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GCSE Maths · EdexcelChapter 13 · Quadratic and other graphs
GCSE Maths · Quadratic and Other Graphs · Higher · Lesson 13.1

GCSE Maths: Tables of values and plotting quadratic graphs (Higher)

Part of the GCSE Maths quadratic and other graphs chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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13.1

Tables of values and plotting quadratic graphs

Edexcel 1MA1: A11, A12
Grade 3-5

In Chapter 12 you drew straight-line graphs. Some rules do not give a straight line. A rule that contains x² (“x squared”) gives a curve. The highest power of x is 2, and a rule like this is called a quadratic. Here are some quadratic rules: y = x², y = x² + 3, y = x² − 2x − 3 and y = 5 − x². The curve has its own name: a parabola.

To draw a quadratic graph we build up the picture from separate points. First we make a table of values. This lists some x-values and works out the matching y-value for each one by substituting: replacing x by the number. Each pair (x, y) is a coordinate. Then we plot the coordinates and join them with a smooth curve.

Be very careful with negative x-values. When you square a negative number the answer is positive, because a negative times a negative is positive: (−3)² = (−3) × (−3) = 9. On a calculator always put the negative number in brackets.

There are two possible shapes. If the number in front of x² is positive the curve is U-shaped and has a lowest point. If it is negative the curve is n-shaped (an upside-down U) and has a highest point. The lowest or highest point is called the turning point. The curve is perfectly symmetrical: it is a mirror image of itself, so the y-values in a table go down and then come back up in exactly the same order (for example 5, 0, −3, −4, −3, 0, 5).

xy-3-2-1123-1123456789(0, 0)y = x² (U-shape)xy-3-2-1123-5-4-3-2-112345(0, 4)y = 4 − x² (n-shape)
A positive x² term gives a U-shape with a lowest point. A negative x² term gives an n-shape with a highest point.

Key ideas

  • A quadratic has an x² term and no higher power. Its graph is a smooth curve called a parabola.
  • Make a table of values: substitute each x into the rule to get y. Put negative numbers in brackets.
  • Plot the points (x, y) and join them with a smooth freehand curve (no ruler, no pointed corners).
  • Positive x² gives a U-shape; negative x² gives an n-shape.
  • The curve is symmetrical about a vertical line through its turning point.
Worked example 13.1.1
Complete the table of values for y = x2 + 2.
x−3−2−10123
y                     
▶ Watch this solution as a video

Key words. To substitute means to replace the letter by a number. A table of values lists x-values and the y-values that go with them. Each pair (x, y) is a coordinate that can be plotted.

Method. Put each x-value into the rule, one at a time, and work out y.

  1. Write the rule and the x-values. A table of values pairs every x-value with its y-value. Each y-value comes from putting that x-value into the rule.
    y = x2 + 2
    x-values: −3, −2, −1, 0, 1, 2, 3
  2. Substitute the x-values one at a time. Do the same calculation every time, only the number changes. Use brackets round negative numbers.
    x = −3:  y = (−3)2 + 2 = 9 + 2 = 11
    x = −2:  y = (−2)2 + 2 = 4 + 2 = 6
    x = −1:  y = (−1)2 + 2 = 1 + 2 = 3
    x = 0:  y = 02 + 2 = 0 + 2 = 2
    x = 1:  y = 12 + 2 = 1 + 2 = 3
    x = 2:  y = 22 + 2 = 4 + 2 = 6
    x = 3:  y = 32 + 2 = 9 + 2 = 11
  3. Write the y-values in the table. Each pair of numbers is a coordinate, ready to be plotted on a graph.
    y-values: 11, 6, 3, 2, 3, 6, 11
    Coordinates: (−3, 11), (−2, 6), (−1, 3), (0, 2), (1, 3), (2, 6), (3, 11)

Check. The gaps between neighbouring y-values are −5, −3, −1, 1, 3, 5. The gaps change by 2 every time (second differences are constant), which is what must happen for a quadratic. ✓

Watch out. Work out the x² part first. A negative number squared is positive.

Worked example 13.1.2
(a) Complete the table of values for y = x2 − 2x − 3. (b) Draw the graph of y = x2 − 2x − 3 for values of x from −2 to 4.
x−2−101234
y                     
▶ Watch this solution as a video

Key words. To substitute means to replace the letter by a number. A table of values lists x-values and the y-values that go with them. Each pair (x, y) is a coordinate that can be plotted.

Method. Make a table of values, plot the points, then join them with a smooth curve.

