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GCSE Maths · EdexcelChapter 22 · Constructions, loci, bearings and vectors
GCSE Maths · Loci, Bearings and Vectors · Foundation · Lesson 22.8

GCSE Maths: Vectors: column vectors, addition and scalar multiples (Foundation)

Part of the GCSE Maths loci, bearings and vectors chapter (Foundation). Chapter overview · Higher version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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22.8

Vectors: column vectors, addition and scalar multiples

Edexcel 1MA1: G24, G25
Grade 4-8

Some quantities only need a number: a mass of 5 kg or a time of 10 seconds. These are called scalars. Others need a number and a direction: a move of 3 squares right and 2 squares up, or a wind of 20 km/h from the west. These are vectors. A vector has a size (its length, also called its magnitude) and a direction.

Notation. A vector can be named by a single bold letter, such as a (you write a with an underline by hand), or by its start and end points with an arrow above them, such as →AB (the vector from A to B). On a diagram, the vector is drawn as an arrow.

Column vectors. A column vector gives the vector as two numbers written one above the other: x
y
. The top number x is the move across (right is positive, left is negative). The bottom number y is the move up (up is positive, down is negative). For example 3
2
means 3 right and 2 up, and −2
−4
means 2 left and 4 down.

abc
a = (3 over 2): 3 right, 2 up. b = (−2 over 3): 2 left, 3 up. c = (4 over 0): 4 right, no up or down.

Equal and negative vectors. Two vectors are equal if they have the same length and the same direction. Where they start does not matter: all the arrows 3
2
are the same vector wherever they are drawn. The negative of a vector, written −a, has the same length but the opposite direction. If a = 3
2
then −a = −3
−2
.

Translations. A translation moves every point of a shape the same distance in the same direction. It is described by a column vector. The translation 2
−3
moves every point 2 right and 3 down (Chapter 21).

xy−6−5−4−3−2−112345678−5−4−3−2−1123456AB
Triangle A is translated by (2 over −3) to triangle B. Every vertex moves 2 right and 3 down.

Adding vectors. To add two vectors, draw them nose to tail: start the second arrow where the first ends. The sum a + b goes straight from the start of the first to the end of the second. With column vectors, add the top numbers and add the bottom numbers.

aba + b
a = (3 over 1) and b = (1 over 3). a + b = (3 + 1 over 1 + 3) = (4 over 4).

Subtracting vectors. a − b means a + (−b): add the opposite of b. With column vectors, subtract the top numbers and subtract the bottom numbers. On a diagram, if a and b start at the same point, then a − b goes from the tip of b to the tip of a.

aba − b
a = (4 over 3), b = (1 over 2). a − b = (3 over 1), the arrow from the tip of b to the tip of a.

Scalar multiples. Multiplying a vector by a scalar (a number) changes its length. 2a is twice as long as a in the same direction, ½a is half as long, and −a is the same length in the opposite direction. With column vectors, multiply both numbers by the scalar. Vectors that are scalar multiples of each other are parallel.

a2a−a½a
a, 2a, −a and ½a are all parallel. They have lengths in the ratio 1 : 2 : 1 : 0.5.

Magnitude. The magnitude (length) of a vector is written |a|. For x
y
draw a right-angled triangle with shorter sides x and y: |a| = √(x2 + y2) by Pythagoras’ theorem. The vector from A to B is found by subtracting the coordinates: end minus start, so if A = (1, 2) and B = (4, 6) then the vector from A to B is 4 − 1
6 − 2
= 3
4
.

Key ideas

  • A column vector x
    y
    means x across (right +) and y up (up +).
  • Add or subtract vectors by adding or subtracting the top numbers and the bottom numbers.
  • Multiply a vector by a scalar: multiply both numbers. Vectors that are scalar multiples are parallel.
  • Magnitude: |a| = √(x2 + y2). The vector from A to B = coordinates of B minus coordinates of A.
  • A translation by a column vector moves every point the same way.
Worked example 22.8.1
Write down the column vector for the arrow a.
a

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. Count the squares from the tail of the arrow to its tip: across first, then up or down.

  1. Find the move across. Right is positive and left is negative. Count from the start of the arrow to its tip, sideways only.
    4 right: top number = 4
  2. Find the move up or down. Up is positive and down is negative.
    2 down: bottom number = −2
  3. Write the column vector. Across on top, up underneath.
    a = 4
    −2

Check. Start at the tail and add the vector: move 4 right and 2 down. You arrive at the tip. ✓

Watch out. The top number is across (x) and the bottom number is up (y). Do not swap them.

Worked example 22.8.2
a = 3
−2
and b = −1
4
. Work out a + b.

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. To add column vectors, add the top numbers and add the bottom numbers separately.

