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Primary Maths · Year 6Chapter 8 · Algebra
Year 6 · Algebra · Lesson 8.6

Year 6: Combinations of two variables

Part of the Year 6 algebra chapter. Chapter overview · whole chapter on one page

8.6

Combinations of two variables

Year 6
Enumerate possibilities of combinations of two variables

Sometimes two letters stand for amounts of two things, and the amounts must add up to a total. For example, if a is the number of 2p coins and b is the number of 5p coins, then the total value is 2a + 5b pence.

To find every combination, we list every possible number of one item, in order, and work out the number of the other item each time. Only the lists where the number of each item is a whole number that fits the total count as combinations.

Make a table, so that no combination is missed and none is counted twice.

Key ideas

  • A combination uses a whole number of each item.
  • Start with 0 (or 1, if each item must be used at least once) and count up in order.
  • For each choice, work out how much is left, and check that it can be made with the other item.
  • Count the rows of the table to find the number of combinations.
Worked example 8.6.1
How many different ways can you make 12p using only 2p coins and 5p coins? (You may use none of one kind.)

Key words. A combination is one way of choosing an amount of each thing. To enumerate means to list every possibility in order, so that none is missed.

Method. List every choice in order, check each one, then count the ways.

  1. Write the total and the value of each item. One 2p coin is worth 2p. One 5p coin is worth 5p.
    12p from 2p and 5p items
  2. Choose how many 5p coins, starting at 0, and work out how much is left. The rest of the total must be made from 2p coins.
    the rest must be a whole number of the other item
  3. Keep the list in order, so that no way is missed or repeated. Trying each choice in turn gives a complete list.
    Number of 2p coinsNumber of 5p coinsCheck
    121 × 2 + 2 × 5 = 12
    606 × 2 + 0 × 5 = 12
  4. Count the ways. Each row is one way.
    2 ways
  5. Write the answer.
    2

Check. Each row adds to 12p, and no row is repeated. ✓

Watch out. Check that every row uses the right number of items. Do not forget the rows where one item is not used, if the question allows it.

Worked example 8.6.2
Pens cost 3p each and pencils cost 5p each. Sam spends exactly 26p and buys at least one of each. How many ways can he do this?

Key words. A combination is one way of choosing an amount of each thing. To enumerate means to list every possibility in order, so that none is missed.

Method. List every choice in order, check each one, then count the ways.

  1. Write the total and the value of each item. One pen is worth 3p. One pencil is worth 5p.
    26p from 3p and 5p items
  2. Choose how many pencils, starting at 1, and work out how much is left. The rest of the total must be made from pens.
    the rest must be a whole number of the other item
  3. Keep the list in order, so that no way is missed or repeated. Trying each choice in turn gives a complete list.
    Number of pensNumber of pencilsCheck
    242 × 3 + 4 × 5 = 26
    717 × 3 + 1 × 5 = 26
  4. Count the ways. Each row is one way.
    2 ways
  5. Write the answer.
    2

Check. Each row adds to 26p, and no row is repeated. ✓

Watch out. Check that every row uses the right number of items. Do not forget the rows where one item is not used, if the question allows it.

Worked example 8.6.3
A game gives 9 points for each red card and 4 points for each blue card. A player scores exactly 49 points, using at least one of each card. How many ways can this happen?

Key words. A combination is one way of choosing an amount of each thing. To enumerate means to list every possibility in order, so that none is missed.

Method. List every choice in order, check each one, then count the ways.

  1. Write the total and the value of each item. One red card is worth 9 points. One blue card is worth 4 points.
    49 points from 9 points and 4 points items
  2. Choose how many blue cards, starting at 1, and work out how much is left. The rest of the total must be made from red cards.
    the rest must be a whole number of the other item
  3. Keep the list in order, so that no way is missed or repeated. Trying each choice in turn gives a complete list.
    Number of red cardsNumber of blue cardsCheck
    1101 × 9 + 10 × 4 = 49
    515 × 9 + 1 × 4 = 49
  4. Count the ways. Each row is one way.
    2 ways
  5. Write the answer.
    2

Check. Each row adds to 49 points, and no row is repeated. ✓

Watch out. Check that every row uses the right number of items. Do not forget the rows where one item is not used, if the question allows it.

Watch out

Check whether the question allows zero of one item. If it says “at least one of each”, start your list at 1, not 0.

Exam tip

Make a table with the two columns and a check column. Stop when the first item is too big to fit the total.

Exercise 8F  Combinations and systems

Non-calculator
1
FHow many different ways can 25p be made using 5p coins and 10p coins? (You may use none of one kind.)
2
FHow many different ways can 30p be made using 2p coins and 10p coins? Use at least one of each coin.
3
PSA club gives 7 points for each adult and 3 points for each child. The total is 40 points. There is at least one adult and one child. How many ways can this happen?
4
PSx and y are positive whole numbers, and 3x + 2y = 12. How many pairs (x, y) are there?
5
PSMia buys apples at 25p each and bananas at 15p each. She spends exactly 150p and buys at least one of each. How many ways can she do this?
6
PSUsing 2p and 10p coins, with at least one of each, how many ways can 16p be made?
7
RBen has 12 counters, all red or blue. Red counters are worth 2 points and blue counters are worth 3 points. His score is 30 points. How many blue counters does he have?
8
PSUsing 5p and 10p coins, with at least one of each, how many ways can 40p be made?
9
RSam says there are 4 ways to make 12p using 2p and 3p coins, with at least one of each. Is he right?
10
PSA pencil costs 3p and a rubber costs 7p. Sam spends exactly 30p and buys at least one of each. How many ways can he do this?
11
RAli has 20 coins, all 2p or 5p, worth 70p altogether. How many 5p coins does he have?
12
RTom has 10 coins, all 50p or 20p, worth £2.60 altogether. How many 50p coins does he have?

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