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GCSE Maths · EdexcelChapter 16 · Units and compound measures
Chapter 16 · Higher tier

GCSE Maths Units and Compound Measures (Higher): worked examples and questions with answers

By the end of this chapter you will be able to

  • Change between metric units of length, mass, capacity and time
  • Convert area and volume units such as cm² to m²
  • Use imperial units and currency with a given conversion factor
  • Solve speed, distance and time problems, including km/h and m/s
  • Use density, pressure, rates of pay and unit prices
  • Recognise and use direct and inverse proportion in tables, graphs and equations
  • Interpret the gradient of a straight-line graph as a rate of change
  • Higher: construct and use equations such as y = kx², y = k/x and y ∝ √x

You should already know

  • Multiplying and dividing by 10, 100 and 1000 (Chapter 1)
  • Decimals and rounding (Chapter 4)
  • Fractions of amounts (Chapter 3)
  • Ratio and unitary method (Chapter 15)

Where this leads

  • Straight-line graphs and rates of change (Chapter 12)
  • Volume and surface area (Chapter 19)
  • Similar shapes: length, area and volume scale factors (Chapter 21)
  • Gradients under graphs (Chapter 25)

Edexcel GCSE (9–1) Mathematics 1MA1, Higher tier. Content references: R1, R10, R11, R13, N13, R14.

Printable worksheets. Every lesson in this chapter has a free worksheet and an answer sheet to download and print.
16.1

Metric units and time

Edexcel 1MA1: N13, R1
Grade 1-4

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Metric units and timeComing soon

Every measurement has two parts: a number and a unit. “5” on its own means nothing, but 5 centimetres or 5 kilograms means something you can picture. The metric system is used almost everywhere in the world. Its great advantage is that units are linked by 10, 100 and 1000, so changing between them just means moving the decimal point.

The prefixes tell you the size: kilo means 1000 (a kilometre is 1000 metres), centi means one hundredth (a centimetre is 1/100 of a metre) and milli means one thousandth (a millimetre is 1/1000 of a metre). The same prefixes work for grams and litres.

kmmcmmm×1000÷1000×100÷100×10÷10
Going right (to a smaller unit) you multiply. Going left (to a bigger unit) you divide.

The facts to learn

MeasureUnits and links
Length1 km = 1000 m  ·  1 m = 100 cm  ·  1 cm = 10 mm  ·  1 m = 1000 mm
Mass1 tonne = 1000 kg  ·  1 kg = 1000 g  ·  1 g = 1000 mg
Capacity1 litre = 1000 ml  ·  1 litre = 100 cl  ·  1 cl = 10 ml
Time1 minute = 60 seconds  ·  1 hour = 60 minutes  ·  1 day = 24 hours  ·  1 week = 7 days

Which way do I go: multiply or divide?

Think about how many you will need. A metre is a big unit and a centimetre is small, so one metre needs 100 of the little ones. So when you change from a big unit to a small unit the number gets bigger: multiply. When you change from a small unit to a big unit the number gets smaller: divide. Always ask yourself whether your answer should be bigger or smaller than the number you started with. If it is the wrong way round, you used the wrong operation.

Multiplying or dividing by 10, 100 or 1000 moves the digits. For example 3.2 × 100 = 320 (digits move two places left on the place-value grid) and 4500 ÷ 1000 = 4.5 (three places right). Some conversions need two steps, such as kilometres to centimetres: go km → m → cm, so 1 km = 1000 × 100 = 100 000 cm.

Key ideas

  • Big unit to small unit: multiply (you get more of them).
  • Small unit to big unit: divide (you get fewer of them).
  • Know: 1 km = 1000 m, 1 m = 100 cm, 1 cm = 10 mm, 1 kg = 1000 g, 1 tonne = 1000 kg, 1 litre = 1000 ml.
  • To compare measurements, first write them all in the same unit.
Worked example 16.1.1
Change 4.7 km into metres.

Key words. A unit is a standard size we measure in. Kilometres and metres measure the same kind of thing, but one is bigger than the other.

Method. To change units, use the fact that links them. Changing to a smaller unit means a bigger number (multiply); changing to a bigger unit means a smaller number (divide).

  1. Decide what should happen to the number: kilometres to metres. Kilometres are the bigger unit and metres are the smaller unit, so it takes more metres to make the same amount. We expect the number to get bigger.
    4.7 km → ? m
  2. Change kilometres to metres. Use the fact 1 km = 1000 m. Each kilometre is 1000 m, so you need 1000 times as many metres as kilometres. The metre is the smaller unit, so the number gets bigger: multiply by 1000.
    4.7 × 1000 = 4700 m
  3. Write the answer with its unit. Always finish by writing the new unit.
    4.7 km = 4700 m

Check. Convert back: 4700 m gives 4.7 km (4700 ÷ 1000 = 4.7). ✓

Watch out. Ask yourself: will the number get bigger or smaller? Metres to centimetres: you get more of the smaller unit, so the number grows.

Worked example 16.1.2
Change 2350 g into kilograms.

Key words. A unit is a standard size we measure in. Grams and kilograms measure the same kind of thing, but one is bigger than the other.

Method. To change units, use the fact that links them. Changing to a smaller unit means a bigger number (multiply); changing to a bigger unit means a smaller number (divide).

  1. Decide what should happen to the number: grams to kilograms. Grams are the smaller unit and kilograms are the bigger unit, so it takes fewer kilograms to make the same amount. We expect the number to get smaller.
    2350 g → ? kg
  2. Change grams to kilograms. Use the fact 1 kg = 1000 g. It takes 1000 grams to make one kilogram, so you need 1000 times fewer kilograms than grams. The kilogram is the bigger unit, so the number gets smaller: divide by 1000.
    2350 ÷ 1000 = 2.35 kg
  3. Write the answer with its unit. Always finish by writing the new unit.
    2350 g = 2.35 kg

Check. Convert back: 2.35 kg gives 2350 g (2.35 × 1000 = 2350). ✓

Watch out. Ask yourself: will the number get bigger or smaller? Metres to centimetres: you get more of the smaller unit, so the number grows.

Worked example 16.1.3
Write these lengths in order of size, smallest first: 2.4 km, 2350 m, 2410 m.

Method. Convert every measurement to the same unit, then compare the numbers.

  1. Pick one unit to compare in. We cannot compare 3 km with 250 m directly. Put every measurement in the same unit first.
    We will use m.
  2. Convert each one to m. Going to a smaller unit: multiply. Going to a bigger unit: divide.
    2.4 km: 2.4 × 1000 = 2400 m
    2350 m is already in m
    2410 m is already in m
  3. Put the numbers in order. Now they are in the same unit, so we can order them (smallest first).
    2350, 2400, 2410
  4. Write the original measurements in that order. The question asks for the measurements as they were given.
    2350 m, 2.4 km, 2410 m

Check. Compare the biggest and the smallest again in the common unit: they are 2410 and 2350 m. ✓

Watch out. Do not order the numbers as they are written. 250 m looks bigger than 3 km because 250 is bigger than 3, but 3 km is 3000 m, which is much longer.

Worked example 16.1.4
Change 0.06 tonnes into grams.

Key words. A unit is a standard size we measure in. Tonnes and grams measure the same kind of thing, but one is bigger than the other.

Method. To change units, use the fact that links them. Changing to a smaller unit means a bigger number (multiply); changing to a bigger unit means a smaller number (divide).

  1. Decide what should happen to the number: tonnes to grams. Tonnes are the bigger unit and grams are the smaller unit, so it takes more grams to make the same amount. We expect the number to get bigger.
    0.06 tonnes → ? g
  2. Change tonnes to kilograms. Use the fact 1 tonne = 1000 kg. Each tonne is 1000 kg, so you need 1000 times as many kilograms as tonnes. The kilogram is the smaller unit, so the number gets bigger: multiply by 1000.
    0.06 × 1000 = 60 kg
  3. Change kilograms to grams. Use the fact 1 kg = 1000 g. Each kilogram is 1000 g, so you need 1000 times as many grams as kilograms. The gram is the smaller unit, so the number gets bigger: multiply by 1000.
    60 × 1000 = 60,000 g
  4. Write the answer with its unit. We went one unit at a time so each step uses a fact you already know.
    0.06 tonnes = 60,000 g

Check. Convert back: 60,000 g gives 0.06 tonnes (60,000 ÷ 1,000,000 = 0.06). ✓

Watch out. Ask yourself: will the number get bigger or smaller? Metres to centimetres: you get more of the smaller unit, so the number grows.

Worked example 16.1.5
Write an expression for the number of millimetres in (3x + 2) centimetres.

Method. 1 cm = 10 mm, so changing centimetres to millimetres (a smaller unit) means multiplying by 10. The same rule works when the length is an algebraic expression.

  1. Write down the fact. Centimetres are bigger than millimetres, so there will be more millimetres.
    1 cm = 10 mm
  2. Multiply the whole expression by 10. The whole length (3x + 2) must be multiplied, so use brackets.
    10 × (3x + 2)
  3. Expand the brackets. Multiply each term inside by 10.
    10 × 3x = 30x and 10 × 2 = 20
    Answer: (30x + 20) mm

Check. Try x = 1: (3 + 2) = 5 cm = 50 mm, and 30 + 20 = 50. ✓

Watch out. Multiply the whole bracket, not just the first term: 10 × 3x + 2 would be wrong.

Watch out

Do not use 100 for everything. There are 100 cm in a metre but 1000 m in a kilometre and 1000 g in a kilogram. Check each fact carefully, and check your answer is the right size (a car cannot be 4.5 cm long, and a pencil cannot be 15 m).

