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GCSE Maths · EdexcelChapter 13 · Quadratic and other graphs
GCSE Maths · Quadratic and Other Graphs · Foundation · Lesson 13.3

GCSE Maths: Solving equations using graphs (Foundation)

Part of the GCSE Maths quadratic and other graphs chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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13.3

Solving equations using graphs

Edexcel 1MA1: A11, A12
Grade 4-6

A graph can be used to solve an equation. This is useful when an equation is hard to solve in any other way, and it shows you what the solutions mean. The idea is always the same: a solution is the x-value of a point where two graphs meet.

Solving x² − 2x − 3 = 0. The curve y = x² − 2x − 3 has the rule on one side of the equation. The equation says that this rule equals 0. On the graph, y = 0 is the x-axis. So the solutions are the x-values where the curve crosses the x-axis. They are the roots.

Solving x² − 2x − 3 = 5. Now the rule must equal 5. Draw the horizontal line y = 5 across the grid. Where it meets the curve, the curve has y = 5. Read the x-values of those points. There can be two, one or no solutions.

xy-2-11234-5-4-3-2-112345
Solving x² − 2x − 3 = 5. The horizontal line y = 5 meets the curve at the two red points. Reading across the bottom: x = −2 and x = 4.

Solving x² = 2x + 3. The two sides are two different rules. Draw both as graphs on the same grid: the curve y = x² and the straight line y = 2x + 3. At a crossing point both graphs have the same x and the same y, so x² = 2x + 3 is true there. The solutions are the x-values of the crossing points.

xy-2-112342468101214
The curve y = x² (blue) and the line y = 2x + 3 (orange) cross at (−1, 1) and (3, 9). The solutions of x² = 2x + 3 are x = −1 and x = 3.

Answers read from a graph are only approximate: you can only read as accurately as the grid allows. If the crossing is between grid lines, estimate to 1 decimal place. Exam questions that need this will say “use the graph” or “give your answers to 1 decimal place”. Always show the line you drew.

Key ideas

  • A solution of an equation is the x-value of a point where two graphs meet.
  • To solve (rule) = 0, read where the curve crosses the x-axis.
  • To solve (rule) = k, draw the horizontal line y = k and read the x-values where it meets the curve.
  • To solve (rule 1) = (rule 2), graph both on the same grid and read the x-values where they cross.
  • Graph answers are approximate. Read the x-values, not the y-values.
Worked example 13.3.1
Here is the graph of y = x² − 2x − 3. Use it to solve x² − 2x − 3 = 0.
xy-2-11234-5-4-3-2-112345
▶ Watch this solution as a video

Key words. To solve an equation graphically means to read its answers from a graph. Where two graphs meet they have the same x and the same y, so the x-value at a crossing point makes the two rules equal. Graph readings are approximate because we can only read to the accuracy of the drawing.

Method. Draw the horizontal line y = (the number on the right). Where it crosses the curve, read the x-values.

  1. Spot the graph being used. The graph shows y = x2 − 2x − 3. The equation we want to solve is the same expression set equal to 0.
    x2 − 2x − 3 = 0 means y = 0 on this graph
  2. Draw the horizontal line y = 0. Every point on this line has a y-value of 0. Where the line meets the curve, the curve has y = 0, which is exactly when the equation is true.
    Start at 0 on the y-axis and draw straight across (a ruler helps).
  3. Find where the line crosses the curve. Mark each crossing point.
    The line meets the curve at (−1, 0) and (3, 0).
  4. Read the x-values. The solutions of the equation are the x-values of the crossing points (the numbers along the bottom axis).
    x = −1 or 3

Check. Substitute back: y = (−1)2 − 2 × (−1) − 3 = 1 + 2 − 3 = 0; y = 32 − 2 × 3 − 3 = 9 − 6 − 3 = 0 ✓

Watch out. Read the x-values of the crossing points, not the y-values. The y-value is just the number you started with.