  1. Make a table of values. Each y-value comes from putting an x-value into the rule. Use brackets round negative numbers.
    x = −2:  y = (−2)2 − 2 × (−2) − 3 = 4 + 4 − 3 = 5
    x = −1:  y = (−1)2 − 2 × (−1) − 3 = 1 + 2 − 3 = 0
    x = 0:  y = 02 − 2 × 0 − 3 = 0 + 0 − 3 = −3
    x = 1:  y = 12 − 2 × 1 − 3 = 1 − 2 − 3 = −4
    x = 2:  y = 22 − 2 × 2 − 3 = 4 − 4 − 3 = −3
    x = 3:  y = 32 − 2 × 3 − 3 = 9 − 6 − 3 = 0
    x = 4:  y = 42 − 2 × 4 − 3 = 16 − 8 − 3 = 5
  2. List the coordinates. Each x with its y makes a point (x, y) to plot.
    (−2, 5), (−1, 0), (0, −3), (1, −4), (2, −3), (3, 0), (4, 5)
  3. Choose the scales for the axes. The x-values go from −2 to 4 and the y-values go from −4 to 5. The axes must cover all of these, and each square must always stand for the same amount.
    x-axis: −2 to 4.   y-axis: −5 to 6.
  4. Plot each point carefully. Go along the x-axis first, then up or down to the y-value. Mark each point with a small cross.
    Plot (−2, 5), (−1, 0), (0, −3), (1, −4), (2, −3), (3, 0), (4, 5).
  5. Join the points with a smooth curve. The graph of this rule is a smooth curve, not a set of straight lines. Draw it freehand in one flowing line, rounded at the turning point (no sharp corner).
    Label the curve y = x2 − 2x − 3.

Check. Every plotted point should lie on the curve, and the curve should pass through (−2, 5) and (4, 5) at the ends. It should be symmetrical about the line x = 1. ✓

Watch out. Do not use a ruler to join the points, and do not draw pointed corners. A quadratic is smooth and rounded at the turning point.

xy-2-11234-5-4-3-2-1123456
The finished graph of y = x² − 2x − 3 (Worked example 13.1.2). It is U-shaped, symmetrical, with its lowest point at (1, −4).
Worked example 13.1.3
Draw the graph of y = −x2 + 5 for values of x from −3 to 3. Is the curve U-shaped or n-shaped?
▶ Watch this solution as a video

Key words. To substitute means to replace the letter by a number. A table of values lists x-values and the y-values that go with them. Each pair (x, y) is a coordinate that can be plotted.

Method. Make a table of values, plot the points, then join them with a smooth curve.

  1. Make a table of values. Each y-value comes from putting an x-value into the rule. Use brackets round negative numbers.
    x = −3:  y = −(−3)2 + 5 = −9 + 5 = −4
    x = −2:  y = −(−2)2 + 5 = −4 + 5 = 1
    x = −1:  y = −(−1)2 + 5 = −1 + 5 = 4
    x = 0:  y = −(0)2 + 5 = 0 + 5 = 5
    x = 1:  y = −(1)2 + 5 = −1 + 5 = 4
    x = 2:  y = −(2)2 + 5 = −4 + 5 = 1
    x = 3:  y = −(3)2 + 5 = −9 + 5 = −4
  2. List the coordinates. Each x with its y makes a point (x, y) to plot.
    (−3, −4), (−2, 1), (−1, 4), (0, 5), (1, 4), (2, 1), (3, −4)
  3. Choose the scales for the axes. The x-values go from −3 to 3 and the y-values go from −4 to 5. The axes must cover all of these, and each square must always stand for the same amount.
    x-axis: −3 to 3.   y-axis: −5 to 6.
  4. Plot each point carefully. Go along the x-axis first, then up or down to the y-value. Mark each point with a small cross.
    Plot (−3, −4), (−2, 1), (−1, 4), (0, 5), (1, 4), (2, 1), (3, −4).
  5. Join the points with a smooth curve. The graph of this rule is a smooth curve, not a set of straight lines. Draw it freehand in one flowing line, rounded at the turning point (no sharp corner).
    Label the curve y = −x2 + 5.