Exercise 16A  Metric units of length, mass and capacity

Non-calculator
1
FChange each length to the unit shown.
(a)3 m to cm
(b)450 cm to m
(c)2.5 km to m
(d)6000 m to km
(e)8 cm to mm
(f)35 mm to cm
2
FChange each mass to the unit shown.
(a)4 kg to g
(b)3500 g to kg
(c)2 tonnes to kg
(d)7500 kg to tonnes
(e)0.6 kg to g
(f)450 g to kg
3
FChange each capacity to the unit shown.
(a)3 litres to ml
(b)4500 ml to litres
(c)250 cl to litres
(d)1.5 litres to cl
(e)8 cl to ml
(f)90 ml to cl
4
FWrite these masses in order of size, largest first: 1.2 kg, 950 g, 1.05 kg, 1100 g.
5
FThese need two steps. Change each measurement to the unit shown.
(a)0.4 km to cm
(b)0.02 tonnes to g
(c)3 km to mm
(d)5,000,000 mg to kg
6
PSA bag of flour has mass 1.5 kg. How many 250 g portions can be made from one bag?
7
PSA jug holds 1.2 litres of squash. Each glass holds 150 ml. How many glasses can be filled?
8
RSam says “3.5 kg is 350 g”. Explain what Sam has done wrong and give the correct answer.
9
FA running track is 400 m long. Asha runs 5 laps. How far does she run, in kilometres?
10
FWork out 1.4 m + 35 cm + 800 mm. Give your answer in centimetres.
11
FThree parcels have masses 1.2 kg, 850 g and 2.05 kg. Work out the total mass in kilograms.
12
PSA 3 m length of wood is cut into pieces of length 35 cm. How many whole pieces can be cut, and how much wood is left over?
13
PSA doctor gives 5 ml of medicine at each dose. A bottle holds 0.25 litres. How many doses are in a full bottle?
14
RIs 0.05 km longer than 5000 cm? Show your working.
15
PSWrite an expression, in grams, for the mass of n bags of sugar when each bag has mass 0.75 kg.
16
RA square has sides of length x centimetres. Show that its perimeter in metres is x/25.
17
RA tap drips 2 ml of water every 10 seconds. How many litres of water does it waste in one day? Give your answer to 2 decimal places.

Units of time

Time is the one common measure that is not metric. The facts are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day and 7 days in a week. So changing between time units uses 60, 24 and 7 instead of 10, 100 and 1000. The same rule holds: to a smaller unit, multiply; to a bigger unit, divide. For example 2.5 hours is 2.5 × 60 = 150 minutes.

The 12-hour and 24-hour clock

The 12-hour clock uses am (morning, before midday) and pm (afternoon and evening). The 24-hour clock counts all the way from 00:00 (midnight) to 23:59, so there is no need for am or pm. After 12:59, add 12 to the hour: 3:20 pm is 15:20. To go back, subtract 12: 20:45 is 8:45 pm. Midnight is 00:00 (or 12 am) and midday is 12:00 (12 pm).

00:0006:0012:0018:0024:00amampmpm
A day on the 24-hour clock. 15:20 is 3:20 pm; 07:45 is 7:45 am.

How long does it take? (durations)

Do not subtract 24-hour times like ordinary numbers, because an hour has 60 minutes, not 100. Instead count on: go from the start time to the next whole hour, then jump whole hours, then add the last few minutes. If the finish time is earlier than the start time, the journey goes past midnight into the next day.

Decimal hours

A calculator gives times as decimals, such as 2.4 hours. This does not mean 2 hours 40 minutes! The 0.4 is 0.4 of an hour, which is 0.4 × 60 = 24 minutes. To change hours and minutes into a decimal, divide the minutes by 60: 3 hours 15 minutes = 3 + 15/60 = 3.25 hours.

Key ideas

  • 60 s = 1 min, 60 min = 1 hour, 24 hours = 1 day, 7 days = 1 week.
  • After 12:59 add 12 to turn pm into 24-hour time; subtract 12 to go back.
  • Find a time difference by counting on: to the next hour, then whole hours, then minutes.
  • Decimal hours × 60 = minutes. Minutes ÷ 60 = decimal hours.
Worked example 16.1.6
Work out the time between 09:35 and 13:20.

Key words. The 24-hour clock counts the hours from 00:00 to 23:59. 15:30 is 3:30 pm. Duration means how long something lasts.

Method. To find a time difference, count on from the start time to the finish time in easy jumps: to the next whole hour, then whole hours, then the minutes left.

  1. Write both times on the 24-hour clock. The 24-hour clock avoids am and pm mix-ups.
    Start 09:35, finish 13:20
  2. Count on to the next whole hour. Counting on in easy jumps is safer than subtracting 24-hour times, because there are 60 minutes (not 100) in an hour.
    09:35 to 10:00 = 25 minutes
  3. Count on in whole hours. Now we are at the start of an hour, so we can jump whole hours.
    10:00 to 13:00 = 3 hours
  4. Count on the remaining minutes. Finish by counting on to the finishing time.
    13:00 to 13:20 = 20 minutes
  5. Add the pieces together. The total is the time taken.
    25 minutes + 3 hours + 20 minutes = 3 hours 45 minutes

Check. Add back: 09:35 + 3 hours 45 minutes = 13:20. ✓

Watch out. Never subtract 24-hour times like 1420 − 0950 as ordinary numbers. An hour has 60 minutes, not 100.

Worked example 16.1.7
A train leaves at 22:45 and arrives at 02:10 the next morning. How long is the journey?

Key words. The 24-hour clock counts the hours from 00:00 to 23:59. 15:30 is 3:30 pm. Duration means how long something lasts.

Method. To find a time difference, count on from the start time to the finish time in easy jumps: to the next whole hour, then whole hours, then the minutes left.

  1. Write both times on the 24-hour clock. The 24-hour clock avoids am and pm mix-ups.
    Start 22:45, finish 02:10 (the next day)
  2. Count on to the next whole hour. Counting on in easy jumps is safer than subtracting 24-hour times, because there are 60 minutes (not 100) in an hour.
    22:45 to 23:00 = 15 minutes
  3. Count on in whole hours. Now we are at the start of an hour, so we can jump whole hours.
    23:00 to 02:00 = 3 hours
  4. Count on the remaining minutes. Finish by counting on to the finishing time.
    02:00 to 02:10 = 10 minutes
  5. Add the pieces together. The total is the time taken.
    15 minutes + 3 hours + 10 minutes = 3 hours 25 minutes

Check. Add back: 22:45 + 3 hours 25 minutes = 02:10. ✓

Watch out. Never subtract 24-hour times like 1420 − 0950 as ordinary numbers. An hour has 60 minutes, not 100.

Worked example 16.1.8
Write 7:05 pm using the 24-hour clock.

Method. Convert from the 12-hour clock to the 24-hour clock: add 12 to pm hours (except 12 pm); 12 am becomes 00.

  1. Decide: is it am or pm? am is before midday and pm is after midday. This decides whether we add 12.
    7:05 pm
  2. Add 12 to the hour (pm). The 24-hour clock carries on counting after 12 at midday: 1 pm is 13:00.
    7 + 12 = 19
  3. Write it with four digits. Always use two digits for the hour and two for the minutes.
    19:05

Check. 19:05 converted back is 7:05 pm. ✓

Worked example 16.1.9
Write 2.4 hours in hours and minutes.

Method. Decimal hours are not hours and minutes. Keep the whole hours and multiply the decimal part by 60 to get minutes.

  1. Split off the whole hours. The digits before the decimal point are whole hours.
    2.4 hours = 2 hours + 0.4 hours
  2. Change the decimal part to minutes. There are 60 minutes in 1 hour, so multiply the decimal by 60.
    0.4 × 60 = 24 minutes
  3. Put them together.
    2 hours 24 minutes

Check. 24 ÷ 60 = 0.4, so 2 hours 24 minutes is 2.4 hours. ✓

Watch out. 2.5 hours is not 2 hours 50 minutes. The .5 is half an hour = 30 minutes.

Watch out

Never write 2.4 hours as “2 hours 40 minutes”. The part after the decimal point is a fraction of an hour, not a number of minutes. Also, 100 minutes is not 1 hour; it is 1 hour 40 minutes.

Exercise 16B  Time

Non-calculator
1
FChange each time to the unit shown.
(a)3 minutes to seconds
(b)2 hours to minutes
(c)180 seconds to minutes
(d)300 minutes to hours
(e)5 days to hours
(f)3 weeks to days
2
FWrite each time using the 24-hour clock.
(a)7:30 am
(b)2:15 pm
(c)11:40 pm
(d)12:05 am
(e)12:30 pm
(f)9:05 pm
3
FWrite each time using the 12-hour clock (with am or pm).
(a)06:45
(b)13:20
(c)20:05
(d)00:15
(e)12:50
(f)23:59
4
FWork out the time taken from the start time to the finish time.
(a)07:15 to 09:40
(b)10:50 to 14:25
(c)16:35 to 20:10
(d)22:20 to 01:05
5
FWork out the finishing time on the 24-hour clock.
(a)Start 08:30, takes 2 hours 45 minutes
(b)Start 13:40, takes 1 hour 35 minutes
(c)Start 18:20, takes 3 hours 50 minutes
(d)Start 21:45, takes 4 hours 30 minutes
6
FWrite each time in hours and minutes.
(a)3.5 hours
(b)1.25 hours
(c)2.4 hours
(d)0.75 hours
7
FWrite each time as a decimal number of hours.
(a)2 hours 30 minutes
(b)1 hours 45 minutes
(c)3 hours 12 minutes
(d)4 hours 6 minutes
8
PSHere is part of a train timetable.
StationTime
Bellview07:48
Corton08:26
Dunmere09:05
Eastgate09:41
Work out the journey time from
(a)Bellview to Eastgate
(b)Corton to Dunmere
(c)Bellview to Corton, and then Corton to Eastgate. Write both answers.
9
PSA film starts at 7:45 pm and lasts 2 hours 25 minutes. At what time does it finish? Give your answer using the 12-hour clock.
10
FHow many seconds are there in one day?
11
PSJo runs for 50 minutes, 3 times a week. How many hours does she run in 4 weeks?
12
RBen says “3.4 hours is 3 hours 40 minutes”. Is he correct? Explain.
13
PSA night shift starts at 21:45 and finishes at 06:20 the next morning. There is a 35 minute unpaid break. Pay is £9.40 per hour. Work out the pay for the shift.
14
PSWrite an expression, in seconds, for the time taken by a journey of t hours and m minutes.
15
PSA concert starts at 7:30 pm and finishes at 10:05 pm. An interval of 20 minutes is included. For how many minutes is the music played?
16.2

Area and volume units

Edexcel 1MA1: R1, N13
Grade 3-5

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Area and volume unitsComing soon

Length is measured in a single direction, so its units are cm, m, km. Area measures a flat surface, so its units are square units: cm² means “squares with sides of 1 cm”. Volume measures the space inside a 3D shape, so its units are cubic units: cm³ means “cubes with edges of 1 cm”. Because of this, the conversion factors for area and volume are not the same as for length.

Why the factor is squared

Look at a square with sides of 1 m. Each side is also 100 cm. The square is 100 cm long and 100 cm wide, so it holds 100 × 100 = 10 000 squares of 1 cm². So 1 m² = 10 000 cm², not 100 cm². The area factor is the length factor squared.

