 = 2 × 10 and combine the powers of 10.20 × 105 = 2 × 10 × 105 = 2 × 105 + 1 = 2 × 106
- Write the answer with its unit. 2 × 106 pages
Check. As ordinary numbers: 4000 × 500 = 2000000, which is 2 × 106. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Divide the front numbers, subtract the powers of 10, then make sure the front number is between 1 and 10.
- Decide what to do. To find how many small masses fit into 1 kg, divide 1 kg by the mass of one grain. Write 1 in standard form as 1 × 100.number of grains = (1 × 100) ÷ (2.5 × 10−5)
- Write the division with the number parts together and the powers of 10 together. We can split the division into the front numbers and the powers of 10.(1 × 100) ÷ (2.5 × 10−5) = (1 ÷ 2.5) × (100 ÷ 10−5)
- Divide the front numbers. Do this like an ordinary decimal division.Multiply both numbers by 10 to make them whole (the answer does not change): 1 ÷ 2.5 = 10 ÷ 25 = 0.4
- Divide the powers of 10: subtract the indices. 10a ÷ 10b = 10a−b.100 ÷ 10−5 = 100 − (−5) = 105
- Put the two parts together. 0.4 × 105
- Check: is the front number between 1 and 10? 0.4 is less than 1, so this is not standard form yet. Write 0.4 = 4 × 10−1 and combine the powers of 10.0.4 × 105 = 4 × 10−1 × 105 = 4 × 10−1 + 5 = 4 × 104
- Write the answer with its unit. 4 × 104 grains
Check. Multiply back: 4 × 2.5 = 10 and the powers give 104 × 10−5 = 10−1, so we get 10 × 10−1 = 1, which is the number we started with. ✓
Watch out. Subtract the powers when you divide, and take care with negative powers: 4 − (−2) = 6. If the front number comes out less than 1, adjust it.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Decide what to do. Total water = number of people × water per person.total = (6 × 107) × (1.5 × 102)
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(6 × 107) × (1.5 × 102) = (6 × 1.5) × (107 × 102)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.Ignore the decimal points: 6 × 15 = 90
There are 1 decimal place altogether in 6 and 1.5, so the answer has 1 decimal place: 6 × 1.5 = 9 - Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.107 × 102 = 107 + 2 = 109
- Put the two parts together. 9 × 109
- Write the answer with its unit. 9 × 109 litres
Check. As ordinary numbers: 60000000 × 150 = 9000000000, which is 9 × 109. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Add standard form numbers: give them the same power of 10, add the front numbers, then tidy the answer back into standard form.
- Decide what to do. “Total” means add the two amounts.3.6 × 106 + 5.2 × 106
- Look at the powers of 10. Both numbers have the same power, 106, so the pieces are the same size and we can add the front numbers straight away. (It is like adding 3 lots of something and 5 lots of the same thing.)Both numbers are in units of 106.
- Add the front numbers. The power of 10 stays the same: it just tells us the size of the unit.3.6 + 5.2 = 8.8
so the result is 8.8 × 106 - Write the answer. 8.8 × 106
Check. As ordinary numbers: 3600000 + 5200000 = 8800000, which is 8.8 × 106. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Add standard form numbers: give them the same power of 10, add the front numbers, then tidy the answer back into standard form.
- Make the powers of 10 the same. We can only add when the powers of 10 match, just as we can only add fractions with the same denominator. Change the number with the smaller power so that it uses 104. Each increase of 1 in the power means moving the decimal point of the front number one place to the left.2 × 103 = 0.2 × 104
- Add the front numbers. The power of 10 stays the same: it just tells us the size of the unit.3 + 0.2 = 3.2
so the result is 3.2 × 104 - Write the answer. 3.2 × 104
Check. As ordinary numbers: 30000 + 2000 = 32000, which is 3.2 × 104. ✓
Watch out. You cannot just add the front numbers when the powers are different: 3 × 104 + 2 × 103 is not 5 × 107.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(2 × 103) × (5 × 104) = (2 × 5) × (103 × 104)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.2 × 5 = 10
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.103 × 104 = 103 + 4 = 107
- Put the two parts together. 10 × 107
- Check: is the front number between 1 and 10? 10 is 10 or more, so this is not standard form yet. Write 10 = 1 × 10 and combine the powers of 10.10 × 107 = 1 × 10 × 107 = 1 × 107 + 1 = 1 × 108
- Write the answer. 1 × 108
Check. As ordinary numbers: 2000 × 50000 = 100000000, which is 1 × 108. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Exercise 6M Calculator questions and context
Calculator allowedKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 4.5 [×10x] 7 [×] 2.4 [×10x] [(−)] 3 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 1.08 × 105 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.1.08 × 105
Check. Estimate by rounding each front number to the nearest whole number: (5 × 107) × (2 × 10−3) ≈ 1 × 105, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 5.97 [×10x] 24 ) [÷] ( 7.35 [×10x] 22 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 8.12244898 × 101 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.8.12 × 101
Check. Estimate by rounding each front number to the nearest whole number: (6 × 1024) ÷ (7 × 1022) ≈ 9 × 101, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 3.2 [×10x] 5 ) [×] ( 4.7 [×10x] [(−)] 2 ) [÷] ( 1.6 [×10x] 4 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 9.4 × 10−1 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.9.40 × 10−1
Check. Estimate by rounding each front number to the nearest whole number: (3 × 105) × (5 × 10−2) ÷ (2 × 104) ≈ 8 × 10−1, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 6.84 [×10x] 8 [+] 3.9 [×10x] 9 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 4.584 × 109 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.4.58 × 109
Check. Estimate by rounding each front number to the nearest whole number: (7 × 108) + (4 × 109) ≈ 5 × 109, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 2.7 [×10x] 4 ) [x2] [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 7.29 × 108 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.7.29 × 108
Check. Estimate by rounding each front number to the nearest whole number: (3 × 104)2 ≈ 9 × 108, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: [√] ( 8.1 [×10x] 7 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 9 × 103 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.9.00 × 103
Check. Estimate by rounding each front number to the nearest whole number: √(8 × 107) ≈ 9 × 103, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 9.2 [×10x] [(−)] 3 [−] 3.7 [×10x] [(−)] 4 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 8.83 × 10−3 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.8.83 × 10−3
Check. Estimate by rounding each front number to the nearest whole number: (9 × 10−3) − (4 × 10−4) ≈ 9 × 10−3, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. Time = distance ÷ speed.time = (1.496 × 1011) ÷ (3 × 108)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 1.496 [×10x] 11 ) [÷] ( 3 [×10x] 8 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 4.98666667 × 102 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.4.99 × 102 s