Worked example 13.3.2
Use the same graph of y = x² − 2x − 3 to solve x² − 2x − 3 = 5.
▶ Watch this solution as a video

Key words. To solve an equation graphically means to read its answers from a graph. Where two graphs meet they have the same x and the same y, so the x-value at a crossing point makes the two rules equal. Graph readings are approximate because we can only read to the accuracy of the drawing.

Method. Draw the horizontal line y = (the number on the right). Where it crosses the curve, read the x-values.

  1. Spot the graph being used. The graph shows y = x2 − 2x − 3. The equation we want to solve is the same expression set equal to 5.
    x2 − 2x − 3 = 5 means y = 5 on this graph
  2. Draw the horizontal line y = 5. Every point on this line has a y-value of 5. Where the line meets the curve, the curve has y = 5, which is exactly when the equation is true.
    Start at 5 on the y-axis and draw straight across (a ruler helps).
  3. Find where the line crosses the curve. Mark each crossing point.
    The line meets the curve at (−2, 5) and (4, 5).
  4. Read the x-values. The solutions of the equation are the x-values of the crossing points (the numbers along the bottom axis).
    x = −2 or 4

Check. Substitute back: y = (−2)2 − 2 × (−2) − 3 = 4 + 4 − 3 = 5; y = 42 − 2 × 4 − 3 = 16 − 8 − 3 = 5 ✓

Watch out. Read the x-values of the crossing points, not the y-values. The y-value is just the number you started with.

Worked example 13.3.3
The graphs of y = x² and y = 2x + 3 are drawn on the same grid. Use them to solve x² = 2x + 3.
xy-2-112342468101214
▶ Watch this solution as a video

Key words. To solve an equation graphically means to read its answers from a graph. Where two graphs meet they have the same x and the same y, so the x-value at a crossing point makes the two rules equal. Graph readings are approximate because we can only read to the accuracy of the drawing.

Method. The solutions are the x-values of the points where the two graphs cross.

  1. Say which two graphs are being used. The equation has the rule of the curve on one side and the rule of the line on the other. Each side is drawn as its own graph.
    Curve: y = x2
    Line: y = 2x + 3
  2. Explain why crossing points give the answers. At a crossing point both graphs have the same x and the same y, so the two rules give the same value. That is what the equation says.
    Solve x² = 2x + 3: the curve y = x² and the line y = 2x + 3 are both drawn.
  3. Find the crossing points. Look for every place where the two graphs meet.
    They cross at (−1, 1) and (3, 9).
  4. Read the x-values. The solutions are the x-coordinates of the crossing points.
    x = −1 or 3

Check. Substitute each x-value into both sides.
x = −1: left = 1, right = 1. Equal. ✓
x = 3: left = 9, right = 9. Equal. ✓

Watch out. Write only the x-values. (The y-values at the crossings are not the answer.)

Worked example 13.3.4
Here is the graph of y = x². Use it to find estimates of the solutions of x² = 10. Give your answers to 1 decimal place.
xy-4-3-2-11234246810121416
▶ Watch this solution as a video

Key words. To solve an equation graphically means to read its answers from a graph. Where two graphs meet they have the same x and the same y, so the x-value at a crossing point makes the two rules equal. Graph readings are approximate because we can only read to the accuracy of the drawing.

Method. Draw the horizontal line y = (the number on the right). Where it crosses the curve, read the x-values.

  1. Spot the graph being used. The graph shows y = x2. The equation we want to solve is the same expression set equal to 10.
    x2 = 10 means y = 10 on this graph
  2. Draw the horizontal line y = 10. Every point on this line has a y-value of 10. Where the line meets the curve, the curve has y = 10, which is exactly when the equation is true.
    Start at 10 on the y-axis and draw straight across (a ruler helps).
  3. Find where the line crosses the curve. Mark each crossing point.
    The line meets the curve at (−3.2, 10) and (3.2, 10).
  4. Read the x-values. The solutions of the equation are the x-values of the crossing points (the numbers along the bottom axis).
    x ≈ −3.2 or 3.2 (accept answers within 0.1)

Check. Substitute back: at x = −3.2 the rule gives 10.00; at x = 3.2 the rule gives 10.00 ✓

Watch out. Read the x-values of the crossing points, not the y-values. The y-value is just the number you started with.