1 m = 100 cm1 m100 × 100= 10 000 smallsquares of 1 cm²1 m² = 10 000 cm²
A square metre is 100 cm by 100 cm, which is 10 000 square centimetres.

Why the factor is cubed

A cube with edges of 1 m has edges of 100 cm. It holds 100 × 100 × 100 = 1 000 000 cubes of 1 cm³. So 1 m³ = 1 000 000 cm³. The volume factor is the length factor cubed.

100 cm100 cm100 cm
A cube of side 1 m = 100 cm has volume 100 × 100 × 100 = 1 000 000 cm³.

Facts to know

LengthAreaVolume
1 cm = 10 mm1 cm² = 100 mm²1 cm³ = 1000 mm³
1 m = 100 cm1 m² = 10 000 cm²1 m³ = 1 000 000 cm³
1 km = 1000 m1 km² = 1 000 000 m²1 km³ = 1 000 000 000 m³

Volume and capacity are two ways of measuring the same amount: 1 ml = 1 cm³, 1 litre = 1000 cm³ and 1 m³ = 1000 litres. So a fish tank that has volume 30 000 cm³ holds 30 litres.

The method

(1) Write the length fact. (2) Square it for area, cube it for volume. (3) Multiply if you are changing to a smaller unit, divide if you are changing to a bigger unit. You can also change all the lengths to the new unit before you work out the area or volume, which avoids the squared factor altogether.

Key ideas

  • Area factor = (length factor)². Volume factor = (length factor)³.
  • 1 m² = 10 000 cm² and 1 m³ = 1 000 000 cm³.
  • 1 ml = 1 cm³, 1 litre = 1000 cm³, 1 m³ = 1000 litres.
  • Smaller unit: multiply. Bigger unit: divide.
Worked example 16.2.1
Change 3.5 m² into cm².

Key words. Area is the amount of flat surface, measured in square units such as cm². Volume is the space inside a 3D shape, measured in cubic units such as cm³.

Method. To change area units, square (or cube) the length factor. The area factor is the length factor squared.

  1. Write the length fact for the two units. Area and volume units are built from lengths, so start with the length fact.
    1 m = 100 cm
  2. Find how many cm² fit in 1 m². A square of side 1 m has side 100 cm. Its area is the length squared. The number of small squares is length × length.
    1 m² = 100 cm × 100 cm = 10,000 cm²
  3. Multiply by the area/volume factor. We are changing to the smaller unit, so the number of cm² is bigger.
    3.5 × 10,000 = 35,000 cm²

Check. Convert back: 35,000 cm² ÷ 10,000 = 3.5 m². ✓

Watch out. Do not use the length factor on its own. 1 m = 100 cm but 1 m² is not 100 cm²; it is 10,000 cm².

Worked example 16.2.2
Change 45 000 cm² into m².

Key words. Area is the amount of flat surface, measured in square units such as cm². Volume is the space inside a 3D shape, measured in cubic units such as cm³.

Method. To change area units, square (or cube) the length factor. The area factor is the length factor squared.

  1. Write the length fact for the two units. Area and volume units are built from lengths, so start with the length fact.
    1 m = 100 cm
  2. Find how many cm² fit in 1 m². A square of side 1 m has side 100 cm. Its area is the length squared. The number of small squares is length × length.
    1 m² = 100 cm × 100 cm = 10,000 cm²
  3. Divide by the area/volume factor. We are changing to the bigger unit, so the number of m² is smaller.
    45,000 ÷ 10,000 = 4.5 m²

Check. Convert back: 4.5 m² × 10,000 = 45,000 cm². ✓

Watch out. Do not use the length factor on its own. 1 m = 100 cm but 1 m² is not 100 cm²; it is 10,000 cm².

Worked example 16.2.3
Change 0.004 m³ into cm³.

Key words. Area is the amount of flat surface, measured in square units such as cm². Volume is the space inside a 3D shape, measured in cubic units such as cm³.

Method. To change volume units, square (or cube) the length factor. The volume factor is the length factor cubed.

  1. Write the length fact for the two units. Area and volume units are built from lengths, so start with the length fact.
    1 m = 100 cm
  2. Find how many cm³ fit in 1 m³. A cube of side 1 m has side 100 cm. Its volume is the length cubed. The number of small cubes is length × length × length.
    1 m³ = 100 cm × 100 cm × 100 cm = 1,000,000 cm³
  3. Multiply by the area/volume factor. We are changing to the smaller unit, so the number of cm³ is bigger.
    0.004 × 1,000,000 = 4000 cm³

Check. Convert back: 4000 cm³ ÷ 1,000,000 = 0.004 m³. ✓

Watch out. Do not use the length factor on its own. 1 m = 100 cm but 1 m² is not 100 cm²; it is 1,000,000 cm³.

Worked example 16.2.4
A fish tank has volume 36 000 cm³. How many litres of water does it hold when full?

Method. Volume and capacity are linked by a fact you must know. Use it to multiply or divide.

  1. Write the link between the units. Capacity (litres, ml) measures liquids; volume (cm³, m³) measures space. They are two ways to measure the same amount.
    1 litre = 1000 cm³  (and 1 ml = 1 cm³)
  2. Decide: multiply or divide? We are changing to the bigger unit, so we need fewer of them: divide by 1000.
    36,000 ÷ 1000
  3. Calculate.
    36,000 ÷ 1000 = 36 litres

Check. Convert back: 36 litres × 1000 = 36,000 cm³. ✓

Watch out. 1 litre is 1000 cm³ (not 100 and not 10 000). Think of a 10 cm cube: 10 × 10 × 10 = 1000 cm³ holds exactly 1 litre.

Worked example 16.2.5
A water tank is a cuboid 1.5 m long, 80 cm wide and 50 cm high. Work out its capacity in litres.

Method. Write all three lengths in the same unit first (centimetres), find the volume, then change cm³ to litres.

  1. Change 1.5 m to cm. Metres to centimetres: multiply by 100.
    1.5 × 100 = 150 cm
  2. Find the volume. Volume of a cuboid = length × width × height.
    150 × 80 × 50 = 600000 cm³
  3. Change cm³ to litres. 1 litre = 1000 cm³, and cm³ to litres means divide by 1000.
    600000 ÷ 1000 = 600 litres

Check. In metres: 1.5 × 0.8 × 0.5 = 0.6 m³ and 0.6 × 1000 = 600 litres. ✓

Watch out. Do not multiply 1.5 × 80 × 50 with mixed units. Always match the units before you multiply.

Watch out

1 m = 100 cm, but 1 m² is not 100 cm², and 1 m³ is not 100 cm³. Square or cube the factor. A quick check: 1 m² is a big square, so it must hold lots of tiny cm squares (10 000 of them).

Exercise 16C  Converting area and volume units

Non-calculator
1
FChange each area to the unit shown.
(a)2 m² to cm²
(b)0.5 m² to cm²
(c)3 cm² to mm²
(d)1.2 cm² to mm²
2
FChange each area to the unit shown.
(a)50,000 cm² to m²
(b)25,000 cm² to m²
(c)700 mm² to cm²
(d)450 mm² to cm²
3
FChange each area to the unit shown.
(a)2 km² to m²
(b)3,500,000 m² to km²
(c)0.04 m² to cm²
(d)62,000 cm² to m²
4
FChange each volume to the unit shown.
(a)3 m³ to cm³
(b)2.5 cm³ to mm³
(c)4,500,000 cm³ to m³
(d)6000 mm³ to cm³
5
FChange each amount to the unit shown.
(a)4500 cm³ to litres
(b)3 litres to cm³
(c)2 m³ to litres
(d)750 litres to m³
6
FA cuboid has edges 2 cm, 3 cm and 4 cm. Work out its volume in mm³.
7
FA carpet measures 4 m by 2.5 m. Work out its area in cm².
8
PSA floor is 3 m by 2 m. It is covered with square tiles of side 20 cm. How many tiles are needed?
9
RKayla says “1 m = 100 cm, so 1 m² = 100 cm²”. Explain why she is wrong and give the correct value.
10
PSA tank is a cuboid 1.5 m long, 80 cm wide and 50 cm high. Work out its capacity in litres.
1.5 m50 cm80 cm
11
PSA fish tank is 60 cm long, 30 cm wide and 40 cm high. It is filled to a depth of 30 cm. How many litres of water are in the tank?
12
RWhich is larger, 0.6 m² or 5500 cm²? Show your working.
13
PSA square has sides of length x metres. Write an expression for its area in cm².
14
RA cube has edge length a cm. Show that its volume in m³ is a31 000 000.
15
RA swimming pool is a cuboid 25 m long, 10 m wide and 1.6 m deep. (a) Work out the volume in litres when it is full. (b) A pump fills it at 500 litres per minute. How long does it take? Give your answer in hours and minutes.
(a)Volume in litres
(b)Time to fill
16.3

Imperial units and currency

Edexcel 1MA1: R1, N13
Grade 2-5

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Imperial units and currencyComing soon

Most of the world uses metric units, but in the UK you will still meet imperial units: miles on road signs, pints of milk, pounds and stones for body weight, and feet and inches for height. You also need to change between different currencies when you go abroad, such as pounds (£) and euros (€). Both use the same idea: a conversion fact or rate that links the two units.

Facts that link imperial units

Imperial facts (exact)Approximate metric equivalents (often given in questions)
12 inches = 1 foot
3 feet = 1 yard
1760 yards = 1 mile
16 ounces = 1 pound
14 pounds = 1 stone
8 pints = 1 gallon
1 inch ≈ 2.5 cm
1 foot ≈ 30 cm
1 mile ≈ 1.6 km (5 miles ≈ 8 km)
1 kg ≈ 2.2 pounds
1 litre ≈ 1.75 pints
1 gallon ≈ 4.5 litres

The ≈ sign means “is approximately equal to”. Between metric and imperial the conversions are only approximate, so answers are rounded sensibly.

miles05101520km08162432
A double number line for 5 miles ≈ 8 km. Matching marks show equal distances.

The method

(1) Write the fact you are given, for example 1 mile ≈ 1.6 km. (2) Decide whether you need more or fewer of the target unit. A mile is longer than a km, so a distance in km is a bigger number: multiply by 1.6. To go back from km to miles you need fewer, so divide by 1.6. (3) Calculate and round sensibly. (4) Check by converting back.

Currency

An exchange rate tells you how much of one currency you get for one unit of another. If £1 = €1.15 then £200 gives 200 × 1.15 = €230. To change euros to pounds, divide by 1.15. Always round money to the nearest penny (or cent). If a question asks how much you need to buy something, check whether rounding up is more sensible.

