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GCSE Maths · EdexcelChapter 21 · Transformations, congruence and similarity
GCSE Maths · Transformations and Similarity · Higher · Lesson 21.1

GCSE Maths: Reflection (Higher)

Part of the GCSE Maths transformations and similarity chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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21.1

Reflection

Edexcel 1MA1: G7
Grade 1-5

A transformation changes a shape in some way. The shape we start with is called the object and the new shape is called the image. In this chapter you will meet four transformations: reflection, rotation, translation and enlargement. The first three only move the shape, so the image is exactly the same size and shape as the object. These shapes are called congruent. Enlargement changes the size, so the image is similar to the object but not congruent.

A reflection gives a mirror image. Imagine standing a mirror on the mirror line and looking at the shape in it. Each point of the image is the same distance from the mirror line as the matching point of the object, but on the opposite side. The line joining a point to its image crosses the mirror line at a right angle. That is why the mirror line is exactly half-way between a point and its image.

xy-112345678-112345x = 4AB
Shape B is the reflection of shape A in the line x = 4. Each dashed line is crossed in its middle by the mirror line.

On a coordinate grid the mirror line is usually one of four kinds of line:

For a vertical or horizontal mirror line, count the squares from each vertex to the line, then count the same number of squares on the other side. For the diagonals there is a shortcut, shown in the picture: a reflection in y = x swaps the coordinates, (a, b) → (b, a), and a reflection in y = −x swaps them and changes both signs, (a, b) → (−b, −a). The axes themselves are easy as well: reflecting in the x-axis changes the sign of y, and reflecting in the y-axis changes the sign of x.

xy-7-6-5-4-3-2-11234567-5-4-3-2-112345y = xy = −xP (3, 1)in x-axis (3, −1)in y-axis (−3, 1)in y = x (1, 3)in y = −x (−1, −3)
The point P(3, 1) and its four reflections.

Describing a reflection. To describe a reflection fully you must say that it is a reflection and give the equation of the mirror line. To find the line, look at a point and its image: the line is exactly half-way between them. If you have tracing paper, you can also trace the object, flip the tracing paper over and slide it until it lands on the image, then draw along the fold.

Key ideas

  • A reflection flips a shape over a mirror line. The image is the same size and shape (congruent) but a mirror image.
  • Each point and its image are the same distance from the mirror line, on opposite sides.
  • Vertical line x = a: the y-coordinate stays the same. Horizontal line y = b: the x-coordinate stays the same.
  • In y = x: (a, b) → (b, a). In y = −x: (a, b) → (−b, −a).
  • To describe a reflection, give the equation of the mirror line.
  • A point on the mirror line is invariant: it does not move.
Worked example 21.1.1
Reflect shape A in the line x = 5. Write down the coordinates of the vertices of the image B. A has vertices at (1, 1), (4, 1), (1, 3).
xy-1123456-11234x = 5A

Key words. A reflection flips a shape over a mirror line. The object and its image are the same distance from the mirror line, on opposite sides.

Method. To reflect a shape, reflect every vertex over the mirror line x = 5, then join the image points in the same order.

  1. Draw the mirror line. The line x = 5 is a vertical line: every point on it has x = 5. Everything in the picture will flip over this line.
    Draw a vertical line through x = 5.
  2. Reflect each vertex of A in turn. For a reflection in a vertical line x = 5, the y-coordinate stays the same. Count how far each point is from the line (sideways), then go the same distance on the other side.
    (1, 1): 4 left of the line, so the image is 4 right of the line. x = 5 + 4 = 9. Image (9, 1)
    (4, 1): 1 left of the line, so the image is 1 right of the line. x = 5 + 1 = 6. Image (6, 1)
    (1, 3): 4 left of the line, so the image is 4 right of the line. x = 5 + 4 = 9. Image (9, 3)
  3. Plot the image points and join them up in the same order to make shape B. The image has the same size and shape as the object but is the other way round, like a mirror image.
    B has vertices at (9, 1), (6, 1), (9, 3).
    xy-112345678910-11234x = 5AB

Check. The mirror line should be exactly half-way between a point and its image. The midpoint of (1, 1) and (9, 1) is (1 + 9) ÷ 2, (1 + 1) ÷ 2 = (5, 1), which lies on the line x = 5. ✓

Watch out. Measure the distance from the mirror line, not from the y-axis. The line is x = 5, so distances start from there.

