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GCSE Maths · EdexcelChapter 19 · Volume, surface area and 3D shapes
GCSE Maths · Volume, Surface Area and 3D Shapes · Foundation · Lesson 19.7

GCSE Maths: Surface area of cuboids, prisms and cylinders (Foundation)

Part of the GCSE Maths volume, surface area and 3d shapes chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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19.7

Surface area of cuboids, prisms and cylinders

Edexcel 1MA1: G16, G17
Grade 3-6

The surface area of a solid is the total area of all of its faces. It tells you how much wrapping paper you need for a present, or how much paint covers a tank. Because it is an area, it is measured in square units such as cm2 or m2. Do not mix it up with volume, which is the space inside (cubic units).

The best way to find a surface area is to think of the net (Section 19.2). The net shows every face flat, so you can work out each area and add.

Cuboid. There are six rectangles in three matching pairs. Surface area = 2lw + 2lh + 2wh. For a cube with edge a all six faces are the same: surface area = 6a2.

5 cm5 cm4 cm4 cm3 cm
5 cm3 cm4 cm
A 5 cm by 4 cm by 3 cm cuboid and its net. The six rectangles are 5 × 4 (twice), 5 × 3 (twice) and 4 × 3 (twice).

Prisms. A prism has two identical end faces (the cross-section) and a rectangle along each side. Each rectangle is one edge of the cross-section multiplied by the length of the prism. So

surface area = 2 × (area of cross-section) + (perimeter of cross-section) × length

The second part works because all the rectangles have the same length, so together they make one big rectangle: the perimeter by the length.

Cylinders. The net of a cylinder is two circles and a rectangle. The rectangle wraps round the side, so its width is the circumference 2πr and its height is h.

surface area of a cylinder = 2πr2 + 2πrh

The first part is the two circles, the second part is the curved surface. If the cylinder has no lid (an open can) there is only one circle, so the surface area is πr2 + 2πrh.

2πr = circumference8 cm3 cm
8 cm3 cm
The net of a cylinder: two circles of area πr2 and a rectangle of area 2πr × h.

Key ideas

  • Surface area = total area of all the faces, in square units.
  • Cuboid: 2lw + 2lh + 2wh. Cube: 6a2.
  • Prism: 2 × (cross-section area) + (perimeter of cross-section) × length.
  • Cylinder: 2πr2 + 2πrh (curved surface 2πrh). An open cylinder has only one circle.
  • Use the net to check that you have included every face.
Worked example 19.7.1
Work out the surface area of this cuboid.5 cm3 cm4 cm

Key words. The surface area of a solid is the total area of all its faces added together. It is measured in square units (cm2), because it is an area.

Method. Surface area is the total area of all the faces. Work out the area of each face (or matching pair of faces) and add.

  1. Picture the six faces. A cuboid has 6 rectangular faces that come in 3 matching pairs: top and bottom, front and back, left and right.
  2. Top and bottom. Each is length × width.
    5 × 4 = 20  (and there are 2 of them, so 40)
  3. Front and back. Each is length × height.
    5 × 3 = 15  (2 of them: 30)
  4. Left and right. Each is width × height.
    4 × 3 = 12  (2 of them: 24)
  5. Add the three pairs. The surface area is every face added together.
    40 + 30 + 24 = 94
  6. Write the unit. Area, so square units.
    Surface area = 94 cm2

Check. Use the formula 2(lw + lh + wh) = 2 × (20 + 15 + 12) = 2 × 47 = 94. ✓

Watch out. Count every face: forgetting one pair of faces is the most common error. Give the answer in cm2, not cm3.

Worked example 19.7.2
Work out the total surface area of this triangular prism. The triangle is right-angled.3 cm5 cm4 cm10 cm

Key words. The surface area of a solid is the total area of all its faces added together. It is measured in square units (cm2), because it is an area.

Method. Surface area = the area of the two ends + the area of all the rectangular faces. Using the net helps you not to miss a face.

