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GCSE Maths · EdexcelChapter 21 · Transformations, congruence and similarity
GCSE Maths · Transformations and Similarity · Higher · Lesson 21.8

GCSE Maths: Similar shapes and scale factors (Higher)

Part of the GCSE Maths transformations and similarity chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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21.8

Similar shapes and scale factors

Edexcel 1MA1: G7, G19, R12
Grade 3-8

Two shapes are similar if one is an enlargement of the other. They have exactly the same shape but can be different sizes (one might also be turned or flipped). For similar shapes:

Corresponding sides are the ones in the same position in both shapes. For example, the shortest side of one triangle matches the shortest side of the similar triangle. Remember the difference: congruent shapes are the same size and shape; similar shapes are the same shape but not necessarily the same size.

6 cm4 cm5 cmABC9 cm6 cm7.5 cmPQR
Triangle PQR is similar to triangle ABC with scale factor 1.5: 6 × 1.5 = 9, 4 × 1.5 = 6, 5 × 1.5 = 7.5. The angles are equal.

Finding a missing length. (1) Find a pair of corresponding sides that you know both lengths of. (2) Work out the scale factor: larger ÷ smaller. (3) Use it on the side you want: multiply if you are going from the small shape to the large shape, divide if you are going from the large shape to the small one.

Are two shapes similar? Check that all pairs of corresponding sides are in the same ratio. A rectangle 4 cm by 6 cm and a rectangle 6 cm by 9 cm are similar: 6 ÷ 4 = 1.5 and 9 ÷ 6 = 1.5. A 4 cm by 6 cm rectangle and a 6 cm by 8 cm rectangle are not similar, since 6 ÷ 4 = 1.5 but 8 ÷ 6 = 1.33…. (For triangles, equal angles are enough: you do not need to check the sides.)

Similar triangles from parallel lines. Parallel lines create similar triangles. If DE is parallel to BC in triangle ABC, then triangle ADE is similar to triangle ABC. The angle at A is shared, and the corresponding angles ADE and ABC are equal, and so are AED and ACB. Note that the matching side to AD is the whole of AB, not DB. Two triangles that meet at a point (a “bow-tie” shape) with a pair of parallel sides are also similar, because the alternate angles are equal and the vertically opposite angles are equal.

4 cm6 cm15 cm6 cmABCDE
DE is parallel to BC. Triangle ADE is similar to triangle ABC with scale factor AB ÷ AD = 10 ÷ 4 = 2.5.
57.5344.56ABCDX
AB is parallel to CD, so triangles XAB and XCD are similar with scale factor 1.5.

Proving two triangles are similar (Higher). Show that two angles are equal (the third then must be equal as well), and give a reason for each pair: parallel lines (corresponding or alternate angles), vertically opposite angles, a common angle, or angles in a triangle that add up to 180°. Then state: “the triangles are similar (equal angles)”.

Key ideas

  • Similar shapes: equal corresponding angles and corresponding sides in the same ratio. The ratio is the scale factor.
  • Scale factor = length on the larger shape ÷ matching length on the smaller shape.
  • Small to large: multiply by the scale factor. Large to small: divide.
  • Parallel lines make similar triangles; look for a common angle, alternate or corresponding angles, or vertically opposite angles.
  • Congruent = same size and shape. Similar = same shape, any size.
Worked example 21.8.1
The two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
6 cm5 cm9 cmx

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. Similar shapes have corresponding sides in the same ratio. Find the scale factor from a pair of matching sides we know, then use it on the side we want.

  1. Match the corresponding sides. In similar shapes the sides that are in the same position match. Their lengths are in the same ratio, and that ratio is the scale factor.
    Known pair: 6 cm (small shape) and 9 cm (large shape).
    The side we want is the one marked x.
  2. Find the scale factor from the pair of sides we know. Scale factor = length in the large shape ÷ matching length in the small shape.
    9 cm ÷ 6 cm = 32
    So the large shape is 32 times as big as the small shape.
  3. Use the scale factor to find x. x is on the large shape and we know the matching side on the small shape. Going from small to large we multiply by the scale factor.
    x = 5 cm × 32 = 7.5 cm
  4. Write the answer with its unit. Lengths need a unit.
    x = 7.5 cm

Check. Ratio check: 7.5 cm ÷ 5 cm = 32, the same scale factor as before. ✓

Watch out. Make sure you pair the matching sides (same position in both shapes). Multiply when going from the small shape to the large one and divide when going from large to small.

Worked example 21.8.2
The two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
4 cmx10 cm15 cm

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. Similar shapes have corresponding sides in the same ratio. Find the scale factor from a pair of matching sides we know, then use it on the side we want.

