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GCSE Maths · EdexcelChapter 9 · Linear equations
Chapter 9 · Foundation tier

GCSE Maths Linear Equations (Foundation): worked examples and questions with answers

By the end of this chapter you will be able to

  • Explain what an equation is and use the balance idea: do the same to both sides
  • Solve one-step and two-step equations, including negative and fractional solutions
  • Solve equations with the unknown on both sides and equations with brackets
  • Solve equations that contain fractions (Higher: including algebraic fractions)
  • Form an equation from words, perimeters, angles, ages and costs, solve it and interpret the answer
  • Check a solution by substitution, and find approximate solutions using a graph

You should already know

  • Negative numbers and the four operations (Chapter 1)
  • Collecting like terms and expanding brackets (Chapter 7)
  • Fractions and common denominators (Chapter 3)

Where this leads

  • Rearranging formulae (Chapter 8)
  • Inequalities (Chapter 10)
  • Straight-line graphs (Chapter 12)
  • Simultaneous equations (Chapter 14)

Edexcel GCSE (9–1) Mathematics 1MA1, Foundation tier. Content references: A17, A21.

Printable worksheets. Every lesson in this chapter has a free worksheet and an answer sheet to download and print.

Exercise P  Do you remember?

Non-calculator
1
FWork out 4 − 9.
2
FSimplify 3x + 5x − 2.
3
FExpand 3(x + 4).
4
FWork out the value of 2n + 3 when n = 4.
5
FFind the lowest common multiple (LCM) of 2 and 3.
9.1

Equations and the balance idea

Edexcel 1MA1: A17
Grade 1-3

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Equations and the balance ideaComing soon

In algebra a letter stands for a number that we do not know yet. An expression such as 3x + 5 has no equals sign. It is just a recipe for making a number, so it has no single answer. An equation such as 3x + 5 = 20 does have an equals sign. It says that two things have the same value. To solve an equation means to find the value of the letter that makes the statement true.

The best way to think about an equation is as a pair of balanced scales. Whatever is on the left pan weighs exactly the same as whatever is on the right pan. In the picture, the blue box is an unknown mass x and each orange circle is 1 kg. The scales balance, so x + 3 = 7.

xx + 3 = 7xx = 4
Take 3 away from both pans and the scales still balance. The box is left on its own, and it balances 4 circles, so x = 4.

This gives us the one rule of equation solving: whatever you do to one side, do the same to the other side. If you take 3 kg off one pan but not the other, the scales tip and the equation is no longer true. Our aim is always to get the letter on its own, with nothing added to it, taken away from it, multiplying it or dividing it.

To get the letter on its own we undo what has been done to it. We use the inverse operation, which is the operation that does the opposite. Adding and subtracting are inverses of each other. Multiplying and dividing are inverses of each other.

The equation looks likeIt meansDo this to both sides
x + 5 = 125 has been addedsubtract 5
x − 5 = 125 has been taken awayadd 5
5x = 20x has been multiplied by 5divide by 5
x5 = 4x has been divided by 5multiply by 5

Remember that 5x is short for 5 × x: in algebra we do not write the multiplication sign. Also remember that x5 means x ÷ 5, as you saw with fractions in Chapter 3.

xx2x = 8xx = 4
Two equal boxes balance 8 circles. Cut each pan in half (divide both sides by 2): one box balances 4 circles.

Key ideas

  • An equation has an equals sign; an expression does not.
  • To solve an equation is to find the value of the letter that makes it true.
  • Do the same to both sides so that the equation stays balanced.
  • Use the inverse operation: the opposite of + is −, and the opposite of × is ÷.
  • Finish with the letter on its own: x = a number.
Worked example 9.1.1
Solve x + 7 = 15.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x + 7 = 15
  2. Subtract 7 from both sides. This undoes the +7, because +7 − 7 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    x + 7 − 7 = 15 − 7
    x = 8
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 8

Check. Substitute x = 8 into the original equation. Left side: 8 + 7 = 15. Right side: 15. Both sides equal 15, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.1.2
Solve x − 4 = 9.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x − 4 = 9
  2. Add 4 to both sides. This undoes the −4, because −4 + 4 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    x − 4 + 4 = 9 + 4
    x = 13
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 13

Check. Substitute x = 13 into the original equation. Left side: 13 − 4 = 9. Right side: 9. Both sides equal 9, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.1.3
Solve 5x = 35.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    5x = 35
  2. Divide both sides by 5. 5x means 5 multiplied by x. The inverse of multiplying by 5 is dividing by 5, and we do it to both sides to keep the balance. This leaves x on its own.
    5x5 = 355
    x = 355 = 7
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 7

Check. Substitute x = 7 into the original equation. Left side: 5 × 7 = 35. Right side: 35. Both sides equal 35, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.1.4
Solve x3 = 6.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x3 = 6
  2. Multiply both sides by 3. x3 means x divided by 3. The inverse of dividing by 3 is multiplying by 3. We do it to both sides to keep the balance.
    3 × x3 = 3 × 6
    x = 18
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 18

Check. Substitute x = 18 into the original equation. Left side: 183 = 6. Right side: 6. Both sides equal 6, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Watch out

Do the opposite operation. To solve x + 6 = 15 you subtract 6 from both sides, giving x = 9. Adding 6 would give 21, which is wrong. Always check your answer by putting it back into the equation.

Exercise 9A  Equations and one-step equations

Non-calculator
1
FWrite down whether each of these is an expression or an equation.
(a)4x + 1
(b)4x + 1 = 13
(c)7 − x
(d)x5 = 2
2
FSolve these equations. Each one needs you to subtract.
(a)x + 3 = 10
(b)x + 8 = 15
(c)x + 6 = 9
(d)x + 15 = 40
(e)7 + x = 12
(f)x + 25 = 61
3
FSolve these equations. Each one needs you to add.
(a)x − 2 = 7
(b)x − 5 = 9
(c)x − 10 = 4
(d)x − 1 = 20
(e)x − 8 = 8
(f)x − 3 = 0
4
FSolve these equations. Each one needs you to divide.
(a)2x = 14
(b)5x = 20
(c)3x = 27
(d)10x = 90
(e)4x = 36
(f)7x = 56
5
FSolve these equations. Each one needs you to multiply.
(a)x2 = 5
(b)x3 = 4
(c)x5 = 6
(d)x10 = 3
(e)x4 = 8
(f)x7 = 7
6
FWrite down the operation you do to both sides first to get x on its own. You do not need to finish solving.
(a)x + 9 = 14
(b)x − 6 = 10
(c)4x = 20
(d)x5 = 3
7
FSolve these equations, using what you know about inverse operations.
(a)x + 47 = 91
(b)8x = 96
(c)x − 29 = 31
(d)x6 = 12
(e)x + 148 = 372
(f)12x = 180
8
PSRavi thinks of a number. He adds 9 and gets 25. What number did Ravi think of?
9
PSA box of 8 identical chocolates costs £6. Work out the cost of one chocolate. Give your answer in pence.
10
PSThe scales balance. The box has a mass of x kg. Write down an equation and use it to find the mass of the box.
x12box + 5 kg = 12 kg
11
FSam says “x = 4” is the solution of each equation. Substitute 4 for x to decide whether he is right. Write yes or no.
(a)x + 5 = 9
(b)3x = 15
(c)x − 2 = 3
(d)x2 = 2
12
RSam solves x + 6 = 15 and writes x = 21. Explain his mistake and work out the correct solution.
13
PSWrite an equation for each sentence, then solve it to find the number.
(a)A number plus 7 is 19
(b)A number minus 6 is 11
(c)5 times a number is 40
(d)A number divided by 4 is 9
14
RThe equations x + a = 12 and 3x = 18 have the same solution. Work out the value of a.
15
FComplete the solutions. Use the balance idea to find x.
(a)x + 1 = 4
(b)x + 2 = 5
(c)2x = 6
(d)x − 1 = 3
16
PSThere are 5 identical bags of sweets. In total there are 40 sweets. How many sweets are in one bag?
9.2

Two-step equations

Edexcel 1MA1: A17
Grade 2-4

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Two-step equationsComing soon

Many equations need two steps. Look at 3x + 5 = 20. Two things have been done to x: it was first multiplied by 3, and then 5 was added. A function machine shows this.

x×3+520Undo it: do the opposite operations, in the opposite order20−5÷3x
Top row: what the equation does to x. Bottom row: undo it by working backwards, doing the opposite of each operation in the opposite order.

To get x back we undo the steps in reverse order, just as you take your shoes off before your socks if you put your socks on first. We undo the adding first (subtract 5), then the multiplying (divide by 3):

3x + 5 = 20  →  subtract 5 from both sides: 3x = 15  →  divide both sides by 3: x = 5.

Why this order? The “+ 5” is stuck to the whole of 3x. If you divide by 3 first, you have to divide everything (the 5 and the 20 too), which gives fractions and is much harder. Take away the number added or subtracted first, then deal with the multiplication or division.

The same method works when the equation is written the other way round, such as 17 = 2x + 5. The unknown is on the right-hand side, but you do exactly the same steps. When you reach 6 = x you can write it as x = 6, because an equals sign works both ways.

When x is divided by a number, as in x4 − 2 = 3, we still add 2 first, and then multiply by 4 to undo the division.

