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GCSE Maths · EdexcelChapter 6 · Standard form, indices and surds
GCSE Maths · Standard Form, Indices and Surds · Higher · Lesson 6.2

GCSE Maths Standard Form, Indices and Surds: Zero and negative indices (Higher)

Part of the GCSE Maths standard form, indices and surds chapter (Higher). Chapter overview · Foundation version of this lesson · whole chapter on one page · Download worksheet (PDF) · Answers (PDF)

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6.2

Zero and negative indices

Edexcel 1MA1: N7, A4
Grade 4-6

So far every index has been a positive whole number. But what do 20 and 2−1 mean? We cannot multiply “zero lots of 2”, so instead we follow the pattern.

23= 8÷222= 4÷221= 2÷220= 1÷22−1= 1/2÷22−2= 1/4÷22−3= 1/8Each step to the right divides by 2
Going one step to the right the index goes down by 1 and the value is divided by 2. Keep the pattern going and 20 = 1, 2−1 = 1/2, 2−2 = 1/4.

Look at the boxes from left to right: 8, 4, 2, then the next number must be 2 ÷ 2 = 1. So 20 = 1. The same thing happens with any base, so any non-zero number to the power 0 equals 1. You can also see it from the division law: a3 ÷ a3 = a3−3 = a0, but anything divided by itself is 1.

Continue the pattern past 1: the next value is 1 ÷ 2 = 1/2, so 2−1 = 1/2. Then 2−2 = 1/4 and 2−3 = 1/8. A negative index means “one over” (the reciprocal; see Chapter 3):

a−n = 1an

A negative index does not make the answer negative. It makes the answer small: a fraction. For a fraction base, the reciprocal turns the fraction upside down, so 23−2 = 322 = 94.

Two more things to know. 10−1 = 0.1, 10−2 = 0.01 and 10−3 = 0.001 (you will need these for standard form in section 6.4). And all the laws of section 6.1 still work with zero and negative indices. For example 52 × 5−4 = 52+(−4) = 5−2 = 125, and x3 ÷ x5 = x−2 = 1x2.

Key ideas

  • a0 = 1 for any number a that is not 0. (50 = 1, 10000 = 1.)
  • a1 = a.
  • a−n = 1 ÷ an. A negative index means “one over”, not a negative number.
  • (a/b)−n = (b/a)n: flip the fraction and make the index positive.
  • 10−1 = 0.1, 10−2 = 0.01, 10−3 = 0.001.
  • The laws of indices work for all whole-number indices, including zero and negative ones.
Worked example 6.2.1
Work out 50 + 2 × 30.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. A number (or bracket) to the power zero is 1.

  1. Remember the rule for a zero index. Any non-zero number raised to the power 0 equals 1. This is because an ÷ an = 1, and by the division law it is also an−n = a0.
    a0 = 1
  2. Replace every power with index 0 by 1, and work out the rest. Powers are worked out before multiplying and adding (BIDMAS): each zero power becomes 1.
    50 = 1 and 30 = 1
    50 + 2 × 30 = 1 + 2 × 1
    = 1 + 2 = 3
  3. Write the answer.
    3

Check. Look again: each 0 index was changed to 1 and nothing else was changed. ✓

Watch out. 50 = 1, not 0 and not 5. And in 5x0 only the x has the index 0, so it is 5 × 1 = 5.

Worked example 6.2.2
Work out 2−3.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.

  1. Spot the negative index. A negative index does not make the answer negative. It means "one over".
    2−3: the index is −3
  2. Turn it into a reciprocal with a positive index. The rule is a−n = 1an. (Check with a pattern: 22 = 4, 21 = 2, 20 = 1, and each step is ÷ 2, so 2−1 = 12.)
    2−3 = 123
  3. Work out the bottom. 23 means 3 lots of 2 multiplied together.
    23 = 2 × 2 × 2 = 8
  4. Write the answer as a fraction.
    2−3 = 18

Check. Multiply the answer by 23: 18 × 8 = 1, and 2−3 × 23 = 20 = 1. ✓

Watch out. A negative index does not give a negative answer: 2−3 = 18, not a negative number.

