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GCSE Maths · EdexcelChapter 2 · Factors, multiples, primes and powers
GCSE Maths · Factors, Multiples and Primes · Foundation · Lesson 2.7

GCSE Maths: Powers and the laws of indices (Foundation)

Part of the GCSE Maths factors, multiples and primes chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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2.7

Powers and the laws of indices

Edexcel 1MA1: N7
Grade 3-6

A power (or index) tells you how many times to multiply a number by itself. In 25 the base is 2 and the index is 5, so 25 = 2 × 2 × 2 × 2 × 2 = 32. The plural of index is indices. Powers let us write long multiplications briefly. The laws of indices are shortcuts for working with powers of the same base.

Law 1: multiplying. What is 23 × 24? Write out the copies of 2:

22222223 lots of 24 lots of 23 + 4 = 7 lots of 2 in total
23 × 24 has three 2s and four 2s multiplied together: seven 2s in all, so it is 27.

So 23 × 24 = 23+4 = 27 = 128. When you multiply powers of the same base, add the indices.

Law 2: dividing. 26 ÷ 22 = (2 × 2 × 2 × 2 × 2 × 2) ÷ (2 × 2). Two 2s cancel top and bottom, leaving four 2s. So 26 ÷ 22 = 26−2 = 24 = 16. When you divide powers of the same base, subtract the indices.

Law 3: a power of a power. (23)2 = 23 × 23 = 23+3 = 26. That is 2 lots of 3 copies, which is 2 × 3 = 6 copies. When you raise a power to a power, multiply the indices.

Key ideas

  • Multiply: am × an = am+n (add the indices).
  • Divide: am ÷ an = am−n (subtract the indices).
  • Power of a power: (am)n = amn (multiply the indices).
  • The laws only work when the bases are the same. If they are different, try to rewrite them as powers of the same base (for example 4 = 22).
  • Do powers before multiplying (BIDMAS).
Worked example 2.7.1
Write 23 × 24 as a single power of 2, and work out its value.

Key words. In 25, 2 is the base and 5 is the index (also called the power or exponent). The plural of index is indices. 25 means five 2s multiplied together.

Method. To multiply powers of the same base, add the indices: am × an = am+n.

  1. Write each power out in full. 23 is 3 copies of 2 multiplied, and 24 is 4 copies.
    23 = 2 × 2 × 2
    24 = 2 × 2 × 2 × 2
  2. Join them into one multiplication and count the copies of 2. Multiplying the two powers puts all the copies together: 3 + 4 copies.
    3 + 4 = 7 copies of 2
  3. Write the answer as a single power. The number of copies is the new index. This is the rule: add the indices when you multiply powers of the same base.
    23 × 24 = 27
  4. Work out the value. Multiply the copies out.
    27 = 128

Check. Work out each power: 8 × 16 = 128, which is 27. ✓

Watch out. Add the indices, do not multiply them: 23 × 24 = 27, not 212. And the base stays the same.

Worked example 2.7.2
Write 56 ÷ 52 as a single power of 5, and work out its value.

Key words. In 25, 2 is the base and 5 is the index (also called the power or exponent). The plural of index is indices. 25 means five 2s multiplied together.

Method. To divide powers of the same base, subtract the indices: am ÷ an = am−n.

  1. Write the division as a fraction with each power written in full. A fraction line means divide, and it lets us cancel.
    56 ÷ 52 = 5 × 5 × 5 × 5 × 5 × 55 × 5
  2. Cancel the copies of 5 that appear on the top and the bottom. Each 5 on the bottom cancels with one on the top, because 5 ÷ 5 = 1. We cancel 2 of them.
    6 − 2 = 4 copies of 5 left on the top
  3. Write the answer as a single power. The copies left on the top are the new index. This is the rule: subtract the indices when you divide powers of the same base.
    56 ÷ 52 = 54
  4. Work out the value. Multiply the copies out.
    54 = 625

Check. 15,625 ÷ 25 = 625. ✓

Watch out. Subtract the indices, do not divide them. The base stays 5.

Worked example 2.7.3
Write (32)3 as a single power of 3, and work out its value.

Key words. In 25, 2 is the base and 5 is the index (also called the power or exponent). The plural of index is indices. 25 means five 2s multiplied together.

Method. To raise a power to a power, multiply the indices: (am)n = amn.