Watch out

Read the x-values where the graphs meet. The y-value of a crossing point is not the answer. For x² = 2x + 3 the crossing points are (−1, 1) and (3, 9), but the solutions are x = −1 and x = 3. Also remember there can be two solutions: look for both crossings.

Exam tip

Draw the line you use in a different colour with a ruler, and put a small cross at each crossing point before you read down to the x-axis. Write “x = ... or x = ...”.

Exercise 13C  Solving equations using graphs

Non-calculator
1
FHere is the graph of y = x² − 2x − 3. Use it to solve (a) x² − 2x − 3 = 0, (b) x² − 2x − 3 = 5, (c) x² − 2x − 3 = −3, (d) x² − 2x − 3 = −4.
xy-2-11234-5-4-3-2-112345
(a)x² − 2x − 3 = 0
(b)x² − 2x − 3 = 5
(c)x² − 2x − 3 = −3
(d)x² − 2x − 3 = −4
2
FHere is the graph of y = x². Use it to solve each equation. Give any approximate answers to 1 decimal place.
xy-4-3-2-11234246810121416
(a)x² = 4
(b)x² = 9
(c)x² = 6.25
(d)x² = 10
3
FHere is the graph of y = x² − 4x + 3. Use it to solve (a) x² − 4x + 3 = 0, (b) x² − 4x + 3 = 3, (c) x² − 4x + 3 = 8, (d) x² − 4x + 3 = −1.
xy-2-112345-2-112345
(a)x² − 4x + 3 = 0
(b)x² − 4x + 3 = 3
(c)x² − 4x + 3 = 8
(d)x² − 4x + 3 = −1
4
FHere is the graph of y = 4 − x². Use it to solve (a) 4 − x² = 0, (b) 4 − x² = 3, (c) 4 − x² = −5, (d) 4 − x² = 4.
xy-3-2-1123-5-4-3-2-112345
(a)4 − x² = 0
(b)4 − x² = 3
(c)4 − x² = −5
(d)4 − x² = 4
5
FThe graphs of y = x² and y = 2x + 3 are drawn on the grid. Use the graphs to solve x² = 2x + 3.
xy-2-112342468101214
6
FThe graphs of y = x² and y = x + 2 are drawn on the grid. Use the graphs to solve x² = x + 2.
xy-2-1123-112345678910
7
FThe graphs of y = x² − 4 and y = x − 2 are drawn on the grid. Use them to solve x² − 4 = x − 2.
xy-2-1123-5-4-3-2-1123456
8
PSUse the graph of y = x² − 2x − 3 (drawn above) to find estimates of the solutions of x² − 2x − 3 = 7. Give your answers to 1 decimal place.
xy-2-11234-5-4-3-2-112345
9
PSHere is the graph of y = x² − 3x. Use it to find estimates of the solutions of x² − 3x = 1. Give your answers to 1 decimal place.
xy-2-112345-3-2-11234567
10
RHana says: “The solutions of x² − 2x − 3 = 0 are the roots of the graph of y = x² − 2x − 3.” Explain why she is right.
11
REmma solves x² = 2x + 3 by drawing both graphs. The graphs cross at (−1, 1) and (3, 9). Emma writes: “The solutions are 1 and 9.” Explain her mistake and give the correct solutions.
12
RUse the graph of y = x² to explain why the equation x² = −5 has no solutions.
13
RThe graph of y = x² − 2x − 3 has its lowest point at (1, −4). Write down the number of solutions of x² − 2x − 3 = k when (a) k = 2, (b) k = −4, (c) k = −6. Explain how you know.
(a)k = 2
(b)k = −4
(c)k = −6

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