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GCSE Maths · EdexcelChapter 8 · Substitution and formulae
GCSE Maths · Substitution and Formulae · Foundation · Lesson 8.9

GCSE Maths: Using formulae: problems and reasoning (Foundation)

Part of the GCSE Maths substitution and formulae chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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8.9

Using formulae: problems and reasoning

Edexcel 1MA1: A2, A5, A21
Grade 4-8

Exam questions often use a formula in a short story, and you must decide what to do. Here is a reliable plan.

1. Readlist what youknow and want2. Choosethe formula3. Rearrange(if the subjectis wrong)4. Substituteand work out5. Checkunits andsense
A five-step plan for formula problems.

There are two sound ways to find an unknown that is not the subject. Suppose A = ½(a + b)h and we know A, a and b but want h.

Other useful skills in this section:

rh
A cylinder of radius r and height h has volume V = πr²h.

Key ideas

  • Read carefully and write down what you know and what you want.
  • Either substitute first and solve, or rearrange first and substitute.
  • Check units (convert minutes to hours, pence to pounds) before you start.
  • To check a formula, try simple numbers. To show something, give a calculation and a conclusion.
  • Does the answer make sense? A speed of 600 km/h for a bike does not.

Watch out

Average speed is total distance ÷ total time. It is not the average of the two speeds. If you ride 12 km at 15 km/h and 8 km at 10 km/h, the average speed is not (15 + 10) ÷ 2 = 12.5 by luck: work out each time first.
Worked example 8.9.1
The area of a trapezium is A = ½(a + b)h. A trapezium has area 54 cm², a = 7 cm and b = 11 cm. Work out h.

Method. Substitute the known values, simplify, then solve the simple equation for h.

  1. Write the formula and substitute. Put in A = 54, a = 7 and b = 11.
    54 = ½ × (7 + 11) × h
  2. Work out the bracket, then ½ of it. Brackets first. 7 + 11 = 18 and ½ of 18 is 9.
    54 = 9h
  3. Divide both sides by 9. h is multiplied by 9, so the inverse is dividing by 9.
    h = 54 ÷ 9 = 6 cm

Check. Put h = 6 back: A = 12 × (7 + 11) × 6 = 12 × 18 × 6 = 9 × 6 = 54 cm². ✓

Watch out. Do not forget the ½. A common slip is to forget it and get h = 3.

Worked example 8.9.2
A cyclist rides 12 km at 15 km/h and then 8 km at 10 km/h. Work out her average speed for the whole journey.

Method. Average speed = total distance ÷ total time. Use t = d/s to find each time first.

  1. Find the time for the first part. Time = distance ÷ speed.
    t = 1215 = 0.8 hours (= 0.8 h)
  2. Find the time for the second part. Same formula.
    t = 810 = 0.8 hours (= 0.8 h)
  3. Add the distances and the times. The whole journey is both parts together.
    distance = 12 + 8 = 20 km
    time = 0.8 + 0.8 = 1.6 hours
  4. Work out the average speed. Use s = d/t with the totals.
    s = 201.6 = 12.5 km/h

Check. In 1.6 hours at 12.5 km/h she would travel 1.6 × 12.5 = 20 km. ✓

Watch out. The average of the two speeds is 12.5 here only by chance; try 12 km at 12 km/h and 4 km at 4 km/h to see it fail.

Worked example 8.9.3
A circular lawn has circumference 31.4 m. Use π = 3.14 and the formulae C = 2πr and A = πr² to work out its area.

Method. The area needs the radius. Use the circumference formula to find r first, then use it in the area formula.

  1. Make r the subject of C = 2πr. Divide both sides by 2π.
    r = C2π
  2. Substitute to find r. 2 × 3.14 = 6.28 and 31.4 ÷ 6.28 = 5.
    r = 31.42 × 3.14 = 31.46.28 = 5 m
  3. Use r in the area formula. Square first, then multiply by π.
    A = 3.14 × 52 = 3.14 × 25 = 78.5 m²

Check. Estimate: π ≈ 3 and 3 × 25 = 75, close to 78.5. ✓

Watch out. Find the radius first. Do not put the circumference straight into the area formula.

Exercise 8J  Using formulae: problems and reasoning

Non-calculator
1
PSThe volume of a cylinder is V = πr²h.
rh
(a)Make h the subject.
(b)A cylinder has volume 157 cm³ and radius 5 cm. Use π = 3.14 to work out its height.
2
PSA bicycle wheel has circumference 220 cm. Use C = πd with π = 227 to work out the diameter of the wheel.
3
PSA car travels 30 km at 60 km/h and then 60 km at 40 km/h. Use t = d/s to find the time for each part, then work out the average speed for the whole journey.
4
R(a) Make C the subject of F = 95C + 32. (b) Show that −40°C is the same temperature as −40°F.
(a)Make C the subject
(b)Show that −40°C = −40°F
5
RThe area of a circle of radius r is A = πr². Show that doubling the radius makes the area four times as big.
6
PSA car of mass 1200 kg has kinetic energy E = ½mv² joules when its speed is v m/s.
(a)Work out E when v = 20.
(b)Work out E when v = 40.
(c)How many times bigger is the energy when the speed is doubled?
7
PSDensity is D = m/V.
(a)Make m the subject.
(b)Steel has density 7800 kg/m³. Work out the mass of 2.5 m³ of steel.
8
RShow that the expression 3(x + 2) − 3x − 6 is always equal to 0, whatever the value of x.
9
PSA model for the stopping distance d metres of a car travelling at v metres per second is d = 0.3v + v²50.
(a)Work out d when v = 20.
(b)Work out d when v = 40.
(c)Tom says, “If the speed doubles, the stopping distance doubles.” Use your answers to show that Tom is wrong.
10
RThe formula y = 3x + 2 is rearranged to give x = y − 23. Show that putting this value of x back into 3x + 2 gives y.

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