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GCSE Maths · EdexcelChapter 20 · Pythagoras and trigonometry
GCSE Maths · Pythagoras and Trigonometry · Foundation · Lesson 20.4

GCSE Maths: Trigonometry: finding sides (SOH CAH TOA) (Foundation)

Part of the GCSE Maths pythagoras and trigonometry chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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20.4

Trigonometry: finding sides (SOH CAH TOA)

Edexcel 1MA1: G20
Grade 4-6

Pythagoras uses two sides to find the third. But what if you know only one side and one angle? That is where trigonometry helps. It links the angles of a right-angled triangle to the ratios of its sides.

Look at the picture. All three triangles have a 30° angle and a right angle, so they are similar (the same shape, different sizes). Work out opposite ÷ hypotenuse for each: 1 ÷ 2, 2 ÷ 4 and 3 ÷ 6. They all equal 0.5. This is no accident. In any right-angled triangle with a 30° angle, the ratio of the side opposite the angle to the hypotenuse is always 0.5. We call this ratio the sine of the angle, so sin 30° = 0.5.

36241230°
Three similar right-angled triangles with a 30° angle. Opposite (blue) ÷ hypotenuse (green): 1÷2, 2÷4, 3÷6 are all 0.5.

Naming the sides. We name the sides from the point of view of the angle we are using (call it θ, said “theta”).

adjacentoppositehypotenuseθ
The names of the sides depend on which angle θ you stand at.

There are three trigonometric ratios. Each compares two sides.

sin θ = OH    cos θ = AH    tan θ = OA

A memory aid: SOH CAH TOA. Sin = Opposite over Hypotenuse, Cos = Adjacent over Hypotenuse, Tan = Opposite over Adjacent. You can also use the triangle trick below: cover the one you want and read what is left.

OSHsin θACHcos θOTAtan θ
Cover up the letter you want. If you cover S you see O over H, so sin = O ÷ H. If you cover O you see S × H, so O = sin × H.

The method for finding a side.

  1. Label the sides O, A, H from the angle θ.
  2. Choose the ratio: look at the side you know and the side you want, and find the two letters in SOH CAH TOA.
  3. Write the ratio with the numbers: sin θ = O ÷ H becomes, for example, sin 35° = x ÷ 8.2.
  4. Rearrange to get x alone. If x is on the top, multiply both sides by the number on the bottom. If x is on the bottom, you will multiply by x and then divide.
  5. Calculate with your calculator in degree mode and round sensibly.

The shortcut for step 4: if the unknown is on the top you multiply, and if the unknown is on the bottom you divide. Use this as a check but know why it works. You can also check that your answer is sensible. The hypotenuse must be the longest side.

Key ideas

  • Label O, A, H from the angle θ. H is opposite the right angle.
  • SOH: sin θ = O ÷ H.   CAH: cos θ = A ÷ H.   TOA: tan θ = O ÷ A.
  • Choose the ratio from the two sides involved (one known, one wanted).
  • Unknown on top: multiply. Unknown on the bottom: divide.
  • Calculator in degree mode.
Worked example 20.4.1
Work out the length x. Give your answer correct to 1 decimal place.
x8.2 cm35°

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio with the numbers, then rearrange to get the unknown side.

  1. Label the sides. Stand at the angle θ. The hypotenuse is opposite the right angle. The opposite is across from θ and the adjacent is next to θ.
    8.2 cm is the hypotenuse.
    x is the opposite.
  2. Choose the ratio. We use the ratio that contains the two sides involved: the hypotenuse and the opposite. Use SOH CAH TOA to pick it.
    SOH stands for Sin, Opposite, Hypotenuse:
    sin θ = OH   (O = opposite, H = hypotenuse)
  3. Put the numbers into the ratio. Replace θ with the angle and the sides with the lengths.
    sin 35° = x8.2
  4. Multiply both sides by 8.2. x is being divided by 8.2. Multiplying both sides by 8.2 gets x on its own.
    x = 8.2 × sin 35°
  5. Use the calculator (degree mode). First find sin 35°, then finish the calculation.
    sin 35° = 0.57357…
    x = 8.2 × 0.57357… = 4.70332…
  6. Round to 1 d.p.. Give the answer to the accuracy asked, with the unit.
    x = 4.7 cm

Check. The other acute angle is 90° − 35° = 55°. From that angle the opposite and adjacent sides swap, so we use cos: x = 8.2 × cos 55° = 4.70332…, the same answer. ✓

Watch out. Check your calculator is in degree mode (DEG). The unknown is on the top, so you multiply. A quick check: the hypotenuse must be the longest side.

Worked example 20.4.2
Work out the length x. Give your answer correct to 1 decimal place.
12 mx40°

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio with the numbers, then rearrange to get the unknown side.