  1. Picture the faces. A prism has two identical ends (triangles) and a rectangle for every edge of the end: each rectangle is the edge length × the length of the prism (10 cm).
  2. Area of one triangular end. It is a right-angled triangle, so use the two shorter sides as base and height: ½ × base × height.
    ½ × 3 × 4 = 6 cm2
  3. Double it for the two ends. The two end faces are identical.
    2 × 6 = 12 cm2
  4. Find each rectangular face. Each rectangle is an edge of the end multiplied by the length of the prism.
    Rectangle on the side of length 3: 3 × 10 = 30
    Rectangle on the side of length 4: 4 × 10 = 40
    Rectangle on the side of length 5: 5 × 10 = 50
  5. Add all the faces together. Surface area = the two ends + all the rectangles.
    12 + 30 + 40 + 50 = 132
  6. Write the unit. Area, so square units.
    Surface area = 132 cm2

Check. The rectangles together make (perimeter of an end) × length = 12 × 10 = 120. Then 12 + 120 = 132. ✓

Watch out. Do not forget the two ends, and make sure each rectangle uses the edge length (not the height of the triangle).

Worked example 19.7.3
Work out the surface area of this prism, which has an L-shaped cross-section.8 cm6 cm3 cm2 cm10 cm

Key words. The surface area of a solid is the total area of all its faces added together. It is measured in square units (cm2), because it is an area.

Method. Surface area = the area of the two ends + the area of all the rectangular faces. Using the net helps you not to miss a face.

  1. Picture the faces. A prism has two identical ends (L-shapes) and a rectangle for every edge of the end: each rectangle is the edge length × the length of the prism (10 cm).
  2. Split the L-shape into two rectangles. We can only use the area formula on simple shapes, so cut the L into two rectangles.
    Bottom rectangle: 8 by 2
    Top rectangle: 3 by (6 − 2) = 3 by 4
  3. Find the area of each rectangle. Width × height each time.
    8 × 2 = 16 cm2
    3 × 4 = 12 cm2
  4. Add the two areas. The whole cross-section is the two parts together.
    A = 16 + 12 = 28 cm2
  5. Double it for the two ends. The two end faces are identical.
    2 × 28 = 56 cm2
  6. Find each rectangular face. Each rectangle is an edge of the end multiplied by the length of the prism.
    Bottom edge: 8 × 10 = 80
    Right edge: 2 × 10 = 20
    Inner horizontal edge: 5 × 10 = 50
    Inner vertical edge: 4 × 10 = 40
    Top edge: 3 × 10 = 30
    Left edge: 6 × 10 = 60
  7. Add all the faces together. Surface area = the two ends + all the rectangles.
    56 + 80 + 20 + 50 + 40 + 30 + 60 = 336
  8. Write the unit. Area, so square units.
    Surface area = 336 cm2

Check. The rectangles together make (perimeter of an end) × length = 28 × 10 = 280. Then 56 + 280 = 336. ✓

Watch out. Do not forget the two ends, and make sure each rectangle uses the edge length (not the height of the triangle).

Worked example 19.7.4
Work out the total surface area of this cylinder. Give your answer in terms of π.10 cm3 cm

Key words. The surface area of a solid is the total area of all its faces added together. It is measured in square units (cm2), because it is an area.

Method. Surface area of a cylinder = two circles + the curved surface (a rectangle).

  1. Think of the net. A cylinder opens out into two circles (top and bottom) and a rectangle. The rectangle wraps round the curved side, so its width is the circumference of the circle, 2πr, and its height is h.
  2. Area of the two circles. Area of a circle = πr2. There are two of them.
    2 × π × 32 = 18π
  3. Area of the curved surface. This is the rectangle: circumference × height = 2πr × h.
    2 × π × 3 × 10 = 60π
  4. Add them together. Total surface area = circles + curved surface.
    18π + 60π = 78π
  5. Write the answer in terms of π. Leave the answer in terms of π: write the number in front of π and do not multiply by 3.14.
    Surface area = 78π cm2

Check. Using the factorised formula: 2πr(r + h) = 2 × π × 3 × 13 = 78π. ✓

Watch out. The curved surface is 2πr × h. Do not use the diameter for the circles, and remember both circular ends (unless the question says one end is open).

Worked example 19.7.5
An open tank (no lid) is a cuboid 2 m long, 1.5 m wide and 1 m high. The outside faces are to be painted. Paint costs £4 for each square metre. How much does it cost to paint the five outside faces?

Method. Work out the area of the five faces (base and four sides, no lid) and multiply by the cost per square metre.

  1. Area of the base. length × width.
    2 × 1.5 = 3 m2
  2. Area of the two long sides. Each is length × height.
    2 × 1 = 2 m2, so 2 of them: 4 m2
  3. Area of the two short sides. Each is width × height.
    1.5 × 1 = 1.5 m2, so 2 of them: 3 m2
  4. Add to get the area to paint. There is no lid so we do not count one.
    3 + 4 + 3 = 10 m2
  5. Multiply by the cost. £4 for each m2.
    10 × 4 = £40

Check. A closed tank would be 13 m2; removing the lid (3 m2) leaves 10 m2. ✓

Watch out. Check whether the question includes the top. An open tank has 5 faces.

