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GCSE Maths · EdexcelChapter 6 · Standard form, indices and surds
GCSE Maths · Standard Form, Indices and Surds · Higher · Lesson 6.1

GCSE Maths: Index notation and the laws of indices (Higher)

Part of the GCSE Maths standard form, indices and surds chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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6.1

Index notation and the laws of indices

Edexcel 1MA1: N6, N7, A4
Grade 2-5

Fold a sheet of paper in half and it has 2 layers. Fold it again and there are 4 layers. Fold again: 8. Every fold doubles the number of layers, so after 3 folds there are 2 × 2 × 2 layers. Mathematicians write this in a short way: 23, said “2 to the power 3”. This is called index notation.

34baseindex (power)3 × 3 × 3 × 3= 814 lots of 3 multiplied
In 34 the base is 3 and the index is 4: four lots of 3 are multiplied together.

The big number is the base. The small raised number is the index (plural: indices; it is also called the power or exponent). The index tells you how many lots of the base are multiplied together. You already know two special cases: “squared” means index 2 and “cubed” means index 3. Be careful: 23 is 2 × 2 × 2 = 8. It is not 2 × 3 = 6.

The index counts lots, and counting lots is easy. That is why there are three simple laws of indices. Each one comes straight from writing the powers out in full.

333333343234+2 = 64 lots + 2 lots = 6 lots
Law 1: 34 × 32. Four lots of 3 and then two more lots of 3 makes 4 + 2 = 6 lots of 3.

Law 1 (multiplying). When you multiply powers of the same base, add the indices. 34 × 32 = 34+2 = 36.

Law 2 (dividing). When you divide powers of the same base, subtract the indices. 35 ÷ 32 = (3 × 3 × 3 × 3 × 3) ÷ (3 × 3). Two of the 3s cancel on the top and bottom, leaving three of them: 35−2 = 33.

Law 3 (power of a power). (32)3 means three lots of 32, that is 32 × 32 × 32 = 32+2+2 = 36. Three lots of 2 is 3 × 2, so we multiply the indices.

These laws only work when the bases are the same. They also work with letters, because a letter stands for a number. For example x2 × x5 = x7. When there are numbers in front of the letters (the coefficients), deal with the numbers and the letters separately: 3x2 × 4x5 = (3 × 4) × x2+5 = 12x7. A letter on its own has index 1, so x = x1.

Key ideas

  • am × an = am+n   (add the indices)
  • am ÷ an = am−n   (subtract the indices)
  • (am)n = am×n   (multiply the indices)
  • The bases must be the same for the first two laws.
  • With coefficients: multiply or divide the numbers, then use the laws on each letter. (2a)3 = 23a3 = 8a3.
  • a1 = a.
Worked example 6.1.1
Write 2 × 2 × 2 × 2 × 2 as a power of 2, and work out its value.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. Count how many 2s are multiplied to get the index, then multiply them out.

  1. Count the 2s. The index of a power is the number of equal numbers being multiplied.
    There are 5 lots of 2, so the index is 5.
  2. Write it as a power. Base 2, index 5.
    2 × 2 × 2 × 2 × 2 = 25
  3. Multiply step by step. Do one multiplication at a time.
    2 × 2 = 4
    4 × 2 = 8
    8 × 2 = 16
    16 × 2 = 32
  4. Write the answer.
    25 = 32

Check. 25 = 22 × 23 = 4 × 8 = 32. ✓

Watch out. 25 is not 2 × 5 = 10. The index counts lots of 2 multiplied together.

Worked example 6.1.2
Write 34 × 32 as a single power of 3.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. When you multiply powers with the same base, you add the indices: am × an = am+n.

  1. Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.
    Both bases are 3.
  2. Write each power out in full. This shows what is really happening: we are counting how many lots of the base are multiplied.
    34 = 3 × 3 × 3 × 3
    32 = 3 × 3
    Together: 4 lots of 3 and 2 lots of 3 make 6 lots of 3.
  3. Add the indices. Joining the lots means adding the number of lots.
    4 + 2 = 6
  4. Write the answer as a single power. Keep the same base and use the new index.
    34 × 32 = 36

Check. Work out the numbers: 34 = 81 and 32 = 9. 81 × 9 = 729, and 36 = 729. ✓

Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).

Worked example 6.1.3
Write (57 × 52) ÷ 56 as a single power of 5.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. Use the laws of indices in order: add indices to multiply, subtract indices to divide.