Check. Estimate by rounding each front number to the nearest whole number: (1 × 1011) ÷ (3 × 108) ≈ 3 × 102, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. “How many times heavier” means divide the bigger mass by the smaller mass.Earth ÷ Moon = (5.97 × 1024) ÷ (7.35 × 1022)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 5.97 [×10x] 24 ) [÷] ( 7.35 [×10x] 22 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 8.12244898 × 101 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.8.12 × 101
Check. Estimate by rounding each front number to the nearest whole number: (6 × 1024) ÷ (7 × 1022) ≈ 9 × 101, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. Population density = population ÷ area.density = (6.7 × 107) ÷ (2.4 × 105)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 6.7 [×10x] 7 ) [÷] ( 2.4 [×10x] 5 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 2.79166667 × 102 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.2.79 × 102 people per km2
Check. Estimate by rounding each front number to the nearest whole number: (7 × 107) ÷ (2 × 105) ≈ 4 × 102, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. The number of photos is the total bytes divided by the bytes per photo.photos = (2 × 1012) ÷ (3.5 × 106)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 2 [×10x] 12 ) [÷] ( 3.5 [×10x] 6 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 5.71428571 × 105 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.5.71 × 105 photos
Check. Estimate by rounding each front number to the nearest whole number: (2 × 1012) ÷ (4 × 106) ≈ 5 × 105, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. Atoms = number of moles × atoms per mole. Write 3.5 as 3.5 × 100.atoms = (3.5 × 100) × (6.02 × 1023)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 3.5 [×10x] 0 [×] 6.02 [×10x] 23 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 2.107 × 1024 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.2.11 × 1024 atoms
Check. Estimate by rounding each front number to the nearest whole number: (4 × 100) × (6 × 1023) ≈ 2 × 1024, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. “How much bigger” means subtract the smaller diameter from the larger.difference = (1.43 × 105) − (1.27 × 104)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 1.43 [×10x] 5 [−] 1.27 [×10x] 4 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 1.303 × 105 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.1.30 × 105 km
Check. Estimate by rounding each front number to the nearest whole number: (1 × 105) − (1 × 104) ≈ 9 × 104, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. Distance in km = number of light-years × km in one light-year.distance = (2.5 × 106) × (9.46 × 1012)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: 2.5 [×10x] 6 [×] 9.46 [×10x] 12 [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 2.365 × 1019 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.2.37 × 1019 km
Check. Estimate by rounding each front number to the nearest whole number: (3 × 106) × (9 × 1012) ≈ 3 × 1019, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Round each front number to the nearest whole number, then multiply as normal.
- Round the front numbers. 3.9 rounds to 4 and 2.1 rounds to 2.(4 × 105) × (2 × 10−2)
- Multiply the front numbers. 4 × 2 = 8
- Add the powers. 5 + (−2) = 3, so 103
- Write the estimate. 8 × 103
Check. The exact value is 3.9 × 2.1 = 8.19, so 8190, which is very close to 8000. ✓
Watch out. An estimate checks your calculator answer is the right size.
Exact answers with π
Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page
The number π (pi) is the circumference of any circle divided by its diameter. Its decimal never ends and never repeats: 3.14159265…. Because it cannot be written exactly as a decimal or fraction, any answer found with a rounded value of π is only approximate. If you want an exact answer you leave π as the symbol π. Questions say “give your answer in terms of π” or “leave your answer as a multiple of π”.
Remember the formulae: circumference C = πd = 2πr and area A = πr2 (more on circles in Chapter 18). Square only the radius, then write the number first and π after it: 36π, not π36. Treat π like a letter in algebra. 3π + 5π = 8π (like 3x + 5x = 8x), 4 × 3π = 12π, and 12π ÷ 4 = 3π.
Parts of circles use fractions: a semicircle is half and a quarter circle is one quarter. Take the fraction of the exact answer: a quarter of 64π is 16π. For a perimeter, the curved part is a fraction of the circumference and the straight edges are ordinary lengths, so the answer has two terms, such as (5π + 10) cm. Compound shapes: find each area exactly and add. If you need a decimal at the end, use the π button on your calculator and round at the very end.
Key ideas
- Exact answer: leave π in the answer, with the number in front: 36π.
- C = πd = 2πr and A = πr2. Use the radius for the area (half the diameter).
- Treat π like a letter: 3π + 5π = 8π.
- A fraction of a circle: take that fraction of the exact area (or circumference).
- Only use the π button, and round, when you want a decimal.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 62
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.62 = 6 × 6 = 36
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.36π cm2
Check. Use the π button to get a decimal and compare: 36π = 113.097 to 3 decimal places, so about 113.1 cm2 to 1 d.p. This is similar in size to 113.04 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Find the radius. The radius is half of the diameter.radius = 10 ÷ 2 = 5 cm
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 5 = 10 cm
C = π × 10 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.10π cm
Check. Use the π button to get a decimal and compare: 10π = 31.416 to 3 decimal places, so about 31.4 cm to 1 d.p. This is similar in size to 31.4 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. It is a number, but we do not write it as a decimal. So 3π + 5π works just like 3x + 5x = 8x: 3 lots of π and 5 lots of π make 8 lots of π.3π + 5π
- Add the numbers in front of π. The number in front tells us how many lots of π there are.3 + 5 = 8
- Write the answer with π. 8π
Check. Use 3.14 for π as a rough check: 3 lots of 3.14 and the answer 8 lots of 3.14 = 25.12, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Find the area of the whole circle, then take the fraction of it that the shape is. Leave π in the answer.
- Write the area of the whole circle. A = πr2.A = π × 82 = 64π cm2
- Take the fraction of it. The shape is a quarter of the circle, so multiply by 14.14 × 64π = 16π
- Write the answer with units. 16π cm2
Check. As a decimal this is about 50.3 cm2, which is less than the whole circle (201.1 cm2). ✓
Watch out. Use the radius. If you are given the diameter, halve it first.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Add the curved length (a fraction of the circumference) to the straight edges. Leave π in the answer.