Key ideas

  • Undo the adding or subtracting first, then undo the multiplying or dividing.
  • Do the same to both sides each time.
  • Write every step on a new line, one operation per line, and keep the equals signs lined up.
  • Always check by substituting your answer back into the original equation.
Worked example 9.2.1
Solve 3x + 5 = 20.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    3x + 5 = 20
  2. Subtract 5 from both sides. This undoes the +5, because +5 − 5 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    3x + 5 − 5 = 20 − 5
    3x = 15
  3. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    3x3 = 153
    x = 153 = 5
  4. Write the solution. x is now on its own, so the equation tells us its value.
    x = 5

Check. Substitute x = 5 into the original equation. Left side: 3 × 5 + 5 = 15 + 5 = 20. Right side: 20. Both sides equal 20, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.2.2
Solve 4x − 7 = 21.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    4x − 7 = 21
  2. Add 7 to both sides. This undoes the −7, because −7 + 7 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    4x − 7 + 7 = 21 + 7
    4x = 28
  3. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    4x4 = 284
    x = 284 = 7
  4. Write the solution. x is now on its own, so the equation tells us its value.
    x = 7

Check. Substitute x = 7 into the original equation. Left side: 4 × 7 − 7 = 28 − 7 = 21. Right side: 21. Both sides equal 21, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.2.3
Solve x5 + 2 = 6.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x5 + 2 = 6
  2. Subtract 2 from both sides. This undoes the +2, because +2 − 2 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    x5 + 2 − 2 = 6 − 2
    x5 = 4
  3. Multiply both sides by 5. x5 means x divided by 5. The inverse of dividing by 5 is multiplying by 5. We do it to both sides to keep the balance.
    5 × x5 = 5 × 4
    x = 20
  4. Write the solution. x is now on its own, so the equation tells us its value.
    x = 20

Check. Substitute x = 20 into the original equation. Left side: 205 + 2 = 4 + 2 = 6. Right side: 6. Both sides equal 6, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.2.4
Solve 17 = 2x + 5.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    17 = 2x + 5
  2. Subtract 5 from both sides. This undoes the +5, because +5 − 5 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    17 − 5 = 2x + 5 − 5
    12 = 2x
  3. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    122 = 2x2
    x = 122 = 6
  4. Write the solution. x is now on its own, so the equation tells us its value.
    x = 6

Check. Substitute x = 6 into the original equation. Left side: 17. Right side: 2 × 6 + 5 = 12 + 5 = 17. Both sides equal 17, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Watch out

Do not divide only one term. In 3x + 5 = 20, dividing just the 3x by 3 gives x + 5 = 20, which is wrong. Subtract 5 first: 3x = 15, then divide both sides by 3.

Exercise 9B  Two-step equations

Non-calculator
1
FSolve these two-step equations. In each, add or subtract first.
(a)2x + 3 = 11
(b)3x + 1 = 16
(c)5x + 4 = 24
(d)4x + 7 = 31
(e)2x + 9 = 21
(f)6x + 2 = 20
2
FSolve these equations. Each has a subtraction.
(a)2x − 3 = 9
(b)3x − 5 = 13
(c)5x − 1 = 24
(d)4x − 9 = 15
(e)7x − 2 = 40
(f)10x − 6 = 34
3
FSolve these equations. Each has a fraction.
(a)x2 + 3 = 8
(b)x3 + 1 = 5
(c)x4 − 2 = 3
(d)x5 + 4 = 9
(e)x6 − 1 = 2
(f)x10 + 7 = 10
4
FSolve these equations. The unknown is on the right-hand side.
(a)13 = 2x + 3
(b)22 = 4x + 2
(c)17 = 3x − 4
(d)30 = 5x + 5
5
FWrite the missing numbers in the working for 6x + 4 = 40.
(a)6x + 4 = 40
(b)6x = 36
6
FSolve 8x + 5 = 93
7
FSolve x7 − 3 = 4
8
PSMia thinks of a number. She multiplies it by 4 and then adds 3. The answer is 35. What was her number?
9
PSThree cinema tickets and a booking fee of £4 cost £31 altogether. The booking fee is charged once. Work out the cost of one ticket.
10
PSJade has £12. She saves £5 each week. After how many weeks will she have £62?
11
RAli and Beth each solve an equation. Ali solves 4x + 3 = 19. Beth solves 3x − 1 = 11. Who gets the bigger answer, and by how much?
12
RZoe says: “To solve 3x + 5 = 23 I divide by 3 first.” Show that her method needs fractions, and explain why subtracting 5 first is easier.
13
PSOmar has already read 18 pages of a 90-page book. He wants to finish it in 6 more days, reading the same number of pages each day. How many pages must he read each day?
14
FSolve x4 − 2 = 3. Show each step and check your answer.
15
FSolve 2x + 1 = 9.
9.3

Negative and fractional solutions, and checking

Edexcel 1MA1: A17
Grade 3-5

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Negative and fractional solutions, and checkingComing soon

The answer to an equation does not have to be a positive whole number. It can be negative, a fraction or a decimal. That is not a sign that you have made a mistake. Look at 2x + 9 = 3.

Subtract 9 from both sides: 2x = 3 − 9 = −6. Now divide both sides by 2: x = −6 ÷ 2 = −3. Remember from Chapter 1 that a negative number divided by a positive number gives a negative answer, and that 3 − 9 goes below zero.

-6-5-4-3-2-101234
The solution x = −3 of 2x + 9 = 3 is a negative number: it lies to the left of zero.

When the number you divide by does not go into the other number exactly, the answer is a fraction. If 3x = 7 then x = 73. You can leave it as an improper fraction, or write it as a mixed number: 73 = 213. If the question asks for a decimal and the fraction is exact, such as 52 = 2.5, give the decimal. Never round a fraction like 73 unless the question tells you to; it is exact, and 2.33 is not.

Sometimes the x term is negative, as in 3 − 2x = 11. Subtract 3 from both sides: −2x = 8. Now −2x means −2 × x, so divide both sides by −2: x = 8 ÷ (−2) = −4. A positive divided by a negative is negative.

Checking by substitution. You can always test an answer. Put it back into the original equation, in place of the letter, and work out the left side and the right side separately. If they are equal the answer is correct. This is especially helpful when the answer is negative or a fraction, because those are easy places to slip. Use brackets around a negative number when you substitute: 2 × (−3) + 9 = −6 + 9 = 3, which equals the right-hand side. So x = −3 works.

Key ideas

  • A solution can be negative, a fraction or a decimal.
  • Keep the sign with the number. Positive ÷ negative = negative, negative ÷ negative = positive.
  • Leave a fraction exact (in simplest form, or as a mixed number); do not round unless asked.
  • To check: substitute the answer into the original equation and show that both sides are equal. Use brackets for negative values.
Worked example 9.3.1
Solve 2x + 9 = 3.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    2x + 9 = 3
  2. Subtract 9 from both sides. This undoes the +9, because +9 − 9 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x + 9 − 9 = 3 − 9
    2x = −6
  3. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = −62
    x = −62 = −3
  4. Write the solution. x is now on its own, so the equation tells us its value.
    x = −3

Check. Substitute x = −3 into the original equation. Left side: 2 × (−3) + 9 = −6 + 9 = 3. Right side: 3. Both sides equal 3, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.3.2
Solve 4x = 10. Give your answer as a mixed number.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    4x = 10
  2. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    4x4 = 104
    x = 104 = 52
  3. Write the solution. x is now on its own, so the equation tells us its value.
    x = 52
  4. Write the answer as a mixed number. The question asks for a mixed number. Divide the top by the bottom: the whole number is how many times it goes in, the remainder is the numerator of the fraction.
    5 ÷ 2 = 2 remainder 1
    x = 212

Check. Substitute x = 52 into the original equation. Left side: 4 × 52 = 10. Right side: 10. Both sides equal 10, so the solution is correct. ✓

Watch out. Whatever you do to one side of the equation you must do to the other side. Use the opposite operation: the opposite of + is −, and the opposite of × is ÷.

Worked example 9.3.3
Solve 3 − 2x = 11.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    3 − 2x = 11
  2. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: write the x term first (adding can be done in any order).
    The equation is now −2x + 3 = 11
  3. Subtract 3 from both sides. This undoes the +3, because +3 − 3 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    −2x + 3 − 3 = 11 − 3
    −2x = 8
  4. Divide both sides by −2. −2x means −2 multiplied by x. The inverse of multiplying by −2 is dividing by −2, and we do it to both sides to keep the balance. This leaves x on its own. Careful with signs: a positive divided by a negative gives a negative answer, and a negative divided by a negative gives a positive.
    −2x−2 = 8−2
    x = 8−2 = −4
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = −4

Check. Substitute x = −4 into the original equation. Left side: 3 − 2 × (−4) = 3 + 8 = 11. Right side: 11. Both sides equal 11, so the solution is correct. ✓

Watch out. Dividing by a negative number changes the sign: a positive divided by a negative gives a negative. Check your answer by substitution.

Worked example 9.3.4
Is x = −2 a solution of 5x + 7 = 2x + 1? Show your working.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Substitute the value into both sides of the equation, work each side out, and compare.

  1. Write the equation and the value to test. A number is a solution of an equation if it makes both sides equal. We test it by substituting it (putting it in place of the letter).
    5x + 7 = 2x + 1,   x = −2
  2. Substitute into the left-hand side. Replace every x with the number. Use brackets around a negative number so that the signs stay clear.
    Left side = 5 × (−2) + 7 = −10 + 7 = −3
  3. Substitute into the right-hand side. Do exactly the same to the other side of the equation.
    Right side = 2 × (−2) + 1 = −4 + 1 = −3
  4. Compare the two sides. If the two sides are equal the number is a solution; if not, it is not.
    −3 = −3, so yes, x = −2 is a solution.

Check. The two sides match, which is exactly what we wanted to see. ✓

Watch out. Work out the left side and the right side separately. Do not use an = sign between the two until you have shown they are equal.

Watch out

When you substitute a negative number, put it in brackets. 5 × (−2) = −10. Without brackets, writing 5 −2 looks like a subtraction and the sign gets lost. Also, do not drop the minus sign when you divide: −6 ÷ 2 = −3, not 3.