Worked example 21.1.2
Reflect shape A in the line y = −1. Write down the coordinates of the vertices of the image B. A has vertices at (1, 2), (3, 2), (3, 3), (2, 3), (2, 5), (1, 5).
xy-11234-2-1123456y = −1A

Key words. A reflection flips a shape over a mirror line. The object and its image are the same distance from the mirror line, on opposite sides.

Method. To reflect a shape, reflect every vertex over the mirror line y = −1, then join the image points in the same order.

  1. Draw the mirror line. The line y = −1 is a horizontal line: every point on it has y = −1. Everything in the picture will flip over this line.
    Draw a horizontal line through y = −1.
  2. Reflect each vertex of A in turn. For a reflection in a horizontal line y = −1, the x-coordinate stays the same. Count how far each point is from the line (up or down), then go the same distance on the other side.
    (1, 2): 3 above the line, so the image is 3 below the line. y = −1 − 3 = −4. Image (1, −4)
    (3, 2): 3 above the line, so the image is 3 below the line. y = −1 − 3 = −4. Image (3, −4)
    (3, 3): 4 above the line, so the image is 4 below the line. y = −1 − 4 = −5. Image (3, −5)
    (2, 3): 4 above the line, so the image is 4 below the line. y = −1 − 4 = −5. Image (2, −5)
    (2, 5): 6 above the line, so the image is 6 below the line. y = −1 − 6 = −7. Image (2, −7)
    (1, 5): 6 above the line, so the image is 6 below the line. y = −1 − 6 = −7. Image (1, −7)
  3. Plot the image points and join them up in the same order to make shape B. The image has the same size and shape as the object but is the other way round, like a mirror image.
    B has vertices at (1, −4), (3, −4), (3, −5), (2, −5), (2, −7), (1, −7).
    xy-11234-8-7-6-5-4-3-2-1123456y = −1AB

Check. The mirror line should be exactly half-way between a point and its image. The midpoint of (1, 2) and (1, −4) is (1 + 1) ÷ 2, (2 + −4) ÷ 2 = (1, −1), which lies on the line y = −1. ✓

Watch out. Measure the distance from the mirror line, not from the x-axis. The line is y = −1, so distances start from there.

Worked example 21.1.3
Reflect shape A in the line y = x. Write down the coordinates of the vertices of the image B. A has vertices at (3, 1), (5, 1), (6, 3), (3, 2).
xy-11234567-11234y = xA

Key words. A reflection flips a shape over a mirror line. The object and its image are the same distance from the mirror line, on opposite sides.

Method. To reflect a shape, reflect every vertex over the mirror line y = x, then join the image points in the same order.

  1. Draw the mirror line. The line y = x is a diagonal line. Every point on it has the same x and y coordinates (for example (0, 0), (1, 1), (2, 2), (3, 3)).
    Draw a straight line through (0, 0), (1, 1), (2, 2) and (3, 3).
  2. Reflect each vertex of A in turn. A mirror along y = x swaps the two coordinates: the point (a, b) becomes (b, a). This works because the diagonal is the line where the x and y coordinates are equal.
    (3, 1) → (1, 3)
    (5, 1) → (1, 5)
    (6, 3) → (3, 6)
    (3, 2) → (2, 3)
  3. Plot the image points and join them up in the same order to make shape B. The image has the same size and shape as the object but is the other way round, like a mirror image.
    B has vertices at (1, 3), (1, 5), (3, 6), (2, 3).
    xy-11234567-11234567y = xAB

Check. The mirror line should be exactly half-way between a point and its image. The midpoint of (3, 1) and (1, 3) is (3 + 1) ÷ 2, (1 + 3) ÷ 2 = (2, 2), which lies on the line y = x. ✓

Watch out. Reflecting in y = x swaps the coordinates; it does not change any signs. (Changing signs is for y = −x.)