Check. Every plotted point should lie on the curve, and the curve should pass through (−3, −4) and (3, −4) at the ends. It should be symmetrical about the line x = 0. ✓

Watch out. Do not use a ruler to join the points, and do not draw pointed corners. A quadratic is smooth and rounded at the turning point.

xy-3-2-1123-5-4-3-2-1123456
The graph of y = 5 − x² (Worked example 13.1.3). The x² term is negative, so it is n-shaped.
Worked example 13.1.4
Does the point (−1, 6) lie on the graph of y = x2 − x + 4? Show your working.
▶ Watch this solution as a video

Key words. To substitute means to replace the letter by a number. A table of values lists x-values and the y-values that go with them. Each pair (x, y) is a coordinate that can be plotted.

Method. A point lies on a graph if its coordinates make the rule true. Substitute the x-value and see whether we get the y-value.

  1. Choose the x-value from the point. The point is (−1, 6), so x = −1 and the claim is that y = 6.
    y = x2 − x + 4
  2. Substitute x = −1 into the rule. Use brackets round the negative number. (−1)² = 1 and −(−1) = +1.
    y = (−1)2 − (−1) + 4 = 1 + 1 + 4 = 6
  3. Compare with the y-value in the point. We found y = 6, which is the same as the y-value in the point.
    y = 6, so the point (−1, 6) does lie on the graph.

Check. Try a different point: x = 0 gives y = 4, so (0, 4) is on the graph. The point (0, 6) would not be. ✓

Watch out. A point is on the graph only if the y-value matches exactly.

Watch out

Do not join the points with a ruler. A quadratic is a smooth curve, rounded at the turning point. A pointed bottom or straight pieces will lose marks. Also check every negative x: (−2)² is +4, not −4.

Exam tip

In a table the first and last y-values are usually the biggest, and the table is symmetrical. If your values are not, check the negative x calculations again.

Exercise 13A  Tables of values and plotting quadratics

Non-calculator
1
FWork out the value of y for each rule when x takes the value shown. Show the calculation.
(a)y = x2 when x = −2
(b)y = x2 + 3 when x = −1
(c)y = x2 − 5 when x = 3
(d)y = 2x2 when x = −2
(e)y = x2 + x when x = −3
(f)y = x2 − 3x + 1 when x = −2
2
FComplete the table of values for y = x2 + 2. Some values are already filled in.
x−3−2−10123
y   6   2   6   
3
FComplete the table of values for y = x2 − 4.
x−3−2−10123
y                     
4
FComplete the table of values for y = x2 + x.
x−3−2−1012
y                  
5
F(a) Complete the table of values for y = x2 + 1. (b) Draw the graph of y = x2 + 1 for values of x from −3 to 3.
x−3−2−10123
y                     
6
F(a) Complete the table of values for y = x2 − 4x + 3. (b) Draw the graph of y = x2 − 4x + 3 for values of x from −1 to 5.
x−1012345
y                     
7
F(a) Complete the table of values for y = −x2 + 2x + 3. (b) Draw the graph of y = −x2 + 2x + 3 for values of x from −2 to 4.
x−2−101234
y                     
8
RAisha is working out y when x = −3 for y = x² + 2. She writes: “(−3)² = −9, so y = −9 + 2 = −7.” Explain her mistake and work out the correct value.
9
FFor each point, say whether it lies on the graph of y = x2 − 3.
(a)(2, 1)
(b)(−1, −4)
(c)(0, −3)
(d)(−3, 6)
10
FWithout drawing the graph, say whether each quadratic graph is U-shaped or n-shaped.
(a)y = x2 + 5
(b)y = −x2 + 5
(c)y = −x2 + 3
(d)y = x2 − 5x
11
PSThe point (k, 11) lies on the graph of y = x² + 2. Work out the two possible values of k.
12
F(a) Complete the table of values for y = 2x2 − 3x − 5. (b) Draw the graph of y = 2x2 − 3x − 5 for values of x from −2 to 3.
x−2−10123
y                  
13
F(a) Complete the table of values for y = x² − 3x. (b) Draw the graph for values of x from 0 to 3. (c) Write down the coordinates of the turning point.
x00.511.522.53
y                     
14
RExplain why the graph of y = x² never goes below the x-axis.
15
RBen draws the graph of y = x² − 2x − 3 by joining his plotted points with a ruler. Explain why this is wrong.
16
R(a) Complete the table of values for y = x² − 6x + 8. (b) The point (1, 3) is on the graph. Use the symmetry of the table to write down the x-value of another point with y = 3. (c) Write down the equation of the line of symmetry. (d) Explain how you know.
x0123456
y                     
(a)Complete the table.
(b)Another point with y = 3.
(c)Line of symmetry.
(d)Explain.

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