Exercise 9C  Negative and fractional solutions

Non-calculator
1
FSolve these equations. Each solution is a negative number.
(a)x + 9 = 4
(b)x + 12 = 3
(c)2x + 10 = 4
(d)3x + 14 = 5
(e)x − 3 = −7
(f)4x − 1 = −13
2
FSolve these equations. Give each answer as a fraction in its simplest form.
(a)2x = 5
(b)3x = 4
(c)4x = 6
(d)5x = 2
(e)6x = 9
(f)2x + 1 = 6
3
FSolve these equations. Give each answer as a mixed number.
(a)3x = 7
(b)4x + 1 = 10
(c)5x − 2 = 14
(d)2x + 3 = 12
4
FSolve these equations. Give each answer as a decimal.
(a)2x + 1 = 6
(b)4x = 1
(c)5x + 2 = 3
(d)8x − 3 = 1
5
FSolve these equations. The x term is negative.
(a)5 − x = 2
(b)10 − 2x = 4
(c)3 − 2x = 11
(d)7 − 3x = −8
(e)1 − x = 6
(f)12 − 5x = 2
6
FDecide whether each statement is true or false by substituting the value for x. The value to test is x = −2.
(a)3x + 8 = 2
(b)2x − 1 = 3
(c)5x + 4 = −6
(d)x2 + 4 = 3
7
FSolve 6x + 7 = −17
8
FSolve 9 = 4x + 21
9
PSA number is multiplied by 3 and then 11 is added. The answer is 2. Find the number.
10
PSAt 6 pm the temperature is 5°C. It falls by 3°C every hour. After how many hours is the temperature −7°C?
11
PSFive identical books cost £12 altogether. Work out the cost of one book.
12
RDev solves x + 7 = 2 and writes x = 9. Substitute his answer to show that it is wrong, then find the correct answer.
13
RWithout solving the equation, explain why 4x + 8 = 3 cannot have a positive solution. Then solve it.
14
PSFour child tickets for a theme park cost £30 altogether. Work out the cost of one child ticket. Give your answer to the nearest penny.
15
FSolve these. Give each answer as a whole number.
(a)x − 9 = −4
(b)2x = −8
(c)x + 6 = 1
(d)3x = −15
9.4

The unknown on both sides

Edexcel 1MA1: A17
Grade 4-5

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: The unknown on both sidesComing soon

Often the letter appears on both sides of the equals sign, such as 3x + 2 = x + 8. Now we cannot get x on its own just by undoing one side. First we must collect all the x terms on one side.

Think of the scales again. The left pan has three boxes and two circles, the right pan has one box and eight circles. Take one box off both pans and the scales still balance.

xxxx3x + 2 = x + 8xx2x + 2 = 8xx2x = 6
Take 1 box off both pans, then take 2 circles off both pans. Two boxes balance 6 circles, so one box is 3.

Here is the method.

  1. Choose the smaller x term (the one with the smaller number in front of x) and remove it from both sides. Subtracting the smaller one means the x terms that are left are positive.
  2. Move the plain numbers to the other side: add or subtract the number that is on the same side as the x term, on both sides.
  3. Divide both sides by the number in front of x.

For 3x + 2 = x + 8, the smaller x term is x (that is 1x). Subtract x from both sides to get 2x + 2 = 8. Then subtract 2 to get 2x = 6, and divide by 2 to get x = 3.

What if the bigger x term is on the right? In 3x + 10 = 7x − 6, the smaller x term is 3x on the left. Subtract 3x from both sides: 10 = 4x − 6. Add 6: 16 = 4x. Divide by 4: 4 = x, which means x = 4. You could remove the bigger x term instead, but then you get a negative number of x and mistakes with signs become more likely. Both ways give the same answer.

Key ideas

  • Remove the smaller x term from both sides, so the x terms combine on one side.
  • Then move the plain numbers to the other side, and divide.
  • When you subtract a term from both sides, subtract it from every part of both sides, and watch the signs.
  • Check by substituting into both sides of the original equation.
Worked example 9.4.1
Solve 5x + 3 = 2x + 12.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    5x + 3 = 2x + 12
  2. Remove the x term from the right side: subtract 2x from both sides. We want all the x terms on one side. The right side has 2x; subtracting 2x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    5x + 3 − 2x = 2x + 12 − 2x
    3x + 3 = 12
  3. Subtract 3 from both sides. This undoes the +3, because +3 − 3 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    3x + 3 − 3 = 12 − 3
    3x = 9
  4. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    3x3 = 93
    x = 93 = 3
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 3

Check. Substitute x = 3 into the original equation. Left side: 5 × 3 + 3 = 15 + 3 = 18. Right side: 2 × 3 + 12 = 6 + 12 = 18. Both sides equal 18, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Worked example 9.4.2
Solve 7x − 4 = 3x + 20.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    7x − 4 = 3x + 20
  2. Remove the x term from the right side: subtract 3x from both sides. We want all the x terms on one side. The right side has 3x; subtracting 3x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    7x − 4 − 3x = 3x + 20 − 3x
    4x − 4 = 20
  3. Add 4 to both sides. This undoes the −4, because −4 + 4 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    4x − 4 + 4 = 20 + 4
    4x = 24
  4. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    4x4 = 244
    x = 244 = 6
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 6

Check. Substitute x = 6 into the original equation. Left side: 7 × 6 − 4 = 42 − 4 = 38. Right side: 3 × 6 + 20 = 18 + 20 = 38. Both sides equal 38, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Worked example 9.4.3
Solve 3x + 10 = 7x − 6.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    3x + 10 = 7x − 6
  2. Remove the x term from the left side: subtract 3x from both sides. We want all the x terms on one side. The left side has 3x; subtracting 3x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    3x + 10 − 3x = 7x − 6 − 3x
    10 = 4x − 6
  3. Add 6 to both sides. This undoes the −6, because −6 + 6 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    10 + 6 = 4x − 6 + 6
    16 = 4x
  4. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    164 = 4x4
    x = 164 = 4
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 4

Check. Substitute x = 4 into the original equation. Left side: 3 × 4 + 10 = 12 + 10 = 22. Right side: 7 × 4 − 6 = 28 − 6 = 22. Both sides equal 22, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Worked example 9.4.4
Solve 2x + 9 = 5x + 15.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    2x + 9 = 5x + 15
  2. Remove the x term from the left side: subtract 2x from both sides. We want all the x terms on one side. The left side has 2x; subtracting 2x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    2x + 9 − 2x = 5x + 15 − 2x
    9 = 3x + 15
  3. Subtract 15 from both sides. This undoes the +15, because +15 − 15 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    9 − 15 = 3x + 15 − 15
    −6 = 3x
  4. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    −63 = 3x3
    x = −63 = −2
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = −2

Check. Substitute x = −2 into the original equation. Left side: 2 × (−2) + 9 = −4 + 9 = 5. Right side: 5 × (−2) + 15 = −10 + 15 = 5. Both sides equal 5, so the solution is correct. ✓

Watch out. Do the same to both sides. Take away the smaller x term from both sides so the x term stays positive. Check the sign of each term as you move it.

Watch out

Take the x term away from both sides, and think about the sign. In 5x − 3 = 2x + 9, subtracting 2x from both sides gives 3x − 3 = 9. If you add 2x to the left (a common mistake) you get 7x, which is wrong.

Exercise 9D  The unknown on both sides

Non-calculator
1
FSolve these equations. There are no plain numbers to move.
(a)5x = 3x + 8
(b)4x = x + 12
(c)7x = 4x + 15
(d)6x = 2x + 20
(e)9x = 5x + 28
(f)8x = 3x + 35
2
FSolve these equations.
(a)3x + 5 = x + 11
(b)5x + 2 = 2x + 14
(c)4x + 1 = x + 16
(d)6x + 3 = 4x + 11
(e)7x + 4 = 3x + 20
(f)8x + 1 = 5x + 19
3
FSolve these equations. Each has a subtraction.
(a)5x − 3 = 2x + 9
(b)6x − 4 = 3x + 14
(c)4x − 7 = x + 8
(d)7x − 1 = 5x + 13
(e)9x − 8 = 4x + 27
(f)8x − 5 = 3x + 20
4
FSolve these equations. The bigger x term is on the right-hand side.
(a)x + 12 = 3x + 4
(b)2x + 9 = 5x
(c)3x + 8 = 5x − 4
(d)4x + 3 = 7x − 18
(e)2x + 15 = 6x − 13
(f)3x + 7 = 8x − 23
5
FSolve these equations. Each solution is a negative number.
(a)2x + 9 = 5x + 15
(b)3x + 14 = 7x + 22
(c)5x + 4 = 8x + 13
(d)2x − 3 = 4x + 7
(e)x + 1 = 4x + 10
(f)6x + 5 = 9x + 20
6
PSTaxi firm A charges £3 plus £2 per mile. Taxi firm B charges £1 plus £3 per mile. For how many miles do the two firms charge the same amount?
7
PSSam thinks of a number. He multiplies it by 5 and subtracts 6. If he had multiplied it by 3 and added 10 instead, he would have got the same answer. What is Sam's number?
8
RLily solves 6x + 5 = 2x + 17. Her first line is 8x + 5 = 17. Explain her mistake and solve the equation correctly.
9
RShow that x = 5 is the solution of 7x − 9 = 3x + 11.
10
PSAli has £5 and saves £4 each week. Ben has £21 and saves £2 each week. After how many weeks will they have the same amount?
11
RTo solve 3x + 8 = 7x − 4, Amy subtracts 7x from both sides and gets −4x + 8 = −4. Ben subtracts 3x from both sides and gets 8 = 4x − 4. Show that they both get the same value of x.
12
FSolve these equations.
(a)2x + 4 = x + 9
(b)3x = x + 10
(c)4x + 2 = 2x + 12
9.5

Equations with brackets

Edexcel 1MA1: A17
Grade 4-6

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Equations with bracketsComing soon

A bracket means “multiply everything inside by the number outside”. In 3(x + 4) the 3 multiplies both the x and the 4. You met expanding in Chapter 7. A picture helps: the rectangle below has height 3 and width (x + 4), so its area is 3(x + 4). Cut it into two rectangles and the area is 3 × x + 3 × 4 = 3x + 12.

