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GCSE Maths · EdexcelChapter 13 · Quadratic and other graphs
GCSE Maths · Quadratic and Other Graphs · Foundation · Lesson 13.8

GCSE Maths: Speed-time graphs (Foundation)

Part of the GCSE Maths quadratic and other graphs chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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13.8

Speed-time graphs

Edexcel 1MA1: A14
Grade 4-7

A speed-time graph (also called a velocity-time graph) shows how the speed of something changes. Time is along the horizontal axis and speed is up the vertical axis. This is different from a distance-time graph, so be careful to read the labels on the axes.

The gradient of a speed-time graph is the acceleration: change in speed ÷ change in time. With speed in m/s and time in s the unit is m/s² (metres per second per second). A gradient of 2 means the speed rises by 2 m/s every second. A negative gradient means the speed is falling. This is a deceleration.

The area under the graph (between the line and the time axis) is the distance travelled. This works because distance = speed × time: speed is the height and time is the width. Split the area into rectangles, triangles and trapezia. (Chapter 25 returns to areas under curved graphs.)

246810121416182022246810121416Speed (m/s)Time (seconds)
A car speeds up for 8 s, travels at 16 m/s for 10 s, then slows to a stop in 4 s. The three coloured areas (triangle, rectangle, triangle) are the distances travelled in each stage.

Key ideas

  • Speed-time graph: gradient = acceleration = change in speed ÷ change in time (unit m/s²).
  • Sloping up = accelerating. Flat = constant speed. Sloping down = decelerating (negative acceleration).
  • Area under the graph = distance travelled. Use a rectangle (flat), a triangle (starts or ends at 0) or a trapezium (area = ½(a + b) × width).
  • Average speed = total distance ÷ total time.
Worked example 13.8.1
A car's journey is shown on the speed-time graph. Find its speed after 4 seconds.
246810121416182022246810121416Speed (m/s)Time (seconds)
▶ Watch this solution as a video

Key words. A speed-time graph shows the speed (up the side) as time passes (along the bottom). The gradient is the acceleration (how fast the speed changes), and the area under the graph is the distance travelled. Negative acceleration (the speed is dropping) is called deceleration.

Method. Go up from the time to the line, then across to the speed axis.

  1. Find the time on the horizontal axis. The horizontal axis shows time in seconds.
    Find 4 s along the bottom.
  2. Go straight up to the line, then straight across. The vertical axis shows speed.
    The line is at height 8.
  3. Read the speed. Write the unit.
    8 m/s

Check. The speed at this time is between the speeds at the two corners either side of it. ✓

Watch out. Read the vertical axis for speed.

Worked example 13.8.2
Work out the acceleration of the car during the first 8 seconds.
▶ Watch this solution as a video

Key words. A speed-time graph shows the speed (up the side) as time passes (along the bottom). The gradient is the acceleration (how fast the speed changes), and the area under the graph is the distance travelled. Negative acceleration (the speed is dropping) is called deceleration.

Method. Acceleration is the gradient of a speed-time graph: change in speed ÷ change in time.

  1. Pick the part of the graph. Acceleration is the gradient of the line, so we use the change in speed and the change in time.
    From (0, 0) to (8, 16)
  2. Find the change in speed and the change in time. Subtract the start values from the end values.
    Change in speed = 16 − 0 = 16 m/s
    Change in time = 8 − 0 = 8 s
  3. Divide. Acceleration = change in speed ÷ change in time.
    16 ÷ 8 = 2
  4. Write the answer with its unit. The unit is metres per second per second, written m/s².
    Acceleration = 2 m/s²

Check. The speed changes by 2 m/s every second, for 8 s: 2 × 8 = 16 m/s, the change we found. ✓

Watch out. Acceleration is the gradient. The height of the line is the speed, not the acceleration.

Worked example 13.8.3
Work out the deceleration of the car in the last 4 seconds.
▶ Watch this solution as a video

Key words. A speed-time graph shows the speed (up the side) as time passes (along the bottom). The gradient is the acceleration (how fast the speed changes), and the area under the graph is the distance travelled. Negative acceleration (the speed is dropping) is called deceleration.

Method. Acceleration is the gradient of a speed-time graph: change in speed ÷ change in time.

  1. Pick the part of the graph. Acceleration is the gradient of the line, so we use the change in speed and the change in time.
    From (18, 16) to (22, 0)
  2. Find the change in speed and the change in time. Subtract the start values from the end values.
    Change in speed = 0 − 16 = −16 m/s
    Change in time = 22 − 18 = 4 s
  3. Divide. Acceleration = change in speed ÷ change in time.
    −16 ÷ 4 = −4
  4. Interpret the sign. The line slopes downwards, so the speed is falling. This is a deceleration. As a gradient it is negative.
    Acceleration = −4 m/s² (a deceleration of 4 m/s²)

Check. The speed changes by −4 m/s every second, for 4 s: −4 × 4 = −16 m/s, the change we found. ✓

Watch out. Acceleration is the gradient. The height of the line is the speed, not the acceleration.

Worked example 13.8.4
Work out the total distance travelled by the car in the 22 seconds.
▶ Watch this solution as a video

Key words. A speed-time graph shows the speed (up the side) as time passes (along the bottom). The gradient is the acceleration (how fast the speed changes), and the area under the graph is the distance travelled. Negative acceleration (the speed is dropping) is called deceleration.

