GCSE Maths · Circle Theorems · Higher · Summary
GCSE Maths Circle Theorems (Higher): summary and key words
Part of the GCSE Maths circle theorems chapter (Higher). Chapter overview · whole chapter on one page
Chapter summary
| Skill | Method |
|---|---|
| Circle words | Radius (centre to circle), diameter (chord through centre), chord (joins two points on the circle), arc, sector (two radii), segment (a chord), tangent (touches at one point) |
| Radii triangle | Two radii are equal, so triangle OAB is isosceles: base angles equal, angles add up to 180° |
| Angle in a semicircle | If AB is a diameter and C is on the circle then angle ACB = 90° |
| Angle at the centre | Centre angle = 2 × circumference angle on the same arc. Minor-arc point: use the reflex angle |
| Same segment | Angles made by the same chord with corners on the same side of it are equal |
| Cyclic quadrilateral | Opposite angles add up to 180°; exterior angle = interior opposite angle |
| Tangent and radius | The angle between a tangent and the radius at the point of contact is 90°; use Pythagoras for lengths |
| Two tangents | Tangents from an external point are equal; OATB is a kite; angle AOB + angle ATB = 180° |
| Alternate segment | Angle between a tangent and a chord = angle in the alternate segment (the opposite side of the chord) |
| Chords | The perpendicular from the centre bisects the chord; r2 = d2 + (half chord)2 |
| Algebra with angles | Equal angles: expression = expression. Angles adding to 180° (or 90°): sum of expressions = 180. Solve, then substitute back |
| Proof | Use letters, give a reason for each line, finish with a conclusion |
Can you…?
- I can name and describe a chord, tangent, arc, sector and segment.
- I can use the angle in a semicircle and explain why it is 90°.
- I can use and prove that the angle at the centre is twice the angle at the circumference, including with a reflex angle.
- I can use angles in the same segment and find the equal pairs in a diagram with crossing chords.
- I can use opposite angles and exterior angles of a cyclic quadrilateral, and prove the theorem.
- I can use a tangent being perpendicular to the radius, and tangents from a point being equal, with angles and Pythagoras.
- I can use and prove the alternate segment theorem.
- I can use that the perpendicular from the centre bisects a chord to find lengths and angles.
- I can combine theorems with isosceles triangles and algebra, giving a reason for every step in standard wording.
- I can write a clear proof or “show that” argument with letters, reasons and a conclusion.
Key terms
- Chord
- A straight line that joins two points on a circle.
- Diameter
- A chord that passes through the centre. It is twice the radius.
- Radius
- A straight line from the centre of a circle to a point on the circle.
- Arc
- A part of the circumference. The shorter is the minor arc, the longer is the major arc.
- Sector
- The region between two radii and an arc.
- Segment
- The region between a chord and an arc.
- Tangent
- A straight line that touches a circle at exactly one point (the point of contact).
- Circumference
- The distance all the way round a circle, or the circle itself.
- Cyclic quadrilateral
- A four-sided shape with all four corners on a circle.
- Alternate segment
- The segment on the opposite side of a chord from a given angle.
- Bisect
- To cut exactly in half.
- Subtend / stand on
- An angle stands on an arc if its arms end at the two ends of that arc.
- Reflex angle
- An angle bigger than 180° and smaller than 360°.
- Kite
- A quadrilateral with two pairs of equal adjacent sides. OATB is a kite when TA and TB are tangents.
- Converse
- The statement the other way round: if the angle is 90°, then the line is a diameter.