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GCSE Maths · EdexcelChapter 13 · Quadratic and other graphs
GCSE Maths · Quadratic and Other Graphs · Foundation · Lesson 13.7

GCSE Maths: Distance-time graphs (Foundation)

Part of the GCSE Maths quadratic and other graphs chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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13.7

Distance-time graphs

Edexcel 1MA1: A14
Grade 3-6

A distance-time graph shows a journey. Time goes along the horizontal axis and the distance from the start goes up the vertical axis. You can read how far someone has travelled at any time and when they reached any distance.

The important idea is that the gradient (steepness) of the line is the speed. Remember from Chapter 12 that gradient = change up ÷ change across. On this graph that is change in distance ÷ change in time, which is exactly the formula for speed.

1235101520253035Distance (km)Time (hours)
A cyclist rides for 1 hour, stops for half an hour, then rides on. Part 1 and part 3 slope up (moving). Part 2 is flat (stopped). Part 3 is steeper than part 1, so it is faster.

Finding a speed. Pick a straight part. Work out the change in distance and the change in time, then divide. For the first hour: 15 km in 1 hour is 15 ÷ 1 = 15 km/h. For the last part: 20 km in 1 hour is 20 km/h.

Average speed. The average speed of a whole journey is total distance travelled ÷ total time taken. The time includes stops. For the cyclist: 35 km in 2.5 hours = 14 km/h.

Units. Distance in kilometres and time in hours give a speed in km/h. If the graph uses minutes, change to hours (divide minutes by 60) before you give a speed in km/h. 30 minutes = 0.5 hours.

Key ideas

  • Gradient of a distance-time graph = speed = change in distance ÷ change in time.
  • Steeper line = faster. Horizontal line = stopped. Line sloping down = returning.
  • Average speed = total distance travelled ÷ total time taken (including stops).
  • Use units that match: km and hours give km/h; m and seconds give m/s.
  • Two journeys on the same graph meet where the lines cross.
Worked example 13.7.1
The graph shows the cyclist’s journey. How far had she cycled after 1 hour, and how far after 2 hours?
1235101520253035Distance (km)Time (hours)
▶ Watch this solution as a video

Key words. A distance-time graph shows how far something has travelled from its start (up the side) as time passes (along the bottom). The gradient (steepness) of the line is the speed, because gradient = change up ÷ change across = distance ÷ time. A flat line means stationary (not moving).

Method. Go up from the time to the graph, then across to the distance axis.

  1. Find the time on the horizontal axis. The horizontal axis shows time (Time (hours)).
    Find 2 on the bottom axis.
  2. Go straight up to the line, then straight across. Draw a vertical line up to the graph, then a horizontal line across to the vertical (distance) axis.
    The line meets the graph at height 25.
  3. Read the distance. Read the number on the distance axis, and include the unit.
    25 km

Check. This time is between 1.5 and 2.5, where the distance goes from 15 to 35; 25 lies between them. ✓

Watch out. Read from the right axis: time is along the bottom, distance is up the side.

Worked example 13.7.2
Work out the speed of the cyclist during the last part of her journey, from 1.5 hours to 2.5 hours.

Key words. A distance-time graph shows how far something has travelled from its start (up the side) as time passes (along the bottom). The gradient (steepness) of the line is the speed, because gradient = change up ÷ change across = distance ÷ time. A flat line means stationary (not moving).

Method. Speed is the gradient of a distance-time graph: speed = change in distance ÷ change in time.

  1. Pick the part of the graph. Speed is the gradient of the line. We need the change in distance and the change in time for this part.
    From (1.5, 15) to (2.5, 35)
  2. Find the change in distance and the change in time. Subtract the start values from the end values.
    Change in distance = 35 − 15 = 20 km
    Change in time = 2.5 − 1.5 = 1 hours
  3. Divide distance by time. Speed = distance ÷ time.
    20 ÷ 1 = 20 km/h

Check. Distance = speed × time = 20 × 1 = 20 km, the change we read from the graph. ✓

Watch out. Use the change in distance and the change in time for the same part of the journey, not the totals from the start.

Worked example 13.7.3
A bus travels as shown. Find its speed during the first 20 minutes, in km/h.
51015202530354045505560510152025303540Distance (km)Time (minutes)

Key words. A distance-time graph shows how far something has travelled from its start (up the side) as time passes (along the bottom). The gradient (steepness) of the line is the speed, because gradient = change up ÷ change across = distance ÷ time. A flat line means stationary (not moving).

Method. Speed is the gradient of a distance-time graph: speed = change in distance ÷ change in time.

  1. Pick the part of the graph. Speed is the gradient of the line. We need the change in distance and the change in time for this part.
    From (0, 0) to (20, 10)
  2. Find the change in distance and the change in time. Subtract the start values from the end values.
    Change in distance = 10 − 0 = 10 km
    Change in time = 20 − 0 = 20 minutes
  3. Divide distance by time. Speed = distance ÷ time.
    10 ÷ 20 = 0.5 km/min
  4. Change to the units asked for. The question wants a different unit, so convert.
    There are 60 minutes in an hour, so multiply by 60: 0.5 × 60 = 30 km/h
    Speed = 30 km/h

Check. Distance = speed × time: 30 km/h for 20 minutes (after converting the units) gives 10 km. ✓

Watch out. Use the change in distance and the change in time for the same part of the journey, not the totals from the start.

Worked example 13.7.4
Work out the average speed of the bus for the whole 60 minutes, in km/h.
▶ Watch this solution as a video

Key words. A distance-time graph shows how far something has travelled from its start (up the side) as time passes (along the bottom). The gradient (steepness) of the line is the speed, because gradient = change up ÷ change across = distance ÷ time. A flat line means stationary (not moving).