Worked example 6.2.3
Work out (23)−2.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. A negative index means "one over": a−n = 1 ÷ an. For a fraction, flip it upside down and make the index positive.

  1. Spot the negative index. A negative index means "reciprocal". The reciprocal of a fraction is the fraction turned upside down.
    (23)−2: the index is −2
  2. Flip the fraction and change the index to positive. Negative index = reciprocal. The reciprocal of 23 is 32.
    (23)−2 = (32)2
  3. Raise the top and the bottom to the power. The index 2 applies to the numerator and to the denominator.
    3222 = 94
  4. Write the answer (simplify if possible).
    94

Check. Multiply the answer by (23)2 = 49: the product is 1, as (23)−2 × (23)2 = (23)0 = 1. ✓

Watch out. A negative index does not give a negative answer: (23)−2 = 94, not a negative number.

Worked example 6.2.4
Write 125 as a power of 5.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. Write the bottom of the fraction as a power, then use a−n = 1/an backwards.

  1. Look at the fraction. It has 1 on the top and a number on the bottom, so it is "one over" something. A negative index means "one over".
    125
  2. Write the denominator as a power of the base. 25 = 5 × 5 = 52
    125 = 152
  3. Use the rule for a negative index. "One over a power" is the same as the power with a negative index: 1an = a−n.
    152 = 5−2

Check. Convert back: 5−2 = 152 = 125. ✓

Watch out. The number on the bottom becomes the base. The index gets the minus sign.

Worked example 6.2.5
Work out 52 × 5−4, giving your answer as a fraction.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81.

Method. When you multiply powers with the same base, you add the indices: am × an = am+n.

  1. Check that the bases are the same. These laws only work when the base (the big number) is the same in both powers.
    Both bases are 5.
  2. Say what the rule means. The index counts the lots of the base. Multiplying powers joins the lots together.
    52 has 2 lots of 5; 5−4 has −4 lots of 5.
  3. Add the indices. Joining the lots means adding the number of lots. The rule works for negative indices too, so take care with the signs.
    2 + (−4) = −2
  4. Write the answer as a single power. Keep the same base and use the new index.
    52 × 5−4 = 5−2
  5. Work out the value. A negative index means "one over" the positive power (see section 6.2).
    5−2 = 152 = 125

Watch out. Add the indices when you multiply. Do not multiply the indices, and do not multiply the bases (32 × 34 is not 96).

Worked example 6.2.6
Simplify x3 ÷ x5, and write your answer with a positive index.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.

Method. Divide the numbers, then subtract the indices of each letter: am ÷ an = am−n.

  1. Deal with the letter x: subtract the indices. The letter is the same in both terms, so the index law applies. (x on its own means x1.)
    x3 ÷ x5 = x3 − 5 = x−2 = 1x2
  2. Put the number and the letters together. Write the coefficient first, then the letters in alphabetical order.
    x−2
  3. Write with positive indices. A negative index means "one over": a−n = 1/an.
    x−2 = 1x2

Check. Choose numbers: x = 2. The original expression has the value 14, and the answer x−2 also has the value 14. ✓

Watch out. Subtract the indices (top minus bottom), and divide the numbers. Do not subtract the numbers.

Worked example 6.2.7
Simplify (2x−3)2, writing your answer with a positive index.

Key words. In 34, the base is 3 and the index (also called the power or exponent) is 4. The index tells you how many lots of the base are multiplied together: 34 = 3 × 3 × 3 × 3 = 81. A coefficient is the number in front of a letter, so in 7x3 the coefficient is 7. A letter on its own, like x, really means x1.

Method. Raise the number and every letter to the power. Multiply the indices: (am)n = am×n.

