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GCSE Maths · EdexcelChapter 11 · Sequences
GCSE Maths · Sequences and nth Term · Higher · Lesson 11.3

GCSE Maths: Position-to-term rules (Higher)

Part of the GCSE Maths sequences and nth term chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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11.3

Position-to-term rules

Edexcel 1MA1: A23
Grade 2-5

A term-to-term rule is slow if you want a term that is far along. To find the 100th term you would need the 99 terms before it. A position-to-term rule (also called the nth term) is much quicker. It lets you find a term directly from its position.

The position of a term is its place in the list: 1st, 2nd, 3rd, and so on. We use the letter n for the position. The rule is a formula with n in it. For example, “nth term = 3n + 2” means “multiply the position by 3, then add 2”. The picture shows this as a machine.

n = 4× 312+ 214
The nth term 3n + 2 as a function machine. Position 4 goes in and the 4th term, 14, comes out.

To find a term, replace n by the position number and work it out. With 3n + 2:

Position n1234
3n + 23 × 1 + 2 = 53 × 2 + 2 = 83 × 3 + 2 = 113 × 4 + 2 = 14

So the sequence is 5, 8, 11, 14, … Use BIDMAS (Chapter 1) when you work it out: brackets and powers first, then multiplying and dividing, then adding and subtracting. The most common mistakes are with powers:

Terms can be negative. For 10 − 2n the terms are 8, 6, 4, 2, 0, −2, … (n = 6 gives 10 − 12 = −2). Some nth terms are special: n² gives the square numbers 1, 4, 9, 16, …; n³ gives the cube numbers 1, 8, 27, 64, …; 2n gives the powers of 2: 2, 4, 8, 16, … You will see these in Section 11.6.

Look back at 5, 8, 11, 14 from 3n + 2. The term-to-term rule is “add 3”, and the nth term has 3n in it. That is not an accident. The number in front of n is the amount the sequence goes up each time, which is the secret of Section 11.4.

Key ideas

  • The position n is the place of the term: the first term has n = 1.
  • To find a term, replace n by the position number and work it out using BIDMAS.
  • n² = n × n, and 2n² = 2 × (n × n).
  • A position-to-term rule jumps straight to any term, such as the 50th or 100th.
Worked example 11.3.1
The nth term of a sequence is 5n − 3. Write down the first four terms.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Replace n in the formula by each position number, and work out the answer.

  1. Write the rule and say what it means. The letter n stands for the position of the term (1 for the first term, 2 for the second, and so on). To get a term, replace n by the position number.
    nth term = 5n − 3
  2. Replace n by 1 to find the 1st term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    1st term = 5 × 1 − 3 = 5 − 3 = 2
  3. Replace n by 2 to find the 2nd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    2nd term = 5 × 2 − 3 = 10 − 3 = 7
  4. Replace n by 3 to find the 3rd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    3rd term = 5 × 3 − 3 = 15 − 3 = 12
  5. Replace n by 4 to find the 4th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    4th term = 5 × 4 − 3 = 20 − 3 = 17
  6. Write the terms as a list.
    2, 7, 12, 17

Check. The terms should go up by 5 each time (the number in front of n): 5, 5, 5. ✓

Watch out. n² means n × n, not 2 × n. And the first term is when n = 1, not n = 0.

Worked example 11.3.2
The nth term of a sequence is n² + 4. Write down the first five terms.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Replace n in the formula by each position number, and work out the answer.

  1. Write the rule and say what it means. The letter n stands for the position of the term (1 for the first term, 2 for the second, and so on). To get a term, replace n by the position number.
    nth term = n2 + 4
  2. Replace n by 1 to find the 1st term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    1st term = 12 + 4 = 1 + 4 = 5
  3. Replace n by 2 to find the 2nd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    2nd term = 22 + 4 = 4 + 4 = 8
  4. Replace n by 3 to find the 3rd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    3rd term = 32 + 4 = 9 + 4 = 13
  5. Replace n by 4 to find the 4th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    4th term = 42 + 4 = 16 + 4 = 20
  6. Replace n by 5 to find the 5th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    5th term = 52 + 4 = 25 + 4 = 29
  7. Write the terms as a list.
    5, 8, 13, 20, 29

Check. The first differences are 3, 5, 7, 9; the second differences are all 2, which is 2 × 1 as expected. ✓

Watch out. n² means n × n, not 2 × n. And the first term is when n = 1, not n = 0.

