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GCSE Maths · EdexcelChapter 3 · Fractions
GCSE Maths · Fractions · Foundation · Lesson 3.5

GCSE Maths: Adding and subtracting fractions (Foundation)

Part of the GCSE Maths fractions chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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3.5

Adding and subtracting fractions

Edexcel 1MA1: N2, N8
Grade 3–4

You can only add or subtract fractions when the parts are the same size, that is, when the denominators match.

24
+
14
=
34
12 + 14 = 24 + 14 = 34

Key ideas

  • Same denominator: add (or subtract) the numerators, keep the denominator.
  • Different denominators: change to equivalent fractions with a common denominator (use the LCM), then add or subtract.
  • Mixed numbers: either add/subtract the whole numbers and fractions separately, or change to improper fractions first.
  • Always simplify your answer, and write it as a mixed number if it is larger than 1.
Worked example 3.5.1
Work out 25 + 13

Method. To add fractions, give them the same denominator, then add the numerators and keep the denominator.

  1. Read the question and decide the plan. We can only add pieces that are the same size. So first look at the type of numbers and at the denominators (the bottom numbers).
    25 + 13
  2. Find a common denominator: the LCM of 5 and 3. We can only add or subtract pieces of the same size, so the denominators must match. The lowest common multiple (LCM) is the smallest number that both denominators divide into.
    Multiples of 5: 5, 10, 15
    Multiples of 3: 3, 6, 9, 12, 15
    LCM = 15
  3. Rewrite both fractions with denominator 15. Multiply the top and the bottom by the same number so the value does not change.
    25 = 615 (× 3)
    13 = 515 (× 5)
  4. Add the numerators and keep the denominator. The denominator only tells us the size of each piece, so it stays the same.
    615 + 515 = 1115
  5. Check the answer is in its simplest form. See whether any number except 1 divides into both the top and the bottom. If not, we are finished.
    11 and 15 have no common factor except 1, so 1115 is the answer.

Check. A different route, as decimals: 0.4 + 0.3333 = 0.7333, and our answer 1115 = 0.7333. ✓

Watch out. Never add the denominators. The denominator stays the same once the pieces are the same size.

Worked example 3.5.2
Work out 56 − 38

Method. To subtract fractions, give them the same denominator, then subtract the numerators and keep the denominator.

  1. Read the question and decide the plan. We can only subtract pieces that are the same size. So first look at the type of numbers and at the denominators (the bottom numbers).
    56 − 38
  2. Find a common denominator: the LCM of 6 and 8. We can only add or subtract pieces of the same size, so the denominators must match. The lowest common multiple (LCM) is the smallest number that both denominators divide into.
    Multiples of 6: 6, 12, 18, 24
    Multiples of 8: 8, 16, 24
    LCM = 24
  3. Rewrite both fractions with denominator 24. Multiply the top and the bottom by the same number so the value does not change.
    56 = 2024 (× 4)
    38 = 924 (× 3)
  4. Subtract the numerators and keep the denominator. The denominator only tells us the size of each piece, so it stays the same.
    2024 − 924 = 1124
  5. Check the answer is in its simplest form. See whether any number except 1 divides into both the top and the bottom. If not, we are finished.
    11 and 24 have no common factor except 1, so 1124 is the answer.

Check. A different route, as decimals: 0.8333 − 0.375 = 0.4583, and our answer 1124 = 0.4583. ✓

Watch out. Subtract in the right order: the first fraction minus the second.

Worked example 3.5.3
Work out 213 + 134

Method. Add mixed numbers by adding the whole numbers and the fractions separately, then combine the two results.

  1. Split each mixed number into a whole number and a fraction. A mixed number is a whole number plus a fraction, so we can deal with the two parts one at a time.
    213 = 2 + 13
    134 = 1 + 34
  2. Add the whole numbers. Whole numbers are added in the normal way.
    2 + 1 = 3
  3. Find a common denominator for the fractions. We can only add pieces that are the same size. The LCM of 3 and 4 is the smallest number both divide into.
    Multiples of 3: 3, 6, 9, 12
    Multiples of 4: 4, 8, 12
    LCM = 12
    13 = 412 (× 4) and 34 = 912 (× 3)
  4. Add the fractions. Add the numerators and keep the denominator.
    412 + 912 = 1312
  5. Change the improper fraction to a mixed number. The fraction part is more than 1, so it contains one whole.
    13 ÷ 12 = 1 remainder 1, so 1312 = 1112
  6. Add the whole number and the mixed number. Put the two answers together.
    3 + 1112 = 4112

Check. A different route: change to improper fractions. 73 + 74 = 2812 + 2112 = 4912, and 49 ÷ 12 = 4 remainder 1, which is 4112. ✓

Watch out. If the fraction parts add up to more than 1, carry the extra whole one across to the whole numbers.

Worked example 3.5.4
Work out 314 − 123

Method. To subtract fractions, give them the same denominator, then subtract the numerators and keep the denominator.

