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GCSE Maths · EdexcelChapter 9 · Linear equations
GCSE Maths · Linear Equations · Foundation · Lesson 9.4

GCSE Maths: The unknown on both sides (Foundation)

Part of the GCSE Maths linear equations chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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9.4

The unknown on both sides

Edexcel 1MA1: A17
Grade 4-5

Often the letter appears on both sides of the equals sign, such as 3x + 2 = x + 8. Now we cannot get x on its own just by undoing one side. First we must collect all the x terms on one side.

Think of the scales again. The left pan has three boxes and two circles, the right pan has one box and eight circles. Take one box off both pans and the scales still balance.

xxxx3x + 2 = x + 8xx2x + 2 = 8xx2x = 6
Take 1 box off both pans, then take 2 circles off both pans. Two boxes balance 6 circles, so one box is 3.

Here is the method.

  1. Choose the smaller x term (the one with the smaller number in front of x) and remove it from both sides. Subtracting the smaller one means the x terms that are left are positive.
  2. Move the plain numbers to the other side: add or subtract the number that is on the same side as the x term, on both sides.
  3. Divide both sides by the number in front of x.

For 3x + 2 = x + 8, the smaller x term is x (that is 1x). Subtract x from both sides to get 2x + 2 = 8. Then subtract 2 to get 2x = 6, and divide by 2 to get x = 3.

What if the bigger x term is on the right? In 3x + 10 = 7x − 6, the smaller x term is 3x on the left. Subtract 3x from both sides: 10 = 4x − 6. Add 6: 16 = 4x. Divide by 4: 4 = x, which means x = 4. You could remove the bigger x term instead, but then you get a negative number of x and mistakes with signs become more likely. Both ways give the same answer.

Key ideas

  • Remove the smaller x term from both sides, so the x terms combine on one side.
  • Then move the plain numbers to the other side, and divide.
  • When you subtract a term from both sides, subtract it from every part of both sides, and watch the signs.
  • Check by substituting into both sides of the original equation.
Worked example 9.4.1
Solve 5x + 3 = 2x + 12.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    5x + 3 = 2x + 12
  2. Remove the x term from the right side: subtract 2x from both sides. We want all the x terms on one side. The right side has 2x; subtracting 2x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    5x + 3 − 2x = 2x + 12 − 2x
    3x + 3 = 12
  3. Subtract 3 from both sides. This undoes the +3, because +3 − 3 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    3x + 3 − 3 = 12 − 3
    3x = 9
  4. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    3x3 = 93
    x = 93 = 3
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 3

Check. Substitute x = 3 into the original equation. Left side: 5 × 3 + 3 = 15 + 3 = 18. Right side: 2 × 3 + 12 = 6 + 12 = 18. Both sides equal 18, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Worked example 9.4.2
Solve 7x − 4 = 3x + 20.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    7x − 4 = 3x + 20
  2. Remove the x term from the right side: subtract 3x from both sides. We want all the x terms on one side. The right side has 3x; subtracting 3x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    7x − 4 − 3x = 3x + 20 − 3x
    4x − 4 = 20
  3. Add 4 to both sides. This undoes the −4, because −4 + 4 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    4x − 4 + 4 = 20 + 4
    4x = 24
  4. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    4x4 = 244
    x = 244 = 6
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 6

Check. Substitute x = 6 into the original equation. Left side: 7 × 6 − 4 = 42 − 4 = 38. Right side: 3 × 6 + 20 = 18 + 20 = 38. Both sides equal 38, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Worked example 9.4.3
Solve 3x + 10 = 7x − 6.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    3x + 10 = 7x − 6
  2. Remove the x term from the left side: subtract 3x from both sides. We want all the x terms on one side. The left side has 3x; subtracting 3x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    3x + 10 − 3x = 7x − 6 − 3x
    10 = 4x − 6
  3. Add 6 to both sides. This undoes the −6, because −6 + 6 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    10 + 6 = 4x − 6 + 6
    16 = 4x
  4. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    164 = 4x4
    x = 164 = 4
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 4

