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GCSE Maths · EdexcelChapter 11 · Sequences
GCSE Maths · Sequences and nth Term · Higher · Lesson 11.6

GCSE Maths: Special sequences (Higher)

Part of the GCSE Maths sequences and nth term chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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11.6

Special sequences

Edexcel 1MA1: A24
Grade 2-6

Some sequences turn up so often that they have names. You should know them well: you will see them in non-calculator exams. Here they are, with the nth term of each.

Square numbers14916253649…
Cube numbers182764125216343…
Triangular numbers13610152128…
Powers of 2248163264128…
Powers of 1010100100010 000…

Square numbers. The nth term is n² = n × n. They are the numbers of dots in a square pattern. Cube numbers. The nth term is n³ = n × n × n. They count the small cubes in a bigger cube.

Pattern 1Pattern 2Pattern 3Pattern 4
Square numbers: 1, 4, 9, 16.
1³ = 12³ = 83³ = 27
Cube numbers: 1, 8, 27.

Triangular numbers. These count the dots in triangles with rows of 1, 2, 3, … dots: 1, 3, 6, 10, 15, … The nth term is n(n + 1) ÷ 2. Why? Put two identical triangles together and you get a rectangle that is n dots by (n + 1) dots. One triangle is half of the rectangle. Here is the idea for n = 4: two triangles of 10 dots make a 4 by 5 rectangle of 20 dots.

Pattern 1Pattern 2Pattern 3Pattern 4
Triangular numbers: 1, 3, 6, 10. The differences are 2, 3, 4, …

Powers of 2 and 10. These are made by multiplying by 2 (or by 10) each time. They are examples of geometric sequences (Section 11.7). The nth term is 2n, which means n twos multiplied together, so 25 = 2 × 2 × 2 × 2 × 2 = 32.

Fibonacci-type sequences. In a Fibonacci-type sequence you make each term by adding the two terms before it. The famous Fibonacci sequence starts 1, 1, 2, 3, 5, 8, 13, 21, … Other Fibonacci-type sequences start with different numbers, for example 2, 5, 7, 12, 19, … (2 + 5 = 7, 5 + 7 = 12, 7 + 12 = 19). To find a missing term, add the two terms before it, or work backwards by subtracting.

How to recognise them. Look at the differences and ratios. Differences 3, 5, 7, 9 (odd numbers going up by 2) mean square numbers. Differences 2, 3, 4, 5 mean triangular numbers. If each term is double the last, they are powers of 2. If each term is the sum of the two before, it is Fibonacci-type.

Key ideas

  • Squares: 1, 4, 9, 16, 25, …   nth term n²
  • Cubes: 1, 8, 27, 64, 125, …   nth term n³
  • Triangular: 1, 3, 6, 10, 15, …   nth term n(n + 1) ÷ 2
  • Powers of 2: 2, 4, 8, 16, 32, …   nth term 2n
  • Fibonacci-type: each term is the sum of the two before it.
  • Learn the first ten squares, the first five cubes and the first eight triangular numbers.
Worked example 11.6.1
Work out the 15th triangular number.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Use the nth-term rule for triangular numbers.

  1. Remember what triangular numbers are. A triangular number is the number of dots in a triangle with rows of 1, 2, 3, … dots. The nth triangular number is 1 + 2 + … + n. Two copies of the same triangle fit together to make a rectangle n by (n + 1), so one copy is half of that: n(n + 1) ÷ 2.
    nth term = n(n + 1)2
  2. Replace n by 15. We want the term in position 15, so use 15 in place of every n.
    15th term = 15 × (15 + 1) ÷ 2
  3. Work it out. Follow the order of operations: brackets, powers, multiply and divide, then add and subtract.
    15th term = 15 × (15 + 1) ÷ 2 = 15 × 16 ÷ 2 = 240 ÷ 2 = 120

Check. Add the numbers 1 to 15 directly: 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 = 120. ✓

Watch out. Multiply n by (n + 1) first, and only then divide by 2.

