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GCSE Maths · EdexcelChapter 25 · Functions and advanced graphs
GCSE Maths · Functions and Advanced Graphs · Higher · Lesson 25.2

GCSE Maths: Inverse functions (Higher)

Part of the GCSE Maths functions and advanced graphs chapter (Higher). Chapter overview · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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25.2

Inverse functions

Edexcel 1MA1: A7
Grade 6-8

Some jobs can be undone. If you put your socks on and then your shoes, to undo it you take your shoes off first and then your socks. A function can be undone in the same way. The inverse function of f, written f−1, takes the output of f and returns the original input. If f(4) = 7 then f−1(7) = 4.

x× 3− 5f(x)fx+ 5÷ 3f⁻¹(x)f inverse
The function machine for f(x) = 3x − 5 and its inverse. Each step is reversed, and the order of the steps is reversed too.

Method 1: reverse the machine. Write down what f does to x in order: “multiply by 3, then subtract 5”. The inverse does the opposite operations in the opposite order: “add 5, then divide by 3”. So f−1(x) = (x + 5) ÷ 3.

Method 2: algebra. This works for every function. (1) Write y = f(x). (2) Rearrange the equation to make x the subject, using the same steps you used to rearrange formulae in Chapter 8. (3) Replace y by x in the answer, because the input of a function is normally called x. For y = 3x − 5 we get y + 5 = 3x, so x = (y + 5) ÷ 3, and f−1(x) = (x + 5) ÷ 3. When x appears twice, such as in f(x) = (2x + 1) ÷ (x − 3), multiply out the fraction first, collect all the x terms on one side and factorise.

Finding one value. To find f−1(7) you do not need the whole inverse. It is the input that f turns into 7, so just solve f(x) = 7.

The graph of the inverse. If (a, b) is on the graph of y = f(x), then (b, a) is on the graph of y = f−1(x), because the roles of input and output swap. So the two graphs are reflections of each other in the line y = x.

xy-4-3-2-1123456-4-3-2-1123456(2, 5)(5, 2)
The blue line is y = f(x) = 2x + 1 and the orange line is y = f⁻¹(x) = (x − 1)/2. The grey dashed line is y = x. The points (2, 5) and (5, 2) are mirror images.

Not every function has an inverse. If two different inputs give the same output, the inverse would not know which one to return. For example g(x) = x2 sends both 3 and −3 to 9. To make an inverse we restrict the inputs, for instance to x ≥ 0, and then g−1(x) = √x. The questions in this chapter will say when this is needed.

Key ideas

  • The inverse function f−1 undoes f: if f(a) = b then f−1(b) = a.
  • To find it: write y = f(x), make x the subject, then swap y for x. Or reverse the machine: opposite operations, opposite order.
  • To find f−1(b) for one value, solve f(x) = b.
  • The graph of y = f−1(x) is the reflection of y = f(x) in the line y = x.
  • f−1(x) does not mean 1 ÷ f(x).
Worked example 25.2.1
f(x) = 3x − 5. Find f−1(x).

Key words. The inverse function f−1 reverses f: if f takes 3 to 11, then f−1 takes 11 back to 3. Subject means the letter on its own on one side.

Method. To find the inverse function f⁻¹, write y = f(x), make x the subject, then swap the letters. The inverse undoes what the function did.

  1. Write the function as y = … f(x) is the output, which we call y. We want to turn the rule round so that x is given in terms of y.
    y = 3x − 5
  2. Describe what the function does to x, in order. Think of a function machine. To undo it we must reverse every step, in reverse order.
    x× 3− 5y
  3. Swap the sides so the x part is on the left. We now rearrange to make x the subject.
    3x − 5 = y
  4. Add 5 to both sides. The last thing that happens is that 5 is subtracted. The opposite of subtracting 5 is adding 5. Do it to both sides.
    3x = y + 5
  5. Divide both sides by 3. The unknown part is being multiplied by 3. The opposite of multiplying by 3 is dividing by 3.
    x = y + 53
  6. Write x in terms of y. Now x is the subject.
    x = y + 53
  7. Swap the letters: write x for the input of the inverse function. A function is written with x as its input, so we rename y as x.
    f−1(x) = x + 53

Check. Test with a number: f(2) = 1. Then f−1(1) = 13 + 53 = 2, which takes us back to the input 2. ✓

Watch out. The notation f−1(x) does not mean 1 divided by f(x). It means the inverse function.

Worked example 25.2.2
f(x) = 2x + 13. Find f−1(x).

Key words. The inverse function f−1 reverses f: if f takes 3 to 11, then f−1 takes 11 back to 3. Subject means the letter on its own on one side.