3x12x433(x + 4) = 3x + 12
The bracket multiplies every term inside it: 3(x + 4) = 3x + 12.

To solve an equation with brackets, expand the brackets first, collect like terms if there are any, and then solve as before.

A shortcut when the bracket stands alone. If the whole of one side is a bracket and the other side is a number, such as 3(x + 4) = 27, you can divide both sides by 3 first: x + 4 = 9, so x = 5. This works because 3 is multiplying the entire bracket. Expanding first also works: 3x + 12 = 27, 3x = 15, x = 5. Use whichever you find easier; expanding always works.

Negative numbers and minus signs. A minus sign in front of a bracket multiplies everything inside by −1, so it changes the sign of every term inside. 10 − (x + 2) = 10 − x − 2 = 8 − x. Likewise −2(x − 3) = −2x + 6, because (−2) × (−3) = +6.

When there are brackets on both sides, expand both, then collect the x terms as in the last section.

Key ideas

  • Expand first: multiply every term inside the bracket by the number outside.
  • A minus sign in front of a bracket changes the sign of every term inside it.
  • Collect like terms, then solve (unknown on both sides: remove the smaller x term).
  • Shortcut: if one side is just a bracket and the other is a number, you may divide both sides by the number in front of the bracket first.
Worked example 9.5.1
Solve 3(x + 4) = 27.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    3(x + 4) = 27
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 3(x + 4):
    3 × x = 3x
    3 × 4 = 12

    The equation is now 3x + 12 = 27
  3. Subtract 12 from both sides. This undoes the +12, because +12 − 12 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    3x + 12 − 12 = 27 − 12
    3x = 15
  4. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    3x3 = 153
    x = 153 = 5
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 5

Check. Substitute x = 5 into the original equation. Left side: 3 × (5 + 4) = 3 × 9 = 27. Right side: 27. Both sides equal 27, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Worked example 9.5.2
Solve 2(3x − 5) = 14.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    2(3x − 5) = 14
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 2(3x − 5):
    2 × 3x = 6x
    2 × (−5) = −10

    The equation is now 6x − 10 = 14
  3. Add 10 to both sides. This undoes the −10, because −10 + 10 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    6x − 10 + 10 = 14 + 10
    6x = 24
  4. Divide both sides by 6. 6x means 6 multiplied by x. The inverse of multiplying by 6 is dividing by 6, and we do it to both sides to keep the balance. This leaves x on its own.
    6x6 = 246
    x = 246 = 4
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 4

Check. Substitute x = 4 into the original equation. Left side: 2 × (3 × 4 − 5) = 2 × 7 = 14. Right side: 14. Both sides equal 14, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Worked example 9.5.3
Solve 5(x − 2) = 3(x + 4).

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    5(x − 2) = 3(x + 4)
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 5(x − 2):
    5 × x = 5x
    5 × (−2) = −10

    Expand 3(x + 4):
    3 × x = 3x
    3 × 4 = 12

    The equation is now 5x − 10 = 3x + 12
  3. Remove the x term from the right side: subtract 3x from both sides. We want all the x terms on one side. The right side has 3x; subtracting 3x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    5x − 10 − 3x = 3x + 12 − 3x
    2x − 10 = 12
  4. Add 10 to both sides. This undoes the −10, because −10 + 10 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x − 10 + 10 = 12 + 10
    2x = 22
  5. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = 222
    x = 222 = 11
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 11

Check. Substitute x = 11 into the original equation. Left side: 5 × (11 − 2) = 5 × 9 = 45. Right side: 3 × (11 + 4) = 3 × 15 = 45. Both sides equal 45, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Worked example 9.5.4
Solve 7 − 2(x − 1) = 3.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    7 − 2(x − 1) = 3
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it. A negative number multiplied by a negative number gives a positive answer, and a negative multiplied by a positive gives a negative.
    Expand −2(x − 1):
    (−2) × x = −2x
    (−2) × (−1) = 2

    The equation is now 7 − 2x + 2 = 3
  3. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the numbers 7 + 2 make 9.
    The equation is now −2x + 9 = 3
  4. Subtract 9 from both sides. This undoes the +9, because +9 − 9 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    −2x + 9 − 9 = 3 − 9
    −2x = −6
  5. Divide both sides by −2. −2x means −2 multiplied by x. The inverse of multiplying by −2 is dividing by −2, and we do it to both sides to keep the balance. This leaves x on its own. Careful with signs: a positive divided by a negative gives a negative answer, and a negative divided by a negative gives a positive.
    −2x−2 = −6−2
    x = −6−2 = 3
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 3

Check. Substitute x = 3 into the original equation. Left side: 7 − 2 × (3 − 1) = 7 − 2 × 2 = 7 − 4 = 3. Right side: 3. Both sides equal 3, so the solution is correct. ✓

Watch out. Multiply every term inside the bracket by the number outside, not just the first one. Take care with a minus sign in front of a bracket: it changes the sign of every term inside.

Watch out

Multiply every term in the bracket. 3(x + 4) is 3x + 12, not 3x + 4. And with a negative in front, change both signs: −2(x − 3) = −2x + 6, not −2x − 6.

Exercise 9E  Equations with brackets

Non-calculator
1
FSolve these equations. Each bracket has a plus sign.
(a)2(x + 3) = 14
(b)3(x + 1) = 18
(c)5(x + 2) = 35
(d)4(x + 5) = 36
(e)6(x + 1) = 30
(f)2(x + 9) = 30
2
FSolve these equations. Each bracket has a minus sign.
(a)3(x − 2) = 15
(b)2(x − 4) = 10
(c)5(x − 1) = 20
(d)4(x − 3) = 8
(e)3(2x + 1) = 21
(f)2(3x − 4) = 22
3
FSolve these equations. Expand the bracket first.
(a)3(x + 2) + 4 = 19
(b)2(x + 5) − 3 = 19
(c)4(x − 1) + 7 = 23
(d)5(x + 2) − 8 = 27
(e)2(2x + 1) + 5 = 19
(f)3(x − 4) + 2 = 8
4
FSolve these equations. There is a bracket on one side and x on the other.
(a)3(x + 2) = 2x + 9
(b)4(x − 1) = 2x + 8
(c)2(x + 5) = x + 14
(d)5(x − 3) = 3x + 1
(e)3(2x + 1) = 4x + 11
(f)2(3x − 2) = 5x + 3
5
FSolve these equations. There are brackets on both sides.
(a)5(x − 2) = 3(x + 4)
(b)2(x + 7) = 4(x + 1)
(c)4(x − 1) = 3(x + 2)
(d)4(x + 3) = 3(x + 6)
(e)6(x − 2) = 2(x + 8)
(f)5(2x − 1) = 3(3x + 1)
6
FSolve these equations. Be careful with the minus signs in front of the brackets.
(a)10 − (x + 2) = 5
(b)7 − 2(x − 1) = 3
(c)20 − 3(x + 1) = 2
(d)5 − (x − 3) = 1
(e)12 − 2(x + 3) = 4
(f)9 − 3(x − 2) = 6
7
RJo expands 3(x − 4) and gets 3x − 4. Explain her mistake. Then solve 3(x − 4) = 15.
8
PSI think of a number, add 4 and then multiply the result by 3. My answer is 33. What number did I think of?
9
PSAt a museum, a child ticket costs £3 less than an adult ticket. Two adult tickets and three child tickets cost £41 altogether. Work out the cost of an adult ticket.
10
RShow that x = 4 is the solution of 2(3x − 5) = 5x − 6.
11
PSThe area of this rectangle is 36 cm2. Work out the value of x.
(x + 5) cm3 cm
12
FSolve these equations.
(a)2(x + 3) = 10
(b)3(x − 1) = 12
(c)4(x + 2) = 20
9.6

Equations with fractions

Edexcel 1MA1: A17
Grade 4-7

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Equations with fractionsComing soon

In Chapter 3 you added and subtracted fractions by changing them to the same bottom number (the common denominator). We use the same idea to solve equations that contain fractions, but we use it to remove the fractions altogether.

Consider x + 32 = 5. The whole of the top, x + 3, is divided by 2. To undo “divide by 2” we multiply both sides by 2: x + 3 = 10, so x = 7. On the left, 2 × x + 32 = x + 3, because the 2 on the top and the 2 on the bottom cancel. Note that the top is a bracket in disguise: the fraction bar acts like a bracket around x + 3.

When there is more than one fraction, for example x2 + x3 = 10, find the lowest common multiple (LCM) of the bottom numbers. Here the LCM of 2 and 3 is 6. Multiply every term on both sides by 6:

6 × x2 = 3x    6 × x3 = 2x    6 × 10 = 60, so 3x + 2x = 60, which gives 5x = 60 and x = 12.

Why does this work? Multiplying both sides of an equation by the same number keeps it balanced. If we choose a number that every bottom divides into, each fraction turns into a whole expression. It is exactly like the way you made equivalent fractions in Chapter 3, only now the aim is to get rid of the bottoms.

The most common slips are (1) forgetting to multiply a term that is not a fraction, such as the 10 above, and (2) forgetting that a numerator with two terms needs a bracket when you multiply: 6 × x + 12 = 3(x + 1), not 3x + 1.