Key ideas

  • Always start by writing the conversion fact.
  • Ask: will my answer be a bigger or smaller number? That tells you to multiply or divide.
  • For a rate such as £1 = €1.15: £ to € multiply by 1.15; € to £ divide by 1.15.
  • Round money to 2 decimal places.
Worked example 16.3.1
Given that 1 inch ≈ 2.54 cm, change 8 inches to centimetres.

Method. Use the given fact to link the two units. To change into the unit with the bigger number multiply; to change back, divide.

  1. Write the conversion fact you are given. This tells us how the two units are linked. It is like an exchange rate.
    1 inch ≈ 2.54 cm
  2. Decide: multiply or divide? The fact says 1 inch gives 2.54 cm, so the answer is 2.54 times the starting number: multiply by 2.54. The answer should be bigger than the number we started with.
    8 inches × 2.54
  3. Calculate. Use a calculator or work it out carefully.
    8 × 2.54 = 20.32

Check. Work backwards: 20.32 ÷ 2.54 ≈ 8. ✓

Watch out. Multiplying and dividing are easy to mix up. Ask yourself: should my answer be a bigger or a smaller number than the one I started with?

Worked example 16.3.2
Given that 1 mile ≈ 1.6 km, change 56 km into miles.

Method. Use the given fact to link the two units. To change into the unit with the bigger number multiply; to change back, divide.

  1. Write the conversion fact you are given. This tells us how the two units are linked. It is like an exchange rate.
    1 mile ≈ 1.6 km
  2. Decide: multiply or divide? The fact says 1.6 km make 1 mile, so the answer is the starting number shared into groups of 1.6: divide by 1.6. The answer should be smaller than the number we started with.
    56 km ÷ 1.6
  3. Calculate. Use a calculator or work it out carefully.
    56 ÷ 1.6 = 35

Check. Work backwards: 35 × 1.6 ≈ 56. ✓

Watch out. Multiplying and dividing are easy to mix up. Ask yourself: should my answer be a bigger or a smaller number than the one I started with?

Worked example 16.3.3
£1 = €1.16. Change £250 into euros.

Method. Use the given fact to link the two units. To change into the unit with the bigger number multiply; to change back, divide.

  1. Write the conversion fact you are given. This tells us how the two units are linked. It is like an exchange rate.
    £1 = €1.16
  2. Decide: multiply or divide? The fact says 1 pound gives 1.16 euros, so the answer is 1.16 times the starting number: multiply by 1.16. The answer should be bigger than the number we started with.
    £250 × 1.16
  3. Calculate. Use a calculator or work it out carefully.
    250 × 1.16 = 290

Check. Work backwards: 290 ÷ 1.16 = 250. ✓

Watch out. Multiplying and dividing are easy to mix up. Ask yourself: should my answer be a bigger or a smaller number than the one I started with?

Worked example 16.3.4
£1 = €1.16. Change €300 into pounds.

Method. Use the given fact to link the two units. To change into the unit with the bigger number multiply; to change back, divide.

  1. Write the conversion fact you are given. This tells us how the two units are linked. It is like an exchange rate.
    £1 = €1.16
  2. Decide: multiply or divide? The fact says 1.16 euros make 1 pound, so the answer is the starting number shared into groups of 1.16: divide by 1.16. The answer should be smaller than the number we started with.
    €300 ÷ 1.16
  3. Calculate. Use a calculator or work it out carefully.
    300 ÷ 1.16 = 258.6207
  4. Round to 2 decimal places. The conversion fact is only approximate, so a sensible rounded answer is right.
    258.6207 ≈ 258.62

Check. Work backwards: 258.62 × 1.16 ≈ 300. ✓

Watch out. Multiplying and dividing are easy to mix up. Ask yourself: should my answer be a bigger or a smaller number than the one I started with?

Worked example 16.3.5
Change 3 stone 4 pounds into pounds. (1 stone = 14 pounds)

Method. Change the stones into pounds, then add the extra pounds.

  1. Write the fact. The fact links stones and pounds exactly.
    1 stone = 14 pounds
  2. Change 3 stone to pounds. Stones are bigger than pounds, so multiply by 14.
    3 × 14 = 42 pounds
  3. Add the extra pounds. Do not forget the 4 pounds.
    42 + 4 = 46 pounds

Check. 46 ÷ 14 = 3 remainder 4, which is 3 stone 4 pounds. ✓

Watch out. Multiply only the stones by 14, then add the pounds.

Worked example 16.3.6
£1 = €r. Write an expression for the number of euros in £x, and the number of pounds in €y.

Method. Use the same multiply/divide rule as with numbers.

  1. Pounds to euros. Each pound gives r euros, so multiply the number of pounds by r.
    £x = €(r × x) = €rx
  2. Euros to pounds. It takes r euros to make one pound, so divide the number of euros by r.
    €y = £yr
  3. Check with numbers. Let r = 1.2, x = 10, y = 24.
    10 × 1.2 = 12 euros and 24 ÷ 1.2 = 20 pounds. Both make sense.

Check. Converting £x to euros and back: rx ÷ r = x. ✓

Watch out

Do not just “times by the number”. Decide first whether the answer should be bigger or smaller. 100 euros is worth less than £100 here, so €100 in pounds must be a number smaller than 100: divide by the rate.

Exercise 16D  Imperial units and currency

Calculator allowed
1
FUse 1 inch ≈ 2.5 cm, 1 mile ≈ 1.6 km and 1 kg ≈ 2.2 pounds to change:
(a)20 inches to cm
(b)150 cm to inches
(c)30 miles to km
(d)72 km to miles
(e)10 kg to pounds
(f)33 pounds to kg
2
FUse the exact imperial facts to change (12 in = 1 ft, 3 ft = 1 yd, 14 lb = 1 st, 16 oz = 1 lb, 8 pints = 1 gallon):
(a)4 feet to inches
(b)60 inches to feet
(c)3 yards to feet
(d)2 stone to pounds
(e)48 ounces to pounds
(f)24 pints to gallons
3
FThe exchange rate is £1 = €1.15. Change:
(a)£40 to euros
(b)£225 to euros
(c)€92 to pounds
(d)€172.50 to pounds
4
FThe exchange rate is £1 = $1.25. Change:
(a)£64 to dollars
(b)$135 to pounds
(c)£18.40 to dollars
5
PSA hotel in Spain costs €85 per night. Work out the cost of 5 nights in pounds when £1 = €1.15. Give your answer to the nearest penny.
6
PSA phone costs £480 in the UK and €540 in Spain. The exchange rate is £1 = €1.15. In which country is it cheaper, and by how much (to the nearest penny)?
7
RA speed limit sign in the UK says 30 mph. A sign abroad says 50 km/h. Which limit is higher? Use 1 mile ≈ 1.6 km.
8
RA recipe needs 8 ounces of butter. Sue has 200 g. Does she have enough? Use 1 ounce ≈ 28 g.
9
RDan changes 100 euros to pounds by working out 100 × 1.15 = 115, when £1 = €1.15. Explain why his answer must be wrong and give the correct answer to the nearest penny.
10
PSA bureau charges a fee of £6 and then changes the rest of the money at £1 = $1.28. Zara gives the bureau £300. How many dollars does she get?
11
PSA boxer has mass 12 stone 6 pounds. (a) Write this in pounds. (b) Use 1 kg ≈ 2.2 pounds to change this to kilograms, to 1 decimal place.
(a)In pounds
(b)In kg
12
PSA traveller changes £400 into euros at £1 = €1.15. She spends €280 on holiday. She changes the rest back into pounds at £1 = €1.25. How many pounds does she get back?
13
RA hotel costs €590. At the start of the week the rate was £1 = €1.18. At the end of the week it was £1 = €1.12. How much more does the hotel cost, in pounds, at the end of the week? Give your answer to the nearest penny.
16.4

Speed, distance and time

Edexcel 1MA1: R1, R11, N13
Grade 3-6

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Speed, distance and timeComing soon

A compound measure combines two different units. Speed is the most common one: it tells you how far something travels in one unit of time. If a car goes 60 kilometres in 1 hour its speed is 60 kilometres per hour, written 60 km/h. Speed is measured in km/h, mph (miles per hour) or m/s (metres per second).

Three quantities are linked: distance, speed and time. If you know any two you can find the third. This only works for a constant (steady) speed, or when you are using average speed.

DST
The formula triangle for speed. D = distance, S = speed, T = time.

Cover up the letter you want to find. What is left shows the calculation:

Why does this work? A car at 60 km/h goes 60 km each hour, so in 3 hours it goes 60 × 3 = 180 km. That is distance = speed × time. The other two formulae come from rearranging it.

Matching the units

The units must match. If the speed is in km/h, the time must be in hours and the distance will be in km. If the time is given in minutes, change it to hours first by dividing by 60 (so 30 minutes is 0.5 hours and 45 minutes is 0.75 hours). If you work out a time as a decimal such as 2.5 hours, remember the decimal part is not minutes: 0.5 hours = 30 minutes.

Average speed

In a real journey the speed changes. The average speed is the total distance divided by the total time (including any time standing still). It is the speed you would need to cover the same distance in the same time at a steady pace. Do not find the average of two speeds by adding them and halving, unless the two parts of the journey take the same time.

Changing km/h and m/s

To change 72 km/h into m/s, change the distance to metres (× 1000) and the time to seconds (÷ 3600): 72 × 1000 ÷ 3600 = 20 m/s. The shortcut is: km/h ÷ 3.6 = m/s and m/s × 3.6 = km/h. A speed in m/s is a smaller number than the same speed in km/h.

Key ideas

  • S = D ÷ T, D = S × T, T = D ÷ S (use the formula triangle).
  • Units must match: km, km/h and hours; m, m/s and seconds.
  • Change minutes to hours by dividing by 60. Decimal hours × 60 gives minutes.
  • Average speed = total distance ÷ total time.
  • km/h ÷ 3.6 = m/s; m/s × 3.6 = km/h.
Worked example 16.4.1
A train travels 150 km in 2.5 hours. Work out its average speed.

Key words. Speed tells you how far something travels in one unit of time. Average speed is the total distance divided by the total time.

