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GCSE Maths · EdexcelChapter 22 · Constructions, loci, bearings and vectors
GCSE Maths · Loci, Bearings and Vectors · Higher · Lesson 22.3

GCSE Maths: Constructing triangles (Higher)

Part of the GCSE Maths loci, bearings and vectors chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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22.3

Constructing triangles

Edexcel 1MA1: G2, G15
Grade 3-6

A triangle has three sides and three angles, but you do not need all six to draw it. If you are told enough information, there is only one possible triangle (apart from its position on the page). In Chapter 21 you met the same ideas as the conditions for congruent triangles: three sides (SSS), two sides and the angle between them (SAS), and two angles and a side (ASA).

SSS: three sides. Draw one side as the base, say AB. The corner C must be the right distance from A and from B. Draw an arc of the right radius from A, and another from B. The arcs cross at C.

Step 1AB7 cmStep 2AB7 cmStep 3AB7 cmCStep 4AB7 cmC
Constructing a triangle with sides 7 cm, 6 cm and 5 cm. Step 1: base AB = 7 cm. Step 2: arc of radius 6 cm from A. Step 3: arc of radius 5 cm from B, crossing at C. Step 4: join AC and BC.

SAS: two sides and the angle between them. Draw one side, measure the angle at one end with a protractor, mark the second side along the new line, then join the ends.

Step 1AB6 cmStep 2AB6 cm50°Step 3AB6 cm50°CStep 4AB6 cm50°C
SAS: AB = 6 cm, angle A = 50°, AC = 4.5 cm. Step 3 marks C with the compasses. Join BC to finish.

ASA: two angles and a side. Draw the side, then measure one angle at each end. The two lines cross at the third corner.

Step 1AB6 cmStep 2AB6 cm50°Step 3AB6 cm50°60°Step 4AB6 cm50°60°C
ASA: angle A = 50°, AB = 6 cm, angle B = 60°. The third angle C is 180° − 50° − 60° = 70°.

Right-angled triangles (RHS). If you know the hypotenuse and one other side, construct the right angle, then use an arc for the hypotenuse.

When is a triangle impossible? The two shorter sides must be able to reach each other. If the arcs do not cross, there is no triangle. This happens when the two short sides add up to less than or equal to the longest side. For example 3 cm, 4 cm and 8 cm cannot make a triangle because 3 + 4 = 7 is less than 8: the arcs fall short of each other.

Accuracy. A good construction is accurate to about 1 mm for lengths and 1° for angles. Always say which measurement you have taken and give a sensible unit. Leave all construction arcs on your page.

Key ideas

  • SSS: base, then an arc from each end. SAS: side, angle at one end, then second side. ASA: side, then an angle at each end.
  • Three angles alone do not fix a triangle: you can have a small or a big one with the same angles.
  • A triangle with sides a, b, c is only possible if the two shorter sides add up to more than the longest.
  • Measure carefully and leave construction arcs.
  • RHS: build the right angle first, then use an arc for the hypotenuse.
Worked example 22.3.1
Construct triangle ABC with AB = 7 cm, AC = 6 cm and BC = 5 cm. Measure the largest angle of the triangle.

Key words. To construct means to draw accurately using only a ruler and a pair of compasses (no protractor). The construction arcs are the curved lines the compasses leave; you must not rub them out.

Method. Draw the longest side as a base, then find the third corner with two arcs. Measure the angle with a protractor.

  1. Draw the base AB. Choose one side as the base and draw it with a ruler.
    AB = 7 cm
  2. Draw an arc from A. C is 6 cm from A, so every possible position of C is on an arc of radius 6 cm centred on A.
    Compasses set to 6 cm, point on A.
  3. Draw an arc from B. C is also 5 cm from B. Where the two arcs cross is the only point that is the right distance from both A and B.
    Compasses set to 5 cm, point on B. The arcs cross at C.
  4. Join AC and BC. Use a ruler. Keep the arcs.
    ABC7 cm5 cm6 cm?
  5. Measure angle C. The biggest angle is opposite the longest side (7 cm), which is angle C. Use a protractor.
    Angle C = 78.5° to 1 decimal place, so about 78°

Check. Cosine rule: cos C = (52 + 62 − 72) ÷ (2 × 5 × 6) = 0.2000, so C = 78.5°. Your measurement should be within 1° of this. ✓

Watch out. The two arcs must have the radii of the two sides that meet at C. Do not swap them.