Key ideas

  • To solve an equation with fractions, multiply every term on both sides by the lowest common multiple of the bottom numbers.
  • This removes the fractions: after you multiply, the bottoms cancel.
  • If a numerator has two terms, use a bracket after multiplying, then expand it.
  • Multiply every term, including whole numbers. Then solve the ordinary equation that is left, and check in the original equation.
Worked example 9.6.1
Solve x + 32 = 5.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A common denominator is a bottom number that all the fractions can be changed to; multiplying every term by it removes the fractions.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x + 32 = 5
  2. Find the common denominator. To get rid of fractions we multiply by a number that every bottom divides into exactly: the lowest common multiple of the bottoms.
    2  →  the lowest common multiple is 2
  3. Multiply every term, on both sides, by 2. Doing the same to both sides keeps the equation balanced. Every term must be multiplied, including plain numbers. This removes the fractions.
    2 × x + 32 = (x + 3)   (2 goes into 2 exactly 1 time, so the bottom disappears)
    2 × 5 = 10
    The new equation is (x + 3) = 10
  4. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    (x + 3) has nothing in front of it except +1, so the brackets can simply be removed: x + 3

    The equation is now x + 3 = 10
  5. Subtract 3 from both sides. This undoes the +3, because +3 − 3 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    x + 3 − 3 = 10 − 3
    x = 7
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 7

Check. Substitute x = 7 into the original equation. Left side: 7 + 32 = 102 = 5. Right side: 5. Both sides equal 5, so the solution is correct. ✓

Watch out. Multiply every term by the common denominator, including the terms that are not fractions. Then check that no fraction is left.

Worked example 9.6.2
Solve 2x − 13 = 5.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A common denominator is a bottom number that all the fractions can be changed to; multiplying every term by it removes the fractions.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    2x − 13 = 5
  2. Find the common denominator. To get rid of fractions we multiply by a number that every bottom divides into exactly: the lowest common multiple of the bottoms.
    3  →  the lowest common multiple is 3
  3. Multiply every term, on both sides, by 3. Doing the same to both sides keeps the equation balanced. Every term must be multiplied, including plain numbers. This removes the fractions.
    3 × 2x − 13 = (2x − 1)   (3 goes into 3 exactly 1 time, so the bottom disappears)
    3 × 5 = 15
    The new equation is (2x − 1) = 15
  4. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    (2x − 1) has nothing in front of it except +1, so the brackets can simply be removed: 2x − 1

    The equation is now 2x − 1 = 15
  5. Add 1 to both sides. This undoes the −1, because −1 + 1 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x − 1 + 1 = 15 + 1
    2x = 16
  6. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = 162
    x = 162 = 8
  7. Write the solution. x is now on its own, so the equation tells us its value.
    x = 8

Check. Substitute x = 8 into the original equation. Left side: 2 × 8 − 13 = 153 = 5. Right side: 5. Both sides equal 5, so the solution is correct. ✓

Watch out. Multiply every term by the common denominator, including the terms that are not fractions. Then check that no fraction is left.

Worked example 9.6.3
Solve x2 + x3 = 10.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A common denominator is a bottom number that all the fractions can be changed to; multiplying every term by it removes the fractions.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x2 + x3 = 10
  2. Find the common denominator. To get rid of fractions we multiply by a number that every bottom divides into exactly: the lowest common multiple of the bottoms.
    2, 3  →  the lowest common multiple is 6
  3. Multiply every term, on both sides, by 6. Doing the same to both sides keeps the equation balanced. Every term must be multiplied, including plain numbers. This removes the fractions.
    6 × x2 = 3x   (2 goes into 6 exactly 3 times, so the bottom disappears)
    6 × x3 = 2x   (3 goes into 6 exactly 2 times, so the bottom disappears)
    6 × 10 = 60
    The new equation is 3x + 2x = 60
  4. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the x terms 3x + 2x make 5x.
    The equation is now 5x = 60
  5. Divide both sides by 5. 5x means 5 multiplied by x. The inverse of multiplying by 5 is dividing by 5, and we do it to both sides to keep the balance. This leaves x on its own.
    5x5 = 605
    x = 605 = 12
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 12

Check. Substitute x = 12 into the original equation. Left side: 122 + 123 = 6 + 4 = 10. Right side: 10. Both sides equal 10, so the solution is correct. ✓

Watch out. Multiply every term by the common denominator, including the terms that are not fractions. Then check that no fraction is left.

Worked example 9.6.4
Solve x3 + 2 = x2.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A common denominator is a bottom number that all the fractions can be changed to; multiplying every term by it removes the fractions.

Method. Solve the equation by using inverse operations (the opposite operation) on both sides, so that the equation stays balanced, until the letter x is on its own.

  1. Write down the equation. The two sides of an equation are equal, like the two sides of a balanced pair of scales. We want the value of x that keeps them balanced.
    x3 + 2 = x2
  2. Find the common denominator. To get rid of fractions we multiply by a number that every bottom divides into exactly: the lowest common multiple of the bottoms.
    3, 2  →  the lowest common multiple is 6
  3. Multiply every term, on both sides, by 6. Doing the same to both sides keeps the equation balanced. Every term must be multiplied, including plain numbers. This removes the fractions.
    6 × x3 = 2x   (3 goes into 6 exactly 2 times, so the bottom disappears)
    6 × 2 = 12
    6 × x2 = 3x   (2 goes into 6 exactly 3 times, so the bottom disappears)
    The new equation is 2x + 12 = 3x
  4. Remove the x term from the left side: subtract 2x from both sides. We want all the x terms on one side. The left side has 2x; subtracting 2x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    2x + 12 − 2x = 3x − 2x
    12 = x
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 12

Check. Substitute x = 12 into the original equation. Left side: 123 + 2 = 4 + 2 = 6. Right side: 122 = 6. Both sides equal 6, so the solution is correct. ✓

Watch out. Multiply every term by the common denominator, including the terms that are not fractions. Then check that no fraction is left.

Watch out

Multiply every term. In x2 + 3 = 7, multiplying by 2 gives x + 6 = 14, not x + 3 = 14. And when the top has two terms, treat it like a bracket: 6 × x + 12 = 3(x + 1).

Exercise 9F  Equations with fractions

Non-calculator
1
FSolve these equations. Multiply both sides by the bottom number.
(a)x + 32 = 5
(b)x + 13 = 4
(c)x − 25 = 2
(d)x + 74 = 3
(e)x − 42 = 6
(f)x + 56 = 2
2
FSolve these equations. The top has two terms.
(a)2x + 13 = 5
(b)3x − 24 = 4
(c)5x + 32 = 14
(d)4x − 13 = 5
(e)2x + 57 = 3
(f)3x + 15 = 2
3
FSolve these equations. Find the lowest common multiple of the bottoms first.
(a)x2 + x3 = 10
(b)x3 + x4 = 7
(c)x2 − x5 = 6
(d)x4 + x2 = 9
(e)x3 + 2 = x2
(f)x5 + 3 = x2
4
FSolve these equations.
(a)x4 + 3 = 8
(b)x3 − 5 = 1
(c)x6 + 2 = 7
(d)x2 − 3 = 4
5
PSHalf of a number, plus 3, makes 11. Find the number.
6
PSAna has read a third of her book and 10 more pages. She has read 40 pages altogether. How many pages are in the book?
7
RKai solves x2 + 3 = 7. His first line is x + 3 = 14. Explain his mistake and find the correct solution.
8
PSThree numbers are x, x + 4 and x + 8. Their mean is 12. Find the three numbers.
9
FSolve these equations.
(a)x2 = 4
(b)x3 + 1 = 4
(c)x + 12 = 3
10
RShow that x = 6 is the solution of x2 + x3 = 5.
9.7

Forming equations from words

Edexcel 1MA1: A17, A21
Grade 3-6

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Forming equations from wordsComing soon

Equations are most useful when a real problem is turned into one. A good method has five steps:

  1. Read the question and decide what you need to find.
  2. Choose a letter for the unknown and say what it stands for, with units. (“Let x be the cost of one ticket in pounds.”)
  3. Write an equation using the information. The two sides must have the same value.
  4. Solve the equation.
  5. Answer in words, with units, and check that your answer fits the story.

The hard step is turning words into algebra. Learn these phrases. Notice that the order matters for “less than” and “minus”.

In wordsIn algebra
a number plus 5, 5 more than a numberx + 5
5 less than a number, a number minus 5x − 5
5 minus a number5 − x
5 times a number, double a number (2 times)5x, 2x
a number divided by 4, a quarter of a numberx4
3 more than twice a number2x + 3
twice the sum of a number and 32(x + 3)

Ages. If Ali is x years old and his sister is 5 years older, she is x + 5. In 8 years’ time they will be x + 8 and x + 13. “Three times as old” means 3x.

Costs. If one ticket costs £x, then 4 tickets cost 4x pounds. A fixed charge such as a booking fee is added once, but a charge per item or per hour is multiplied by the number of items or hours.

Finally, check your answer in the words of the question, not just in your equation. If your equation was wrong, an answer that satisfies the equation can still be wrong for the story.

Key ideas

  • Always begin with “Let x = …” and give the units.
  • The two sides of the equation must be equal in value: use words like “is”, “gives”, “total” or “the same as” to find the = sign.
  • “5 less than x” is x − 5 (not 5 − x).
  • After solving, answer the question that was asked (with units) and check it against the story.
Worked example 9.7.1
I think of a number. I multiply it by 4 and then subtract 7. The answer is 29. What is my number?

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Turn the words into an equation, solve it using inverse operations, then use the answer to respond to the question that was asked.

  1. Choose a letter for the unknown. We do not know the number yet, so we give it a letter. Say clearly what the letter stands for, including the units.
    Let x = the number I think of.
  2. Use the words to write an equation. Translate the sentence into maths, a bit at a time. The two sides of the equation must be equal in value.
    I multiply the number by 4 (4x) and subtract 7 (4x − 7). The result is 29.
    Equation: 4x − 7 = 29
  3. Add 7 to both sides. This undoes the −7, because −7 + 7 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    4x − 7 + 7 = 29 + 7
    4x = 36
  4. Divide both sides by 4. 4x means 4 multiplied by x. The inverse of multiplying by 4 is dividing by 4, and we do it to both sides to keep the balance. This leaves x on its own.
    4x4 = 364
    x = 364 = 9
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 9
  6. Answer the question that was asked. The solution of the equation is the value of the letter. Read the question again to see exactly what it wants, and put the units back.
    The number is 9.