  1. Read the question and decide the plan. We can only subtract pieces that are the same size. So first look at the type of numbers and at the denominators (the bottom numbers).
    314 − 123
  2. Change the mixed numbers to improper fractions. A mixed number is a whole number plus a fraction. Multiply the whole number by the denominator, add the numerator, and keep the denominator. This lets us calculate with a single fraction.
    314 = (3 × 4 + 1) over 4 = 134
    123 = (1 × 3 + 2) over 3 = 53
  3. Find a common denominator: the LCM of 4 and 3. We can only add or subtract pieces of the same size, so the denominators must match. The lowest common multiple (LCM) is the smallest number that both denominators divide into.
    Multiples of 4: 4, 8, 12
    Multiples of 3: 3, 6, 9, 12
    LCM = 12
  4. Rewrite both fractions with denominator 12. Multiply the top and the bottom by the same number so the value does not change.
    134 = 3912 (× 3)
    53 = 2012 (× 4)
  5. Subtract the numerators and keep the denominator. The denominator only tells us the size of each piece, so it stays the same.
    3912 − 2012 = 1912
  6. Write the improper fraction as a mixed number. The top is bigger than the bottom, so the answer is more than 1. Divide to find the whole number and the remainder.
    19 ÷ 12 = 1 remainder 7
    1912 = 1712

Check. A different route, as decimals: 3.25 − 1.6667 = 1.5833, and our answer 1712 = 1.5833. ✓

Watch out. Subtract in the right order: the first fraction minus the second.

Worked example 3.5.5
Work out 516 − 223 by subtracting the whole numbers and the fractions separately.

Method. When the fraction you are subtracting is bigger than the fraction you start with, borrow one whole from the whole number.

  1. Look at the fraction parts first. We need 16 − 23, but 23 (which is 46) is bigger than 16, so we cannot take it away yet.
    16 < 46
  2. Borrow one whole from the 5. Take 1 off the whole number 5 to get 4, and write that 1 as sixths so that it can join the fraction (1 = 6 sixths).
    516 = 4 + 66 + 16 = 476
  3. Write the second number with sixths. Both fractions need the same denominator: 6.
    223 = 246
  4. Subtract the fractions. Subtract the numerators and keep the denominator.
    76 − 46 = 36 = 12
  5. Subtract the whole numbers. Now the whole numbers are 4 and 2.
    4 − 2 = 2
  6. Put the answers together. Whole number first, then the fraction.
    212

Check. A different route: improper fractions. 316 − 166 = 156 = 52 = 212. ✓

Watch out. Do not subtract the smaller fraction from the larger one just to avoid the problem. The order matters: the second number is taken away from the first.

Worked example 3.5.6
In a club, 12 of the members play football, 15 play netball and the rest swim. What fraction of the members swim?

Method. The whole club is 1 (or 10 tenths). Add the fractions already used, then subtract the total from the whole.

  1. Decide what the whole is. Every member is in exactly one group, so the three fractions must add up to 1 whole club.
    football + netball + swimming = 1
  2. Find a common denominator. To add halves and fifths we need pieces of the same size. The LCM of 2 and 5 is 10.
    12 = 510 and 15 = 210
  3. Add football and netball. Add the numerators and keep the denominator.
    510 + 210 = 710
  4. Write 1 as tenths. A whole club is all 10 of the 10 equal parts.
    1 = 1010
  5. Subtract to find the swimmers. What is left of the club after football and netball.
    1010 − 710 = 310

Check. Add all three groups: 510 + 210 + 310 = 1010 = 1. ✓

Watch out. “The rest” means: take what has been used away from 1 whole.

Watch out

Do not add the denominators. 13 + 14 is not 27. The answer is 712.

Exercise 3E  Adding and subtracting fractions

Non-calculator
1
FWork out. Give each answer in its simplest form.
(a)27 + 37
(b)59 + 29
(c)710 − 310
(d)1112 − 512
2
FWork out.
(a)12 + 14
(b)13 + 16
(c)25 + 110
(d)34 − 18
(e)56 − 13
(f)78 − 34
3
FWork out.
(a)13 + 14
(b)25 + 13
(c)34 − 25
(d)78 − 13
(e)56 + 34
(f)45 − 310
4
FWork out. Give each answer as a mixed number or fraction in its simplest form.
(a)112 + 214
(b)325 + 112
(c)223 + 134
(d)412 − 113
(e)314 − 112
(f)516 − 223
5
PSMaya walks 23 km to the shop and then 34 km on to the park. How far does she walk altogether?
6
PSA jug holds 56 litre of juice. 14 litre is poured out. How much is left?
7
PSA plank is 312 m long. 134 m is cut off. How long is the piece that is left?
8
RDev says “13 + 14 = 27”. Explain his mistake and work out the correct answer.
9
PSIn a school, 12 of the pupils walk, 15 take the bus and the rest cycle. What fraction of the pupils cycle?
10
RChallenge. The sum of two fractions, one with denominator 3 and one with denominator 4, is 1712. Find the two fractions.

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