Method. To find the inverse function f⁻¹, write y = f(x), make x the subject, then swap the letters. The inverse undoes what the function did.

  1. Write the function as y = … f(x) is the output, which we call y. We want to turn the rule round so that x is given in terms of y.
    y = 2x + 13
  2. Describe what the function does to x, in order. Think of a function machine. To undo it we must reverse every step, in reverse order.
    x× 2+ 1÷ 3y
  3. Swap the sides so the x part is on the left. We now rearrange to make x the subject.
    2x + 13 = y
  4. Multiply both sides by 3. The expression is being divided by 3. The opposite of dividing by 3 is multiplying by 3.
    2x + 1 = 3y
  5. Subtract 1 from both sides. The last thing that happens to the x-part is that 1 is added. The opposite of adding 1 is subtracting 1. Do it to both sides to keep the equation balanced.
    2x = 3y − 1
  6. Divide both sides by 2. The unknown part is being multiplied by 2. The opposite of multiplying by 2 is dividing by 2.
    x = 3y − 12
  7. Write x in terms of y. Now x is the subject.
    x = 3y − 12
  8. Swap the letters: write x for the input of the inverse function. A function is written with x as its input, so we rename y as x.
    f−1(x) = 3x − 12

Check. Test with a number: f(2) = 53. Then f−1(53) = 3 × 532 − 12 = 2, which takes us back to the input 2. ✓

Watch out. The notation f−1(x) does not mean 1 divided by f(x). It means the inverse function.

Worked example 25.2.3
f(x) = 8x − 1, x ≠ 1. Find f−1(x).

Key words. The inverse function f−1 reverses f: if f takes 3 to 11, then f−1 takes 11 back to 3. Subject means the letter on its own on one side.

Method. To find the inverse function f⁻¹, write y = f(x), make x the subject, then swap the letters. The inverse undoes what the function did.

  1. Write the function as y = … f(x) is the output, which we call y. We want to turn the rule round so that x is given in terms of y.
    y = 8x − 1
  2. Describe what the function does to x, in order. Think of a function machine. To undo it we must reverse every step, in reverse order.
    x− 18 ÷ inputy
  3. Swap the sides so the x part is on the left. We now rearrange to make x the subject.
    8x − 1 = y
  4. The unknown is on the bottom of the fraction: multiply both sides by it, then divide both sides by the other side. Multiplying both sides by x − 1 removes the fraction. Then dividing both sides by y leaves x − 1 on its own.
    8 = y(x − 1)
    8y = x − 1
  5. Add 1 to both sides. The last thing that happens is that 1 is subtracted. The opposite of subtracting 1 is adding 1. Do it to both sides.
    x = y + 8y
  6. Write x in terms of y. Now x is the subject.
    x = y + 8y
  7. Swap the letters: write x for the input of the inverse function. A function is written with x as its input, so we rename y as x.
    f−1(x) = x + 8x

Check. Test with a number: f(2) = 8. Then f−1(8) = 88 + 1 = 2, which takes us back to the input 2. ✓

Watch out. The notation f−1(x) does not mean 1 divided by f(x). It means the inverse function.

Worked example 25.2.4
f(x) = (x − 2)3 + 1. Find f−1(x).

Key words. The inverse function f−1 reverses f: if f takes 3 to 11, then f−1 takes 11 back to 3. Subject means the letter on its own on one side.

Method. To find the inverse function f⁻¹, write y = f(x), make x the subject, then swap the letters. The inverse undoes what the function did.

  1. Write the function as y = … f(x) is the output, which we call y. We want to turn the rule round so that x is given in terms of y.
    y = (x − 2)3 + 1
  2. Describe what the function does to x, in order. Think of a function machine. To undo it we must reverse every step, in reverse order.
    x− 2cube+ 1y
  3. Swap the sides so the x part is on the left. We now rearrange to make x the subject.
    (x − 2)3 + 1 = y
  4. Subtract 1 from both sides. The last thing that happens to the x-part is that 1 is added. The opposite of adding 1 is subtracting 1. Do it to both sides to keep the equation balanced.
    (x − 2)3 = y − 1
  5. Take the cube root of both sides. The opposite of cubing is the cube root.
    x − 2 = ∛(y − 1)
  6. Add 2 to both sides. The last thing that happens is that 2 is subtracted. The opposite of subtracting 2 is adding 2. Do it to both sides.
    x = ∛(y − 1) + 2
  7. Write x in terms of y. Now x is the subject.
    x = ∛(y − 1) + 2
  8. Swap the letters: write x for the input of the inverse function. A function is written with x as its input, so we rename y as x.
    f−1(x) = ∛(x − 1) + 2

Check. Test with a number: f(2) = 1. Then f−1(1) = ∛(1 − 1) + 2 = 2, which takes us back to the input 2. ✓

Watch out. The notation f−1(x) does not mean 1 divided by f(x). It means the inverse function.