Worked example 11.6.2
Write down the name of the sequence 1, 8, 27, 64, … and the next two terms.

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Recognise the sequence by its differences or ratios and by comparing with the special sequences you know.

  1. Find the differences between neighbouring terms. This tells us what kind of sequence it is.
    8 − 1 = 7
    27 − 8 = 19
    64 − 27 = 37
    These are 7, 19, 37: going up by a bigger amount each time (the differences 7, 19, 37, … are not simple).
  2. Compare with the special sequences you know. It helps to know these by heart: squares 1, 4, 9, 16, 25; cubes 1, 8, 27, 64, 125; triangular numbers 1, 3, 6, 10, 15; powers of 2: 2, 4, 8, 16; powers of 10: 10, 100, 1000.
    The cube numbers are 1, 8, 27, 64, 125, 216, 343, …
    Our sequence 1, 8, 27, 64 appears in this list.
  3. Use the rule for the cube numbers to find the next 2 terms. The rule is nth term = n3.
    5th term of the cube numbers: 53 = 125
    6th term of the cube numbers: 63 = 216

Check. The next terms 125, 216 carry on the same pattern as 27, 64. ✓

Watch out. A sequence that looks like squares might be something else. Check at least three terms, and use the differences.

Worked example 11.6.3
The first two terms of a Fibonacci-type sequence are 2 and 3. Write down the first eight terms.

Key words. A sequence is a list of numbers that follow a rule. Each number is a term. The term-to-term rule tells you how to get from one term to the next.

Method. A Fibonacci-type sequence is built by adding the previous two terms.

  1. Write the first two terms. A Fibonacci-type sequence needs two starting terms.
    2, 3
  2. Add the last two terms to make each new term. In a Fibonacci-type sequence every term is the sum of the two terms before it.
    Term 3 = 2 + 3 = 5
    Term 4 = 3 + 5 = 8
    Term 5 = 5 + 8 = 13
    Term 6 = 8 + 13 = 21
    Term 7 = 13 + 21 = 34
    Term 8 = 21 + 34 = 55
  3. Write the sequence.
    2, 3, 5, 8, 13, 21, 34, 55

Check. Check the last term: 21 + 34 = 55. ✓

Watch out. Always add the last two terms, not the first two.

Worked example 11.6.4
Here is a Fibonacci-type sequence: 3, 5,  ? , 13,  ?  Find the missing terms.

Key words. A sequence is a list of numbers that follow a rule. Each number is a term. The term-to-term rule tells you how to get from one term to the next.

Method. Every term is the sum of the previous two. To find a missing term, add the two before it, or subtract to work backwards.

  1. Use the rule: each term is the sum of the two terms before it. Look for a gap where you know the two terms before it (add them) or the two terms after it (subtract).
    Terms: 3, 5, ?, 13, ?
  2. Find term 3. Term 3 is the sum of the two terms before it.
    3 + 5 = 8
  3. Find term 5. Term 5 is the sum of the two terms before it.
    8 + 13 = 21
  4. Write the complete sequence.
    3, 5, 8, 13, 21

Check. Check every term is the sum of the two before it: 3 + 5 = 8, 5 + 8 = 13, 8 + 13 = 21. ✓

Watch out. When working backwards, subtract: the missing term is the later term minus its neighbour.

Worked example 11.6.5
Here is a Fibonacci-type sequence:  ? ,  ? , 7, 11, 18. Find the first two terms.

Key words. A sequence is a list of numbers that follow a rule. Each number is a term. The term-to-term rule tells you how to get from one term to the next.

Method. Every term is the sum of the previous two. To find a missing term, add the two before it, or subtract to work backwards.