Check. 4 × 9 = 36, and 36 − 7 = 29 ✓

Watch out. Always give the answer to the question that was asked, with units. The value of x is not always the final answer.

Worked example 9.7.2
A plumber charges a call-out fee of £35 plus £25 for each hour of work. The bill is £110. For how many hours did the plumber work?

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Turn the words into an equation, solve it using inverse operations, then use the answer to respond to the question that was asked.

  1. Choose a letter for the unknown. We do not know the number yet, so we give it a letter. Say clearly what the letter stands for, including the units.
    Let x = the number of hours the plumber works.
  2. Use the words to write an equation. Translate the sentence into maths, a bit at a time. The two sides of the equation must be equal in value.
    The call-out fee of £35 is charged once. The hourly charge is £25 for each hour, which is 25x. The bill is 35 + 25x = 110.
    Equation: 25x + 35 = 110
  3. Subtract 35 from both sides. This undoes the +35, because +35 − 35 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    25x + 35 − 35 = 110 − 35
    25x = 75
  4. Divide both sides by 25. 25x means 25 multiplied by x. The inverse of multiplying by 25 is dividing by 25, and we do it to both sides to keep the balance. This leaves x on its own.
    25x25 = 7525
    x = 7525 = 3
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 3
  6. Answer the question that was asked. The solution of the equation is the value of the letter. Read the question again to see exactly what it wants, and put the units back.
    The plumber worked for 3 hours.

Check. 25 × 3 = 75, and 75 + 35 = 110 ✓

Watch out. Always give the answer to the question that was asked, with units. The value of x is not always the final answer.

Worked example 9.7.3
Ali's sister is 5 years older than Ali. The sum of their ages is 31. How old is Ali?

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Turn the words into an equation, solve it using inverse operations, then use the answer to respond to the question that was asked.

  1. Choose a letter for the unknown. We do not know the number yet, so we give it a letter. Say clearly what the letter stands for, including the units.
    Let x = Ali's age in years.
  2. Use the words to write an equation. Translate the sentence into maths, a bit at a time. The two sides of the equation must be equal in value.
    His sister is 5 years older, so she is x + 5. Their ages add up to 31.
    Equation: x + (x + 5) = 31
  3. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    (x + 5) has nothing in front of it except +1, so the brackets can simply be removed: x + 5

    The equation is now x + x + 5 = 31
  4. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the x terms x + x make 2x.
    The equation is now 2x + 5 = 31
  5. Subtract 5 from both sides. This undoes the +5, because +5 − 5 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x + 5 − 5 = 31 − 5
    2x = 26
  6. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = 262
    x = 262 = 13
  7. Write the solution. x is now on its own, so the equation tells us its value.
    x = 13
  8. Answer the question that was asked. The solution of the equation is the value of the letter. Read the question again to see exactly what it wants, and put the units back.
    Ali is 13 years old, and his sister is 18.

Check. 13 + 18 = 31, and 18 is 5 more than 13 ✓

Watch out. Always give the answer to the question that was asked, with units. The value of x is not always the final answer.

Worked example 9.7.4
Jo thinks of a number, adds 6 and then doubles the result. She gets 30. What number did Jo think of?

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Turn the words into an equation, solve it using inverse operations, then use the answer to respond to the question that was asked.

  1. Choose a letter for the unknown. We do not know the number yet, so we give it a letter. Say clearly what the letter stands for, including the units.
    Let x = the number Jo thinks of.
  2. Use the words to write an equation. Translate the sentence into maths, a bit at a time. The two sides of the equation must be equal in value.
    Jo adds 6 to her number: x + 6. She then doubles the whole result, so the bracket is multiplied by 2: 2(x + 6). The answer is 30.
    Equation: 2(x + 6) = 30
  3. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 2(x + 6):
    2 × x = 2x
    2 × 6 = 12

    The equation is now 2x + 12 = 30
  4. Subtract 12 from both sides. This undoes the +12, because +12 − 12 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x + 12 − 12 = 30 − 12
    2x = 18
  5. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = 182
    x = 182 = 9
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 9
  7. Answer the question that was asked. The solution of the equation is the value of the letter. Read the question again to see exactly what it wants, and put the units back.
    Jo's number is 9.

Check. 9 + 6 = 15, and 2 × 15 = 30 ✓

Watch out. Always give the answer to the question that was asked, with units. The value of x is not always the final answer.

Watch out

“5 less than x” is x − 5. It is not 5 − x. For example, 5 less than 20 is 15 = 20 − 5. Also read what the question asks: after you find x, you may still need to use it (for example to find the sister’s age, not Ali’s).

Exercise 9G  Forming and solving equations from words

Non-calculator
1
FWrite each phrase as an algebraic expression. Use x for the number.
(a)a number plus 5
(b)3 less than a number
(c)twice a number
(d)a number divided by 4
(e)3 more than twice a number
(f)twice the sum of a number and 3
2
FWrite an equation for each sentence, solve it, and write down the number.
(a)Max thinks of a number. He adds 7 and gets 15.
(b)Mia thinks of a number. She subtracts 6 and gets 11.
(c)Half of a number, plus 3, equals 11.
(d)5 less than 3 times a number is 22.
3
PSA plumber charges a call-out fee of £35 plus £25 for each hour of work. Sandeep's bill is £135. For how many hours did the plumber work?
4
PSBen is 4 years older than Cara. The total of their ages is 30. How old is Cara?
5
PSA pen costs £x. Three pens and a ruler costing £2 cost £11 altogether. Work out the cost of one pen.
6
PSA phone plan costs 1200 pence a month plus 5 pence for every minute of calls. One month the bill is 1500 pence. How many minutes of calls were made?
7
PSZara is three times as old as her brother. The sum of their ages is 36. How old is Zara?
8
PSSam buys 4 identical notebooks and a pen costing £3. He pays with £20 and gets £5 change. How much does one notebook cost?
9
PSThree consecutive whole numbers add up to 51. Work out the smallest of the numbers.
10
PSGym A charges £20 to join and then £10 each month. Gym B charges £50 to join and then £5 each month. After how many months will the total cost for the two gyms be the same?
11
RHana says: “5 less than a number is 17, so the equation is 5 − x = 17.” Explain what is wrong, then solve the correct equation.
12
FKim thinks of a number, adds 7 and gets 15. What is her number?
13
FA box holds 6 identical pencils and costs £3. How much is one pencil, in pence?
9.8

Equations from geometry: perimeters and angles

Edexcel 1MA1: A17, A21
Grade 4-6

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Equations from geometry: perimeters and anglesComing soon

Diagrams often give lengths or angles as expressions with x in them. To find x we need a fact that tells us what the lengths or angles add up to. This gives us an equation. Here are the facts we will use (you meet them again in Chapters 17 and 18):

The method is: (1) say which fact you are using, (2) write an equation, (3) solve it, (4) put x back into the expressions on the diagram to find the length or angle that the question asks for, and (5) check, for example by adding the angles to see that they total 180°.

Diagrams in this book are drawn to scale, but in an exam a diagram may say “not drawn accurately”. Do not measure: use the facts.

(3x + 2) cm(x + 4) cm
A rectangle with sides (3x + 2) cm and (x + 4) cm. The perimeter is 2 × (3x + 2) + 2 × (x + 4).

Key ideas

  • Perimeter = the sum of all the sides. For a rectangle: 2 × length + 2 × width.
  • Angles in a triangle: 180°. On a straight line: 180°. At a point: 360°. In a quadrilateral: 360°.
  • Use equal sides or equal angles (isosceles, square, rhombus) to write an equation without a total.
  • After finding x, find what the question asks for, and check it.
Worked example 9.8.1
The rectangle in the diagram has a perimeter of 36 cm. Work out the value of x and the length of each side.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Use a fact from geometry to write an equation, solve it by doing the same to both sides, then use the value of x to answer the question.

  1. Use the perimeter. The perimeter is the total length around the rectangle. A rectangle has two sides of each length.
    Perimeter = 2(3x + 2) + 2(x + 4) = 36
    Equation: 2(3x + 2) + 2(x + 4) = 36
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    Expand 2(3x + 2):
    2 × 3x = 6x
    2 × 2 = 4

    Expand 2(x + 4):
    2 × x = 2x
    2 × 4 = 8

    The equation is now 6x + 4 + 2x + 8 = 36
  3. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the x terms 6x + 2x make 8x and the numbers 4 + 8 make 12.
    The equation is now 8x + 12 = 36
  4. Subtract 12 from both sides. This undoes the +12, because +12 − 12 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    8x + 12 − 12 = 36 − 12
    8x = 24
  5. Divide both sides by 8. 8x means 8 multiplied by x. The inverse of multiplying by 8 is dividing by 8, and we do it to both sides to keep the balance. This leaves x on its own.
    8x8 = 248
    x = 248 = 3
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 3
  7. Answer the question that was asked. The value of x is usually only a stepping stone: read the question again to see what is wanted (a length, an angle, a perimeter) and put the units back.
    x = 3. The sides are 3 × 3 + 2 = 11 cm and 3 + 4 = 7 cm.

Check. Perimeter = 2 × 11 + 2 × 7 = 36 cm ✓

Watch out. Do not stop at the value of x. Put it back into the expressions on the diagram to find the angle or length that the question asks for.

BCA(x + 20)°2x°(3x − 20)°
A triangle with angles (x + 20)°, 2x° and (3x − 20)°.
Worked example 9.8.2
Find the angles of the triangle in the diagram.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Use a fact from geometry to write an equation, solve it by doing the same to both sides, then use the value of x to answer the question.