  1. Raise the number in front to the power. Everything inside the bracket is raised to the power, and that includes the number.
    (2)2 = 2 × 2 = 4
  2. Raise the letter x to the power: multiply the indices. (am)n = am×n.
    (x−3)2 = x−3 × 2 = x−6
  3. Put it all together.
    4x−6
  4. Write with positive indices. A negative index means "one over": a−n = 1/an.
    4x−6 = 4x6

Check. Choose numbers: x = 2. The original expression has the value 116, and the answer 4x−6 also has the value 116. ✓

Watch out. The number in front is raised to the power too: (2a)3 = 8a3, not 2a3.

Watch out

A negative index does not make a number negative. 2−3 is 18, not −8 and not −6. Also be careful with zero: 50 = 1, not 0. And in 5x0 the index 0 belongs to the x only, so it is 5 × 1 = 5, while (5x)0 = 1.

Exercise 6C  Zero and negative indices

Non-calculator
1
FWork out the value of each.
(a)70
(b)1000
(c)(−3)0
(d)20 + 30
(e)5 × 40
2
FWrite each as a fraction.
(a)2−1
(b)3−2
(c)10−3
(d)5−2
(e)4−1
(f)2−4
3
FWrite each fraction as a power with a negative index.
(a)18
(b)19
(c)1100
(d)1125
(e)132
4
FWork out each. Give your answers as whole numbers or fractions in their simplest form.
(a)(12)−3
(b)(23)−2
(c)(15)−2
(d)(34)−2
(e)(25)−1
5
FWrite each of these as a decimal.
(a)10−1
(b)10−2
(c)10−3
(d)10−4
(e)10−5
6
FComplete the pattern: 103 = 1000, 102 = 100, 101 = 10. Work out the value of the next three powers.
(a)100
(b)10−1
(c)10−2
7
FWork out the value of each. Give a whole number or a fraction.
(a)52 × 5−4
(b)23 ÷ 25
(c)(32)−1
(d)10−3 × 105
(e)7−2 × 7−1
8
FSimplify each. Write your answer with positive indices.
(a)x2 ÷ x6
(b)y3 ÷ y8
(c)a2 × a−5
(d)3x−2 × 4x5
9
RJack says that 3−2 = −9. Explain his mistake and work out the correct value.
10
RUse the division law to show that 50 = 1.
11
PSA virus is about 10−7 m long. A bacterial cell is about 10−5 m long. How many times longer is the cell than the virus?
12
PSWhich is larger, 2−3 or 3−2? Show your working.
13
PSA radioactive sample has a mass of 80 g. After n days its mass is 80 × 2−n grams. Work out the mass after 3 days and after 5 days.
14
FSimplify each. Write your answers with positive indices.
(a)(2x−3)2
(b)6x2 ÷ 3x−1
(c)(4a−2b)2 ÷ 8a−1b3
15
RShow that (2−3 × 25) ÷ 2−2 = 16.
16
R4a = 164. Find the value of a.

Exercise 6D  Index equations and mixed practice

Non-calculator
1
FFind the value of n in each equation.
(a)2n = 32
(b)3n = 81
(c)5n = 125
(d)10n = 1000
(e)2n = 128
2
FFind the value of n in each equation. (The answers are negative whole numbers.)
(a)2n = 18
(b)3n = 19
(c)10n = 1100
(d)5n = 15
(e)4n = 116
3
FFind the value of x.
(a)2x + 3 = 28
(b)3x − 1 = 34
(c)5x + 2 = 56
(d)10x − 2 = 103
4
FWork out each. Give your answer as a fraction.
(a)2−1 + 2−2
(b)3−1 + 3−2
(c)50 + 5−1
5
PSWrite these numbers in order, smallest first: 2−1, 20, 2−3, 22.
6
RWrite 18 as a power of 2, and write 8 × 132 as a power of 2.
(a)18
(b)8 × 132
7
RShow that (13)−2 × 3−4 = 19.
8
RFind the value of x when 2x × 23 ÷ 2−2 = 29.

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