- Split the perimeter into the curved part and the straight part(s). The perimeter is the distance all the way round the shape. A semicircle has one curved edge and straight edges.perimeter = curved edge + straight edge(s)
- Find the length of the curved edge. The curved edge is half of the circumference of the full circle.half of 2πr = πr = π × 5 = 5π cm
- Find the length of the straight edge(s). the diameter = 2 × 5 = 10 cm
- Add them. Leave π in the answer. A multiple of π and a whole number cannot be combined into one term, so the answer has two parts.(5π + 10) cm
Check. As a decimal: 15.71 + 10 = 25.71 cm (about). This is a sensible length for a shape with radius 5 cm. ✓
Watch out. Do not forget the straight edge(s). The perimeter of a semicircle is more than half the circumference of the circle.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Split into a rectangle and a semicircle, find each area exactly, then add.
- Split the shape into a rectangle and a semicircle. It is easier to find the areas of simple shapes and add them.area = rectangle + semicircle
- Find the area of the rectangle. area = length × width8 × 5 = 40 cm2
- Find the radius of the semicircle. The diameter of the semicircle is the width of the rectangle. The radius is half the diameter.radius = 8 ÷ 2 = 4 cm
- Find the area of the semicircle. A semicircle is half a circle: half of πr2.12 × π × 42 = 12 × π × 16 = 8π cm2
- Add the two areas. Leave π in the answer. The whole numbers and the π part cannot be combined into one term.(40 + 8π) cm2
Check. As a decimal: 40 + 25.13 = 65.13 cm2 (about). The rectangle alone is 40 cm2, so this is a little bigger. ✓
Watch out. Use the radius (half the width) in the circle formula, not the whole width.
Watch out
Do not replace π by 3.14 in an exact answer, and do not square the π. Area is π × (radius)2: for radius 6 it is 36π, not 6π. And use the radius: if you are given the diameter, halve it first.Exercise 6N Exact answers with π
Non-calculatorKey words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 32
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.32 = 3 × 3 = 9
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.9π cm2
Check. Use the π button to get a decimal and compare: 9π = 28.274 to 3 decimal places, so about 28.3 cm2 to 1 d.p. This is similar in size to 28.26 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 52
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.52 = 5 × 5 = 25
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.25π cm2
Check. Use the π button to get a decimal and compare: 25π = 78.54 to 3 decimal places, so about 78.5 cm2 to 1 d.p. This is similar in size to 78.5 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 62
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.62 = 6 × 6 = 36
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.36π cm2
Check. Use the π button to get a decimal and compare: 36π = 113.097 to 3 decimal places, so about 113.1 cm2 to 1 d.p. This is similar in size to 113.04 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 102
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.102 = 10 × 10 = 100
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.100π cm2
Check. Use the π button to get a decimal and compare: 100π = 314.159 to 3 decimal places, so about 314.2 cm2 to 1 d.p. This is similar in size to 314 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Find the radius. The radius is half of the diameter.radius = 8 ÷ 2 = 4 cm
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 4 = 8 cm
C = π × 8 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.8π cm
Check. Use the π button to get a decimal and compare: 8π = 25.133 to 3 decimal places, so about 25.1 cm to 1 d.p. This is similar in size to 25.12 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Find the radius. The radius is half of the diameter.radius = 10 ÷ 2 = 5 cm
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 5 = 10 cm
C = π × 10 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.10π cm
Check. Use the π button to get a decimal and compare: 10π = 31.416 to 3 decimal places, so about 31.4 cm to 1 d.p. This is similar in size to 31.4 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Find the radius. The radius is half of the diameter.radius = 14 ÷ 2 = 7 cm
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 7 = 14 cm
C = π × 14 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.14π cm
Check. Use the π button to get a decimal and compare: 14π = 43.982 to 3 decimal places, so about 44 cm to 1 d.p. This is similar in size to 43.96 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Find the radius. The radius is half of the diameter.radius = 20 ÷ 2 = 10 cm
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 10 = 20 cm
C = π × 20 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.20π cm
Check. Use the π button to get a decimal and compare: 20π = 62.832 to 3 decimal places, so about 62.8 cm to 1 d.p. This is similar in size to 62.8 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 4 = 8 cm
C = π × 8 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.8π cm
Check. Use the π button to get a decimal and compare: 8π = 25.133 to 3 decimal places, so about 25.1 cm to 1 d.p. This is similar in size to 25.12 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 7 = 14 cm
C = π × 14 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.14π cm
Check. Use the π button to get a decimal and compare: 14π = 43.982 to 3 decimal places, so about 44 cm to 1 d.p. This is similar in size to 43.96 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the circumference. The circumference is the distance around the circle: π times the diameter, which is also 2 × π × radius.C = πd or C = 2πr
- Substitute. Use the diameter, which is double the radius. Leave π as the symbol.d = 2 × 9 = 18 cm
C = π × 18 - Write the number in front of π. Write the exact answer with the number first and then π, and add the units.18π cm
Check. Use the π button to get a decimal and compare: 18π = 56.549 to 3 decimal places, so about 56.5 cm to 1 d.p. This is similar in size to 56.52 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. It is a number, but we do not write it as a decimal. So 3π + 5π works just like 3x + 5x = 8x: 3 lots of π and 5 lots of π make 8 lots of π.3π + 5π
- Add the numbers in front of π. The number in front tells us how many lots of π there are.3 + 5 = 8
- Write the answer with π. 8π
Check. Use 3.14 for π as a rough check: 3 lots of 3.14 and the answer 8 lots of 3.14 = 25.12, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. It is a number, but we do not write it as a decimal. So 3π + 5π works just like 3x + 5x = 8x: 3 lots of π and 5 lots of π make 8 lots of π.9π − 4π
