Websink Prep UKGCSE MathsTextbook contentsMaths textbooksYear 1Year 2Year 4Year 5Year 6GCSEBrowse allPast papersFind a tutorBecome a tutor
GCSE Maths · EdexcelChapter 14 · Quadratics and simultaneous equations
GCSE Maths · Quadratic and Simultaneous Equations · Higher · Lesson 14.2

GCSE Maths: Solving quadratic equations by factorising (Higher)

Part of the GCSE Maths quadratic and simultaneous equations chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

Download worksheet (PDF)Answers (PDF)
14.2

Solving quadratic equations by factorising

Edexcel 1MA1: A18
Grade 4-6

A quadratic equation is an equation that contains an x2 term (and no higher power), for example x2 + 5x + 6 = 0. To solve it means to find the values of x that make it true. A linear equation such as 2x + 1 = 9 has one solution. A quadratic equation usually has two solutions. You can see why from its graph (Chapter 13): the curve crosses the x-axis in two places, and each crossing is a solution of the equation “expression = 0”.

xy-4-3-2-11234567-14-12-10-8-6-4-2246810
The curve y = x2 − 3x − 10 crosses the x-axis where x = −2 and x = 5. These are the two solutions of x2 − 3x − 10 = 0.

So how do we find them without drawing a graph? The key is an idea called the null factor law. Think about multiplying two numbers together. If the answer is 0, one of the numbers must have been 0, because 7 × 3 = 21, 7 × 1 = 7, and only 7 × 0 = 0. This is also true when the two things are brackets. If (x − 5)(x + 2) = 0 then either (x − 5) = 0 or (x + 2) = 0. So x = 5 or x = −2.

Most quadratics are not written as brackets, so first we have to factorise (section 14.1). The method is:

  1. Make sure the equation has 0 on one side (the null factor law only works for a product that equals 0).
  2. Factorise the other side.
  3. Set each bracket equal to 0.
  4. Solve each of the two little equations.
  5. Check both answers in the original equation.

Some special cases are worth knowing. If there is no number term, such as x2 − 5x = 0, take out the common factor x: x(x − 5) = 0, so x = 0 or x = 5. If it is a difference of two squares, such as x2 − 49 = 0, then (x − 7)(x + 7) = 0 gives x = 7 or x = −7, usually written x = ±7. And if both brackets are identical, such as (x − 3)2 = 0, there is only one solution, x = 3. This is called a repeated root; the curve just touches the x-axis.

Key ideas

  • A quadratic equation has an x2 term. It usually has two solutions (also called roots).
  • Null factor law: if A × B = 0 then A = 0 or B = 0.
  • Steps: (1) 0 on one side, (2) factorise, (3) each bracket = 0, (4) solve, (5) check.
  • Never divide by x. For x2 − 5x = 0 factorise to x(x − 5) = 0 so that you do not lose the answer x = 0.
  • The solutions of “expression = 0” are where the graph crosses the x-axis.
Worked example 14.2.1
Solve (x + 3)(x − 5) = 0.
▶ Watch this solution as a video

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. The quadratic is already written as brackets multiplied together and equal to 0.
    (x + 3)(x − 5) = 0
  2. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    (x + 3)(x − 5) = 0
    So (x − 5) = 0 or (x + 3) = 0.
  3. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x − 5 = 0
    Add 5 to both sides: x = 5

    x + 3 = 0
    Subtract 3 from both sides: x = −3
  4. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = −3 or x = 5

Check. When x = −3: ((−3) − 5)((−3) + 3) = (−8) × 0 = 0. ✓
When x = 5: (5 − 5)(5 + 3) = 0 × 8 = 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Worked example 14.2.2
Solve x2 + 7x + 12 = 0.
▶ Watch this solution as a video

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. A quadratic equation contains a squared letter. We want every value of the letter that makes the two sides equal.
    x2 + 7x + 12 = 0
  2. Check that one side is 0. We can only use the null factor law when one side of the equation is exactly 0.
    The right-hand side is already 0, so there is nothing to move.
  3. Factorise the quadratic. Factorising writes it as brackets multiplied together. Then the null factor law can be used.
    Spot the pattern. This is a quadratic of the form x² + bx + c, with b = 7 and c = 12.
    We need two numbers that multiply to 12 (the last number) and add to 7 (the middle number). List the pairs that multiply to 12:
    1 × 12 = 12,   add: 1 + 12 = 13 ✗
    -1 × -12 = 12,   add: -1 + -12 = -13 ✗
    2 × 6 = 12,   add: 2 + 6 = 8 ✗
    -2 × -6 = 12,   add: -2 + -6 = -8 ✗
    3 × 4 = 12,   add: 3 + 4 = 7 ✓ this pair works
    Put the pair into two brackets: (x + 3)(x + 4).
    Check by expanding: x² + 4x + 3x + 12 = x2 + 7x + 12. ✓
    x2 + 7x + 12 = (x + 3)(x + 4)
  4. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    (x + 3)(x + 4) = 0
    So (x + 3) = 0 or (x + 4) = 0.
  5. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x + 3 = 0
    Subtract 3 from both sides: x = −3