  1. Label the sides. Stand at the angle θ. The hypotenuse is opposite the right angle. The opposite is across from θ and the adjacent is next to θ.
    12 m is the adjacent.
    x is the hypotenuse.
  2. Choose the ratio. We use the ratio that contains the two sides involved: the adjacent and the hypotenuse. Use SOH CAH TOA to pick it.
    CAH stands for Cos, Adjacent, Hypotenuse:
    cos θ = AH   (A = adjacent, H = hypotenuse)
  3. Put the numbers into the ratio. Replace θ with the angle and the sides with the lengths.
    cos 40° = 12x
  4. Multiply both sides by x. x is on the bottom of the fraction. Multiplying by x brings it to the top.
    x × cos 40° = 12
  5. Divide both sides by cos 40°. This leaves x on its own.
    x = 12cos 40° = 12 ÷ cos 40°
  6. Use the calculator (degree mode). First find cos 40°, then finish the calculation.
    cos 40° = 0.76604…
    x = 12 ÷ 0.76604… = 15.66488…
  7. Round to 1 d.p.. Give the answer to the accuracy asked, with the unit.
    x = 15.7 m

Check. The other acute angle is 90° − 40° = 50°. From that angle the opposite and adjacent sides swap, so we use sin: x = 12 ÷ sin 50° = 15.66488…, the same answer. ✓

Watch out. Check your calculator is in degree mode (DEG). The unknown is on the bottom, so you divide. A quick check: the hypotenuse must be the longest side.

Worked example 20.4.3
Work out the length x. Give your answer correct to 1 decimal place.
7.5 cmx52°

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio with the numbers, then rearrange to get the unknown side.

  1. Label the sides. Stand at the angle θ. The hypotenuse is opposite the right angle. The opposite is across from θ and the adjacent is next to θ.
    7.5 cm is the adjacent.
    x is the opposite.
  2. Choose the ratio. We use the ratio that contains the two sides involved: the adjacent and the opposite. Use SOH CAH TOA to pick it.
    TOA stands for Tan, Opposite, Adjacent:
    tan θ = OA   (O = opposite, A = adjacent)
  3. Put the numbers into the ratio. Replace θ with the angle and the sides with the lengths.
    tan 52° = x7.5
  4. Multiply both sides by 7.5. x is being divided by 7.5. Multiplying both sides by 7.5 gets x on its own.
    x = 7.5 × tan 52°
  5. Use the calculator (degree mode). First find tan 52°, then finish the calculation.
    tan 52° = 1.27994…
    x = 7.5 × 1.27994… = 9.59956…
  6. Round to 1 d.p.. Give the answer to the accuracy asked, with the unit.
    x = 9.6 cm

Check. The other acute angle is 90° − 52° = 38°. From that angle the opposite and adjacent sides swap, so we use tan: x = 7.5 ÷ tan 38° = 9.59956…, the same answer. ✓

Watch out. Check your calculator is in degree mode (DEG). The unknown is on the top, so you multiply. A quick check: the hypotenuse must be the longest side.

Worked example 20.4.4
Work out the length x. Give your answer correct to 3 significant figures.
x14.2 mm27°

Key words. In a right-angled triangle the hypotenuse is the longest side (opposite the right angle). Measured from the angle θ: the opposite side is directly across from θ, and the adjacent side is next to θ (it is not the hypotenuse). A trigonometric ratio compares two of the sides.

Method. Label the sides, pick SOH, CAH or TOA, write the ratio with the numbers, then rearrange to get the unknown side.

  1. Label the sides. Stand at the angle θ. The hypotenuse is opposite the right angle. The opposite is across from θ and the adjacent is next to θ.
    14.2 mm is the opposite.
    x is the adjacent.
  2. Choose the ratio. We use the ratio that contains the two sides involved: the opposite and the adjacent. Use SOH CAH TOA to pick it.
    TOA stands for Tan, Opposite, Adjacent:
    tan θ = OA   (O = opposite, A = adjacent)
  3. Put the numbers into the ratio. Replace θ with the angle and the sides with the lengths.
    tan 27° = 14.2x
  4. Multiply both sides by x. x is on the bottom of the fraction. Multiplying by x brings it to the top.
    x × tan 27° = 14.2
  5. Divide both sides by tan 27°. This leaves x on its own.
    x = 14.2tan 27° = 14.2 ÷ tan 27°
  6. Use the calculator (degree mode). First find tan 27°, then finish the calculation.
    tan 27° = 0.50952…
    x = 14.2 ÷ 0.50952… = 27.86906…
  7. Round to 3 s.f.. Give the answer to the accuracy asked, with the unit.
    x = 27.9 mm

Check. The other acute angle is 90° − 27° = 63°. From that angle the opposite and adjacent sides swap, so we use tan: x = 14.2 × tan 63° = 27.86906…, the same answer. ✓

Watch out. Check your calculator is in degree mode (DEG). The unknown is on the bottom, so you divide. A quick check: the hypotenuse must be the longest side.

Watch out

Label the sides from the angle you are using, not from the picture. The same side can be opposite for one angle and adjacent for the other. Also check that your calculator is in degree mode. If sin 30° does not give 0.5, it is not.