Worked example 21.1.4
Reflect shape A in the line y = −x. Write down the coordinates of the vertices of the image B. A has vertices at (−4, 1), (−1, 2), (−3, 4).
xy-5-4-3-2-11-112345y = −xA

Key words. A reflection flips a shape over a mirror line. The object and its image are the same distance from the mirror line, on opposite sides.

Method. To reflect a shape, reflect every vertex over the mirror line y = −x, then join the image points in the same order.

  1. Draw the mirror line. The line y = −x is a diagonal line sloping down to the right. Every point on it has y equal to the opposite of x (for example (−2, 2), (−1, 1), (0, 0), (1, −1), (2, −2)).
    Draw a straight line through (−2, 2), (0, 0) and (2, −2).
  2. Reflect each vertex of A in turn. A mirror along y = −x swaps the coordinates and changes both signs: the point (a, b) becomes (−b, −a). For example (2, 1) goes to (−1, −2).
    (−4, 1) → (−1, 4)
    (−1, 2) → (−2, 1)
    (−3, 4) → (−4, 3)
  3. Plot the image points and join them up in the same order to make shape B. The image has the same size and shape as the object but is the other way round, like a mirror image.
    B has vertices at (−1, 4), (−2, 1), (−4, 3).
    xy-5-4-3-2-11-112345y = −xAB

Check. The mirror line should be exactly half-way between a point and its image. The midpoint of (−4, 1) and (−1, 4) is (−4 + −1) ÷ 2, (1 + 4) ÷ 2 = (−2.5, 2.5), which lies on the line y = −x. ✓

Watch out. Reflecting in y = −x swaps the coordinates and changes both signs. Swapping alone gives a reflection in y = x.

Worked example 21.1.5
Describe fully the single transformation that maps shape A onto shape B.
xy-1123456789101112-11234AB

Key words. A reflection flips a shape over a mirror line. The object and its image are the same distance from the mirror line, on opposite sides.

Method. Decide which type of transformation maps A onto B, then find the extra details each type needs (a line, a centre, an angle, a vector or a scale factor).

  1. Decide which type of transformation it is. A reflection flips the shape over. All other transformations of this type keep the shape facing the same way.
    Compare a side: it is 3 long in A and 3 long in B.
    The size is unchanged, but B is the mirror image of A: if you go round the corners in the same order, one shape is clockwise and the other is anticlockwise. So the transformation is a reflection.
  2. Pick vertices and their images, and find the midpoints. A mirror line is exactly half-way between an object point and its image, so find the midpoint of a point and its image.
    (1, 1) and (11, 1): midpoint = ((1 + 11) ÷ 2, (1 + 1) ÷ 2) = (6, 1)
    (4, 1) and (8, 1): midpoint = ((4 + 8) ÷ 2, (1 + 1) ÷ 2) = (6, 1)
  3. Write the equation of the mirror line. The midpoints all have x = 6. The points are in a vertical line, so the mirror line is the vertical line x = 6.
    Mirror line: x = 6
  4. Write the full description. We have found every piece of information needed for this transformation.
    Reflection in the line x = 6
    xy-1123456789101112-11234x = 6AB

Check. Reflect (4, 1) in x = 6 and we get (8, 1), which matches (8, 1) in B. ✓

Watch out. A reflection needs the equation of the mirror line. Writing just “reflection” or “reflect in the x-axis” for a line like x = 3 is wrong.

Worked example 21.1.6
Describe fully the single transformation that maps shape A onto shape B.
xy-1123456-1123456AB

Key words. A reflection flips a shape over a mirror line. The object and its image are the same distance from the mirror line, on opposite sides.

Method. Decide which type of transformation maps A onto B, then find the extra details each type needs (a line, a centre, an angle, a vector or a scale factor).