Worked example 22.3.2
Construct triangle ABC with AB = 6 cm, angle A = 50° and AC = 4.5 cm. Measure the length of BC.

Key words. To construct means to draw accurately using only a ruler and a pair of compasses (no protractor). The construction arcs are the curved lines the compasses leave; you must not rub them out.

Method. Draw one side, measure the angle at one end of it, mark the second side along the new line, then join up.

  1. Draw the side AB. It is one of the two sides next to the known angle.
    AB = 6 cm
  2. Measure the angle at A. Place the centre of the protractor on A with its zero line along AB. Mark the angle and draw a faint line through the mark.
    Angle A = 50°
  3. Mark C. C is on the new line and AC is a given length. Measure with a ruler (or an arc of the compasses).
    AC = 4.5 cm
  4. Join BC and measure it. This completes the triangle. Measure BC with a ruler.
    ABC6 cm4.5 cm?50°
    BC = 4.64 cm ≈ 4.6 cm

Check. Cosine rule: BC2 = 62 + 4.52 − 2 × 6 × 4.5 × cos 50° = 21.54, so BC = 4.64 cm. Your measurement should be within 1 mm of this. ✓

Watch out. The angle must be between the two given sides. If it is not between them, you cannot draw the triangle this way.

Worked example 22.3.3
Construct triangle ABC with angle A = 50°, AB = 6 cm and angle B = 60°. Measure the length of AC.

Key words. To construct means to draw accurately using only a ruler and a pair of compasses (no protractor). The construction arcs are the curved lines the compasses leave; you must not rub them out.

Method. Draw the side, then draw the angle at each end. The lines meet at the third corner.

  1. Draw the side AB. The side between the two known angles is the base.
    AB = 6 cm
  2. Draw the angle at A. Use a protractor at A with its zero line along AB. Draw a long faint line.
    Angle A = 50°
  3. Draw the angle at B. Use the protractor at B. Measure from BA (the zero line points back towards A). Draw a line that crosses the first line at C.
    Angle B = 60°
  4. Measure the side you want. Where the two lines cross is the third corner C. Measure with a ruler.
    ABC6 cm?50°60°
    AC = 5.53 cm ≈ 5.5 cm

Check. Sine rule: the third angle is 180° − 50° − 60° = 70°, and AC = 6 × sin 60° ÷ sin 70° = 5.53 cm. ✓

Watch out. Angles in a triangle add up to 180°, so the angles must add up to less than 180° or the lines will never meet.

Worked example 22.3.4
Explain why it is not possible to construct a triangle with sides of length 3 cm, 4 cm and 8 cm.

Key words. To construct means to draw accurately using only a ruler and a pair of compasses (no protractor). The construction arcs are the curved lines the compasses leave; you must not rub them out.

Method. Try to draw it. The two shorter sides must reach each other when they are attached to the ends of the longest side.

  1. Draw the longest side. Take the 8 cm side as the base AB.
    AB = 8 cm
  2. Draw the two arcs. C must be 3 cm from A and 4 cm from B. So the arcs have radii 3 cm and 4 cm.
    Arc from A: radius 3 cm. Arc from B: radius 4 cm.
  3. See what happens. The arcs reach 3 cm and 4 cm from the ends. Together they cover only 3 + 4 = 7 cm of the 8 cm base.
    3 + 4 = 7 and 7 < 8, so the arcs do not meet.
  4. Write the conclusion. If the arcs never cross there is no point C.
    No triangle can be drawn. The two shorter sides must add up to more than the longest side.

Check. A triangle with sides 3, 4, 5 does exist, because 3 + 4 = 7 is more than 5. ✓

Watch out. It is not enough for the sides to be different. They must satisfy: two shorter sides add up to more than the longest.

Worked example 22.3.5
Construct a right-angled triangle ABC with the right angle at B, AB = 2.5 cm and hypotenuse AC = 6.5 cm. Measure BC.

Key words. To construct means to draw accurately using only a ruler and a pair of compasses (no protractor). The construction arcs are the curved lines the compasses leave; you must not rub them out.

Method. A right angle, the hypotenuse and one other side fix a triangle. Construct the right angle first, then the arc for the hypotenuse.