  1. Check that every base is the same. The laws of indices only work when the bases match.
    Every base is 5.
  2. Work out the top first: multiply, so add the indices. am × an = am+n.
    7 + 2 = 9, so the top is 59
  3. Divide: subtract the indices. am ÷ an = am−n.
    5956 = 59 ÷ 56 = 53, because 9 − 6 = 3

Check. The total of the indices on top is 9 and on the bottom is 6; 9 − 6 = 3. ✓

Watch out. Deal with the multiplication in the top (and bottom) first, then divide. Only subtract once the top and bottom are each a single power.

Worked example 6.1.4
Work out (23)4 as a power of 2, and then as a number.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. To raise a power to a power, multiply the indices: (am)n = am×n.

  1. Write the bracket out as repeated multiplication. The outer index 4 means 4 lots of 23 multiplied together.
    (23)4 = 23 × 23 × 23 × 23
    = 23 + 3 + 3 + 3
    That is 4 lots of 3, which is 4 × 3 = 12.
  2. Multiply the indices. Each of the outer lots holds m of the base, so the total is m × n.
    3 × 4 = 12
  3. Write the answer as a single power. Keep the same base and use the new index.
    (23)4 = 212
  4. Work out the value. 212 means 12 lots of 2 multiplied together.
    212 = 2 × 2 × … × 2 (12 lots of 2) = 4096

Check. Work out the numbers: 23 = 8, and 84 = 4096. Also 212 = 4096. ✓

Watch out. A power of a power: multiply the indices. Adding them would be for 32 × 34, which is a different question.

Worked example 6.1.5
Simplify 3x2 × 4x5.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.

Method. Multiply the numbers, then add the indices of each letter: am × an = am+n.

  1. Multiply the numbers in front (the coefficients). The numbers can be dealt with separately from the letters.
    3 × 4 = 12
  2. Deal with the letter x: add the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)
    x2 × x5 = x2 + 5 = x7
  3. Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.
    12x7

Check. Choose numbers: x = 2. The original expression has the value 1536, and the answer 12x7 also has the value 1536. ✓

Watch out. Add the indices of the same letter only. You cannot combine different letters: a2 × b3 stays as it is.

Worked example 6.1.6
Simplify (2a3)4.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.

Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.

  1. Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.
    (2)4 = 2 × 2 × 2 × 2 = 16
  2. Raise the letter a to the power: multiply the indices. (am)n = am×n.
    (a3)4 = a3 × 4 = a12
  3. Put it all together.
    16a12

Check. Choose numbers: a = 2. The original expression has the value 65,536, and the answer 16a12 also has the value 65,536. ✓

Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.

Worked example 6.1.7
Simplify (2x3y)3 × 4xy2 ÷ 8x2y.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.

Method. Work through the expression one operation at a time, using the laws of indices on the number and on each letter.

  1. Look at the order of the operations. Work from the left, one operation at a time, exactly as in BIDMAS (brackets and powers first).
  2. Do the first operation: raise to the power 3. Raise the number and every index to the power: multiply the indices.
    (2)3 = 2 × 2 × 2 = 8
    (x3)3 = x3 × 3 = x9
    (y1)3 = y1 × 3 = y3
    Result so far: 8x9y3
  3. Do the second operation: multiply by 4xy2. Multiply the numbers; add the indices of each letter.
    8 × 4 = 32
    x9 × x1 = x9 + 1 = x10
    y3 × y2 = y3 + 2 = y5
    Result so far: 32x10y5
  4. Do the third operation: divide by 8x2y. Divide the numbers; subtract the indices of each letter.
    32 ÷ 8 = 4
    x10 ÷ x2 = x10 − 2 = x8
    y5 ÷ y1 = y5 − 1 = y4
    Result so far: 4x8y4

Check. Choose numbers: x = 2, y = 3. The original expression gives 82,944 and the answer 4x8y4 gives 82,944. ✓

Watch out. Keep the working in the same order each time. Deal with brackets and powers first, then multiplication and division from left to right.

Watch out

Do not multiply the bases and do not multiply the indices when you are multiplying powers. 32 × 34 is not 96. The base stays 3 and the indices add: 36. And you cannot combine powers of different letters or different numbers: x3 + x2 does not equal x5, and 23 × 32 is not 65.

Exam tip

In an exam, show the indices adding: write 34+2 = 36. If the question says “work out the value” you must also give the final number.

