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GCSE Maths · EdexcelChapter 26 · Circle theorems
GCSE Maths · Circle Theorems · Higher · Lesson 26.1

GCSE Maths: Circle words and isosceles triangles (Higher)

Part of the GCSE Maths circle theorems chapter (Higher). Chapter overview · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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26.1

Circle words and isosceles triangles

Edexcel 1MA1: G9, G10
Grade 3-6

A circle is made of all the points that are the same distance from one fixed point, the centre. You met the main words in Chapter 18. Circle theorems depend on them, so every word must be exact. A diagram usually uses lots of these words at once, and you need to spot them quickly.

OABCDEFGHJ
Chord AB (the blue region above it is a segment). CD passes through the centre O, so it is a diameter. The orange region OEF is a sector, and the curved line from E to F is an arc. The red line HJ touches the circle at G: it is a tangent.

Words to know

  • Radius: a straight line from the centre to a point on the circle. All radii of one circle are equal.
  • Diameter: a chord through the centre. It is twice the radius, and it is the longest chord.
  • Chord: a straight line that joins two points on the circle.
  • Arc: a part of the circumference. The shorter one is the minor arc, the longer is the major arc.
  • Sector: the region between two radii and an arc (a slice of pizza).
  • Segment: the region between a chord and an arc. A chord cuts a circle into two segments.
  • Tangent: a straight line that touches the circle at exactly one point, the point of contact.

Two radii always make an isosceles triangle. Every radius is the same length. So if A and B are on a circle with centre O, then OA = OB and triangle OAB is isosceles. The two equal angles (the base angles) are at A and B, which are the points on the circle. This one idea is used in almost every proof in the chapter. Remember from Chapter 17: in an isosceles triangle the angles opposite the equal sides are equal, and the three angles add up to 180°.

OAB76°x
Triangle OAB is isosceles because OA and OB are radii (the tick marks show equal lengths). The two base angles are equal, here 52° each.

Writing reasons. In the exam, circle theorem questions say “give reasons for your answer”. You get marks for the angle and for the reason, and the reason must be in the right words. Learn the wording in the box below and use it exactly. Each section of this chapter shows you how a theorem works and why it is true.

The reasons you must be able to write

  • Angle in a semicircle is 90°.
  • The angle at the centre is twice the angle at the circumference.
  • Angles in the same segment are equal.
  • Opposite angles of a cyclic quadrilateral add up to 180°.
  • The angle between a tangent and a radius is 90°.
  • Tangents from an external point are equal in length.
  • The angle between a tangent and a chord is equal to the angle in the alternate segment.
  • The perpendicular from the centre to a chord bisects the chord.
  • Also use: base angles of an isosceles triangle are equal; angles in a triangle add up to 180°; angles on a straight line add up to 180°; angles in a quadrilateral add up to 360°.

Watch out

A chord is not the same as a radius. A radius has one end at the centre. A chord has both ends on the circle. The only chord that passes through the centre is the diameter.
Worked example 26.1.1
The diagram shows a circle with centre O. Name (a) the line CD, (b) the shaded region OEF, (c) the shaded region next to the line AB, (d) the line HJ, which touches the circle at G.
OABCDEFGHJ

Method. Match each description to the exact circle word.

  1. Look at CD. It joins two points on the circle and passes through the centre O.
    (a) CD is a diameter (a chord through the centre)
  2. Look at the region OEF. It is bounded by two radii (OE and OF) and an arc.
    (b) a sector
  3. Look at the region by AB. AB is a chord that does not pass through the centre. The region between the chord and its arc is cut off from the rest of the circle.
    (c) a segment
  4. Look at HJ. It touches the circle at one point, G, and does not cross into the circle.
    (d) a tangent

Check. A sector has two radii as straight sides. A segment has a chord as its straight side. ✓

Watch out. A sector is bounded by radii; a segment is bounded by a chord. Both have an arc.

Worked example 26.1.2
O is the centre of the circle. A and B are points on the circle. Angle AOB = 70°. Work out the size of angle OAB.
OAB70°x

Key words. A radius joins the centre to the circle. A chord joins two points on the circle. Isosceles means two equal sides, which gives two equal angles.

Method. Two radii of a circle are equal, so any triangle made from two radii and a chord is isosceles. Then use the isosceles and angle-sum facts.

  1. Spot the radii. Every line from the centre to the circle is a radius, and all radii of one circle are the same length.
    OA and OB are both radii, so OA = OB.
  2. Name the triangle. A triangle with two equal sides is isosceles.
    Triangle OAB is isosceles, with the two equal sides meeting at O.
  3. Use the angle sum. The three angles of any triangle add up to 180°. The two base angles (at A and B) are equal because the triangle is isosceles.
    Angle OAB + angle OBA + angle AOB = 180°
    2 × angle OAB + 70° = 180°
  4. Solve for the base angle. Take away the known angle, then share the rest equally between the two base angles.
    2 × angle OAB = 180° − 70° = 110°
    angle OAB = 110° ÷ 2 = 55°

Check. The three angles are 55° + 55° + 70° = 180°, which is a full triangle. ✓

Watch out. Do not give the base angles as the angle at the centre. In triangle OAB the equal angles are the two at the circumference, A and B.

