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GCSE Maths · EdexcelChapter 22 · Constructions, loci, bearings and vectors
GCSE Maths · Loci, Bearings and Vectors · Foundation · Lesson 22.5

GCSE Maths: Combined loci and region problems (Foundation)

Part of the GCSE Maths loci, bearings and vectors chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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22.5

Combined loci and region problems

Edexcel 1MA1: G2
Grade 4-7

Real problems often give more than one rule: “the treasure is within 5 m of the tree and nearer to the gate than to the wall”. Each rule gives a locus. The answer is the region where all the rules are true at once. You find it in five steps.

  1. Draw an accurate plan (use the scale you are given, and a ruler).
  2. Draw the first locus lightly: a circle, a bisector, a parallel line. Decide which side (or inside/outside) obeys the rule.
  3. Draw the second locus in the same way, and any others.
  4. Shade the overlap: only the part of the plan that obeys every rule.
  5. Check with a test point inside your region. Measure to see that it obeys each rule.

Think of each rule as cutting away the part of the plan that does not obey it. What is left is the answer. For a rule such as “within 4 m of A” you keep the inside of a circle. For “at least 2 m from the wall” you keep the part of the plan on the far side of a line 2 m from the wall. For “nearer to A than B” you keep one side of the perpendicular bisector. For “nearer to side AB than to side AD” you keep one side of the angle bisector.

If a region would be empty (no point obeys every rule) say so. For example, no point can be within 2 cm of A and at least 5 cm from A.

Key ideas

  • Draw each locus separately, then shade the overlap of all of them.
  • Within / at most = inside the circle or band. At least = outside.
  • “Nearer to A than B”: the side of the perpendicular bisector with A on it. “Nearer to AB than AD”: one side of the angle bisector.
  • Use a test point to check your shaded region.
  • Use the scale: each square in the plans in this book is 1 unit (1 m or 1 km).
Worked example 22.5.1
The plan shows a rectangular garden ABCD with AB = 8 m and AD = 5 m. The plan is drawn on a grid where each square is 1 m. A tap is at corner A. Lily plants flowers in the region that is within 4 m of A and nearer to side AB than to side AD. Shade this region.
ABCD

Key words. A locus (plural loci) is the set of all the points that obey a rule. Equidistant means the same distance away.

Method. Draw each rule as a boundary line, then shade the region that obeys all the rules.

  1. Look at the plan and list the rules. Each rule gives a locus. The answer must obey every rule at the same time.
    Rule 1: within 4 m of A
    Rule 2: nearer to side AB than to side AD
  2. Draw rule 1: within 4 m of A. Each square is 1 m, so set the compasses to 4 squares. Put the point on A and draw an arc (a quarter circle) inside the garden.
    ABCD
  3. Draw rule 2: nearer to side AB than to side AD. Points the same distance from AB and AD are on the bisector of angle DAB. Construct it (it is the diagonal 45° line from A). Points nearer to AB are below this line.
    ABCD
  4. Shade the region that obeys all the rules. Points that are in the right place for every rule are where the regions overlap.
    ABCD

Check. Pick a point in the shaded region, for example (2.4, 1) measured from the bottom left corner of the plan. Test each rule:
distance from A = 2.6 m, which is at most 4 m ✓
distance from AB = 1.0 m and from AD = 2.4 m, so it is closer to AB ✓

Watch out. A point must pass every test. Shade only the overlap, not all of each region separately.

Worked example 22.5.2
The plan shows a field ABCD, 12 m by 7 m, drawn on a grid where each square is 1 m. There are two trees, P and Q. A treasure chest is buried so that it is nearer to P than to Q, at least 2 m from P, and within 3 m of the wall AB. Shade the region where the chest could be.
PQ

Key words. A locus (plural loci) is the set of all the points that obey a rule. Equidistant means the same distance away.

Method. Draw each rule as a boundary line, then shade the region that obeys all the rules.

  1. Look at the plan and list the rules. Each rule gives a locus. The answer must obey every rule at the same time.
    Rule 1: nearer to the tree P than to the tree Q
    Rule 2: at least 2 m from the tree P
    Rule 3: within 3 m of the wall AB
  2. Draw rule 1: nearer to the tree P than to the tree Q. Points the same distance from P and Q lie on the perpendicular bisector of PQ. Construct it (it is the vertical line half way between the trees). Shade the side with P.
    PQ
  3. Draw rule 2: at least 2 m from the tree P. Draw a circle with centre P and radius 2 squares. “At least 2 m” means on the circle or outside it.
    PQ
  4. Draw rule 3: within 3 m of the wall AB. Draw a line parallel to AB and 3 squares above it. “Within 3 m” means between this line and the wall AB.
    PQ
  5. Shade the region that obeys all the rules. Points that are in the right place for every rule are where the regions overlap.
    PQ

Check. Pick a point in the shaded region, for example (3, 1.2) measured from the bottom left corner of the plan. Test each rule:
distance from P = 2.3 m and from Q = 6.4 m, so it is closer to P ✓
distance from P = 2.3 m, which is at least 2 m ✓
distance from AB = 1.2 m, which is at most 3 m ✓

Watch out. A point must pass every test. Shade only the overlap, not all of each region separately.