  1. Decide which type of transformation it is. A reflection flips the shape over. All other transformations of this type keep the shape facing the same way.
    Compare the areas: 4 square units for A and 4 for B.
    The size is unchanged, but B is the mirror image of A: if you go round the corners in the same order, one shape is clockwise and the other is anticlockwise. So the transformation is a reflection.
  2. Compare the coordinates of a vertex and its image. For the diagonal mirror lines y = x and y = −x the coordinates change in a special way.
    The coordinates have been swapped: (2, 1) became (1, 2).
  3. Use the midpoint as a check. The mirror line must pass through the midpoint of a point and its image.
    Midpoint of (2, 1) and (1, 2) = (1.5, 1.5), which lies on y = x.
  4. Write the equation of the mirror line. A reflection that swaps x and y is a reflection in the line y = x.
    Mirror line: y = x
  5. Write the full description. We have found every piece of information needed for this transformation.
    Reflection in the line y = x
    xy-1123456-1123456y = xAB

Check. Reflect (5, 2) in y = x and we get (2, 5), which matches (2, 5) in B. ✓

Watch out. A reflection needs the equation of the mirror line. Writing just “reflection” or “reflect in the x-axis” for a line like x = 3 is wrong.

Watch out

Always measure from the mirror line, not from the axes (unless the axis is the mirror line). For a line like x = 4, a point at x = 1 is 3 squares from the line, so its image is at x = 4 + 3 = 7. Also, in y = −x do not forget to change both signs as well as swapping.

Exercise 21A  Reflection

Non-calculator
1
FShape A has vertices at (2, 2), (5, 2), (2, 4). Reflect A in each mirror line and write down the coordinates of the vertices of the image.
xy-7-6-5-4-3-2-1123456789101112-7-6-5-4-3-2-1123456789101112A
(a)the y-axis (the line x = 0)
(b)the x-axis (the line y = 0)
(c)the line x = 6
(d)the line y = 6
2
FReflect shape A in the line y = −2. Write down the coordinates of the vertices of the image B. A has vertices at (1, 2), (4, 2), (3, 4), (1, 4).
xy-112345-3-2-112345y = −2A
3
FReflect shape A in the line x = −1. Write down the coordinates of the vertices of the image B. A has vertices at (2, 1), (4, 1), (4, 2), (3, 2), (3, 4), (2, 4).
xy-2-112345-112345x = −1A
4
FReflect shape A in the line y = x. Write down the coordinates of the vertices of the image B. A has vertices at (2, 1), (5, 1), (2, 3).
xy-1123456-11234y = xA
5
FReflect shape A in the line y = −x. Write down the coordinates of the vertices of the image B. A has vertices at (2, 1), (4, 1), (5, 3), (2, 2).
xy-1123456-11234y = −xA
6
FWrite down the image of the point P(3, −2) when it is reflected in:
(a)the x-axis
(b)the y-axis
(c)the line y = x
(d)the line y = −x
7
PSTriangle A is drawn on the grid and is crossed by the mirror line x = 3. Reflect A in the line x = 3 and write down the coordinates of the image. A has vertices at (1, 1), (4, 2), (2, 4).
xy-112345-112345x = 3A
8
RPriya reflects triangle A, with vertices (2, 1), (5, 1), (2, 3), in the line y = x. She writes the image as (−1, −2), (−1, −5), (−3, −2). Explain her mistake and write down the correct image.
9
FDescribe fully the single transformation that maps shape A onto shape B.
xy-1123456789101112-11234AB
10
FDescribe fully the single transformation that maps shape A onto shape B.
xy-112345-7-6-5-4-3-2-112345AB
11
FDescribe fully the single transformation that maps shape A onto shape B.
xy-5-4-3-2-11234567-7-6-5-4-3-2-112345AB
12
PSThe point P(4, 5) is reflected in a vertical line. Its image is P′(10, 5). Work out the equation of the mirror line.
13
RShape A is reflected in the line x = 3 to give shape B. Shape B is then reflected in the line x = 3 to give shape C. Where is shape C? Explain.
14
RA shape has an area of 18 cm². It is reflected in a line to give an image. What is the area of the image? Give a reason.
15
FReflect shape A in the line y = x + 1. Write down the coordinates of the image B. A has vertices at (1, 2), (4, 2), (3, 4), (1, 4).
xy-112345-112345y = x + 1A
16
RShow that the reflection of the point (a, b) in the line y = −x is the point (−b, −a).

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