Worked example 11.3.3
The nth term of a sequence is 2n² − 1. Work out the 6th term.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Replace n in the nth-term rule by the position you want.

  1. Write the rule. This formula gives the term for any position n.
    nth term = 2n2 − 1
  2. The position we want is 6, so replace n by 6. Every n in the formula becomes the same number.
    6th term = 2 × 62 − 1
  3. Work it out, doing powers first, then multiplying, then adding or subtracting. This is the BIDMAS order.
    6th term = 2 × 62 − 1 = 2 × 36 − 1 = 72 − 1 = 71
  4. Write the answer.
    The 6th term is 71.

Check. Check on a calculator: the 6th term is 71. ✓

Watch out. Substitute the position number for n. For 3n + 2 with n = 50 you work out 3 × 50 + 2 = 152, you do not multiply anything else by 50.

Worked example 11.3.4
The nth term of a sequence is 4n + 7. Work out the 100th term.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Replace n in the nth-term rule by the position you want.

  1. Write the rule. This formula gives the term for any position n.
    nth term = 4n + 7
  2. The position we want is 100, so replace n by 100. Every n in the formula becomes the same number.
    100th term = 4 × 100 + 7
  3. Work it out, doing powers first, then multiplying, then adding or subtracting. This is the BIDMAS order.
    100th term = 4 × 100 + 7 = 400 + 7 = 407
  4. Write the answer.
    The 100th term is 407.

Check. The 100th term should be the first term plus 99 steps of 4: 11 + 99 × 4 = 407. ✓

Watch out. Substitute the position number for n. For 3n + 2 with n = 50 you work out 3 × 50 + 2 = 152, you do not multiply anything else by 50.

Worked example 11.3.5
The nth term of a sequence is 20 − 3n. Write down the first six terms.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Replace n in the formula by each position number, and work out the answer.

  1. Write the rule and say what it means. The letter n stands for the position of the term (1 for the first term, 2 for the second, and so on). To get a term, replace n by the position number.
    nth term = 20 − 3n
  2. Replace n by 1 to find the 1st term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    1st term = 20 − 3 × 1 = 20 − 3 = 17
  3. Replace n by 2 to find the 2nd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    2nd term = 20 − 3 × 2 = 20 − 6 = 14
  4. Replace n by 3 to find the 3rd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    3rd term = 20 − 3 × 3 = 20 − 9 = 11
  5. Replace n by 4 to find the 4th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    4th term = 20 − 3 × 4 = 20 − 12 = 8
  6. Replace n by 5 to find the 5th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    5th term = 20 − 3 × 5 = 20 − 15 = 5
  7. Replace n by 6 to find the 6th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    6th term = 20 − 3 × 6 = 20 − 18 = 2
  8. Write the terms as a list.
    17, 14, 11, 8, 5, 2

Check. The terms should go up by −3 each time (the number in front of n): −3, −3, −3, −3, −3. ✓

Watch out. n² means n × n, not 2 × n. And the first term is when n = 1, not n = 0.

Worked example 11.3.6
The nth term of a sequence is n² − 3n + 5. Write down the first five terms.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Replace n in the formula by each position number, and work out the answer.