Worked example 26.1.3
O is the centre of the circle. A and B are points on the circle. Angle OAB = 25°. Work out the size of angle AOB.
OABx25°

Key words. A radius joins the centre to the circle. A chord joins two points on the circle. Isosceles means two equal sides, which gives two equal angles.

Method. Two radii of a circle are equal, so any triangle made from two radii and a chord is isosceles. Then use the isosceles and angle-sum facts.

  1. Spot the radii. All radii of a circle are the same length.
    OA and OB are both radii, so OA = OB and triangle OAB is isosceles.
  2. Write down the other base angle. The base angles of an isosceles triangle are equal.
    Angle OBA = angle OAB = 25°
  3. Use the angle sum. The three angles of a triangle add up to 180°, so subtract the two base angles from 180°.
    Angle AOB = 180° − 25° − 25° = 130°

Check. 25° + 25° + 130° = 180°. ✓

Watch out. Do not give the base angles as the angle at the centre. In triangle OAB the equal angles are the two at the circumference, A and B.

Worked example 26.1.4
A and B are points on a circle with centre O. The length of the chord AB is equal to the radius of the circle. Show that angle AOB = 60°.
OAB

Method. Show that all three sides of triangle OAB are equal. Then the triangle is equilateral and each angle is 60°.

  1. List the three sides. OA and OB are radii of the circle. AB is the chord, and the question says it is equal to the radius.
    OA = OB = radius, and AB = radius
  2. Say what kind of triangle it is. A triangle with three equal sides is equilateral.
    Triangle OAB is equilateral.
  3. Use the angle fact. The three angles of a triangle add up to 180°, and in an equilateral triangle they are all equal.
    180° ÷ 3 = 60°
  4. Write the conclusion. End a “show that” question with a clear statement.
    So angle AOB = 60°. ✓

Check. Another way: the base angles are equal and so is the apex, so 3 × 60° = 180°. ✓

Watch out. In a “show that” question, state each fact and reason; do not just draw a number from nowhere.

Exercise 26A  Circle words and isosceles triangles

Non-calculator
1
FThe diagram shows a circle with centre O. Name each of these.
OABCDEFGHJ
(a)The line AB
(b)The line CD
(c)The line OE
(d)The orange shaded region OEF
(e)The blue shaded region next to AB
(f)The line HJ
(g)The curved line from E to F
2
FWrite the correct word for each description.
(a)A straight line from the centre to the circle
(b)The distance all the way round the circle
(c)A chord that passes through the centre
(d)Half of a circle, cut off by a diameter
(e)A straight line that touches the circle at exactly one point
(f)The region between a chord and the arc it cuts off
3
FWork out the missing measurement for each circle.
(a)The radius is 9 cm. Work out the diameter.
(b)The diameter is 26 cm. Work out the radius.
(c)The radius is 6.5 m. Work out the diameter.
4
RDev says: “A chord is a straight line from the centre of the circle to the circle.” Dev is wrong. Explain his mistake and say what the line he described is called.
5
RThe diameter is the longest chord of a circle. Use the triangle OAB in the diagram to explain why a chord AB that does not go through the centre must be shorter than the diameter.
OAB100°x
6
FO is the centre of the circle. A and B are points on the circle. Angle AOB = 40°. Work out the size of angle OAB.
OAB40°x
7
FO is the centre of the circle. A and B are points on the circle. Angle AOB = 66°. Work out the size of angle OAB.
OAB66°x
8
FO is the centre of the circle. A and B are points on the circle. Angle AOB = 110°. Work out the size of angle OAB.
OAB110°x
9
FO is the centre of the circle. A and B are points on the circle. Angle OAB = 48°. Work out the size of angle AOB.
OABx48°
10
FO is the centre of the circle. A and B are points on the circle. Angle OAB = 71°. Work out the size of angle AOB.
OABx71°
11
FO is the centre of the circle. A and B are points on the circle. Angle OAB = 15°. Work out the size of angle AOB.
OABx15°
12
PSO is the centre of a circle and A and B are points on the circle. Angle OAB = (2x + 5)° and angle AOB = (x + 10)°. Work out the value of x and the size of angle OAB.
(a)Work out the value of x.
(b)Work out the size of angle OAB.
13
PSA circular cake with centre O is cut into 5 equal sectors. A straight cut AB across one sector makes triangle OAB, where A and B are on the edge of the cake. Work out angle OAB.
OAB72°x
14
PSA, B and C are points on a circle with centre O. Angle AOB = 100° and angle BOC = 80°. Work out the size of angle ABC. Give a reason for each step.
ABCO100°80°x
15
PSA, B and C are points on a circle with centre O. Angle AOB = 130° and angle BOC = 70°. Work out the size of angle ABC. Give a reason for each step.
ABCO130°70°x
16
RA and B are points on a circle with centre O. Angle OAB = x. Show that angle AOB = 180° − 2x.
17
RExplain why each base angle of the isosceles triangle OAB (where OA and OB are radii) must be less than 90°.

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