- Subtract the numbers in front of π. The number in front tells us how many lots of π there are.9 − 4 = 5
- Write the answer with π. 5π
Check. Use 3.14 for π as a rough check: 9 lots of 3.14 and the answer 5 lots of 3.14 = 15.7, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. It is a number, but we do not write it as a decimal. So 3π + 5π works just like 3x + 5x = 8x: 3 lots of π and 5 lots of π make 8 lots of π.12π − π
- Subtract the numbers in front of π. The number in front tells us how many lots of π there are.12 − 1 = 11
- Write the answer with π. 11π
Check. Use 3.14 for π as a rough check: 12 lots of 3.14 and the answer 11 lots of 3.14 = 34.54, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. It is a number, but we do not write it as a decimal. So 3π + 5π works just like 3x + 5x = 8x: 3 lots of π and 5 lots of π make 8 lots of π.7π + 2π
- Add the numbers in front of π. The number in front tells us how many lots of π there are.7 + 2 = 9
- Write the answer with π. 9π
Check. Use 3.14 for π as a rough check: 7 lots of 3.14 and the answer 9 lots of 3.14 = 28.26, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. 3π × 4 works like 3x × 4 = 12x. Multiply the numbers; π stays where it is.4π × 3
- Multiply the numbers. Do not turn π into 3.14.4 × 3 = 12
- Write the answer with π. 12π
Check. Use 3.14 for π as a rough check: 4 lots of 3.14 and the answer 12 lots of 3.14 = 37.68, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. 3π × 4 works like 3x × 4 = 12x. Multiply the numbers; π stays where it is.34π × 8
- Multiply the numbers. Do not turn π into 3.14.34 × 8 = 6
- Write the answer with π. 6π
Check. Use 3.14 for π as a rough check: 34 lots of 3.14 and the answer 6 lots of 3.14 = 18.84, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. 3π × 4 works like 3x × 4 = 12x. Multiply the numbers; π stays where it is.5π × 6
- Multiply the numbers. Do not turn π into 3.14.5 × 6 = 30
- Write the answer with π. 30π
Check. Use 3.14 for π as a rough check: 5 lots of 3.14 and the answer 30 lots of 3.14 = 94.2, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. 12π ÷ 4 works like 12x ÷ 4 = 3x. Divide the number in front; π stays where it is.6π ÷ 2
- Divide the numbers. 6 ÷ 2 = 3
- Write the answer with π. 3π
Check. Use 3.14 for π as a rough check: 6 lots of 3.14 and the answer 3 lots of 3.14 = 9.42, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Treat π as if it were a letter. Work with the numbers in front of it and keep π in the answer.
- Treat π like a letter in algebra. 12π ÷ 4 works like 12x ÷ 4 = 3x. Divide the number in front; π stays where it is.10π ÷ 4
- Divide the numbers. 10 ÷ 4 = 52
- Write the answer with π. 52π
Check. Use 3.14 for π as a rough check: 10 lots of 3.14 and the answer 52 lots of 3.14 = 7.85, which has the right size. ✓
Watch out. π does not change when you add or subtract numbers in front of it. 3π + 5π = 8π, not 8π2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Type the exact answer into the calculator using the π key and round as asked.
- Use the π button on the calculator. The π button holds π to many more digits than 3.14, so the answer will be more accurate.36π = 113.097336… (calculator display)
- Round to 1 decimal place. Look at the next digit after decimal place 1: 5 or more rounds up.113.1 cm2
Check. Rough check with 3: 36 × 3 = 108, which is a little below 113.1. ✓
Watch out. Round only at the very end.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Type the exact answer into the calculator using the π key and round as asked.
- Use the π button on the calculator. The π button holds π to many more digits than 3.14, so the answer will be more accurate.10π = 31.415927… (calculator display)
- Round to 1 decimal place. Look at the next digit after decimal place 1: 5 or more rounds up.31.4 cm
Check. Rough check with 3: 10 × 3 = 30, which is a little below 31.4. ✓
Watch out. Round only at the very end.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Type the exact answer into the calculator using the π key and round as asked.
- Use the π button on the calculator. The π button holds π to many more digits than 3.14, so the answer will be more accurate.25π = 78.539816… (calculator display)
- Round to 2 decimal places. Look at the next digit after decimal place 2: 5 or more rounds up.78.54 m2
Check. Rough check with 3: 25 × 3 = 75, which is a little below 78.54. ✓
Watch out. Round only at the very end.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Find the area of the whole circle, then take the fraction of it that the shape is. Leave π in the answer.
- Write the area of the whole circle. A = πr2.A = π × 82 = 64π cm2
- Take the fraction of it. The shape is a quarter of the circle, so multiply by 14.14 × 64π = 16π
- Write the answer with units. 16π cm2
Check. As a decimal this is about 50.3 cm2, which is less than the whole circle (201.1 cm2). ✓
Watch out. Use the radius. If you are given the diameter, halve it first.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Find the area of the whole circle, then take the fraction of it that the shape is. Leave π in the answer.
- Write the area of the whole circle. A = πr2.A = π × 102 = 100π cm2
- Take the fraction of it. The shape is a quarter of the circle, so multiply by 14.14 × 100π = 25π
- Write the answer with units. 25π cm2
Check. As a decimal this is about 78.5 cm2, which is less than the whole circle (314.2 cm2). ✓
Watch out. Use the radius. If you are given the diameter, halve it first.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Find the area of the whole circle, then take the fraction of it that the shape is. Leave π in the answer.
- Write the area of the whole circle. A = πr2.A = π × 62 = 36π cm2
- Take the fraction of it. The shape is a half of the circle, so multiply by 12.12 × 36π = 18π
- Write the answer with units. 18π cm2
Check. As a decimal this is about 56.5 cm2, which is less than the whole circle (113.1 cm2). ✓
Watch out. Use the radius. If you are given the diameter, halve it first.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Find the area of the whole circle, then take the fraction of it that the shape is. Leave π in the answer.
- Write the area of the whole circle. A = πr2.A = π × 42 = 16π cm2
- Take the fraction of it. The shape is a half of the circle, so multiply by 12.12 × 16π = 8π
- Write the answer with units. 8π cm2
Check. As a decimal this is about 25.1 cm2, which is less than the whole circle (50.3 cm2). ✓
Watch out. Use the radius. If you are given the diameter, halve it first.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Add the curved length (a fraction of the circumference) to the straight edges. Leave π in the answer.