    x + 4 = 0
    Subtract 4 from both sides: x = −4
  6. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = −4 or x = −3

Check. When x = −4: left side = (−4)2 + 7 × (−4) + 12 = 16 − 28 + 12 = 0. It equals 0. ✓
When x = −3: left side = (−3)2 + 7 × (−3) + 12 = 9 − 21 + 12 = 0. It equals 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Worked example 14.2.3
Solve x2 − 5x = 0.
▶ Watch this solution as a video

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. A quadratic equation contains a squared letter. We want every value of the letter that makes the two sides equal.
    x2 − 5x = 0
  2. Check that one side is 0. We can only use the null factor law when one side of the equation is exactly 0.
    The right-hand side is already 0, so there is nothing to move.
  3. Factorise the quadratic. Factorising writes it as brackets multiplied together. Then the null factor law can be used.
    Look for a common factor. A common factor is something that divides into every term.
    The terms are x2, −5x. The biggest number and the highest power of x that divide into all of them is x.
    Take it outside a bracket, and inside the bracket put each term divided by it:
    x2 ÷ x = x
    −5x ÷ x = −5
    So x2 − 5x = x(x − 5).
    Check by expanding: x × (x − 5) = x × x, x × (−5) → x2 − 5x. ✓
    x2 − 5x = x(x − 5)
  4. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    x(x − 5) = 0
    So (x − 5) = 0 or x = 0.
  5. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x − 5 = 0
    Add 5 to both sides: x = 5

    x = 0
    x = 0 is a solution.
  6. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = 0 or x = 5

Check. When x = 0: left side = 02 − 5 × 0 = 0 + 0 = 0. It equals 0. ✓
When x = 5: left side = 52 − 5 × 5 = 25 − 25 = 0. It equals 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Worked example 14.2.4
Solve x2 − 81 = 0.
▶ Watch this solution as a video

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. A quadratic equation contains a squared letter. We want every value of the letter that makes the two sides equal.
    x2 − 81 = 0
  2. Check that one side is 0. We can only use the null factor law when one side of the equation is exactly 0.
    The right-hand side is already 0, so there is nothing to move.
  3. Factorise the quadratic. Factorising writes it as brackets multiplied together. Then the null factor law can be used.
    Spot the pattern. There are two terms, both are perfect squares, and there is a minus between them. This is a difference of two squares.
    The rule is: a² − b² = (a − b)(a + b).
    Find a and b. x2 = (x)², so a = x. And 81 = 9², so b = 9.
    Put them into the rule: (x − 9)(x + 9).
    Check by expanding: (x − 9)(x + 9) = x2 + 9x − 9x − 81 = x2 − 81. ✓ (the middle terms cancel)
    x2 − 81 = (x − 9)(x + 9)
  4. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    (x − 9)(x + 9) = 0
    So (x − 9) = 0 or (x + 9) = 0.
  5. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x − 9 = 0
    Add 9 to both sides: x = 9

    x + 9 = 0
    Subtract 9 from both sides: x = −9
  6. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = −9 or x = 9

Check. When x = −9: left side = (−9)2 − 81 = 81 − 81 = 0. It equals 0. ✓
When x = 9: left side = 92 − 81 = 81 − 81 = 0. It equals 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Worked example 14.2.5
Solve x2 − 6x + 9 = 0.
▶ Watch this solution as a video