Method. Use the formula triangle for distance, speed and time: distance = speed × time. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the distance (150 km) and the time (2.5 hours).
    We want the speed.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    speed = distance ÷ time
  3. Put the numbers in and calculate. Use the values with matching units.
    speed = 150 ÷ 2.5 = 60
  4. Write the answer with its unit. The unit is km/h.
    speed = 60 km/h

Check. Work backwards: 60 × 2.5 = 150 (the distance). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.4.2
A car travels at 48 km/h for 45 minutes. How far does it go?

Key words. Speed tells you how far something travels in one unit of time. Average speed is the total distance divided by the total time.

Method. Use the formula triangle for distance, speed and time: distance = speed × time. Cover what you want to find to see the calculation.

  1. Change the time to hours. The speed is in km per hour, so the time must be in hours. There are 60 minutes in 1 hour, so divide by 60.
    45 minutes = 45 ÷ 60 = 0.75 hours
  2. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the speed (48 km/h) and the time (0.75 hours).
    We want the distance.
  3. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    distance = speed × time
  4. Put the numbers in and calculate. Use the values with matching units.
    distance = 48 × 0.75 = 36
  5. Write the answer with its unit. The unit is km.
    distance = 36 km

Check. Work backwards: 36 ÷ 0.75 = 48 (the speed). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.4.3
A coach travels 150 km at an average speed of 60 km/h. How long does the journey take?

Key words. Speed tells you how far something travels in one unit of time. Average speed is the total distance divided by the total time.

Method. Use the formula triangle for distance, speed and time: distance = speed × time. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the distance (150 km) and the speed (60 km/h).
    We want the time.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    time = distance ÷ speed
  3. Put the numbers in and calculate. Use the values with matching units.
    time = 150 ÷ 60 = 2.5
  4. Change the decimal hours to hours and minutes. The decimal part of an hour is multiplied by 60 to get minutes.
    0.5 × 60 = 30 minutes
    2.5 hours = 2 hours 30 minutes
  5. Write the answer with its unit. The unit is hours.
    time = 2.5 hours

Check. Work backwards: 60 × 2.5 = 150 (the distance). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.4.4
A sprinter runs 100 m in 12.5 seconds. Work out the speed in m/s.

Key words. Speed tells you how far something travels in one unit of time. Average speed is the total distance divided by the total time.

Method. Use the formula triangle for distance, speed and time: distance = speed × time. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the distance (100 m) and the time (12.5 seconds).
    We want the speed.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    speed = distance ÷ time
  3. Put the numbers in and calculate. Use the values with matching units.
    speed = 100 ÷ 12.5 = 8
  4. Write the answer with its unit. The unit is m/s.
    speed = 8 m/s

Check. Work backwards: 8 × 12.5 = 100 (the distance). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.4.5
A cyclist rides 30 km in 20 minutes then 50 km in 40 minutes. Work out the average speed for the whole ride.

Method. Average speed = total distance ÷ total time. Do not average the speeds themselves.

  1. Add the distances. Average speed uses the total distance.
    30 + 50 = 80 km
  2. Add the times. It also uses the total time, including any stops that are part of the journey.
    20 + 40 = 60 minutes
  3. Change the total time to hours. We want a speed in per hour, so the time must be in hours: divide minutes by 60.
    60 ÷ 60 = 1 hour
  4. Divide total distance by total time. speed = distance ÷ time.
    80 ÷ 1 = 80
  5. Write the answer with its unit.
    average speed = 80 km/h

Check. Work backwards: 80 × 1 = 80 km, which is the total distance. ✓

Watch out. Do not add the speeds and halve them. A slow part that lasts a long time counts for more.

Worked example 16.4.6
Change 72 km/h into m/s.

Method. Change kilometres to metres and hours to seconds. 1 km = 1000 m and 1 hour = 3600 seconds.

  1. Change the kilometres to metres. Metres are smaller than km, so multiply by 1000.
    72 km = 72 × 1000 = 72,000 m
    so 72 km/h = 72,000 metres per hour
  2. Change the hour to seconds. 1 hour = 60 × 60 = 3600 seconds. In one second the car goes 3600 times less far, so divide by 3600.
    72,000 ÷ 3600 = 20 metres per second
  3. Write the answer.
    72 km/h = 20 m/s

Check. Shortcut: km/h ÷ 3.6 gives m/s: 72 ÷ 3.6 = 20. ✓

Watch out. You are dividing by 3600 for the time but multiplying by 1000 for the distance. Both parts are needed.

Worked example 16.4.7
A car travels (3x + 6) km in (x + 2) hours. Show that its average speed is the same whatever the value of x.

Method. Use speed = distance ÷ time, then factorise the top of the fraction to cancel.

  1. Write the formula. Average speed = distance ÷ time.
    speed = 3x + 6x + 2
  2. Factorise the top. 3x + 6 has a common factor of 3.
    3x + 6 = 3(x + 2)
  3. Cancel the common bracket. The top and bottom both contain (x + 2), so it cancels (divide top and bottom by it).
    3(x + 2)x + 2 = 3
  4. Write the conclusion. The answer has no x in it.
    The speed is always 3 km/h.

Check. Try x = 4: distance = 18 km, time = 6 hours, 18 ÷ 6 = 3 km/h. Try x = 10: 36 ÷ 12 = 3. ✓

Watch out

Check the units before you calculate. 30 minutes is 0.5 hours, not 30 hours and not 0.30. And average speed is not (speed 1 + speed 2) ÷ 2. Always use total distance ÷ total time.

Exercise 16E  Speed, distance and time

Calculator allowed
1
FWork out the average speed in each case.
(a)120 km in 2 hours
(b)90 miles in 1.5 hours
(c)200 m in 25 seconds
(d)15 km in 30 minutes (give the speed in km/h)
(e)450 km in 5 hours
(f)18 miles in 45 minutes (give the speed in mph)
2
FWork out the distance travelled in each case.
(a)60 km/h for 3 hours
(b)40 mph for 2.5 hours
(c)8 m/s for 15 seconds
(d)80 km/h for 12 minutes
(e)36 km/h for 45 minutes
(f)72 km/h for 15 minutes
3
FWork out the time taken in each case. Give times in hours and minutes where sensible.
(a)180 km at 60 km/h
(b)150 miles at 40 mph
(c)100 m at 8 m/s
(d)90 km at 36 km/h
(e)45 km at 30 km/h
(f)270 km at 72 km/h
4
PSA train leaves Penford at 09:15 and travels 210 km at an average speed of 84 km/h. At what time does it arrive?
5
PSCar A travels 150 km in 2 hours. Car B travels 200 km in 2.5 hours. Which car has the greater average speed?
6
RZoe says: “If I double my speed, the time my journey takes will be halved.” Is she correct? Give an example to support your answer.
7
PSUsain runs 100 m in 9.58 seconds. Work out his average speed in m/s, to 2 decimal places.
8
PSJoe cycles at 15 km/h for 2 hours 24 minutes. How far does he cycle?
9
RWhich of these is a sensible average speed for a person riding a bicycle: 5 km/h, 20 km/h or 200 km/h? Give a reason.
10
PSA bus travels at an average speed of 30 mph. How many minutes does it take to travel 12 miles?
11
PSA ferry leaves port at 13:40 and arrives at 15:10. The crossing is 36 miles. Work out the average speed in mph.
12
RA car travels (3x + 6) km in (x + 2) hours, where x is greater than 0. Show that its speed is constant and find it.
13
PSDilara wants to drive 240 km in 3 hours 20 minutes at a constant speed. Work out the speed she needs to drive at.
14
RTwo cyclists start 90 km apart and ride towards each other along the same road. Amy cycles at 18 km/h and Ben cycles at 12 km/h. (a) How long until they meet? (b) How far has Amy ridden when they meet?
(a)Time until they meet
(b)Distance Amy rides

Exercise 16F  Average speed and changing speed units

Calculator allowed
1
FChange each speed to m/s.
(a)36 km/h
(b)54 km/h
(c)90 km/h
(d)144 km/h
2
FChange each speed to km/h.
(a)5 m/s
(b)12 m/s
(c)25 m/s
(d)40 m/s
3
FWork out the average speed (in km/h) for each journey.
(a)24 km in 30 minutes, then 36 km in 30 minutes
(b)20 km in 24 minutes, then 30 km in 36 minutes
(c)30 km in 45 minutes, then 10 km in 15 minutes
(d)45 km in 30 minutes, then 25 km in 30 minutes
4
PSA coach leaves at 09:00 and arrives at 11:30. It travels 135 miles and has a 30 minute stop on the way. Work out (a) the average speed for the whole journey, (b) the average speed while moving.
(a)Whole journey
(b)While moving
5
PSA car travels 40 km at 50 km/h and then 60 km at 120 km/h. Work out the average speed for the whole journey, to 1 decimal place.
6
RRavi drives to his grandmother at an average speed of 60 km/h and returns along the same road at 40 km/h. He says his average speed for the whole round trip is 50 km/h. Show that he is wrong.
7
PSA sprinter runs at 10 m/s. A car is travelling at 40 km/h. Which is faster?
8
PSYou see lightning and hear the thunder 6 seconds later. Sound travels at 340 m/s. How far away was the lightning? Give your answer in kilometres.
9
PSA speed camera measures a car travelling 600 m in 40 seconds. The speed limit is 50 km/h. Is the car breaking the limit? Show your working.
10
RShow that a speed of 4 m/s is equal to 14.4 km/h.
11
PSA runner runs 5 km in 24 minutes at a steady speed. (a) Work out her speed in km/h. (b) How long would she take to run 10 km at the same speed?
(a)Speed
(b)Time for 10 km
12
RShow that a speed of v km/h is the same as 5v18 m/s.
13
RA train 200 m long passes a signal pole in 8 seconds at a steady speed. (a) Work out the speed of the train in m/s and in km/h. (b) The train then takes 24 seconds to completely cross a bridge. How long is the bridge?
(a)Speed
(b)Bridge length
16.5

Density and pressure

Edexcel 1MA1: R1, R11
Grade 4-7

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Density and pressureComing soon

Density is another compound measure. It tells you how much mass is packed into each unit of volume. A block of iron and a block of wood of the same size do not have the same mass, because iron has a greater density. Density = mass ÷ volume, and the usual units are g/cm³ (grams per cubic centimetre) or kg/m³. Water has a density of 1 g/cm³, so 1 cm³ of water has a mass of 1 g. Materials with a density less than 1 g/cm³ float on water.

MDV
Density triangle: M = mass, D = density, V = volume. Cover what you want.

Cover M and you see D next to V: mass = density × volume. Cover D: density = mass ÷ volume. Cover V: volume = mass ÷ density. This works the same way as the speed triangle: only the names have changed. Keep the units matching: grams with cm³ give g/cm³, kilograms with m³ give kg/m³.