  1. Write the two column vectors. Each column vector has a top number (across) and a bottom number (up).
    a + b = 3
    −2
    + −1
    4
  2. Add the top numbers. To add vectors, add the matching numbers: top with top.
    3 + −1 = 2
  3. Add the bottom numbers. Now do the same with the bottom with bottom.
    −2 + 4 = 2
  4. Write the answer as a column vector. Put the new top number over the new bottom number.
    a + b = 2
    2

Check. On a grid: start at the origin, go 3 right and 2 down, then follow b. You arrive 2 right and 2 up of the start. ✓

Watch out. Take care with minus signs: subtracting a negative number adds. For example 3 − (−2) = 5.

Worked example 22.8.3
a = 3
1
and b = 1
−2
. Work out 2a − 3b.

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. Multiply each vector by its scalar first, then add or subtract the top numbers and the bottom numbers.

  1. Write each vector as a column. We can only add and subtract once everything is in column form.
    2a − 3b = 2 × 3
    1
    + −3 × 1
    −2
  2. Do the scalar multiplications first. Multiply every number in each vector by its scalar (like BIDMAS: multiply before adding).
    6
    2
    + −3
    6
  3. Add the top numbers. Add the matching numbers: top with top.
    6 + (−3) = 3
  4. Add the bottom numbers. Then bottom with bottom.
    2 + 6 = 8
  5. Write the answer.
    2a − 3b = 3
    8

Check. Check the top numbers again: 6 −3 = 3. ✓

Watch out. Do not forget to multiply both numbers, and watch the signs when you subtract a vector.

Worked example 22.8.4
A is the point (1, 2) and B is the point (4, −3). Write down the vector from A to B.

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. Subtract the coordinates of the start point from the coordinates of the end point.

  1. Write the two points. A column vector from A to B says how far to move across and up to get from A to B.
    A = (1, 2) and B = (4, −3)
  2. Find the across move. Subtract the x-coordinates: end minus start.
    4 − 1 = 3
  3. Find the up move. Subtract the y-coordinates: end minus start.
    −3 − 2 = −5
  4. Write the column vector. Across on top, up underneath.
    →AB = 3
    −5

Check. Start at A and add the vector: (1 + 3, 2 + −5) = (4, −3) = B. ✓

Watch out. It is end minus start. If you swap them you get the vector going the other way, which has the opposite signs.

Worked example 22.8.5
a = 5
−12
. Work out the magnitude of a.

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. The magnitude (length) of a vector is found with Pythagoras’ theorem on its two numbers.

  1. Draw the right-angled triangle. The vector a goes 5 across and 12 up or down. These two moves are at right angles, so the length of the vector is the hypotenuse.
    Shorter sides: 5 and 12
  2. Use Pythagoras’ theorem. Square each number, add them, then take the square root. Squaring removes any minus signs.
    |a|2 = 52 + (−12)2 = 25 + 144 = 169
  3. Square root. Find the length.
    |a| = √169 = 13

Check. The length must be at least as big as each number: 13 = 13.00 is bigger than 5 and 12. ✓

Watch out. Write |a| for the magnitude. The magnitude is never negative, even if the numbers in the vector are.

Worked example 22.8.6
Triangle ABC has vertices A(1, 1), B(3, 1) and C(2, 3). It is translated by the vector 2
−3
. Write the coordinates of the new vertices.

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. A translation moves every point of the shape by the same vector, so add the vector to each vertex.

  1. Read the translation. The top number is the move across and the bottom number is the move up.
    2
    −3
    : move 2 right and 3 down
  2. Move vertex A. Add the vector to the coordinates of the vertex.
    (1, 1) → (1 + 2, 1 + (−3)) = (3, −2)
  3. Move vertex B. Add the vector to the coordinates of the vertex.
    (3, 1) → (3 + 2, 1 + (−3)) = (5, −2)
  4. Move vertex C. Add the vector to the coordinates of the vertex.
    (2, 3) → (2 + 2, 3 + (−3)) = (4, 0)

Check. Every vertex has moved the same distance in the same direction, so the new shape is identical to the old one (same size, same way up). ✓

Watch out. A translation does not turn or flip the shape. Do not change the order of the vertices.

Worked example 22.8.7
a = 3
−2
and b = −6
4
. Show whether a and b are parallel.

Key words. A vector has a size (its length) and a direction. A column vector writes it as two numbers: how far across (right is +) over how far up (up is +). A scalar is an ordinary number.

Method. Two vectors are parallel when one is a scalar multiple of the other. Find the multiplier for the top numbers and the bottom numbers and see if it matches.

  1. Compare the top numbers. If the vectors are parallel, one is a multiple of the other, so the top numbers have the same scale factor as the bottom numbers.
    −6 ÷ 3 = −2
  2. Compare the bottom numbers. Is the multiplier the same?
    4 ÷ −2 = −2
  3. Write the conclusion. Both numbers are multiplied by the same scalar.
    b = −2a, so they are parallel.