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. A quadratic equation contains a squared letter. We want every value of the letter that makes the two sides equal.
    x2 − 6x + 9 = 0
  2. Check that one side is 0. We can only use the null factor law when one side of the equation is exactly 0.
    The right-hand side is already 0, so there is nothing to move.
  3. Factorise the quadratic. Factorising writes it as brackets multiplied together. Then the null factor law can be used.
    Spot the pattern. This is a quadratic of the form x² + bx + c, with b = -6 and c = 9.
    We need two numbers that multiply to 9 (the last number) and add to -6 (the middle number). List the pairs that multiply to 9:
    1 × 9 = 9,   add: 1 + 9 = 10 ✗
    -1 × -9 = 9,   add: -1 + -9 = -10 ✗
    3 × 3 = 9,   add: 3 + 3 = 6 ✗
    -3 × -3 = 9,   add: -3 + -3 = -6 ✓ this pair works
    Put the pair into two brackets: (x − 3)(x − 3).
    Check by expanding: x² − 3x − 3x + 9 = x2 − 6x + 9. ✓
    x2 − 6x + 9 = (x − 3)2
  4. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    (x − 3)2 = 0
    So (x − 3) = 0.
    A bracket that appears twice gives the same answer twice, so there is only one solution from it (a repeated root).
  5. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x − 3 = 0
    Add 3 to both sides: x = 3
  6. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = 3

Check. When x = 3: left side = 32 − 6 × 3 + 9 = 9 − 18 + 9 = 0. It equals 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Worked example 14.2.6
Solve (2x − 3)(x + 4) = 0.

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. The quadratic is already written as brackets multiplied together and equal to 0.
    (2x − 3)(x + 4) = 0
  2. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    (2x − 3)(x + 4) = 0
    So (x + 4) = 0 or (2x − 3) = 0.
  3. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x + 4 = 0
    Subtract 4 from both sides: x = −4

    2x − 3 = 0
    Add 3 to both sides: 2x = 3
    Divide both sides by 2: x = 3 ÷ 2 = 32
  4. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = −4 or x = 32

Check. When x = −4: ((−4) + 4)(2 × (−4) − 3) = 0 × (−11) = 0. ✓
When x = 32: (32 + 4)(2 × 32 − 3) = 112 × 0 = 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Worked example 14.2.7
Solve 3x2 − 27 = 0.

Key words. A quadratic equation is an equation whose highest power of the letter is 2 (it has an x2 term), like x2 + 5x + 6 = 0. To solve it means to find every value of x that makes it true. These values are called the solutions or roots. To factorise means to write it as brackets multiplied together.

Method. To solve a quadratic equation by factorising: (1) get one side equal to 0, (2) factorise, (3) use the null factor law to make each bracket equal to 0, (4) solve the little equations.

  1. Write down the equation. A quadratic equation contains a squared letter. We want every value of the letter that makes the two sides equal.
    3x2 − 27 = 0
  2. Check that one side is 0. We can only use the null factor law when one side of the equation is exactly 0.
    The right-hand side is already 0, so there is nothing to move.
  3. Factorise the quadratic. Factorising writes it as brackets multiplied together. Then the null factor law can be used.
    Look for a common factor. A common factor is something that divides into every term.
    The terms are 3x2, −27. The biggest number and the highest power of x that divide into all of them is 3.
    Take it outside a bracket, and inside the bracket put each term divided by it:
    3x2 ÷ 3 = x2
    −27 ÷ 3 = −9
    So 3x2 − 27 = 3(x2 − 9).
    Check by expanding: 3 × (x2 − 9) = 3 × x2, 3 × (−9) → 3x2 − 27. ✓
    Can the bracket be factorised again? Look at (x2 − 9).
    Spot the pattern. There are two terms, both are perfect squares, and there is a minus between them. This is a difference of two squares.
    The rule is: a² − b² = (a − b)(a + b).
    Find a and b. x2 = (x)², so a = x. And 9 = 3², so b = 3.
    Put them into the rule: (x − 3)(x + 3).
    Check by expanding: (x − 3)(x + 3) = x2 + 3x − 3x − 9 = x2 − 9. ✓ (the middle terms cancel)
    3x2 − 27 = 3(x − 3)(x + 3)
  4. Use the null factor law. The null factor law. If two numbers multiply to make 0, then at least one of them must be 0. Think about it: 7 × 0 = 0 and 0 × 12 = 0, but 7 × 12 is not 0. The same is true when the numbers are brackets: if (x + 2)(x − 5) = 0, then either the first bracket is 0 or the second bracket is 0.
    3(x − 3)(x + 3) = 0
    So (x − 3) = 0 or (x + 3) = 0.
    The number 3 in front can never be 0, so it gives no solution. Ignore it.
  5. Solve each bracket separately. Each bracket gives a very small equation of the kind you solved in Chapter 9. Use inverse operations on both sides.
    x − 3 = 0
    Add 3 to both sides: x = 3

    x + 3 = 0
    Subtract 3 from both sides: x = −3
  6. Write the solutions. Quadratics usually have two solutions (a curve crosses the x-axis twice).
    x = −3 or x = 3

Check. When x = −3: left side = 3 × (−3)2 − 27 = 27 − 27 = 0. It equals 0. ✓
When x = 3: left side = 3 × 32 − 27 = 27 − 27 = 0. It equals 0. ✓

Watch out. Do not divide both sides by x: you would lose the solution x = 0. And never set a bracket equal to a number other than 0.