  1. Write the rule and say what it means. The letter n stands for the position of the term (1 for the first term, 2 for the second, and so on). To get a term, replace n by the position number.
    nth term = n2 − 3n + 5
  2. Replace n by 1 to find the 1st term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    1st term = 12 − 3 × 1 + 5 = 1 − 3 × 1 + 5 = 1 − 3 + 5 = 3
  3. Replace n by 2 to find the 2nd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    2nd term = 22 − 3 × 2 + 5 = 4 − 3 × 2 + 5 = 4 − 6 + 5 = 3
  4. Replace n by 3 to find the 3rd term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    3rd term = 32 − 3 × 3 + 5 = 9 − 3 × 3 + 5 = 9 − 9 + 5 = 5
  5. Replace n by 4 to find the 4th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    4th term = 42 − 3 × 4 + 5 = 16 − 3 × 4 + 5 = 16 − 12 + 5 = 9
  6. Replace n by 5 to find the 5th term. Work out powers first, then multiplications, then add or subtract (BIDMAS).
    5th term = 52 − 3 × 5 + 5 = 25 − 3 × 5 + 5 = 25 − 15 + 5 = 15
  7. Write the terms as a list.
    3, 3, 5, 9, 15

Check. The first differences are 0, 2, 4, 6; the second differences are all 2, which is 2 × 1 as expected. ✓

Watch out. n² means n × n, not 2 × n. And the first term is when n = 1, not n = 0.

Watch out

Replace n by the position, then follow BIDMAS. For 2n² with n = 5, square first: 2 × 25 = 50. Do not work out 2 × 5 = 10 and then square it. Also remember that the first term is n = 1, not n = 0.

Exercise 11C  Position-to-term rules

Non-calculator
1
FWrite down the first four terms of the sequence with each nth term.
(a)3n + 1
(b)5n − 2
(c)4n + 3
(d)2n − 7
(e)10n + 5
(f)6n − 1
2
FWrite down the first five terms of the sequence with each nth term.
(a)20 − 3n
(b)12 − 2n
(c)50 − 10n
(d)1 − n
3
FWrite down the first four terms of the sequence with each nth term.
(a)n2 + 1
(b)n2 − 1
(c)2n2
(d)3n2 + 2
(e)n3
(f)3n
4
FWork out the term asked for.
(a)The nth term is 4n + 7. Find the 100th term.
(b)The nth term is 3n − 5. Find the 50th term.
(c)The nth term is 9n + 4. Find the 20th term.
(d)The nth term is 100 − n. Find the 60th term.
(e)The nth term is n2 + 3. Find the 12th term.
(f)The nth term is 2n2 + 1. Find the 10th term.
5
FThe nth term of a sequence is 3n − 2. Work out the terms in positions 1, 2, 5 and 10.
6
PSA taxi charges a fixed £3 plus £2 for every mile. The cost, in pounds, of a journey of n miles is 2n + 3.
(a)Work out the cost of a 7-mile journey.
(b)Work out the cost of a 15-mile journey.
(c)Work out the cost of a 40-mile journey.
7
PSA gym charges £25 to join and then £15 a month. After n months the total cost in pounds is 15n + 25. Work out the total cost after 12 months.
8
RZoe says, “The 5th term of the sequence 2n² is 100, because 2 × 5 = 10 and 10² = 100.” What mistake has she made, and what is the correct answer?
9
RWhich of these is the nth term of the sequence 5, 8, 11, 14, …?   A 5n   B n + 4   C 3n + 2   D 3n + 5. Show how you decide.
10
RThe nth term of one sequence is n² and the nth term of another is 11n.
(a)Which is bigger, the 10th term of n² or the 10th term of 11n?
(b)Which is bigger, the 12th term of each?
11
PSA function machine does the following to the position number n: multiply by 4, then subtract 3, giving the term.
n× 44n− 34n − 3
(a)Write the nth term.
(b)Work out the 6th term.
12
PSThe nth term of a sequence is 7n − 4. Work out the sum of the 1st term and the 10th term.
13
FWrite down the first five terms of the sequence with each nth term.
(a)n2 − 3n + 5
(b)2n2 + n − 1
(c)−n2 + 10n
(d)n2 + n
14
RThe nth term of a sequence is n² − 6n + 10. Show that the 2nd term and the 4th term are equal. Find another pair of equal terms.

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