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GCSE Maths · EdexcelChapter 9 · Linear equations
GCSE Maths · Linear Equations · Foundation · Lesson 9.5

GCSE Maths: Equations with brackets (Foundation)

Part of the GCSE Maths linear equations chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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9.5

Equations with brackets

Edexcel 1MA1: A17
Grade 4-6

A bracket means “multiply everything inside by the number outside”. In 3(x + 4) the 3 multiplies both the x and the 4. You met expanding in Chapter 7. A picture helps: the rectangle below has height 3 and width (x + 4), so its area is 3(x + 4). Cut it into two rectangles and the area is 3 × x + 3 × 4 = 3x + 12.

3x12x433(x + 4) = 3x + 12
The bracket multiplies every term inside it: 3(x + 4) = 3x + 12.

To solve an equation with brackets, expand the brackets first, collect like terms if there are any, and then solve as before.

A shortcut when the bracket stands alone. If the whole of one side is a bracket and the other side is a number, such as 3(x + 4) = 27, you can divide both sides by 3 first: x + 4 = 9, so x = 5. This works because 3 is multiplying the entire bracket. Expanding first also works: 3x + 12 = 27, 3x = 15, x = 5. Use whichever you find easier; expanding always works.

Negative numbers and minus signs. A minus sign in front of a bracket multiplies everything inside by −1, so it changes the sign of every term inside. 10 − (x + 2) = 10 − x − 2 = 8 − x. Likewise −2(x − 3) = −2x + 6, because (−2) × (−3) = +6.

When there are brackets on both sides, expand both, then collect the x terms as in the last section.

Key ideas

  • Expand first: multiply every term inside the bracket by the number outside.
  • A minus sign in front of a bracket changes the sign of every term inside it.
  • Collect like terms, then solve (unknown on both sides: remove the smaller x term).
  • Shortcut: if one side is just a bracket and the other is a number, you may divide both sides by the number in front of the bracket first.
Worked example 9.5.1
Solve 3(x + 4) = 27.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    3(x + 4) = 27
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 3(x + 4):
    3 × x = 3x
    3 × 4 = 12

    The equation is now 3x + 12 = 27
  3. Subtract 12 from both sides. This undoes the +12, because +12 − 12 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    3x + 12 − 12 = 27 − 12
    3x = 15
  4. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    3x3 = 153
    x = 153 = 5
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 5

Check. Substitute x = 5 into the original equation. Left side: 3 × (5 + 4) = 3 × 9 = 27. Right side: 27. Both sides equal 27, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Worked example 9.5.2
Solve 2(3x − 5) = 14.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    2(3x − 5) = 14
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 2(3x − 5):
    2 × 3x = 6x
    2 × (−5) = −10

    The equation is now 6x − 10 = 14
  3. Add 10 to both sides. This undoes the −10, because −10 + 10 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    6x − 10 + 10 = 14 + 10
    6x = 24
  4. Divide both sides by 6. 6x means 6 multiplied by x. The inverse of multiplying by 6 is dividing by 6, and we do it to both sides to keep the balance. This leaves x on its own.
    6x6 = 246
    x = 246 = 4
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 4

Check. Substitute x = 4 into the original equation. Left side: 2 × (3 × 4 − 5) = 2 × 7 = 14. Right side: 14. Both sides equal 14, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Worked example 9.5.3
Solve 5(x − 2) = 3(x + 4).

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    5(x − 2) = 3(x + 4)
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 5(x − 2):
    5 × x = 5x
    5 × (−2) = −10

    Expand 3(x + 4):
    3 × x = 3x
    3 × 4 = 12

    The equation is now 5x − 10 = 3x + 12
  3. Remove the x term from the right side: subtract 3x from both sides. We want all the x terms on one side. The right side has 3x; subtracting 3x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    5x − 10 − 3x = 3x + 12 − 3x
    2x − 10 = 12
  4. Add 10 to both sides. This undoes the −10, because −10 + 10 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x − 10 + 10 = 12 + 10
    2x = 22
  5. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = 222
    x = 222 = 11
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 11