Check. −2 × 3
−2
= −6
4
. ✓

Watch out. The scalar can be negative. Vectors that point in opposite directions along the same line are still parallel.

Watch out

Keep the top number for across and the bottom for up. A common mistake is to read the vector from the wrong end of the arrow, or to forget the minus signs for left and down. And |a + b| is not |a| + |b|: work out the vector first, then its length.

Exercise 22J  Column vectors and translations

Non-calculator
1
FWrite down each vector as a column vector.
abcd
(a)a
(b)b
(c)c
(d)d
2
FWrite each movement as a column vector.
(a)3 right and 2 up
(b)4 left and 1 up
(c)2 right and 5 down
(d)6 left
3
FWork out the column vector from the first point to the second point.
(a)A(1, 2) to B(4, 6)
(b)A(-2, 3) to B(2, -1)
(c)A(5, 4) to B(1, 4)
(d)A(0, -3) to B(-4, -6)
4
FWork out the coordinates of the end point B.
(a)A(2, 1), vector from A to B is 3
4
(b)A(-1, 5), vector from A to B is 4
−2
(c)A(0, 0), vector from A to B is −3
−6
(d)A(6, -2), vector from A to B is −2
5
5
FTriangle T has vertices A(1, 1), B(3, 1) and C(2, 3). It is translated by the vector 3
−2
to give T′. Write the coordinates of A′, B′ and C′.
xy−6−5−4−3−2−112345678−5−4−3−2−1123456TT'
6
FShape P is translated to shape Q. Describe the translation using a column vector.
xy−6−5−4−3−2−112345−4−3−2−112345PQ
7
Fa = 3
−2
. Write down each vector.
(a)−a
(b)2a
(c)−3a
8
PSA drone moves 3
4
, then −1
2
, then 5
−6
(in metres). Work out its total movement as a column vector and its distance from where it started.
9
PSABCD is a parallelogram with A at (1, 1). The vector from A to B is 4
1
and the vector from A to D is 1
3
. Write down (a) the vector from B to C, (b) the vector from D to C, (c) the coordinates of C.
10
RAre the vectors 2
3
and 3
2
equal? Give a reason.
11
RTriangle T is translated by 3
−2
, and then the image is translated by −3
2
. Show that the final triangle is in the same position as T.
12
PSA translation maps the point A(2, 3) to A′(7, 1). B is the point (5, −4). Work out the coordinates of B′, the image of B under the same translation.
13
PSA ship sails 6 km east and then 8 km north. Write its movement as a column vector and find how far it is from its start.
14
RChallenge. A translation moves the point P(1, 2) to Q and then Q is moved by a second translation −3
5
to R(4, 1). Work out the coordinates of Q and the vector from P to Q.

Exercise 22K  Combining vectors: addition, scalar multiples and magnitude

Calculator allowed
1
FWork out each sum.
(a)3
2
+ 4
1
(b)−1
5
+ 2
−3
(c)6
−4
+ −2
−2
(d)0
7
+ −5
3
2
FWork out each difference.
(a)5
7
− 2
3
(b)1
−2
− 4
5
(c)−3
6
− −1
2
(d)2
−4
− −6
−9
3
FWork out each scalar multiple.
(a)23
−1
(b)−32
4
(c)0.58
−6
(d)0.2512
8
4
Fa = 2
3
,   b = −1
4
. Work out each vector.
(a)a + b
(b)2a + b
(c)3a − 2b
(d)a − 3b
5
FIn each case, say whether the two vectors are parallel.
(a)3
6
and 1
2
(b)2
−3
and −4
6
(c)4
1
and 8
3
(d)5
0
and −10
0
6
FWork out the magnitude of each vector. Give whole-number answers.
(a)3
4
(b)5
12
(c)8
6
(d)−7
24
7
FWork out the magnitude of each vector, correct to 1 decimal place.
(a)2
5
(b)−3
−7
(c)6
−1
8
Fa = 2
3
and b = −1
4
. Work out |a + b| correct to 1 decimal place.
9
PSIn 1 hour a plane would fly 240
180
km (east, north) in still air. The wind blows it by −40
−60
km. Work out the plane’s actual movement as a vector and the distance it actually travels in 1 hour, correct to 1 decimal place.
10
Ra = 6
−9
and b = −2
3
. Show that a is parallel to b, and say how many times as long a is.
11
RZara says that |a + b| = |a| + |b| for all vectors. Use a = 3
0
and b = 0
4
to show she is wrong.
12
PSThe vector k
6
is parallel to 2
3
. Work out the value of k.
13
RChallenge. a = 3
4
. Find a vector that is parallel to a, in the same direction, with magnitude 10.

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