Worked example 25.2.5
f(x) = 2x + 1x − 3, x ≠ 3. Find f−1(x).

Method. Rearrange y = f(x) to make x the subject. When x appears twice, multiply out the fraction, collect the x terms and factorise.

  1. Write the function as y = … This time x appears twice (top and bottom), so we cannot simply undo operations one by one. We will rearrange carefully.
    y = 2x + 1x − 3
  2. Multiply both sides by the bottom. This removes the fraction.
    y(x − 3) = 2x + 1
  3. Expand the bracket. Multiply y by each term inside.
    xy − 3y = 2x + 1
  4. Get all the x terms on one side and everything else on the other. We need x on its own eventually, so collect the terms containing x together.
    xy − 2x = 3y + 1
  5. Factorise the left side. Take x out as a common factor so that x appears only once.
    x(y − 2) = 3y + 1
  6. Divide both sides by the bracket. This leaves x on its own.
    x = 3y + 1y − 2
  7. Swap the letters. Write x for the input of the inverse function.
    f−1(x) = 3x + 1x − 2

Check. Test: f(4) = 9, and f−1(9) = 4, the number we started with. ✓

Watch out. Do not forget that y multiplies both terms of the bracket when you expand.

Watch out

Do not confuse f−1(x) with 1 ÷ f(x). They are different: for f(x) = 3x − 5, f−1(x) = (x + 5) ÷ 3 but 1 ÷ f(x) = 1 ÷ (3x − 5). Also, when rearranging, divide or add to the whole of the other side: x = (y + 5) ÷ 3, not y + 5 ÷ 3.

Exercise 25B  Inverse functions

Non-calculator
1
FFind the inverse function f−1(x) of each function.
(a)f(x) = x + 7
(b)f(x) = 5x
(c)f(x) = x3
(d)f(x) = −x + 10
2
FFind the inverse function f−1(x) of each function.
(a)f(x) = 2x + 3
(b)f(x) = 3x − 4
(c)f(x) = x − 25
(d)f(x) = 4(x + 1)
3
FThis function machine shows f. (a) Draw the inverse machine. (b) Write down f−1(x).
x× 4− 1f(x)
4
Ff(x) = 4x − 1. Find
(a)f−1(7)
(b)f−1(−5)
(c)f−1(0)
5
FFind the inverse function f−1(x), where x ≠ 0 or the denominator is not zero.
(a)f(x) = 8x
(b)f(x) = 6x − 2
(c)f(x) = 4x + 1
(d)f(x) = 32x
6
FEach function below is used only for the inputs shown, so it has an inverse. Find f−1(x).
(a)f(x) = x2 + 3,   x ≥ 0
(b)f(x) = (x − 1)2,   x ≥ 1
(c)f(x) = √(x + 4),   x ≥ −4
(d)f(x) = x3 − 1,   all values of x
7
PSFind f−1(x).
(a)f(x) = 3(x − 2) + 1
(b)f(x) = −2x + 5
(c)f(x) = (x + 2)3
(d)f(x) = x + 42
8
PSFind the inverse of each function. In each case there is an x on the top and the bottom of the fraction.
(a)f(x) = 3x + 1x − 2
(b)f(x) = 2x − 1x + 3
(c)f(x) = xx + 1
9
PSThe diagram shows the graph of y = f(x) (blue), the graph of y = f−1(x) (orange) and a dashed line.
xy-4-3-2-1123456-4-3-2-1123456(2, 5)(5, 2)
(a)Write down the equation of the dashed line.
(b)Use the diagram to find f(2) and then write down f−1(5).
(c)Find f−1(x) using algebra, where f(x) = 2x + 1.
10
PSThe temperature in degrees Fahrenheit is F = 1.8C + 32, where C is the temperature in degrees Celsius. Make C the subject of the formula, and use it to convert 68°F to Celsius.
11
PSA taxi charges a fixed fee of £3 plus £2.50 per mile. The cost for d miles is C(d) = 3 + 2.5d. Find the inverse function, and use it to work out how far Priya can travel for £21.
12
RExplain why the function g(x) = x2, for all values of x, does not have an inverse function.
13
Rf(x) = 6 ÷ x, x ≠ 0. Show that f is its own inverse, so f−1(x) = f(x).
14
Rf(x) = kx + 6, where k is a constant. The function f is its own inverse, so f−1(x) = f(x). Find the value of k.
15
Rf(x) = 2x + 3x − 1, x ≠ 1. Find f−1(4) by solving an equation. Then confirm your answer using the inverse function f−1(x) = x + 3x − 2.

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