Pressure

Pressure measures how concentrated a force is. A force is a push or pull, measured in newtons (N). If you spread the same force over a bigger area the pressure is smaller. That is why snow shoes stop you sinking into snow, and why a sharp knife cuts better than a blunt one: the same force acts on a much smaller area. Pressure = force ÷ area, measured in N/m² (newtons per square metre, also called pascals, Pa) or N/cm².

FPA
Pressure triangle: F = force, P = pressure, A = area.

The formulae are pressure = force ÷ area, force = pressure × area and area = force ÷ pressure. Again, match the units: N with m² gives N/m², and N with cm² gives N/cm².

Changing the units of density and pressure (Higher)

To change g/cm³ to kg/m³, change the mass unit (g → kg is ÷ 1000) and the volume unit (cm³ → m³ is ÷ 1 000 000). Dividing by 1000 and then dividing by 1 000 000 on the bottom makes the number 1000 times bigger overall, so 1 g/cm³ = 1000 kg/m³. Similarly 1 N/cm² = 10 000 N/m², because there are 10 000 cm² in 1 m².

Key ideas

  • Density = mass ÷ volume; mass = density × volume; volume = mass ÷ density.
  • Pressure = force ÷ area; force = pressure × area; area = force ÷ pressure.
  • Match the units (g with cm³, kg with m³, N with m² or cm²).
  • Water has density 1 g/cm³. Less than that floats, more sinks.
Worked example 16.5.1
A metal block has mass 450 g and volume 50 cm³. Work out its density.

Key words. Density tells you how much mass there is in each unit of volume. A material with a high density, like iron, is heavy for its size. Mass is the amount of matter (in g or kg); volume is the space it takes up.

Method. Use the formula triangle for mass, density and volume: mass = density × volume. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the mass (450 g) and the volume (50 cm³).
    We want the density.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    density = mass ÷ volume
  3. Put the numbers in and calculate. Use the values with matching units.
    density = 450 ÷ 50 = 9
  4. Write the answer with its unit. The unit is g/cm³.
    density = 9 g/cm³

Check. Work backwards: 9 × 50 = 450 (the mass). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.5.2
Aluminium has density 2.7 g/cm³. Work out the mass of 40 cm³ of aluminium.

Key words. Density tells you how much mass there is in each unit of volume. A material with a high density, like iron, is heavy for its size. Mass is the amount of matter (in g or kg); volume is the space it takes up.

Method. Use the formula triangle for mass, density and volume: mass = density × volume. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the density (2.7 g/cm³) and the volume (40 cm³).
    We want the mass.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    mass = density × volume
  3. Put the numbers in and calculate. Use the values with matching units.
    mass = 2.7 × 40 = 108
  4. Write the answer with its unit. The unit is g.
    mass = 108 g

Check. Work backwards: 108 ÷ 40 = 2.7 (the density). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.5.3
A liquid has density 0.8 g/cm³. What volume has a mass of 56 g?

Key words. Density tells you how much mass there is in each unit of volume. A material with a high density, like iron, is heavy for its size. Mass is the amount of matter (in g or kg); volume is the space it takes up.

Method. Use the formula triangle for mass, density and volume: mass = density × volume. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the mass (56 g) and the density (0.8 g/cm³).
    We want the volume.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    volume = mass ÷ density
  3. Put the numbers in and calculate. Use the values with matching units.
    volume = 56 ÷ 0.8 = 70
  4. Write the answer with its unit. The unit is cm³.
    volume = 70 cm³

Check. Work backwards: 0.8 × 70 = 56 (the mass). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.5.4
A force of 600 N acts on an area of 0.5 m². Work out the pressure.

Key words. Force is a push or pull, measured in newtons (N). Pressure tells you how much force is acting on each unit of area. The same force on a small area gives a large pressure.

Method. Use the formula triangle for force, pressure and area: force = pressure × area. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the force (600 N) and the area (0.5 m²).
    We want the pressure.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    pressure = force ÷ area
  3. Put the numbers in and calculate. Use the values with matching units.
    pressure = 600 ÷ 0.5 = 1200
  4. Write the answer with its unit. The unit is N/m².
    pressure = 1200 N/m²

Check. Work backwards: 1200 × 0.5 = 600 (the force). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.5.5
The pressure under a shoe is 25 N/cm². The area is 12 cm². Work out the force.

Key words. Force is a push or pull, measured in newtons (N). Pressure tells you how much force is acting on each unit of area. The same force on a small area gives a large pressure.

Method. Use the formula triangle for force, pressure and area: force = pressure × area. Cover what you want to find to see the calculation.

  1. Write down what you know and what you want. Always list the quantities with their units before you start.
    We know the pressure (25 N/cm²) and the area (12 cm²).
    We want the force.
  2. Choose the formula. Cover the quantity you want in the formula triangle. What is left tells you whether to multiply or divide.
    force = pressure × area
  3. Put the numbers in and calculate. Use the values with matching units.
    force = 25 × 12 = 300
  4. Write the answer with its unit. The unit is N.
    force = 300 N

Check. Work backwards: 300 ÷ 12 = 25 (the pressure). ✓

Watch out. Check the units match before you calculate (for example, minutes must be changed to hours if the speed is per hour).

Worked example 16.5.6
Change 8.9 g/cm³ into kg/m³.

Method. Change the mass unit and the volume unit separately.

  1. Change 8.9 g to kg. Grams to kg: divide by 1000.
    8.9 g = 0.0089 kg
  2. Change 1 cm³ to m³. 1 m³ = 1 000 000 cm³, so 1 cm³ is one millionth of a m³.
    1 cm³ = 0.000 001 m³
  3. Divide mass by volume. 0.0089 kg in 0.000 001 m³ means 1 000 000 times as many per m³.
    0.0089 × 1 000 000 = 8900 kg/m³

Check. The shortcut 1 g/cm³ = 1000 kg/m³ gives 8.9 × 1000 = 8900. ✓

Watch out. Remember the shortcut: g/cm³ × 1000 = kg/m³. Water is 1 g/cm³ = 1000 kg/m³.

Watch out

Check which quantity you are finding before you divide. Density is mass divided by volume, not volume divided by mass. If your density for a solid comes out as 0.02 or 500, check you have the right way round and the units match.

Exercise 16G  Density and pressure

Calculator allowed
1
FWork out the density of each object, in g/cm³.
(a)mass 120 g, volume 40 cm³
(b)mass 780 g, volume 100 cm³
(c)mass 90 g, volume 120 cm³
(d)mass 2700 g, volume 1000 cm³
2
FWork out the mass of each object.
(a)density 8 g/cm³, volume 25 cm³
(b)density 2.5 g/cm³, volume 60 cm³
(c)density 0.9 g/cm³, volume 200 cm³
(d)density 19.3 g/cm³, volume 10 cm³
3
FWork out the volume of each object.
(a)mass 360 g, density 9 g/cm³
(b)mass 56 g, density 0.8 g/cm³
(c)mass 5400 g, density 2.7 g/cm³
(d)mass 193 g, density 19.3 g/cm³
4
FWork out the pressure in each case.
(a)force 500 N on an area of 2 m²
(b)force 90 N on an area of 3 cm²
(c)force 1200 N on an area of 0.4 m²
(d)force 48 N on an area of 16 cm²
5
FWork out the force in each case.
(a)pressure 15 N/cm², area 6 cm²
(b)pressure 200 N/m², area 3.5 m²
(c)pressure 8 N/cm², area 25 cm²
6
FWork out the area in each case.
(a)force 600 N, pressure 150 N/m²
(b)force 72 N, pressure 6 N/cm²
(c)force 2000 N, pressure 500 N/m²
7
PSA solid block is a cuboid 5 cm by 4 cm by 3 cm. Its mass is 468 g. Work out its density.
5 cm3 cm4 cm
8
PSGold has a density of 19.3 g/cm³. A gold bar has volume 250 cm³. Work out the mass of the bar in kilograms.
9
RA block of wood has mass 450 g and volume 500 cm³. Water has density 1 g/cm³. Will the block float or sink? Give a reason.
10
PSObject A has mass 240 g and volume 80 cm³. Object B has mass 150 g and volume 60 cm³. Which object is made from the denser material?
11
PSA girl has a weight (force) of 500 N. Each of her feet has an area of 200 cm². Work out the pressure on the ground in N/cm² when she stands (a) on two feet, (b) on one foot.
(a)Two feet
(b)One foot
12
RA person of weight 600 N wears either flat shoes (contact area 100 cm² in total) or stiletto heels (contact area 1 cm² in total). Compare the pressure on the floor and explain why stilettos can damage a wooden floor.
13
RA swimming pool is 10 m long, 5 m wide and 2 m deep and is full of water. Water has density 1000 kg/m³. Work out the mass of the water in tonnes.
14
FCopper has density 8.9 g/cm³. Write this in kg/m³.
15
R200 cm³ of liquid A (density 0.8 g/cm³) is mixed with 300 cm³ of liquid B (density 1.2 g/cm³). Work out the density of the mixture, assuming the volumes just add.
16
PSA pressure of 3 N/cm² acts on a surface. Write this pressure in N/m².
16.6

Rates of pay, unit prices and best buys

Edexcel 1MA1: R1, R11
Grade 2-5

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Rates of pay, unit prices and best buysComing soon

A rate compares two different quantities by saying how much of one there is for one of the other. £9.50 per hour, 45p per litre, 12 litres per minute and 3000 people per km² are all rates. The word “per” means “for each” (or “divided by”). Rates are compound measures, like speed and density, and you use them with multiplication and division.

Rates of pay

Pay = rate of pay (per hour) × hours worked. Overtime is extra hours beyond the normal hours and is often paid at a higher rate: “time and a half” means 1.5 times the normal rate and “double time” means 2 times. Work out the normal pay and the overtime pay separately, then add them.

Unit pricing and best buys

To find the best value, compare the price of the same amount each time. The unit price is the cost of one unit (one gram, 100 g, one litre, one egg). Divide the price by the quantity; if the answer is a tiny number (0.4p per gram) scale up to a friendlier amount such as 100 g. The smallest unit price is the best buy. You can also compare how much you get for the same money: more grams per pound is better.

The unitary method

If you know the cost of 5 pens you can find the cost of 8: first work out the cost of one (divide) then multiply. This is the same unitary method from Chapter 15. It works whenever two quantities are in a fixed rate, such as price and number of items.