  1. Use the angles in a triangle. The three angles of a triangle add up to 180°.
    (x + 20) + 2x + (3x − 20) = 180
    Equation: (x + 20) + 2x + (3x − 20) = 180
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    (x + 20) has nothing in front of it except +1, so the brackets can simply be removed: x + 20

    (3x − 20) has nothing in front of it except +1, so the brackets can simply be removed: 3x − 20

    The equation is now x + 20 + 2x + 3x − 20 = 180
  3. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the x terms x + 2x + 3x make 6x and the numbers 20 − 20 make 0.
    The equation is now 6x = 180
  4. Divide both sides by 6. 6x means 6 multiplied by x. The inverse of multiplying by 6 is dividing by 6, and we do it to both sides to keep the balance. This leaves x on its own.
    6x6 = 1806
    x = 1806 = 30
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 30
  6. Answer the question that was asked. The value of x is usually only a stepping stone: read the question again to see what is wanted (a length, an angle, a perimeter) and put the units back.
    x = 30. The angles are 50°, 60° and 70°.

Check. 50 + 60 + 70 = 180 ✓

Watch out. Do not stop at the value of x. Put it back into the expressions on the diagram to find the angle or length that the question asks for.

(2x + 10)°(x + 35)°
Two angles on a straight line.
Worked example 9.8.3
Two angles on a straight line are (2x + 10)° and (x + 35)°. Work out both angles.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Use a fact from geometry to write an equation, solve it by doing the same to both sides, then use the value of x to answer the question.

  1. Use angles on a straight line. The angles on a straight line add up to 180°.
    (2x + 10) + (x + 35) = 180
    Equation: (2x + 10) + (x + 35) = 180
  2. Expand the brackets. Multiply each term inside the bracket by the number outside it.
    (2x + 10) has nothing in front of it except +1, so the brackets can simply be removed: 2x + 10

    (x + 35) has nothing in front of it except +1, so the brackets can simply be removed: x + 35

    The equation is now 2x + 10 + x + 35 = 180
  3. Collect like terms on each side. Like terms are terms with the same letter part: all the x terms go together, and all the plain numbers go together. Doing this makes each side as short as possible.
    On the left side: the x terms 2x + x make 3x and the numbers 10 + 35 make 45.
    The equation is now 3x + 45 = 180
  4. Subtract 45 from both sides. This undoes the +45, because +45 − 45 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    3x + 45 − 45 = 180 − 45
    3x = 135
  5. Divide both sides by 3. 3x means 3 multiplied by x. The inverse of multiplying by 3 is dividing by 3, and we do it to both sides to keep the balance. This leaves x on its own.
    3x3 = 1353
    x = 1353 = 45
  6. Write the solution. x is now on its own, so the equation tells us its value.
    x = 45
  7. Answer the question that was asked. The value of x is usually only a stepping stone: read the question again to see what is wanted (a length, an angle, a perimeter) and put the units back.
    x = 45. The angles are 100° and 80°.

Check. 100 + 80 = 180 ✓

Watch out. Do not stop at the value of x. Put it back into the expressions on the diagram to find the angle or length that the question asks for.

BCA(3x + 1) cm(x + 9) cm8 cm
Triangle ABC is isosceles: the two ticked sides are equal.
Worked example 9.8.4
Triangle ABC is isosceles with AB = AC. Work out the value of x and the perimeter of the triangle.

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side. A bracket such as 3(x + 2) means 3 multiplied by everything inside. Expanding the bracket means multiplying each term inside by the number outside.

Method. Use a fact from geometry to write an equation, solve it by doing the same to both sides, then use the value of x to answer the question.

  1. Use the equal sides. In an isosceles triangle two sides are equal. The ticks show that AB = AC.
    AB = AC, so 3x + 1 = x + 9
    Equation: 3x + 1 = x + 9
  2. Remove the x term from the right side: subtract x from both sides. We want all the x terms on one side. The right side has x; subtracting x removes it. We take away the smaller x term, so that the x term that is left is positive and easier to work with. We must do it to both sides to keep the balance.
    3x + 1 − x = x + 9 − x
    2x + 1 = 9
  3. Subtract 1 from both sides. This undoes the +1, because +1 − 1 = 0, which leaves the x term on its own. We do it to both sides to keep the balance.
    2x + 1 − 1 = 9 − 1
    2x = 8
  4. Divide both sides by 2. 2x means 2 multiplied by x. The inverse of multiplying by 2 is dividing by 2, and we do it to both sides to keep the balance. This leaves x on its own.
    2x2 = 82
    x = 82 = 4
  5. Write the solution. x is now on its own, so the equation tells us its value.
    x = 4
  6. Answer the question that was asked. The value of x is usually only a stepping stone: read the question again to see what is wanted (a length, an angle, a perimeter) and put the units back.
    x = 4. AB = AC = 13 cm and BC = 8 cm, so the perimeter is 13 + 13 + 8 = 34 cm.

Check. AB = 3 × 4 + 1 = 13 and AC = 4 + 9 = 13. They are equal ✓

Watch out. Do not stop at the value of x. Put it back into the expressions on the diagram to find the angle or length that the question asks for.

Watch out

Finding x is often not the end. If the question asks for an angle, a length or a perimeter, substitute x back in. And check: three angles of a triangle must add to 180°, so if yours do not, you have made a mistake.

Exercise 9H  Equations from perimeters and angles

Non-calculator
1
FThe perimeter of the rectangle is 32 cm. Work out the value of x.
(2x + 1) cm(x + 3) cm
2
FA square has sides of length (4x − 3) cm. The perimeter of the square is 52 cm. Work out the value of x, and the length of one side.
3
FThe perimeter of the triangle is 31 cm. Find the length of the longest side.
BCA(x + 5) cm2x cm(2x + 1) cm
4
FWork out the value of x, and the size of the largest angle in the triangle.
BCA(x + 10)°2x°(3x + 20)°
5
FThe angles are on a straight line. Work out the value of x.
(3x + 10)°(2x + 20)°
6
FThree angles meet at a point. Work out the value of x, and the size of the smallest angle.
2x°(3x + 10)°(x + 50)°
7
FThe four angles of the quadrilateral add up to 360°. Work out the value of x.
x°(x + 30)°(2x + 10)°(2x + 20)°
8
PSTriangle ABC is isosceles. Work out the value of x, and the size of each base angle.
BCA50°(2x + 5)°(2x + 5)°
9
PSTriangle ABC is isosceles with AB = AC. Work out the perimeter of the triangle.
BCA(2x + 5) cm(4x − 3) cm10 cm
10
PSThe shape is a rhombus. Work out the perimeter of the rhombus.
(3x − 1) cm(x + 9) cm
11
RZane says that the triangle with angles x°, 2x° and 3x° must have a right angle. Is he correct? You must show your working.
12
PSThe angles of a triangle are (2x − 10)°, (x + 30)° and (3x − 20)°. Find the size of the largest angle.
13
FWork out the value of x.
(x + 40)°(2x + 20)°
14
FA rectangle has width 4 cm and length x cm. The perimeter is 20 cm. Work out the length.
x cm4 cm
9.9

Solving equations using graphs, and interpreting solutions

Edexcel 1MA1: A17, A21
Grade 4-6

Printable: Worksheet (PDF) · Answers (PDF) · Open this lesson on its own page

Video lesson: Solving equations using graphs, and interpreting solutionsComing soon

Equations can also be solved with a picture. The straight line y = 2x + 1 shows, for every value of x, the value of 2x + 1 (you will study these lines in Chapter 12). Suppose we want to solve 2x + 1 = 9. That means: for which x does the height of the line equal 9?

Draw a horizontal line at y = 9. It meets the sloping line at one point. Go straight down to the x-axis from that point and read the value: x = 4. This is the solution.

xy-1123456-224681012
The line y = 2x + 1 meets y = 9 at x = 4, so 2x + 1 = 9 has the solution x = 4.

A graph gives approximate answers, because we read a scale by eye. Algebra gives exact answers. But graphs are useful when an equation is hard to solve by hand, and they help you see why an equation has the solution it does.

Two sloping lines. To solve an equation with x on both sides, such as 3x − 2 = x + 4, draw a line for each side: y = 3x − 2 and y = x + 4. The solution is the x-coordinate of the point where the two lines cross, because that is the one place where both sides have the same value.

xy-1123456-4-2246810y = 3x − 2y = x + 4
The lines cross at (3, 7), so the solution of 3x − 2 = x + 4 is x = 3.

Does the answer make sense? A solution of an equation is a number, but in a story the number must also fit the situation. You cannot buy 8.3 tickets, or be −4 years old, or have a rectangle with a negative length. After solving a problem from words, always ask: “Is this a sensible answer for the question?” If not, either you have made a mistake, or the situation is impossible, and you should say so.

Key ideas

  • To solve f(x) = number from a graph: go across from the number on the y-axis to the line, then down to the x-axis.
  • For an equation with x on both sides, plot a line for each side. The x-coordinate of the crossing point is the solution.
  • Graph answers are approximate; algebra gives exact answers.
  • Always check that a solution makes sense in the context (whole number? positive?).
Worked example 9.9.1
The graph shows y = 2x + 1. Use the graph to solve 2x + 1 = 9.

Method. Use the graph: a horizontal line at the value on the right-hand side meets the sloping line where the equation is true.

  1. Rewrite the question as a graph question. On the graph of y = 2x + 1, the height of the line is the value of the left-hand side of the equation. We want the point where that height equals 9.
    2x + 1 = 9   means   y = 9
  2. Find 9 on the y-axis and draw a horizontal line across. Every point on this horizontal line has y = 9.
    Start at y = 9 and go across until you touch the sloping line.
  3. Go straight down to the x-axis. The x-value of the point where the two lines cross is the solution.
    Reading the scale gives x = 4.

Check. Check by substituting: 2 × 4 + 1 = 9. ✓

Watch out. Read the x value (across), not the y value (up). Check the scale on both axes before you read the value.