  1. Match the corresponding sides. In similar shapes the sides that are in the same position match. Their lengths are in the same ratio, and that ratio is the scale factor.
    Known pair: 4 cm (small shape) and 10 cm (large shape).
    The side we want is the one marked x.
  2. Find the scale factor from the pair of sides we know. Scale factor = length in the large shape ÷ matching length in the small shape.
    10 cm ÷ 4 cm = 52
    So the large shape is 52 times as big as the small shape.
  3. Use the scale factor to find x. x is on the small shape and we know the matching side on the large shape. Going from large to small we divide by the scale factor.
    x = 15 cm ÷ 52 = 6 cm
  4. Write the answer with its unit. Lengths need a unit.
    x = 6 cm

Check. Ratio check: 15 cm ÷ 6 cm = 52, the same scale factor as before. ✓

Watch out. Make sure you pair the matching sides (same position in both shapes). Multiply when going from the small shape to the large one and divide when going from large to small.

Worked example 21.8.3
The two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
6 m5 m12 mx

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. Similar shapes have corresponding sides in the same ratio. Find the scale factor from a pair of matching sides we know, then use it on the side we want.

  1. Match the corresponding sides. In similar shapes the sides that are in the same position match. Their lengths are in the same ratio, and that ratio is the scale factor.
    Known pair: 6 m (small shape) and 12 m (large shape).
    The side we want is the one marked x.
  2. Find the scale factor from the pair of sides we know. Scale factor = length in the large shape ÷ matching length in the small shape.
    12 m ÷ 6 m = 2
    So the large shape is 2 times as big as the small shape.
  3. Use the scale factor to find x. x is on the large shape and we know the matching side on the small shape. Going from small to large we multiply by the scale factor.
    x = 5 m × 2 = 10 m
  4. Write the answer with its unit. Lengths need a unit.
    x = 10 m

Check. Ratio check: 10 m ÷ 5 m = 2, the same scale factor as before. ✓

Watch out. Make sure you pair the matching sides (same position in both shapes). Multiply when going from the small shape to the large one and divide when going from large to small.

Worked example 21.8.4
In triangle ABC, D is on AB and E is on AC. DE is parallel to BC. The diagram is drawn to scale. Work out the value of x.
4 cm6 cmx8 cmABCDE

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. Parallel lines make triangles ADE and ABC similar. Find the scale factor from a pair of sides we know, then use it on the side we need.

  1. Explain why the triangles are similar. We may only use scale factors if the triangles are similar. Parallel lines give equal corresponding angles.
    DE is parallel to BC, so angle ADE = angle ABC (corresponding angles) and angle AED = angle ACB (corresponding angles). Angle A is common to both triangles. All three angles match, so triangles ADE and ABC are similar.
  2. Find AB. AB is the whole side. The small triangle ADE uses AD, and the large triangle ABC uses AB = AD + DB.
    AB = AD + DB = 4 cm + 6 cm = 10 cm
  3. Find the scale factor from the small triangle to the large triangle. Scale factor = length in ABC ÷ matching length in ADE. AB matches AD.
    AB ÷ AD = 10 cm ÷ 4 cm = 52
  4. Use it to find BC. BC matches DE. Going from the small triangle to the large one, multiply.
    BC = DE × 52 = 8 cm × 52 = 20 cm
  5. Write the answer with its unit.
    x = 20 cm

Check. Ratio check: AD : AB = 4 : 10 and DE : BC = 8 : 20. Both equal 25 when written as a fraction. ✓

Watch out. The side AB of the large triangle is the whole side AD + DB. Do not use DB alone as the matching side for AD.

Worked example 21.8.5
AC and BD cross at X. AB is parallel to CD. The diagram is drawn to scale. Work out the value of x.
5 cmx3 cm4.5 cmABCDX

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. The crossing lines make triangles XAB and XCD similar. Find the scale factor from a pair of sides we know, then use it on the side we need.

  1. Explain why the triangles are similar. Parallel lines give equal alternate angles, and crossing lines give equal vertically opposite angles.
    AB is parallel to CD, so angle XAB = angle XCD (alternate angles) and angle XBA = angle XDC (alternate angles). Angle AXB = angle CXD (vertically opposite angles). All three angles match, so triangles XAB and XCD are similar.
  2. Find the scale factor from the small triangle to the large triangle. XA matches XC. Scale factor = XC ÷ XA.
    4.5 cm ÷ 3 cm = 32
  3. Use it to find CD. CD matches AB. Multiply by the scale factor.
    CD = AB × 32 = 5 cm × 32 = 7.5 cm
  4. Write the answer with its unit.
    x = 7.5 cm

Check. Ratio check: CD ÷ AB = 7.5 cm ÷ 5 cm = 32. ✓

Watch out. Match the sides by position: XA matches XC, XB matches XD and AB matches CD. The small triangle is the one at the top.

Worked example 21.8.6
A man who is 1.8 m tall casts a shadow 2.4 m long. At the same time a tree casts a shadow 10 m long. Work out the height of the tree.
2.4 m1.8 m10 mh

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. The man and the tree make similar right-angled triangles with the sun’s rays, because the sun’s rays are parallel and both stand vertically. Use the scale factor from the shadows.