Changing the units of a rate

You can change the units of a rate in the same way as for speed. For example £2.40 per kg is 240p per 1000 g, which is 24p per 100 g. Work in two stages: change the money unit, then the quantity unit. Watch out when the quantity is on the bottom: if you change 1 kg into 1000 g, the price for each gram becomes 1000 times smaller.

Key ideas

  • Pay = rate × hours. Overtime: work out the normal and overtime pay separately and add.
  • Unit price = price ÷ quantity. Lowest unit price is the best buy.
  • Compare the same quantity (per 100 g, per litre, per item) and use the same units.
  • Unitary method: find the value for 1, then multiply.
Worked example 16.6.1
Dev is paid £9.20 an hour. One week he works 35 hours at the normal rate and 6 hours overtime at time and a half. Work out his total pay.

Key words. A rate compares two different quantities, such as pounds per hour. Overtime is extra hours worked, often paid at a higher rate.

Method. Total pay = rate of pay per hour × number of hours (work out overtime separately).

  1. Pay for the normal hours. Rate of pay means pay per hour. Multiply the rate by the hours.
    £9.20 × 35 = £322
  2. Find the overtime rate. Overtime is paid at 1.5 times the normal rate (this is "time and a half").
    £9.20 × 1.5 = £13.80 per hour
  3. Pay for the overtime hours.
    £13.80 × 6 = £82.80
  4. Add the two amounts.
    £322 + £82.80 = £404.80

Check. Round numbers: about £9 × 41 = £369, close to £404.80. ✓

Watch out. Overtime hours are paid at the higher rate only for the extra hours, not for all hours.

Worked example 16.6.2
Which is the better buy: Pack A, 450 g for £1.89, or Pack B, 750 g for £2.60?

Key words. Unit price is the cost of one unit (1 g, 100 g, 1 kg, 1 litre). A best buy is the option with the lowest unit price.

Method. Best value means the lowest cost for the same amount. Work out the cost of 100 g for each, then compare.

  1. Find the cost per 100 g for Pack A. To compare fairly we need the same amount each time. Divide the price by the quantity, then scale to 100 g.
    189p ÷ 450 × 100 = 42p per 100 g
  2. Find the cost per 100 g for Pack B. To compare fairly we need the same amount each time. Divide the price by the quantity, then scale to 100 g.
    260p ÷ 750 × 100 = 34.6667p per 100 g ≈ 34.67p
  3. Compare the unit costs. The smallest cost per unit is the best value.
    Pack A: 42p, Pack B: 34.67p
    The lowest is Pack B.

Check. Another way: work out how much you get for 1p (or £1) each time; the biggest amount is the best buy. The same item wins. ✓

Watch out. The biggest pack is not always the cheapest per unit, and the lowest price is not always the best value.

Worked example 16.6.3
5 pens cost £3.50. Work out the cost of 8 pens.

Method. Unitary method: first find the value for ONE, then multiply to get the amount you need.

  1. Write down the rate you know. The same rate applies to every amount, so the amount for one can be found from any known amount.
    5 pens goes with £3.50
  2. Find the cost for one pen. Dividing by 5 gives the amount for 1.
    £3.50 ÷ 5 = £0.70
  3. Multiply by 8. We want 8 lots of one pen.
    £0.70 × 8 = £5.60

Check. Compare with the original: 8 pens is 1.6 times 5 pens, so the cost is 1.6 times £3.50 = £5.60. ✓

Watch out. Divide by the quantity you were given first, then multiply by the quantity you want.

Worked example 16.6.4
Petrol costs £1.50 per litre. A car uses 6.5 litres of petrol per 100 km. Work out the cost of petrol for a 260 km journey.

Method. Find how many litres are used, then multiply by the cost per litre.

  1. Find how many lots of 100 km there are. The fuel use is given per 100 km.
    260 ÷ 100 = 2.6
  2. Find the litres used. Each 100 km uses 6.5 litres.
    2.6 × 6.5 = 16.9 litres
  3. Find the cost. Cost = litres × price per litre.
    16.9 × 1.50 = £25.35

Check. Rough check: 260 km is about 17 litres; 17 × £1.50 = £25.50. ✓

Watch out. Check which quantity the rate is “per”. Here it is per 100 km, not per km.

Worked example 16.6.5
Change £2.40 per kg into pence per 100 g.

Method. Change the money to pence and the mass to 100 g units.

  1. Change pounds to pence. £1 = 100p.
    £2.40 = 240p, so 240p per kg
  2. Change 1 kg to 100 g units. 1 kg = 1000 g = 10 lots of 100 g. The same 240p now buys 10 lots, so each 100 g costs 10 times less.
    240 ÷ 10 = 24p per 100 g
  3. Write the answer. Give the new units.
    24p per 100 g

Check. 10 lots of 100 g at 24p each is 240p = £2.40 for 1 kg. ✓

Watch out. When the quantity on the bottom gets bigger, the unit price gets smaller. Divide, do not multiply.

Watch out

The biggest pack is not always the cheapest per unit, and the cheapest pack is not always the best value for you. Always compare the price for the same quantity. Make sure both quantities are in the same units (grams with grams) before you divide.

Exercise 16H  Rates of pay, unit prices and best buys

Calculator allowed
1
FWork out the total pay.
(a)£8.40 per hour for 25 hours
(b)£11.50 per hour for 36 hours
(c)£10.25 per hour for 40 hours
(d)£9 per hour for 35 hours normal pay plus 5 hours overtime at time and a half
2
FUse the unitary method to work out each cost.
(a)6 apples cost £2.70. Find the cost of 10 apples.
(b)8 pens cost £5.20. Find the cost of 5 pens.
(c)12 eggs cost £3.00. Find the cost of 30 eggs.
(d)15 litres of petrol cost £22.50. Find the cost of 40 litres.
3
FWhich is the better buy? Work out the cost per unit for each and compare.
(a)Cereal: A 375 g for £1.50, or B 750 g for £2.85 (compare the cost per 100 g)
(b)Shampoo: A 250 ml for £1.80, B 400 ml for £2.60, C 500 ml for £3.50 (cost per 100 ml)
(c)Eggs: 6 for £1.74, 12 for £3.24, 15 for £4.20 (cost per egg)
4
PSA car uses 6.5 litres of petrol per 100 km. Petrol costs £1.50 per litre. Work out the cost of petrol for a 260 km journey.
5
PSA tap fills a bath at a rate of 12 litres per minute. The bath needs 90 litres. How long does it take? Give your answer in minutes and seconds.
6
FWrite £3.60 per kg as pence per 100 g.
7
PSPriya earns £18 720 a year. She works 36 hours a week for 52 weeks a year. Work out her pay per hour.
8
RTom says: “A bigger pack is always cheaper per gram.” Give an example that shows he is wrong.
9
PSA town has 54 000 people living in an area of 18 km². (a) Work out the population density in people per km². (b) A second town has the same population density and an area of 45 km². How many people live there?
(a)Density
(b)People in second town
10
PSPaint covers 12 m² per litre. A wall is 5.5 m long and 2.4 m high and needs two coats. How many 1-litre tins of paint are needed?
11
PSAn appliance uses 2.5 kilowatts (kW) of power. It is used for 3 hours. Electricity costs 28p per kilowatt-hour (kWh), where kWh = kW × hours. Work out the cost.
12
RBrand X sells 500 ml of juice for £1.10 with “20% extra free”. Brand Y sells 450 ml for 90p. Which brand is better value?
13
PSA plumber charges £48 for the first hour and £31 for each further hour. How much does a job lasting 4.5 hours cost?
14
RA pack of n pencils costs £p. (a) Write an expression for the cost of one pencil in pence. (b) A second pack has 3n pencils and costs £2.4p. Show that the second pack is better value.
(a)Cost of one pencil
(b)Show better value
15
RRaj is paid £12 an hour for the first 35 hours each week, and time and a half for any hours after that. One week he is paid £528. How many hours did he work?
16.7

Direct and inverse proportion

Edexcel 1MA1: R10, R13
Grade 3-7

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Direct and inverse proportionComing soon

Two quantities are in direct proportion when they increase or decrease at the same rate: if one doubles, the other doubles; if one is halved, the other is halved. The cost of fuel and the number of litres bought is a good example: 20 litres cost twice as much as 10 litres. The key fact is that the ratio (y ÷ x) is always the same number.

That fixed number is the constant of proportionality, called k. Here, k is the price of one litre. The relationship is written y = kx, and we say “y is directly proportional to x” or y ∝ x. To test a table of values for direct proportion, work out y ÷ x for every column: they must all be equal.

Litres, x10203550
Cost (£), y14284970
y ÷ x1.41.41.41.4
Every ratio y ÷ x is 1.4, so the cost is directly proportional to the litres: y = 1.4x.

Two ways to solve a direct proportion problem

Unitary method: find the value for one, then multiply. Equation method: use a known pair to find k (k = y ÷ x), write y = kx, then substitute. The equation method is the best for algebra, and it is the one you need for Higher problems.

Inverse proportion

Two quantities are in inverse proportion when one increases as the other decreases in such a way that if one doubles the other is halved. More workers finish a job in fewer days; a faster speed gives a shorter time for the same distance; sharing a prize among more people gives each person less. In inverse proportion the product x × y is always the same number k. We write y = k ÷ x, and say “y is inversely proportional to x”, which means y is proportional to 1/x.

Workers, n12346
Days, d126432
n × d1212121212
Every product is 12, so the days are inversely proportional to the workers: d = 12 ÷ n.

Spot the difference

Direct: y = kx. Both go up together, and the graph is a straight line through the origin. Inverse: y = k/x. As one goes up the other goes down, and the graph is a curve. Be careful: not every pair that both increase is proportional. A taxi that charges a fixed fee plus a price per mile is not directly proportional to distance, because doubling the distance does not double the cost.

Key ideas

  • Direct proportion: y = kx, so y ÷ x is constant; doubling x doubles y.
  • Inverse proportion: y = k ÷ x, so x × y is constant; doubling x halves y.
  • To solve: use a known pair to find k, write the equation, then substitute.
  • A graph that does not go through the origin is not direct proportion.
Worked example 16.7.1
Is y directly proportional to x? x: 2, 3, 5 and y: 6, 9, 15.

Method. Test for directly proportional: check that y ÷ x is the same for every pair.