  1. Write the outer power as repeated multiplication of the bracket. (32)3 means 3 copies of 32 multiplied together.
    (32)3 = 32 × 32 × 32
  2. Each bracket holds 2 copies of 3. Count the copies altogether. 3 brackets with 2 copies in each.
    3 × 2 = 6 copies of 3
  3. Write the answer as a single power. This is the rule: multiply the indices when you raise a power to a power.
    (32)3 = 36
  4. Work out the value. Multiply the copies out.
    36 = 729

Check. 93 = 729 and 36 = 729. ✓

Watch out. (32)3 multiplies the indices (2 × 3 = 6). Do not add them: 2 + 3 = 5 is the rule for multiplying two separate powers.

Worked example 2.7.4
Write (25 × 24) ÷ 23 as a single power of 2.

Key words. In 25, 2 is the base and 5 is the index (also called the power or exponent). The plural of index is indices. 25 means five 2s multiplied together.

Method. Use the index laws one at a time, in BIDMAS order: add indices to multiply, subtract to divide, multiply for a power of a power.

  1. Write the expression. Look for brackets and decide the order.
    (25 × 24) ÷ 23
  2. Do the multiplication on the top first. Multiplying powers of the same base: add the indices.
    25 × 24 = 29   (5 + 4 = 9)
  3. Now divide. Dividing powers of the same base: subtract the indices.
    29 ÷ 23 = 26   (9 − 3 = 6)

Check. Evaluate the original with numbers: 32 × 16 ÷ 8 = 64. ✓

Watch out. Only combine indices when the bases are the same. 23 × 32 cannot be written as one power.

Worked example 2.7.5
Find the value of n when 3n × 34 = 39.

Key words. In 25, 2 is the base and 5 is the index (also called the power or exponent). The plural of index is indices. 25 means five 2s multiplied together.

Method. Use the index law to write the left side as a single power, then make the indices equal.

  1. Write the equation. We want the value of n.
    3n × 34 = 39
  2. Use the multiplication law on the left. Add the indices.
    3n × 34 = 3n + 4
  3. Make the indices equal. The bases are the same, so the indices must match.
    n + 4 = 9
  4. Solve. Subtract 4 from both sides.
    n = 9 − 4 = 5

Check. 35 × 34 = 39 = 39. ✓

Watch out. Use the law in the correct direction: add for multiply, subtract for divide, multiply for a power of a power.

Watch out

You add the indices when multiplying, not multiply them: 23 × 24 = 27, not 212. And the base does not change: 23 × 24 is not 47. The laws do not work for adding: 23 + 24 = 8 + 16 = 24, which is not 27.

Exercise 2G  Laws of indices

Non-calculator
1
FWrite each of these as a single power.
(a)34 × 32
(b)53 × 56
(c)27 × 25
(d)72 × 79
(e)104 × 103
(f)42 × 45
2
FWrite each of these as a single power.
(a)29 ÷ 24
(b)58 ÷ 55
(c)37 ÷ 32
(d)76 ÷ 73
(e)108 ÷ 105
(f)65 ÷ 62
3
FWrite each of these as a single power.
(a)(32)4
(b)(53)2
(c)(24)3
(d)(102)5
(e)(73)2
(f)(42)3
4
FWrite each as a single power, then work out its value.
(a)23 × 22
(b)35 ÷ 33
(c)(22)3
(d)102 × 103
(e)54 ÷ 52
(f)(32)2
5
FFind the value of n in each equation.
(a)2n × 23 = 28
(b)7n × 75 = 79
(c)3n ÷ 32 = 35
(d)5n ÷ 54 = 53
(e)(2n)3 = 212
(f)(10n)2 = 106
6
FWrite each as a single power, then work out its value.
(a)(25 × 24) ÷ 23
(b)(32)3 × 31
(c)29 ÷ (22 × 23)
(d)(56 × 53) ÷ 54
(e)(23)2 × 24
(f)310 ÷ (33 × 32)
7
FFind the value of x in each equation.
(a)2x = 64
(b)3x = 81
(c)5x = 125
(d)2x = 1024
(e)4x = 256
(f)3x = 729
8
PSA tile is placed in a pattern. Each row has twice as many tiles as the row before. Row 1 has 2 tiles, so row n has 2n tiles. How many tiles are in row 10?
9
PSA sheet of paper is 0.1 mm thick. Each time it is folded in half the thickness doubles. (a) Write the thickness after 10 folds as a number multiplied by a power of 2. (b) Work out the thickness after 10 folds in mm.
(a)(a)
(b)(b)
10
RCheck each statement and decide whether the pupil is correct. Explain any mistake.
(a)Ali says: 23 × 24 = 47
(b)Ben says: (23)2 = 25
(c)Cara says: 32 + 33 = 35
11
R2a × 2b = 210 and 2a ÷ 2b = 22. Find the values of a and b.

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