Worked example 9.9.2
Use the graph above to solve 3x − 2 = x + 4.

Method. Draw (or read) the graph of each side of the equation. The x-coordinate of the point where the lines cross is the solution.

  1. Think of each side of the equation as a straight line. The left-hand side is the line y = 3x − 2 and the right-hand side is the line y = x + 4. The equation is true where the two lines have the same height.
    y = 3x − 2   and   y = x + 4
  2. Find where the two lines cross. At the crossing point both lines have the same x and the same y, so that x makes the equation true.
    The lines cross at (3, 7).
  3. Read off the x-coordinate. The question asks for x, so we use the first number of the point.
    x = 3

Check. Left side: 3 × 3 − 2 = 7. Right side: 1 × 3 + 4 = 7. Equal. ✓

Watch out. The answer is the x-coordinate only, not the whole point.

Worked example 9.9.3
Tickets cost £6 each. Ben says he spent exactly £50 on tickets. Could he be right?

Key words. An equation says that two things are equal, for example 3x + 5 = 20. To solve it means to find the value of the letter that makes it true. The inverse operation is the operation that undoes another: adding and subtracting undo each other, and multiplying and dividing undo each other. An equation is like a pair of balanced scales: whatever you do to one side you must do to the other side.

Method. Turn the words into an equation, solve it using inverse operations, then use the answer to respond to the question that was asked.

  1. Choose a letter for the unknown. We do not know the number yet, so we give it a letter. Say clearly what the letter stands for, including the units.
    Let x = the number of tickets Ben bought.
  2. Use the words to write an equation. Translate the sentence into maths, a bit at a time. The two sides of the equation must be equal in value.
    Each ticket costs £6, so x tickets cost 6x pounds. Ben spent £50.
    Equation: 6x = 50
  3. Divide both sides by 6. 6x means 6 multiplied by x. The inverse of multiplying by 6 is dividing by 6, and we do it to both sides to keep the balance. This leaves x on its own.
    6x6 = 506
    x = 506 = 253
  4. Write the solution. x is now on its own, so the equation tells us its value.
    x = 253
  5. Answer the question that was asked. The solution of the equation is the value of the letter. Read the question again to see exactly what it wants, and put the units back.
    x = 253 = 8.333… This is not a whole number, and Ben can only buy a whole number of tickets. So Ben cannot have spent exactly £50 on tickets. (He could buy 8 tickets for £48.)

Check. Substitute x = 253 into the original equation. Left side: 6 × 253 = 50. Right side: 50. Both sides equal 50, so the solution is correct. ✓

Watch out. Always give the answer to the question that was asked, with units. The value of x is not always the final answer.

Watch out

The solution is the x-value (how far across), not the y-value (how far up). When you draw the line y = 9, the 9 is the number on the y-axis that you start from. The answer you read from the x-axis is 4.

Exercise 9I  Graphs and interpreting solutions

Non-calculator
1
FThis is the graph of y = 2x + 1. Use the graph to solve each equation. For (f) give your answer to 1 decimal place.
xy-1123456-224681012
(a)2x + 1 = 7
(b)2x + 1 = 11
(c)2x + 1 = 3
(d)2x + 1 = 5
(e)2x + 1 = 9
(f)2x + 1 = 8
2
FThis is the graph of y = 3x − 2. Use the graph to solve each equation.
xy-112345-4-224681012
(a)3x − 2 = 7
(b)3x − 2 = 10
(c)3x − 2 = 1
(d)3x − 2 = −2
(e)3x − 2 = 4
(f)3x − 2 = −5
3
FThe graphs of y = 3x − 2 and y = x + 4 are drawn. Use the graph to solve 3x − 2 = x + 4.
xy-1123456-4-2246810y = 3x − 2y = x + 4
4
FThe graphs of y = 2x + 1 and y = 10 − x are drawn. Use the graph to solve 2x + 1 = 10 − x.
xy-1123456-11234567891011y = 2x + 1y = 10 − x
5
FUse the graph to solve 2x − 1 = x + 3, then check your answer using algebra.
xy-1123456-2246810y = 2x − 1y = x + 3
6
RAva uses the graph of y = 2x + 1 to solve 2x + 1 = 9. She says the answer is x = 9 because the horizontal line goes through 9. Explain her mistake and give the correct solution.
xy-1123456-224681012
7
RTickets for a play cost £6 each. Ben says he spent exactly £50 on tickets. Could he be right? Explain.
8
RDee thinks of a whole number, multiplies it by 4 and adds 3. She gets 20. Could she be telling the truth? Explain.
9
PSAn internet plan costs £15 a month plus £4 for every extra gigabyte. A bill is £51. How many extra gigabytes were used? Is your answer sensible?
10
RRavi says that the number of cups of flour x in a recipe satisfies 3x + 8 = 2. Solve the equation. Explain why the answer cannot be right for the recipe.
11
FUse the graph of y = 2x + 1 (drawn for −1 ≤ x ≤ 6) to estimate the solution of 2x + 1 = 8.
xy-1123456-224681012
12
FSolve 2x + 1 = 7 using algebra, and check that it agrees with the point where y = 7 meets the line y = 2x + 1 in the graph.
xy-1123456-224681012

Chapter summary

SkillMethod
Equation vs expressionAn equation has an = sign and can be solved; an expression cannot
One-step equationsDo the opposite operation to both sides: + and − undo each other, × and ÷ undo each other
Two-step equationsUndo + or − first, then × or ÷. Always do the same to both sides
Negative and fractional answersKeep the sign when dividing. Leave exact fractions (or write mixed numbers); do not round unless asked
Unknown on both sidesSubtract the smaller x term from both sides, then move the plain numbers, then divide
BracketsExpand first (multiply every term inside); a minus before a bracket changes every sign inside
Equations with fractionsMultiply every term by the LCM of the denominators; use a bracket when the top has two terms
Equations from wordsLet x = … (with units); write the equation; solve; answer the question in words; check
Geometry equationsUse perimeter, angle sum 180° (triangle, straight line), 360° (point, quadrilateral), or equal sides/angles
GraphsSolution is the x-value where the graph meets the line, or where two lines cross
CheckingSubstitute into the original equation: both sides must be equal
Higher: special casesx in the denominator: multiply by the bottom (reject a value that makes it 0). A false statement (6 = 5) means no solution; a true one (6 = 6) means every x works

Can you…?

  • I can tell an equation from an expression, and explain the balance idea.
  • I can solve one-step and two-step equations by doing the same to both sides.
  • I can solve equations with negative or fractional solutions and give the answer in a sensible form.
  • I can solve equations with the unknown on both sides.
  • I can expand brackets and solve equations that contain them.
  • I can solve equations that contain fractions (Higher: algebraic fractions and unknowns in denominators).
  • I can turn a worded problem into an equation, solve it, and answer in context.
  • I can use perimeter and angle facts to form and solve equations.
  • I can use a graph to solve an equation approximately, and decide whether a solution makes sense.
  • I can check a solution by substitution.

Key terms

Equation
A statement that two expressions are equal, such as 3x + 5 = 20. It contains an equals sign.
Expression
A collection of numbers and letters with no equals sign, such as 3x + 5.
Unknown
A letter standing for a number we want to find.
Solve
Find the value of the unknown that makes the equation true.
Solution
The value of the unknown that makes an equation true.
Inverse operation
The operation that undoes another: + and − are inverses; × and ÷ are inverses.
Substitute
Replace a letter by a number.
Like terms
Terms with the same letter part, such as 3x and 5x.
Expand
Remove a bracket by multiplying every term inside by the number outside.
Common denominator
A bottom number that several fractions can all be changed to.
Perimeter
The total distance around the edge of a shape.
Identity (Higher)
An equation that is true for every value of the unknown, such as 3(x + 2) = 3x + 6.

Exercise 9Z  Check-up (non-calculator)

Non-calculator
1
Solve x + 9 = 20
2
Solve 4x = 36
3
Solve 3x + 7 = 25
4
Solve 5x − 8 = 12
5
Solve 2x + 9 = 3
6
Solve 7x − 5 = 3x + 11
7
Solve 4(x − 3) = 20
8
Solve x + 53 = 4
9
Tom thinks of a number. He multiplies it by 3 and then subtracts 4. The answer is 17. Find Tom's number.
10
The angles are on a straight line. Work out the value of x.
(4x + 20)°(2x + 40)°

Total 35 marks. Allow about 35 minutes.

Exercise 9X  Exam-style questions

Non-calculator
1
FSolve 5x + 3 = 38[2 marks]
2
FSolve x4 + 3 = 8[2 marks]
3
FSolve 7x − 3 = 3x + 17[3 marks]
4
FSolve 3(2x − 1) = 21[3 marks]
5
FSolve 5(x − 2) = 3(x + 4)[3 marks]
6
FThree angles on a straight line are (5x + 10)°, (3x + 30)° and 2x°. Work out the value of x. You must show your working.[3 marks]
(5x + 10)°(3x + 30)°2x°
7
PSThe rectangle has a perimeter of 46 cm. (a) Work out the value of x. (b) Work out the area of the rectangle.[4 marks]
(3x + 1) cm(2x − 3) cm
8
PSSia buys 4 identical T-shirts. Delivery costs £3 and is added once. The total is £35. Work out the cost of one T-shirt.[3 marks]
9
PSAmy is 3 years older than Ben. Cal is twice as old as Ben. The total of their ages is 39. Work out the age of each person.[4 marks]
10
RShow that x = 4 is the solution of 5x − 7 = 3x + 1.[2 marks]
11
PSPhone deal A costs 1000 pence a month plus 4 pence per minute of calls. Phone deal B costs 400 pence a month plus 10 pence per minute. For how many minutes of calls do the two deals cost the same?[4 marks]
12
RChen says that x = 3 is the solution of 2x + 5 = 4x − 1. Is Chen correct? You must show your working.[2 marks]

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