  1. Work out y ÷ x for every pair. In direct proportion this ratio is always the same number (the constant k).
    6 ÷ 2 = 3
    9 ÷ 3 = 3
    15 ÷ 5 = 3
  2. Compare the answers. If they are all equal the quantities are proportional; if even one is different they are not.
    The answers are all the same.
  3. State the conclusion.
    Yes, directly proportional (k = 3)

Check. A graph of a directly proportional relation is a straight line through (0, 0); an inverse one is a curve that never touches the axes.

Watch out. A table can go up steadily and still not be proportional. Check the ratio (or product) for every column.

Worked example 16.7.2
Is y directly proportional to x? x: 1, 2, 3 and y: 3, 5, 7.

Method. Test for directly proportional: check that y ÷ x is the same for every pair.

  1. Work out y ÷ x for every pair. In direct proportion this ratio is always the same number (the constant k).
    3 ÷ 1 = 3
    5 ÷ 2 = 2.5
    7 ÷ 3 = 73
  2. Compare the answers. If they are all equal the quantities are proportional; if even one is different they are not.
    The answers are not all the same.
  3. State the conclusion.
    No, not directly proportional

Check. A graph of a directly proportional relation is a straight line through (0, 0); an inverse one is a curve that never touches the axes.

Watch out. A table can go up steadily and still not be proportional. Check the ratio (or product) for every column.

Worked example 16.7.3
A recipe for 4 people uses 300 g of flour. How much flour is needed for 10 people?

Method. Unitary method: first find the value for ONE, then multiply to get the amount you need.

  1. Write down the rate you know. The same rate applies to every amount, so the amount for one can be found from any known amount.
    4 people goes with 300 g
  2. Find the flour for one person. Dividing by 4 gives the amount for 1.
    300 g ÷ 4 = 75 g
  3. Multiply by 10. We want 10 lots of one person.
    75 g × 10 = 750 g

Check. Compare with the original: 10 people is 2.5 times 4 people, so the flour is 2.5 times 300 g = 750 g. ✓

Watch out. Divide by the quantity you were given first, then multiply by the quantity you want.

Worked example 16.7.4
y is directly proportional to x. When x = 4, y = 20. Find y when x = 7.

Key words. The constant of proportionality k is the fixed number that links the two quantities. ∝ means “is proportional to”.

Method. For a proportion problem: write the equation with k, use the known pair to find k, then use the equation to answer the question.

  1. Write the proportion as an equation with a constant k. "y is directly proportional to x" means y ∝ x. A proportion sign always turns into an equals sign with a multiplier k (the constant of proportionality).
    y = kx
  2. Use the known pair to find k. Put x = 4 and y = 20 into the equation, then solve for k.
    20 = k × 4
    k = 20 ÷ 4 = 5
  3. Write the equation with the value of k. Now the equation links every pair of values.
    y = 5x
  4. Substitute x = 7. We want y when x is 7.
    y = 5 × 7 = 35
  5. Write the answer.
    y = 35

Check. For the new pair, 35 ÷ 7 = 5, the same constant k. ✓

Watch out. In direct proportion the ratio y ÷ x is always the same number, k.

Worked example 16.7.5
The number of days d a job takes is inversely proportional to the number of workers n. With 6 workers the job takes 10 days. How many days does it take with 4 workers?

Key words. The constant of proportionality k is the fixed number that links the two quantities. ∝ means “is proportional to”.

Method. For a proportion problem: write the equation with k, use the known pair to find k, then use the equation to answer the question.

  1. Write the proportion as an equation with a constant k. "d is inversely proportional to n" means d ∝ 1n. A proportion sign always turns into an equals sign with a multiplier k (the constant of proportionality).
    d = kn
  2. Use the known pair to find k. Put n = 6 and d = 10 into the equation, then solve for k.
    10 = k6
    k = 10 × 6 = 60
  3. Write the equation with the value of k. Now the equation links every pair of values.
    d = 60n
  4. Substitute n = 4. We want d when n is 4.
    d = 60 ÷ 4 = 15
  5. Write the answer.
    d = 15 days

Check. For the new pair, 4 × 15 = 60, the same constant k = 60. ✓

Watch out. For inverse proportion, y goes down as x goes up, and the product is constant.

Worked example 16.7.6
p is inversely proportional to q. When q = 3, p = 8. (a) Find a formula for p in terms of q. (b) Find q when p = 2.

Key words. The constant of proportionality k is the fixed number that links the two quantities. ∝ means “is proportional to”.

Method. For a proportion problem: write the equation with k, use the known pair to find k, then use the equation to answer the question.

  1. Write the proportion as an equation with a constant k. "p is inversely proportional to q" means p ∝ 1q. A proportion sign always turns into an equals sign with a multiplier k (the constant of proportionality).
    p = kq
  2. Use the known pair to find k. Put q = 3 and p = 8 into the equation, then solve for k.
    8 = k3
    k = 8 × 3 = 24
  3. Write the equation with the value of k. Now the equation links every pair of values.
    p = 24q
  4. Substitute p = 2 and solve for q. We know p and want q, so rearrange the equation.
    2 = 24 ÷ q
    q = 24 ÷ 2 = 12
  5. Write the answer.
    q = 12

Check. For the new pair, 12 × 2 = 24, the same constant k = 24. ✓

Watch out. For inverse proportion, y goes down as x goes up, and the product is constant.

Watch out

A table can go up steadily and still not show proportion. Check the ratio (or product) in every column. And do not confuse the two types: in direct proportion you divide (y ÷ x) to find k; in inverse proportion you multiply (x × y).

Exercise 16I  Direct proportion

Calculator allowed
1
FIn each table, decide whether y is directly proportional to x. If it is, write down the value of k.
(a)x: 2, 3, 5 and y: 6, 9, 15
(b)x: 1, 2, 3 and y: 4, 8, 11
(c)x: 4, 6, 10 and y: 10, 15, 25
(d)x: 2, 4, 6 and y: 5, 8, 11
2
Fy is directly proportional to x. When x = 2, y = 6. Find y when:
(a)x = 5
(b)x = 8
(c)x = 10
3
FA recipe for 4 people uses 300 g of flour. How much flour is needed for 10 people?
4
FIn each part y is directly proportional to x. Find the missing value.
(a)When x = 3, y = 12. Find y when x = 10.
(b)When x = 5, y = 35. Find y when x = 8.
(c)When x = 8, y = 20. Find x when y = 35.
(d)When x = 6, y = 9. Find y when x = 14.
5
PSThe extension e cm of a spring is directly proportional to the force F newtons pulling it. A force of 12 N gives an extension of 3 cm. Find (a) the extension for a force of 20 N, (b) the force needed for an extension of 7.5 cm.
(a)Extension for 20 N
(b)Force for 7.5 cm
6
PSThe cost C pounds of n tickets is given by C = 12.5n. (a) What does 12.5 represent? (b) Find the cost of 8 tickets. (c) How many tickets can be bought for £200?
(a)Meaning of 12.5
(b)Cost of 8
(c)Tickets for £200
7
PSPay is directly proportional to the hours worked. For 15 hours Lena is paid £127.50. Work out (a) her pay for 22 hours, (b) the number of hours she works for pay of £204.
(a)Pay for 22 hours
(b)Hours for £204
8
PSA map is drawn so that 2 cm on the map represents 5 km on the ground. Find (a) the real distance for 7.5 cm on the map, (b) the length on the map for a real distance of 32.5 km.
(a)Real distance
(b)Map length
9
RA taxi company charges £3 plus £2 for every mile. Pat says “The cost is directly proportional to the distance.” Show that Pat is wrong.
10
RPat says “y is proportional to x because y goes up when x goes up.” The table shows x: 1, 2, 3 and y: 3, 5, 7. Is Pat correct?
11
PSPrinting 250 leaflets costs £17.50. Work out the cost of printing 600 leaflets at the same rate.
12
Ry is directly proportional to x. Show that if x is increased by 20%, then y is also increased by 20%.
13
Fy is directly proportional to x. When x = 5, y = 3. (a) Write y in terms of x. (b) Find x when y = 2.4.
(a)Equation
(b)Find x
14
PSA machine fills 360 bottles in 45 minutes. At the same rate, how many hours will it take to fill 2400 bottles?

Exercise 16J  Inverse proportion

Calculator allowed
1
FIn each table, decide whether y is inversely proportional to x. If it is, write down k.
(a)x: 1, 2, 3, 4 and y: 24, 12, 8, 6
(b)x: 2, 4, 5 and y: 10, 5, 3
(c)x: 2, 5, 10 and y: 15, 6, 3
(d)x: 1, 2, 3 and y: 10, 8, 6
2
FThe number of days d a job takes is inversely proportional to the number of workers n. With 6 workers the job takes 10 days. How many days does it take with:
(a)4 workers
(b)12 workers
(c)15 workers
(d)5 workers
3
FA journey of 180 km takes 3 hours at 60 km/h. For a fixed distance, time t hours is inversely proportional to speed v km/h. Find the time at:
(a)90 km/h
(b)45 km/h
(c)120 km/h
4
Fy is inversely proportional to x and y = 24 when x = 1. Find the missing values.
(a)Find y when x = 2
(b)Find y when x = 3
(c)Find y when x = 4
(d)Find y when x = 8
5
RSay whether each pair of quantities is in direct proportion, inverse proportion, or neither. Give a reason.
(a)The number of taps filling a bath (all the same) and the time to fill it
(b)A child's age and the child's height
(c)The time for a 100 km journey and the speed
(d)The number of people sharing £60 and the amount each gets
(e)The number of books bought and the total cost at £4.50 each
6
PSA bag of 60 sweets is shared equally between n children, so each child gets s sweets, where s is inversely proportional to n. When n = 10, s = 6. Find (a) s when n = 12, (b) n when s = 4.
(a)Sweets each for 12 children
(b)Children when each gets 4
7
Ry is inversely proportional to x. Explain what happens to y when x is multiplied by 4.
8
PSThe volume V litres of a gas is inversely proportional to the pressure P kPa. When P = 150, V = 12. Find V when P = 200.
9
Fy is inversely proportional to x. When x = 8, y = 5. Find the value of y when x = 20.
10
Fy is proportional to 1/x. When x = 0.5, y = 40. Find x when y = 16.
11
PSThe force F newtons between two magnets is inversely proportional to the distance d cm between them. When d = 4, F = 30. (a) Write a formula for F in terms of d. (b) Find F when d = 6. (c) Find d when F = 12.
(a)Formula
(b)F when d = 6
(c)d when F = 12
12
R10 workers can build a wall in 12 days. After 4 days, 2 of the workers leave. How many more days will it take to finish the wall?

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