- Split the perimeter into the curved part and the straight part(s). The perimeter is the distance all the way round the shape. A semicircle has one curved edge and straight edges.perimeter = curved edge + straight edge(s)
- Find the length of the curved edge. The curved edge is half of the circumference of the full circle.half of 2πr = πr = π × 5 = 5π cm
- Find the length of the straight edge(s). the diameter = 2 × 5 = 10 cm
- Add them. Leave π in the answer. A multiple of π and a whole number cannot be combined into one term, so the answer has two parts.(5π + 10) cm
Check. As a decimal: 15.71 + 10 = 25.71 cm (about). This is a sensible length for a shape with radius 5 cm. ✓
Watch out. Do not forget the straight edge(s). The perimeter of a semicircle is more than half the circumference of the circle.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Add the curved length (a fraction of the circumference) to the straight edges. Leave π in the answer.
- Split the perimeter into the curved part and the straight part(s). The perimeter is the distance all the way round the shape. A semicircle has one curved edge and straight edges.perimeter = curved edge + straight edge(s)
- Find the length of the curved edge. The curved edge is half of the circumference of the full circle.half of 2πr = πr = π × 6 = 6π cm
- Find the length of the straight edge(s). the diameter = 2 × 6 = 12 cm
- Add them. Leave π in the answer. A multiple of π and a whole number cannot be combined into one term, so the answer has two parts.(6π + 12) cm
Check. As a decimal: 18.85 + 12 = 30.85 cm (about). This is a sensible length for a shape with radius 6 cm. ✓
Watch out. Do not forget the straight edge(s). The perimeter of a semicircle is more than half the circumference of the circle.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Add the curved length (a fraction of the circumference) to the straight edges. Leave π in the answer.
- Split the perimeter into the curved part and the straight part(s). The perimeter is the distance all the way round the shape. A quarter circle has one curved edge and straight edges.perimeter = curved edge + straight edge(s)
- Find the length of the curved edge. The curved edge is a quarter of the circumference of the full circle.a quarter of 2πr = πr ÷ 2 = π × 8 ÷ 2 = 4π cm
- Find the length of the straight edge(s). two radii = 2 × 8 = 16 cm
- Add them. Leave π in the answer. A multiple of π and a whole number cannot be combined into one term, so the answer has two parts.(4π + 16) cm
Check. As a decimal: 12.57 + 16 = 28.57 cm (about). This is a sensible length for a shape with radius 8 cm. ✓
Watch out. Do not forget the straight edge(s). The perimeter of a semicircle is more than half the circumference of the circle.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Split into a rectangle and a semicircle, find each area exactly, then add.
- Split the shape into a rectangle and a semicircle. It is easier to find the areas of simple shapes and add them.area = rectangle + semicircle
- Find the area of the rectangle. area = length × width8 × 5 = 40 cm2
- Find the radius of the semicircle. The diameter of the semicircle is the width of the rectangle. The radius is half the diameter.radius = 8 ÷ 2 = 4 cm
- Find the area of the semicircle. A semicircle is half a circle: half of πr2.12 × π × 42 = 12 × π × 16 = 8π cm2
- Add the two areas. Leave π in the answer. The whole numbers and the π part cannot be combined into one term.(40 + 8π) cm2
Check. As a decimal: 40 + 25.13 = 65.13 cm2 (about). The rectangle alone is 40 cm2, so this is a little bigger. ✓
Watch out. Use the radius (half the width) in the circle formula, not the whole width.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Split into a rectangle and a semicircle, find each area exactly, then add.
- Split the shape into a rectangle and a semicircle. It is easier to find the areas of simple shapes and add them.area = rectangle + semicircle
- Find the area of the rectangle. area = length × width12 × 7 = 84 cm2
- Find the radius of the semicircle. The diameter of the semicircle is the width of the rectangle. The radius is half the diameter.radius = 12 ÷ 2 = 6 cm
- Find the area of the semicircle. A semicircle is half a circle: half of πr2.12 × π × 62 = 12 × π × 36 = 18π cm2
- Add the two areas. Leave π in the answer. The whole numbers and the π part cannot be combined into one term.(84 + 18π) cm2
Check. As a decimal: 84 + 56.55 = 140.55 cm2 (about). The rectangle alone is 84 cm2, so this is a little bigger. ✓
Watch out. Use the radius (half the width) in the circle formula, not the whole width.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Use V = πr2h and leave π in the answer.
- Write the formula for the volume of a cylinder. The base is a circle of area πr2, and the cylinder is that area repeated for the height.V = πr2h
- Substitute the radius and the height. Leave π as the symbol.V = π × 32 × 10
- Work out the numbers (square the radius first). Powers come before multiplication.32 = 9
9 × 10 = 90 - Write the exact answer with units. 90π cm3
Check. As a decimal: 282.7 cm3 (about). ✓
Watch out. Square only the radius, and use the radius, not the diameter.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Use the area formula backwards: divide by π, then take the square root.
- Write the formula for the area. A = πr2
- Put in the area and divide both sides by π. The area is 49π cm2. Dividing both sides by π leaves the number.49π = πr2, so r2 = 49
- Take the square root. 49 = 7 × 7.r = √49 = 7 cm
Check. Put it back: π × 72 = 49π. ✓
Watch out. Do not forget to take the square root at the end.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Use the area formula backwards: divide by π, then take the square root.
- Write the formula for the area. A = πr2
- Put in the area and divide both sides by π. The area is 100π cm2. Dividing both sides by π leaves the number.100π = πr2, so r2 = 100
- Take the square root. 100 = 10 × 10.r = √100 = 10 cm
Check. Put it back: π × 102 = 100π. ✓
Watch out. Do not forget to take the square root at the end.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Use the circumference formula backwards: divide by 2π.
- Write the formula for the circumference. C = 2πr
- Put in the circumference and divide by 2π. The circumference is 14π cm. Divide both sides by 2π.14π = 2πr, so r = 14 ÷ 2 = 7 cm
Check. Put it back: 2 × π × 7 = 14π. ✓
Watch out. C = 2πr, so r is half of the number in front of π.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Use the circumference formula backwards: divide by 2π.
- Write the formula for the circumference. C = 2πr
- Put in the circumference and divide by 2π. The circumference is 30π cm. Divide both sides by 2π.30π = 2πr, so r = 30 ÷ 2 = 15 cm
Check. Put it back: 2 × π × 15 = 30π. ✓
Watch out. C = 2πr, so r is half of the number in front of π.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. The track is the big circle with the small circle removed. Subtract the areas.