  1. Draw the base AB. The base is one of the shorter sides.
    AB = 2.5 cm
  2. Construct a right angle at B. Use the perpendicular-at-a-point construction at B (arcs from B, then larger arcs). The perpendicular line goes up from B.
    Angle ABC = 90°
  3. Draw an arc from A. C is 6.5 cm from A, so set the compasses to 6.5 cm and draw an arc from A that crosses the perpendicular at C.
    AC = 6.5 cm
  4. Join AC and measure BC. Use a ruler.
    ABC2.5 cm6.5 cm?
    BC = 6.0 cm

Check. Pythagoras: BC2 = 6.52 − 2.52 = 36.00, so BC = 6.0 cm. ✓

Watch out. The hypotenuse is opposite the right angle, so the arc is drawn from the end of the base that is not at the right angle.

Watch out

Check which sides and angles you have been given. For SAS the angle must be between the two sides. If you use the wrong end of the line you will draw a different triangle. And three angles (AAA) is not enough: it only tells you the shape, not the size.

Exercise 22D  Constructing triangles and measuring

Calculator allowed
1
FIs there enough information to construct exactly one triangle? Write “Yes” or “No” and say why.
(a)Three sides: 5 cm, 6 cm, 7 cm.
(b)Three angles: 40°, 60°, 80°.
(c)AB = 6 cm, angle A = 35°, AC = 4 cm.
(d)Sides 3 cm, 4 cm and 8 cm.
2
FConstruct each triangle with sides of the lengths given. Measure the largest angle in each.
(a)Sides 4 cm, 5 cm and 6 cm.
(b)Sides 6 cm, 6 cm and 6 cm.
(c)Sides 3 cm, 4 cm and 5 cm.
(d)Sides 5 cm, 5 cm and 8 cm.
3
FConstruct each triangle ABC. AB, the angle at A, and AC are given. Measure BC.
(a)AB = 7 cm, angle A = 40°, AC = 5 cm.
(b)AB = 6 cm, angle A = 90°, AC = 8 cm.
(c)AB = 5 cm, angle A = 60°, AC = 5 cm.
(d)AB = 8 cm, angle A = 120°, AC = 6 cm.
4
FConstruct each triangle ABC. Measure the length asked for.
(a)Angle A = 40°, AB = 7 cm, angle B = 70°. Measure AC.
(b)Angle A = 60°, AB = 6 cm, angle B = 60°. Measure AC.
(c)Angle A = 30°, AB = 8 cm, angle B = 45°. Measure AC.
5
FConstruct a right-angled triangle with a right angle at B, AB = 6 cm and hypotenuse AC = 10 cm. Measure BC.
6
FTriangle ABC is isosceles with AB = AC = 6 cm and BC = 4 cm. Construct the triangle. Measure angle BAC and one of the base angles.
7
PSA triangular plot of land has sides of 40 m, 50 m and 60 m. Make a scale drawing using a scale of 1 cm to 10 m. Measure the largest angle of the plot. Give your answer to the nearest degree.
8
PSTwo lighthouses A and B are 6 km apart. A boat C is seen from A at an angle of 50° from the line AB, and from B at an angle of 60° from the line BA, with the boat on the same side of AB. Make a scale drawing using 1 cm to 1 km. How far is the boat from A?
9
RKatie says: “I can make a triangle with sides of 4 cm, 5 cm and 10 cm.” Show that Katie is wrong.
10
RTwo triangles both have angles of 50°, 60° and 70°. One has its shortest side 5 cm long and the other has its shortest side 8 cm long. Explain why these triangles are not congruent, and say what you can say about their shapes.
11
RConstruct triangle ABC with AB = 6 cm, AC = 4.5 cm and angle A = 50°. Measure BC. Then use the cosine rule to calculate BC, and show that your measurement agrees with the calculation to the nearest millimetre.
12
RChallenge. Triangle ABC has angle A = 30°, AB = 7 cm and BC = 4 cm. Show that two different triangles are possible. Find the two possible lengths of AC.
13
PSA rhombus has sides of 5 cm and one angle of 60°. Construct the rhombus. Measure its longer diagonal.
14
RChallenge. A triangle has sides in the ratio 3 : 4 : 5 and a perimeter of 24 cm. Construct it. Show that it has a right angle.

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