Method. Distance travelled = area under the speed-time graph. Split it into rectangles, triangles and trapezia.

  1. Remember: distance is the area under the graph. Distance = speed × time. On the graph, speed is the height and time is the width, so distance is the area between the line and the time axis.
  2. Split the area into simple shapes. Use a rectangle where the line is flat, a triangle where it starts or ends at 0, and a trapezium otherwise.
    From 0 s to 8 s, a triangle: ½ × 8 × 16 = 64
    From 8 s to 18 s, a rectangle: 16 × 10 = 160
    From 18 s to 22 s, a triangle: ½ × 4 × 16 = 32
  3. Add the areas. The total area is the total distance travelled.
    64 + 160 + 32 = 256 m

Check. Sense check: the vehicle never goes faster than 16 m/s and travels for 22 s, so the distance must be less than 352 m. Our 256 m is smaller. ✓

Watch out. The unit of the area is the unit of distance (m), not m/s. Area = height × width means speed × time.

Worked example 13.8.5
A train's speed is shown. Work out its average speed over the whole 40 seconds.
5101520253035402468101214161820Speed (m/s)Time (seconds)
▶ Watch this solution as a video

Key words. A speed-time graph shows the speed (up the side) as time passes (along the bottom). The gradient is the acceleration (how fast the speed changes), and the area under the graph is the distance travelled. Negative acceleration (the speed is dropping) is called deceleration.

Method. Average speed = total distance ÷ total time. Find the distance from the area under the graph.

  1. Find the area of each part. Triangle, rectangle, triangle.
    Triangle: ½ × 10 × 20 = 100
    Rectangle: 20 × 20 = 400
    Triangle: ½ × 10 × 20 = 100
  2. Add to get the total distance.
    100 + 400 + 100 = 600 m
  3. Divide by the total time. The time is 40 seconds.
    600 ÷ 40 = 15 m/s

Check. 15 m/s for 40 s = 600 m. ✓

Watch out. Average speed is not the top speed (20 m/s).

Watch out

On a speed-time graph a flat line means constant speed (not stopped). A line sloping down means slowing down, not going backwards. And a gradient is acceleration here, not speed. The area under the graph has units of distance (m), not m/s.

Exam tip

Label each area you use (A, B, C) with its shape and its calculation, and add them at the end. Check the units of every axis before you start.

Exercise 13H  Speed-time graphs

Non-calculator
1
FThe graph shows the speed of a car. Use it to find (a) the speed after 4 seconds, (b) how long the car travelled at a constant speed, (c) the acceleration in the first 8 seconds, (d) the deceleration in the last 4 seconds.
246810121416182022246810121416Speed (m/s)Time (seconds)
(a)speed after 4 seconds
(b)time at constant speed
(c)acceleration in the first 8 seconds
(d)deceleration in the last 4 seconds
2
FA train’s journey is shown. Find (a) its acceleration in the first 10 seconds, (b) its speed while moving steadily, (c) how long it takes to stop at the end, (d) its deceleration at the end.
5101520253035402468101214161820Speed (m/s)Time (seconds)
(a)acceleration
(b)steady speed
(c)time to stop
(d)deceleration
3
FUse the car graph to work out the distance travelled (a) in the first 8 seconds, (b) in the 10 seconds at constant speed, (c) in the whole 22 seconds.
246810121416182022246810121416Speed (m/s)Time (seconds)
(a)first 8 seconds
(b)the 10 seconds at constant speed
(c)the whole 22 seconds
4
FWork out the total distance travelled by the train in the graph (40 seconds).
5101520253035402468101214161820Speed (m/s)Time (seconds)
5
FA cyclist’s speed is shown. Find (a) the acceleration in the first 6 seconds, (b) the distance travelled in the 10 seconds.
123456789101234567891011121314Speed (m/s)Time (seconds)
(a)acceleration
(b)distance in 10 seconds
6
FA lorry travels at a steady speed, then brakes to a stop. Use the graph to find (a) the speed of the lorry before braking, (b) the deceleration, (c) the total distance travelled in the 10 seconds.
12345678910123456789101112Speed (m/s)Time (seconds)
(a)speed before braking
(b)deceleration
(c)total distance
7
FA car starts from rest and speeds up to 12 m/s in 6 seconds. It then travels at 12 m/s for 10 seconds, then slows down to a stop in 4 seconds. Draw a speed-time graph for the car, then work out its total distance.
8
PSUse the train graph to find the train’s average speed over the 40 seconds.
5101520253035402468101214161820Speed (m/s)Time (seconds)
9
PSThe train’s speed increases steadily from 0 to 20 m/s in 10 seconds. How far has it travelled when its speed first reaches 15 m/s?
5101520253035402468101214161820Speed (m/s)Time (seconds)
10
RLayla says: “The line on a speed-time graph slopes down, so the car is going backwards.” Explain her mistake.
11
RComplete the table to compare what a flat line and a sloping-up line mean on each type of graph.
(a)A flat line on a distance-time graph
(b)A flat line on a speed-time graph
(c)A sloping-up line on a speed-time graph
12
RCar A accelerates at 2 m/s² from rest for 10 seconds and then travels at constant speed. Car B accelerates steadily from rest at 1 m/s² for 20 seconds. Both start together. Draw both on a speed-time graph. Which car has travelled further after 20 seconds, and by how much?

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