- Area of the outer circle. A = πr2 with r = 10.π × 102 = 100π
- Area of the inner circle. With r = 6.π × 62 = 36π
- Subtract. The track is the difference. Treat π like a letter.100π − 36π = 64π m2
Check. As a decimal: 64π = 201.06… m2; and 314.16 − 113.10 = 201.06. ✓
Watch out. Do not subtract the radii first: (10 − 6)2π = 16π is wrong.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Work out 22/7 as a decimal and compare it with π.
- Work out 22 ÷ 7. Use short division.22 ÷ 7 = 3.142857…
- Write π to the same accuracy. Use the π button.π = 3.141592…
- Compare. They differ from the third decimal place.3.142857 ≠ 3.141592
- Conclude. π is irrational: its decimal never ends or repeats, so it is not equal to any fraction.22/7 is only an approximation.
Check. Using 22/7: a circle of radius 7 would have area 154. Using π: 49π = 153.94. Close but not equal. ✓
Watch out. 22/7 is a useful estimate, not an exact value.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 62
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.62 = 6 × 6 = 36
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.36π cm2
Check. Use the π button to get a decimal and compare: 36π = 113.097 to 3 decimal places, so about 113.1 cm2 to 1 d.p. This is similar in size to 113.04 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Find the radius, then half the area of the full circle.
- Find the radius. The radius is half the diameter.10 ÷ 2 = 5 cm
- Area of the full circle. A = πr2.π × 52 = 25π
- Take half. A semicircle is half a circle.25π ÷ 2 = 12.5π
- Write the conclusion. The area is 12.5π cm2.
Check. 12.5 × 2 = 25, so two semicircles make 25π. ✓
Watch out. Half of 25 is 12.5.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Work out both areas exactly and divide.
- Area of A. π × 22.A = 4π cm2
- Area of B. π × 62.B = 36π cm2
- Divide B by A. The π cancels.36π ÷ 4π = 9
- Conclude. Tripling the radius multiplies the area by 32 = 9.B is 9 times as big as A.
Check. 6 ÷ 2 = 3 and 32 = 9. ✓
Watch out. When the radius is multiplied by k, the area is multiplied by k2.
Chapter summary
| Skill | Method |
|---|---|
| Index laws (same base) | Multiply: add indices. Divide: subtract indices. Power of a power: multiply indices. a1 = a. |
| Zero and negative indices | a0 = 1. a−n = 1/an. For fractions, flip the fraction and make the index positive. |
| Indices with letters | Deal with the number and each letter separately. (2a3)4 = 16a12. |
| Roots | √a: number that multiplies by itself to give a. Between two whole numbers: use the perfect squares or cubes on either side. x2 = k has two solutions. |
| Fractional indices (Higher) | am/n = (n-th root of a)m. Do the root first. Negative: reciprocal first. Solve xp/q = k by raising to the power q/p. |
| Standard form | A × 10n with 1 ≤ A < 10. Big number: positive n. Number less than 1: negative n. Count the places the decimal point moves. |
| Calculating in standard form | Multiply: multiply the A values, add the powers. Divide: divide the A values, subtract the powers. Add or subtract: make the powers match. Then tidy so that 1 ≤ A < 10. |
| Comparing standard form | Compare the powers of 10 first; if equal compare the front numbers. |
| Exact answers with π | Leave π in the answer: area 36π. Treat π like a letter. Use the radius for area. |
| Simplifying surds (Higher) | √a × √b = √(ab). Use the largest square factor: √12 = 2√3. Add or subtract only like surds. |
| Expanding with surds (Higher) | Every term × every term. √a × √a = a. (a + √b)(a − √b) = a2 − b. |
| Rationalising (Higher) | k/(c√n): multiply top and bottom by √n. k/(a + √b): multiply top and bottom by the conjugate (a − √b). |
Can you…?
- I can write numbers using index notation and use the three index laws with numbers and letters.
- I know that a0 = 1 and that a negative index means “one over”.
- I can work out roots, place a root between two whole numbers, and use a calculator for powers and roots.
- I can write any large or small number in standard form and convert back.
- I can compare, order and calculate with numbers in standard form, with and without a calculator.
- I can give exact answers for circle questions in terms of π.
- (Higher) I can work with fractional indices and solve index equations.
- (Higher) I can simplify, add, multiply and expand surds.
- (Higher) I can rationalise a denominator, including using the conjugate.
Key terms
- Base
- The number that is multiplied in a power. In 34 the base is 3.
- Index (power, exponent)
- The small raised number that says how many lots of the base are multiplied. Plural: indices.
- Reciprocal
- One divided by a number. The reciprocal of 5 is 1/5 and a−1 = 1/a.
- Root
- The number that gives the original when raised to a power. √25 = 5 and 3√8 = 2.
- Perfect square / cube
- The square or cube of a whole number: 1, 4, 9, 16… and 1, 8, 27, 64…
- Standard form
- A number written as A × 10n with 1 ≤ A < 10 and n a whole number.
- Significant figures
- The digits of a number counted from the first non-zero digit.
- Exact answer
- An answer that has not been rounded, such as 36π or 2√3.
- Surd
- A square root that is not a whole number or fraction, such as √2. It is irrational.
- Irrational number
- A number that cannot be written as a fraction. Its decimal never ends or repeats.
- Like surds
- Surds with the same number under the root, for example 3√2 and 5√2.
- Rationalise the denominator
- Rewrite a fraction so that its bottom is a whole number, with no surd.
- Conjugate
- For a + √b, the conjugate is a − √b (the sign in the middle changed). Their product is a2 − b.
Exercise 6Z Check-up (non-calculator)
Non-calculatorKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 45,000 is 4.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 4.5
- Count how many places the decimal point has moved. Starting from 45000 the decimal point has to move 4 places to the left to sit after the 4. Each place moved is a factor of 10.45000 → 4.5: 4 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 4
- Write the answer. Put A and the power of 10 together.4.5 × 104
Check. Convert back: 4.5 × 104 = 45000 = 45,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −3, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−3 means divide by 10, 3 times
- Move the decimal point 3 places to the left. Move it one place at a time and fill the new places with zeros.3.2 → 0.32 → 0.032 → 0.0032
- Write the answer. The last number in the chain is the answer.0.0032
Check. Convert back to standard form: 0.0032 has first non-zero digit 3, so A = 3.2 and n = −3. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.