Check. Substitute x = 4 into the original equation. Left side: 3 × 4 + 10 = 12 + 10 = 22. Right side: 7 × 4 − 6 = 28 − 6 = 22. Both sides equal 22, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Worked example 9.4.4
Solve 2x + 9 = 5x + 15.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    2x + 9 = 5x + 15
  2. Remove the x term from the left side: subtract 2x from both sides. We want all the x terms on one side. The left side has 2x; subtracting 2x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    2x + 9 − 2x = 5x + 15 − 2x
    9 = 3x + 15
  3. Subtract 15 from both sides. This undoes the +15, because +15 − 15 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    9 − 15 = 3x + 15 − 15
    −6 = 3x
  4. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    −63 = 3x3
    x = −63 = −2
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = −2

Check. Substitute x = −2 into the original equation. Left side: 2 × (−2) + 9 = −4 + 9 = 5. Right side: 5 × (−2) + 15 = −10 + 15 = 5. Both sides equal 5, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Watch out

Take the x term away from both sides, and think about the sign. In 5x − 3 = 2x + 9, subtracting 2x from both sides gives 3x − 3 = 9. If you add 2x to the left (a common mistake) you get 7x, which is wrong.

Exercise 9D  The unknown on both sides

Non-calculator
1
FSolve these equations. There are no plain numbers to move.
(a)5x = 3x + 8
(b)4x = x + 12
(c)7x = 4x + 15
(d)6x = 2x + 20
(e)9x = 5x + 28
(f)8x = 3x + 35
2
FSolve these equations.
(a)3x + 5 = x + 11
(b)5x + 2 = 2x + 14
(c)4x + 1 = x + 16
(d)6x + 3 = 4x + 11
(e)7x + 4 = 3x + 20
(f)8x + 1 = 5x + 19
3
FSolve these equations. Each has a subtraction.
(a)5x − 3 = 2x + 9
(b)6x − 4 = 3x + 14
(c)4x − 7 = x + 8
(d)7x − 1 = 5x + 13
(e)9x − 8 = 4x + 27
(f)8x − 5 = 3x + 20
4
FSolve these equations. The bigger x term is on the right-hand side.
(a)x + 12 = 3x + 4
(b)2x + 9 = 5x
(c)3x + 8 = 5x − 4
(d)4x + 3 = 7x − 18
(e)2x + 15 = 6x − 13
(f)3x + 7 = 8x − 23
5
FSolve these equations. Each solution is a negative number.
(a)2x + 9 = 5x + 15
(b)3x + 14 = 7x + 22
(c)5x + 4 = 8x + 13
(d)2x − 3 = 4x + 7
(e)x + 1 = 4x + 10
(f)6x + 5 = 9x + 20
6
PSTaxi firm A charges £3 plus £2 per mile. Taxi firm B charges £1 plus £3 per mile. For how many miles do the two firms charge the same amount?
7
PSSam thinks of a number. He multiplies it by 5 and subtracts 6. If he had multiplied it by 3 and added 10 instead, he would have got the same answer. What is Sam's number?
8
RLily solves 6x + 5 = 2x + 17. Her first line is 8x + 5 = 17. Explain her mistake and solve the equation correctly.
9
RShow that x = 5 is the solution of 7x − 9 = 3x + 11.
10
PSAli has £5 and saves £4 each week. Ben has £21 and saves £2 each week. After how many weeks will they have the same amount?
11
RTo solve 3x + 8 = 7x − 4, Amy subtracts 7x from both sides and gets −4x + 8 = −4. Ben subtracts 3x from both sides and gets 8 = 4x − 4. Show that they both get the same value of x.
12
FSolve these equations.
(a)2x + 4 = x + 9
(b)3x = x + 10
(c)4x + 2 = 2x + 12

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