Watch out

When you solve (x − 5) = 0 the answer is x = +5; for (x + 2) = 0 it is x = −2. The sign in the solution is the opposite of the sign in the bracket. And never set a bracket equal to a number other than 0: if (x − 1)(x + 4) = 10, you cannot say x − 1 = 10. You must rearrange to equal 0 first (see the next section).

Exercise 14B  Solving quadratic equations by factorising

Non-calculator
1
FSolve. These equations are already factorised.
(a)(x + 2)(x + 5) = 0
(b)(x − 3)(x + 7) = 0
(c)(x − 4)(x − 1) = 0
(d)x(x + 6) = 0
(e)(x + 8)(x − 8) = 0
(f)(x − 5)2 = 0
2
FSolve by factorising.
(a)x2 + 6x + 5 = 0
(b)x2 + 7x + 12 = 0
(c)x2 + 8x + 15 = 0
(d)x2 + 9x + 14 = 0
(e)x2 + 11x + 10 = 0
(f)x2 + 10x + 21 = 0
3
FSolve by factorising.
(a)x2 − 7x + 10 = 0
(b)x2 − 6x + 8 = 0
(c)x2 − 8x + 12 = 0
(d)x2 − 9x + 18 = 0
(e)x2 − 10x + 16 = 0
(f)x2 − 11x + 24 = 0
4
FSolve by factorising.
(a)x2 + 2x − 8 = 0
(b)x2 − x − 6 = 0
(c)x2 + 3x − 10 = 0
(d)x2 − 4x − 12 = 0
(e)x2 + x − 20 = 0
(f)x2 − 2x − 24 = 0
5
FSolve. Take out the common factor first.
(a)x2 + 3x = 0
(b)x2 − 7x = 0
(c)x2 + 10x = 0
(d)2x2 − 8x = 0
(e)3x2 + 9x = 0
(f)x2 − x = 0
6
FSolve these differences of two squares.
(a)x2 − 4 = 0
(b)x2 − 25 = 0
(c)x2 − 64 = 0
(d)x2 − 121 = 0
(e)x2 − 1 = 0
(f)x2 − 400 = 0
7
RJo solves (x − 3)(x + 2) = 0 and writes “x = 3 or x = 2”. Explain her mistake and write down the correct solutions.
8
RHow many solutions does each equation have? You do not need to find them.
(a)(x − 1)(x + 4) = 0
(b)(x − 6)2 = 0
(c)x(x − 2) = 0
(d)x2 + 4 = 0
9
PSThe graph of y = x2 − 2x − 3 is shown. Use the graph to write down the solutions of x2 − 2x − 3 = 0. Then check your answer by factorising.
xy-3-2-112345-5-4-3-2-1123456
10
PSFind the x-coordinates of the points where the curve y = x2 + 4x − 5 crosses the x-axis.
11
FSolve.
(a)x2 + 9x + 18 = 0
(b)x2 − 3x = 0
(c)x2 − 49 = 0
(d)x2 − 8x + 7 = 0
(e)x2 + 5x − 14 = 0
(f)x2 − 6x = 0
12
FSolve.
(a)(2x − 3)(x + 4) = 0
(b)(3x + 1)(x − 5) = 0
(c)(5x − 2)(2x + 7) = 0
(d)x(4x − 3) = 0
(e)(2x − 1)2 = 0
(f)(x − 2)(3 − x) = 0
13
FSolve.
(a)3x2 − 27 = 0
(b)2x2 − 50 = 0
(c)4x2 − 9 = 0
(d)25x2 − 4 = 0
(e)5x2 − 20x = 0
(f)6x2 + 9x = 0
14
RWrite down a quadratic equation, in the form x2 + bx + c = 0, whose solutions are x = 3 and x = −7.
15
RThe equation x2 + kx + 16 = 0 has exactly one solution. Find the two possible values of k.

Websink Prep UK is an independent site. It is not affiliated with, endorsed by or sponsored by AQA, Pearson Edexcel, OCR, WJEC, Eduqas, CCEA, SQA, GL Assessment, CEM or the Department for Education. All exam board names and trademarks belong to their owners. Past papers are linked from the exam boards' own websites and are not hosted here.

About Websink Prep UK · Find a tutor · Privacy · Terms · Cookie settings