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GCSE Maths · EdexcelChapter 3 · Fractions
GCSE Maths · Fractions · Foundation · Lesson 3.1

GCSE Maths: Understanding fractions (Foundation)

Part of the GCSE Maths fractions chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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3.1

Understanding fractions

Edexcel 1MA1: N1, N8
Grade 1–2

A fraction describes part of a whole. The whole could be a shape, a quantity, or a group of objects. To be a fraction, the whole must be split into equal parts.

3 of 8 equal parts shaded
5 of 6 equal parts

Key ideas

  • In 38, the numerator (top) says how many parts we have. The denominator (bottom) says how many equal parts the whole is split into.
  • A unit fraction has a numerator of 1, for example 15.
  • A proper fraction is less than 1 (numerator smaller than denominator). An improper fraction is 1 or more (numerator bigger than or equal to the denominator), for example 94.
  • A fraction is also a division: 35 means 3 ÷ 5.
Worked example 3.1.1
What fraction of this shape is shaded?

Method. A fraction of a shape = (number of shaded parts) over (number of equal parts altogether).

  1. Check that the parts are equal. A fraction only makes sense when the whole is split into equal parts. Every small square here is the same size, so we can go on.
    All 12 squares are the same size.
  2. Count all the equal parts. This total goes on the bottom of the fraction. It is the denominator. The grid has 3 rows of 4 squares, so we can multiply instead of counting one by one.
    3 × 4 = 12 parts altogether
  3. Count the shaded parts. This goes on the top of the fraction. It is the numerator. Count row by row so that none is missed.
    Row 1: 2 shaded
    Row 2: 1 shaded
    Row 3: 2 shaded
    2 + 1 + 2 = 5 shaded
  4. Write the shaded parts over the total parts. Top = how many parts we have, bottom = how many equal parts the whole is split into.
    512
  5. Check whether it can be simplified. A fraction is in its simplest form if no number except 1 divides into both numbers.
    5 is a prime number and it does not divide into 12, so 512 is already in its simplest form.

Check. Count the unshaded squares: there are 7. Then 5 shaded + 7 unshaded = 12, the total, so every square has been counted exactly once. ✓

Watch out. Count all the parts for the denominator, not just the unshaded ones.

Worked example 3.1.2
Shade 23 of this bar.

Method. To shade a fraction of a bar: the denominator tells you how many equal groups to make, the numerator tells you how many groups to shade.

  1. Read the fraction. The denominator is 3, so the bar must be split into 3 equal groups. The numerator is 2, so we shade 2 of those groups.
    23: make 3 equal groups, shade 2 of them
  2. Find how many parts are in each group. The bar has 6 equal parts and we need 3 equal groups, so share the 6 parts out equally.
    6 ÷ 3 = 2 parts in each group
  3. Work out how many parts to shade. We shade 2 groups, and each group has 2 parts.
    2 × 2 = 4 parts
  4. Shade the parts. It does not matter which parts we pick, as long as 4 of the 6 are shaded.
    Shade 4 of the 6 parts.

Check. 4 parts out of 6 is 46. Divide the top and the bottom by 2: 46 = 23. This is the fraction we were asked for. ✓

Watch out. Do not shade just 2 parts. The 2 on top counts groups of parts, and each group here is 2 parts big.

Worked example 3.1.3
A bag holds 5 red, 3 blue and 2 green counters. What fraction of the counters are blue?

Method. The fraction of a group is (the number we want) over (the total number in the group).

  1. Find the total number of counters. The total goes on the bottom. It is every counter in the bag, of all colours.
    5 + 3 + 2 = 10 counters
  2. Find the number of blue counters. This is the part we want, so it goes on the top.
    3 blue counters
  3. Write the part over the total. Numerator = blue counters, denominator = all counters.
    310
  4. Check whether it can be simplified. See if any number except 1 divides into both 3 and 10.
    The factors of 3 are 1 and 3, and 3 does not divide 10, so 310 is already in its simplest form.

Check. Find the other fractions too: red 510, green 210. 510 + 310 + 210 = 1010 = 1 whole bag. ✓

Watch out. The denominator is the total of all the counters (10), not the number of the other colours (7).

Watch out

The parts must be equal. A shape cut into 4 unequal pieces does not show quarters, even if one piece is shaded.

Exercise 3A  Understanding fractions

Non-calculator
1
FWrite down the fraction of each shape that is shaded.
(a)
(b)
(c)
(d)
(e)
(f)
2
FCopy each bar and shade the fraction given.
(a)34 of a bar split into 4 parts
(b)23 of a bar split into 6 parts
(c)58 of a bar split into 8 parts
(d)35 of a bar split into 10 parts
3
FWrite down the numerator and the denominator of each fraction.
(a)59
(b)712
(c)1120
(d)13
4
FWhich of these are unit fractions?   15   25   112   34   1100
5
FWrite down the fraction marked by each letter.
01ABC
(a)A
(b)B
(c)C
6
FWrite down the fraction marked by each letter.
012PQR
(a)P
(b)Q
(c)R
7
FWrite each statement as a fraction.
(a)3 out of 7 students wear glasses
(b)4 of the 9 flowers are red
(c)A bag has 2 yellow and 7 white sweets. What fraction are yellow?
(d)5 days out of the 7 days in a week
8
FWrite each division as a fraction, and each fraction as a division.
(a)3 ÷ 5
(b)7 ÷ 8
(c)47
(d)113
9
FWrite each fraction as proper or improper.
(a)53
(b)38
(c)99
(d)127
10
PSA pizza is cut into 8 equal slices. Ali eats 3 slices and Ben eats 2 slices. What fraction of the pizza is eaten altogether? What fraction is left?
11
PSA bag contains 5 red, 3 blue and 2 green counters. Write the fraction that are (a) red (b) not green.
(a)red
(b)not green
12
RSam says “This rectangle, cut into 4 pieces of different sizes, has 14 shaded.” Explain why Sam is wrong.
13
PSThe numerator of a fraction is 3. The denominator is 4 more than the numerator. Write down the fraction.
14
RWrite down a proper fraction with a denominator of 6 which is not a unit fraction.
15
RChallenge. A fraction has a denominator that is 3 more than its numerator. It is shown by drawing 11 equal parts. What is the fraction if it is a proper fraction and the numerator is as big as possible?

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