Worked example 22.5.3
The map shows two towns X and Y joined by a straight road. Each square is 1 km. A phone mast is to be built at most 6 km from X, at least 4 km from Y, and within 2 km of the road XY. Shade the region where the mast can be built.
XY

Key words. A locus (plural loci) is the set of all the points that obey a rule. Equidistant means the same distance away.

Method. Draw each rule as a boundary line, then shade the region that obeys all the rules.

  1. Look at the plan and list the rules. Each rule gives a locus. The answer must obey every rule at the same time.
    Rule 1: at most 6 km from town X
    Rule 2: at least 4 km from town Y
    Rule 3: within 2 km of the straight road XY
  2. Draw rule 1: at most 6 km from town X. Each square is 1 km. Draw a circle with centre X and radius 6 squares. “At most 6 km” means inside the circle.
    XY
  3. Draw rule 2: at least 4 km from town Y. Draw a circle with centre Y and radius 4 squares. “At least 4 km” means outside the circle.
    XY
  4. Draw rule 3: within 2 km of the straight road XY. The road runs along the line through X and Y. Draw lines 2 squares above and 2 squares below it. “Within 2 km” means between these lines.
    XY
  5. Shade the region that obeys all the rules. Points that are in the right place for every rule are where the regions overlap.
    XY

Check. Pick a point in the shaded region, for example (3.6, 4) measured from the bottom left corner of the plan. Test each rule:
distance from X = 0.6 m, which is at most 6 m ✓
distance from Y = 7.4 m, which is at least 4 m ✓
distance from the road XY = 0.0 m, which is at most 2 m ✓

Watch out. A point must pass every test. Shade only the overlap, not all of each region separately.

Worked example 22.5.4
The diagram shows a triangular park ABC drawn on a grid where each square is 1 m. A bench is to go nearer to A than to B, within 5 m of C, and nearer to side AB than to side AC. Shade the region where the bench can go.
ABC

Key words. A locus (plural loci) is the set of all the points that obey a rule. Equidistant means the same distance away.

Method. Draw each rule as a boundary line, then shade the region that obeys all the rules.

  1. Look at the plan and list the rules. Each rule gives a locus. The answer must obey every rule at the same time.
    Rule 1: nearer to A than to B
    Rule 2: within 5 m of C
    Rule 3: nearer to side AB than to side AC
  2. Draw rule 1: nearer to A than to B. Construct the perpendicular bisector of AB and shade the side that contains A.
    ABC
  3. Draw rule 2: within 5 m of C. Draw a circle with centre C and radius 5 squares. Shade inside it.
    ABC
  4. Draw rule 3: nearer to side AB than to side AC. Construct the bisector of angle BAC. Points nearer to AB are on the AB side of the bisector.
    ABC
  5. Shade the region that obeys all the rules. Points that are in the right place for every rule are where the regions overlap.
    ABC

Check. Pick a point in the shaded region, for example (3.3, 1.6) measured from the bottom left corner of the plan. Test each rule:
distance from A = 3.7 m and from B = 5.0 m, so it is closer to A ✓
distance from C = 4.4 m, which is at most 5 m ✓
distance from AB = 1.6 m and from AC = 2.2 m, so it is closer to AB ✓

Watch out. A point must pass every test. Shade only the overlap, not all of each region separately.

Watch out

Do not shade each locus separately and stop. The answer is only where the shading overlaps. Also, check each inequality: “at least” means outside the circle, and “nearer to AB” means one particular side of the bisector, so test a point before you choose.

Exercise 22F  Region problems

Non-calculator
1
FThe plan shows a rectangular garden ABCD with AB = 8 m and AD = 5 m. Each square is 1 m. Shade the region that is within 4 m of A and within 2 m of side AB.
ABCD
2
FThe plan shows a rectangular garden ABCD. Each square is 1 m. Shade the region that is within 5 m of C and nearer to C than to D.
ABCD
3
PSA school playground ABCD is 10 m by 6 m and a tree T stands in the middle. Each square on the plan is 1 m. A bench is placed within 4 m of T, nearer to side AB than to side DC and at least 1 m from side AD. Shade the region where the bench could go.
ABCDT
4
PSA rectangular field PQRS is 10 m by 6 m. Each square on the plan is 1 m. A flag is placed within 6 m of Q, at least 2 m from side PS, and nearer to side RS than to side RQ. Shade the region where the flag can be placed.
PQRS
5
PSA lighthouse L and a port P are shown on a sea chart. Each square is 1 km. A ship is within 5 km of L, nearer to P than to L, and at least 2 km from the straight coastline AB. Shade the region where the ship could be.
LP
6
FUse the garden ABCD (A at the origin, AB along the x-axis, AD along the y-axis, each unit 1 m). The region is within 4 m of A and nearer to AB than to AD. Is each point in the region?
(a)(3, 2)
(b)(1, 3)
(c)(3.5, 3)
(d)(4, 1)
7
RAisha says: “It is impossible for a point to be within 2 cm of A and at least 5 cm from A.” Is she right? Explain.
8
RPoints A and B are 10 cm apart. A point must be within 3 cm of A and within 3 cm of B. Show that there is no such point.
9
PSIn the garden problem (the region within 4 m of A and nearer to AB than to AD), the region is a sector of a circle of radius 4 m with an angle of 45°. Work out its area to 2 decimal places.
10
PSA map has a scale of 1 : 50 000. A lighthouse can be seen up to 20 km away. On the map, a boat must be within the range of the lighthouse. Work out the radius of the circle that shows the range on the map, in cm.

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