Exercise 6A  Powers and the laws of indices with numbers

Non-calculator
1
FWrite each product as a power.
(a)5 × 5 × 5 × 5
(b)2 × 2 × 2 × 2 × 2 × 2
(c)10 × 10 × 10
(d)7 × 7
2
FWork out the value of each power.
(a)25
(b)34
(c)103
(d)53
(e)43
(f)62
3
FWrite each as a single power.
(a)23 × 24
(b)52 × 56
(c)75 × 71
(d)103 × 103
4
FWrite each as a single power.
(a)68 ÷ 63
(b)49 ÷ 45
(c)37 ÷ 32
(d)106 ÷ 104
5
FWrite each as a single power.
(a)(32)4
(b)(53)2
(c)(25)3
(d)(102)3
6
FWork out the value of each. Write it as a single power first.
(a)23 × 22
(b)35 ÷ 33
(c)(22)3
(d)102 × 103
(e)54 ÷ 52
7
FWork out the value of each product.
(a)23 × 52
(b)22 × 33
(c)103 × 42
(d)32 × 24
8
FFind the missing index in each equation.
(a)34 × 3? = 39
(b)7? × 72 = 75
(c)58 ÷ 5? = 53
(d)2? ÷ 23 = 24
(e)(4?)3 = 412
9
FWrite each as a single power of the base.
(a)57 × 5256
(b)23 × 2524
(c)3932 × 33
(d)74 × 7372 × 71
10
RZoe says that 23 × 24 is the same as 47. Is she right? Explain your answer.
11
RDan writes 56 ÷ 52 = 53. Explain his mistake and write down the correct answer.
12
PSA piece of paper is folded in half again and again. Each fold doubles the number of layers.
(a)How many layers are there after 6 folds? Write the answer as a power of 2 and then as a number.
(b)What is the smallest number of folds that gives more than 1000 layers?
13
PSA message is sent in rounds. In round 1, one person sends it to 3 people. In every later round, each person who has just received it sends it to 3 new people. In round n, 3n people receive the message.
(a)How many people receive the message in round 5?
(b)Show that the number of people in round 3 multiplied by the number in round 2 is the number in round 5.
14
PSA cube has edges of length 102 cm. The volume of a cube is (edge)3. Work out the volume as a number of cm3.
15
RShow that 8 × 16 = 27.
16
Ra and b are positive whole numbers. 2a × 2b = 28 and 2a ÷ 2b = 22. Find a and b.

Exercise 6B  The laws of indices with letters

Non-calculator
1
FSimplify each expression.
(a)x3 × x4
(b)y5 × y2
(c)a × a6
(d)p3 × p3
2
FSimplify each expression.
(a)x9 ÷ x4
(b)y7 ÷ y2
(c)m8 ÷ m
(d)t5 ÷ t4
3
FSimplify each expression.
(a)(x3)2
(b)(y4)3
(c)(a2)5
(d)(p6)2
4
FSimplify each expression.
(a)3x2 × 4x5
(b)2y3 × 5y
(c)6a4 × 2a2
(d)7p × 3p3
5
FSimplify each expression.
(a)12y8 ÷ 4y3
(b)20a7 ÷ 5a2
(c)18x5 ÷ 6x
(d)8m6 ÷ 2m6
6
FSimplify each expression.
(a)(2a3)4
(b)(5x2)3
(c)(3y4)2
(d)(10p3)2
7
FSimplify each expression.
(a)3a2b × 5ab3
(b)4x2y × 2xy2
(c)6p3q2 ÷ 3pq
(d)10m5n4 ÷ 5m2n
8
RMia writes 2x3 × 3x4 = 6x12. Is she right? Give a reason.
9
RIs it true that x3 + x2 = x5? Use x = 2 to explain.
10
PSA rectangle has length 4x3 cm and width 3x2 cm. Write an expression for its area in the simplest form.
11
PSThe area of a rectangle is 24x7 cm2. Its length is 6x3 cm. Find its width.
12
PSThe three edges of a cuboid are 2a, 3a2 and 5a3. Find an expression for its volume.
13
FSimplify (2x3y)3 × 4xy2 ÷ 8x2y.
14
FSimplify each expression.
(a)(3a2b3)2 ÷ 9ab2
(b)(5m2n)3 ÷ 25mn2
(c)4x2 × (2x3)2 ÷ 8x5
15
RSimplify xn+2 × xn−1.
16
R2x = k. Write 2x+3 in terms of k.

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