- Check that every base is the same. The laws of indices only work when the bases match.Every base is 2.
- Work out the top first: multiply, so add the indices. am × an = am+n.5 + 3 = 8, so the top is 28
- Divide: subtract the indices. am ÷ an = am−n.2824 = 28 ÷ 24 = 24, because 8 − 4 = 4
Check. The total of the indices on top is 8 and on the bottom is 4; 8 − 4 = 4. ✓
Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".5−2: the index is −2
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 52 = 25, 51 = 5, 50 = 1, and each step is ÷ 5, so 5−1 = 15.)5−2 = 152
- Work out the bottom. 52 means 2 lots of 5 multiplied together.52 = 5 × 5 = 25
- Write the answer as a fraction. 5−2 = 125
Check. Multiply the answer by 52: 125 × 25 = 1, and 5−2 × 52 = 50 = 1. ✓
Watch out. A negative index does not give a negative answer: 5−2 = 125, not a negative number.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.
- Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.3 × 4 = 12
- Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)x2 × x3 = x2 + 3 = x5
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.12x5
Check. Choose numbers: x = 2. The original expression has the value 384, and the answer 12x5 also has the value 384. ✓
Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(2 × 103) × (4 × 105) = (2 × 4) × (103 × 105)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.2 × 4 = 8
- Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.103 × 105 = 103 + 5 = 108
- Put the two parts together. 8 × 108
- Write the answer. 8 × 108
Check. As ordinary numbers: 2000 × 400000 = 800000000, which is 8 × 108. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Put the numbers into the formula but leave π as the symbol π. Then the answer is exact.
- Write the formula for the area of a circle. The area of a circle is π times the radius squared.A = πr2
- Substitute the radius. Replace r with the radius. Leave π as the symbol.A = π × 52
- Work out the square first. In BIDMAS, powers come before multiplication. Square the radius, not the π.52 = 5 × 5 = 25
- Write the number in front of π. Write the exact answer with the number first and then π, and add the units.25π cm2
Check. Use the π button to get a decimal and compare: 25π = 78.54 to 3 decimal places, so about 78.5 cm2 to 1 d.p. This is similar in size to 78.5 found using 3.14. ✓
Watch out. Do not replace π by 3.14 or press the π key if the question says "in terms of π" or "give your answer exactly". Also square only the radius.
Method. Work out each root or power separately, then add and subtract.
- Work out each root or power on its own. A root undoes a power; a power is repeated multiplication.√49 = 7, because 7 × 7 = 49
3√8 = 2, because 2 × 2 × 2 = 8 - Put the values into the calculation. Keep the signs the same.√49 + 3√8 = 7 + 2
- Work out the answer. Add and subtract from left to right.7 + 2 = 9
Check. Work through it again from the left: 7 + 2 = 9. ✓
Watch out. Do each root or power first (BIDMAS: powers and roots before adding and subtracting).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Compare the powers of 10 first. If the powers are the same, compare the front numbers.
- Check both numbers are in standard form. The front numbers must be between 1 and 10 for this comparison to work.3.2 and 9.9 are both at least 1 and less than 10.
- Compare the powers of 10 first. A bigger power of 10 means a bigger number, because both front numbers are between 1 and 10 and so cannot make up the difference.105 and 104: 5 > 4
- Decide. The powers are different, so the powers decide it. We do not need to look at the front numbers.3.2 × 105 > 9.9 × 104
Check. As ordinary numbers: 320000 and 99000, and 320000 is bigger than 99000. ✓
Watch out. Do not compare the front numbers first. 9.9 × 102 is much smaller than 1.1 × 105.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. 10 to a negative power is one over a power of 10: it is a small decimal.
- Use the rule for a negative index. A negative index means "one over": a−n = 1 ÷ an.10−2 = 1102
- Work out the bottom. 102 is 1 followed by 2 zeros.102 = 100, so 10−2 = 1100
- Write it as a decimal. Dividing by 10 moves the decimal point one place to the left, 2 times, starting from 1.1 → 0.1 → 0.01
Check. 1 ÷ 100 = 0.01. ✓
Watch out. 10−2 is 0.01, not −100 and not −20.
Total 20 marks. Allow about 20 minutes.
Exercise 6X Exam-style questions
Non-calculatorKey words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Write the number as A × 10n: put the decimal point after the first non-zero digit, then count how many places it moved.
- Find the first non-zero digit. In standard form A is at least 1 and less than 10, so A has exactly one non-zero digit in front of the decimal point. That digit is the first non-zero digit of the number.The first non-zero digit of 7,300,000 is 7.
- Place the decimal point just after it to make A. The digits of A are the same as the digits of the number (without the zeros at the ends).A = 7.3
- Count how many places the decimal point has moved. Starting from 7300000 the decimal point has to move 6 places to the left to sit after the 7. Each place moved is a factor of 10.7300000 → 7.3: 6 places to the left
- Decide the sign of the power. The number is 10 or more (a big number). We made it smaller to get A, so we must multiply by 10 to put the size back.n is positive: n = 6
- Write the answer. Put A and the power of 10 together.7.3 × 106
Check. Convert back: 7.3 × 106 = 7300000 = 7,300,000. ✓
Watch out. A big number has a positive power and a small number (less than 1) has a negative power. Do not count the zeros, count the places the point moves.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. A positive power of 10 makes the number bigger (move the decimal point right). A negative power makes it smaller (move the decimal point left).
- Look at the power of 10. The power is −4, which is negative, so the number is small. Dividing by 10 moves every digit one place to the right, which is the same as moving the decimal point one place to the left.10−4 means divide by 10, 4 times
- Move the decimal point 4 places to the left. Move it one place at a time and fill the new places with zeros.4.5 → 0.45 → 0.045 → 0.0045 → 0.00045
- Write the answer. The last number in the chain is the answer.0.00045
Check. Convert back to standard form: 0.00045 has first non-zero digit 4, so A = 4.5 and n = −4. ✓
Watch out. A negative power makes a number smaller, but it does not make it negative.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. When you multiply powers with the same base, you add the indices: am × an = am+n.
- Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.Both bases are 2.
- Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.23 = 2 × 2 × 2
24 = 2 × 2 × 2 × 2
Together: 3 lots of 2 and 4 lots of 2 make 7 lots of 2. - Add the indices. Joining the lots means adding the number of lots.3 + 4 = 7
- Write the answer as a single power. Keep the same base and use the new index.23 × 24 = 27
Check. Work out the numbers: 23 = 8 and 24 = 16. 8 × 16 = 128, and 27 = 128. ✓
Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Multiply the front numbers, add the powers of 10, then make sure the front number is between 1 and 10.
- Write the multiplication with the number parts together and the powers of 10 together. Multiplication can be done in any order, so we can group the front numbers and group the powers of 10.(3.2 × 104) × (2.5 × 103) = (3.2 × 2.5) × (104 × 103)
- Multiply the front numbers. Do this like an ordinary decimal multiplication.Ignore the decimal points: 32 × 25 = 800
There are 2 decimal places altogether in 3.2 and 2.5, so the answer has 2 decimal places: 3.2 × 2.5 = 8 - Multiply the powers of 10: add the indices. 10a × 10b = 10a+b.104 × 103 = 104 + 3 = 107
- Put the two parts together. 8 × 107
- Write the answer. 8 × 107
Check. As ordinary numbers: 32000 × 2500 = 80000000, which is 8 × 107. ✓
Watch out. Add the powers when you multiply (do not multiply them). Always check the front number at the end: 12 × 107 is not in standard form.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.
Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.
- Divide the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.6 ÷ 2 = 3
- Deal with the letter a: subtract the indices. The letter is the same in both terms, so the index law applies. (a on its own means a1.)a5 ÷ a2 = a5 − 2 = a3
- Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.3a3
Check. Choose numbers: a = 2. The original expression has the value 24, and the answer 3a3 also has the value 24. ✓
Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.
- Spot the negative index. A negative index does not make the answer negative. It means "one over".4−2: the index is −2
- Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 42 = 16, 41 = 4, 40 = 1, and each step is ÷ 4, so 4−1 = 14.)4−2 = 142
- Work out the bottom. 42 means 2 lots of 4 multiplied together.42 = 4 × 4 = 16
- Write the answer as a fraction. 4−2 = 116
Check. Multiply the answer by 42: 116 × 16 = 1, and 4−2 × 42 = 40 = 1. ✓
Watch out. A negative index does not give a negative answer: 4−2 = 116, not a negative number.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Order by the power of 10 first; use the front number to break ties.
- List the power of 10 of each number. The power of 10 is the main thing that decides the size.6.1 × 103: power 3
8.2 × 10−2: power −2
5.9 × 103: power 3
1.7 × 104: power 4 - Order by the powers of 10. We need smallest to largest. Remember that −7 is smaller than −3.power −2, power 3, power 3, power 4
- If two numbers have the same power, compare their front numbers. With equal powers, the bigger front number is the bigger number.power 3: 6.1 and 5.9 → smaller first is 5.9
- Write the numbers in order. 8.2 × 10−2 , 5.9 × 103 , 6.1 × 103 , 1.7 × 104
Check. As ordinary numbers: 0.082, 5900, 6100, 17000 — these increase along the list. ✓
Watch out. A negative power is smaller than a positive power, and a larger negative power (like −8) is smaller than −2.
Key words. π (pi) is the number 3.14159… that you get when you divide the circumference of any circle by its diameter. It never ends and never repeats, so we cannot write it exactly as a decimal. An answer left in terms of π (such as 12π) is exact: nothing has been rounded.
Method. Split into a rectangle and a semicircle, find each area exactly, then add.
- Split the shape into a rectangle and a semicircle. It is easier to find the areas of simple shapes and add them.area = rectangle + semicircle
- Find the area of the rectangle. area = length × width8 × 3 = 24 cm2
- Find the radius of the semicircle. The diameter of the semicircle is the width of the rectangle. The radius is half the diameter.radius = 8 ÷ 2 = 4 cm
- Find the area of the semicircle. A semicircle is half a circle: half of πr2.12 × π × 42 = 12 × π × 16 = 8π cm2
- Add the two areas. Leave π in the answer. The whole numbers and the π part cannot be combined into one term.(24 + 8π) cm2
Check. As a decimal: 24 + 25.13 = 49.13 cm2 (about). The rectangle alone is 24 cm2, so this is a little bigger. ✓
Watch out. Use the radius (half the width) in the circle formula, not the whole width.
Key words. Standard form is a way to write very big or very small numbers as A × 10n, where A is at least 1 and less than 10 (so exactly one non-zero digit before the decimal point) and n is a whole number (positive, negative or zero).
Method. Use the ×10x key on a calculator, then write the display in standard form to the accuracy asked for.
- Decide what to do. Time = distance ÷ speed.time = (3.84 × 108) ÷ (3 × 108)
- Enter the calculation using the ×10x key. The ×10x key (on some calculators it is EXP) types "× 10 to the power" in one go. For a negative power, press the (−) key before the power number. Brackets stop the calculator mixing the numbers up.Press: ( 3.84 [×10x] 8 ) [÷] ( 3 [×10x] 8 ) [=]
- Read the answer from the display. Your calculator may show the answer as an ordinary number or in its own standard form style, such as 2.4E−3. The digits are what matter.Display: 1.28 × 100 (about)
- Round to 3 significant figures and write in standard form. Round the front number A to 3 significant figures: look at the digit after the last one you keep, and round up if it is 5 or more. The power of 10 stays the same unless the rounding makes A reach 10.1.28 × 100 s
Check. Estimate by rounding each front number to the nearest whole number: (4 × 108) ÷ (3 × 108) ≈ 1 × 100, which is close to our answer. ✓
Watch out. Use the ×10x key, not separate × 10 ^ keys, unless you use brackets. Always check the power is sensible with a quick estimate.
Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.
Method. Find the edge of the cube with a cube root, then the area of one face, then multiply by 6.
- Find the edge. Edge × edge × edge = 343, so edge = 3√343.3√343 = 7, because 7 × 7 × 7 = 343
- Find the area of one face. Each face is a square with side 7 cm.7 × 7 = 49 cm2
- Multiply by the number of faces. A cube has 6 faces.6 × 49 = 294 cm2
Check. 73 = 343 and 6 × 49 = 294. ✓
Watch out. Marks: 1 for the edge, 1 for the face, 1 for the surface area.