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GCSE Maths · EdexcelChapter 23 · Probability
GCSE Maths · Probability · Foundation · Lesson 23.5

GCSE Maths: Independent events: the AND rule and the OR rule (Foundation)

Part of the GCSE Maths probability chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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23.5

Independent events: the AND rule and the OR rule

Edexcel 1MA1: P8, P6
Grade 3-6

Two events are independent if the result of one has no effect on the result of the other. Tossing a coin and rolling a die are independent: whatever the coin shows, the die is still fair. Rain on two different, far-apart days is usually treated as independent too. In real life we assume independence only when it is reasonable.

The AND rule. To find the probability that both of two independent events happen, multiply the probabilities: P(A and B) = P(A) × P(B). Why? Look at the table of the 12 outcomes when a coin is tossed and a die is rolled. Only one cell, H6, is “heads and a 6”, so the probability is 1/12. And 1/2 × 1/6 = 1/12. Half of all the outcomes have heads, and one sixth of those have a 6, so we take one sixth of one half, which is multiplying.

coin \ die123456
HH1H2H3H4H5H6
TT1T2T3T4T5T6
Coin and die: 12 equally likely outcomes. Only H6 gives “heads and a 6”, so P = 1/12 = 1/2 × 1/6.

The OR rule. Two events are mutually exclusive if they cannot happen at the same time (a die cannot show 2 and 5 on the same roll). For such events, the probability that either happens is found by adding: P(A or B) = P(A) + P(B). For example P(roll 2 or 5) = 1/6 + 1/6 = 2/6 = 1/3.

Do not mix them up. “And” (both things, one after the other) means multiply, and the answer is smaller. “Or” (one thing or the other, in the same trial) means add, and the answer is bigger. The AND rule needs independent events. The OR rule needs mutually exclusive events.

At least one. “At least one 6 in two rolls” means one 6, or two sixes. That is lots of cases, so use the opposite instead: P(at least one) = 1 − P(none). P(no 6 on one roll) = 5/6, so P(no 6 in two rolls) = 5/6 × 5/6 = 25/36, and P(at least one 6) = 1 − 25/36 = 11/36. Notice that this is not 1/6 + 1/6 = 1/3: that adds events that are not mutually exclusive (both rolls could be sixes).

Key ideas

  • Independent events do not affect each other. The AND rule: P(A and B) = P(A) × P(B).
  • Mutually exclusive events cannot happen together. The OR rule: P(A or B) = P(A) + P(B).
  • “And” means multiply (smaller answer). “Or” means add (bigger answer).
  • P(at least one) = 1 − P(none).
  • We should say what we assume: for example, that the coin is fair and the events are independent.
Worked example 23.5.1
A fair coin is tossed and a fair die is rolled. Find the probability of getting heads and a 6.

Key words. Two events are independent if one happening does not change the probability of the other. Mutually exclusive events cannot happen at the same time. For independent events, P(A and B) = P(A) × P(B).

Method. For independent events, “A and B” means we multiply their probabilities: P(A and B) = P(A) × P(B).

  1. Check that the events are independent. The outcome of one does not change the chances for the other. So we can multiply their probabilities.
    Independent events
  2. Write down the probability of each event. We need each probability on its own.
    P(heads) = 12
    P(a 6) = 16
  3. Multiply the probabilities. For independent events, P(A and B) = P(A) × P(B). Multiply the tops together and the bottoms together.
    12 × 16 = 112

Check. Both things have to happen, so the answer must be smaller than each single probability: 112 is smaller than 16. ✓

Watch out. Multiply for “and”. Do not add the probabilities.

Worked example 23.5.2
The probability of rain on Saturday is 0.3 and the probability of rain on Sunday is 0.4. Assume the two days are independent. Find the probability that it rains on both days.

Key words. Two events are independent if one happening does not change the probability of the other. Mutually exclusive events cannot happen at the same time. For independent events, P(A and B) = P(A) × P(B).

Method. For independent events, “A and B” means we multiply their probabilities: P(A and B) = P(A) × P(B).

  1. Check that the events are independent. Rain on one day does not change the chance of rain on the other (we assume this). So we can multiply their probabilities.
    Independent events
  2. Write down the probability of each event. We need each probability on its own.
    P(rain on Saturday) = 0.3
    P(rain on Sunday) = 0.4
  3. Multiply the probabilities. For independent events, P(A and B) = P(A) × P(B). Multiply as if there were no decimal points, then count the decimal places.
    0.3 × 0.4
    3 × 4 = 12, and there are 2 decimal places altogether
    = 0.12

Check. Both things have to happen, so the answer must be smaller than each single probability: 0.12 is smaller than 0.3. ✓

Watch out. Multiply for “and”. Do not add the probabilities.

