Year 6 Maths reasoning (SATs): Explaining patterns and checking terms
Part of the Year 6 Maths reasoning (SATs) algebra and sequences chapter. Chapter overview · whole chapter on one page
Explaining patterns and checking terms
Rule
To explain a pattern, show the difference between two terms and check it on at least three pairs.
To say whether a number is a term, check that the difference from the first term is a whole-number multiple of the difference.
Key ideas
- Check the pattern on several pairs of terms before you explain it.
- A number is a term only if it can be reached by adding the difference.
- One counter-example is enough to show a rule is wrong.
Method. Check the difference between each pair of terms.
- Differences. 4 - 2 = 2, but 8 - 4 = 4 and 16 - 8 = 8.2, 4, 8
- Decide. The differences are not the same, so the sequence does not go up by 2 each time.no
- Write the answer. no
Check. The differences 2, 4, 8 are not equal. ✓
Method. Check whether the difference from the first term is a multiple of the difference.
- Find the difference from the first term. 17 - 2 = 15.15
- Divide by the difference. 15 / 3 = 5, a whole number.5
- Decide. So 17 is term number 6.term 6
- Write the answer. yes
Check. The terms are 2 + 3 x (whole number). ✓
Watch out. A number is in the sequence only if it can be reached by adding the difference repeatedly.
Method. Find the difference between two terms.
- Difference. 27 - 30 = -3.-3
- Rule. Each term is 3 less than the one before, so subtract 3.subtract 3
- Write the answer. subtract 3
Check. 27 - 3 = 24. ✓
Watch out
Watch out. A pattern that works for the first two terms is not always right. Check the next pair too.
Exam tip
Practice guide. Write a short explanation with the difference, the check, and the answer.
Exercise 7E Practice: explaining patterns and terms
Non-calculatorMethod. Find the difference.
- Difference. 12 - 15 = -3.-3
- Rule. Each term is 3 less, so subtract 3.subtract 3
- Write the answer. subtract 3
Check. 6 + 3 = 9. ✓
Method. Check whether the difference from the first term is a multiple of the difference.
- Find the difference from the first term. 50 - 5 = 45.45
- Divide by the difference. 45 / 3 = 15, a whole number.15
- Decide. So 50 is term number 16.term 16
- Write the answer. yes
Check. The terms are 5 + 3 x (whole number). ✓
Watch out. A number is in the sequence only if it can be reached by adding the difference repeatedly.
Method. Check whether the difference from the first term is a multiple of the difference.
- Find the difference from the first term. 100 - 7 = 93.93
- Check the division by the difference. 93 / 6 is not a whole number.not whole
- Decide. The terms never land on 100.no
- Write the answer. no
Check. The terms are 7 + 6 x (whole number). ✓
Watch out. A number is in the sequence only if it can be reached by adding the difference repeatedly.
Method. Check the difference from the first term.
- Difference. 10 - 3 = 7.7
- Divide. 7 / 4 is not a whole number, so 10 is not a term.not whole
- Write the answer. no
Check. The terms go up by 4. ✓
Method. Test each option.
- Check each option. Test each one against the rule or the calculation.
- Tick the true ones. The difference is 3, so the 4th term is 11 and the 5th term is 14.It goes up by 3 each time, The 5th term is 14
- Leave the others unticked. These do not match.The 4th term is 12, The difference is 4 are not ticked
- Write the answer. It goes up by 3 each time, The 5th term is 14
Check. Each ticked option is true. ✓
Watch out. The 4th term is 11, not 12, and the difference is 3, not 4.
Method. Use first term + (n - 1) x difference.
- Steps. The 10th term is 9 steps after 2.9 steps
- Work out. 2 + 9 x 2 = 20, not 10.20
- Write the answer. no
Check. 2 + 18 = 20. ✓
Method. Find the difference between each pair of neighbours.
- Differences. 4 - 1 = 3, 9 - 4 = 5, 16 - 9 = 7.3, 5, 7
- Decide. The differences are not the same, so it is not linear.not linear
- Write the answer. Because the differences are 3, 5, 7, which are not equal.
Check. 3, 5 and 7 are not equal. ✓
Method. Check whether 50 is a multiple of 5 as the sequence goes down.
- Difference from the first term. 58 - 8 = 50.50
- Divide. 50 / -5 = -10 steps, which means 58 is before the first term, so it is not a term.no
- Write the answer. no
Check. The sequence goes down from 8, so 58 is not reached. ✓
Method. Look at the first term.
- First term. The sequence starts at 1.1
- Conclude. So 1 is always a term.yes
- Write the answer. Yes, because the first term is 1 and it is always the first term.
Check. 1 is the first term. ✓
Method. Start at the first term and add the difference for each step after it.
- Find the first term and the difference. The first term is 1, and the difference is 2.1 and 2
- Count the steps to the nth term. The 100th term is 99 steps from the first term.100 - 1 = 99 steps
- Work out the term. Start at 1 and add 2 for each step.1 + 198 = 199
- Write the answer. 199
Check. 1 + (100 - 1) x 2 = 199. ✓
Watch out. The 1st term has 0 steps added, so the 10th term has 9 steps.