Watch out

Do not forget faces! Use the net to count them. A cuboid has six faces, a triangular prism has five, and a closed cylinder has two circles and one curved surface. Give the answer in square units, and do not confuse surface area with volume.

Exercise 19H  Surface area (non-calculator)

Non-calculator
1
FWork out the surface area of each cuboid.
(a)5 cm by 4 cm by 3 cm
(b)6 cm by 6 cm by 2 cm
(c)10 cm by 3 cm by 2 cm
(d)4 cm by 3 cm by 2.5 cm
2
FWork out the surface area of each cube.
(a)edge 4 cm
(b)edge 7 cm
(c)edge 10 mm
3
FAn open box with no lid is a cuboid 20 cm long, 15 cm wide and 10 cm high. Work out the outside surface area.
20 cm10 cm15 cm
4
FThe diagram shows a triangular prism. The triangle is right-angled. Work out the total surface area.
3 cm5 cm4 cm10 cm
5
FThe triangular ends of this prism are isosceles. Work out the total surface area.
6 cm5 cm12 cm4 cm
6
PSThe cross-section of this prism is a trapezium. Work out the total surface area.
8 cm4 cm10 cm3 cm
7
PSWork out the total surface area of this prism, which has an L-shaped cross-section.
8 cm6 cm3 cm2 cm10 cm
8
FWork out the total surface area of each cylinder. Give your answers in terms of π.
(a)radius 3 cm, height 10 cm
(b)diameter 8 cm, height 5 cm
(c)radius 5 cm, height 2 cm
9
FWork out the curved surface area of each cylinder, in terms of π.
(a)radius 4 cm, height 10 cm
(b)radius 3 cm, height 7 cm
10
PSAn open tin has no lid. It is a cylinder with radius 5 cm and height 12 cm. Work out the outside surface area, in terms of π.
11
PSA gift box is a cuboid 30 cm by 20 cm by 10 cm. It is covered completely with wrapping paper. Sheets of paper are 50 cm by 40 cm. How many sheets are needed? (Assume no overlap and that the paper can be cut and joined.)
12
PSAn open water tank is a cuboid 2 m long, 1.5 m wide and 1 m high. The five outside faces are painted. Paint costs £4 per square metre. Work out the cost.
13
PSThe total surface area of a cube is 216 cm2. Work out the length of an edge.
14
RA cube has edge 6 cm. A cuboid measures 9 cm by 6 cm by 4 cm. Show that they have the same volume. Which has the smaller surface area?
15
RTom says that the total surface area of a cylinder with radius 3 cm and height 10 cm is 60π cm2. Explain his mistake and work out the correct total surface area.
16
RA cuboid 6 cm by 4 cm by 3 cm is cut in half horizontally to make two identical cuboids, each 6 cm by 4 cm by 1.5 cm. Show that the total surface area increases by 48 cm2.
17
RTwo cubes with edges 2 cm are stuck together face to face to make a cuboid 4 cm by 2 cm by 2 cm. Work out the surface area of the cuboid, and explain why it is less than the total surface area of the two separate cubes.
18
FA cube has edges of length 3 cm. Work out the area of one face of the cube.
19
FHow many faces does a cuboid have? Write down the areas of the faces of a cuboid that is 4 cm by 3 cm by 2 cm and work out the total surface area.

Exercise 19I  Surface area of cylinders (calculator)

Calculator allowed
1
FWork out the total surface area of each cylinder. Give your answers to 3 significant figures.
(a)radius 4 cm, height 10 cm
(b)radius 2.5 cm, height 7.2 cm
(c)diameter 12 cm, height 15 cm
2
PSAn open cylinder (no lid) has radius 6 cm and height 14 cm. Work out the outside surface area to 1 decimal place.
3
PSA tin of soup is a cylinder of diameter 7.4 cm and height 10.8 cm. The paper label covers the curved surface only. Work out the area of the label, to 3 significant figures.
4
PSAn open cylindrical tank has radius 0.8 m and height 1.5 m. The outside (base and curved surface) is painted. One litre of paint covers 4 m2. How many litres of paint are needed, to the nearest litre?
5
RA cylinder has radius 3 cm and height 8 cm. Work out the ratio of the curved surface area to the total surface area, in its simplest form.

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