Exercise 20E  Labelling sides and choosing the ratio

Non-calculator
1
FThe angle θ is marked in each right-angled triangle. Name the hypotenuse, the opposite side and the adjacent side.
(a)
ABCθ
(b)
PQRθ
(c)
XYZθ
2
FWrite down what each of S, O, H, C, A, T stands for, and then complete each ratio.
OSHsin θACHcos θOTAtan θ
(a)sin θ =
(b)cos θ =
(c)tan θ =
3
FWhich ratio, sin, cos or tan, would you use to find x? Write down the ratio only.
(a)
x8 cm35°
(b)
12 mx40°
(c)
x6.4 cm55°
(d)
x15 mm28°
4
FWrite down an equation that you could use to find x. Do not solve it.
(a)
x8 cm35°
(b)
12 mx40°
(c)
x6.4 cm55°
(d)
x9.5 cm62°
5
FFor the triangle shown, write down sin θ, cos θ and tan θ as fractions.
12 cm5 cm13 cmθ
6
FThe triangle ABC has a right angle at C. For angle A, write down the opposite and adjacent sides. Then do the same for angle B. What do you notice?
CBA4 cm3 cm5 cmBA
7
PSFor each situation, choose the ratio you would use. Label the sides of the sketch first.
(a)A 4 m ladder makes an angle of 70° with the ground. You want its height h up the wall. Which ratio (sin, cos or tan)?
groundhladder 4 m70°
(b)A ramp rises 0.5 m and makes an angle of 12° with the ground. You want the horizontal distance d. Which ratio?
drise 0.5 m12°
(c)A kite string is 30 m long and makes an angle of 55° with the level ground. You want the horizontal distance d from the kite to the person. Which ratio?
dstring 30 m55°
8
RDev says that tan x = 513 for this triangle. Explain his mistake and write down the correct value of tan x as a fraction.
12 cm5 cm13 cmx
9
RExplain why sin θ and cos θ can never be bigger than 1 for an angle θ in a right-angled triangle.
AOH (longest)θ
10
PSThe diagram shows three right-angled triangles that share a 30° angle. Work out (opposite) ÷ (hypotenuse) for each triangle and say what you notice.
36241230°

Exercise 20F  Finding sides with sin, cos and tan

Calculator allowed
1
FUse a calculator in degree mode to work out each value. Give each answer correct to 3 decimal places.
(a)sin 40°
40°
(b)cos 25°
25°
(c)tan 63°
63°
(d)sin 72°
72°
(e)cos 58°
58°
(f)tan 18°
18°
2
FWork out the length of the side marked x in each triangle. Give your answers correct to 1 decimal place. All the lengths are in centimetres.
(a)
x10 cm30°
(b)
x7.5 cm42°
(c)
x12 cm65°
(d)
x9.6 cm23°
3
FWork out the length of the side marked x in each triangle. Give your answers correct to 1 decimal place. All the lengths are in centimetres.
(a)
x15 cm40°
(b)
x8.2 cm55°
(c)
x11 cm28°
(d)
x6.5 cm71°
4
FWork out the length of the side marked x in each triangle. Give your answers correct to 1 decimal place. All the lengths are in centimetres.
(a)
8 cmx50°
(b)
12.5 cmx33°
(c)
5.4 cmx68°
(d)
15 cmx20°
5
FWork out the length of the side marked x in each triangle. Be careful: in some of them x will be on the bottom of the fraction. Give your answers correct to 1 decimal place. All the lengths are in centimetres.
(a)
9 cmx35°
(b)
7 cmx48°
(c)
x5.5 cm62°
(d)
14 cmx26°
6
FWork out the length x. Give your answer correct to 3 significant figures.
x19.4 cm36°
7
FWork out the length x. Give your answer correct to 2 decimal places.
3.8 mx57°
8
PSA ladder 6.5 m long leans against a vertical wall. The ladder makes an angle of 68° with the horizontal ground. How high up the wall does the ladder reach? Give your answer correct to 2 decimal places.
groundhladder 6.5 m68°
9
PSA slide is 3.2 m long and slopes at 38° to the horizontal. Work out the vertical height of the top of the slide above the ground. Give your answer correct to 2 decimal places.
hslide 3.2 m38°
10
PSA kite is flying on a string 45 m long. The string makes an angle of 52° with the level ground. Work out the horizontal distance from the person to the point on the ground below the kite. Give your answer correct to 1 decimal place.
dstring 45 m52°
11
PSA wheelchair ramp rises 0.6 m and makes an angle of 7° with the ground. How long is the ramp? Give your answer correct to 2 decimal places.
rise 0.6 mL7°
12
PSIn this right-angled triangle the hypotenuse is 12 cm and one angle is 34°. Find x and y, correct to 1 decimal place.
xy12 cm34°
(a)y (opposite the 34° angle)
(b)x (next to the 34° angle)
13
RAnya works out x in this triangle as 10 × cos 40° = 7.7 cm. Explain her mistake and find the correct value of x, to 1 decimal place.
x10 cm40°
14
RChallenge. A right-angled triangle has a hypotenuse of 10 cm and an angle of 36°. Work out the perimeter of the triangle, correct to 1 decimal place.
??10 cm36°

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