Worked example 23.5.3
A bag has 10 counters: 3 red, 2 blue and 5 green. One counter is picked at random. Find the probability that it is red or blue.

Key words. Two events are independent if one happening does not change the probability of the other. Mutually exclusive events cannot happen at the same time. For independent events, P(A and B) = P(A) × P(B).

Method. For mutually exclusive events, “A or B” means we add their probabilities: P(A or B) = P(A) + P(B).

  1. Check that the events are mutually exclusive. One counter cannot be both red and blue. So we can add their probabilities.
    Mutually exclusive events
  2. Write down the probability of each event. We need each probability on its own.
    P(red) = 310
    P(blue) = 15
  3. Add the probabilities. For mutually exclusive events, P(A or B) = P(A) + P(B).
    310 + 15 = 310 + 210 = 510 = 12

Check. The opposite event has probability 1 − 12 = 12, and the two add to 1. ✓

Watch out. Add for “or”, but only when the events cannot both happen.

Worked example 23.5.4
A fair die is rolled twice. Find the probability of getting at least one 6.

Key words. Two events are independent if one happening does not change the probability of the other. Mutually exclusive events cannot happen at the same time. For independent events, P(A and B) = P(A) × P(B).

Method. P(at least one) = 1 − P(none). Find the probability of none by multiplying, then subtract from 1.

  1. Use the opposite event. “At least one 6” is the opposite of “no 6 every time”. It is easier to find the opposite and subtract from 1.
    P(at least one) = 1 − P(none)
  2. Find the probability of the event not happening on one trial. Use P(not A) = 1 − P(A).
    P(not 6) = 1 − 16 = 56
  3. Multiply for all 2 trials. The trials are independent, so multiply the 2 probabilities.
    P(none) = 56 × 56 = 2536
  4. Subtract from 1. P(at least one) = 1 − P(none).
    3636 − 2536 = 1136

Check. P(none) + P(at least one) = 2536 + 1136 = 1. ✓

Watch out. Do not add the probabilities of each trial. For “at least one” always think “1 minus none”.

Watch out

Do not add when you should multiply. The probability of heads and a 6 is 1/2 × 1/6 = 1/12, not 1/2 + 1/6. And do not use the OR rule on events that can both happen: “a 6 on the first roll or a 6 on the second roll” is not 1/6 + 1/6, because both can be sixes.

Exercise 23F  Independent events: AND and OR

Non-calculator
1
FA fair coin is tossed and a fair die is rolled. Find the probability of...
(a)heads and a 3
(b)tails and an even number
(c)heads and a number bigger than 4
2
FTwo fair coins are tossed. Find the probability that both coins land on heads.
3
FA fair die is rolled twice. Find the probability of a 6 both times.
4
FA and B are independent events. Work out P(A and B).
(a)P(A) = 0.3, P(B) = 0.5
(b)P(A) = 0.6, P(B) = 0.2
(c)P(A) = 0.9, P(B) = 0.9
(d)P(A) = 0.04, P(B) = 0.5
5
FA and B are mutually exclusive events. Work out P(A or B).
(a)P(A) = 0.3, P(B) = 0.5
(b)P(A) = 0.15, P(B) = 0.25
(c)P(A) = 0.07, P(B) = 0.4
6
FThe probability that a spinner lands on red is 0.2 and the probability that it lands on blue is 0.3. Work out the probability that it lands on red or blue.
7
FA fair die is rolled once. Find the probability of...
(a)a 1 or a 6
(b)a 2, a 3 or a 4
8
PSPat takes a bus and then a train to work. The probability that the bus is late is 0.2 and the probability that the train is late is 0.1. The two are independent. Find the probability that...
(a)both are late
(b)neither is late
(c)at least one is late
9
FFind the probability of getting at least one...
(a)head when two fair coins are tossed
(b)head when three fair coins are tossed
(c)6 when a fair die is rolled twice
10
PSA fair spinner has the numbers 1 to 5 on equal sections. It is spun and a fair coin is tossed. Find the probability of a number bigger than 3 and tails.
11
PSThe probability that a seed germinates is 0.8. Two seeds are planted and they grow independently. Find the probability that exactly one of them germinates.
12
RAli says: “The probability of getting a 6 on both of two rolls is 1/6 + 1/6 = 1/3.” Explain his mistake and give the correct answer.
13
RDan says: “P(rain on Saturday) = 0.3 and P(rain on Sunday) = 0.4, so P(rain on both days) = 0.3 + 0.4 = 0.7.” Explain why Dan cannot be correct without working out the answer.
14
RFor each pair of events say whether they are mutually exclusive. Give a reason. A fair die is rolled once.
(a)A: the score is even. B: the score is 6.
(b)A: the score is even. B: the score is 5.
15
PSFind the probability of getting at least one 6 when a fair die is rolled 3 times. Give your answer as a fraction.

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