Method. Average speed = total distance ÷ total time. Change the time to hours so the answer is in km/h.

  1. Find the total distance travelled. Add the distances of the parts where the vehicle moved.
    10 + 30 = 40 km
  2. Find the total time taken, in hours. Speed in km/h needs the time in hours. There are 60 minutes in an hour, so divide the minutes by 60.
    60 minutes = 60 ÷ 60 = 1 hours
  3. Divide distance by time. Average speed = total distance ÷ total time.
    40 ÷ 1 = 40 km/h

Check. In 1 hours at 40 km/h the distance is 40 × 1 = 40 km. ✓

Watch out. Do not divide kilometres by minutes and call it km/h: convert the minutes to hours first.

Worked example 13.7.5
Priya cycles from town A to town B, 80 km away, at a steady speed. Quinn leaves B one hour later and travels towards A. Use the graph to find when they meet and how far they are from A.
12341020304050607080Distance (km)Time (hours)
▶ Watch this solution as a video

Key words. A distance-time graph shows how far something has travelled from its start (up the side) as time passes (along the bottom). The gradient (steepness) of the line is the speed, because gradient = change up ÷ change across = distance ÷ time. A flat line means stationary (not moving).

Method. They meet where the two lines cross, because at that point they are at the same distance at the same time.

  1. Find the crossing point. Look for where the two lines meet.
    The lines cross at (2, 40).
  2. Read the time. The time is the horizontal coordinate.
    Time = 2 hours after Priya set off
  3. Read the distance. The distance from A is the vertical coordinate.
    Distance = 40 km
  4. Write the answer.
    They meet after 2 hours, 40 km from A.

Check. Priya: 20 km/h × 2 h = 40 km. Quinn has travelled 1 hour at 40 km/h = 40 km from B, which is 80 − 40 = 40 km from A. ✓

Watch out. The crossing point gives both the time and the distance.

Watch out

A horizontal line on a distance-time graph means the person is stopped, not moving at constant speed. A line sloping down means returning to the start, and the speed is still the size of the gradient. Also use total distance travelled ÷ total time for the average speed, and include the time spent stopped.

Exam tip

When the graph is in minutes and the answer is in km/h, convert the time to hours first, or multiply a speed in km per minute by 60.

Exercise 13G  Distance-time graphs

Non-calculator
1
FThe graph shows a cycle ride. Use it to find (a) the distance travelled after 1 hour, (b) the distance after 2 hours, (c) the time when the distance was 35 km, (d) how long the cyclist stopped.
1235101520253035Distance (km)Time (hours)
(a)after 1 hour
(b)after 2 hours
(c)the time when the distance was 35 km
(d)how long she stopped
2
FUse the cycle ride graph to work out (a) the speed during the first hour, (b) the speed during the last hour, (c) the average speed for the whole ride.
1235101520253035Distance (km)Time (hours)
(a)the speed in the first hour
(b)the speed in the last hour
(c)the average speed for the whole ride
3
FA car makes a journey to a shop and back. Use the graph to find (a) the greatest distance from the start, (b) how long the car stopped at the shop, (c) the speed on the way there, (d) the speed on the way back, (e) the average speed for the whole journey.
123451015202530354045505560Distance (km)Time (hours)
(a)the greatest distance
(b)how long the car stopped
(c)the speed on the way there
(d)the speed on the way back
(e)the average speed
4
FThe graph shows a bus journey. Distance is in kilometres and time is in minutes. Find (a) the speed during the first 20 minutes in km/h, (b) how long the bus stopped, (c) the speed in the last 30 minutes in km/h.
51015202530354045505560510152025303540Distance (km)Time (minutes)
(a)speed in the first 20 minutes
(b)how long the bus stopped
(c)speed in the last 30 minutes
5
FWork out the average speed of the bus in the previous question for the whole 60 minutes. Give your answer in km/h.
51015202530354045505560510152025303540Distance (km)Time (minutes)
6
PSJo walks to school. The graph shows distance in metres and time in minutes. Find Jo’s speed (a) in metres per minute during the first 10 minutes, (b) in km/h during the first 10 minutes.
510152025303520040060080010001200140016001800Distance (m)Time (minutes)
(a)in metres per minute
(b)in km/h
7
FMia leaves home and cycles 12 km in 1 hour. She rests for half an hour, then cycles home in 1.5 hours. Draw a distance-time graph of her journey. Use a horizontal axis from 0 to 3 hours and a vertical axis from 0 to 12 km.
8
PSSam drives 90 km in 1.5 hours, stops for 30 minutes, then drives a further 60 km in 1 hour. Draw a distance-time graph and work out his average speed for the whole journey.
9
PSPriya cycles from A to B (80 km) at a steady speed. Quinn leaves B one hour later and travels towards A. Use the graph to find (a) when they meet, (b) how far from A they meet, (c) who travels faster, and how you can tell.
12341020304050607080Distance (km)Time (hours)
(a)when they meet
(b)how far from A
(c)who is faster
10
RTom says: “A horizontal line on a distance-time graph means the person is travelling at a constant speed.” Explain his mistake.
11
ROn a journey graph the line slopes down from (2, 60) to (3, 0). Ali says the car is slowing down. Explain why he is wrong.
12
RIn a 200 m race Amy runs at a steady 8 m/s from the start. Ben starts 4 seconds later and runs at a steady 10 m/s. Draw both on a distance-time graph and decide who wins and by how long.

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