  1. Explain why the triangles are similar. The man and the tree are both vertical, the ground is horizontal and the rays of the sun are parallel. So the triangles have equal angles.
    Man’s triangle and tree’s triangle are similar.
  2. Find the scale factor from the man’s shadow to the tree’s shadow. The shadows match each other. Scale factor = tree shadow ÷ man shadow.
    10 ÷ 2.4 = 25 ÷ 6 = 256
  3. Use it to find the height of the tree. The heights match each other. Multiply the man’s height by the scale factor.
    1.8 × 256 = 45 ÷ 6 = 7.5 m

Check. Check the ratio the other way: 1.8 ÷ 2.4 = 0.75 and 7.5 ÷ 10 = 0.75. ✓

Watch out. Match shadow to shadow and height to height. Do not match the height of one with the shadow of the other.

Worked example 21.8.7
Triangles ABC and PQR are similar. AB = 6 cm and PQ = 9 cm. BC = x cm and QR = (x + 4) cm. Work out x.

Key words. Two shapes are similar if one is an enlargement of the other: same shape, different size. Corresponding sides are in the same position in both shapes. The scale factor is the number you multiply lengths by to go from one shape to the other.

Method. Write the scale factor two ways: from the lengths we know and from the lengths with x. They must be equal, so we get an equation to solve.

  1. Find the scale factor from AB to PQ. Scale factor = PQ ÷ AB.
    9 ÷ 6 = 1.5
  2. Write QR in terms of BC using the scale factor. QR matches BC, and every length on PQR is 1.5 times the matching length on ABC.
    x + 4 = 1.5 × x
  3. Solve the equation. Subtract x from both sides, then divide by 0.5.
    4 = 1.5x − x = 0.5x
    x = 4 ÷ 0.5 = 8

Check. BC = 8 cm and QR = 12 cm, and 12 ÷ 8 = 1.5. ✓

Watch out. Write the scale factor as a number first, then form the equation. Do not mix the two triangles up.

Watch out

Match the corresponding sides carefully: the side opposite the same angle, or in the same position. In the nested triangle, the side matching AD is AB (the whole side), not DB. Also remember: from the small shape to the large shape multiply; from the large shape to the small shape divide.

Exercise 21I  Similar shapes and missing lengths

Non-calculator
1
FEach pair of shapes is similar and drawn to scale. Work out the value of x in each pair.
(a)
5 cm3 cm10 cmx
(b)
4 cm3 cm12 cmx
(c)
6 cm5 cm12 cmx
2
FThe two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
4 cmx10 cm15 cm
3
FThe two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
5 cmx15 cm12 cm
4
FThe two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
6 cm4 cm9 cmx
5
FThe two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
8 m3 m12 mx
6
FThe ratio of the corresponding sides of two similar shapes is 2 : 5. A side of the smaller shape is 8 cm. Work out the length of the matching side of the larger shape.
7
FSay whether each pair of rectangles is similar. Show your working.
(a)4 cm by 6 cm and 6 cm by 9 cm
(b)3 cm by 5 cm and 6 cm by 9 cm
(c)2 cm by 5 cm and 4 cm by 10 cm
8
FIn triangle ABC, D is on AB and E is on AC. DE is parallel to BC. The diagram is drawn to scale. Work out the value of x.
4 cm6 cmx8 cmABCDE
9
FIn triangle ABC, D is on AB and E is on AC. DE is parallel to BC. The diagram is drawn to scale. Work out the value of x.
3 cm2 cm15 cmxABCDE
10
PSIn triangle ABC, D is on AB and E is on AC. DE is parallel to BC. The diagram is drawn to scale. Work out the value of x.
6 cm3 cm8 cmxABCDE
11
FAC and BD cross at X. AB is parallel to CD. The diagram is drawn to scale. Work out the value of x.
5 cmx3 cm4.5 cmABCDX
12
PSAC and BD cross at X. AB is parallel to CD. The diagram is drawn to scale. Work out the value of x.
4 cm12 cmx6 cmABCDX
13
PSA photograph measures 12 cm by 18 cm. It is enlarged so that its width becomes 20 cm. Work out the new height of the photograph.
14
PSA model car is made with a scale of 1 : 24. The real car is 4.8 m long. Work out the length of the model, in centimetres.
15
PSA pole 2 m tall casts a shadow 1.5 m long. At the same time a building casts a shadow 18 m long. Work out the height of the building.
16
RExplain why any two squares are similar, but two rectangles are not always similar.
17
RTriangle ABC has angles of 40° and 60°. Triangle PQR has angles of 60° and 80°. Show that the triangles are similar.
18
PSThe two triangles are similar. The sides of the smaller triangle are 6 cm and 8 cm. The matching sides of the larger triangle are x cm and (x + 6) cm. Work out the value of x.
19
RIn triangle ABC, D is a point on AB and E is a point on AC. DE is parallel to BC. Prove that triangles ADE and ABC are similar.
ABCDE
20
RChallenge. A4 paper measures 297 mm by 210 mm and A5 paper measures 210 mm by 148.5 mm. Show that A4 and A5 paper are similar rectangles (correct to 3 significant figures).
21
FThe two shapes are mathematically similar. The diagrams are drawn to scale. Work out the value of x.
10 cm8 cm25 cmx

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