  1. Use the rule: each term is the sum of the two terms before it. Look for a gap where you know the two terms before it (add them) or the two terms after it (subtract).
    Terms: ?, ?, 7, 11, 18
  2. Find term 2. Term 4 is the sum of terms 2 and 3, so term 2 = term 4 − term 3. We are working backwards.
    11 − 7 = 4
  3. Find term 1. Term 3 is the sum of terms 1 and 2, so term 1 = term 3 − term 2. We are working backwards.
    7 − 4 = 3
  4. Write the complete sequence.
    3, 4, 7, 11, 18

Check. Check every term is the sum of the two before it: 3 + 4 = 7, 4 + 7 = 11, 7 + 11 = 18. ✓

Watch out. When working backwards, subtract: the missing term is the later term minus its neighbour.

Worked example 11.6.6
Which term of the sequence of square numbers is 144?

Key words. The position of a term is its place in the sequence: 1st, 2nd, 3rd and so on. We use the letter n for the position number. The nth term (or position-to-term rule) is a formula that gives the term for any position n.

Method. Work backwards from the term to the position.

  1. Remember the rule for square numbers. A square number is a whole number multiplied by itself. It is the number of small squares in a bigger square with that side length.
    nth term = n2
  2. Use the square root. The inverse (undo) of squaring is the square root. We need the number that multiplies by itself to give 144.
    √144 = 12, because 12 × 12 = 144
  3. Write the answer. The position is the value of n.
    144 is the 12th term of the square numbers.

Check. Substitute n = 12: 122 = 144. ✓

Watch out. The answer is the position (n), not the term. Say which one you are giving.

Watch out

n² is n × n, not 2 × n. The square numbers go 1, 4, 9, 16, but 2n goes 2, 4, 6, 8. In the same way, 2n (2, 4, 8, 16, …) is not the same as 2n or n². They only look alike at the start: all three have 4 as the second term.

Exercise 11F  Special sequences

Non-calculator
1
FWork out each of these.
(a)The 9th square number
(b)The 4th cube number
(c)The 7th triangular number
(d)The 8th power of 2
(e)The 15th square number
(f)The 6th cube number
2
FWrite down the name of each sequence and the next two terms.
(a)1, 4, 9, 16, …
(b)1, 8, 27, 64, …
(c)3, 6, 10, 15, …
(d)4, 9, 16, 25, …
(e)2, 4, 8, 16, …
(f)10, 100, 1000, …
3
FWhich term of the sequence is each number?
(a)169 in the square numbers
(b)343 in the cube numbers
(c)55 in the triangular numbers
(d)64 in the powers of 2
(e)1000 in the powers of 10
4
FThe first two terms of each Fibonacci-type sequence are given. Write down the first eight terms.
(a)1, 1, …
(b)2, 3, …
(c)1, 3, …
(d)5, 2, …
5
FEach of these is part of a Fibonacci-type sequence. Find the missing terms.
(a)3 , 5 ,  ?  , 13 ,  ? 
(b) ?  ,  ?  , 7 , 11 , 18
(c)1 ,  ?  ,  ?  , 7 , 11
(d)2 , 5 ,  ?  , 12 ,  ? 
(e) ?  ,  ?  ,  ?  , 11 , 18
6
PSTins are stacked in a triangular pile with 1 tin in the top row, 2 in the next row, 3 in the next row, and so on.
(a)How many tins are in a pile with 9 rows?
(b)A pile has 66 tins. How many rows does it have?
7
PSA cube is made from small cubes. A 5 by 5 by 5 cube is made from 125 small cubes. How many more small cubes are needed to make a 6 by 6 by 6 cube?
8
PSIn a computer game, level 1 needs 2 points, level 2 needs 4 points, level 3 needs 8 points and the number of points doubles with each level. How many points are needed for level 10?
9
RWork out the sum of each pair of consecutive triangular numbers. What do you notice?
(a)3 + 6
(b)6 + 10
(c)10 + 15
10
RIs 50 a triangular number? Give a reason.
11
RPete says that 2n and n² are the same. Show that Pete is wrong.
12
RThe first term of a Fibonacci-type sequence is x and the second term is 3. The sixth term is 36. Find the value of x.
13
RShow that no square number ends in 2, 3, 7 or 8.

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