Check. Substitute x = 11 into the original equation. Left side: 5 × (11 − 2) = 5 × 9 = 45. Right side: 3 × (11 + 4) = 3 × 15 = 45. Both sides equal 45, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Worked example 9.5.4
Solve 7 − 2(x − 1) = 3.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    7 − 2(x − 1) = 3
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it. A negative number multiplied by a negative number gives a positive answer, and a negative multiplied by a positive gives a negative.
    Expand −2(x − 1):
    (−2) × x = −2x
    (−2) × (−1) = 2

    The equation is now 7 − 2x + 2 = 3
  3. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the numbers 7 + 2 make 9.
    The equation is now −2x + 9 = 3
  4. Subtract 9 from both sides. This undoes the +9, because +9 − 9 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    −2x + 9 − 9 = 3 − 9
    −2x = −6
  5. Divide both sides by −2. −2x means −2 multiplied by x. The inverse of multiplying by −2 is dividing by −2, and we do it to both sides to keep the balance. This leaves x on its own. Careful with signs: a positive divided by a negative gives a negative answer, and a negative divided by a negative gives a positive.
    −2x−2 = −6−2
    x = −6−2 = 3
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 3

Check. Substitute x = 3 into the original equation. Left side: 7 − 2 × (3 − 1) = 7 − 2 × 2 = 7 − 4 = 3. Right side: 3. Both sides equal 3, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Watch out

Multiply every term in the bracket. 3(x + 4) is 3x + 12, not 3x + 4. And with a negative in front, change both signs: −2(x − 3) = −2x + 6, not −2x − 6.

Exercise 9E  Equations with brackets

Non-calculator
1
FSolve these equations. Each bracket has a plus sign.
(a)2(x + 3) = 14
(b)3(x + 1) = 18
(c)5(x + 2) = 35
(d)4(x + 5) = 36
(e)6(x + 1) = 30
(f)2(x + 9) = 30
2
FSolve these equations. Each bracket has a minus sign.
(a)3(x − 2) = 15
(b)2(x − 4) = 10
(c)5(x − 1) = 20
(d)4(x − 3) = 8
(e)3(2x + 1) = 21
(f)2(3x − 4) = 22
3
FSolve these equations. Expand the bracket first.
(a)3(x + 2) + 4 = 19
(b)2(x + 5) − 3 = 19
(c)4(x − 1) + 7 = 23
(d)5(x + 2) − 8 = 27
(e)2(2x + 1) + 5 = 19
(f)3(x − 4) + 2 = 8
4
FSolve these equations. There is a bracket on one side and x on the other.
(a)3(x + 2) = 2x + 9
(b)4(x − 1) = 2x + 8
(c)2(x + 5) = x + 14
(d)5(x − 3) = 3x + 1
(e)3(2x + 1) = 4x + 11
(f)2(3x − 2) = 5x + 3
5
FSolve these equations. There are brackets on both sides.
(a)5(x − 2) = 3(x + 4)
(b)2(x + 7) = 4(x + 1)
(c)4(x − 1) = 3(x + 2)
(d)4(x + 3) = 3(x + 6)
(e)6(x − 2) = 2(x + 8)
(f)5(2x − 1) = 3(3x + 1)
6
FSolve these equations. Be careful with the minus signs in front of the brackets.
(a)10 − (x + 2) = 5
(b)7 − 2(x − 1) = 3
(c)20 − 3(x + 1) = 2
(d)5 − (x − 3) = 1
(e)12 − 2(x + 3) = 4
(f)9 − 3(x − 2) = 6
7
RJo expands 3(x − 4) and gets 3x − 4. Explain her mistake. Then solve 3(x − 4) = 15.
8
PSI think of a number, add 4 and then multiply the result by 3. My answer is 33. What number did I think of?
9
PSAt a museum, a child ticket costs £3 less than an adult ticket. Two adult tickets and three child tickets cost £41 altogether. Work out the cost of an adult ticket.
10
RShow that x = 4 is the solution of 2(3x − 5) = 5x − 6.
11
PSThe area of this rectangle is 36 cm2. Work out the value of x.
(x + 5) cm3 cm
12
FSolve these equations.
(a)2(x + 3) = 10
(b)3(x − 1) = 12
(c)4(x + 2) = 20

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